Assign months within a range of dates (by almost every day in a given month)

Similar Questions

• Search a directory of data and display the data that is within the range of dates

  Hello

  I have a full idrectory of data from overtime, and I think of search in the directory and display the data files for specific dates. I only started this encoding yet but I figure I'll take the brain of some SMEs here labview and start in the right direction. My goal is to go through a comprehensive directory of data taken for a month or MORE csv files and select the data to process and display office files the date of its registration. If I take the data of last week, last month or last minute, it should just treat as an exact or more.

  Please help me get started on the right foot

  End date will be probably greater than the start date, right? So, end date must connect at the entrance to the upper limit. Then wire in the range? to the conditional terminal of a tunnel of conditional indexation.

  Lynn

• How to get the number of days in a month of belonging to a range of dates

  Hi, I'm going crazy around a problem, I have 2 dates and one month I wanto to retrieve the number of days belonging to the months that fall within the range.
  
  for example:
  
  month of January 2011. begin_date = January 11, 2011, May 30, 2011 end_date result is 21
  month of January 2011. begin_date = December 11, 2010, result of end_date, January 10, 2011 10
  month January 2011 .begin_date = 2 February 2011, end_date may 25, 2011 result 0
  month of January 2011. begin_date = January 3, 2011, January 5, 2011 result DATE END 3
  
  and so on...
  
  I appreciate any suggestion
  Thank you
  
  
  Andrea

  Something like that... ?

  SQL> with t as
    2  (select  to_date('11/01/11','dd/mm/yy') from_dt,
    3           to_date('30/05/11','dd/mm/yy') to_dt,
    4           'Jan-11' mnth from dual)
    5  select least(last_day(to_date(mnth,'Mon-yy')),to_dt) -
    6         greatest(to_date(mnth,'Mon-yy'),from_dt) cnt
    7  from t  ;
  
         CNT
  ----------
          20
  

  If 0 is also expected...

  SQL> with t as
    2  (select  to_date('11/01/11','dd/mm/yy') from_dt,
    3           to_date('30/05/11','dd/mm/yy') to_dt,
    4           'Jan-11' mnth from dual union all
    5           select  to_date('11/01/11','dd/mm/yy') from_dt,
    6           to_date('30/05/11','dd/mm/yy') to_dt,
    7           'Jan-12' mnth from dual
    8           )
    9  select from_dt,to_dt,mnth,
   10         greatest(
   11              least(last_day(to_date(mnth,'Mon-yy')),to_dt)
   12              -
   13              greatest(to_date(mnth,'Mon-yy'),from_dt)
   14                 ,0) cnt
   15  from t;
  
  FROM_DT   TO_DT     MNTH          CNT
  --------- --------- ------ ----------
  11-JAN-11 30-MAY-11 Jan-11         20
  11-JAN-11 30-MAY-11 Jan-12          0
  

  Published by: JAC on February 9, 2012 19:22

• Extend a range of dates

  I have the following query, which works without problem. This will expand the range of dates, proof of identity, in a list of dates for me:
  

  SELECT     j_id
            ,  date_1
             + LEVEL
             - 1
               datum
  FROM       (SELECT 123 j_id, TO_DATE('01/01/2012', 'DD/MM/YYYY') date_1, TO_DATE('31/01/2012', 'DD/MM/YYYY') date_2
              FROM   DUAL)
  CONNECT BY LEVEL <= (  date_2
                       - date_1
                       + 1);

  How can I do this for more than 1 sheet well? for example
  

  SELECT     j_id
            ,  date_1
             + LEVEL
             - 1
               datum
  FROM       (SELECT 123 j_id, TO_DATE('01/01/2012', 'DD/MM/YYYY') date_1, TO_DATE('31/01/2012', 'DD/MM/YYYY') date_2
              FROM   DUAL
              UNION
              SELECT 456 j_id, TO_DATE('01/02/2012', 'DD/MM/YYYY') date_1, TO_DATE('29/02/2012', 'DD/MM/YYYY') date_2
              FROM   DUAL)
  CONNECT BY LEVEL <= (  date_2
                       - date_1
                       + 1);

  Thank you.

  Hello

  Here's one way:

  WITH   cntr          AS
  (
       SELECT     LEVEL - 1     AS n
       FROM     (
                SELECT  MAX (date_2 - date_1)     AS max_dif
                FROM    table_x
            )
       CONNECT BY     LEVEL <= 1 + max_dif
  )
  SELECT       x.j_id
  ,       x.date_1 + c.n
  FROM       table_x  x
  JOIN       cntr        c  ON  c.n <= x.date_2 - x.date_1
  ORDER BY  x.j_id
  ,            c.n
  ;
  

  If you do any filtering, it may be more effective to do this first. Start the WITH clause with a subquery that performs filtering, then use this result placed instead of your full table in the view online within the cntr as well as in the main query.
  For example:

  CREATE TABLE  table_x         AS
           SELECT 123 j_id, TO_DATE('01/01/2012', 'DD/MM/YYYY') date_1, TO_DATE('31/01/2012', 'DD/MM/YYYY') date_2
              FROM   DUAL
              UNION
              SELECT 456 j_id, TO_DATE('01/02/2012', 'DD/MM/YYYY') date_1, TO_DATE('29/02/2012', 'DD/MM/YYYY') date_2
              FROM   DUAL
  UNION         SELECT 999,          TO_DATE ('01/01/2013', 'DD/MM/YYYY'),     TO_DATE ('31/12/2013', 'DD/MM/YYYY')     FROM dual
  ;
  
  WITH     filtered_data     AS
  (
       SELECT     *
       FROM     table_x
       WHERE     date_1     < TO_DATE ('01/07/2012', 'DD/MM/YYYY')
  )
  ,        cntr          AS
  (
       SELECT     LEVEL - 1     AS n
       FROM     (
                SELECT  MAX (date_2 - date_1)     AS max_dif
                FROM    filtered_data
            )
       CONNECT BY     LEVEL <= 1 + max_dif
  )
  SELECT       f.j_id
  ,       f.date_1 + c.n
  FROM       filtered_data  f
  JOIN       cntr              c  ON   c.n  <= f.date_2 - f.date_1
  ORDER BY  f.j_id
  ,            c.n
  ;
  

  Published by: Frank Kulash, 27 January 2012 10:10
  Posted filtering example

• How to define the range of data to a strict typdef through the control reference

  Hello world

  I'm trying to define the range of data to a strict typdef through the reference of the order, when I do, I get an 'error of property node.

  Is it possible to set the range of the strict typdef.

  Thank you

  Vignesh

  Vignesh1987 wrote:

  I'm trying to define the range of data to a strict typdef through the reference of the order, when I do, I get an 'error of property node.

  Is it possible to set the range of the strict typdef.

  Try to set the original control (type-def) and not its instances... to open the reference of the original type-def command, use 'Open VI reference'.

  Published:

  These properties are not available with STRICT TYPE DEF.

  a. data entry limits: increment property

  b. data entry property of limits: Maximum

  c. property limits: Minimum for the data entry

• Filter for table data, the range of data obtained and defined 2D

  I produce data of an ultrasonic sensor at 1 K Hz, and there is a lot of data (data points range of 0 to 10). However, in some cases when I know that the data should be about 7 (for example) I get outliers (about 9 and 10). Is it possible to define a filter for data in the defined range.

  I averaged the data to get an average value, and outliers are distorting. In the worst case, my outliers are 30 to 40% of the data generated. I created a filter to sort the data and, taken from the lowest value. I stop the loop when data reaches a value greater then 9. But this seems to take a long time (because the loop checks for each data point and there are 1000s of them).

  Is there a better way to filter data and define a predefined table range to collect?

  I enclose my filter.vi... and a set of samples of my previous data. The ranges of data of 10-8 and would like to have the range 7.5 to 8.5 to consider. The sensor records tension here and the problem can be solved by installing a different type of sensor, but if a filter in LabView can due it, the sensor that we use now is absolute.

  I am in kind of emergency, my design in unfinished because of this problem, if someone can find some time to share some suggestions, I will be grateful.

  Thanks in advance.

  See attachment.  I have incorporated the data you've posted in the vi.  It doesn't seem like any data were less than 8.7 or so, so I modified the scope so it would be a few points on average.  Some games were completely out of reach while the average came back like NaN (not a number) due to a division by zero.

• How to filter for a range of dates calendar events in OS10

  In earlier versions of BlackBerry, I used blackberry.find.FilterExpression to filter the events calendar for a specific range of dates.

  However for BlackBerry OS10 I scoured the web to find a way to do it. I found:http://developer.blackberry.com/html5/apis/blackberry.pim.calendar.calendarfindoptions.html

  I also googled a lot of other sites, but I am unable to understand how to use CalendarFindOptions to refine the calendar of events of a specific timetable. For example, the current week or the next 7 days.

  I found this code example...
  Function listEvents (limit) {}
  Calendar var = blackberry.pim.calendar;
    var CalendarFindOptions = calendar. CalendarFindOptions;
    var findOptions = {}
  'Sort': [{}
  "fieldName": CalendarFindOptions.SORT_FIELD_SUMMARY.
  'desc': false
  }],
  'detail': CalendarFindOptions.DETAIL_AGENDA,
  'limit': limit
  };

  But unable to find examples how adequately limited by date?
  I'm guessing that something like this:
  'Start': new Date (' January 1, 2013, 13:00 "): CalendarFindOptions.SORT_FIELD_START.
  'end': new Date (' January 1, 2013, 16:00 "): CalendarFindOptions.SORT_FIELD_STOP.

  But it is an assumption and does not work I can find no example of how do

  Any help would be appreciated

  See the example for pimcalendar on Github:

  https://github.com/BlackBerry/BB10-WebWorks-samples/tree/master/pimcalendar

  You can find the JS to set filters of beginning and end starts here:

  https://github.com/BlackBerry/BB10-WebWorks-samples/BLOB/master/pimcalendar/index.html#L107

• Report with 2 settings of filtering by day and 3 measures for a range of dates

  Hello

  I need to establish a relationship with the following criteria:

  (a) I have 5 settings

  (b) tell of 2 measures of data should be based on a date 01/01/2015

  (c) rest of 3 data measures should be based on a range of dates say 01/01/2015-31/01/2015

  No idea how to achieve this?  If so please help me.

  Thanks in advance

  LonaD

  You cannot filter the reports by using the filter function in the formula in the column?

• At least a record exists in details that cover the range of dates

  Oracle version:

  Oracle Database 11g Express Edition Release 11.2.0.2.0 - Production

  Hi gurus

  I'm stuck with a scenario and your employees need help to solve this problem.

  I have the following table:

  Insertion and table creation

  drop table ident;

  create table ident

  (

  agreement_id number (5),

  ident_pk number (5),

  Date of Cov_effective_date,

  Date of Cov_termination_date

  );

  -------------------

  Insert ident

  (

  Select 100,1,to_date('2013-01-01','YYYY-MM-DD'), double to_date('2013-01-31','YYYY-MM-DD')

  Union of all the

  Select 200,2,to_date('2013-01-01','YYYY-MM-DD'), double to_date('2013-12-31','YYYY-MM-DD')

  Union of all the

  Select 300,3, to_date ('2013-03-01 ',' YYYY-MM-DD '), double null

  );

  Query on table

  Select * ident;

  Agreement_id ident_pk Cov_effective_date Cov_termination_date

  100	1	13/01/01	13/01/31
  200	2	13/01/01	13/12/31
  300	3	13/03/01

  ------------------------

  Drop table ident_dtl;

  create the table ident_dtl

  (

  ident_pk number (5),

  ident_dtl_pk number (5),

  date of effective_date,

  date of termination_date

  );

  ---------------------------------

  insert into ident_dtl

  (

  Select 1-ident_pk, 10 ident_dtl_pk, to_date('2013-01-01','YYYY-MM-DD') effective_date, to_date('2013-01-31','YYYY-MM-DD') termination_date of double - to agreement_id = 100

  Union of all the

  Select 1,11,to_date('2013-01-01','YYYY-MM-DD'), to_date('2013-01-30','YYYY-MM-DD') of double - to agreement_id = 100

  Union of all the

  Select 2,12,to_date('2013-01-01','YYYY-MM-DD'), to_date('2013-01-30','YYYY-MM-DD') of double - for agreement_id = 200

  Union of all the

  Select 2.13, to_date('2013-01-01','YYYY-MM-DD'), double to_date('2013-01-15','YYYY-MM-DD') - for agreement_id is 200

  Union of all the

  Select 3.14, to_date('2013-01-01','YYYY-MM-DD'), double to_date('2013-01-15','YYYY-MM-DD') - for agreement_id = 300

  Union of all the

  Select 3.15, to_date('2013-01-01','YYYY-MM-DD'), double to_date('2013-01-15','YYYY-MM-DD') - for agreement_id = 300

  );

  Query on table

  Ident_pk Ident_dtl_pk Effective_date Termination_date
  

  1	10	13/01/01	13/01/31
  1	11	13/01/01	13/01/30
  2	12	13/01/01	13/01/30
  2	13	13/01/01	13/01/15
  3	14	13/01/01	13/01/15
  3	15	13/01/01	13/01/15

  
  

  Result of the will

  Agreement_Id Ident_pk

  200                                        2

  300                                        3

  ------------------------------------

  There is a single entry in ident against agreement_id and Ident_pk and if you can see that ident_pk is also present in the child table. My requirement is that at least 1 effective_date and child termination_date table must be match/equal to the parent table that is ident cov_effective_date and cov_termination_date against the same column of Ident_pk.

  for example:

  See the data in Ident_pk = 1, a = cov_effective_date 13/01/01 and its cov_termination_date = 13/01/31 and in the details table against column Ident_pk = 1, you can find that at lease 1 combinaisondes date match against Ident_pk = 1

  If you see Ident_pk = 2, then you can't find all the effective_date and termination_date against its corresponding cov_effective_date and termination_date Ident_pk...

  Same as 3

  -----------

  Summary is that there are date range in the ident against agreement_id and Ident_pk table and at least a range of dates even should be exist in detail table is ident_dtl against Ident_pk and if not then show that agreement_id and Ident_pk .

  I made this task using PL/SQL, but I think that there is a way to do the same task in SQL. Guide and if you have any questions then please let me know. Thank you

  Concerning

  Shu

  
  

  Hello

  To be considered as a football game, the same line in ident_dtl must have effective_date and termination_date correspondence?

  If so, a solution is:

  SELECT i.agreement_id

  i.ident_pk

  Ident I have

  LEFT OUTER JOIN ident_dtl d.ident_pk d = i.ident_pk

  AND d.effective_date = i.cov_effective_date

  AND d.termination_date = i.cov_termination_date

  WHERE d.ident_pk IS NULL

  ;

  Another pure SQL approach to such problems is to use an EXISTS subquery.

• code to run a process for a range of dates, ignoring Sundays and holidays

  I have a proc by name (P_NAME, P_BIZDATE) INS_INVENTORY (P_NAME IS OF TYPE VARCHAR2, P_BIZDATE IS PRESENT). Actuallythis proc runs every day in our Planner. I had to make changes to this procedure. Now, I need to run this proc for P_BIZDATE taking the dates of 1 January 09 to 31 December 09. We also have a table by its PT_HOLIDAYS name, which consists of the list of holidays from 1 January 2009 to 31 December 2009. Now I need a code or a process through which I can run this proc 1 January 09 to 31 December 09 and also this proc should not be run 'SUNDAY' and public holidays as specified in the PT_HOLIDAYS table
  
  CREATE TABLE PT_HOLIDAYS
  (
  HOLIDAY_DATE DATE NOT NULL,
  DISPLAY_NAME VARCHAR2 (35 BYTE) NOT NULL,
  )
  
  Insert into PT_HOLIDAYS
  (HOLIDAY_DATE, DISPLAY_NAME)
  Values
  (TO_DATE (1 January 2009 00:00:00 ',' DD/MM/YYYY HH24:MI:SS'), "New Year Day");
  Insert into PT_HOLIDAYS
  (HOLIDAY_DATE, DISPLAY_NAME)
  Values
  (TO_DATE (25 May 2009 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), "Memorial Day");
  Insert into PT_HOLIDAYS
  (HOLIDAY_DATE, DISPLAY_NAME)
  Values
  (TO_DATE (4 July 2009 00:00:00 ',' DD/MM/YYYY HH24:MI:SS'), 'July 4');
  Insert into PT_HOLIDAYS
  (HOLIDAY_DATE, DISPLAY_NAME)
  Values
  (TO_DATE (7 September 2009 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), 'Labor Day');
  Insert into PT_HOLIDAYS
  (HOLIDAY_DATE, DISPLAY_NAME)
  Values
  (TO_DATE (26 November 2009 00:00:00 ',' DD/MM/YYYY HH24:MI:SS'), 'Thanks Giving Day');
  Insert into PT_HOLIDAYS
  (HOLIDAY_DATE, DISPLAY_NAME)
  Values
  (TO_DATE (26 December 2009 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), 'Christmas');
  COMMIT;
  
  
  Please advice

  Like this?

  declare
  start_date date := to_date('01/01/2009','MM/DD/YYYY');
  end_date date :=to_date('12/31/2009','MM/DD/YYYY');
  cur_date date;
  total_run number := (end_date - start_date)+1;
  holiday number := 0;
  begin
  for i in 1..total_run loop
       cur_date := start_date + (i-1);
            begin
                 select 1 into holiday from PT_HOLIDAYS where HOLIDAY_DATE = cur_date;
            exception
                 when no_data_found then
                 holiday:=0;
            end;
       if to_char(cur_date,'DY') != 'SUN' and holiday != 1 then
            dbms_output.put_line(cur_date||'-'||to_char(cur_date,'DY'));
            --INS_INVENTORY( , cur_date)
       end if;
       end loop;
  end;
  /
  

  Kind regards
  Prazy

  Published by: Prazy on March 29, 2010 12:39

• I want my mail hot calendar to print like a monthly calendar, as it appears on the screen. The only option I get is a list of every day. How to change that?

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  I want my mail hot calendar to print like a monthly calendar, as it appears on the screen. The only option I get is a list of every day. How to change that?

  I could get a link that I sent to my work email, but I wouldn't have to so roundabout. I should be able to go on my hotmail home account, update my calendar and print it like a standard monthly calendar. Help.

  Hello

  Please see the post below for the links to support for all popular Microsoft e-mail programs.

  Where can I get help with my questions by e-mail? (Windows 7)-Microsoft Answers:
  http://answers.Microsoft.com/en-us/Windows/Forum/Windows_7-networking/where-do-i-get-help-with-my-email-questions/461490c7-302b-4cc8-bcd9-127e177d71c3

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• Is it possible to set up a computer to turn on and turn off itself every day or on any selected date?

  Is it possible to set up a computer to turn on and turn off itself every day or on any selected date?

  Mine is a HP G72-b27CL running Windows 7 64 bit laptop.

  Yes can schedule a task to start the system using the option shown in the screenshot below:

  

  You can schedule a task to turn the system off by as shown in the link below:

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• HI everyone, I paid almost 10 days ago, my supcripcion to plan for all the app elements, and after u date of my latest plan, any program is runing, always appear, your time taking, is late, please by the app with my adobe ID works correctly?

  HI everyone, I paid almost 10 days ago, my supcripcion to plan for all the app elements, and after u date of my latest plan, any program is runing, always appear, your time taking, is late, please by the app with my adobe ID works correctly?

  Photoshop Elements and Premiere Elements are NOT part of the cloud... you buy a serial number, not a subscription, and you enter the serial number during installation

  If you don't want to say things, read below

  Your subscription to cloud shows correctly on your account page?

  If you have more than one email, you will be sure that you use the right Adobe ID?

  https://www.adobe.com/account.html for subscriptions on your page from Adobe

  .

  If Yes

  Some general information for a subscription of cloud

  Cloud programs don't use serial... numbers you, connect you to your cloud account paying to download & install & activate... you may need to sign out of the cloud and restart your computer and log into the cloud for things to work

  Sign out of your account of cloud... Restart your computer... Connect to your paid account of cloud

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  -http://helpx.adobe.com/creative-cloud/kb/sign-in-out-creative-cloud-desktop-app.html

  -http://helpx.adobe.com/x-productkb/policy-pricing/activation-network-issues.html

  -http://helpx.adobe.com/creative-suite/kb/trial--1-launch.html

  -ID help https://helpx.adobe.com/contact.html?step=ZNA_id-signing_stillNeedHelp

  -http://helpx.adobe.com/creative-cloud/kb/license-this-software.html

  .

  If no

  This is an open forum, Adobe support... you need Adobe personnel to help

  Adobe contact information - http://helpx.adobe.com/contact.html

  Chat/phone: Mon - Fri 05:00-19:00 (US Pacific Time)<=== note="" days="" and="">

  -Select your product and what you need help with

  -Click on the blue box "still need help? Contact us. "

• In recent months, every day when I open photoshop, it says the license is not good and I need to contact adobe support...

  In recent months, every day when I open photoshop, it says the license is not good and I need to contact adobe support...

  The WHO and wher can I contact someone who can solve my problems?

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  Go to this direct link, then click on 'Chat '. https://helpx.Adobe.com/contact.html?step=PHSP-PHXS_adobe-ID-signing-in_stillNeedHelp

  Benjamin

• How to generate date thru sysdate and day of the week

  Hello world!

  Please give me a hand with this:

  I need calculate a date thru sysdate and day of the week.

  For example:

  SYSDATE: 22/08/2013

  DAY: TUESDAY

  Result: 27/08/2013 (the date for Tuesday next from today ' hui).

  Another example:

  SYSDATE: 22/08/2013

  DAY: FRIDAY

  Result: 23/08/2013 (the date for Friday next today).

  My version of oracle's 8i (I work with a legacy database).

  Thanks in advance! ... and sorry for my English

  Search the NEXT_DAY function it does exactly what you want