AWR time model statistics vs SQL Statistics
Looking at an AWR report took on a unique snapshot interval, I note the following:In time model statistics, DB time is listed as 161,47 seconds, with sql execute represents the time of 127,83 seconds.
When I DBA_HIST_SQLSTAT to queries on the same cliché and summarize all the elapsed_time_delta of each SQL stored in AWR, I find that it's 132,05 seconds, even after filtering of all PL/SQL (command_type 47) and each SQL with parsing_schema_name SYS.
If anything, I expect this sum less than that contained in the statistics of the model time, thinking that only the top n sql is included in DBA_HISSQLSTAT.
Does anyone know where my reasoning was an error?
KDeWeerd wrote:
Detailed analysis of an environment, trying to give meaning to all the numbers and to explain things to people doesn't make not easier if you can not all numbers that collects Oracle corresponding to some how.
Yes, I understand. Here you can not because the statistical statement have no knowledge of what what call. This is probably why Oracle introduced the chronological model: it gives information that you can't derive from other sources.
Any timed operation will be buffer at most 5 seconds of time data. This means that if a timed (such as the SQL execution) takes a long period of time to perform, the data published to this point of view lack maximum 5 seconds of the time accumulated for the operation.Can't really make sense of interpretation which
means that the value may be missed for 5 seconds for each running of instruction.
Tags: Database
Similar Questions
-
Hello everyone,
I need an answer everything into question of my mind.
I have an example of awr report and I wonder on below...
How is it 'execute sql elapsed time' and "DB CPU" are both is greater than the total duration of DB. Or the sum of all statisctics are greate than the total duration of DB.
I knew that TIME DB = DB CPU + sql execute elapsed time + analysis elapsed time...
But all of them are greater than 100, how and why.
Statistics name time (s) per cent of the time Total of DB
---------------------------------------- -------- ------------------------
DB time 124 564
Execute SQL time elapsed 95 118 853
DB 27 033 22 CPU
analysis time elapsed 12 15 552
12-14-868 elapsed hard analysis
elapsed time of bottom 6 7 804
hard analysis (sharing criteria) elapsed ti 4 5 198
me
PL/SQL 3 3 272 elapsed execution
time 2 2 546 background cpu
Statistics name time (s) per cent of the time Total of DB
---------------------------------------- -------- ------------------------
hard analysis (bind incompatibility) passed 1 1 672
PL/SQL compilation elapsed 1 1 050
elapsed time of connection management call 178 0
sequence of time charge 141 0
Time cpu RMAN (backup/restore) 38 0
repeated bind passed 13-0
could not parse elapsed 3 0
entering the time of PL/SQL rpc 0 0881931 wrote:
Thank you my friend,I saw this response drinking I did not understand, Tom explained sql out of time, but I want to learn "why all are 100% grater."
Thank you very much
The simple reason why the statistics add up to more than 100% is because the statistics are not designed to be added together in the way that you add statistics. Statistics of time DB is just the CPU and wait event total time for the sessions of the user, so it was a logical choice as a divider for all statistics. Most of the time model statistics contributes to the statistic of time DB, but there is overlap between the statistics - for example, time CPU DB is required to run SQL statements (these two are listed statistics). Also included in the report of statistics that are not components of the statistics of time DB, as background the elapsed time, time background and RMAN (backup/restore) time cpu - cpu but the report still divides these statistics of statistics of time DB, probably just so that you have a common point of reference.
Time model statistics should be seen in a tree that represents the parent relationships and the child between the statistics. The following article shows the directory structure and how you would interpret the statistics:
http://hoopercharles.WordPress.com/2010/01/13/working-with-Oracle-time-model-data/If you take another look at your statistics:
Statistic Name Time (s) Percent of Total DB Time ---------------------------------------- -------- ------------------------ DB time 124,564 sql execute elapsed time 118,853 95 DB CPU 27,033 22 parse time elapsed 15,552 12 hard parse elapsed time 14,868 12 background elapsed time 7,804 6 hard parse (sharing criteria) elapsed ti 5,198 4 PL/SQL execution elapsed time 3,272 3 background cpu time 2,546 2 hard parse (bind mismatch) elapsed time 1,672 1 PL/SQL compilation elapsed time 1,050 1 connection management call elapsed time 178 0 sequence load elapsed time 141 0 RMAN cpu time (backup/restore) 38 0 repeated bind elapsed time 13 0 failed parse elapsed time 3 0 inbound PL/SQL rpc elapsed time 0 0You can make certain assumptions as follows:
27 033 CPU seconds spent doing the work for user sessions. Because 124 564 seconds are indicated by the statistics of time DB, you can determine that about 124 564-27 033 seconds were spent in the events of waiting for user sessions. Sessions spent 15 552 seconds, the analysis of the SQL statements (note that some time CPU would be also consumed during analysis) and 14 868 seconds of this hard time parsing SQL statements, so sessions consume 15 552-14 868 seconds soft analysis of SQL statements. 14 868 seconds past hard analysis, 5 198 seconds were caused by sharing criteria and that 14 868-5 198 seconds were probably due to the unique SQL statements being submitted to the database. And so on.Charles Hooper
Co-author of "Expert Oracle practices: Oracle Database Administration of the Oak Table.
http://hoopercharles.WordPress.com/
IT Manager/Oracle DBA
K & M-making Machine, Inc. -
Calculation of the time wall of a SQL query.
Hello
While trying to discover the time of running a SQL query (wall time) I read in one place that CPU_TIME/EXECUTIONS of v$ SQLAREA, is the precise runtime we can come close to.
I can't use "set timing on ' or 'DBMS_UTILITY. GET_TIME' that I need to extract the execution time of the story because the query will be drawn to an end, and I need to know how long it took to DB level and compare it with the end time before calculating the % of time used in the DB level total.
Maybe another way to track sessions and the user TKPORPOF but now I donot want to take the help of the ADMINISTRATOR at this initial stage.
Is CPU_TIME/EXECUTIONS of v$ SQLAREA where (SQL_TEXT) AS "SELECT... OF... %'; should be enough?
user2925917, yes as Brian already answered your understanding as posted above seems correct. Except in the case where there has been only a running query you will download an average time. The problem with averages is that one or two unusual executions that can skew the average, but in most cases the average will be probably fairly accurate.
- -
HTH - Mark D Powell.
-
Time of execution of SQL statements
Is there a way to see the time of the last sql instructions? (as the TOAD request viewer)
Without having to execute the statement as a script and use "set timing on."
Kind regards
Carsten
We show the run down by the exit time
You can also see the query execution times in the historical Panel SQL
-
is their any option to make its contribution to the time of execution in SQL
is their any option to make its contribution to the time of execution in SQL instead of &Waran wrote:
When to use & symbol to make his contribution in SQL queries. is their another way to provide the same.Yes, you can use a whole set to use any other symbol you like.
SQL> select '&input' from dual; Enter value for input: Test1 old 1: select '&input' from dual new 1: select 'Test1' from dual 'TEST ----- Test1 SQL> set define "#" SQL> select '#input' from dual; Enter value for input: Test2 old 1: select '#input' from dual new 1: select 'Test2' from dual 'TEST ----- Test2If this is not what you mean, please explain what you do and where you need to run SQL and the version of the database, like everyone else, it's important.
-
How to know the execution time of query in sql plus
Hello
I want to know the duration of execution of query in sql more accompanied by statistics
I say time is set on;
Set autotrace on;
Select * view where usr_id = "abcd";
If the result is 300 lines it scrolls up until all the rows are retrieved and finally gives me the run time in 40 seconds, or 1 minute... (it is after all records scrolls)
but when I run it in Toad he gives 350 milli seconds...
I want to see the execution time in sql how to proceed
client and database server 11g is g 10
concerning
REDAIn sqlplus you can do set autotrace traces to suppress the display of the selected lines.
John
-
AWR: Time CPU = 0, % of time Total DB > 0
Hello!
I use * 10.2.0.5 *, AWR I see next statistical operation in one of my report:
Please explain, how is it possibleSQL ordered by Elapsed Time CPU Time ... % Total DB Time 0 12.21
DB-time does not time CPU here?
Thank you and best regards,
Pavel
Published by: Pavel on April 18, 2012 04:17Hello
for explanation of time CPU and DB, please visit http://savvinov.com/2012/04/06/awr-reports-interpreting-cpu-usage/.
In your case, I think that the numbers is not reliable due to errors of instrumentation (for example, I saw 0 time processor in an extremely overloaded system).
Best regards
Nikolai -
Concatinate date and time models
Hello
I have a problem.
In forms 6i, I have two columns of data base no:
1st is the Date format (exact)
2nd is the time format (HH24:MI:SS)
Now, I want to combine these two in 3rd fild who is date/time format (exact HH24:MI:SS).
I tried this approach:
Select to_date (to_char(:field1,'dd.mm.yyyy'): double to_char(:field2,'HH24:MI:SS');)
ORA: 01850
I also tried various other optios I found on the net but all I get are variations to errors ora 01850.
Help, please!
Thank you!
994543 wrote:
The two responses gives always the error: ora-01858
Is there another way... I mean I didn't event know what to post here to help solve this problem.
When I tried the solution answer was almost identical to what you guys posted here.
You must post the values of Field1 and Field2. If they contain the values in the format that you specified then the solution should work without any fault. Here is an example
SQL > var field1 varchar2 (10)
SQL > varchar2 (8) var field2
"SQL > exec: field1: = October 30, 2013.
PL/SQL procedure successfully completed.
"SQL > exec: field2: = 23:59 min 59 s.
PL/SQL procedure successfully completed.
SQL > alter session set nls_date_format = ' DD. MM YYYY HH24:MI:SS';
Modified session.
SQL > select to_date(:field1 ||) ' ' || : field2, ' JJ. MM YYYY HH24:MI:SS) double dt;
DT
-------------------
30.10.2013 23:59:59SQL >
-
Help with time operations invloving the SQL query
I created 2 tables in my SQL. One is the user_info_table table that stores the connection time and time zone of login for each user. The other is the post_table that stores user postid, who makes the post time post and time zone for each message.
CREATE TABLE user_info ( user_id VARCHAR(20), login_date DATE, login_time_zone VARCHAR(20), PRIMARY KEY (user_id) );
Some examples of data for my paintings is as below.CREATE TABLE post_table ( post_id VARCHAR(20), user_id VARCHAR(20), datepost DATE, time_zone VARCHAR(20), PRIMARY KEY (post_id), FOREIGN KEY (user_id) REFERENCES user_info(user_id) ON DELETE CASCADE ) ;
I need to write a SQL query which - is the user whose time difference between the time of the connection and the last time when he or she wrote a post is the smallest. I need to consider the time zones here as well.INSERT INTO user_info VALUES( 'u1', to_date('9/17/2009 20:00','MM/DD/YYYY mi:ss'), -2 ); INSERT INTO user_info VALUES( 'u2', to_date('9/17/2009 19:55','MM/DD/YYYY mi:ss'), -4 ); INSERT INTO post_table VALUES( 'p1', 'u1', to_date('9/17/2009 20:50','MM/DD/YYYY mi:ss'), 6 ); INSERT INTO post_table VALUES( 'p2', 'u2', to_date('9/17/2009 20:30','MM/DD/YYYY mi:ss'), -5 ); INSERT INTO post_table VALUES( 'p3', 'u2', to_date('9/18/2009 6:00','MM/DD/YYYY mi:ss'), 2 ); INSERT INTO post_table VALUES( 'p4', 'u1', to_date('9/17/2009 21:00','MM/DD/YYYY mi:ss'), -3 );
I am not sure if time_zone must be of type VARCHAR or TIMESTAMP then have created as a VARCHAR in my paintings.
Someone help me please to form this query.
PS: How can I tags < code > user in this forum to write sql statements.
Published by: user11994430 on October 9, 2009 17:59You can do this by adding a clause of "HAVING" as shown below. However, with your test defined data it returns ZERO rows because for all users of the MAX (DATEPOST) IS LESS than MAX (LOGIN_DATE)
SELECT USER_ID FROM ( SELECT USER_ID , DENSE_RANK() OVER (ORDER BY POST_LOGIN_DIFF) RNK FROM ( SELECT USER_INFO.USER_ID , MAX(DATEPOST) - MAX(LOGIN_DATE) AS POST_LOGIN_DIFF FROM USER_INFO JOIN POST_TABLE ON POST_TABLE.USER_ID = USER_INFO.USER_ID GROUP BY USER_INFO.USER_ID HAVING MAX(DATEPOST) > MAX(LOGIN_DATE) ) ) WHERE RNK = 1 -
Hello! I have a Sql that returns
col1 col2 col3 col4 col5
1 1 0 1
1 0 1 1
0 1 B 0 0
1 1 0 0
0 1 B 0 0
Assuming that the sentence: Select col1, col2, col3, col4 col5 table
How I model the sentence to get this result:
col1 col2 col3 col4 col5
4 1 1 2
B 0 0 1 0
The columns col3, col4 y col5 are obtained by adding the result of each line. col1 and col2 is the only value that is displayed.
Thanks in advanceSearch SELECT, GROUPBY, SUM... in the documentation, you
http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/statements_10002.htm#i2065646
http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/statements_10002.htm#i2182483
http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/functions163.htm#i89126and then tell us please what you don't understand
-
Can I use session variables in data model BI publisher SQL query?
Hi Experts,
We apply security at the level of the BI Publisher 11g data.
In OBIEE we do so using session variables, so I wanted to just ask if we can use the same session variables in BI Publisher as well
That is, we can include a where clause in the SQL for the sample data as
Where ORG_ID = @{biServer.variables ['NQ_SESSION.]} {[INV_ORG']}
I would like to know your opinion on this.
PS: We implement security EBS r12 in BI Publisher.
Thank youRead this-> OBIEE 11 g: error: "[nQSError: 23006] the session variable, NQ_SESSION.» LAN_INT, has no definition of value. "When you create a SQL query using the session NQ_SESSION variable. LAN_INT in BI Publisher [ID 1511676.1]
Follow the ER - BUG: 13607750 -NEED TO be able TO SET up a SESSION IN OBIEE VARIABLE AND use it IN BI PUBLISHER
HTH,
SVS -
Same link several times variable using dynamic SQL
Salvation;
I have a query that uses the variable even several times, is there a way I could just use that variable only once and it will take several times.
Request is;
run immediately "SELECT count (*) x WHERE MONTH_ID =: VOMNTH_ID"
UNION
SELECT count (*) FROM Y WHERE MONTH_ID =: VOMNTH_ID
Union
SELECT count (*) FROM WHERE MONTH_ID = z: VOMNTH_ID ' help months1, month1, months1
What I don't want only once to provide months1.
Your help is appreciated.
PKMexecute immediate 'with p as (select :vmonth_id pmon from dual) SELECT count(*) FROM x,p WHERE MONTH_ID = p.pmon UNION SELECT count(*) FROM Y,p WHERE MONTH_ID = p.pmon union SELECT count(*) FROM z,p WHERE MONTH_ID =p.pmon ' using month1;HTH
Nigel cordially
-
PerfMon statement drive dramatic increase in access to Oracle starting times
Hello
My Oracle 10 g (10.2.0.4) server is hosted on a windows 2003 server.
The data files are stored on a disk RAID1 on a dedicated partition array: currently 30 free concerts on 180, that shouldn't be a concern unless I am mistaken, because the data files have been created in the form of 10 GB of files with no automatic growth. I add a new data file whenever I need more space for my tables (alerts when 80% used).
Since 2 days I feel a loss of theatrical representation:
The EM console reports nothing special (no alarm storage-related) outside the need for a more paged memory.
I have a reorg when segmentation Adviser suggests.
My the optimizer statistics are calculated by the default scheduled task.
The strange thing I noticed is that as soon as I start the database, there is a huge disk activity increase even if no request at all is submitted to the database.
PerfMon reports current length of queue of > 1000 disc and disc > 3000 ms access time
CPU is 2% of the activity on the 4-CPU server.
I have a lot of spare memory (currently 3 used on the 16 GB).
It is a server dev for ETL processes, there is very little simultaneous connections.
Any suggestion is welcome.
AWR report is available here
http://min.us/mqnXQhd5Z
Published by: user10799939 on March 22, 2012 09:30Cache Sizes ~~~~~~~~~~~ Begin End ---------- ---------- Buffer Cache: 1,296M 1,296M Std Block Size: 8K Shared Pool Size: 160M 160M Log Buffer: 14,364K Load Profile ~~~~~~~~~~~~ Per Second Per Transaction --------------- --------------- Redo size: 460,955.72 ; 2,477,358.63 Logical reads: 3,392.16 ; 18,230.80 Block changes: 6,451.93 ; 34,675.22 Physical reads: 2.92 ; 15.67 Physical writes: 394.52 ; 2,120.28 User calls: 1.69 ; 9.08 Parses: 3.31 ; 17.81 Hard parses: 0.17 ; 0.90 Sorts: 1.32 ; 7.09 Logons: 0.06 ; 0.31 Executes: 7.01 ; 37.68 Transactions: 0.19 % Blocks changed per Read: 190.20 ; Recursive Call %: 96.23 Rollback per transaction %: 0.30 ; Rows per Sort: 14.41 Instance Efficiency Percentages (Target 100%) ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Buffer Nowait %: 99.98 ; Redo NoWait %: 99.86 Buffer Hit %: 99.92 ; In-memory Sort %: 100.00 Library Hit %: 96.30 ; Soft Parse %: 94.96 Execute to Parse %: 52.74 ; Latch Hit %: 99.07 Parse CPU to Parse Elapsd %: 0.35 ; % Non-Parse CPU: 99.30 Shared Pool Statistics Begin End ------ ------ Memory Usage %: 75.48 ; 75.51 % SQL with executions>1: 79.92 ; 85.03 % Memory for SQL w/exec>1: 77.07 ; 70.09 Top 5 Timed Events Avg %Total ~~~~~~~~~~~~~~~~~~ wait Call Event Waits Time (s) (ms) Time Wait Class ------------------------------ ------------ ----------- ------ ------ ---------- db file sequential read 9,052 17,688 1954 51.3 ; User I/O log file switch (checkpoint in 5,303 4,649 877 13.5 Configurat log file switch completion 4,245 4,023 948 11.7 Configurat wait for a undo record 32,393 3,531 109 10.3 ; Other db file parallel write 18,771 3,437 183 10.0 System I/Ohaven't seen as much waiting on average. For example, 877ms for "log file switch" is above the threshold. And other events waiting too...
Time Model Statistics DB/Inst: MDMPRJ/MDMPRJ Snaps: 2840-2841 -> Total time in database user-calls (DB Time): 34446.5s -> Statistics including the word "background" measure background process time, and so do not contribute to the DB time statistic -> Ordered by % or DB time desc, Statistic name Statistic Name Time (s) % of DB Time ------------------------------------------ ------------------ ------------ sql execute elapsed time 4,008.5 ; 11.6 parse time elapsed 352.9 ; 1.0 hard parse elapsed time 352.7 ; 1.0 PL/SQL compilation elapsed time 120.1 ; .3 DB CPU 61.8 ; .2 failed parse elapsed time 21.3 ; .1 PL/SQL execution elapsed time 8.0 ; .0 connection management call elapsed time 0.0 ; .0 hard parse (sharing criteria) elapsed time 0.0 ; .0 repeated bind elapsed time 0.0 ; .0 hard parse (bind mismatch) elapsed time 0.0 ; .0 DB time 34,446.5 ; N/A background elapsed time 14,889.7 ; N/A background cpu time 39.0 ; N/A ------------------------------------------------------------- Wait Class DB/Inst: MDMPRJ/MDMPRJ Snaps: 2840-2841 -> s - second -> cs - centisecond - 100th of a second -> ms - millisecond - 1000th of a second -> us - microsecond - 1000000th of a second -> ordered by wait time desc, waits desc Avg %Time Total Wait wait Waits Wait Class Waits -outs Time (s) (ms) /txn -------------------- ---------------- ------ ---------------- ------- --------- User I/O 10,515 .1 17,785 1691 15.8 Configuration 10,186 79.5 ; 8,865 870 15.3 System I/O 27,619 .0 8,774 318 41.6 Other 57,768 98.3 ; 6,915 120 87.0 Commit 2,634 88.6 ; 2,481 942 4.0 Concurrency 2,847 75.4 ; 2,240 787 4.3 Application 219 2.3 ; 23 105 0.3 Network 4,790 .0 0 0 7.2 -------------------------------------------------------------once seen it yet, there is an expectation very strong user IO
Wait Events DB/Inst: MDMPRJ/MDMPRJ Snaps: 2840-2841 -> s - second -> cs - centisecond - 100th of a second -> ms - millisecond - 1000th of a second -> us - microsecond - 1000000th of a second -> ordered by wait time desc, waits desc (idle events last) Avg %Time Total Wait wait Waits Event Waits -outs Time (s) (ms) /txn ---------------------------- -------------- ------ ----------- ------- --------- db file sequential read 9,052 .0 17,688 1954 13.6 log file switch (checkpoint 5,303 78.0 ; 4,649 877 8.0 log file switch completion 4,245 89.2 ; 4,023 948 6.4 wait for a undo record 32,393 99.8 ; 3,531 109 48.8 db file parallel write 18,771 .0 3,437 183 28.3 wait for stopper event to be 24,203 99.8 ; 2,634 109 36.5 log file sync 2,634 88.6 ; 2,481 942 4.0 control file sequential read 7,356 .0 2,431 330 11.1 buffer busy waits 2,513 83.1 ; 2,173 865 3.8 log file parallel write 520 .0 1,566 3012 0.8 control file parallel write 840 .0 1,334 1588 1.3 rdbms ipc reply 172 91.3 ; 330 1916 0.3 enq: CF - contention 309 23.0 ; 268 867 0.5 log buffer space 638 28.5 ; 192 301 1.0 enq: PS - contention 52 23.1 ; 71 1362 0.1 db file scattered read 113 .0 67 590 0.2 os thread startup 76 77.6 ; 63 834 0.1 reliable message 57 78.9 ; 50 878 0.1 enq: RO - fast object reuse 22 22.7 ; 23 1038 0.0 latch free 537 .0 16 30 0.8 Streams AQ: qmn coordinator 3 100.0 ; 15 5005 0.0Overrides
Background Wait Events DB/Inst: MDMPRJ/MDMPRJ Snaps: 2840-2841 -> ordered by wait time desc, waits desc (idle events last) Avg %Time Total Wait wait Waits Event Waits -outs Time (s) (ms) /txn ---------------------------- -------------- ------ ----------- ------- --------- db file parallel write 18,772 .0 3,437 183 28.3 events in waitclass Other 24,367 99.5 ; 3,010 124 36.7 control file sequential read 6,654 .0 2,333 351 10.0 log file parallel write 520 .0 1,566 3012 0.8 control file parallel write 840 .0 1,334 1588 1.3 buffer busy waits 899 94.2 ; 884 984 1.4 log file switch (checkpoint 206 82.0 ; 185 898 0.3 os thread startup 76 77.6 ; 63 834 0.1 log file switch completion 46 93.5 ; 45 982 0.1 log buffer space 158 31.0 ; 12 77 0.2 db file sequential read 62 .0 7 111 0.1 db file scattered read 20 .0 6 318 0.0 direct path read 660 .0 5 7 1.0 log file sequential read 66 .0 4 65 0.1 log file single write 66 .0 1 16 0.1 enq: RO - fast object reuse 2 .0 0 38 0.0 latch: cache buffers chains 3 .0 0 6 0.0 direct path write 660 .0 -5 -8 1.0 rdbms ipc message 9,052 87.5 ; 21,399 2364 13.6 pmon timer 1,318 90.4 ; 3,562 2703 2.0 Streams AQ: qmn coordinator 633 97.6 ; 3,546 5602 1.0 Streams AQ: waiting for time 77 61.0 ; 3,449 44795 0.1 PX Deq: Join ACK 21 .0 0 0 0.0Once again exceeded
Tablespace IO Stats DB/Inst: MDMPRJ/MDMPRJ Snaps: 2840-2841 -> ordered by IOs (Reads + Writes) desc Tablespace ------------------------------ Av Av Av Av Buffer Av Buf Reads Reads/s Rd(ms) Blks/Rd Writes Writes/s Waits Wt(ms) -------------- ------- ------ ------- ------------ -------- ---------- ------ UNDOTBS1 914 0 ###### 1.0 ; 1,368,515 383 2,534 863.2 MDMREF_INDICES 6,918 2 ###### 1.0 ; 11,086 3 0 0.0 SYSAUX 626 0 ###### 1.1 ; 1,804 1 0 0.0 SYSTEM 850 0 ###### 1.7 ; 296 0 0 0.0 MDMREF_DATA 293 0 712.3 ; 1.0 ; 274 0 0 0.0 MDMPRJ_ODS 198 0 72.1 ; 1.0 ; 198 0 0 0.0 FEU_VERT 33 0 61.5 ; 1.0 ; 33 0 0 0.0 USERS 33 0 31.5 ; 1.0 ; 33 0 0 0.0 -------------------------------------------------------------Now have a serious look. AV Dr (ms). For a value of tablespace cannot event now enter the window that's why its display #.
According to the recommendation of the oracle Av Rd (ms) should not be greater than 20, if his will on 20 so its considered to be a problem with the IO subsystem. But as its seen in your case its passing.
Now the question on my side
Did configuration changes?
I suggest you undo these changes as soon as possible and to communicate with the storage admin guys...Hope this helps
-
I need help to understand time model statistics and wait events, I understand that statistical model time is divided into two trees, one for the background processing carried out by the database instance itself and one for the foreground treatment (treatment performed on behalf of an application). In the foreground tree are the time for treatment, measurement process that do not expect. My question is:
All measures in the foreground process tree is a part of the time processor, for example, if I see a DB CPU TIME of 4.4% and an elapsed time of sql in the 90s, I can't assume it's 90% 4.4% and the rest of the DB spend their waiting time?
I know that the statistics of time DB indicates the duration of treatment accumulated elapsed time of not-idle sessions.
The image you posted is from book Chris Antognini ALBUMS - do you have a copy? The answer to your question is in the paragraphs following the figures.
Example:
- From time to time DB's CPU
- From time to time DB is SQL execute elapsed time
- From time to time DB is PL/SQL execution elapsed
BUT you can simply add the three components together because
- Some of the DB CPU comes from the SQL execute elapsed time
- Some of the DB CPU comes the duration of execution of PL/SQL
- etc.
In order to do not you talk about 90% or 4.4% - maybe that 4.4 percent is CPU used in the treatment of PL/SQL and a bit of it is used in the SQL - you can't tell of this set of statistics.
Concerning
Jonathan Lewis
-
Difference between CPU DB and DB times
Hello
What is the difference between CPU DB and DB AWR report?
BR,
REDAFor a session, with a view to the db, a session can be one of three things:
1 work (i.e. on the CPU or waiting for CPU)
2. pending a not-idle event
3 idle
> 1DB CPU is the CPU time. It means only ACTIVELY work on CPU. Queue TIME is not included.
Queue time is not included - it is the CPU or waiting to get the CPU (which the db has no knowledge of)
> In 10 Minute intervals with four CPU, is the Maximum DB CPU 40 Minutes?
Fix.
> It says that time DB = includes time CPU + IO time + queue time
E/s time is measured in queue time - file db scattered reading, sequential reading of file db, etc, etc.
> Why has separated?
Don't know. Perhaps to clarify the absoluately then IO is included in DB times
> Is it possbile to split TIME CPU? As the analysis etc... What display you give him?
See time model statistics
> in a given interval, where can I find NO idle timeout in AWR?
Top 5 + Foreground wait Class + waiting in the foreground events
Maybe you are looking for
-
Write to the file of text formatting issues
My apologies if I touch on a topic that is discussed elsewhere. I have two questions, which seems to be related, I'll have to overcome the difficulties. I date of blood collection, converting it to a temperature and then writes the timestamp, tempe
-
All Progammically DTR, DSR, and RTS to CTS?
I am trying to contact an extech with Labview power Analyzer. Recording of data and all thier software cable work. According to the manual. I need to bind the RTS to CTS and DTR, DSR. I try to use the Visa controls. Series of visa, Visa Read and
-
How can I programmatically draw new circles on an image control
Hi, I'm fairly new LV and programming in general. I'm creating a program to get better. In this program, I have balls bouncing around on an image control. I use a table to keep track of the ball position (x, y) and the other to follow their speed. I
-
XP, fs9 my tracks are black, I do not see the shadow of the planes. Is it possible to recover?
-
How can I update the video card driver
video card How do I see what I've got the video card. Windows xp pro tried playind a new game and all I get is square and lines where should be the graphixs and letters.