Another hierarchical query

Similar Questions

• How to write a hierarchical query so that only the child nodes are displayed?

  Hi all

  I have a hierarchical query that I use in an area of tree demand APEX and there are nodes that have no children and I am trying to find a way to not display these nodes. Essentially if the user does not have to develop a lot of knots to know that nothing exists at the most detailed level.

  The data are based on the Oracle Fusion FND tables but for example purposes here is enough data to illustrate my question:

  
  

  create table APPL_TAXONOMY_HIERARCHY (SOURCE_MODULE_ID varchar2(30), TARGET_MODULE_ID varchar2(30));
  create table APPL_TAXONOMY_TL (module_id varchar2(30), description varchar2(100), user_module_name varchar2(30), language varchar2(5));
  create table APPL_TAXONOMY (MODULE_ID    varchar2(30),    MODULE_NAME    varchar2(30), MODULE_TYPE varchar2(10),    MODULE_KEY varchar2(30));
  create table TABLES (table_name varchar2(30), module_key varchar2(30));
  
  

  insert into APPL_TAXONOMY_TL values ('1', null, 'Oracle Fusion', 'US' );
  insert into APPL_TAXONOMY_TL values ('2', null, 'Financials', 'US' );
  insert into APPL_TAXONOMY_TL values ('3', null, 'Human Resources', 'US' );
  insert into APPL_TAXONOMY_TL values ('20', null, 'Accounts Payable', 'US' );
  insert into APPL_TAXONOMY_TL values ('10', null, 'General Ledger', 'US' );
  
  insert into APPL_TAXONOMY_HIERARCHY values ('1', 'DDDDDDDD');
  insert into APPL_TAXONOMY_HIERARCHY values ('2', '1');
  insert into APPL_TAXONOMY_HIERARCHY values ('3', '1');
  insert into APPL_TAXONOMY_HIERARCHY values ('4', '1');
  insert into APPL_TAXONOMY_HIERARCHY values ('10', '2');
  insert into APPL_TAXONOMY_HIERARCHY values ('20', '2');
  
  insert into APPL_TAXONOMY values ('1', 'Fusion', 'PROD', 'Fusion');
  insert into APPL_TAXONOMY values ('2', 'Financials', 'FAMILY', 'FIN');
  insert into APPL_TAXONOMY values ('10', 'GL', 'APP', 'GL');
  insert into APPL_TAXONOMY values ('3', 'Human Resources', 'FAMILY', 'HR');
  insert into APPL_TAXONOMY values ('20', 'AP', 'APP', 'AP');
  
  insert into tables values ('GL_JE_SOURCES_TL','GL');
  insert into tables values ('GL_JE_CATEGORIES','GL');
  

  My hierarchical query is as follows:

  with MODULES as
  (
  SELECT h.source_module_id, b.user_module_name, h.target_module_id
        FROM APPL_TAXONOMY_HIERARCHY H,
        APPL_TAXONOMY_TL B,
  APPL_TAXONOMY VL
  where H.source_module_id = b.module_id
  and b.module_id = vl.module_id
  and vl.module_type not in ('PAGE', 'LBA')
  UNION ALL
  select distinct table_name, table_name,  regexp_substr(table_name,'[^_]+',1,1) 
  from TABLES --needed as a link between TABLES and APPL_TAXONOMY
  union all
  select module_key as source_module_id, module_name as user_module_name, module_id as target_module_id  from appl_taxonomy VL where VL.module_type = 'APP')
  SELECT  case when connect_by_isleaf = 1 then 0
              when level = 1             then 1
              else                           -1
         end as status,
  LEVEL,
  user_module_name as title,
  null as icon,
  ltrim(user_module_name, ' ') as value,
  null as tooltip,
  null as link
        FROM MODULES
        START WITH source_module_id = '1'
        CONNECT BY PRIOR source_module_id = target_module_id
  ORDER SIBLINGS BY user_module_name;
  

  In Oracle APEX, this gives a tree with the appropriate data, you can see here:

  https://Apex.Oracle.com/pls/Apex/f?p=32581:29 (username: guest, pw: app_1000);

  The SQL of the query results are:

  STATUS

  TITLE LEVEL

  VALUE

  ---------- ---------- ------------------------------ ------------------------------

  	1	1 oracle Fusion	Oracle Fusion
  	-1	2 financial tables	Financials
  	-1	3 accounts payable	Accounts payable
  	0	4 AP	AP
  	-1	General Accounting 3	General Accounting
  	-1	4 GL	GL
  	0	5 GL_JE_CATEGORIES	GL_JE_CATEGORIES
  	0	5 GL_JE_SOURCES_TL	GL_JE_SOURCES_TL
  	0	2 human resources	Human resources

  The lowest level is the name of the table to level 5. HR is not any level under level 2, in the same way, "AP" (level 4) has nothing below, i.e. no level 5 and that's why I don't want to show these nodes. Is this possible with the above query?

  Thanks in advance for your suggestions!

  John

  Hello

  The following query will include only the nodes of level = 5 and their ancestors (or descendants):

  WITH modules LIKE

  (

  SELECT h.source_module_id

  b.user_module_name AS the title

  h.target_module_id

  To appl_taxonomy_hierarchy:

  appl_taxonomy_tl b

  appl_taxonomy vl

  WHERE h.source_module_id = b.module_id

  AND b.module_id = vl.module_id

  AND vl.module_type NOT IN ('PAGE', "LBA")

  UNION ALL

  SELECT DISTINCT

  table-name

  table_name

  , REGEXP_SUBSTR (table_name, ' [^ _] +')

  From the tables - required as a link between the TABLES and APPL_TAXONOMY

  UNION ALL

  SELECT module_key AS source_module_id

  AS user_module_name module_name

  module_id AS target_module_id

  Of appl_taxonomy vl

  WHERE vl.module_type = 'APP '.

  )

  connect_by_results AS

  (

  SELECT THE CHECK BOX

  WHEN CONNECT_BY_ISLEAF = 1 THEN 0

  WHEN LEVEL = 1 THEN 1

  OF ANOTHER-1

  The END as status

  LEVEL AS lvl

  title

  -, NULL AS icon

  , LTRIM (title, "") AS the value

  -, NULL as ToolTip

  -, Link AS NULL

  source_module_id

  SYS_CONNECT_BY_PATH (source_module_id - or something unique

  , ' ~' - or anything else that may occur in the unique key

  ) || ' ~' AS the path

  ROWNUM AS sort_key

  Modules

  START WITH source_module_id = '1'

  CONNECT BY PRIOR Source_module_id = target_module_id

  Brothers and SŒURS of ORDER BY title

  )

  SELECT the status, lvl, title, value

  -, icon, tooltip, link

  OF connect_by_results m

  WHEN THERE IS)

  SELECT 1

  OF connect_by_results

  WHERE the lvl = 5

  AND the path AS ' % ~' | m.source_module_id

  || '~%'

  )

  ORDER BY sort_key

  ;

  You may notice that subqueries modules and the connect_by_results are essentially what you've posted originally.  What was the main request is now called connect_by_results, and it has a couple of additional columns that are necessary in the new main request or the EXISTS subquery.

  However, I am suspicious of the 'magic number' 5.  Could you have a situation where the sheets you are interested in can be a different levels (for example, some level = 5 and then some, into another branch of the tree, at the LEVEL = 6, or 7 or 4)?  If so, post an example.  You have need of a Query of Yo-Yo, where you do a bottom-up CONNECT BY query to get the universe of interest, and then make a descendant CONNECT BY query on this set of results.

• Query on hierarchical query in interactive report!

  Hello

  In Apex Oracle 5.1, I tried to use an interactive report to view details of employee based on a hierarchy. I used the query to display data below:

  SELECT last_name, employe_id, manager_id, LEVEL

  Employees

  START WITH employee_id = 100

  CONNECT BY PRIOR employee_id = manager_id

  Brothers and SŒURS of ORDER BY last_name;

  The output was as below:

  LAST_NAME EMPLOYEE_ID MANAGER_ID LEVEL

  ------------------------- ----------- ---------- ----------

  King                                100                                                       1

  Cambrault                        148                                 100                 2

  Bates                              172                                 148                 3

  Bloom                             169                                  148                3

  Fox                                 170                                  148                3

  Kumar                             173                                  148                3

  Ozer                                168                                  148               3

  Smith                               171                                  148              3

  De Haan                           102                                   100             2

  Hunold                              103                                   102             3

  Austin                               105                                   103             4

  Ernst                                 104                                   103             4

  Lorentz                              107                                   103             4

  Pataballa                           106                                    103            4

  Errazuriz                           147                                   100              2

  Ande                                 166                                    147             3

  Banda                               167                                     147             3

  ...

  Now, I would like to display data based on the connection of employees.

  For example (based on above request): If an employee named - Cambrault is the login, only employees under him (Bates, Bloom, Fox, Kumar, Smith, Ozer) and its own contact information should appear in the report.

  Please advise.

  Kind regards

  mebu

  Mebu wrote:

  I used a hierarchical query. But based on Login, I want to display only members under him.

  For example: If Cambrault LOGIN, only employees under him (Bates, Bloom, Fox, Kumar, Smith, Ozer) and its own coordinates must display in Oracle Apex.

  SELECT last_name, employe_id, manager_id, LEVEL

  Employees

  START WITH employee_id = 100

  CONNECT BY PRIOR employee_id = manager_id

  Brothers and SŒURS of ORDER BY last_name;

  See what/when/where? How to get the answers from the forum

  Describe the requirements clearly and completely, using the APEX, Oracle and terminology of web standard.

• hierarchical query of VO in the ofa page

  Hello

  I try to use the hierarchical query in VO for the display of all levels of supervisors for employee and want to display in populist:

  This is the query

  REPLACE SELECT distinct (mgx.full_name, "',' ') supervisor_full_name;

  XPP. Employee_number

  OF per_assignments_x pax,.

  per_people_x ppx,

  per_people_x mgx,

  per_positions pp,

  per_jobs pj,

  per_position_definitions ppd

  WHERE ppx.person_id = pax.person_id

  AND ppx.current_employee_flag = 'Y '.

  AND mgx.person_id = pax.supervisor_id

  AND pp.position_id = pax.position_id

  AND pj.job_id = pax.job_id

  AND ppd.position_definition_id = pp.position_definition_id

  START WITH ppx.employee_number =: 1

  CONNECT BY PRIOR MGX.employee_number = ppx.employee_number AND LEVEL < 6

  I'm trying to get this VO implemented PR when I run the page in jdeveloper with parameter binding, it's getting error.

  oracle.apps.fnd.framework.OAException: oracle.jbo.SQLStmtException: 27122 Houston: SQL error in the preparation of the statement.

  I would like to delete the parameter binding and executing CO VO past these two statements may be:

  START WITH ppx.employee_number =: 1

  CONNECT BY PRIOR MGX.employee_number = ppx.employee_number AND LEVEL < 6

  How can I do?

  Thank you

  MK

  has worked?

• Hierarchical query help

  Version: Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit Production

  Hello

  I can't just writing this hierarchical query.

  CREATE TABLE resources
  (
      resource_name   VARCHAR2( 20 )
     ,resource_id     NUMBER
     ,resource_mgr_id NUMBER
  );
  
  INSERT INTO resources(resource_name,resource_id,resource_mgr_id)
  VALUES ('Phupinder',29269,29298);
  
  INSERT INTO resources(resource_name,resource_id,resource_mgr_id)
  VALUES ('Terry',29298,NULL);
  
  INSERT INTO resources(resource_name,resource_id,resource_mgr_id)
  VALUES ('Matt',4876,32942);
  
  INSERT INTO resources(resource_name,resource_id,resource_mgr_id)
  VALUES ('Bryan',29429,29269);
  
  INSERT INTO resources(resource_name,resource_id,resource_mgr_id)
  VALUES ('Cathy',32942,4922);
  
  INSERT INTO resources(resource_name,resource_id,resource_mgr_id)
  VALUES ('Scott',4257,29429);
  
  INSERT INTO resources(resource_name,resource_id,resource_mgr_id)
  VALUES ('Joe',44026,4876);
  
  INSERT INTO resources(resource_name,resource_id,resource_mgr_id)
  VALUES ('Greg',4922,4257);
  
  
  
  
  
  
  
  
  

  I also tried this:

  1. SELECT DISTINCT R.resource_name
  2. r.resource_id
  3. From r resources
  4. WHERE r.resource_id IN (SELECT DISTINCT r2.resource_mgr_id
  5. RESOURCE r2
  6. WHERE r.resource_id = r2.resource_mgr_id OR
  7. R2.resource_mgr_id IS NULL)
  8. ORDER BY 1;

  Which gives correct results, but isn't that a hierarchical query?

  It was the (almost) good solution to your problem.

  The only thing is:

  -you don't need to do a correlated subquery to solve the problem

  -you don't need to separate your subqurey

  -you don't need to separate your mainquery

  SELECT resource_name, id_ressource

  RESOURCES

  where id_ressource in (select r2.resource_mgr_id from r2 resources);

  would be sufficient.

  HTH

• Help with hierarchical query

  I'm trying to parse each string inside of individual characters. For this, I used the link by the hierarchical query clause. I am not able to use connect by correctly. Here is my example.

  with the CBC as)

  Select 1: the nurse, 'abc' double union all Str

  Select 2: the nurse, '123' Str of all union double

  Select 3: the nurse, "pqr xyz" dual union all Str

  Select option 4: the nurse, 'john doe' double Str

  )

  Select the level, homobasidiomycetes, substr(s.str,level,1) as chr

  s of the CBC

  connect nocycle level < = length (homobasidiomycetes)

  /

  The above query returns 3 028 lines when I want that 21. Adding a distinct to select, it's what I want.

  with the CBC as)

  Select 1: the nurse, 'abc' double union all Str

  Select 2: the nurse, '123' Str of all union double

  Select 3: the nurse, "pqr xyz" dual union all Str

  Select option 4: the nurse, 'john doe' double Str

  )

  Select distinct level, homobasidiomycetes, substr(s.str,level,1) as chr

  s of the CBC

  connect nocycle level < = length (homobasidiomycetes)

  order by str, level

  /

  For a large data set I could end up with several million rows before the separate would lead. So, how can I restrict the connection by clause to go within each line.

  Assuming that the AI is the primary key, you could do this:

  with src as (
    select 1 as rn, 'abc' as str from dual union all
    select 2 as rn, '123' as str from dual union all
    select 3 as rn, 'pqr xyz' as str from dual union all
    select 4 as rn, 'john doe' as str from dual
  )
  select level,
        s.str,
        substr(s.str,level,1) as chr
  from src s
  connect by level <= length(s.str)
            and prior rn = rn
            and prior dbms_random.value is not null;
  

  See DBMS_RANDOM.value in a hierarchical solution for string to table? for an exchange of views around the case.

• Hierarchical query result

  Dear all

  I use Oracle Database 10g and I need a hierarchical query giving following release

  KING

  | __JONES

  |   | __SCOTT

  |   | __ADAMS

  |   | __FORD

  |      | __SMITH

  | __BLAKE

  |   | __ALLEN

  |   | __WARD

  |   | __MARTIN

  |   | __TURNER

  |   | __JAMES

  | __CLARK

  | __MILLER

  Best regards

  Try this

  SELECT CASE WHEN level > 1 THEN LPAD (': _ ', LEVEL,' |) ')

  END | Ename AS ename_tree

  WCP

  START WITH mgr IS NULL

  CONNECT BY PRIOR empno = mgr;

• Support for hierarchical query

  Hi all

  I must be tired and can't think clearly, so I am a little confused the following query.

  The environment is Oracle 9i:

  Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64 bit Production

  PL/SQL Release 9.2.0.8.0 - Production

  CORE Production 9.2.0.8.0

  AMT for HP - UX: 9.2.0.8.0 - Production Version

  NLSRTL Version 9.2.0.8.0 - Production

  Suppose I have the following data:

  with mydata as

  (

  Select the code 1, code_high, null, 'John' cname 'Smith' csurname, 'X' union resp. double all the

  Select 2 code, 1 code_high, cname 'Bill', 'White' csurname, RESP null in union double all the

  Select 3 code, code_high 2, 'Fred' cname 'Reed' csurname, 'X' union resp. double all the

  Select 4 code, code_high, null, 'Tim' cname 'Hackman' csurname, 'X' union resp. double all the

  Select code 5, code_high 4, 'John', 'Reed' cname csurname resp null in union double all the

  Select 6 code, code_high 5, cname 'Bill', 'Hakcman' csurname, 'X' union resp. double all the

  Select the code 7, code_high 6, cname 'Fred' csurname 'White', null union resp. double all the

  Select code 8, code_high 7, 'Bill' cname 'Smith' csurname, resp. union null double all the

  Select 9 code, code_high 8, cname "Tom", "Reed" csurname, null double RESP

  )

  Select *.

  of mydata;

  CODE CODE_HIGH CNAME CSURNAME RESP

  ---------- ---------- ----- -------- ----

  John Smith 1 X

  2 1 bill White

  3 2 Fred Reed X

  4 Tim Hackman X

  5 4 John Reed

  6 5 bill Hakcman X

  7 6 Fred white

  8 7 bill Smith

  9 8 Tom Reed

  It is a hierarchical query where code_high represents the father.

  I need to find in the hierarchy of higher level responsible for each code.

  Suppose I want to find in the hierarchy, one with resp = 'X '.

  Run the following query I find for the code = 9

  Select phone, cname, csurname code

  of mydata

  When resp = 'X '.

  and rownum = 1

  Connect prior code_high = code

  start with code = 9;

  CODE CNAME CSURNAME

  ---------- ----- --------

  Bill 6 Hakcman

  Is there a way to get the full list with the loaded correspondents.

  The expected results are:

  CODE CODE_HIGH CNAME CSURNAME RESP. RESP_CODE RESP_NAME RESP_SURNAME

  ---------- ---------- ----- -------- ---- --------- --------- ------------

  1 John Smith John Smith 1 X

  2 1 bill White 1 John Smith

  3 2 Fred Reed X 3 Fred Reed

  Tim Hackman 4 X 4 Tim Hackman

  5 4 John Smith 4 Tim Hackman

  6 5 bill Hakcman Bill Hakcman 6 X

  7 6 Fred White 6 Bill Hakcman

  8 7 bill Smith 6 Bill Hakcman

  9 8 Tom Reed 6 Bill Hakcman

  Kind regards.

  Alberto

  Hi, Alberto.

  I know that you are using Oracle 9; That's why I mentioned that you would have to use a substitute for CONNECT_BY_ROOT.  Before I could show how, I saw the solution of the Padders, which is probably simpler and more efficient for this work.  Padders used REGEXP_SUBSTR, which is not available in Oracle 9, but you can use SUBSTR and INSTR instead.

  Here is the solution of the Padders for Orcle 9:

  WITH got_resp_path AS

  (

  SELECT m.*

  RTRIM (SYS_CONNECT_BY_PATH (CASE

  WHEN resp = 'X '.

  THEN the code

  END

  , ' '

  )

  ) AS resp_path

  OF mydata m

  START WITH code_high IS NULL

  CONNECT BY code_high = code PRIOR

  )

  C. SELECT

  r.code AS resp_code

  r.cname AS resp_name

  r.csurname AS resp_surname

  OF got_resp_path c

  JOIN mydata r ON r.code = TO_NUMBER (SUBSTR (c.resp_path

  INSTR (c.resp_path

  , ' '

  -1

  )

  )

  )

  ORDER BY c.code

  ;

  I agree that what you posted in your last post is not very satisfactory.  Rather than make a CONNECT a separate query for each column of resp_ you want to view, you can modify it to get only the unique code and then use it in a join, as Padders, to get all the other columns you need.

• In a hierarchical query, is it possible for a line having more than one immediate ancestor?

  Hello

  Question:
  

  In a hierarchical query, is it possible for a line having more than one immediate ancestor?
  

  ---

  Answer:
  NO.

  
  

  
  

  Isn't it?  Surely this is Yes?

  
  

  Thank you

  Jason
  

  Line may have ancestors as much as you want. It goes the same for successors.

  SY.

• Hierarchical data, how to aggregate over levels in hierarchical query?

  Hello
  
  I hope someone can help me.
  
  I held in a data table ("" what part was built in what other part of when when? "')
  ID parent_id build_in build_out
  1 NULL NULL NULL
  2/1 2010 2012
  3 2 2011 2013
  4 2 2013 NULL
  
  What are the parts is stored in a separate table.
  
  Now I want to know when when which part was built in the first level, in the example, I want to know that
  1 was simply a part of 1
  2 was part of 1 between 2010 and 2012
  3 was part of 1 between 2011 and 2012
  4 has never been a part of 1
  
  I tried several approaches - if there is a fixed number of levels between the types, I am interested I can do using joins and more/less (similarly as some nvl). Unfortunately this is not always the case (some parts appear on several levels).
  If I'm only interested in the parts that are never deleted, I can get by using a style of connect request and get the current configuration. But I can't seem to understand the time connecting part to the high level in such a query, or even filtering absurd combinations (like "4 in 1" in the example above). I could deal with the data recovered outside the database, but I prefer not.
  
  Is there a way to obtain the hierarchical data with an aggregate (min, max) for all levels?

  What version of Oracle you are on?

  In 11.2.x, you can use the recursive subquery factoring. Something like

  with t (id, parent_id, build_in, build_out) as (
  select 1, null, null, null from dual union all
  select 2, 1, 2010, 2012 from dual union all
  select 3, 2, 2011, 2013 from dual union all
  select 4, 2, 2013, null from dual
  )
  , c1 (root_id, id, parent_id, build_in, build_out) as (
  select id, id, parent_id, 0, 9999
  from t
  where parent_id is null
  union all
  select root_id, t.id, t.parent_id
  , greatest(nvl(t.build_in,0), nvl(b.build_in,0))
  , least(nvl(t.build_out,9999), nvl(b.build_out,9999))
  from c1 b, t
  where b.id = t.parent_id
  )
  select * from c1
  where build_in < build_out
  ;
  ROOT_ID ID    PARENT_ID  BUILD_IN  BUILD_OUT
  ------- ----- ---------- --------- ----------
  1       1                0         9999
  1       2     1          2010      2012
  1       3     2          2011      2012      
  

  With a hierarchical query by using the syntax connection, you could do something like

  select * from (
  select connect_by_root id as root, id
  , greatest(nvl(build_in,0), nvl(prior build_in,0)) as max_in, least(nvl(build_out,9999), nvl(prior build_out,9999)) as min_out
  from t
  start with parent_id is null
  connect by parent_id = prior id
  )
  where max_in < min_out
  ;
  

  but it is not powerful enough. This version compares the dates between a current and previous levels, but the recursive subquery is to compare the dates in the current level for the winners of the comparisons to the previous level. Not sure if it's an important distinction for your needs, however.

  If you are on 11.2 I advise to use the recursive subquery factoring. If this isn't the case, you can try the link by version.

  Kind regards
  Bob

• Getting the line without the use of hierarchical query values

  Hi all
  
  
  I want to know the hierarchical values without using a hierarchical query. I have two tables EMP, DEPT
  
  EMP table is to have two columns (empid, mgrid)
  DEPT table is to have two columns (deptid, empid)
  
  Data of the EMP
  
  1,
  2, 1
  3, 2
  4, 3
  
  Data DEPT
  
  10, 1
  
  Each time, I gave deptid = 10, I need to know the this deptid empid then who is this empid (child levels as well). In this case, the output should be
  1
  2
  3
  4
  
  I don't want to use hierarchical query.
  
  Thanks in advance.
  
  
  Thank you
  PAL

  You can use the RECURSIVE subquery, if you are 11 GR 2, like this

  SQL> with EMP (empid,mgrid) as
    2  (
    3  select 1,null from dual union all
    4  select 2, 1 from dual union all
    5  select 3, 2 from dual union all
    6  select 4, 3 from dual
    7  ),
    8  dept(deptid,empid) as
    9  (
   10  select 10, 1  from dual
   11  ),
   12  t(empid,mgrid) as
   13  (
   14  select empid,mgrid
   15  from emp e
   16  where empid in (
   17      select d.empid
   18      from dept d
   19      where deptid = 10
   20                  )
   21  union all
   22  select e.empid,e.mgrid
   23  from emp e, t
   24  where e.mgrid = t.empid
   25  )
   26  select *
   27  from t;
  
       EMPID      MGRID
  ---------- ----------
           1
           2          1
           3          2
           4          3
  

  Yet, the question is valid - why can't use you a hierarchical query?

  Published by: JAC on May 29, 2013 12:37

• Problems with views based on a hierarchical query

  Datamodeler 3.1.3.706 (SQL Dev 3.2.10.09):
  
  When you create a view that uses a hierarchical query, the query designer encounter various difficulties:
  
  When pasting in the SQL code, if the notice is registered without first clicking the schema update button, the object in the entity-relationship diagram view provides a faithful representation of the view without errors, but when the reopening of the view, the code is missing.
  
  Simple example with the classic emp table:

  SELECT level lev
        , emp.*
     FROM emp
    CONNECT BY prior empno = mgr
    START WITH mgr        IS NULL

  If you press the schema update button to refresh the display. He mangles connect it by the clause and the view gets marked with a warning/error icon in the diagram of the relationships, but the now decomposed code remains available on reopening of the query designer.
  
  Same code as above after having clicked on the button of update of schema:

   SELECT Level lev
  , emp.*
     FROM emp
    CONNECT BY

  Other issues are met if the query contains a column CONNECT_BY_ % nickname hierarchical:

  SELECT level
        , emp.*
        , connect_by_root emp.ename root_ename
     FROM emp
    CONNECT BY prior empno = mgr
    START WITH mgr        IS NULL;

  In this case, paste in the code and clicking Update schema button or the OK button translates into a "unexpected Token' error analysis.
  
  These problems are encountered with the logic model and the relational.
  
  Is this a known issue? I searched this forum but have not found any references to this.
  
  Thank you
  
  Sentinel

  Hi, Sentinel,

  I logged a bug for this.
  You can try 3.3 DM treat it better first problem, analysis of connect_by_root operator will pass if you do not alias.

  Philippe

• Hierarchical query help need to Oracle

  Hello
  I'm in a deep trouble.
  
  I want to do a hierarchical query in my TreeView table in oracle. But I want that the query retrieves information path between two nodes.
  
  Review the table below.
  
  ------------------------------------------------------
  Node ID | Name of the node. ID of the parent
  -----------------------------------------------------
  1A 0
  2 1
  3C0
  4 2
  -----------------------------------------------------
  
  What I want is that I'll give you 2 node id in the request. One is the source node and the other is the destination node.
  so if I put 1 node and node 4, I want to be the output
  
  1-> 2-> 4
  
  I want just a return line. Or there may be several rows but stands only the node of this path.
  
  1
  2
  4
  ----
  
  This means that I don't want to node 3 in the search result.
  
  
  More if I have the source as 4 node and the node of destination as 1 then I will also get an output of the query as below-
  4-> 2-> 1
  
  This means that the search for the query for the result in a way directional bi.
  
  
  If anyone can give me some information about who it's going to be great for me.
  
  Published by: user13276471 on December 31, 2012 03:21

  Hello

  Welcome to the forum!

  Assuming you have 2 separate nodes: Node_A and: node_b, you can find the hierarchy from one to the other like this:

  SELECT     SYS_CONNECT_BY_PATH (node_id, ',')     AS lineage
  FROM     table_x
  WHERE     node_id     IN (:node_a, :node_b)
  AND     LEVEL     > 1
  START WITH     node_id          IN (:node_a, :node_b)
  CONNECT BY     parent_id     = PRIOR node_id
  ;
  

  It will work if: the Node_A is an ancestor of the: node_b, or if: node_b is an ancestor of the: Node_A.
  If is the ancestor of the other, then it will produce 0 rows.

• Help in hierarchical query

  Hello
  
  I have data like this.
  
  EMPID ENAME MANAGERID
  1A
  2 1
  1 OF 3
  4 2
  5 2
  6 3
  4 OF 7
  
  And I want to show the data in this way. SUPERMNAGERID is always 1, regardless of the fact that that which is his immediate superior.
  
  EMPID ENAME MANAGERID SUPERMNAGERID
  1A
  2-1-1
  3-1-1
  4-2-1
  5-2-1
  6-3-1
  7-4-1
  
  Your help on this would be really useful.
  
  Edited by: user10827825 may 6, 2012 12:36

  Most inefficient way. If you want to use a hierarchical query, use START WITH and to get the "supermanager" use CONNECT_BY_ROOT:

  WITH t AS
       (SELECT 1 EMPID, 'A' ENAME, NULL MANAGER_ID
          FROM DUAL
        UNION ALL
        SELECT 2 EMPID, 'B' ENAME, 1 MANAGER_ID
          FROM DUAL
        UNION ALL
        SELECT 3 EMPID, 'C' ENAME, 1 MANAGER_ID
          FROM DUAL
        UNION ALL
        SELECT 4 EMPID, 'D' ENAME, 2 MANAGER_ID
          FROM DUAL
          UNION ALL
        SELECT 5 EMPID, 'E' ENAME, 2 MANAGER_ID
          FROM DUAL
        UNION ALL
        SELECT 6 EMPID, 'F' ENAME, 3 MANAGER_ID
          FROM DUAL
        UNION ALL
        SELECT 7 EMPID, 'G' ENAME, 4 MANAGER_ID
          FROM DUAL
          )
  SELECT EMPID, ENAME, MANAGER_ID, CONNECT_BY_ROOT EMPID
    FROM t
    START WITH MANAGER_ID IS NULL
    CONNECT BY MANAGER_ID = PRIOR EMPID
    ORDER BY EMPID;
  

  Compare the number of lines hierarchy is generated by bot queries:

  SQL> WITH t AS
    2       (SELECT 1 EMPID, 'A' ENAME, NULL MANAGER_ID
    3          FROM DUAL
    4        UNION ALL
    5        SELECT 2 EMPID, 'B' ENAME, 1 MANAGER_ID
    6          FROM DUAL
    7        UNION ALL
    8        SELECT 3 EMPID, 'C' ENAME, 1 MANAGER_ID
    9          FROM DUAL
   10        UNION ALL
   11        SELECT 4 EMPID, 'D' ENAME, 2 MANAGER_ID
   12          FROM DUAL
   13          UNION ALL
   14        SELECT 5 EMPID, 'E' ENAME, 2 MANAGER_ID
   15          FROM DUAL
   16        UNION ALL
   17        SELECT 6 EMPID, 'F' ENAME, 3 MANAGER_ID
   18          FROM DUAL
   19        UNION ALL
   20        SELECT 7 EMPID, 'G' ENAME, 4 MANAGER_ID
   21          FROM DUAL
   22          )
   23  SELECT count(*)
   24    FROM t
   25    CONNECT BY PRIOR  MANAGER_ID = EMPID
   26    ORDER BY EMPID;
  
    COUNT(*)
  ----------
          18
  
  SQL> WITH t AS
    2       (SELECT 1 EMPID, 'A' ENAME, NULL MANAGER_ID
    3          FROM DUAL
    4        UNION ALL
    5        SELECT 2 EMPID, 'B' ENAME, 1 MANAGER_ID
    6          FROM DUAL
    7        UNION ALL
    8        SELECT 3 EMPID, 'C' ENAME, 1 MANAGER_ID
    9          FROM DUAL
   10        UNION ALL
   11        SELECT 4 EMPID, 'D' ENAME, 2 MANAGER_ID
   12          FROM DUAL
   13          UNION ALL
   14        SELECT 5 EMPID, 'E' ENAME, 2 MANAGER_ID
   15          FROM DUAL
   16        UNION ALL
   17        SELECT 6 EMPID, 'F' ENAME, 3 MANAGER_ID
   18          FROM DUAL
   19        UNION ALL
   20        SELECT 7 EMPID, 'G' ENAME, 4 MANAGER_ID
   21          FROM DUAL
   22          )
   23  SELECT count(*)
   24    FROM t
   25    START WITH MANAGER_ID IS NULL
   26    CONNECT BY MANAGER_ID = PRIOR EMPID
   27    ORDER BY EMPID;
  
    COUNT(*)
  ----------
           7
  
  SQL> 
  

  Now imagine the table real a couple thousand lines.

  SY.

• Get the value of the root of a hierarchical query

  I'm writing a hierarchical query for one of my paintings.
  
  I need to know the value of the root by entering a value of sheet of any level.
  
  for example: I enter a value which is at level 4. I need to find the value of the root without displaying the other levels.
  
  Help, please.
  
  Thank you.

  TRY THIS,

  SELECT     ename, PRIOR  ename MGRNAME
        FROM emp
       WHERE ename = 
  START WITH mgr IS NULL
  CONNECT BY PRIOR empno = mgr
  

  Published by: NSK2KSN on August 9, 2010 18:10