Analytical function in Oracle
I have a situation where I partitioned a Recordset. If in one partition on this recordset, the value of a field (field name registered) is '45' I need to order the result of this partition by - "outdate" desc "this provision" desc and order the other partition of desc 'key',' sequence ' desc, desc "outdate."If the query looks like to.
Select row_number() over (partition by the order of the keys in sequence) RowNo, key, seq, status, outdate, receivedate from table1 where...
order by?
RowNo status outdate Seq key provision
1 200 0 24 9/13 / 2009 12/9/2009
2 200 1 23 9/10 / 2009 9/09/2009
3 200 2 24 9/09 / 2009 9/08/2009
1 210 0 24 9/13 / 2009 12/9/2009
2 210 1 * 45 * 9/09/2009-9/08/2009
3 210 2 24 9/10 / 2009 9/09/2009
So I need to get the query that will order the first series of partition by desc 'key',' order ' desc, desc "outdate" and the second set of partition (because the status of '45' exists in the second partition) by "outdate" desc "this provision" desc.
The output of the query should look like
RowNo status outdate Seq key provision
1 200 0 24 9/13 / 2009 12/9/2009
2 200 1 23 9/10 / 2009 9/09/2009
3 200 2 24 9/09 / 2009 9/08/2009
1 210 0 24 9/13 / 2009 12/9/2009
2 210 2 24 9/10 / 2009 9/09/2009
3 210 1 * 45 * 9/09/2009-9/08/2009
I don't know if this is possible using the analytical function.
I would appreciate if any can help me with that.
Thanks in advance
Hello
Welcome to the forum!
You can use analytical functions in the ORDER BY clause.
I do not have your tables, so I'll use scott.emp to illustrate.
The following query sorts first by deptno. After this, the sort order for the departments that contain at least one seller is:
b job
(b) ename
DEPTNO = 30 is be the only Department with a seller, so it's the only sorting as shown above.
Other departments will be sorted by
(a) sal
(b) job
SELECT deptno
, ename
, job
, sal
FROM scott.emp
ORDER BY deptno
, CASE
WHEN COUNT ( CASE
WHEN job = 'SALESMAN'
THEN 1
END
) OVER (PARTITION BY deptno) > 0
THEN ROW_NUMBER () OVER ( PARTITION BY deptno
ORDER BY job
, ename
)
ELSE ROW_NUMBER () OVER ( PARTITION BY deptno
ORDER BY sal
, job
)
END
;
Output:
. DEPTNO ENAME JOB SAL
---------- ---------- --------- ----------
10 MILLER CLERK 1300
10 CLARK MANAGER 2450
10 KING PRESIDENT 5000
20 SMITH CLERK 800
20 ADAMS CLERK 1100
20 JONES MANAGER 2975
20 SCOTT ANALYST 3000
20 FORD ANALYST 3000
30 JAMES CLERK 950
30 BLAKE MANAGER 2850
30 ALLEN SALESMAN 1600
30 MARTIN SALESMAN 1250
30 TURNER SALESMAN 1500
30 WARD SALESMAN 1250
The small set of sample data you posted, the results you want can be achieved simply through
ORDER BY key
, outdate DESC
I guess it's just a coincidence.
If you need help, post some examples of data that requires really looking at the status column to get good results. Display the data in executable form, such as CREATE TABLE and the instructions INSERT, olr, as Salim, a WITH clause. (Maybe you can simply add or change a couple of lines in the example Salim already posted data).
Tags: Database
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Which analytical function to use?
Hi gurus,DB - Oracle 11 g 2
I followed the examples of data in the table test_a.
col1 col2 col3
----- ------- --------
x y y
p q y
a b y
p q y
t r y
p q y
The col3 column is always 'y '. But here's the data p, q, there is repeated 3 times (duplicate) and if this is the case I want to update only the first recordings like "n" col3 it is to say p, q, n. rest will be as it is.
I am able to get the row_number() for it but not able to do this.
Select col1, clo2, clo3 row_number() over (partition by col2) arrested by col1 as test_a r_num
Would it be possible directly by any analytic function?
Thank you
SID
COL4 is logical...
Something like that?
with x as)
Select col1, col2 ' x' 'y', 'y' col3 col4 1 Union double all the
Select 'p' col1, col2 'q', 'y' col3 col4 2 Union double all the
Select 'a' col1, col2 'b', 'y' col3 col4 3 of all the double union
Select 'p' col1, col2 'q', 'y' col3 col4 4 Union double all the
Select 't' col1, col2 'r', 'y' col3, col4 5 Union double all the
Select 'p' col1, col2 'q', 'y' col3 col4 6 double
)
---
Select * from)
Select x.*,
ROW_NUMBER() on rn1 (score of col1, col2, col3 col4 sort),
ROW_NUMBER() on rn2 (partition by col1, col2, col3 col4 desc sorting)
x
)
where rn1 = 1 and rn2 <> 1;
Understand the logic and simply change SELECT a query to UPDATE...
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Oracle 11g Release 2
I'm assuming that the best solution is the use of analytical functions.
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Post edited by: orclrunner was updated desired output and rule
Hello
Here's one way:
WITH got_d_count AS
(
SELECT part_type_id, group_id, part_desc_id
MIN (part_cmt) AS min_part_cmt
COUNT AS d_count (*) OVER (PARTITION BY part_type_id)
OF test3
GROUP BY part_type_id, group_id, part_desc_id
)
SELECT DISTINCT
group_id, part_desc_id, part_type_id, min_part_cmt
OF got_d_count
WHERE d_count > 1
;
Output:
GROUP_ID PART_DESC_ID MIN_PART_CMT PART_TYPE_ID
------------ ---------- ------------ ------------
ABC123 1 10 comment1
ABC123 2 15 comment1
XYZ123 1 10 comment6
XYZ123 2 15 comment7
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Analytical functions: FIRST vs FIRST_VALUE
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Say you want the average sal for each Department, but only for the first year (taken from the hiredate column) in the Department (i.e., the column called f in the query below).
WITH got_hireyear AS
(
SELECT deptno and ename, sal, hiredate
EXTRACT (YEAR FROM hiredate) AS hireyear
FROM scott.emp
)
SELECT deptno, hireyear, hiredate, ename, sal
AVG (sal) DUNGEON (DENSE_RANK FIRST ORDER BY hireyear)
COURSES (PARTITION BY deptno
) In the FORM f
FIRST_VALUE (sal) over (PARTITION BY deptno
ORDER BY hireyear
) AS fv
AVG (sal) over (PARTITION BY deptno
hireyear
), A
OF got_hireyear
ORDER BY deptno
hireyear
ename
;
Output:
HIREYEAR ENAME SAL HIREDATE DEPTNO F FV HAS
------ ---------- ----------- ---------- ------ --------- ------ ---------
10 1981 9 June 1981 CLARK 2450 2450 3725,00 3725.00
10 1981 17 November 1981 KING 5000 3725,00 2450 3725.00
10 1982 23 January 1982 MILLER 1300 3725,00 2450 1300.0020, 1980, 17 December 1980 SMITH 800 800.00 800.00 800
20, 1981, 3 December 1981 FORD 3000 800.00 800 2987.50
20, 1981, 2 April 1981 JONES 2975 800.00 800 2987.50
20, 1987, 23 May 1987 ADAMS 1100 800.00 800 2050.00
20, 1987, 19 April 1987 SCOTT 3000 800.00 800 2050.0030 1981 20 February 1981 ALLEN 1600 1566.67 950 1566.67
May 30 1981 1st 1981 BLAKE 2850 1566.67 950 1566.67
December 30 1981 3 1981 JAMES 950 1566.67 950 1566.67
30 1981 28 - sep - 1981 MARTIN 1250 1566.67 950 1566.67
30-08 - sep - 1981 1981 TURNER 1500 1566.67 950 1566.67
30 1981 22 February 1981 WARD 1250 1566.67 950 1566.67The analytical FIRST_VALUE function can do (except in the very special case where only 1 row has the lowest hireyear, as in deptno = 20). AVG analysis can do (except in the very special case that all lines have the same hireyear as in deptno = 30).
-
Hello experts.
I have data similar to what follows below
create table t1 ( id number(30), description varchar(4000) ); insert into t1 values (1, 'zone'); insert into t1 values (2, 'small'); create table t2 ( id number(30), place varchar(4000), info varchar(4000) ); insert into t2 values (1, 'USA', 'Class U'); insert into t2 values (1, 'Mexico', 'Class M'); insert into t2 values (2, 'Germany', 'Class G');
I need help with something similar to what follows below without using any analytic function
Description of the ID info Place
1 box USA class U
Mexico 1 M class
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Hello
user13328581 wrote:
... I use an older version of oracle. Oracle 7.
Normally, your developers are older than your software.
You should be able to do what you want with a self-join on t2; a copy (d) should be displayed, and the other copy (c) contains all related values you need for comparison.
SELECT t2d.id
DECODE (t2d.place
MAX (t2c.place)
t1.description
) AS description
t2d.place
t2d.info
FROM t1
, t2 t2d - display
t2 t2c - compare
WHERE t1.id = t2d.id
AND t2d.id = t2c.id
GROUP BY t1.description
t2d.id
t2d.place
t2d.info
ORDER BY t2d.id
t2d.place DESC
;
Output:
ID DESCRIPTION PLACE INFO
---------- -------------------- -------------------- --------------------
1 box USA class U
Mexico 1 M class
2 small Germany class G
I've tested this in Oracle 11, but it should work in Oracle 7.
If this isn't the case, you may need to create a view.
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Hello
I have two tables b rates and transactions (b).
For each b.FS, I want to know new amount (b.amt time a.rate to the corresponding line of FS b and if a.na is valid based on the flag of the exclusion and the interval defined in the table's).
It is much easier to explain with an example.
So here we go...
Exclude_flag = E (exclude): for b.fs = 433638, b.na = 80000. I have 2 lines in the table for this fs. Both have E exclude_flag (exclude). I want to go on all the lines in this FS in the table in a query and I return only one row in the result, if and only if b.na falls out of scope of a.na_min_value and a.na_max_values. In this example, it falls outside the range excluded for both lines (first two lines of the table a).
Similarly, exclude_flag = I (Include). for b.fs = 432828, b.na = 17200. I have 2 lines in the table for this fs. Both have an exclude_flag of I (include). I want to go on all the lines in this FS in the table in a query and I return only one row in the result, if and only if b.na is between a.na_min_value and a.na_max_values. In this example, it falls in the range of both the range include for the two lines (line 6 and 7 of the table a).
The following query gives me two lines for each b.fs. It is possible to get what I'm looking for simply using sql (possibly write the analytical function?) or I have to write the pl/sql routine for this?
WITH rates_table
Did YOU (select ' E' include_exclude_flag, "81000 ' na_min_value, na_max_value '81999', '433638' FS, 0.8 of double rate
UNION
Select 'E' include_exclude_flag, na_min_value '84000', na_max_value '84999', '433638' FS, 0.8 of double rate
UNION
Select 'I' include_exclude_flag, na_min_value '12000', na_max_value '12999', '432828' FS, rate 0.25 double
UNION
Select 'I' include_exclude_flag, na_min_value '13000', na_max_value '13999', '432828' FS, rate 0.25 double
UNION
Select 'I' include_exclude_flag, na_min_value '15000', na_max_value '15000', '432828' FS, rate 0.25 double
UNION
Select 'I' include_exclude_flag, na_min_value '16100', na_max_value '18000', '432828' FS, rate 0.25 double
UNION
Select 'I' include_exclude_flag, '17100' na_min_value, na_max_value '18000', '432828' FS, rate 0.25 double
UNION
Select 'I' include_exclude_flag, na_min_value '02440', na_max_value '02470', '016532' FS, 0.35 rate double
UNION
Select 'E' include_exclude_flag, na_min_value ' 21000 ', '21000' na_max_value, ' 200020' FS, 0.35 double rate).
transaction_table AS
(select '433638' FS '80000' NA, 300 double amt)
Union
Select '432828' FS '17200' NA, amt 500 double
)
Select * from rates_table a, transaction_table b
where 1 = 1
and ((b.na PAS entre a.na_min_value et a.na_max_value et a.include_exclude_flag = «E») GOLD ())
b.na between a.na_min_value and a.na_max_value and a.include_exclude_flag = 'I'))
and b.fs = a.fs
;
Any help is greatly appreciated. I use oracle 11i
@OP,
For this kind of problems, we get the number of rows that satisfy the required conditions or who do not meet the required conditions. And then eliminate the line that should be eliminated.
As below, I calculate four counts (number of join lines)
EOBCNT - excluded and Out of Bound
EIBCNT - excluded and in the limit
IOBCNT - included and Out of Bound
IIBCNT - included and within the limits
Once those are calculated, simply return the lines that have EIBCNT and IOBCNT are zero.
For Ex:
> WITH
rates_table
AS LONG AS)
Select 'E' include_exclude_flag, na_min_value '79999', na_max_value '79999', '433638' FS, 0.8 double UNION rates
-Select 'E' include_exclude_flag, na_min_value ' 79999', na_max_value '80000', '433638' FS, 0.8 double UNION rate - TEST - THE
-If you uncomment the last line and then 433638 will not be returned
Select 'E' include_exclude_flag, "81000 ' na_min_value, na_max_value '81999', '433638' FS, 0.8 double UNION rates
Select 'E' include_exclude_flag, na_min_value '84000', na_max_value '84999', '433638' FS, 0.8 double UNION rates
Select 'I' include_exclude_flag, na_min_value '12000', na_max_value '12999', '432828' FS, 0.25 rate double UNION
Select 'I' include_exclude_flag, na_min_value '13000', na_max_value '13999', '432828' FS, 0.25 rate double UNION
Select 'I' include_exclude_flag, na_min_value '15000', na_max_value '15000', '432828' FS, 0.25 rate double UNION
Select 'I' include_exclude_flag, na_min_value '16100', na_max_value '18000', '432828' FS, 0.25 rate double UNION
Select 'I' include_exclude_flag, '17100' na_min_value, na_max_value '18000', '432828' FS, 0.25 rate double UNION
Select 'I' include_exclude_flag, na_min_value '02440', na_max_value '02470', '016532' FS, 0.35 rate double UNION
Select 'E' include_exclude_flag, na_min_value ' 21000 ', '21000' na_max_value, ' 200020' FS, 0.35 double rate).
transaction_table AS
(select '433638' FS '80000' NA, amt 300 Union double
Select '432828' FS '17200' NA, amt 500 double
)
getcnts as)
SELECT a.*
b.na, b.amt
, sum (case when (b.na NOT BETWEEN a.na_min_value)
AND a.na_max_value
AND a.include_exclude_flag = 'E '.
end) then 1 else 0) on (a.fs partition) Eobcnt
, sum (case when (b.na NOT BETWEEN a.na_min_value)
AND a.na_max_value
AND a.include_exclude_flag = 'I '.
end) then 1 else 0) on (a.fs partition) Iobcnt
, sum (case when (b.na BETWEEN a.na_min_value)
AND a.na_max_value
AND a.include_exclude_flag = 'E '.
end) then 1 else 0) on (a.fs partition) Eibcnt
, sum (case when (b.na BETWEEN a.na_min_value)
AND a.na_max_value
AND a.include_exclude_flag = 'I '.
end) then 1 else 0) on (a.fs partition) Iibcnt
OF rates_table one
transaction_table b
WHERE b.fs = a.fs
)
getrows as)
Select x.*, row_number() on
(partition by order of fs with null desc) getcnts rn x
where IOBCNT = 0 and eibcnt = 0 - remove lines that are not needed (IF and ONLY if)
)
Select * from getrows
where rn = 1 - to limit a SINGLE row (arbitrarily)
INCLUDE_EXCLUDE_FLAG NA_MIN_VALUE NA_MAX_VALUE FS RATE NA AMT EOBCNT IOBCNT EIBCNT IIBCNT RN
-------------------- ------------ ------------ ------ ---------- ----- ---------- ---------- ---------- ---------- ---------- ----------
433638 84999 84000.8 E 80000 300 3 0 0 0 1
I hope this helps.
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Order of evaluation of analytic function
Hello
have question quite like this:
with
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acct_repres as
(
Select distinct acct_id, origin_id, acct_parm_id of
(
Select a.*
source_id
, dense_rank() over (partition by order source_id by nulls first, acct_id acct_nbr origin_id) as odr
account a join account_parm on (a.parm_id = ap.acct_parm_id) ap
)
where odr = 1
)
Select col1
col2
, (select accct_id from ar acct_repres where ar.acct_parm_id = t2.acct_parm_id) col3
, col4 (select count (1) of acct_repres)
of une_table t1
Join other_table t2 on (...)
And here it is. "Acct_repres" subquery returns more than 300 lines when it is run separately. But when it is used in CTE sometimes (depending on the execution plan) she seems to have that one line - the value in the column col4 is '1 ',.
While the value of col3 is NULL for most of the cases.
It looks like the the dense_rank function and the State 'where odr = 1' are evaluated at the end.
When I use the hint to MATERIALIZE the result was the same.
But when I put the result of account_repres in the dedicated table and use this table instead of CTE output is correct.
What is a bug? Or I do something wrong?
PS: my version of db is 11 GR 1 material (11.1.0.7).
some unorganized comments:
-analytical functions are evaluated towards the end of the execution ("' the last set of operations performed in a query with the exception of the final
ORDER
BY
clause"- http://docs.oracle.com/cd/E11882_01/server.112/e26088/functions004.htm")-but still the result of a SQL query must be deterministic, so I think that your results are not an expected behavior
-the CBO has some problems with common table expressions (http://jonathanlewis.wordpress.com/2012/05/24/subquery-factoring-7/) if they are of great assistance in the structuring of complex queries. In these cases, you can avoid problems by using inline views
-Your query uses the common table expressions in scalar subqueries and scalar subqueries are also likely to confuse the CBO. In addition, they are executed once for each row in your result set (or at least for each different correlation value) and can have a negative impact on the performance of the queries in many cases. Often, they can be replaced by outer joins.
-you say that the suspicion of materialization brings you an erroneous result: the indicator object (online) gives you the correct results?
Concerning
Martin Preiss
-
Return one row of an analytic function
Hello
I pulled the following query:
Select ID_STORNO, first_value (COD_CONTATTO) ON (Partition of COD_CONTATTO
order of COD_PRIORITY asc, desc FT_DAT_OPEN_CNT
rows between unbounded preceding and following unbounded)
as COD_CONTATTO_LAST
of WT_STR_ESG_CONTATTO;
The result is:
2160603 C1-H83J1N 2160603 C8-9FOHXJS 2258072 C1-H83J1N But I just need to take the following lines
2160603 C8-9FOHXJS 2258072 C1-H83J1N Because for the same value of ID_STORNO, I just need to get a value of COD_CONTATTO (to select the best value using COD_PRIORITY and FT_DAT_OPEN_CNT). What is wrong inside the query? I just use 2 or 3 times the oracle analytic functions.
Best regards
As SomeoneElse... you need a where clause clause in order to choose the ones you want.
To do this, the typical is to select a column that you use for this reason, such as:
"I want to just the first record in each group..."
Select id_storno, cod_contatto_last from)
Select ID_STORNO, first_value (COD_CONTATTO) ON (Partition of COD_CONTATTO
order of COD_PRIORITY asc, desc FT_DAT_OPEN_CNT
rows between unbounded preceding and following unbounded)
as COD_CONTATTO_LAST,
ROW_NUMBER() OVER (Partition of COD_CONTATTO
order of COD_PRIORITY asc, desc FT_DAT_OPEN_CNT
rows between unbounded preceding and following unbounded)
as rnum
of WT_STR_ESG_CONTATTO
)
where rnum = 1
/
I prefer to use rownumber in this case, so I always have a rnum = 1...
Usually, you must use the same partition/command by as your other folders (it is usually a good idea... maybe not, depending on your needs, however)
-
I have records that a load dates repeat.
I would like to return records with the maximum load_dates.
My data source looks like this-
(select 60589 as C_number, to_date('01/08/2012','DD/MM/YYYY') as load_dt of all the double union)
Select 60768, to_date('01/08/2012','DD/MM/YYYY') of all the double union
Select 60888, to_date('01/08/2012','DD/MM/YYYY') of all the double union
Select 12345, to_date('01/09/2012','DD/MM/YYYY') of all the double union
Select 54321, to_date('01/09/2012','DD/MM/YYYY') of all the double union
Select 66666, to_date('01/10/2012','DD/MM/YYYY') of all the double union
Select 55555, double to_date('01/10/2012','DD/MM/YYYY'))
;
I would like to return records with the max load_dt which means
C_number load_dt
666666 1 October 12
555555 1 October 12
I wrote an analytical function of the oracle, but it does not work as it should be-
My query looks like this-
Select a.*
Of
(
Select
c_number,
load_dt,
Max (load_dt) more (load_dt partition) as mx_dt
from table_name
)
where
load_dt = mx_dt;
It returns all the lines for some reason any.
Any help or advice is much appreciated
PJmax(load_dt) over (partition by load_dt) as mx_dt
should be
max(load_dt) over () as mx_dt
If you want the maximum all the records, otherwise your was just the maximum per load_dt partition (think of partitions as being groups of data)
-
Purpose of the ORDER BY clause in the analytic function Min Max
I was always using analytical functions like Min Max without ORDER BY clause. But today I used with the ORDER BY clause. The results are very different. I would like to know the purpose of the ORDER BY clause in Min, Max and analogues of analytical functions.user10566312 wrote:
I was always using analytical functions like Min Max without ORDER BY clause. But today I used with the ORDER BY clause. The results are very different. I would like to know the purpose of the ORDER BY clause in Min, Max and analogues of analytical functions.It is a good point that many developers are not so aware. As far as I understand it the way it works.
Some analytical functions do not need an order by or windowing clause (SUM, COUNT, MIN, etc.). If there is no specified window, then the full score is the window.
As soon as you add a command also add you a windowing clause. This window has the default value of 'rank ofrowsbetween unbounded preceding and current_row. So as soon as you add an order by clause, you get a sliding window.Documentation: http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions001.htm
windowing_clause
...
You cannot specify this clause unless you specified the order_by_clause. Window limits defined by the clause RANGE you can not specify only a single expression to the > order_by_clause. Please refer to 'Restrictions on the ORDER BY Clause'.example of
with testdata as (select 10 numval, level lv from dual connect by level < 10) select lv, numval, sum(numval) over () sum1, sum(numval) over (order by lv) sum2 from testdata; LV NUMVAL SUM1 SUM2 -- ------ ---- ---- 1 10 90 10 2 10 90 20 3 10 90 30 4 10 90 40 5 10 90 50 6 10 90 60 7 10 90 70 8 10 90 80 9 10 90 90
Published by: Sven w. on 25 Sep 2012 16:57 - default behavior has been corrected. Thanks to Chris
-
Problem with analytical function for date
Hi all
ORCL worm:
Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit Production
PL/SQL Release 11.2.0.2.0 - Production
"CORE 11.2.0.2.0 Production."
AMT for Linux: Version 11.2.0.2.0 - Production
NLSRTL Version 11.2.0.2.0 - Production
I have a problem with the analtical for the date function. I'm trying to group records based on timestamp, but I'm failing to do.
Could you please help me find where I'm missing.
THXThis is the subquery. No issue with this. I'm just posting it for reference. select sum(disclosed_cost_allocation.to_be_paid_amt) amt, substr(reference_data.ref_code,4,10) cd, to_char(external_order_status.status_updated_tmstp, 'DD-MON-YYYY HH24:MI:SS') tmstp, DISCLOSED_CLOSING_COST.DISCLOSED_CLOSING_COST_ID id FROM Deal.Fee_Mapping_Definition , Deal.Fee_Index_Definition , Deal.Fee_Closing_Cost_Item, Deal.Closing_Cost, Deal.Document_Generation_Request, deal.PRODUCT_REQUEST, deal.External_Order_Request, deal.External_Order_Status, deal. DISCLOSED_CLOSING_COST, deal.DISCLOSED_COST_ALLOCATION, deal.reference_data WHERE Fee_Mapping_Definition.Fee_Code = Fee_Index_Definition.Fee_Code AND Fee_Index_Definition.Fee_Index_Definition_Id = Fee_Closing_Cost_Item.Fee_Index_Definition_Id AND Fee_Closing_Cost_Item.Closing_Cost_Id = Closing_Cost.Closing_Cost_Id AND CLOSING_COST.PRODUCT_REQUEST_ID = Document_Generation_Request.Product_Request_Id AND closing_cost.product_request_id = product_request.product_request_id AND Product_Request.Deal_Id = External_Order_Request.Deal_Id AND external_order_request.external_order_request_id = external_order_status.external_order_request_id AND external_order_request.external_order_request_id = disclosed_closing_cost.external_order_request_id AND DISCLOSED_CLOSING_COST. DISCLOSED_CLOSING_COST_ID = DISCLOSED_COST_ALLOCATION.DISCLOSED_CLOSING_COST_ID AND Fee_Index_Definition.Fee_Index_Definition_Id = Disclosed_Closing_Cost.Fee_Index_Definition_Id AND Fee_Mapping_Definition.Document_Line_Series_Ref_Id = Reference_Data.Reference_Data_Id AND Document_Generation_Request.Document_Package_Ref_Id IN (7392 ,2209 ) AND External_Order_Status.Order_Status_Txt = ('GenerationCompleted') AND Fee_Mapping_Definition.Document_Line_Series_Ref_Id IN ( 7789, 7788,7596 ) AND FEE_MAPPING_DEFINITION.DOCUMENT_TYPE_REF_ID = 1099 AND Document_Generation_Request.Product_Request_Id IN (SELECT PRODUCT_REQUEST.PRODUCT_REQUEST_id FROM Deal.Disclosed_Cost_Allocation, Deal.Disclosed_Closing_Cost, DEAL.External_Order_Request, DEAL.PRODUCT_REQUEST, Deal.Scenario WHERE Disclosed_Cost_Allocation.Disclosed_Closing_Cost_Id = Disclosed_Closing_Cost.Disclosed_Closing_Cost_Id AND Disclosed_Closing_Cost.External_Order_Request_Id = External_Order_Request.External_Order_Request_Id AND External_Order_Request.Deal_Id = Product_Request.Deal_Id AND product_request.scenario_id = scenario.scenario_id AND SCENARIO.SCENARIO_STATUS_TYPE_REF_ID = 7206 AND product_request.servicing_loan_acct_num IS NOT NULL AND product_request.servicing_loan_acct_num = 0017498379 --AND Disclosed_Cost_Allocation.Disclosed_Cost_Allocation_Id = 5095263 ) GROUP BY DISCLOSED_CLOSING_COST.DISCLOSED_CLOSING_COST_ID, External_Order_Status.Status_Updated_Tmstp, Reference_Data.Ref_Code, disclosed_cost_allocation.to_be_paid_amt order by 3 desc, 1 DESC; Result: 2000 1304-1399 28-JUL-2012 19:49:47 6880959 312 1302 28-JUL-2012 19:49:47 6880958 76 1303 28-JUL-2012 19:49:47 6880957 2000 1304-1399 28-JUL-2012 18:02:16 6880539 312 1302 28-JUL-2012 18:02:16 6880538 76 1303 28-JUL-2012 18:02:16 6880537 But, when I try to group the timestamp using analytical function, select amt ,cd ,rank() over(partition by tmstp order by tmstp desc) rn from (select sum(disclosed_cost_allocation.to_be_paid_amt) amt, substr(reference_data.ref_code,4,10) cd, to_char(external_order_status.status_updated_tmstp, 'DD-MON-YYYY HH24:MI:SS') tmstp, DISCLOSED_CLOSING_COST.DISCLOSED_CLOSING_COST_ID id FROM Deal.Fee_Mapping_Definition , Deal.Fee_Index_Definition , Deal.Fee_Closing_Cost_Item, Deal.Closing_Cost, Deal.Document_Generation_Request, deal.PRODUCT_REQUEST, deal.External_Order_Request, deal.External_Order_Status, deal. DISCLOSED_CLOSING_COST, deal.DISCLOSED_COST_ALLOCATION, deal.reference_data WHERE Fee_Mapping_Definition.Fee_Code = Fee_Index_Definition.Fee_Code AND Fee_Index_Definition.Fee_Index_Definition_Id = Fee_Closing_Cost_Item.Fee_Index_Definition_Id AND Fee_Closing_Cost_Item.Closing_Cost_Id = Closing_Cost.Closing_Cost_Id AND CLOSING_COST.PRODUCT_REQUEST_ID = Document_Generation_Request.Product_Request_Id AND closing_cost.product_request_id = product_request.product_request_id AND Product_Request.Deal_Id = External_Order_Request.Deal_Id AND external_order_request.external_order_request_id = external_order_status.external_order_request_id AND external_order_request.external_order_request_id = disclosed_closing_cost.external_order_request_id AND DISCLOSED_CLOSING_COST. DISCLOSED_CLOSING_COST_ID = DISCLOSED_COST_ALLOCATION.DISCLOSED_CLOSING_COST_ID AND Fee_Index_Definition.Fee_Index_Definition_Id = Disclosed_Closing_Cost.Fee_Index_Definition_Id AND Fee_Mapping_Definition.Document_Line_Series_Ref_Id = Reference_Data.Reference_Data_Id AND Document_Generation_Request.Document_Package_Ref_Id IN (7392 ,2209 ) AND External_Order_Status.Order_Status_Txt = ('GenerationCompleted') AND Fee_Mapping_Definition.Document_Line_Series_Ref_Id IN ( 7789, 7788,7596 ) AND FEE_MAPPING_DEFINITION.DOCUMENT_TYPE_REF_ID = 1099 AND Document_Generation_Request.Product_Request_Id IN (SELECT PRODUCT_REQUEST.PRODUCT_REQUEST_id FROM Deal.Disclosed_Cost_Allocation, Deal.Disclosed_Closing_Cost, DEAL.External_Order_Request, DEAL.PRODUCT_REQUEST, Deal.Scenario WHERE Disclosed_Cost_Allocation.Disclosed_Closing_Cost_Id = Disclosed_Closing_Cost.Disclosed_Closing_Cost_Id AND Disclosed_Closing_Cost.External_Order_Request_Id = External_Order_Request.External_Order_Request_Id AND External_Order_Request.Deal_Id = Product_Request.Deal_Id AND product_request.scenario_id = scenario.scenario_id AND SCENARIO.SCENARIO_STATUS_TYPE_REF_ID = 7206 AND product_request.servicing_loan_acct_num IS NOT NULL AND product_request.servicing_loan_acct_num = 0017498379 --AND Disclosed_Cost_Allocation.Disclosed_Cost_Allocation_Id = 5095263 ) GROUP BY DISCLOSED_CLOSING_COST.DISCLOSED_CLOSING_COST_ID, External_Order_Status.Status_Updated_Tmstp, Reference_Data.Ref_Code, disclosed_cost_allocation.to_be_paid_amt order by 3 desc, 1 DESC); Result: 312 1302 1 2000 1304-1399 1 76 1303 1 312 1302 1 2000 1304-1399 1 76 1303 1 Required output: 312 1302 1 2000 1304-1399 1 76 1303 1 312 1302 2 2000 1304-1399 2 76 1303 2
Rod.Hey, Rod,
My guess is that you want:
, dense_rank () over (order by tmstp desc) AS rn
RANK means you'll jump numbers when there is a link. For example, if all 3 rows have the exact same last tmstp, all 3 rows would be assigned number 1, GRADE would assign 4 to the next line, but DENSE_RANK attributes 2.
"PARTITION x" means that you are looking for a separate series of numbers (starting with 1) for each value of x. If you want just a series of numbers for the entire result set, then do not use a PARTITION BY clause at all. (PARTITION BY is never required.)
Maybe you want to PARTITIONNER IN cd. I can't do it without some examples of data, as well as an explanation of why you want the results of these data.
You certainly don't want to PARTITION you BY the same expression ORDER BY; It simply means that all the lines are tied for #1.I hope that answers your question.
If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
Explain, using specific examples, how you get these results from these data.
Simplify the problem as much as possible.
Always tell what version of Oracle you are using.
See the FAQ forum {message identifier: = 9360002}Published by: Frank Kulash, August 1, 2012 13:20
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Deputy of analytical functions
Hi all
I'm writing a query without using the analytical functions.
Analytical func using,.
Expected results. I want that these results without analytical functions.Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production PL/SQL Release 11.2.0.2.0 - Production "CORE 11.2.0.2.0 Production" TNS for Linux: Version 11.2.0.2.0 - Production NLSRTL Version 11.2.0.2.0 - Production SELECT id, sal, rank() OVER (PARTITION BY ID ORDER BY SAL) rnk FROM (SELECT 10 AS id, 100 AS sal FROM DUAL UNION ALL SELECT 10, 300 FROM DUAL UNION ALL SELECT 10, 400 FROM DUAL UNION ALL SELECT 20, 200 FROM DUAL UNION ALL SELECT 20, 200 FROM DUAL UNION ALL SELECT 20, 300 FROM DUAL UNION ALL SELECT 30, 100 FROM DUAL UNION ALL SELECT 40, 100 FROM DUAL UNION ALL SELECT 40, 200 FROM DUAL )
10 100 1 10 300 2 10 400 3 20 200 1 20 200 1 20 300 3 30 100 1 40 100 1 40 200 2
Hello
SamFisher wrote:
Hi allI'm writing a query without using the analytical functions.
Why? What is the problem with the analytical functions? You have Oracle 11.2. Use it. Do not act as you have Oracle 8.0.
One way to do that is a scalar subquery:
SELECT id , sal , ( SELECT 1 + COUNT (*) FROM table_x WHERE id = x.id AND sal < x.sal ) AS rnk FROM table_x x ORDER BY id , rnk ;
But it is extremely inefficient. This is an example of textbood (perhaps literally) why RANK is so useful.
Maybe you are looking for
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