Between specific dates by month SQL

Similar Questions

• records between specific dates

  Hi all
  
  We have a table named where it is saved all the information of people as well as their start date and end date I need the list of all employees who were at the table between the dates
  
  (1) 2001 and 2002
  (2) 2002 and 2003
  (3) 2003 and 2004
  (4) 2004 and 2005
  
  
  
  Any suggestions on what are really appreciated.
  
  Thank you
  
  PK

  Hello

  Your question could mean several different things.
  Please post some sample data and the result you want to obtain from these data. If you post the CREATE TABLE and INSERT statements (or equivalent), then people will be able to test their ideas.

  Looks like you need join a table that contains a line for each period of time in whioch you are interested (2001-2002, 2002-2003,...) to your table and do a COUNT, with period of GROUP BY.
  If you do not have a table with one line per period, you can generate a result set that will work as well in a subquery.

  The join condition will be something like

  (     start_date <= end_period
  AND     end_date   >= begin_period
  )
  

• Months between two dates

  Hello

  I have two dates. start date and end date.

  I want to extract months between two dates

  months should be as

  JAN

  FEB

  MAR

  for example.

  Start - 1-jan-2014

  date of end - 31 - dec - 2014

  How can I do this?

  Thanks and greetings

  CORINE

  You should always use the function MONTHS_BETWEEN...

  for example

  SQL > ed
  A written file afiedt.buf

  1 with t as (select date '' 2014-01-01 as start_date date ' 2014-12-31' as double end_date)
  2  --
  3 end of test data
  4  --
  5. Select to_char (add_months (start_date, rownum-1), 'My') by month
  6 t
  7 * connect by rownum<=>
  SQL > /.

  LUN
  ---
  Jan
  Feb
  Mar
  Apr
  May
  Jun
  Jul
  Aug
  Ms
  Oct
  Nov
  Dec

  12 selected lines.

  And if you want that they display, separated by commas...

  SQL > ed
  A written file afiedt.buf

  1 with t as (select date '' 2014-01-01 as start_date date ' 2014-12-31' as double end_date)
  2  --
  3 end of test data
  4  --
  5 Select listagg (to_char (add_months (start_date, rownum-1), 'My'), ',') group by month (order by rownum)
  6 t
  7 * connect by rownum<=>
  SQL > /.

  MONTH
  -----------------------------------------------------------------------------------------------------------------
  Jan, Feb, Mar, Apr, may, June, July, August, Sept, Oct, Nov, Dec

• difference between two dates in the year/month/day in Obiee

  Hi gurus,

  I know this question have been asked and answered several times but I have a requirement that is a little different, then the previous ones.

  I want to calculate the difference between two dates in OBIEE10g in year/month/day format similar to the below SQL output

  SQL > select end_date, start_date,

  trunc (months_between (end_date, start_date) / 12) years.

  months of mod (trunc (months_between (end_date, start_date)), 12).

  End_date - add_months (start_date, trunc (months_between (end_date, start_date))) days

  t

  Thanks in advance

  SK

  Search for this

  "TIMESTAMPDIFF IN THE FORM OF MTHS # YEARS."

  or else

  To get the current mandate of employees since the date of hiring in the form of # years # mths or # year (s) # month (s)

  Concat (concat (cast (TIMESTAMPDIFF (SQL_TSI_Month, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) / 12 as char),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Month (s)'))

  Concat (concat (CAST (TIMESTAMPDIFF (SQL_TSI_YEAR, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) as CHAR),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Mth (s)'))

• Get the number of months between the dates.

  Hi I need to get the exact number of months between the dates. So if I'm Sysdate - to_date(31-JAN-2011) I should get something like 8.4 months. Months_between function doesn't quite give me what I need. Is it possible that I can do this?

  876056 wrote:
  Hi I need to get the exact number of months between the dates. So if I'm Sysdate - to_date(31-JAN-2011) I should get something like 8.4 months. Months_between function doesn't quite give me what I need. Is it possible that I can do this?

  I don't see how you get 8.4 months. The counted months are February, March, April, may, June, July, August and, as of today, 9 and change the days of September. Unless I forgot the lessons of counting, I learned in kndergarten is 7 full months and a bit.

  Maybe you want something like:

  SQL> select months_between(Sysdate, to_date('01-JAN-2011', 'dd-mon-yyyy')) mb,
    2         (Sysdate - to_date('01-JAN-2011', 'dd-mon-yyyy'))/30 div30
    3  from dual;
  
          MB      DIV30
  ---------- ----------
  8.27800142 8.38726813
  

  If you get the form date a table, you can use trunc (date_column, 'mm') at the date of the first day of the month.

  John

• Display the months between two dates

  Hello:
  I need all the months between two dates. I entered two dates as January 15, 2001 and 2011-mar-03. I want the result as below.
  
  JANUARY 15, 2011 - JANUARY 31, 2011
  February 1, 2011 - February 28, 2011
  MARCH 1, 2011 - MARCH 3, 2011
  
  I held this result of sql query in oracle. Could you please suggest me?
  Thanks in advance.
  Abhishek

  SELECT     GREATEST(st, ADD_MONTHS(TRUNC(st, 'MONTH'), (LEVEL - 1))) dt,
             LEAST(ed, LAST_DAY(ADD_MONTHS(TRUNC(st, 'MONTH'), (LEVEL - 1)))) ld
        FROM (SELECT DATE '2011-01-15' AS st, DATE '2011-03-03' AS ed
                FROM DUAL)
  CONNECT BY LEVEL <= MONTHS_BETWEEN(TRUNC(ed, 'MONTH'), TRUNC(st, 'MONTH')) + 1
    ORDER BY 1;
  
  DT                       LD
  ------------------------ ------------------------
  15.01.2011 00:00:00      31.01.2011 00:00:00
  01.02.2011 00:00:00      28.02.2011 00:00:00
  01.03.2011 00:00:00      03.03.2011 00:00:00
  

  HTH, Urs

• Get the number of month, week and day between 2 dates

  Hi all
  
  Is it possible to display the number of months, weeks and days between 2 dates? by using only the SQL or PL/SQL...
  
  Entry:
  Date: October 1, 2010
  Date: October 19, 2010
  
  I want output like below (assuming starts the week from Monday to Sunday in oracle).
  
  October 1, 2010-(since it's in the middle of the week)
  October 2, 2010-(since it's in the middle of the week)
  October 3, 2010-(since it's in the middle of the week)
  40. (4 Oct-10 Oct falls into the 40th week of the year)
  41. (11 Oct-17 Oct falls into the 41st week of the year)
  October 18, 2010-(since it's in the middle of the week)
  October 19, 2010-(since it's in the middle of the week)
  
  
  Note: If there is a month between the date, the number of the month should be displayed.
  End of the month, the remaining date included with a full week, then the week of the year number should
  displayed. After posting the week, remaining dates should be displayed as it is...
  
  
  Appreciate your help...
  
  
  
  Thank you.
  Fox.

  You mean something like this...

  SQL> ed
  Wrote file afiedt.buf
  
    1  WITH t AS (select date '2010-09-27' as fdate, date '2010-11-21' as tdate from dual)
    2  --
    3  -- END OF TEST DATA
    4  --
    5  select dt2
    6  from (
    7        select dt,
    8               case when days_of_mn = days_in_month then 'Whole: '||to_char(dt,'Month')
    9                    when days_of_wk = 7 then 'Week: '||to_char(dt,'fmWW')
   10               else to_char(dt, 'DD-fmMonth-YYYY')
   11               end as dt2
   12              ,row_number() over (partition by
   13                 case when days_of_mn = days_in_month then to_char(dt,'Month')
   14                                  when days_of_wk = 7 then 'Week: '||to_char(dt,'fmWW')
   15                 else to_char(dt, 'DD-fmMonth-YYYY')
   16                 end order by dt) as rn
   17        from (
   18              select dt, wk, mn, days_in_month
   19                    ,count(*) over (partition by wk) as days_of_wk
   20                    ,count(*) over (partition by mn) as days_of_mn
   21              from (
   22                    select fdate+rownum-1 as dt
   23                          ,to_number(to_char(fdate+rownum-1,'fmWW')) as wk
   24                          ,to_number(to_char(fdate+rownum-1,'fmMM')) as mn
   25                          ,to_number(to_char(last_day(fdate+rownum-1),'fmDD')) as days_in_month
   26                    from t
   27                          connect by rownum <= tdate-fdate+1
   28                   )
   29             )
   30        ) x
   31  where rn = 1
   32* order by dt
  SQL> /
  
  DT2
  -----------------
  27-September-2010
  28-September-2010
  29-September-2010
  30-September-2010
  Whole: October
  Week: 44
  Week: 45
  Week: 46
  19-November-2010
  20-November-2010
  21-November-2010
  
  11 rows selected.
  
  SQL>
  

• get all the date of end of months between two dates

  Hi all, I'll try to find together the date of end of months between two dates.
  I have the following data in a table
  
  WITH AS's Data1
  (
  SELECT To_Date('4/30/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual UNION ALL
  SELECT To_Date('5/01/2009','mm/dd/yyyy') dt, "TEST2" lname FROM dual UNION all
  SELECT To_Date('5/02/2009','mm/dd/yyyy') dt, "TEST3" lname FROM dual UNION all
  SELECT To_Date('5/03/2009','mm/dd/yyyy') dt, "TEST4" lname FROM dual UNION all
  SELECT To_Date('5/04/2009','mm/dd/yyyy') dt, "TEST5" lname FROM dual UNION all
  SELECT To_Date('5/05/2009','mm/dd/yyyy') dt, "TEST6" lname FROM dual UNION ALL
  SELECT To_Date('5/31/2009','mm/dd/yyyy') dt, 'TEST7' lname FROM dual UNION all
  SELECT To_Date('6/01/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual
  
  )
  
  I would like to write an application that gives you all the end date for months between two dates
  for example, if you give the date 9/1/4 and 5/6/9, the output should be
  

  DT          LNAME
  -------------------
  4/30/2009   TEST

  IF I give you the dates 01/04/09 AND 01/06/09, THEN output should be

  DT          LNAME
  -------------------
  4/30/2009   TEST
  5/31/2009   TEST7

  as you can see, I want all the end dates of months between two dates by giving the output.
  
  If I give you 06/05/09 and 05/06/09, and then does so no output because there is no end of month between these two dates.
  Similarly, if I give you 30/04/09 and 30/04/09 then output should be 30/04/09 because it is an end of month date
  
  anyone can help to write a query. Thank you very much

  Jin
  Not sure if you need subquery, analytical functions for this.
  According to me, which should solve your purpose.

  WITH data1 AS
  (
  SELECT To_Date('4/30/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual UNION ALL
  SELECT To_Date('5/01/2009','mm/dd/yyyy') dt, 'TEST2' lname FROM dual UNION all
  SELECT To_Date('5/02/2009','mm/dd/yyyy') dt, 'TEST3' lname FROM dual UNION all
  SELECT To_Date('5/03/2009','mm/dd/yyyy') dt, 'TEST4' lname FROM dual UNION all
  SELECT To_Date('5/04/2009','mm/dd/yyyy') dt, 'TEST5' lname FROM dual UNION all
  SELECT To_Date('5/05/2009','mm/dd/yyyy') dt, 'TEST6' lname FROM dual UNION ALL
  SELECT To_Date('5/31/2009','mm/dd/yyyy') dt, 'TEST7' lname FROM dual UNION all
  SELECT To_Date('6/01/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual 
  
  )
  select distinct last_day(dt) dt,lname
    from data1
   where dt between &start_date and &end_date
     and last_day(dt) <= &end_date
  

  also, i have another request. how would i do this without using the data i provided. lets say,
   i tell you, give me alll the months end between two dates using dual in the from clause of a query.
  how would you do this in a query or pl/sql? thanks again
  

  Can be like that

  with data1 as(
  select &start_date+level-1 dt from dual
  connect by level <= &end_date-&start_date+1)
  select distinct last_day(dt)
    from data1
   where dt between &start_date and &end_date
     and last_day(dt) <= &end_date
   order by last_day(dt)
  

  See you soon!
  Bobin

  Published by: Buga added query for updated the need

• Length of the different interval between two dates in SQL/PLSQL

  Dear gurus, here are three questions to ask:
  1. Why is the result queries are different?
  2 - is a way to measure the length of the interval in seconds (L) between two dates?
  2. why the different result is generated in SQL and PL/SQL only to subtract dates from the 28th day of the month?
  
  declare
  number of l_offset;
  Start
  l_offset: = (to_date('09-nov-2009') - to_date ('28.10.2009 10:40:03 ', ' dd.mm.yyyy hh24:mi:ss')) * 86400;))
  dbms_output.put_line (l_offset);
  l_offset: = (to_date('09-nov-2009') - to_date ('27.10.2009 10:40:03 ', ' dd.mm.yyyy hh24:mi:ss')) * 86400;))
  dbms_output.put_line (l_offset);
  end;
  998396.9999999999999999999999999999999997
  1084797
  
  
  Select (to_date('09-nov-2009') - to_date ('28.10.2009 10:40:03 ', ' dd.mm.yyyy hh24:mi:ss')) * double 86400))
  Union of all the
  Select (to_date('09-nov-2009') - to_date ('27.10.2009 10:40:03 ', ' dd.mm.yyyy hh24:mi:ss')) * double 86400))
  (TO_DATE('09-NOV-2009')-TO_DAT
  998397
  1084797
  
  
  Oracle9i Enterprise Edition Release 9.2.0.7.0 - Production
  PL/SQL Release 9.2.0.7.0 - Production
  CORE 9.2.0.7.0 Production
  AMT for Linux: release 9.2.0.7.0 - Production
  NLSRTL Version 9.2.0.7.0 - Production

  Hello

  Sorry, I'm still not sure you understand the question.

  You wonder why the rounding error is apparent to 6 digits to the left of the decimal separator in numbers, but not in number 7 digits to the left of the decomal? The answer is itself a rounding error.
  When Oracle is the arithmetic mean of the dates, the result is a fraction that cannot be stored in a binary number, such as preciesly
  998396.9999999999999999999999999999999996857... it it rounds to the nearest value it can store, such as
  998396.9999999999999999999999999999999997. in other words, it can store 40 digits. In this case, 6 figures to the left of the decimal separator and 34 of the figures to the right. The number is rounded to the nearest multiple of 10 ^-34 ^
  What happens if we add 86400 this number?

  
   998396.9999999999999999999999999999999997
  + 86400.0000000000000000000000000000000000
  ------------------------------------------
  1084796.9999999999999999999999999999999997
  

  Now we need 7 digits before the comma, then round the number to the nearest multiple of 10 ^-33 ^, which is
  1084797.000000000000000000000000000000000

• Formula to determine if a specific day of the week between two dates?

  I am creating a spreadsheet to track my time PD & holiday. I usually work weekends, and my vacation allowance includes a specific maximum number of Sundays a year. Is there a way to calculate how much Sunday fall between a date range (or any day of the week, by the way)?

  (i.e. If my vacation starts February 1, 2016 and ends March 2, 2016, Sunday how are included?)

  I know that I can calculate how many weeks have passed, using = Quotient (DateDiff (Start_Date, End_Date), 7), but it is possible to include two Sundays in a period of 7 days.

  Hi Eric,.

  Here is one approach.

  

  C2 = A2 + (7−WEEKDAY(A2,2))

  This concludes the first Sunday following the start date.

  

  D2 = STRIPDURATION ((B2−C2) ÷7)

  I formatted this column without decimal places to see full weeks of the first numbers Sunday.

  Quinn

• To find the months and days between 2 dates

  Hello

  I want to find the months and days between 2 dates.

  For example.

  1 - Date: August 25, 2013

  2 - Date: October 23, 2013

  If we consider each month 30 days, it should give

  August 25, 2013 to August 30, 2013 = 6 days

  01-Sep-2013-30-Sep-2013 = 1 month

  October 23, 2013 to October 30, 2013 = 8 days

  Total = 1 month and 14 days.

  Kindly help as soon as possible.

  Thanks and greetings

  Suresh

  Assuming that d2 > d1,.

  where d)

  Select sysdate d1, sysdate + 56 double d2

  Union all select to_date (March 1, 2013 ',' dd-mon-yyyy "") d1, to_date (March 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (5 February 2013 ',' dd-mon-yyyy ') d1, to_date (March 31, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (February 25, 2013 ',' dd-mon-yyyy "") d1, to_date (March 23, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (February 25, 2013 ',' dd-mon-yyyy ') d1, to_date (March 31, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (August 2, 2013 ',' dd-mon-yyyy "") d1, to_date (29 October 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (February 1, 2013 ',' dd-mon-yyyy "") d1, to_date (May 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (25 August 2013 ',' dd-mon-yyyy "") d1, to_date ('03-Sep-2013', 'Mon-dd-yyyy') d2 double

  Union all select to_date (July 30, 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (July 31, 2013 ',' dd-mon-yyyy ') d1, to_date (August 30, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (July 31, 2013 ',' dd-mon-yyyy ') d1, to_date (3 August 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (3 July 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date ('31-08-2013', ' dd-mm-yyyy'), to_date('05-10-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('31-03-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('05-03-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('05-02-2013','dd-mm-yyyy') of the double

  )

  Select d1, d2,

  1 + 30 * trunc (months_between (d2, d1)) + LESS (extract (day of d2), 30)-LESS (excerpt (d1 day), 30)

  + CASE when extracted (d2 day)< extract(day="" from="" d1)="" then="" 30="" else="" 0="" end ="">

  d

  D1 D2 DAYSBETWEEN

  ----------- ----------- -----------

  October 10, 2013 5 December 2013 56

  March 1, 2013 30 March 31, 2013

  5 February 2013 March 31, 2013 56

  February 25, 2013 March 23, 2013 29

  February 25, 2013 March 31, 2013 36

  August 2, 2013 29 October 2013 88

  February 1, 2013 may 31, 2013 120

  August 25, 2013 03 - Sep-2013 9

  July 30, 2013 31 August 31, 2013

  July 31, 2013 August 30, 2013 31

  July 31, 2013 3 August 2013 4

  July 3, 2013 August 31, 2013 58

  31 August 2013 5 October 2013 36

  5 February 2013 March 31, 2013 56

  5 February 2013 March 5, 2013 31

  February 5, 2013 February 5, 2013 1

  In my view, which corresponds to your rules.

• How to calculate the number of days/weeks/months between 2 dates?

  Hello
  
  I would like to know how to calculate the number of days/weeks/months between 2 dates in OBIEE 11 g, for example, I have 26/05/2013 and 19/05/2013, then I want to get 7 days.
  
  Thank you!
  Jamie

  Hi Jamie,

  Through this links...

  http://www.bravesoft.com/blog/?p=682
  http://twobiee.blogspot.in/2012/01/working-with-date-differences.html

  Mark as correct it allows u...
  Thank you...

• How to display each month between the date range

  I want a query that gives me the number of months between two dates given for example, if I going January 1, 2009 and April 1, 2009 then I should get on February 1, 2009 and March 1, 2009 in my trips
  
  Thank you very much

  Srix wrote:
  Thanks for the request

  It is not working do not when the effective date is differs from that in a year i.e start date January 1, 2009 and end date February 1, 2009, that it does not give u then required result

  I don't know what you mean? The dates are in the same year.

• Retrieve all dates between 2 date

  My dear

  If I have 2 Dates I need sql give any dates between these taches\

  for example

  I have table tab1 in this neck of table called hiredate

  I want to get the lowest dates and max then give all dates between these 2 date

  If the lowest date = 01/01/2014

  and the date max = 20/05/2014

  then sql retive

  01/01/2014

  01/02/2014

  01/03/2014

  .....

  ...

  ..

  TO

  20/05/2014

  Thanks in advance

  Hello

  user222 wrote:

  My dear

  If I have 2 Dates I need sql give any dates between these taches\

  for example

  I have table tab1 in this neck of table called hiredate

  I want to get the lowest dates and max then give all dates between these 2 date

  If the lowest date = 01/01/2014

  and the date max = 20/05/2014

  then sql retive

  01/01/2014

  01/02/2014

  01/03/2014

  .....

  ...

  ..

  TO

  20/05/2014

  Thanks in advance

  If you want rows with the date the lowest, highest and any date between these two then:

  SELECT *- or whatever the columns that you want to

  OF tab1

  WHERE hiredate IS NOT NULL;

  I hope that answers your question.

  If this isn't the case, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.

  In the case of a DML (such as INSERT) operation the sample data should show what look like the paintings before the DML, and results will be the content of the or a modified tables after the DML.

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: Re: 2. How can I ask a question on the forums?

• Number of weeks between two dates that are in the same or different year

  Hello

  How to calculate the number of weeks between two dates?

  for example. "" "17-mar-2013' and June 27, 2013" or June 15, 2013 "and" 25-mar-2014
  

  
  

  Thanks in advance.

  lukx
  

  Hello

  Looks like your date range is incorrect.

  Please try the below.

  SQL >-front right

  SQL > select D2 - D1 "days."

  2 round ((D2-D1)/7.0) "weeks."

  3 round (Months_between (d1, d2), 0) 'months '.

  (select 4

  5 TO_DATE ('20121201', 'YYYYMMDD') D1, D2 TO_DATE ('20130116', 'YYYYMMDD')

  6 from two

  (7) date_range;

  Elapsed days weeks months

  ------------ --------- ---------

  46         7         1