Averages for number of loops
Hi all
I have a code (attached) in which a triangular wave is supposed to a magnetic field of ramp up and down to very low frequency (0.1 Hz or low). Reading (X) vs keithley reading field (Y) represented by two random numbers generators must be taken in synchronization with the triangular wave point by point. I would be very grateful if you could help to achieve the following objectives:
1. by taking the average for a few cycles. Basically, I would define the number of loops in the outer circle to the loop and the number of sampling inside everything in a loop and then take the average between the loops.
(Data for data of loop2 +... + loop1) + data to loop n/n
2. the averages should be written to the text file and at the same time, I hope I always get the full date in the file action.
Thank you
Hadi
Assuming that you want to monitor the data happens, I would like to initialize several arrays, both to keep the x and are data and to keep the number of each 'package '.
Now, simply add the new data to the existing elements while incrementing the corresponding number. Dividing by the count will give you the way to be represented graphically. Here's a simple rewrite. The "collection must match the size of the field ramp, so it shouldn't be a separate control, I think. Currently, you graph the two random channels. You would you rather them the two graphic vs of the field instead? You want front and back scans averaged individually or must they go to the same average with a half data table?
You save operation still seems a little convoluted. How do you actually data to be organized in the final file?
Here is a quick project to help you get started.
Tags: NI Software
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Procedure 'IN' settings and in NUMBER of loop dbms_output
I have this procedure which takes two values, a name and a number, as parameters. I do things with them, then try of the output result.
The code will run well and produce the correct result without printing through DBMS with the loop FOR (I RUN the procedure and manually doing a SELECT on the view and the values are correct). Then I deleted a word in the code, spruced up the same word in the same place in the code, and suddenly I had a different and incorrect result. After you delete and retype everything code for fear of a ghost or something character, it ran fine again without the DBMS FOR part print loop. I typed in the loop FOR and now it does not yet work with errors on the assignment of variable "temp" and "temp1". It worked fine before the additional code has been added. It makes no sense to me.
I use Oracle SQL Developer.
The code runs and the results I want, but I keep running in what appears to have problems with the development software. IIF someone could look at the code and help I would really appreciate it. I spent many, many hours on this...
CODE:
PROCEDURE GetThem (nameIn IN varchar2, percIn IN number) AS
Temp varchar2 (30): = '& nameIn'; -SOMETIMES GETTING ERRORS OF TYPE HERE INCORRECT ATTRIBUTION, SOMETIMES NOT...
number of Temp1: = '& percIn'; -HERE TOO, SAME AS ABOVE
BEGIN
EXECUTE IMMEDIATE ' VIEW to CREATE or REPLACE personTotal AS
SELECT person, COUNT (name) AS total FROM (SELECT DISTINCT name, comments FROM person person WHERE! = temp) GROUP BY person ';
EXECUTE IMMEDIATE ' VIEW to CREATE or REPLACE sharedTotal AS
SELECT p.person, COUNT (DISTINCT name) AS best of observations p WHERE p.person! = temp AND p.name IN (SELECT DISTINCT observations g WHERE g.person = temp g.name) GROUP BY p.person';
FOR tt IN (SELECT p.person FROM personTotal p, sharedTotal s p.person WHERE = temp1 AND s.person < = s.bhave/p.total ORDER BY person)
LOOP
dbms_output.put_line (' ' | tt.person |) ' ' ); -SHOULD GENERATE SOME RESULTS HERE BUT UNTESTED
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END GetThem;Hi, Ben.
Aymen says:
Frank,Thank you once again. I have looked at the code and I'm testing it in a procedure.
I do not ask more of you, but I'm going to...
I'm a student in computer engineering and a data base of the course.
Then do not use the query I posted earlier. Your teacher will give you more credit to submit your own work, instead of copying someone else, no matter how elegant which can be. An approach as you suggested above will be fine for this mission.
It is an assignment that I worked on 4 days with what is the last problem. I was not aware of the existence of procedures util, I've seen this problem in my mission.
I have been searching on the internet and got lots of information on procedures, but they are general examples and I don't understand how they apply to my case.
There was therefore no preparatory work on the procedures in your class? I find it quite cruel.
I still have a problem with the part of the output and also, I get an error when I place the SELECT statement in the procedure. (Error (8.7): PLS-00428: an INTO clause in this SELECT statement) It seems that he wants me to put the result in a variable.
When you run a query in SQL * more (or most any front-end) you're doing 2 things:
(1) obtain data tables in the database in a result set, and
(2) display that game results
SQL * more autiomatically makes two things together, so you often do not even consider them as separate steps. In PL/SQL, explicitly do you somehting for each step separately.Here's what I found:
-Use an output variable, declare it before calling the procedure and put it in the settings and then assign it the value to be returned in the variable.
That's right, but it's the only way to make a query in PL/SQL.
Another way, better for this assignment, is to use a cursor loop, as you did in your first post.Consider this problem: write a procedure which, for a specific job in the table scott.emp, considers people who have this work and who has wages are at least as high as the average salary for this job in their own departments (counting their own salaries).
Here is information on all the people with job = 'CLERK ":` DEPTNO ENAME SAL JOB ---------- ---------- ---------- --------- 10 MILLER 1300 CLERK 20 SMITH 800 CLERK 20 ADAMS 1100 CLERK 30 JAMES 950 CLERKIn the 10 departments, there as a CLERK, namely MILLER. The sal average clerks in 10 1300 dept, sal MILLER is equal to that, if MILLER should be included in the output.
Dept = 30 is another trivial case, like dept = 10.
Dept = 20 is more interesting. The average sal for clerks in dept 20 is (800 + 1100) / 2 = 950. Sal of SMITH is less than 950, SMITH should not be in the output. Sal of ADAMS is above 950, ADAMS should be in the output.Here's a way to write a procedure that gets these results:
CREATE OR REPLACE PROCEDURE avg_or_above ( in_job VARCHAR2 ) AS BEGIN FOR this_emp IN ( WITH avg_by_dept AS ( SELECT deptno , AVG (sal) AS avg_sal FROM scott.emp WHERE job = in_job GROUP BY deptno ) SELECT e.ename , e.sal FROM scott.emp e JOIN avg_by_dept a ON e.deptno = a.deptno WHERE e.sal >= a.avg_sal AND e.job = in_job ) LOOP dbms_output.put_line ( RPAD (this_emp.ename, 12) || TO_CHAR (this_emp.sal, '99999') ); END LOOP; END avg_or_above; / SHOW ERRORIn SQL * Plus, you can call the procedure as follows:
SET SERVEROUTPUT ON EXEC avg_or_above ('CLERK');and the output will look like this:
ADAMS 1100 JAMES 950 MILLER 1300Here's how it works:
FOR x IN (q) LOOP ... -- Code here is "inside" the loop END LOOP;runs a query q. Like any question, q can begin with the SELECT keyword or keyword WITH.
For each row returned by the query q, the results of this line are placed in the variable x, which is a data structure created automatically to have an element for each column in the query. In this example, the query produces two columns (an ename called, which is a VARCHAR2, and the other called sal, which is a NUMBER), then x has two components: the x.ename (which is a VARCHAR2) and x.sal (which is a NUMBER). Inside the loop (i.e. after the LOOP but before the END LOOP statement) you can use x.ename any place where you can use a VARCHAR2 expression, and you can use x.sal everywhere where you can use a NUMBER. In this case, the body of the loop includes only one declaration, a call to dbms_output.put_line. However, you can have several statements between the instructions of LOOP and END_LOOP if you need to.It's everything you need to run a query and display its results in PL/SQL. There are other ways, but I think this one will do well enough for this mission.
Note that there is no need of all views. The avg_by_dept of the subquery is like a point of view. In fact, by looking at only the main request in the cursor above:
... SELECT e.ename , e.sal FROM scott.emp e JOIN avg_by_dept a ON e.deptno = a.deptno WHERE e.sal >= a.avg_sal AND e.job = in_jobHe has nothihng to indicate if the avg_by_dept is a table, a view, or a subquery, and it does not affect the query of some sort.
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Hello guys,.
I want to measure the time for a while loop to run once. There is a piece of code raised. So I just created a simple VI to try, please let me know which is the right way to do it?
And I wondered, when I run the VI without highlighting the execution, he wouldn't give me a number, maybe it's because the code is simple and really fast? I have to highlight all the time?
Thank you
Not quite right. Both get primitive value time will run at the same time. use an image sequence to force the order of execution, as shown. I also brought in the relitve of accuracy seconds vi of VI. LIB\utilities because it depends on the clock of the system rather than the mSec timer accuracy.
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Hello
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When a constant empty array (zero element) is connected to the loop For with "allowing the index", there are no interactions performed in loop For. But, if the loop is replaced by any loop, no problem.
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Hello
It is ok. I have no problem at all.
For the 'loop' For when you connect the table thanks to indexing, the number of iterations is set to the size of the array. The iteration number assigned to N (in your case 10) is ignored.
For the 'While' loop the number of iteration is defined by the Boolean Condition and the size of the array is ignored.
Paul
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Disconnect any other (additional) internal hard drives and external USB devices.
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Intel® drive SSD Toolbox
https://Downloadcenter.Intel.com/Detail_Desc.aspx?AGR=Y&DwnldID=18455
Corsair SSD Toolbox:
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Samsung Magican review:
SanDisk SSD Toolkit: http://kb.sandisk.com/app/answers/detail/a_id/9328/
Seagate: http://www.seagate.com/support/internal-hard-drives/laptop-hard-drives/laptop-600-ssd/
Life of the SSD: http://ssd-life.com/
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Check their support site for the latest drivers as the CD that came with the computer
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Visit the download of the manufacture of the graphics card:
Download and install the most recent Windows 7 or 8 drivers for your card.
ATI: http://support.amd.com/us/gpudownload/Pages/index.aspx
NVIDIA: http://www.nvidia.com/Download/index.aspx?lang=en-us
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WAIT % - % IDLE, what is the average for a virtual machine?
I did some research on performance of VM problems and worked with the media to see that there is maybe a bottle neck IO that occur with a virtual VMware machine I have performance problems on. The technician found that the WAITING % - % IDLE on average for this virtual machine is around 200%. The tech said it was abnormally high. I forgot to ask her what was normal but wanted to put a post to see if some people out there know what they are on average. What is an average number of see? I have the system done nothing right now and I see 579% waiting and 372% IDLE. The technology has been able to confirm that no IO queue was occurring in the VMkernel or on the HBA controller.
Some average % positions would be useful. Thank you.
gdewulf18480 wrote:
Supposibly the amount of time in a State of waiting for I/O is the WAIT - IDLE % difference. I was wondering if anyone had the numbers for this feeling. Is there anyone with some of them?
Q: How will I know the VCPU world waiting for I/O events?
A: WAIT - % IDLE % can give you an estimate on how much time processor is spent waiting for I/O events. It is an estimate only, because the world wait perhaps for other than the i/o resources. Note that we should do it only for the worlds of the WWW, not the other kind of worlds. Because the VMM worlds represent the best guest behavior. For the disk i/o, another alternative is to read the disk latency stats that we explain in the drive section.
WAIT % by itself cannot be used, you must develop and examine the individual vCPU % EXPECTATION values and subtract their idle time. You can't do it on the initial view of a single line by VM CPU in esxtop. If technology that you mentioned did not explain it, he doesn't know what it takes.
I have lots of virtual machines that are never less than 300% when I wait - % idle and I have no problems.
It is an example, I caught NimSoft server:
DHSNMS1 100 100 5 192.63 193,80 0.24 0.03 291,44 1.04
%EST USED (s) 192 - in other words, almost two processors are used 100%
The %Idle is 1.04% WAIT 291.44 - according to the calculation of waiting idle, I have a super serious problems of e/s past But this isn't the case, and expanding, I can see that.
5665 vmware-vmx 100 1 0.09 0.11 100.00 0.00 0.00 0.01
5667 100 vmassistant.566 1 0.62 0.65 99,63 0.00 0.00 0.00
5703 100 mks:DHSNMS1 1 0.01 0.01-100.00 0.00 0.00 0.00
5704 vcpu 100 - 0:DHSNMS1 1 32,35 32.88 67,28 0.28 0.11 67,14
5705 vcpu 100 - 1:DHSNMS1 1 31,58 32.05 68.11 0.00 67.85 0.12
So the changed values unfortunately because of ESXTOP bike when you develop... which is annoying, but anyway. In this you see % waiting is 67 and 68 with another respectively being 3 to 100% (which is normal) and the idle being %, 0, 0, 0, 67 and 67.8. Doing the calculation on the processors shows a wait - slowed virtually 0 - or very little IO wait past with processors. But if you add up all the expectations of % and % is idling, you have 434ish, and the 134ish and do the calculation is the difference of 300 - which is the 3 who are always 100%.
So there is no way we can answer your question, we can only help you to understand how the values should be interpreted.
Waiting for i/o States almost always go on the disc anyway, it is unlikely, therefore, the network or the user entered, looking at the stats of disc ESXTOP is a much better way to determine if there is a problem of e/s.
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While why broken arrow will not appear for a timed loop
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I need a little clarification relative to normal while loop and timed looping in labview.
In labview, if I keep a while loop on a block diagram, broken arrow will appear in the upper left corner of the window indicating the error. It displays error because I have not wired conditional terminal of the while loop.
But same is not the case for a timed loop. Can someone tell me what is the reason behind this...
If I release the conditional terminal of the timed while loop, it runs in infinfite time like a normal while loop. Then y labview behaves differently for these two types of loops in the scenario above.
FYI... I'm using labview 2009.
Waiting for response.
Thank you
Herald
Ruben,
the reason is quite simple: call loops are mostly real-time and FPGA targets. Since most of the applications on these targets work continuously (at least this is more often the task), it is possible to create a loop that does not end. So the timed loop by default assumes that there is no need of a stop button.
The 'normal' while loop needs code for termination (conditional terminal) because normal applications on Windows/Linux/Mac are used to be fair...
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Some_Timestamp
"Parameter1" Parameter2 1 JANUARY 2015 02:00. 00:000000 AM - 07:00 2341.4534 676341.4534 1 JANUARY 2015 02:00. 01:000000 AM - 07:00 2341.4533 676341.3 1 JANUARY 2015 03:04. 01:000000 PM - 07:00 5332.3533 676341.53 1 JANUARY 2015 03:00. 01:000046 PM - 07:00 23.34 36434.4345 JANUARY 2, 2015 05:06.01:000236 AM - 07:00 352.33 43543.4353 JANUARY 2, 2015 09:00. 01:000026 AM - 07:00 234.45 3453.54 3 FEBRUARY 2015 10:00. 01:000026 PM - 07:00 3423.353 4634.45 FEBRUARY 4, 2015 11:08. 01:000026 AM - 07:00 324.35325 34534.53 We have data as above a table and we want to calculate all the days, the hourly average for large data set (almost 100 million). Is it possible to use the sql functions of analysis for better performance instead of the ordinary average and group of? Or any other way better performance?
Don't know if that works better, but instead of using to_char, you could use trunc. Try something like this:
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Hi all! This code works great, it returns the average value for contragentid = 1. So correct result is LUAHPER = 14996837,94
But when I add the values for contragentid = 2 (see commented strings), my statement returns incorrect result LUAHPER = 5497801,81
How can I improve my code in order to calculate the average for each contragentid?
Edited by: 858774 14/06/2011 02:29with t as ( select to_date('12.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual union all select to_date('14.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual union all select to_date('15.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual union all select to_date('16.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15274795.50 as luah, 215274795.50 as lusd from dual union all select to_date('17.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15431807.40 as luah, 215431807.40 as lusd from dual union all select to_date('18.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15480730.00 as luah, 215480730 as lusd from dual union all select to_date('21.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15480730.00 as luah, 215480730 as lusd from dual /*union all select to_date('12.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual union all select to_date('14.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual union all select to_date('15.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual union all select to_date('16.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215274795.50 as luah, 215274795.50 as lusd from dual union all select to_date('17.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215431807.40 as luah, 215431807.40 as lusd from dual union all select to_date('18.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215480730 as luah, 215480730 as lusd from dual union all select to_date('21.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215480730 as luah, 215480730 as lusd from dual*/ ) select contragentid, sum(luahper) / cnt as luahper from ( select contragentid, (lead(arcdate,1,date '2011-03-20' + 1) over(order by arcdate) - arcdate) * luah luahper, date '2011-03-20' - date '2011-03-13' + 1 cnt from ( select arcdate, contragentid, luah, lusd from t where arcdate > date '2011-03-13' and arcdate <= date '2011-03-20' union all select greatest(arcdate,date '2011-03-13'), contragentid, luah, lusd from t where arcdate = (select max(arcdate) from t where arcdate <= date '2011-03-13') ) ) where contragentid = 1 group by contragentid, cntHello
858774 wrote:
But when I add the values for contragentid = 2 (see commented strings), my statement returns incorrect result LUAHPER = 5497801,81I guess that's because you don't join and partition on contragentid.
This appears to do:Scott@my10g SQL>/ CONTRAGENTID LUAHPER ------------ ---------- 1 14996837.9 Scott@my10g SQL>l 1 with t as ( 2 select to_date('12.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual 3 union all 4 select to_date('14.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual 5 union all 6 select to_date('15.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual 7 union all 8 select to_date('16.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15274795.50 as luah, 215274795.50 as lusd from dual 9 union all 10 select to_date('17.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15431807.40 as luah, 215431807.40 as lusd from dual 11 union all 12 select to_date('18.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15480730.00 as luah, 215480730 as lusd from dual 13 union all 14 select to_date('21.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15480730.00 as luah, 215480730 as lusd from dual 15 -- 16 union all 17 select to_date('12.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual 18 union all 19 select to_date('14.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual 20 union all 21 select to_date('15.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual 22 union all 23 select to_date('16.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215274795.50 as luah, 215274795.50 as lusd from dual 24 union all 25 select to_date('17.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215431807.40 as luah, 215431807.40 as lusd from dual 26 union all 27 select to_date('18.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215480730 as luah, 215480730 as lusd from dual 28 union all 29 select to_date('21.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215480730 as luah, 215480730 as lusd from dual 30 -- 31 ) 32 select contragentid, sum(luahper) / cnt as luahper 33 from ( 34 select contragentid, (lead(arcdate,1,date '2011-03-20' + 1) over(partition by contragentid order by arcdate) - arcdate) * luah luahper, 35 date '2011-03-20' - date '2011-03-13' + 1 cnt 36 from ( 37 select arcdate, contragentid, luah, lusd 38 from 39 t 40 where arcdate > date '2011-03-13' 41 and arcdate <= date '2011-03-20' 42 union all 43 select greatest(arcdate,date '2011-03-13'), 44 contragentid, luah, lusd 45 from 46 t 47 where arcdate = (select max(arcdate) from 48 t t2 49 where arcdate <= date '2011-03-13' 50 and t.contragentid=t2.contragentid) 51 ) ) 52 where contragentid = 1 53* group by contragentid, cnt Scott@my10g SQL>/ CONTRAGENTID LUAHPER ------------ ---------- 1 14996837.9858774 wrote: How can I improve my code in order to calculate the average for each contragentid?
When I remove the 'where contragentid = 1' seems to do with above query:
Scott@my10g SQL>/ CONTRAGENTID LUAHPER ------------ ---------- 2 214996838 1 14996837.9 -
Number of averages for time waveform acquisition
Hello
It is on the configuration of the device - settings of the acquisition.
in the parameters of the collection file, can I know is there a way to feed the number of averages and % of overlap between averages aquire waving time.
Thank you!!
BR
Pattabi
In version 3.0 of InsightCM, we will support an average and overlap on the data of the spectrum Viewer. These settings will be applied only to the visualization of the spectral data and will not apply to calculations on the waveform or spectral data form.
This will meet your needs? Or are you interested in doing an average and are superimposed on the spectral data to then be used for calculations that are based on spectral data - such as 1 x Magnitude, etc.. ?
Thanks for the question.
-alan
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Create a table in a loop 'for' (reset the number of loops)
Hello
I try to incorporate a signal of acceleration from an analog input CRIO to get speed and then further integrate to get the moving of a vibration system.
I understand that to achieve integration, a table must be fed in. My problem is that I could not buffer the signal in a buffer block, as I couldn't find buffer blocks. so I decided to create my data table by using a loop "for". The nests of the loop 'for' inside a timed loop. The problem that I'm stuck on is how to reset the loop 'for' in order to fill the buffer with each iteration of the outer loop timed.
I enclose the code if that helps. Note that I use labview in 2013.
If anyone who has encountered a similar problem before can help me, I would be gratefull.
Concerning
Ali
You can use a shift register initialized as inputs to your curls, to build your table of one. However, you realize, don't you, that the execution of your program as written loops as soon as the computer can spit out responses, then the output array may contain several points that took place before the entry has updated? Assuming that your thing cRIO (I've not worked with these) has integrated into its routine acquisition of calendar data, I suggest you put that inside the loop to get a data point by reading.
And do you really want your graph to distance for update only every thousand points (points of acceleration million) speed?
Cameron
-
How to create a control of time for the while loop?
Hi all
I want to control my time running of the loop. In other words, I want to stop everything in the execution of the loop after a time (in ms) that is defined by the user. For example user defines Control Panel for 5 seconds before a while loop runs and stops after 5 seconds.
I don't know is it possible with the while loop. I managed with the timed loop, but this must be wrong with my application. Y at - it of the other loops for timed control if it is not possible with while loop? There is also a simple loop with .vi random number (0-1) as an attachment.
Best regards
Jick
Hi again,
I managed to solve my problem right after I posted my first message. I did it with the passage of time and the register shift (for the elapsed time of reset).
Thanks for your replies anyway!
Best R
Jick
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best type of measure daqmx for several closed loop control system
Hello
I wonder what kind of type of measure daqmx which are suitable for the control system of closed loop with control about loop 128?
I design unique loop with continuous sample and sample application. The two correct answer. But I don't know if the control loop number increases.
Another question is, clock synchronization of time needed for such a system?
taov,
I recommend you to use continuous sampling because it is time of material while on demand collection is software time.
As for the RTOS system, please see this link.
CarmenC
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