Before Insert TRIGGER to create partitions problem

Hello

I m having a problem with the following situation in Oracle 8i:

I have a table TEST_TABLE, which is divided by the beach with a DATE column. The idea is to have a partition for each month, so the HIGH_VALUE of partitions is always the first day of the month following that represents the partition.

I created a BEFORE TRIGGER INSERT on the table TEST_TABLE, which tests if the partition for the month of registration which is being inserted exists and, in case it doesn´t, a PROC AUTONOMOUS_TRANSACTION is called to create the TRIGGER.

Running the code below one can see that even if partitions are created as expected, when you try to insert a record with a date greater than the last partition for the first time, this error is returned:
ORA-14400: inserted partition key exceeds plu legal partition key.

Note that if you run the same statement again insert, it s inserted correctly on the partition that was created the first try.

I´ll appreciate any help on this matter.

code
----------------
CREATE TABLE TEST_TABLE)
IDENTIFICATION NUMBER,
DATE OF THE DT
)
TABLESPACE USERS
PARTITION BY RANGE (DT)
(
PART_B42009 PARTITION VALUES LESS THAN (TO_DATE ('2009-01-01 00:00:00 ',' YYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))
LOGGING
TABLESPACE USERS
);
/

CREATE OR REPLACE PROCEDURE SP_ADD_PARTITION (TEST_TABLE P_DATE. DT % TYPE)
IS
PRAGMA AUTONOMOUS_TRANSACTION;
V_STR VARCHAR2 (500);
BEGIN

V_STR: = 'ALTER TABLE TEST_TABLE ADD.
|| 'PARTITION BIRD | TO_CHAR ("P_DATE, ' YYYYMM")
|| ' VALUES LESS (TO_DATE ("')).
|| TO_CHAR (ADD_MONTHS (P_DATE, 1), "YYYY-MM"). '-01 00:00:00 ','
|| ((' SYYYY-MM-DD HH24:MI:SS "," NLS_CALENDAR = GREGORIAN "))';

EXECUTE IMMEDIATE (V_STR);

END SP_ADD_PARTITION;
/

CREATE OR REPLACE TRIGGER TR_B_I_R_TEST_TABLE
BEFORE INSERTING
ON TEST_TABLE FOR EACH LINE
DECLARE
NUMBER OF V_PARTITION_EXISTS;
BEGIN

IF: NEW. DT > = TO_DATE ('2009-01-01 00:00:00 ',' ' YYYY-MM-DD HH24:MI:SS) THEN

IMMEDIATELY EXECUTE (' SELECT COUNT (1) ")
|| "Of all_tab_partitions atp'."
|| "WHERE atp.table_name ="table_test"'.
|| "AND the atp. Nom_partition =: v1 ')
IN V_PARTITION_EXISTS
WITH THE HELP OF "BIRD" | TO_CHAR(:NEW.) "DT,"YYYYMM";)

IF V_PARTITION_EXISTS = 0 THEN

DBMS_OUTPUT. Put_line ('Partition [' |]) 'BIRD ' | TO_CHAR(:NEW.) "DT,"YYYYMM"). does not exist!') ;
DBMS_OUTPUT. Put_line ('creation..');
SP_ADD_PARTITION (: NEW.) DT);
DBMS_OUTPUT. Put_line ('success.');

IMMEDIATELY EXECUTE (' SELECT COUNT (1) ")
|| "Of all_tab_partitions atp'."
|| "WHERE atp.table_name ="table_test"'.
|| "AND the atp. Nom_partition =: v1 ')
IN V_PARTITION_EXISTS
WITH THE HELP OF "BIRD" | TO_CHAR(:NEW.) "DT,"YYYYMM";)

IF V_PARTITION_EXISTS = 1 THEN
DBMS_OUTPUT. Put_line ("it s visible at this point..");
ON THE OTHER
DBMS_OUTPUT. Put_line ("it s not visible at this point..");
END IF;

ON THE OTHER

DBMS_OUTPUT. Put_line ('Partition [' |]) 'BIRD ' | TO_CHAR(:NEW.) DT, "YYYYMM")
|| already exists! ") ;

END IF;

END IF;

DBMS_OUTPUT. Put_line ('continues with insertion...");

END TR_B_I_R_TEST_TABLE;
/

-Go to the low score
INSERT INTO TABLE_TEST VALUES (1, TO_DATE ('2008-12-31 23:59:59 ',' YYYY-MM-DD HH24:MI:SS'));))

-Returns the error on the first try
INSERT INTO TABLE_TEST VALUES (2, TO_DATE ('2009-01-01 00:00:01 ',' YYYY-MM-DD HH24:MI:SS'));))

----------------

It is the use of the pragma AUTONOMOUS TRANSACTION. Your current transaction cannot see the result of this DOF since it occurs outside of the current transaction. The clue is in the name.

Of course, you cannot run the DDL in a trigger without use of this pragma, so you're pretty much stuck. There is a solution in 11g, but that will not help you. Unfortunately, your only option is to pre-create the partitions required in front of the need. For example, you might have a DBMS JOB to create a partition for the next month, which takes place the last day of each month (or logical date of company).

Cheers, APC

blog: http://radiofreetooting.blogspot.com

Tags: Database

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    WHERE profile_questions_id =: new.profilequestion_id;

    IF (v_a IS NOT NULL AND YaeUb IS NOT NULL AND v_c IS NOT NULL AND v_d IS NOT NULL AND EV IS NOT NULL) THEN

    BEGIN

    a_weightage: = 85;

    b_weightage: = 60;

    c_weightage: = 45;

    d_weightage: = 30;

    e_weightage: = 15;

    END;

    ELSIF (v_a IS NOT NULL AND YaeUb IS NOT NULL AND v_c IS NOT NULL AND v_d IS NOT NULL AND ve IS NULL) THEN

    BEGIN

    a_weightage: = 85;

    b_weightage: = 60;

    c_weightage: = 30;

    d_weightage: = 15;

    END;

    ELSIF (v_a IS NOT NULL AND YaeUb IS NOT NULL AND v_c IS NOT NULL AND v_d IS NULL AND ve IS NULL) THEN

    BEGIN

    a_weightage: = 85;

    b_weightage: = 45;

    c_weightage: = 15;

    END;

    ON THE OTHER

    BEGIN

    a_weightage: = 85;

    b_weightage: = 15;

    END;

    END IF;

    IF: new.answer = 'A' THEN

    BEGIN

    UPDATE user_profileanswers

    SET weightage = a_weightage

    WHERE user_id =: new.user_id

    AND profileanswer_id =: new.profileanswer_id

    AND profilequestion_id =: new.profilequestion_id;

    END;

    ELSIF: new.answer = 'B' THEN

    BEGIN

    UPDATE user_profileanswers

    SET weightage = b_weightage

    WHERE user_id =: new.user_id

    AND profileanswer_id =: new.profileanswer_id

    AND profilequestion_id =: new.profilequestion_id;

    END;

    ELSIF: new.answer = 'C' THEN

    BEGIN

    UPDATE user_profileanswers

    SET weightage = c_weightage

    WHERE user_id =: new.user_id

    AND profileanswer_id =: new.profileanswer_id

    AND profilequestion_id =: new.profilequestion_id;

    END;

    ELSIF: new.answer = ' THEN

    BEGIN

    UPDATE user_profileanswers

    SET weightage = d_weightage

    WHERE user_id =: new.user_id

    AND profileanswer_id =: new.profileanswer_id

    AND profilequestion_id =: new.profilequestion_id;

    END;

    ON THE OTHER

    BEGIN

    UPDATE user_profileanswers

    SET weightage = e_weightage

    WHERE user_id =: new.user_id

    AND profileanswer_id =: new.profileanswer_id

    AND profilequestion_id =: new.profilequestion_id;

    END;

    END IF;

    END;

    END;

    Thanks in advance.

    Hmm... Why do after insertion?

    CREATE OR REPLACE TRIGGER BI_weightageCaluculation

    FRONT INSERT ON user_profileanswers FOR EACH ROW

    BEGIN

    SELECT BOX: NEW. RESPONSE

    WHEN 'A' a_weight THEN

    WHEN 'B' THEN b_weight

    WHEN 'C' THEN c_weight

    When ' THEN d_weight

    Of OTHER e_weight

    END

    in: new.weightage

    (SELECT 85 a_weight

    Case option_result

    WHEN 31 THEN 60

    WHEN 15 THEN 60

    WHEN 7 THEN 45

    another 15

    end b_weight

    Case option_result

    WHEN 31 THEN 45

    WHEN 15, THEN 30

    When 7 then 15

    END c_weight

    Case option_result

    WHEN 31 THEN 30

    When 15 then 15

    END d_weight

    Case option_result

    WHEN 31 THEN 15

    END e_weight

    FROM (SELECT DECODE (option_a, NULL, 0, 1) +)

    Decode (option_b, NULL, 0, 2) +.

    Decode (option_c, NULL, 0, 4) +.

    Decode (option_d, NULL, 0, 8) +.

    Decode(option_e,,0,16) option_result

    OF profiles_answers

    WHERE profile_questions_id =: new.profilequestion_id));

    END;

    /

    HTH

  • Truncate a field before inserting

    Suppose I have the following text:

    Array: mytable

    field: username (VARCHAR2 (35))

    field: zip (VARCHAR2 (5))

    I am importing data from an excel with columns username and zip file. A couple of the usernames contains more than 35 characters, and some postal codes are in the format xxxx-xxxxx, therefore containing more than 5 characters.

    I tried to write an insert before truncating the data until they are inserted. For any user name that is longer than 35 characters in Excel, simply truncate the username to the first of 35 characters. Similarly, for any ZIP code which is above 5 characters, just truncate the zip on the first 5 characters.

    The trigger for postal codes:

    CREATE OR REPLACE

    Trigger_zipc RELAXATION

    BEFORE INSERTING

    ON mytable

    FOR EACH LINE

    BEGIN

    SELECT substr (: new .zip, 1, 5)

    IN: new.zip

    Double;

    END;

    However, I get the error: ORA-12899: value too large for column

    I understand that this happens because the value is read before my validation, and because the value is too large, it is not allowed to insert.

    I'm not sure where to go from here. Any suggestions?

    

    Is it excel file or a csv file.
    

    I think you can look into creating an external table as well.
    

    Before inserting it just to make a substring.
    

    Something along the lines.
    

    CREATE TABLE ext_data (
 username CHAR(500),
  zip CHAR(500))
  ORGANIZATION EXTERNAL (TYPE ORACLE_LOADER DEFAULT DIRECTORY ext_tab_dir
  ACCESS PARAMETERS (FIELDS TERMINATED BY ',')
  LOCATION ('csv.dat'));

insert into mytable
select substr(username,1,35) , substr(zip,1,5) from ext_data;

    

    I hope this helps.
    

    Alvinder
    		   
    •  
            
           
  •  
		     
    How to do before delete trigger
     
			 Hi all
    I want to do before you remove the trigger
    I have 2 tables hr_api_transactions and new_table
    When I delete records from table hr_api_transations
    This deleted record should then be stored / table new_table insert
    for this I need before delete trigger
    

    How can I do?			 
    Also, you do not want the table name must be specified
    

    CREATE OR REPLACE TRIGGER before_delete_trigger
    BEFORE DELETE
        ON HR_API_TRANSACTIONS
        FOR EACH ROW
BEGIN
  delete from new_table
   where new_table.name = :OLD.api_addtnl_info;
END;

    

    Justin
    		   
    •  
            
           
  •  
		     
    After the insert trigger error
     
			 Hello
    

    I created a trigger after insert according to for me, it's OK, but it show me error can not insert Null in code.
    


     


CREATE OR REPLACE TRIGGER  "AFT_INS_CRM_CUSTOMER_CONTACTS" 
  AFTER INSERT ON FH_TAPROD.CRM_SALES_CUSTOMER_CONTACTS 
FOR EACH ROW
DECLARE
custo_id NUMBER;
var_code varchar2(8);
cont_code varchar2(5);
BEGIN

SELECT CUSTOMER_ID INTO custo_id FROM CRM_SALES_CUSTOMER_CONTACTS WHERE ID =:NEW.ID;

  select CODE into var_code from VENDOR_CUSTOMER_MAS where CRM_CUST_ID=custo_id ;

  SELECT LPAD ( NVL(MAX(CONTACT_CODE), 0)+ 1, 5, '0') into cont_code FROM vendor_customer_contact
  
  insert into VENDOR_CUSTOMER_CONTACT(SBU_CODE ,CODE,CONTACT_CODE, CONTACT_NAME ,PHONE_NO1 ,MOBILE_NO ,EMAIL, ADDRESS1,CUST_ID,UPLOAD_CRM) 
   values('0002',var_code,cont_code,:NEW.CONTACT_NAME,:NEW.CONTACT_PHONE,:NEW.CONTACT_CELL,:NEW.CONTACT_EMAIL,:NEW.CONTACT_ADDRESS,custo_id,'CRM');


END; 
    CREATE TABLE  "CRM_SALES_CUSTOMER_CONTACTS" 
   (     "ID" NUMBER, 
     "CUSTOMER_ID" NUMBER, 
     "CONTACT_NAME" VARCHAR2(255), 
     "CONTACT_EMAIL" VARCHAR2(255), 
     "CONTACT_PHONE" VARCHAR2(255), 
     "CONTACT_CELL" VARCHAR2(255), 
     "CONTACT_ADDRESS" VARCHAR2(4000), 
      PRIMARY KEY ("ID") ENABLE
   )
/
INSERT INTO CRM_SALES_CUSTOMER_CONTACTS VALUES (204414862717175278810736770347803084847, 204232590877603599356756434170666837075, 'SANJAY',    '[email protected]', 1246456, 57152357,'Near Post Office');
    CREATE OR REPLACE TRIGGER  "BIU_CRM_SALES_CUST_CONTACTS" 
BEFORE INSERT OR UPDATE ON CRM_SALES_CUSTOMER_CONTACTS
    FOR EACH ROW
begin
    if inserting and :new.id is null then
        select to_number(sys_guid(),'XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX') into :new.id from dual;
    end if;
    if inserting then
        :new.created_by := nvl(v('APP_USER'),USER);
        :new.created_on := sysdate;
    end if;
    if updating then
        :new.updated_by := nvl(v('APP_USER'),USER);
        :new.updated_on := sysdate;
    end if;
end;
    My after insert a table
    CREATE TABLE  "VENDOR_CUSTOMER_CONTACT" 
   (     "SBU_CODE" VARCHAR2(4) NOT NULL ENABLE, 
     "CODE" VARCHAR2(8) NOT NULL ENABLE, 
     "CONTACT_CODE" VARCHAR2(5) NOT NULL ENABLE, 
     "CONTACT_NAME" VARCHAR2(1000) NOT NULL ENABLE, 
     "PHONE_NO1" VARCHAR2(100), 
     "MOBILE_NO" VARCHAR2(25), 
     "EMAIL" VARCHAR2(1000), 
     "ADDRESS1" VARCHAR2(4000), 
     "CUST_ID" NUMBER, 
     "UPLOAD_CRM" VARCHAR2(10), 
      CONSTRAINT "VCV_PK" PRIMARY KEY ("SBU_CODE", "CODE", "CONTACT_CODE") ENABLE
   )
    ORA-01400: cannot insert NULL into ("FH_TAPROD"."VENDOR_CUSTOMER_CONTACT"."CODE") ORA-06512: at "FH_TAPROD.AFT_INS_CRM_CUSTOMER_CONTACTS", line 30 ORA-04088: error during execution of trigger 'FH_TAPROD.AFT_INS_CRM_CUSTOMER_CONTACTS'
    How to solve it.
    

    Thank you
    

    Published by: 805629 on January 14, 2011 01:26			 
    This is the error...
    

    SELECT CUSTOMER_ID INTO custo_id FROM CRM_SALES_CUSTOMER_CONTACTS WHERE ID =: NEW.ID;
    

    Is there a reason why not to use: NEW. CUSTOMER_ID rather the query?
    		   
    •  
            
           
  •  
		     
    Helps relaxation that fits into another table before insertion
     
			 I have two tables:
    

    TABLE A as follows:
    x, y, z
    1, 1, 1
    1, 1, 2
    1, 1, 3
    

    TABLE B as follows
    c, d, e, f
    1, 1, 1, 8
    1, 1, 1, 2
    1, 1, 1, 6
    1, 1, 2, 5
    1, 1, 2, 10
    1, 1, 2, 3
    1, 1, 3, 12
    1, 1, 3, 11
    1, 1, 3, 15
    

    

    I want a trigger, BEFORE insertion in the TABLE B, I want to INSERT into TABLE A as follows:
    

    c = > x
    d = > y
    e = > z
    

    ONLY IF a (x, y, z) record does not already exist in the TABLE.
    

    That is to say. If record (1, 1, 3) already exists in the TABLE, we do not try to put it back when you insert in the TABLE B with values containing (1, 1, 3).			 
    You will need
    

    CREATE OR REPLACE trig_on_insert
BEFORE INSERT ON B
FOR EACH ROW
IS
   lv_count    NUMBER := 0;
BEGIN
   SELECT COUNT(1)
     INTO lv_count
     FROM a
    WHERE x = :new.c
      AND y = :new.d
      AND z = :new.e ;

   IF ( lv_count = 0 ) THEN
      INSERT INTO A VALUES(:new.c,:new.d ,:new.e);
   END IF;
END;
/

    

    Concerning
    Arun
    		   
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