Auto increase the lines of input text

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• How to concatenate strings with the lines of a text file

  Hello
  I tried concatenate strings with the lines of a text file, but something is wrong with my code and I belive is the agruments I use in the cycle for. If anyone can help me I will appreciate it very much.
  My code is:
  [code]@echo off
  the value "input=C:\Users\123\Desktop\List.txt".
  for /f "usebackq tokens = *" % in (' input % ') do)
  the value 'str1 = C:\some directory\ ".
  the value ' str2 = %% ~ F '.
  the value "str3 = .pdf".
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  echo.%STR4%
  ) [/ code]
  and the text file is something like:
  121122 [code]
  122233
  123344
  124455 [/ code]
  But I get only one wrong answer and I have to run it like 3 times to get a real result and it is a mistake, the first two are empty spaces and gives the third one as the last line of the text file but repeated n times, where n is the number of lines in the text file.
  Result:
  [code] C:\Users\123\Desktop>concatenate.bat
  C:\Users\123\Desktop>concatenate.bat
  C:\Users\123\Desktop>concatenate.bat
  C:\some directory\124455.pdf
  C:\some directory\124455.pdf
  C:\some directory\124455.pdf
  C:\some directory\124455.pdf
  C:\some directory\124455.pdf
  C:\Users\123\Desktop>[/code]
  So if anyone has an idea about what is wrong please let me know.
  Concerning
  -Victor-

  Hi Victor,

  This forum is dedicated to the support of the Office of consumer Windows (fonts, colors, personal settings).  Since your question is about programming and usually outside the context of most of the customers, I suggest you post your question in the forums as http://msdn.microsoft.com - the Microsoft network to users will be more adapted to help you in your quest.

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  I have a text file containing the lines...

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  1234

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  External table will do.

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  I get an error in ESTK

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  I will get the contents of the text/csv file in a string variable to no not as a file.
  
  EX: string var = "123\n234\n123\n3456\nsdfsd\n" this is \n in the new line.
  
  for that I have to get the total rows 5.
  
  Please advice.
  
  Thank you.

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• How to increase the line width

  I used PSE 7 for a couple of monthe, mainly for basic photo editing. I am

  try learning how to make graphic art a little for my business. The project, I am working is to brand cattle of the client, which is a simpleton with a X connected by one leg to the bottom of the T. Y there a way to increase the thickness of the lines without changing the proportions of all?

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• How to use substr and instr, where the line of input Multi text

  Hi all

  with

  data in the form of)

  Select ' Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234..' double val

  Union of all the

  Select 'Bill Johnson.Apartment 3 b. Sterling.VA.20166.3 Plaza Falke' of the double

  )

  Select

  regexp_substr (shipping_instructions, "[^ #] +' 1, 1") name

  , regexp_substr (shipping_instructions, "[^ #] +' 1, 2") address

  , regexp_substr (shipping_instructions, "[^ #] +' 1, 3") city

  , regexp_substr (shipping_instructions, "[^ #] +' 1, 4") State

  , regexp_substr (shipping_instructions, "[^ #] +' 1, 5") zip

  , regexp_substr (shipping_instructions, "[^ #] +' 1, 6") County

  FROM (select REGEXP_REPLACE (val, ' \.)) () [^.])', ' #\1 ") data shipping_instructions)

  (1)'Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234..'

  (2)'Bill Johnson.Apartment 3 b. Sterling.VA.20166.3 Falke Plaza. »

  "Mary America. 1234 Southridge Park Dr. Samna Lorie. MO.31234..'

  NAME ADDRESS CITY ZIP County SATE

  ---------                  --------                                ------------           ------           -------    -- -----

  Married America 1234 Southridge Park Dr.    Samna Lorie MO 31234  NULL VALUE

  "Bill Johnson. Apartment 3B. Sterling. VA. 20166. Falke Plaza 3... "

  NAME ADDRESS CITY ZIP County SATE

  ----------------      -----------------        -------       -----        ---         --------

  Bill Johnson apartment 3B Sterling, WILL 20166 3 Falke Plaza.

  Problem

  ---------

  (1) if the value, if the County (if null) value then it shows the ZIP with dot's (.) value, in the 31234 above..,.

  How to solve this problem?

  (2) another possible to fix the code, I want to use substr and InStr.

  (3) who is the best approach?

  Conditions:

  --------------

  (1) shipping_instructions column has the value with "Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234... »

  This means it combined all the similar name, address, city, State, zip

  (2) we insreted in the table separately.

  =========================

  / * Use Substr and Instr * /.

  =========================

  I used substr and instr, but I'm getting the money results (no point in the address).

  "America Mary. 1234 Southridge Park Dr. Samna Lorie.MO.31234..'

  
  

  NAME ADDRESS CITY ZIP County SATE

  ---------                  --------                                ------------           ------           -------    -- -----

  Mary America 1234 Southridge Park Dr. Samna Lorie MO 31234  NULL VALUE

  But I need the results (no point in the address)

  NAME ADDRESS CITY ZIP County SATE

  ---------                  --------                                ------------           ------           -------    -- -----

  Mary America 1234 Southridge Park Dr.    Samna Lorie MO 31234  NULL VALUE

  Hello

  994122 wrote:

  Hello

  (1) how do to do this, use the substr and instr functions?

  Thank you

  You can't do all the work with SUBSTR and INSTR; you need regular expressions to obtain a string delimited by a #.

  Once you have such a string, then you can use SUBSTR and INSTR (instead of REGEXP_SUBSTR) to get the separate secondary strings:

  WITH got_delimited_string AS

  (

  SELECT REGEXP_REPLACE (val

  , '\. ([^ .]| $)'

  , '#\1'

  ) AS delimited_string

  FROM the data

  )

  got_pos AS

  (

  SELECT delimited_string

  , INSTR (delimited_string, "#", 1, 1) AS pos_1

  , INSTR (delimited_string, "#", 1, 2), pos_2

  , INSTR (delimited_string, "#", 1, 3) AS pos_3

  , INSTR (delimited_string, "#", 1, 4) AS pos_4

  , INSTR (delimited_string, "#", 1, 5) AS pos_5

  , INSTR (delimited_string, "#", 1, 6) AS pos_6

  OF got_delimited_string

  )

  SELECT SUBSTR (delimited_string, 1, pos_1 - 1) AS the name

  SUBSTR (delimited_string, pos_1 + 1, pos_2 - (pos_1 + 1)) AS address

  SUBSTR (delimited_string, pos_2 + 1, pos_3 - (pos_2 + 1)) AS city

  SUBSTR (delimited_string, pos_3 + 1, pos_4 - (pos_3 + 1)) AS State

  REPLACE (SUBSTR (delimited_string, pos_4 + 1, pos_5 - (pos_4 + 1))

  , '.'

  )                                                           AS zip

  SUBSTR (delimited_string, pos_5 + 1, pos_6 - (pos_5 + 1)) AS the County

  OF got_pos

  ORDER BY delimited_string

  ;

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