Display the months between two dates

Hello:
I need all the months between two dates. I entered two dates as January 15, 2001 and 2011-mar-03. I want the result as below.

JANUARY 15, 2011 - JANUARY 31, 2011
February 1, 2011 - February 28, 2011
MARCH 1, 2011 - MARCH 3, 2011

I held this result of sql query in oracle. Could you please suggest me?
Thanks in advance.
Abhishek

SELECT     GREATEST(st, ADD_MONTHS(TRUNC(st, 'MONTH'), (LEVEL - 1))) dt,
           LEAST(ed, LAST_DAY(ADD_MONTHS(TRUNC(st, 'MONTH'), (LEVEL - 1)))) ld
      FROM (SELECT DATE '2011-01-15' AS st, DATE '2011-03-03' AS ed
              FROM DUAL)
CONNECT BY LEVEL <= MONTHS_BETWEEN(TRUNC(ed, 'MONTH'), TRUNC(st, 'MONTH')) + 1
  ORDER BY 1;

DT                       LD
------------------------ ------------------------
15.01.2011 00:00:00      31.01.2011 00:00:00
01.02.2011 00:00:00      28.02.2011 00:00:00
01.03.2011 00:00:00      03.03.2011 00:00:00

HTH, Urs

Tags: Database

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According to me, which should solve your purpose.
```
WITH data1 AS
(
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)
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 where dt between &start_date and &end_date
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```
```
also, i have another request. how would i do this without using the data i provided. lets say,
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how would you do this in a query or pl/sql? thanks again
```
Can be like that
```
with data1 as(
select &start_date+level-1 dt from dual
connect by level <= &end_date-&start_date+1)
select distinct last_day(dt)
  from data1
 where dt between &start_date and &end_date
   and last_day(dt) <= &end_date
 order by last_day(dt)
```
See you soon!
Bobin

Published by: Buga added query for updated the need

Months between two dates

Hello
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I want to extract months between two dates
months should be as
JAN
FEB
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for example.
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Thanks and greetings
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You should always use the function MONTHS_BETWEEN...

for example

SQL > ed
A written file afiedt.buf

1 with t as (select date '' 2014-01-01 as start_date date ' 2014-12-31' as double end_date)
2 --
3 end of test data
4 --
5. Select to_char (add_months (start_date, rownum-1), 'My') by month
6 t
7 * connect by rownum<=>
SQL > /.

LUN
---
Jan
Feb
Mar
Apr
May
Jun
Jul
Aug
Ms
Oct
Nov
Dec

12 selected lines.

And if you want that they display, separated by commas...

SQL > ed
A written file afiedt.buf

1 with t as (select date '' 2014-01-01 as start_date date ' 2014-12-31' as double end_date)
2 --
3 end of test data
4 --
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MONTH
-----------------------------------------------------------------------------------------------------------------
Jan, Feb, Mar, Apr, may, June, July, August, Sept, Oct, Nov, Dec

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I have a requirement to count the hours with 2 given timestamps, something like:
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         B
----------
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```
declare
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declare
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-----------
My Blog: http://www.inside-oracle-apex.com
APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
Twitter: http://www.twitter.com/patrickwolf

Published by: Patrick Wolf on January 17, 2011 10:54

Find the difference between two date and time

Hi friends,

I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."

select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
from eval.EVAL_RUNTIME_DETAILS
where trunc(start_date) = trunc(sysdate) 
order by sql_step_num;

You try to get the feel between two char strings.
And more difference between two dates gives a NUMBER of days.
Try this:

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Select the mountains between two dates

Hi all
How can I select all months between two dates. For example, if two dates are say 2008-05-25 and 2009-07-15, then I need following output

May-2008
June-2008
July-2008
August-2008
September-2008
October-2008
November-2008
December-2008
January-2009
February-2009
March-2009
April-2008
May-2009
-June 2009
July-2009

Thank you
Sujnan

Try this one

SQL>  SELECT TO_CHAR(add_months(TRUNC(to_date('25/05/2008','DD/MM/YYYY'),'MM') ,(level-1)),'fmMonth-YYYY')
  2     FROM dual
  3    CONNECT BY level <= months_between(to_date('15/07/2009','DD/MM/YYYY'),to_date('25/05/2008','DD/MM/YYYY')) + 2;

TO_CHAR(ADD_MO
--------------
May-2008
June-2008
July-2008
August-2008
September-2008
October-2008
November-2008
December-2008
January-2009
February-2009
March-2009

TO_CHAR(ADD_MO
--------------
April-2009
May-2009
June-2009
July-2009

15 rows selected.

SQL>

Need help on the list of months between two Dates

Hi all

I have a table which has startdate and enddate and need a select to list all the months between these two dates for each given ID.
I did some tests and could not figure out how to get the startdate and enddate table (instead of hard coding) tests in the select statement.

Could someone please help on this (Oracle 11 g 2),
Thanks in advance!

create table testing(
id          number,
start_date  date,
end_date    date);
insert into testing values(100, to_date('05-FEB-2011', 'DD-MON-YYYY'), to_date('28-MAY-2011', 'DD-MON-YYYY'));
insert into testing values(200, to_date('20-JUN-2011', 'DD-MON-YYYY'), to_date('28-DEC-2011', 'DD-MON-YYYY'));
commit;

select * from testing;

        ID START_DAT END_DATE
---------- --------- ---------
       100 05-FEB-11 28-MAY-11
       200 20-JUN-11 28-DEC-11

Elapsed: 00:00:00.01

*for testing.id = 100:*
select to_char(add_months(to_date('05-FEB-2011', 'DD-MON-YYYY'), l - 1), 'YYYY-Mon') Dates
 from (select level l
       from dual
    connect by level <= months_between(trunc(to_date('28-MAY-2011', 'DD-MON-YYYY'), 'MONTH'),
                                       trunc(to_date('05-FEB-2011', 'DD-MON-YYYY'), 'MONTH')) + 1);

DATES
-----------------
2011-Feb
2011-Mar
2011-Apr
2011-May

Elapsed: 00:00:00.01

*for testing.id = 200:*
select to_char(add_months(to_date('20-JUN-2011', 'DD-MON-YYYY'), l - 1), 'YYYY-Mon') Dates
 from (select level l
       from dual
    connect by level <= months_between(trunc(to_date('28-DEC-2011', 'DD-MON-YYYY'), 'MONTH'),
                                       trunc(to_date('20-JUN-2011', 'DD-MON-YYYY'), 'MONTH')) + 1);

DATES
-----------------
2011-Jun
2011-Jul
2011-Aug
2011-Sep
2011-Oct
2011-Nov
2011-Dec

7 rows selected.

SQL> select * from testing
  2  /

        ID START_DAT END_DATE
---------- --------- ---------
       100 05-FEB-11 28-MAY-11
       200 20-JUN-11 28-DEC-11

SQL> select  id,
  2          to_char(add_months(start_date,column_value - 1),'YYYY-Mon') dates
  3    from  testing,
  4          table(
  5                cast(
  6                     multiset(
  7                              select  level
  8                                from  dual
  9                                connect by add_months(trunc(start_date,'MM'),level - 1) <= end_date
 10                             )
 11                     as sys.OdciNumberList
 12                    )
 13               )
 14    order by id,
 15             column_value
 16  /

        ID DATES
---------- --------
       100 2011-Feb
       100 2011-Mar
       100 2011-Apr
       100 2011-May
       200 2011-Jun
       200 2011-Jul
       200 2011-Aug
       200 2011-Sep
       200 2011-Oct
       200 2011-Nov
       200 2011-Dec

11 rows selected.

SQL>

SY.

Need to query to find missing months between two dates.

A bank customer a monthly overview of databases (in the tens of millions of accounts)

The data are sent with a line per account each month. It is stored in a table called "ACCOUNTS_TAB".

Fields on registration, which

Column	Description	Example of format.
* YRMTH-1	Year and month of the snapshot	6-character numeric, 4-digit year added to months of 2 digits, example 201301, 201311
* AccountID	Unique identifier for an account.	Integer, example 100098322
Opening balance - 1	Initial account balance at the closing of the previous month	$30000
Closing balance - 1

The account balance at the end of the month of closing

$34200

Class-1 relative to investments

.....

...

.....

......

.....

Many more columns, two favorites (*) columns are alone, that you will need for the query. There are no columns to tell when an account is closed, or has just opened, and not separate "master account" - you use this single table for your query that results.

The table was in place from 200301, so many accounts have dozens of lines, if they have been open for many years and other only 1 or 2 ranks, if new.

Write a query to give just a list of accountDs that meet the following criteria.

1) has a record for specific 201503
2) was also a record for the month specific 201602
3) missing one or several months between these two records.

A good account which was opened from 201503 to 201602 inclusive would of course have lines for

201503

201504

201505

201506

201507

201508

201509

201510

201511

201512

201601

201602

It's good to hardcode the month of departure (201503), end of month (201602) and the actual number of months between them (10 exclusive or 12 inclusive) as part of your query.

Once again the account must meet all 3 criteria to be an account issue. If only, they have a partial set of these documents but do not have the month of departure, or is not the end of the month, it is not a problem, only when they have so specified and end early and not a full between game.

Help, please!

Maybe this...

-----

-The Dataset for the test begins

WITH dataset (ACCOUNT_NO, DATES)

AS (SELECT 100, DOUBLE 201503

UNION ALL

SELECT 100, DOUBLE 201504

UNION ALL

SELECT 100, DOUBLE 201505

UNION ALL

SELECT 100, DOUBLE 201506

UNION ALL

SELECT 100, DOUBLE 201507

UNION ALL

SELECT 100, DOUBLE 201508

UNION ALL

SELECT 100, 201509 OF THE DOUBLE

UNION ALL

SELECT 100, DOUBLE 201510

UNION ALL

SELECT 100, 201511 OF THE DOUBLE

UNION ALL

SELECT 100, DOUBLE 201512

UNION ALL

SELECT 100, 201601 DOUBLE

UNION ALL

SELECT 100, DOUBLE 201602

UNION ALL

SELECT 200, DOUBLE 201503

UNION ALL

SELECT 200, DOUBLE 201504

UNION ALL

SELECT 200, DOUBLE 201505

UNION ALL

SELECT 200, DOUBLE 201506

UNION ALL

SELECT 200, DOUBLE 201508

UNION ALL

SELECT 200, DOUBLE 201509

UNION ALL

SELECT 200, DOUBLE 201510

UNION ALL

SELECT 200, DOUBLE 201511

UNION ALL

SELECT 200, DOUBLE 201512

UNION ALL

SELECT 200, 201601 DOUBLE

UNION ALL

SELECT 200, DOUBLE 201602

UNION ALL

SELECT 300, DOUBLE 201503

UNION ALL

SELECT 300, DOUBLE 201504

UNION ALL

SELECT 300, DOUBLE 201505

UNION ALL

SELECT 300, DOUBLE 201506

UNION ALL

SELECT 300, DOUBLE 201507

UNION ALL

SELECT 300, DOUBLE 201508

UNION ALL

SELECT 300, DOUBLE 201509

UNION ALL

SELECT 300, DOUBLE 201510

UNION ALL

SELECT 300, DOUBLE 201511

UNION ALL

SELECT 300, 201601 DOUBLE

UNION ALL

SELECT 300, DOUBLE 201602

UNION ALL

SELECT 400, DOUBLE 201504

UNION ALL

SELECT 400, DOUBLE 201505

UNION ALL

SELECT 400, DOUBLE 201506

UNION ALL

SELECT 400, DOUBLE 201507

UNION ALL

SELECT 400, 201508 DOUBLE),

-The Dataset to test ends

-Hand with clause begins

ResultSet

AS (SELECT account_no,

CASE

WHEN COUNT)

CASE WHEN dates IN (201503, 201602) THEN 1 END)

COURSES (PARTITION BY account_no) = 2

AND (COUNT (DISTINCT SUBSTR (dates, 4)))

COURSES (PARTITION BY account_no) = 12

OR COUNT (DISTINCT SUBSTR (dates, 4))

COURSES (PARTITION BY account_no)<>

AND COUNT (DISTINCT SUBSTR (dates, 1, 4))

(PARTITION BY account_no) > 1

THEN

« Y »

ON THE OTHER

« N »

END

FLG

THE dataset---> replace with your table name

GROUP BY account_no, dates)

SELECT DISTINCT Account_no

FROM THE result set

WHERE flg = 'Y ';

-Hand with the ends of the clause

ACCOUNT_NO

-----------------------

100

300

200

See you soon,.

Manik.

Formula to determine if a specific day of the week between two dates?

I am creating a spreadsheet to track my time PD & holiday. I usually work weekends, and my vacation allowance includes a specific maximum number of Sundays a year. Is there a way to calculate how much Sunday fall between a date range (or any day of the week, by the way)?

(i.e. If my vacation starts February 1, 2016 and ends March 2, 2016, Sunday how are included?)

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I have 3 columns in my table

date of purchase date sold days
computer 24 April 09-11 May 09

How can I write that a sql statement will help me to create a new column days and days between date bought and sold

Thank you
872959 wrote:
I have 3 columns in my table

date of purchase date sold days
computer 24 April 09-11 May 09

How can I write that a sql statement will help me to create a new column days and days between date bought and sold

Thank you

just subtract two dates & the difference will be in units of days

SQL > select to_date('11-MAY-09','DD-MON-YY') - double TO_DATE('24-APR-09','DD-MON-YY');

TO_DATE('11-MAY-09','DD-MON-YY')-TO_DATE('24-APR-09','DD-MON-YY')
-----------------------------------------------------------------
17

Published by: sb92075 on July 19, 2011 10:26

How to tell the difference between two dates
Hello:

I have a question on how to get the difference in quantities for two dates in the replies and dashboard.

This is the scenario. I have two guests date and three columns. The first column must be the sum of the amounts for the first quick date. The second column should be the sum of the amounts for the second fast date. And the third column is the difference between the first two columns.

Basically, I'm trying to do something similar to a function of sum of two lines but trying to get the difference between the two rows. Any help to solve this problem would be appreciated.
Use the COLUMN FILTERS level...

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Similarly, the second column in the second variable of quick overview of date filter

Kind regards
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Excerpt from the hours between two dates

Hello
This is the value stored in the table of my database.
I want to extract betwwen hours two dates. How can I extract it.
I try to run like this
Select to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM') double, but it gives the answer as the format 21:10:00.000000000 + 000000365
I want simple hours, minutes, and seconds
What is the format of this value as "dd-MON-yy."
27 JANUARY 14 01.30.00.000000 PM
26 JANUARY 14 06.22.32.170033 PM

Use the Extract function. Like this.

() AS T1 (C1)

Select to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM') of double)

SELECT EXTRACT (DAY OF C1) | ' DAYS '.

EXTRACT (HOUR OF C1) | ' HOURS '.

EXTRACT (MINUTE OF C1) | ' MINUTES '.

EXTRACT (SECOND C1) | ' SECONDS

FROM T1;

OUTPUT:

365 DAYS 21 HOURS 10 MINUTES 0 SECONDS

If not try it.

SELECT EXTRACT (DAY OF to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM')) | ' DAYS '.

EXTRACT (HOUR FROM to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM')) | ' HOURS '.

EXTRACT (to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM') MINUTE) | ' MINUTES '.

EXCERPT ((SECOND from to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM')) |) ' SECONDS

DOUBLE;

Post edited by: Parth272025

How to find the difference between two dates in time except Sunday

Hi all

I have a table, as shown below.

SQL> select * from test;

TR_ID                                              CREATE_TIME                                                                       CODE
-------------------------------------------------- --------------------------------------------------------------------------- ----------
S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.

For example:

TR_ID: S12344
1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
1003_Create_time: 12.01.04.188000 AM 6 July 12

1002 create time is 22:00 Sunday.

If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.

I tried the sub query after doing a search on this forum but I am not getting the desired output.

SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
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Need help to get the desired o/p

Hello

If I unederstand the problem correctly, that's what you want:

WITH       got_extrema     AS
(
     SELECT       tr_id
     ,       CAST (MIN (create_time) AS DATE)     AS start_date
     ,       CAST (MAX (create_time) AS DATE)     AS end_date
     FROM       test
     GROUP BY  tr_id
)
SELECT       tr_id
,       start_date, end_date          -- If wanted
,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                    - TRUNC (start_date, 'IW')
             )
           / -7
              )
            + LEAST ( end_date               -- If end_date is a Sunday
                        , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                 )
            - CASE
                      WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
               THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
               ELSE  start_date
                  END
            )     AS total_hours
FROM      got_extrema
;

I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
(a) 1 day is deducted for each week between start_date and end_date
(b) if End_date is a Sunday, none of the end_date himself hours are counted
(c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
Always tell what version of Oracle you are using.
See the FAQ forum {message identifier: = 9360002}

Display the months between two dates

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