How to get the number of days in a month of belonging to a range of dates

Similar Questions

• Get the number of days in a month based on the month and year of fields

  I have a column in my form which lists the days in a month. I want to configure a hidden field that calculates the total number of days in a month, based on the month and year of the field inputs. The number of days will determine what appears on the column. For example, if I put 4 months, and 2016 in the field of the year, I get 30 in the hidden field. Thus, on the column 'Day', I'll have numbers 1-30. Or if I put 2 months and 2016 in the field of the year, I get the 29 in the hidden field. If the numbers 1-29 appears in the column 'day '.

  Found this on some forum javascript code:

  //Month is 1 based
function daysInMonth(month,year) {
   return new Date(year, month, 0).getDate();
}

//July
daysInMonth(7,2009); //31
//February
daysInMonth(2,2009); //28
daysInMonth(2,2008); //29

  I do not know how to convert this code in JavaScript to adobe and don't really know how to use it. All I know how to do is to configure the field values for the field month and year as variables. I am a novice programmer and would appreciate it really all the help I can get. Thank you in advance!

  The code seems to be JavaScript and runs as needed by using the JavaScript console.

  I would like to consider making more general code, so if you have a date string that includes at least the month and year we could just call the function and get the number of days for that month.

  The following script will calculate the number of days in a month, by using at least the month and year values can display the result on the JavaScript console and all of the value field for the field that has this code as the custom calculation Script.

  function daysInMonth (oDate) {}
  return new Date (oDate.getFullYear (), oDate.getMonth () + 1, 0) .getDate ();
  }

  nMonth var = this.getField("Month").valueAsString; get the value of month;
  nYear var = this.getField("Year").valueAsString; get the value of the year;

  Event.Value = "";

  If (nMonth! = "" & nYear!) = "") {}
  var MyDate = util.scand ("' / mm/yyyy ', nMonth +" / "+ nYear); convert to date object;
  var nDaysInMonth = daysInMonth (MyDate); get the number of days;

  Console.Open (); Open the JavaScript console;

  Console.clear(); clear the console;

  Console.println ("Days in" + nMonth + ":" + nDaysInMonth); show days in month;

  Event.Value = nDaysInMonth; Set the value of the field;

  }

• How to get the number of days

  Hai bloggers,
  See us have 365 days a year for all first half we'll have 180 + days (if we choose first half as the guest and we select week as guest number and the last date of this particular week must indicate in the report) and the number of days until this date or a week should also display... If we choose the second half and half week number it should show number of days until this week and more Date of this issue of the day week should be from 1 to 180 + only way (July 1 m is 1)
  
  Thank you

  You must use the timestampdiff function to calculate the number of days. One of the way to calculate is how

  cases where "Time". "" Calendar semester "= 1 then timestampdiff (SQL_TSI_DAY, CAST (EVALUATE ('TO_DATE (%1, %2)','' 01-01 |' @{YEAR} {2010}',"DD-MM-YYYY") AS DATE), cast OFF (EVALUATE ('TO_DATE' (1%, 2%), 30-06' |' @{YEAR} {2010}',"DD-MM-YYYY") AS DATE)) else timestampdiff (SQL_TSI_DAY, MOUNT (EVALUATE ('TO_DATE (%1, %2)','01-07' |' @{YEAR} {2010}',"DD-MM-YYYY") AS DATE), cast OFF (EVALUATE ('TO_DATE' (1%, 2%),' 31-12 |' @{YEAR} {2010}',"DD-MM-YYYY") AS DATE)) end

  If you want to calculate between the 1st day of the half and the last date a week then after

  cases where "Time". ' ' Calendar semester ' = 1 then timestampdiff (SQL_TSI_DAY, CAST (EVALUATE ('TO_DATE (%1, %2)','01-01' |' @{YEAR} {2010}', 'DD-MM-YYYY') AS DATE), MAX (MAX ("Time".) "Calendar Date"))) else timestampdiff (SQL_TSI_DAY, CAST (EVALUATE ('TO_DATE (%1, %2)','01-07' |' @{YEAR} {2010}', 'DD-MM-YYYY') AS the DATE), MAX (MAX ("Time".) " End Calendar Date")))

  Hope that it will answer your question

  Thank you
  Phani.

• How to calculate the number of days/weeks/months between 2 dates?

  Hello
  
  I would like to know how to calculate the number of days/weeks/months between 2 dates in OBIEE 11 g, for example, I have 26/05/2013 and 19/05/2013, then I want to get 7 days.
  
  Thank you!
  Jamie

  Hi Jamie,

  Through this links...

  http://www.bravesoft.com/blog/?p=682
  http://twobiee.blogspot.in/2012/01/working-with-date-differences.html

  Mark as correct it allows u...
  Thank you...

• Get the number of days, months and year

  Hi all
  
  I'm using OBIEE 11 g. I have a line of dash for year (2010, 2011, etc.) and months (Jan, Feb,..., Dec). How can I get the number of days in a given month and year in my report?
  
  For example, if I choose to Jan & 2011, I'd get 31 and 356. And if I choose Feb & 2011, I would get 28 and 356.
  
  Thank you!

  I have something more good option here... Try to use this

  DAYOFMONTH (TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, CURRENT_DATE)))

  This will give you the days for the month in progress (Oct 2011) after calculating the last day of each month... Similary dynamically pass the value Date or month... You will need to modify this function but shud be simple. Hope this helps :)

• How to get the number of fonts online

  Hi all

  can you give me solution to the following:

  How to get the number of fonts on a line.

  Ex

  BlackBerry Support 'Community' is supported for my career

  in this line, I want to ITALIC for the word 'Community '.

  Font.GetDefault (). Derive from wil give for total line...

  RichTextField does not?

  See this KB article

  http://supportforums.BlackBerry.com/T5/Java-development/format-text-in-a-RichTextField/Ta-p/445038

• How to get the number of entries in the navigation menu?

  

  How to get the number of entries in the navigation menu? Check the image. What it shows 8 number of customers and 10 products and 10 orders in the list. How to get it?

  --

  Thank you

  Hello

  Create items of the request saying, "CUSTOMERS", "PRODUCTS" and "ORDERS".

  Create the application process that defines these items when loading the page for example

  C1 in select count (*) NTC (of customer_table)

  loop

  : CUSTOMERS: = c1.cnt;

  end loop;

  C1 in select count (*) NTC (of products_table)

  loop

  PRODUCTS: = c1.cnt;

  end loop;

  C1 in select count (*) NTC (of orders_table)

  loop

  : ORDERS: = c1.cnt;

  end loop;

  Components shared Open-> Navigation bar and change:

  In the entry list Label-> customers & CLIENTS.]

• Calculate fees that pay based on the number of days in a month

  Hello

  I'm writing the BR to fresh wages, based on the number of days in the month.

  Fix(Jan:DEC)

  "Salary" = ("Annual salary"-> "BegBalance" / 12) * "workforce";

  The existing calculation was ' wages divided by months no .of (12) ", now instead of number months wages that need to be calculated ("BegBalance"/ No..) OF DAYS IN THE MONTH) * 12.

  Can someone pls guide me, how to begin writing the BR for 'No. DAYS OF THE MONTH.

  You can do an admin enter number of days in the month. I remember CL reminding me the rhyme thirty days has September - Wikipedia, the free encyclopedia

  Jokes aside, you can use SQL to get the number of days. You will get different options for SQL and Oracle.

  If you want to continue to do this in BR then

  Fix(Jan:DEC)

  IF (@ISMBR (SEP) OR @ISMBR (Apr) OR @ISMBR (Jun) OR @ISMBR (Nov))

  ("Salary" = ("annual salary"-> "BegBalance" / 30) * 12) * "workforce";

  ELSEIF (@ISMBR (Jan) OR @ISMBR (Mar) OR @ISMBR (May) OR @ISMBR (July) OR @ISMBR (Aug))

  ("Salary" = ("annual salary"-> "BegBalance" / 31) * 12) * "workforce";

  ELSE (@ISMBR (Feb))

  IF (@Remainder($CurrYr/4) == 0)

  ("Salary" = ("annual salary"-> "BegBalance" / 29) * 12) * "workforce";

  ON THE OTHER

  ("Salary" = ("annual salary"-> "BegBalance" / 28) * 12) * "workforce";

  ENDIF

  ENDIF

  ENDFIX

  Concerning

  Celvin

  http://www.orahyplabs.com

  Post edited by: CelvinKattookaran

• Function to return the number of days in a month?

  In one of my rules, I need to allocate an amount of benefits based on the number of days remaining in the calendar month.
  
  OPM does have a function that can provide me with the number of days in a calendar month?
  
  Thank you very much
  Isamu

  It is not a direct function to do this, however, it can be done with a bit of messing around. The following rules you will get the number of days of the month of the date of the date

  Basically, you get the first day of the month, add a month to the first day of the following month and then get the number of days between them, which will give you the number of days of the month of the date

  the month = ExtractMonth(the date)
  the year = ExtractYear(the date)
  the start of the month =MakeDate(the year, the month, 1)
  the start of the next month = AddMonths(the start of the month, 1)
  The number of days in the month = DayDifference(the start of the month, the start of the next month)
  

  These rules can be a little more compact, but it is basically how to do it.

• get the number of days of the week to sysdate

  Hi all

  my need is to get the number of the day of the week of sysdate.

  Here's how can I make it right now:

  Select to_char(sysdate,'Dy') t1 double

  But he returns the abbreviated name of the day of the week while I need number of days of the week.

  Please help me. Thanks in advance.

  Best regards

  --

  Marco

  Or if you want the ISO week (Monday = day 1):

  Select trunc (sysdate) - trunc(sysdate,'IW') + 1 double;

• How to find the number of days between 2 date elements in the XSLT file

  Hello
  
  I need to calculate the number of days between 2 date elements (type xs: date). Can you please direct me as to how I can do the same thing.
  
  I work in 11g and using XSLT 1.0. I tried several options but yet to get a solution for this. I think that this can be done also using XSLT 2.0, but who has not worked for me.
  
  Can someone please help with this problem, thanks in advance!
  
  Thank you
  Anju

  Hello

  Have you seen this message?
  Re: Get the Date difference between 2 values of date in days

  You can do in the XSLT file since the dates are in ISO 8601 format.
  http://www.w3.org/TR/NOTE-datetime

  Here is a sample XSLT...

  The XSLT above will result in * 4 * for the next entry...

  
  2012-01-11T00:00:00.000-05:00
  2012-01-15T00:00:00.000-05:00
  
  

  You can test this example here...
  http://xslttest.appspot.com/

  I hope this helps...

  See you soon,.
  Vlad

  It is considered good etiquette to the answerers rewards with points (as "useful" - 5 pts - or 'correct' - 10pts)
  https://forums.Oracle.com/forums/Ann.jspa?annID=893

• SQL query to get the number of days monthwise

  Hello
  I'm new to sql, can someone please tell me query to find the number of days between the two dates months wise.
  say
  FIRSTDATE last date
  21/03/2011-25/06/2011
  
  March April May June
  9 22 23 18

  Hello

  Welcome to the forum!

  Here's one way:

  WITH     all_dates     AS
  (
       SELECT     start_date + LEVEL - 1     AS a_date
       FROM     (
                 SELECT     TO_DATE ('21/03/2011', 'DD/MM/YYYY')     AS start_date
                 ,     TO_DATE ('25/06/2011', 'DD/MM/YYYY')     AS end_date
                 FROM     dual
            )
       CONNECT BY     LEVEL     <= end_date + 1 - start_date
  )
  SELECT       TO_CHAR ( TRUNC (a_date, 'MONTH')
              , 'fmMonth YYYY'
              )               AS month
  ,       COUNT (*)               AS num_days
  FROM       all_dates
  WHERE       a_date - TRUNC (a_date, 'IW')     < 5
  GROUP BY  TRUNC (a_date, 'MONTH')
  ORDER BY  TRUNC (a_date, 'MONTH')
  ;
  

  What is a 'working day '? I guess you mean every day except Saturday or Sunday, but the query aboveare sometimes figures less than you have asked:

  MONTH             NUM_DAYS
  --------------- ----------
  March 2011               9
  April 2011              21
  May 2011                22
  June 2011               18
  

  Are a few days working on Saturday or Sunday? How do you get the 22 working days in April 2011 and 23 in may?

  SQL is good at obtaining results with a variable number of rows, but you have to say exactly the desired number of columns when you write the query.
  If you really need the output of the way you said, with any number of columns, then watch in swing or a grouping of the chain . See the FAQ forum
  https://forums.Oracle.com/forums/Ann.jspa?annID=1535
  "4. How can I convert rows to columns.

• Compare and get the number of days since the same date field

  Hello
  
  I need to get the results in days when comparing the same field, date
  
  For example,.
  
  Primary_key_field Date_field
  100000002 1 January 10
  100000004 February 1st, 10
  100000005 30 April 10
  100000006 April 18, 10
  100000007 29 April 10
  100000008 May 1st, 10
  
  extract the first two date_field records based on the primary_key_field. (January 1, 2010 and February 1, 2010) and compare and find the difference and who appear in number of days, the same fetch two disks and do the same math... How can I achieve this... is it possible to make the SQL thro? Please help me solve this problem...
  
  Thank you and best regards,
  KBG.

  This is the query using functions oracle Analytics

  Primary_key_field Date_field
  100000002 1 January 10
  100000004 February 1st, 10
  100000005 30 April 10
  100000006 April 18, 10
  100000007 29 April 10
  100000008 May 1st, 10

  Select rn, date_field, next, next - date_field "Diff".
  de)
  ROW_NUMBER() SELECT over (ORDER BY primary_key_field) rn,
  date_field, LEAD (date_field) OVER (ORDER BY date_field) next
  FROM table_name)
  /

• How to get the number of bits of Windows?

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  How can I get the number of bits of Windows, the application of the LV is running on?

  By using the disabled conditional structure, I can get the number of bits of the application (if it is built in BT 32 or 64), but not the number of bits of windows.

  Thank you

  system variable 'PROCESSOR_ARCHITECTURE '?

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  Number of lines