amount not uncredited
Dear Sir.
I'm recharged subscription monthly but always amount no credited amount in my account
Hello and welcome to the Skype community.
You can not understand how subscriptions work. Your account shows that you used your allocation full minutes in your current billing cycle. The distribution of your next minutes will be added to your account when your next billing cycle begins.
Renew your monthly membership before the end of the present billing cycle has no effect on the date on which your next posting of minutes is added to your account.
To continue the call until your next minutes allowance is applied to purchase an additional, but with a subscription amount different of minutes or a little Skype credit please.
Moderation of Skype unit
I recommend that you always run the latest version of Skype: Windows & Mac
If my advice helped to solve your problem, please mark it as a solution to help others.
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Tags: Skype
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PL/SQL simple report - using break on and calculation amount - not so Simple
Hello, all:
I have a simple pl/sql report which is not so simple. Based on the code below, would like to add a blank line after the line "sum" resulting to make it easier to read. Any help would be appreciated.
Thank you.
Preston@large
Code:
=======================
BREAK ON ALM_OG_CAMPAIGN_CODE
CALCULATE SUM OF THE ALM_OG_AMOUNT ON ALM_OG_CAMPAIGN_CODE
set linesize 1024
set pagesize 60
NewPage 0 value
Set serveroutput on
COIL & so_outfile;
TTITLE Center "Wayne State University" jump jump "WSU online giving Essentials Report" left 1 2
Select TO_CHAR (sysdate, ' dd/mm/yyyy hh: mm AM') 'Date of Report' of the double;
CLEAR COLUMN
ALM_OG_ACCI_CODE column header "ACCI | CODE' format a10
the title of ALM_OG_AMOUNT column ' AMOUNT '. GIFT"format $999,999,999.99
ALM_OG_CAMPAIGN_CODE column header "CAMPAIGN | CODE' format a14
Select
ALM_OG_CAMPAIGN_CODE,
ALM_OG_ACCI_CODE,
ALM_OG_AMOUNT
Of WSUALUMNI. WSU_ONLINE_GIVING_TABLE
ORDER BY ALM_OG_CAMPAIGN_CODE;
CLEAR COLUMN
/
spool off
Output:
Report on the essential online giving WSU
Date of report
======================
05/06/2009 10:06
1 selected line.
Wayne State University
Report on the essential online giving WSU
AMOUNT OF CAMPAIGN ACCI
A GIVEN CODE CODE FACT
====== ======== ==========
$ 560.00
NUR $444814 10.00
***** =======
$ 10.00
PHS $445216 10.00
***** =======
$ 10.00
ABOUT $445211 450.00
$445211 60.00
$445211 250.00
***** =======
$ 760.00
SBA $444216 10.00
***** =======
$ 10.00
SSW $444469 10.00
***** =======
$ 10.00Prestone,
Welcome to the Forum!
I have used skip 2 lines you can use 1 SQL> break on job report skip 2 SQL> compute sum of sal on job report SQL> select job , sal from emp order by job ; JOB SAL --------- ---------- ANALYST 3000 3000 ********* ---------- sum 6000 CLERK 1300 950 800 1100 ********* ---------- sum 4150 MANAGER 2850 2975 2450 ********* ---------- sum 8275 PRESIDENT 5000 ********* ---------- sum 5000 SALESMAN 1500 1250 1250 1600 ********* ---------- sum 5600 14 rows selected.
READ
Quick SQL * Plus Guide
http://download.Oracle.com/docs/CD/B14117_01/server.101/b12171/TOC.htm
SQL * more reference
http://download.Oracle.com/docs/CD/B14117_01/server.101/b12170/TOC.htmSS
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control design and simulation in a loop the final amount not what I expected
Hi the LabVIEW forum members.
I have a frame control and Simulation in which I am simulating a regulator in closed loop (see file attachment). When I apply a step of the input unit that I expected to get the answer to deposit at the unit, i.e. the stage of entry being the set point. However, he moved to about 0.625.
Can someone point me in the right direction please? I'm obviously doing something wrong here.
Kind regards
OK guys,
Cancel my last post, I found my mistake, it was the P + I control shape, I made a mistake in the Integral control action transfer function where the Integrator not arrive to integrate an error.
Kind regards
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Hi Expert,
I have a case for the value of database query. How to create the view additional attribute object where the value get database query?
parameter binding of attributeId object in view I can do this in ADF with JDeveloper 11.1.1.6.
Thank you
Kind regards
Wade W
My problem is solved, maybe it's a bug in the JDeveloper 11.1.1.6.0
I've got error (oracle.jbo.expr.JIEvalException) Houston-25077: name amount not found in the given object: oracle.jbo.server.ViewRowSetImpl@8690e3.
When I develop by tab Overview (presentation of the business components). It is so strange, because I have an another transient viewAttribute that refer to another object in view and not get an error message like this before I create viewAttribute HeaderAmount.
Maybe its ridiculous appearance, but when I go to View (lineVO.xml) object and tab to the source xml file, I have edited here. like to write
<>
Name = "HeaderAmount".
IsUpdateable = "false".
IsSelected = "false".
IsPersistent = "false".
PrecisionRule = 'true '.
Type = "Oracle.jbo.domain.Number"
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SQLType = 'DIGITAL' >
<>
Value = "ActivityHeaderId" / >
and make sure this xml file are:
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When I try to re-run the application model and it's work...
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Option of unstable lens correction
Hey dear community
I have a problem to work with FIXED OPTICS option in a specific case
In the annex, I give two screenshots of a picture of a tree
One is with correction of the goal off the coast and the other without.
What happens is, there's an arround "shadow" the Crown of the tree leave, when lens correction is enabled.
Whe I disellect the lens correction option everything is ok.
The thing turns me crazy is that I can disellect of adjustment of the optical correction of chapter and that never give the effect, this picture is correct, as the total chapter disellection.
System, I work with > > > LR5.7.1 > > Mid 2010 RAM 8GByte, OS X 10.11.2 MACBookPro > > NIKON D800 photo
Someone has a simular problem and found a solution and would like to share with me?
If something not clear, please, let me know
Thanks in advance for the help
And greetings from Frankonia
screenshort with FIXED OPTICS diactivated chapter:
screenshot with "visible shadow" chapter enabled and even lens corrections when each element is manually diactivated
Check the sliders of fringe on the lens Corrections section (Farbe) color space. Do the two sliders of sum zero. It is likely that you have applied green defringing and color range includes a little green and sky blue leaves:
The problem is maybe that you have amounts not void for the sliders fringe configured as default LR or as part of a "Preset" you apply to many images and shouldn't because defringing must be set individually for each image as a set of values does not work for all images.
If you have areas of the image that need defringing green/blue, then instead of the defringing to the entire image and parts accidentally desaturation of trees and sky, disable defringing in the region of lens Corrections and use a setting with a brush amount of fringe non-zero and the paint on the edges which really need defringing.
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How to create date of 300 + pictures of 22 min 03sec?
Hallo,
I have here a buch of photos (over 300) which are manufactured with two different cameras. Camera Booth had different configuration (difference is 22 minutes and 3 seconds). Does anyone know how to get all the images from a camera to this value?
LR can simply adjust the hours (to adjust the time zone) or change the time for a single image.
I tried ExifTool, that works well, but it moves all the time in the CR2, and not in XMP. So LR don't see this offbeat time (no not even to a new import, because CreateDate seems to read XMP (if it exists) and not from CR2 file). I can't delete the XMP because all images are marked and treated.
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Select all the photos you want changed and go to metadata > edit Capture time. Select the first option (adjust at that moment) and correct the time of 22 minutes and 3 seconds you need. All the selected photos will be shifted by the same amount, not to the absolute time that you specified. See the explanation at the top of this dialog box. Of course, you have to return the metadata in the xmp files, but this is trivial.
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Compare values between records.
Hi Experts,
Looking for your help frame a SQL for logic.
I have a table of the source with the following values of records.
EMP_NO QTR YEAR CD AMT
-----------------------------------------------------------------------
4181537 4 2011 764913.57 QR
4181537 4 2011 WC 864913.57
4181537 4 2011 WC 964913.57
4181537 4 2011 WC 964913.57
4181537 4 2011 WC 964913.57
Desired output:
EMP_NO QTR YEAR CD AMT
-----------------------------------------------------------------------
4181537 4 2011 764913.57 QR
4181537 4 2011 WC 100000.00
4181537 4 2011 WC 100000.00
4181537 4 2011 WC 0.00
4181537 4 2011 WC 0.00
Logic:
Only for the type of recording CD = WC, I need to get the value of the amount not remove with the old amount. Means,
2nd record amount would be.
864913.57 - 764913.57 = 100000.00
3rd record would be,.
964913.57 - 864913.57 = 100000.00
record of 4 th amount would be.
964913.57 - 964913.57 = 0.00
record of 5 th amount would be.
964913.57 - 964913.57 = 0.00
Can you please help me framing a SQL for this logic. Any help would be very apprecirated.
Thank you
KThis way:
with data as ( select 1 id, 4181537 no, 4 qtr, 2011 yr, 'QR' cd, 764913.57 amt from dual union all select 2, 4181537, 4, 2011, 'WC', 864913.57 from dual union all select 3, 4181537, 4, 2011, 'WC', 964913.57 from dual union all select 4, 4181537, 4, 2011, 'WC', 964913.57 from dual union all select 5, 4181537, 4, 2011, 'WC', 964913.57 from dual ) select id, no, qtr, yr, cd, amt, case when cd = 'QR' then amt when cd = 'WC' then amt - lag(amt) over (partition by no order by cd, rownum) else null end diff_amt from data; ID NO QTR YR CD AMT AMT ---------------------- ---------------------- ---------------------- ---------------------- -- ---------------------- ---------------------- 1 4181537 4 2011 QR 764913.57 764913.57 2 4181537 4 2011 WC 864913.57 100000 3 4181537 4 2011 WC 964913.57 100000 4 4181537 4 2011 WC 964913.57 0 5 4181537 4 2011 WC 964913.57 0
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Query - Gohan values in the following columns of aging
Oracle 11.2.0.3...
I have this query... working on it in SQL * Navigator.
We pay all suppliers with Net 20, 25 Net and Net 30 terms due date + 15 days. I'm developing an application that will tell me who is due now, which must be returned within next 7, then 10, then 14 and coming 21 days.
The following query returns not due, owed, due + 7, etc... but just what is due is also displayed in the + 7, + 10, etc - because if it's due, it will be always due in a week!
How can I remove these values if they are already due?
(or, if they are due in 7 days, how can I delete + 10, + 14, etc?)
SELECT
PV. $vendor_name "seller."
NPS.invoice_number "Bill."
NPS.invoice_date "Date of the invoice.
NPS.due_date "due date."
Inv.Terms "terms."
(TO_DATE (sysdate) - nps.invoice_date) "Days entries."
(CASE
When to_date (nps.due_date) < to_date (sysdate)
then (to_date (sysdate) - to_date (nps.due_date))
Another null
end) 'days overdue',
"Remaining amount", NPS.amount_remaining
--0-15
(CASE
WHEN (TO_DATE (sysdate) - nps.invoice_date) < 45
THEN nps.amount_remaining
ANOTHER NULL
END
) "Unmatured,"
(CASE
WHEN (TO_DATE (sysdate) - nps.invoice_date) > = 45
THEN nps.amount_remaining
ANOTHER NULL
END
) "Have."
(CASE
WHEN (TO_DATE (sysdate + 7) - nps.invoice_date) > = 45
THEN nps.amount_remaining
ANOTHER NULL
END
) '+ 7 days. "
(CASE
WHEN (TO_DATE (sysdate + 10) - nps.invoice_date) > = 45
THEN nps.amount_remaining
ANOTHER NULL
END
) '+ 10 days. "
(CASE
WHEN (TO_DATE (sysdate + 14) - nps.invoice_date) > = 45
THEN nps.amount_remaining
ANOTHER NULL
END
) '+ 14 days. "
(CASE
WHEN (TO_DATE (sysdate + 21) - nps.invoice_date) > = 45
THEN nps.amount_remaining
ANOTHER NULL
END
) "21 days".
Of
Inv,
PV,
NPS
WHERE
and nps.amount_remaining <>0
and inv.terms ("Net 20', ' Net 25', 'Net 30')
example of output:
Invoice date of invoice terms due Date day days entered late amount not remaining due not due 7 days + 10 days + 14 days + 21 days
seller 00470871 1 12/27/1 / 2012/2013 Net 30 12 126,62 126.62 26
provider 59355648 2 11/28/2012 12/28/2012 Net 30 41 11 538,75 538.75 538,75 538.75 538,75 538.75
the seller 3 75793062 12/4/1/3 of 2012/2013 Net 30 35 5 950 950 950 950 950
seller 4 52835 12/13/1 / 2012/2013 Net 30 26 298.92 13 298,92 298.92
seller 4 52814 12/4/1/3 of 2012/2013 Net 30 35 5 330 330 330 330 330
any sql gurus have ideas?
Published by: camforbes on January 8, 2013 13:24Hello
It's not very clear what you want, but I think something more or less like that will do what you want:
WITH got_grp AS ( SELECT pv.vendor_name , nps.invoice_number , nps.invoice_date , nps.due_date , inv.terms , SYSDATE - nps.invoice_date AS days_entered , CASE WHEN nps.due_date < SYSDATE THEN SYSDATE - nps.due_date ELSE NULL END AS days overdue , nps.amount_remaining , CASE WHEN nps.invoice_date > SYSDATE - 24 THEN 'Over 21 Days' WHEN nps.invoice_date > SYSDATE - 31 THEN '+21 Days' WHEN nps.invoice_date > SYSDATE - 35 THEN '+14 Days' WHEN nps.invoice_date > SYSDATE - 38 THEN '+7 Days' WHEN nps.invoice_date > SYSDATE - 45 THEN 'Due' ELSE 'Not Due' END AS grp FROM inv JOIN pv ON ... JOIN nps ON ... WHERE nps.amount_remaining != 0 AND inv.terms IN ('Net 20', 'Net 25', 'Net 30') ) SELECT pv.vendor_name , nps.invoice_number , nps.invoice_date , nps.due_date , inv.terms , days_entered , days overdue , CASE WHEN grp = 'Not Due' THEN amount_remianing END AS not_due , CASE WHEN grp = 'Due' THEN amount_remianing END AS due , CASE WHEN grp = '+7 Days' THEN amount_remianing END AS plus_7_days , CASE WHEN grp = '+14 Days' THEN amount_remianing END AS plus_14_days , CASE WHEN grp = '+21 Days' THEN amount_remianing END AS plus_21_days FROM got_grp ;
Whenever you have a question, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
If the results are dependent on when the query is run, give an exact time of execution, or better yet, give a couple of different run times and desired outcomes, the same sample for each data.
Explain, using specific examples, how you get these results from these data.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum {message identifier: = 9360002} -
Where am I wrong, subquery
I want 2 check which develop the amount not received order
and display the name of the provider and and the corrsponding PO_no.
I am able to get the individual totals like this;
Please any1 can correct the above querypurchase Ordered QTY select SUPL_name, POh_no, sum(POd_qty) POqty from PURCHASE_order_header,PURCHASE_order_detail,SUPPLIER_master where POh_code = POd_POh_code and POh_no = POd_POh_no and POh_party_code = SUPL_code group by SUPL_name, POh_no; SUPL_NAME POH_NO POQTY ------------------------------ ---------- ---------- SUPL 3 1 85 SUPL 2 2 200 SUPL 5 3 170 Goods Received QTY select SUPL_name, GRNh_PO_no, sum(GRND_QTY_RECEIVED) GRNqty from GRN_TXN_header,GRN_TXN_detail,SUPPLIER_master where GRNh_code = GRNd_GRNh_code and GRNh_no = GRNd_GRNh_no and GRNh_party_code = SUPL_code group by SUPL_name, GRNh_PO_no; SUPL_NAME GRNH_PO_NO GRNQTY ------------------------------ ---------- ---------- SUPL 3 1 70 SUPL 2 2 130 i want to make a query that would calculate the balqty (po_qty - grnqty) and if greater than 0, then the query should return the supl_name, po_no, balqty in this fashion SUPL_NAME POH_NO balQTY ------------------------------ ---------- ---------- SUPL 3 1 15 SUPL 2 2 70 SUPL 5 3 170 i tried something like this, but i dont know the query did not return the balqty (170) for supl5, poh_no 3; SQL> select h.SUPL_name, h.POh_no, (h.Poqty-d.GRNqty) balqty 2 from ( 3 select SUPL_name, POh_no, sum(POd_qty) POqty 4 from PURCHASE_order_header,PURCHASE_order_detail,SUPPLIER_master 5 where POh_code = POd_POh_code 6 and POh_no = POd_POh_no 7 and POh_party_code = SUPL_code 8 group by SUPL_name, POh_no) h, 9 ( 10 select SUPL_name, GRNh_PO_no, sum(GRND_QTY_RECEIVED) GRNqty 11 from GRN_TXN_header,GRN_TXN_detail,SUPPLIER_master 12 where GRNh_code = GRNd_GRNh_code 13 and GRNh_no = GRNd_GRNh_no 14 and GRNh_party_code = SUPL_code 15 group by SUPL_name, GRNh_PO_no) d 16 WHERE h.poh_no = d.grnh_po_no(+); SUPL_NAME POH_NO BALQTY ------------------------------ ---------- ---------- SUPL 3 1 15 SUPL 2 2 70 SUPL 5 3 <-- ??
TYVM(h.Poqty-nvl (d.GRNqty, 0))
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If I want to get the sum of the positive and negative values, can I do it like this?
Negative:
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If this is not the case, how should I go about this?Select sum(amount) INTO positive_amt FROM order where amount not like '%-%';
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I did not purchase request how the amount is deducted from my account without my knowledge
Hello
1. I did not purchase request how the amount is deducted from my account without my knowledge. I ask you to return the amount to my account
2. you download the free app and I have not purchased the app, I didn't purchase was deducted without my knowledge
3. I ask you to bring the amount in my account and I will sue you to withdraw money from my account without my knowledge
< re-titled by host >
Maybe it's authorization is to identify yourself, the money will be in a few days.
Read here: on the payment card's authorization in the iTunes Store - Apple Support
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This has nothing to do with memory - it's the SSD. Word tries to create a temporary file to use as a backup if the program crashes while you are working. First, run the Microsoft Update program to see if there are updates you have missed. Second, Microsoft currently supports only versions 2011 and 2016, so if yours is older, you should consider the upgrade. Thirdly, I suspect that the temporary file is not get created so that you have fewer cancellations (maybe any) and that if the program crashes you have to restore.
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I have a LARGE amount of files music .m4a in a storage drive stand alone that I downloaded from an old Apple computer have more possession of. I can't understand how to enter these data into my old Emachines computer Windows Vista run the Media Player program. I tried to copy a few files m4a manually in the file Media Player Music folder, but they do not play. I'm not really all that computer savvy and know only the basics, I need to use my computer really. Can you give me some step by step instructions how to get these converted files or whatever it is I need to do to get them to play and to integrate properly into my library if it is possible? If this isn't the case, I'll have to go out and buy a new Apple computer for my 60 GB music collection. In the past, that I've never had no real problem shooting files to leave this computer based Vista and convert these files to my old computers Apple Itunes Player. So what's the problem with your system of guys that done anyway this such a pain in the butt? I would really like to understand what exactly is happening with this issue? It's very frustrating for me. I'm a finish Carpenter not a computer programmer. Such things should not be so difficult for someone like me to understand. All I intend to buy a really nice computer, probably in the summer and was considering a Microsoft based computer. But if this kind of problem will be spread with Microsoft products, so maybe I should reconsider. help you can offer to alleviate this problem will be greatly appreciated.
Thank you
Signed;
Tim M. from Detroit.According to research on the Internet, Windows Media Player, atleast this is version 11 (included in Windows Vista and available for Windows XP SP2 +) cannot play Apple loseless type .m4a audio files without having to install any codecs.
If you want to use Windows Media Player, you can follow the instructions mentioned here to install the necessary codecs and plugins.
(In the related instructions above, in the first step talks about codecs - your .m4a files are files Apple loseless then follow the party referred to in the first stage about Apple loseless .m4a)
Personally, I prefer using alternatives to Windows Media Player rather than installing codec packs.
If you don't want to install codecs, download no matter what media player from "programs that open. M4A files"- Windows category list on this page.
If you use a spare player - VLC Media Player is my choice.
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It was OK. Do you see the 1.7 GB? 4.0 - 1, 7 = 2.3 GB you see in a 32-bit Windows. So to learn more, use the Vista 64-bit. "A programmer is just a tool that converts the caffeine in code" Deputy CLIP - http://www.winvistaside.de/
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Thank you
Original title: Maximum file transfer
Hi Chad,
Thanks for posting the question in the Microsoft Community forums.
Looks like you need more information on the transfer of the files of more than 80 k to external devices.
1. have you tried to send files over 40 k?
2. What is the brand and model of the computer?
There is no practical limitation on the number of files that can be transferred from one computer to external devices. Although there is no file transfer limit depends on several factors, first externally you use, the memory of the computer file system if it can retain enormous transfer rates.
Hope this information helps. Get back to us if you have more queries about Windows.
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