algorithm with fill area.

I have that table t defined below.
All 4 columns contain data from only positive integer, the minimum value is 1 in all columns.
1 pair column (STARTVAL, ENDVAL) define the range of integers. And we can be sure that there is at least 2 files with same (STARTVAL, ENDVAL) pair. By pair example '2-5' has 2 records and pair 5-10 a 3 is entered, there is no pair that has only a single folder. Data have probably been inserted as STARTVAL < ENDVAL, so that it is no pairs with the same start and end value.

2 pairs (FILLSTART, FILLEND) column are suppoused to perfectly fill (STARTVAL, ENDVAL) range for the pair (STARTVAL, ENDVAL). Data have probably been inserted as FILLSTART < FILLEND, so that it is no pairs with the same start and end value. For example, (STARTVAL, ENDVAL) =(2-5) we have loads (FILLSTART, FILLEND) =(2-3) (FILLSTART, FILLEND) =(4-5), if we can say that the logical unit (STARTVAL, ENDVAL) =(2-5) is perfectly filled. "But filled" means that no additional space is that none are is filled and more than once. For example "3-6" region has in unnecessary charges addional filled area to the point 7-7 and 4-4 overlaps for two records here as you see.
with T as
(  --OK. Case 2-5 filled with 2-3 and 4-5.
   select 2 StartVal, 5 EndVal, 2 FillStart, 3 FillEnd from dual union all
   select 2 StartVal, 5 EndVal, 4 FillStart, 5 FillEnd from dual union all
   --NOT OK. Case 3-6 filled with 3-4 and 4-7, point 4-4 is fileld more than once, point 7-7 is not needed.
   select 3 StartVal, 6 EndVal, 3 FillStart, 4 FillEnd from dual union all
   select 3 StartVal, 6 EndVal, 4 FillStart, 7 FillEnd from dual union all
   --NOT OK. Case 4-7 filled with 3-4 and 4-7, too much filled in point "4-4" and not needed point "3-3"
   select 4 StartVal, 7 EndVal, 3 FillStart, 4 FillEnd from dual union all
   select 4 StartVal, 7 EndVal, 4 FillStart, 7 FillEnd from dual union all  
   --NOT OK. Case 4-8 filled with 4-5 and 7-8, missing is point 6-6
   select 4 StartVal, 8 EndVal, 4 FillStart, 5 FillEnd from dual union all
   select 4 StartVal, 8 EndVal, 7 FillStart, 8 FillEnd from dual union all
   --OK. Case 5-10 filled with 5-6 and 7-8 and 9-10
   select 5 StartVal, 10 EndVal, 5 FillStart, 6 FillEnd from dual union all
   select 5 StartVal, 10 EndVal, 7 FillStart, 8 FillEnd from dual union all
   select 5 StartVal, 10 EndVal, 9 FillStart, 10 FillEnd from dual union all
   --NOT OK. Case 5-11 filled with 5-6 and 8-9 and 10-11, missing is point 7-7.
   select 5 StartVal, 11 EndVal, 5 FillStart, 6 FillEnd from dual union all
   select 5 StartVal, 11 EndVal, 8 FillStart, 9 FillEnd from dual union all
   select 5 StartVal, 11 EndVal, 10 FillStart, 11 FillEnd from dual
)
select * from T
order by 1,2,3,4;
/*
2     5     2     3
2     5     4     5--OK!
3     6     3     4
3     6     4     7--NOT OK: intersects at (4,4), and (7,7) is out of range (3,6)
4     7     3     4
4     7     4     7--NOT OK: intersects at (4,4)
4     8     4     5
4     8     7     8--NOT OK: area (6,6) is not filled
5     10     5     6
5     10     7     8
5     10     9     10--OK!
5     11     5     6
5     11     8     9--NOT OK: area (7,7) not filled
5     11     10     11
*/
I want to display all (STARTVAL, ENDVAL) pairs that is not 'Perfect fill' in the columns (FILLSTART, FILLEND). The query must exit that I've marked as 'NOT OK'... or it should only those that I've marked marked as 'OK' - any output, I'll customize later query I think. My point is to determine if the filelrs to fill the area perfectly or not, if they do not meet I trigger business mistake later.
How to write this query?

My initial query looks like this:
select * from T T2,
(select T.STARTVAL, T.ENDVAL, min(T.FILLSTART) MINFILLSTART, max(T.FILLEND) MAXFILLEND, 
SUM(T.FILLEND - T.FILLSTART) SUMFILLER from T
group by T.STARTVAL, T.ENDVAL) MINMAX
where T2.STARTVAL = MINMAX.STARTVAL and T2.ENDVAL = MINMAX.ENDVAL
   --The leftmost Filler should start with same value as T2.STARTVAL:
   and T2.STARTVAL = MINMAX.MINFILLSTART
   --The rightmost Filler should end with same value as T2.ENDVAL:
   and T2.ENDVAL = MINMAX.MAXFILLEND
order by 1, 2, 3, 4;
It shows the MINFILLSTARTand MAXFILLEND values that define the minimum and maximum fill value, but it is not always useful. Maybe "SUMFILLER" could be useful?

Edited by: CharlesRoos may 2, 2010 06:30

Edited by: CharlesRoos may 2, 2010 06:36

Edited by: CharlesRoos may 2, 2010 06:39

Edited by: CharlesRoos may 2, 2010 06:48

We can calc using expression box ;-)

col path for a30

with T as
(  --Case1 OK.
select 'Case1' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 36 FillStart, 'Month' TypeFS, 48 FillEnd, 'Month' TypeFE from dual union all
select 'Case1' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 49 FillStart, 'Month' TypeFS, 216 FillEnd, 'Month' TypeFE from dual union all
--Case2 NOT OK.
select 'Case2' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 35 FillStart, 'Month' TypeFS, 47 FillEnd, 'Month' TypeFE from dual union all
select 'Case2' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 47 FillStart, 'Month' TypeFS, 215 FillEnd, 'Month' TypeFE from dual union all
--Case3 OK.
select 'Case3' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 3 FillStart, 'Year' TypeFS, 48 FillEnd, 'Month' TypeFE from dual union all
select 'Case3' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 49 FillStart, 'Month' TypeFS, 216 FillEnd, 'Month' TypeFE from dual union all
--Case4 NOT OK.
select 'Case4' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 3 FillStart, 'Year' TypeFS, 48 FillEnd, 'Month' TypeFE from dual union all
select 'Case4' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 48 FillStart, 'Month' TypeFS, 216 FillEnd, 'Month' TypeFE from dual union all
--Case5 OK.
select 'Case5' Segment, 3 StartVal, 'Year' TypeSV, 216 EndVal, 'Month' TypeEV, 36 FillStart, 'Month' TypeFS, 48 FillEnd, 'Month' TypeFE from dual union all
select 'Case5' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 49 FillStart, 'Month' TypeFS, 216 FillEnd, 'Month' TypeFE from dual union all
--Case6 OK. OK??? I suppose this is not OK
select 'Case6' Segment, 3 StartVal, 'Year' TypeSV, 18 EndVal, 'Year' TypeEV, 36 FillStart, 'Month' TypeFS, 4 FillEnd, 'Year' TypeFE from dual union all
select 'Case6' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 61 FillStart, 'Month' TypeFS, 18 FillEnd, 'Year' TypeFE from dual union all
--Case7 NOT OK.
select 'Case7' Segment, 3 StartVal, 'Year' TypeSV, 18 EndVal, 'Year' TypeEV, 35 FillStart, 'Month' TypeFS, 4 FillEnd, 'Year' TypeFE from dual union all
select 'Case7' Segment, 36 StartVal, 'Month' TypeSV, 216 EndVal, 'Month' TypeEV, 60 FillStart, 'Month' TypeFS, 18 FillEnd, 'Year' TypeFE from dual
)
select Segment,StartVal,EndVal,sys_connect_by_path(FillStart || '->' || FillEnd,',') as path
from (select Segment,
      case TypeSV when 'Year' then 12*StartVal  else StartVal end as StartVal,
      case TypeEV when 'Year' then 12*EndVal    else EndVal end as EndVal,
      case TypeFS when 'Year' then 12*FillStart else FillStart end as FillStart,
      case TypeFE when 'Year' then 12*FillEnd   else FillEnd end as FillEnd,
      min(case TypeFS when 'Year' then 12*FillStart else FillStart end)
      over(partition by Segment) as MinFillStart,
      count(*) over(partition by Segment) as cnt
      from t)
where connect_by_IsLeaf = 1
  and (EndVal != FillEnd or  Level != cnt)
start with FillStart = MinFillStart
connect by nocycle prior Segment = Segment
               and prior FillEnd+1 = FillStart;

SEGME   STARTVAL     ENDVAL  PATH
-----  ---------  ---------  -------
Case2         36        216  ,35->47
Case4         36        216  ,36->48
Case6         36        216  ,36->48
Case7         36        216  ,35->48

Tags: Database

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