Analytical query question
Hi allI'm kinda new in the analytical work with query and have a moment difficult to achieve what I wanted.
Here is the script to create the table and insert data.
create table temp_ar1 (lkey NUMBER,
amount NUMBER
)
;
Insert the Script-Insert into temp_ar1 values (1, -2.5);
Insert into temp_ar1 values (1, -10);
Insert into temp_ar1 values (1, 5);
Insert into temp_ar1 values (2, 0);
Insert into temp_ar1 values (2, -5);
Insert into temp_ar1 values (2, 2);
Insert into temp_ar1 values (2, -1);
With main_table as
(
select lkey,amount
,case when amount > 0 then
'positive'
else
'negative'
end col1
from temp_ar1
)
,Temp_A as
(
Select O.*
,Sum ( case when col1 = 'negative' then amount
else null
end ) Over (partition by col1,lkey) as sumcol1
,Sum ( case when col1 = 'positive' then amount
else null
end ) Over (partition by col1,lkey) as sumcol2
from main_table O
)
select lkey,amount,col1,sumcol1,sumcol2
from Temp_A order by lkey
LKEY AMOUNT COL1 SUMCOL1 SUMCOL2
---------- ---------- -------- ---------- ----------
1 5 positive 5
1 -2.5 negative -12.5
1 -10 negative -12.5
2 -1 negative -6
2 2 positive 2
2 0 negative -6
2 -5 negative -6
7 rows selected.
I'm trying to get the result that resembleslkey , sumcol1 , sumcol2
1 -12.5 5
2 -6 2
So for each separate key, I should get only a line that has sumcol1 (which is the sum of a negative amount for this key) andsumcol2 (which is the sum of the positive amount for this key)
Really appreciate your help on this matter.
or, if you do not want to group by;
SQL> with Temp_A as
2 (
3 select O.*
4 ,sum ( case when amount < 0 then amount
5 else null
6 end ) over (partition by lkey) as sumcol1
7 ,sum ( case when amount > -1 then amount
8 else null
9 end ) over (partition by lkey) as sumcol2
10 ,row_number() over (partition by lkey order by lkey) rn
11 from temp_ar1 O
12 )
13 --
14 select lkey,sumcol1,sumcol2
15 from Temp_A
16 where rn = 1
17 /
LKEY SUMCOL1 SUMCOL2
---------- ---------- ----------
1 -12.5 5
2 -6 2
Tags: Database
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SY.
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Select * from version of v$.
BANNER
----------------------------------------------------------------
Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64 bit Production
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(
Select 1, null, 'Y' from dual union all
Select 2, 1, "n" of all the double union
Select option 3, 2, "n" of all the double union
Select 4, 1, 'Y' from dual union all
Select 5, 4, the double "n" of all union
Select 6, 5, 'Y' from dual union all
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connect mgr_id = emp_id prior
Start by emp_id = 1;
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---------- ---------- ----
1 Y
2 1 N
3 2 N
4 1
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6 5
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8 1 N
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10 selected lines.
Each employee has a Manager (self or the following in the upper hierarchy with RESP = 'Y')
The root must be always charged.
To find who is responsible for a certain employee ID, I can run the following query:
I... responsible e: emp_id = 7 is 6
Select emp_id, mgr_id, RESP
of mydata
When resp = 'Y '.
and rownum < = 1
Connect prior mgr_id = emp_id
Start by emp_id = 7;
EMP_ID
----------
6
1 selected line.
i.e.: head = emp_id is 1/9
Select emp_id
of mydata
When resp = 'Y '.
and rownum < = 1
Connect prior mgr_id = emp_id
Start by emp_id = 9;
EMP_ID
----------
1
1 selected line.
i.e.: Manager emp_id = 4 is auto
Select emp_id
of mydata
When resp = 'Y '.
and rownum < = 1
Connect prior mgr_id = emp_id
Start by emp_id = 4;
EMP_ID
----------
4
1 selected line.
What query is the fastest to get all employees to a certain level of responsibility?
That is to say: all employees not responsible according to 1 should give:
EMP_ID MGR_ID RESP
---------- ---------- ----
2 1 N
3 2 N
8 1 N
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Kind regards.
Alberto
Hi, Alberto.
So, you want to quit looking more far down the tree when you come to a node with an RESP = 'Y', right?
Just include an RESP = ' don't (or resp. <> 'Y' or NVL (RESP, 'Y' <> 'Y') in the CONNECT BY State, like this:)
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of mydata
connect mgr_id = emp_id prior
and RESP = "n"-* NEW *.
Start by emp_id = 1;
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user564819 wrote:
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