Arithmetic operation on complex numbers

Similar Questions

• HP 50 g - complex numbers

  My first question is if there is a way to work with complex numbers to the writer of the equation.

  If this is not the case, how can I write the complex number 100sqrt (2), 30 ° in RPN mode?

  Hello

  I downloaded a video here:

  http://s837.Photobucket.com/user/bdeboer_photbkt/media/calc_pics/HP/HP-50g/movie_0002_zpscd0dc6e5.mp4.html

  (note the mode change complex at 00:12 is LeftShift press and hold and press i (the TOOL button).

  It will be useful.

• First HP CASE - implicit multiplication of complex numbers

  When you make the implicit multiplication of complex numbers in CASE the first mode (6975) does the following:
  
  Enter: (2 + i)(2-i)
  Rewritten (wrongly) as: 2 + i (2-i)
  Returns: 2 + I
  
  This happens in two (a, b) and (a + b * i) formats:

  (2.1) (2, - 1) becomes 2,1(2,-1) and returns the value 1
  
  Explicit multiplication of complex numbers seems to work correctly:
  
  Enter: (2 + i) *(2-i)
  Returns: 5
  
  Sometimes, the rewriting of implicit multiplication treats the imaginary part of the first complex number as a function call with the second number complex as parameters to the function.

  Apparently this tangent actually proved useful.  He looked more closely into the use of parentheses.

  Review: (1 + i)(1-i)

  What seems to take place the second term, (1 - i), apparently ignored is that CASE trying to make a substitution as in the following example:

  (1 + x) (a + b) becomes (1 + (a + b)) due to a substitution of (a + b), the symbol 'x '.

  However, if this substitution occurs when a value is assigned to 'x', the substitution fails and the initial value of 'x' remains.  This creates the illusion that (a + b) is ignored.

  x: = 2

  (1 + x) (a + b) becomes 1 + x and the result is 3 because 'x' remained the value 2.

  I think that 'I' is treated as if 'i' was assigned to the value sqrt(-1).  The substitution is not in the same way that when a value is assigned to 'x '.

  Remember to purge (x).

• Using a C DLL with complex numbers of Labview

  Hello

  So I would try to use the existing C99 to perform calculations, and for the functions code, the code accepts and returns type numbers 'double complex.   I have spent half a day to find out the hard way that Visual Studio does not complex.h header, so before you spend more time trying to compile a DLL, not done Labview even allows you to send and receive complex of a DLL call numbers?

  When I open the node to call a library function and go to settings, the closest return type I see is double 8 bytes, but nothing about the complex... so...   I am not even convinced that this will work... did anyone done this before?

  Thank you

  Yes, you can use complex numbers. See the example with properly called LabVIEW "" call DLL". There is an example here that deals with complex numbers. You may need to write a wrapper DLL, if.

• How perforem arithmetic operations on time

  Studio Edition Version 11.1.2.3.0

  How to perform arithmetic operations on time

  I have a timestamp of data type attribute in VO

  based on the Oracle database field

  I can get the hour and the minutes using the value default adf.currentDateTime and simple date format hh: mm a

  I'm trying to add more hours to calculate the hours of service as Expression groovy

  Ex DocumentDate +(2/24) 2 hours

  I have error

  (oracle.jbo.JboException) Houston-29000: Unexpected exception caught: groovy.lang.MissingMethodException, msg = no signature of method: java.sql.Timestamp.plus () applies to the types of arguments: (Java.Math.BigDecimal) values: [0.2083333333]

  -Level 1: retail - 0

  (groovy.lang.MissingMethodException) no signature of method: java.sql.Timestamp.plus () applies to the types of arguments: (Java.Math.BigDecimal) values: [0.2083333333]

  I have added a transitional attriburte TestHire to the Employees (from a HR DB schema) table

  

  and in the expression of the value the groovy

  

  When I run now present in the Module Tester Application I see that the TestHire attribute is HireDate + 2 h

  

  Timo

• Arithmetic operation resulted in an overflow - System.Data.Odbc.OdbcDataReader.FirstResult)

  Hello

  I installed Oracle Database 11g Release 2 full Client for Microsoft Windows (x 64) of: (link)of Oracle Database 11 g Release 2 for Microsoft Windows (x 64)

  When I run an ODBC statement from a .NET (64-bit) application, I get the following error:

  Type of exception: System.OverflowException

  Exception message: arithmetic operation resulted in an overflow.

  Exception trace: at System.Data.Odbc.OdbcDataReader.FirstResult)

  I tried the same statement from another machine (same configuration), but with only the components of the ODAC 11.2 and it worked perfectly fine.

  I don't want to use 11g ODAC components because it does not support transactions responsible MTS (known bug). The full client for its works perfectly fine for this kind of scenario. I did some research online and I find that there are available patches to fix the above point. Please give me a link to download the fix or tips on how I can fix this problem.

  Concerning

  Regnier

  Hi Ben Amor,.

  You could be hitting the known, documented problem in Note below:

  Data recovery using a .NET ODBC Application may fail with: "arithmetic operation caused an overflow" (Doc ID 1181253.1)

  If you're on 11.2.0.1 Oracle client download and install the patch 11.2. 0.1 PATCH 5:9966926

  Download link:

  https://updates.Oracle.com/download/9966926.html

  This bug is fixed in 11.2.0.2.0 or a later version of the Oracle client.

  The 11.2.0.2 software can be downloaded from My Oracle support: Patch: 10098816

  https://updates.Oracle.com/download/10098816.html

  Last client version 11.2 that is 11.2.0.4, can be downloaded from My Oracle support: Patch: 13390677

  https://updates.Oracle.com/download/13390677.html

  Kind regards

  Ravi

• ODBC Server Bug BI - arithmetic operation resulted in an overflow

  I'm writing some really simple access to the Oracle BI Server ODBC driver .NET code and it doesn't work at all.  I have connected properly, however it seems that everything I try to do related to obtaining the information of database spits out upward an error 'arithmetic operation resulted in an overflow.

  Here is the code:

  Dim ConnectString As String
  Dim FactoryType As String
  Sun factory System.Data.Common.DbProviderFactory
  Var connection as System.Data.Common.DbConnection = Nothing
  Var donneestables As System.Data.DataTable = Nothing
  Dim err As String = «»
  Dim nl As String = Chr (13) + Chr (10)

  Try
  '-------------------------------------
  'Connect to the database via ODBC
  '-------------------------------------
  ConnectString = "DSN = BSODBC_7; UID = TheUser10; "pwd = *".

  FactoryType = "System.Data.Odbc".
  Plant = System.Data.Common.DbProviderFactories.GetFactory (FactoryType)

  Connection = Factory.CreateConnection
  Connection.ConnectionString = ConnectString
  Connection.Open)

  '--------------------------------------------------
  "Ask for a list of the tables in the database
  ' * Tried both unrestricted and without
  '
  "ERROR on this line:
  ""Arithmetic operation resulted in an overflow.""
  '--------------------------------------------------
  Donneestables = Connection.GetSchema ("Tables")

  '--------------------------------------------------
  'Display the list of tables on the screen in a grid.
  "If it was successful.
  '--------------------------------------------------
  OnScreenGrid.AutoGenerateColumns = True
  OnScreenGrid.DataSource = donneestables

  Catch ex As Exception
  '-------------------------------------
  "Report this error.
  '-------------------------------------
  ERR = e.g. Message
  Otherwise (e.g.) InnerException is nothing) then
  Otherwise (e.g.) InnerException.Message is nothing) then
  ERR = err + nl + nl + ex. InnerException.Message
  End If
  End If
  MsgBox (err, MsgBoxStyle.OkOnly + MsgBoxStyle.Exclamation, "Error")

  Finally

  '-------------------------------------
  'Clean up and close the DB connection '.
  '-------------------------------------
  Otherwise (connection is nothing) then
  Connection.Close
  Connection.Dispose)
  Connection = Nothing
  End If
  
  End Try

  
  Any thoughts?  Is this a known bug?  Is there a solution?

  Thank you, it seems that the error occurs in several places when NULLs exist in the data.  This seems to be a known bug.  Nice.

• How to perform arithmetic operation on adf.currentDateTime

  Hello

  Our health care system, we perform a lot of operations with datetime (especially for babies patients) data.

  For example, we need to start bind variable with adf.currentDateTime plus/minus 30 minutes, 2 hours, 8 hours etc etc...

  I tried to set to the default value, an expression such as

  adf.currentDateTime - 1/48 (30 minutes)

  adf.currentDateTime - 2/24 (2 hours)

  But I get the following error:

  No signature of method: java.sql.Timestamp.minus () applies to the types of arguments: (Java.Math.BigDecimal) values: [0.0208333333] possible solutions: minus (int), UNMIS (java.util.Date), UNMIS (int), find(), more (int), is (java.lang.Object)

  I also tried a groovy expression

  adf.currentDateTime - 2.hours

  but without success

  I see adf.currentDateTime, which define a method in the ViewObjectImpl class, but of course our system, we need to define a method more complex that can receive different arguments for the minutes, hours and even any other argument to datetime data to perform the previous operation.

  There is an easier way to set the default values using groovy expressions only without the need of the add methods of the ViewObjectImpl class?

  I use Jdev 12.1.3 on win7 64 bit

  Thank you

  I tried to set to the default value, an expression such as

  adf.currentDateTime - 1/48 (30 minutes)

  adf.currentDateTime - 2/24 (2 hours)

  Well, this isn't like in Oracle DB

  You can use some arithmetic java.util.Calendar, java.util.Date and similar items, but probably not fractions, for example:

  def now = Calendar.instance
  def tomorrow = now.time + 1
  return new java.sql.Timestamp(tomorrow.time)
  

  I also tried a groovy expression

  adf.currentDateTime - 2.hours

  but without success

  It will not work without proper import.

  For example:

  import groovy.time.TimeCategory
  def now = new Date()
  use(TimeCategory) {
      after2h = now + 2.hours
      return new java.sql.Timestamp(after2h.time)
  }
  

  Dario

• Arithmetic operation

  Hello, these days, I find a problem with this operation and I can't find the way to resolved, I think the problem is that I can't use integers in Java Card.
  
  I do with 2 divisions, and there's a moment that Wicks Chang because wear I guess.
  
  short temp = (short) (ofini/2);
  
  I tried to solve this
  
  short temp = (short) ((ofini/2) & 0xF7);
  
  but it solves not all the numbers I can use with "ofini" happening at 0 - JJ.
  
  Is there a solution? If I solve it, I'd be able to finish my applet... XD

  Why divide by 2? Use travel instead. It's faster.

  signed pit: short divided = value > 1; (carpet on the left with the sign bit)
  divide unsigned: short udivided = value > 1; (left-pads with zero bits)

  multiply by 2: using left shifts, (than right buffers of operation with zeros): short multiplied = value<>
  multiply by 5 just an addition is needed for: short fivetimes = (value<2) +="">

  This is a basic optimization which also works with many other languages including C and assembler.

• Find the arithmetic operator

  Hello

  My batch of Document of mathematical equations. So I applied arithmetic operators for character style but couldn't find the ' + '.

  app.findGrepPreferences.findWhat = ' + ';.

  And also I tried this method, I got that result ("−") but I can't find the ('+')

  var test = string.fromCharCode(0)) (8722).

  app.findGrepPreferences.findWhat = test;

  Someone help me

  Kind regards

  Barry B.

  Try this...

  app.findGrepPreferences.findWhat = "\\+";
  

• Replacement of the NULL values to zero to perform an arithmetic operation on column

  Hello
  
  Please enlighten me how to achieve this.
  
  I want to add on the Salary column operation in the EMP table.
  Some values are null in the salary column. I want to replace the value null by zero and we'll do the addition.
  
  
  As: I want to add 15 where for emp 1 and his sal is null.
  It should be 0 + 15 = 15
  
  
  Thank you
  Madam.

  Or maybe you wanted to say:

  NVL(sal,0)+15
  

  depends on if your summation by rows or simply want to add to the value of the current row.

• Problems with arithmetic operations

  I do mathematical operations on my tables to retrieve the average records.
  I have a table of insurance useda table of connected clients, and client.
  Now, I would like to extract the average number of incidents per year took place from the first strategy until today.
  
  If I run this query:
  
  SELECT (SUM (c.incFatti () + c.incSubiti ())) AS AVERAGE / * incFatti() is made by the customer, incSubiti() incidents suffered incidents * /.
  CLIENT c;
  
  I get 8, for example, I have a total of 8 incidents in my DB.
  Now, if I run it:
  
  SELECT ROUND (((SYSDATE - MIN (p.data_stipulazione)) / 365), 2)
  Polizza p;
  
  I receive 1.28, for example, a year and a few months since the creation of the first strategy until today.
  
  OK, 8 / 1.28 = 6.25 accidents per year and that's what I would get with a single query.
  The latter is:
  
  SELECT (ROUND)
  Sum (c.incFatti () + c.incSubiti ()) / / * the first query * /.
  (((SYSDATE - MIN (p.data_stipulazione)) / 365), 2) AS AVERAGE / * the second query * /.
  CLIENT c, polizza p
  
  But I get 31.26! When I make a mistake?

  Try

  select round (n1 / average, 2)
    from (select sum (c.incfatti () + c.incsubiti ()) n1 /* from the first query */
                                                        from cliente) c,
         ( (select ( (sysdate - min (p.data_stipulazione)) / 365) as average /* from the second query */
                                                                            from polizza))
  

• Compare non-numeric data by using arithmetic operations

  Hello
  
  Anyway is to compare non-numeric data in a table to a number.
  
  To run a query like
  

  SELECT rank_id 
                                        FROM   mas_rank
                                        WHERE  rank_code > 26 

  Rank_code contains digital and non-digital data
  
  
  Thanks for the help

  Yes, it will work if you just say > '26' see this demo:

  SQL> create table mas_rank(rank_id number,rank_code varchar2(2));
  
  Table created.
  
  SQL> insert into mas_rank values (100,'aa');
  
  1 row created.
  
  SQL> insert into mas_rank values (101,'ab');
  
  1 row created.
  
  SQL> insert into mas_rank values (102,'ad');
  
  1 row created.
  
  SQL> insert into mas_rank values (103,'ag');
  
  1 row created.
  
  SQL> insert into mas_rank values (104,'ac');
  
  1 row created.
  
  SQL> insert into mas_rank values (105,'22');
  
  1 row created.
  
  SQL> insert into mas_rank values (106,'25');
  
  1 row created.
  
  SQL> insert into mas_rank values (107,'26');
  
  1 row created.
  
  SQL> insert into mas_rank values (108,'27');
  
  1 row created.
  
  SQL> insert into mas_rank values (109,'aa');
  
  1 row created.
  
  SQL> insert into mas_rank values (110,'28');
  
  1 row created.
  
  SQL> SELECT rank_id
    2                                        FROM   mas_rank
    3                                        WHERE  rank_code not in ('ab','ad','ag')
    4                                                 and rank_code > 26;
                                                 and rank_code > 26
                                                     *
  ERROR at line 4:
  ORA-01722: invalid number
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  SELECT rank_id
    2                                        FROM   mas_rank
    3                                        WHERE  rank_code not in ('ab','ad','ag')
    4*                                                and rank_code > '26'
  SQL> /
  
     RANK_ID
  ----------
         100
         104
         108
         109
         110
  
  SQL>
  

  Concerning
  Girish Sharma

• First HP: Common Operations with 2D and 3D vectors

  I have not found a way to work with vector quantities 2D and 3D common representing the position, strength, speed, etc..  in a manner similar to the way in which the first HP manages complex numbers.  I used the HP-48 and the HP-50 where these useful functions were available to my students in engineering, but seems to be missing in the first HP.  The TI - 89 Titanium also.    With the first HP I can add two complex numbers of the mixed formula ("real/imaginary" and "polar"), but have not found a way to do with vectors with real components in two or three dimensions.

  

  What am I missing or what is hopefully a future update?

  You are right - it is something not supported at this time. He will very probably be added at some point however.

• Solve complex equations stored on the HP50g

  Hello

  I stored the 2 equations Δ & K, but when I try to solve in the Num. solv. I get the message bad guess (es). I searched on google and it seems that it is because I work with complex numbers and the num solv. can't handle them.  However, I have not found the way to solve them. I use two equations, so it would be great if you could help me find a solution where I can solve them enter the values of the variables, just like with the num solv.
  

  

  FYI, make sure you go back and read your old post... the method to enter the equations with existing values using EQW is demonstrated in the last entry and unfortunately was added after you received the answer to your question...

  Here's the simplest method

  all four variables stored... S11, S12, S21, S22,

  Press the following keys...

  EVAL

  selection for DELTA key

  Come in

  EVAL

  selection for K key

  Come in

  There is another method by using the MENU (30)

  However, I have to work on the process I'm not as familiar with the algebraic entry mode...

  unless another Member of the forum knows how to use MENU (30) in algebraic mode and can post the post-processing.

  will try to send the process later tonight...

  MENU 30 is generally described beginning on page 6-26 of the 50G (not the user manual) User Guide

  the section is the title "Submenu SOLVR"

  the manual describes the process as

  MENU (74)

  Come in

  Press F1 (root)

  Press F1 (solvr)

  MENU (30)

  Come in

  is direct access