Length of the different interval between two dates in SQL/PLSQL

Similar Questions

• How do the time difference between two dates?

  Hi all
  
  I use this query to get the time difference between two dates.
  
  Select to_timestamp ('2012-10-03 12:00 ',' YYYY-MM-DD hh)-to_timestamp ('2012-10-03 11:00 ',' YYYY-MM-DD hh) as double diff;
  
  but do not get the correct result.
  
  Thank you

  Left KEY... Left Padding of tanks.

• Calculate the (age) years between two dates

  Nice day!

  I have not been able to find an answer, that I was able to use in the archives or online and would be very grateful for the help.  I'm working with Adobe Acrobat Pro XI (not LiveCycle) and I have very little experience with programming (for the most part, copy / paste).

  I need to create a text box that calculates the number of years between two dates entered, i.e. the age when the date of birth and death are given.  Also, would be nice if she was a Virgin until the two were provided.  Anyone would be able to give me the code I need to put in the custom calculation script?

  Once again, any help would be much appreciated!  Thank you and have a wonderful day!

  For the fields for Date of birth DOB and DOD for the Date of death and age in complete years both by using a'd-mmm-yyyy' date format you can use a custom calculation to the JavaScript for the field of age as:

  function GetField (cName) {}
  get the field with error trapping object;
  oField var = this.getField (cName);
  test error;
  if(oField == null) app.alert ("error during the" + cName, 1, 0);
  Returns the field object;
  return oField;
  } / / end GetField function;

  function {Scand (cFormat, cString)
  using date string format convert object date;
  convert string to date using format;
  Kai var = util.scand (cFormat, cString);
  the value null is an error of conversion;
  if(oDate == null) app.alert ("Conversion error" cString "by using the format" + cFormat, 1, 0);
  date of return;
  Return to oDate;
  } / / end Scand function;

  clear the value of the field;

  Event.Value ="";
  get data dob and dod;
  var oDOB = GetField ("DOB");
  Var o = GetField ("DOD");

  treat only if DOB and DOD have value and are not null;
  If (oDOB! = null & o! = null & oDOB.value! = "" & oDOD.value!) = "") {}

  convert the DOB and DOD to date objects.
  oDOB var = util.scand ("d-mmm-yyyy", oDOB.value);
  O var = util.scand ("d-mmm-yyyy", oDOD.value);

  get the difference over the years;
  var Age = oDOD.getFullYear () - oDOB.getFullYear ();

  adjust for month of previous DOD DOB;
  If (oDOD.GetMonth)< odob.getmonth())="">

  adjust the DOD before DOB date in the month of birth;

  If (oDOD.GetMonth () == oDOB.getMonth () & oDOD.getDate ())< odob.getdate())="">
  Set the value of the field;

  Event.Value = Age;
  }

• How to calculate an interval between two dates?

  Hi all
  
  I have two dates, and I need to know if the interval between the two is more than 30 days or not. I can't understand how to calculate this interval.
  Could someone help me?
  Thank you very much.

  See the following forumpost:

  Re: Calculation of difference in date in BPEL

  Kind regards

  Melvin

• What is the time interval between two Oracle certification exams?

  Hello world

  I'm looking forward to associate level certification in SQL and PL/SQL.

  According to a link from the official website of Oracle, I need to spend the next two STAGES to win the Oracle PL/SQL Developer Certified Associate Certification. The two steps are:

  URL of the location where the screenshots below (measures) is as follows:

  https://education.Oracle.com/pls/web_prod-PLQ-dad/db_pages.GetPage?page_id=653 & get_params = P_ID:162 #tabs - 1

  

  

  There are to options available in two stages , so I chose to give the two following tests:

  1 (from step 1) EXAM: 1Z0-061 (database Oracle 12 c: basic SQL)

  REVIEW 2 (step 2): 1Z0-144 (Oracle Database 11 G: program PL/SQL)

  Now my questions are these:

  Question 1: I intend to take the exam 1Z0-061 first (lets say in June), may therefore take the second exam (1Z0-144) at any time after appearing for the first review or is there no specific time frame in which I'm suppose to take the second review?

  
  

  Question 2: will what type of certification I get if I take only one exam (1Z0-061 or 1Z0-144)? I know Oracle's official website said that in order to get "Oracle PL/SQL Developer Certified Associate Certification", I need to pass the two exams; but what happens if I chose to give only a single review at the present time? In the case giving a single review, what type of document of certification will I right to (wave speculation: right to half certification Oracle PL/SQL Developer )?

  Thanking you.

  
  

  Best regards

  Ankit

  Answer 1: He is there no time limit/limit. Finally, I guess Oracle takes his retirement 1Z0-144, but which does not occur for many years.  They have not even removed from the earlier incarnation (1Z0-147).

  Answer 2: Passing a review in itself does not have a certification or credential.  The only "book", you will have is the sheet of test results.

• get all the date of end of months between two dates

  Hi all, I'll try to find together the date of end of months between two dates.
  I have the following data in a table
  
  WITH AS's Data1
  (
  SELECT To_Date('4/30/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual UNION ALL
  SELECT To_Date('5/01/2009','mm/dd/yyyy') dt, "TEST2" lname FROM dual UNION all
  SELECT To_Date('5/02/2009','mm/dd/yyyy') dt, "TEST3" lname FROM dual UNION all
  SELECT To_Date('5/03/2009','mm/dd/yyyy') dt, "TEST4" lname FROM dual UNION all
  SELECT To_Date('5/04/2009','mm/dd/yyyy') dt, "TEST5" lname FROM dual UNION all
  SELECT To_Date('5/05/2009','mm/dd/yyyy') dt, "TEST6" lname FROM dual UNION ALL
  SELECT To_Date('5/31/2009','mm/dd/yyyy') dt, 'TEST7' lname FROM dual UNION all
  SELECT To_Date('6/01/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual
  
  )
  
  I would like to write an application that gives you all the end date for months between two dates
  for example, if you give the date 9/1/4 and 5/6/9, the output should be
  

  DT          LNAME
  -------------------
  4/30/2009   TEST

  IF I give you the dates 01/04/09 AND 01/06/09, THEN output should be

  DT          LNAME
  -------------------
  4/30/2009   TEST
  5/31/2009   TEST7

  as you can see, I want all the end dates of months between two dates by giving the output.
  
  If I give you 06/05/09 and 05/06/09, and then does so no output because there is no end of month between these two dates.
  Similarly, if I give you 30/04/09 and 30/04/09 then output should be 30/04/09 because it is an end of month date
  
  anyone can help to write a query. Thank you very much

  Jin
  Not sure if you need subquery, analytical functions for this.
  According to me, which should solve your purpose.

  WITH data1 AS
  (
  SELECT To_Date('4/30/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual UNION ALL
  SELECT To_Date('5/01/2009','mm/dd/yyyy') dt, 'TEST2' lname FROM dual UNION all
  SELECT To_Date('5/02/2009','mm/dd/yyyy') dt, 'TEST3' lname FROM dual UNION all
  SELECT To_Date('5/03/2009','mm/dd/yyyy') dt, 'TEST4' lname FROM dual UNION all
  SELECT To_Date('5/04/2009','mm/dd/yyyy') dt, 'TEST5' lname FROM dual UNION all
  SELECT To_Date('5/05/2009','mm/dd/yyyy') dt, 'TEST6' lname FROM dual UNION ALL
  SELECT To_Date('5/31/2009','mm/dd/yyyy') dt, 'TEST7' lname FROM dual UNION all
  SELECT To_Date('6/01/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual 
  
  )
  select distinct last_day(dt) dt,lname
    from data1
   where dt between &start_date and &end_date
     and last_day(dt) <= &end_date
  

  also, i have another request. how would i do this without using the data i provided. lets say,
   i tell you, give me alll the months end between two dates using dual in the from clause of a query.
  how would you do this in a query or pl/sql? thanks again
  

  Can be like that

  with data1 as(
  select &start_date+level-1 dt from dual
  connect by level <= &end_date-&start_date+1)
  select distinct last_day(dt)
    from data1
   where dt between &start_date and &end_date
     and last_day(dt) <= &end_date
   order by last_day(dt)
  

  See you soon!
  Bobin

  Published by: Buga added query for updated the need

• How to return all dates between two dates?

  Hi all
  
  I need get all dates between two dates, Oracle SQL and PL/SQL.
  
  for example

  01/10/2011 - date 1
  10/11/2011 - date 2
  
  # Return Values
  01/10/2011
  10/02/2011
  03/10/2011
  .
  .
  .
  09/11/2011
  10/11/2011

  How can I get these values? Any help will be useful.
  
  Thank you

  Maybe

  select :start_date + level - 1 the_date
    from dual
  connect by level <= :end_date - :start_date + 1
  

  Concerning

  Etbin

• Number of weeks between two dates that are in the same or different year

  Hello

  How to calculate the number of weeks between two dates?

  for example. "" "17-mar-2013' and June 27, 2013" or June 15, 2013 "and" 25-mar-2014
  

  
  

  Thanks in advance.

  lukx
  

  Hello

  Looks like your date range is incorrect.

  Please try the below.

  SQL >-front right

  SQL > select D2 - D1 "days."

  2 round ((D2-D1)/7.0) "weeks."

  3 round (Months_between (d1, d2), 0) 'months '.

  (select 4

  5 TO_DATE ('20121201', 'YYYYMMDD') D1, D2 TO_DATE ('20130116', 'YYYYMMDD')

  6 from two

  (7) date_range;

  Elapsed days weeks months

  ------------ --------- ---------

  46         7         1

• difference between two dates in the year/month/day in Obiee

  Hi gurus,

  I know this question have been asked and answered several times but I have a requirement that is a little different, then the previous ones.

  I want to calculate the difference between two dates in OBIEE10g in year/month/day format similar to the below SQL output

  SQL > select end_date, start_date,

  trunc (months_between (end_date, start_date) / 12) years.

  months of mod (trunc (months_between (end_date, start_date)), 12).

  End_date - add_months (start_date, trunc (months_between (end_date, start_date))) days

  t

  Thanks in advance

  SK

  Search for this

  "TIMESTAMPDIFF IN THE FORM OF MTHS # YEARS."

  or else

  To get the current mandate of employees since the date of hiring in the form of # years # mths or # year (s) # month (s)

  Concat (concat (cast (TIMESTAMPDIFF (SQL_TSI_Month, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) / 12 as char),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Month (s)'))

  Concat (concat (CAST (TIMESTAMPDIFF (SQL_TSI_YEAR, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) as CHAR),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Mth (s)'))

• JavaScript anomaly on the number of days between two dates

  Use ApEx 4.0, I found an anomaly in a javascript code that calculates the number of days between two dates, the current_date and the past_date. If the past and present is the or before March 10, 2013, and the current_date lies between 10 March 2013 and November 3, 2013, the number of days will be from 1 day to less than the actual number. Between November 3, 2013 and on 4 November 2013, the increments of number by 2, then the count will be accurate from this date forward.
  
  Here are some examples:
  
  March 10, 2013 = 69 days of December 31, 2012
  March 11, 2013 = 69 days of December 31, 2012
  March 12, 2013 = 70 days of December 31, 2012
  
  November 3, 2013 = 306 days in December 31, 2012
  November 4, 2013 = 308 days in December 31, 2012
  
  11 March should be 70 and 12 March should be 71. November 3 is 307 and 4 November corrects the number of fake, which began March 11.
  
  Change the past_date to March 10, 2013 produces the following:
  
  March 10, 2013 = 0 days of March 10, 2013
  March 11, 2013 = 0 days of March 10, 2013
  March 12, 2013 = 1 days of March 10, 2013
  
  But change the past_date to 11 March 2013, product of the correct numbers:
  
  March 11, 2013 = 0 days of March 11, 2013
  March 12, 2013 = 1 days of March 11, 2013
  March 13, 2013 = 2 days of March 11, 2013
  
  I would certainly all help to determine the cause of this anomaly. Here's the javascript code:
  
  var w1 = ($v ("P48_PAST_DATE"));
  W1 = (w1.toString ());
  vmon var = (w1.substr (3.3));
  vyr var = (w1.substr (7));
  var r = (vyr.length);
  If (r == 2)
  vyr. = (parseFloat (vyr) + 2000);
  vday var = (w1.substr (0.2));
  var y = (vmon.concat ("", vday, ",", vyr));
  y = Date.parse (y);
  
  var w2 = ($v ("P48_CURRENT_DATE"));
  var vmon2 = (w2.substr (3.3));
  var vyr2 = (w2.substr (7));
  var vday2 = (w2.substr (0.2));
  var x = (vmon2.concat ("", vday2, ",", vyr2));
  x = Date.parse (x);
  
  var numdays = (x - y);
  numdays = (Math.floor(numdays / 86400000));
  $s ("P48_NUMBEROFDAYS", numdays);

  Did you google for something like "javascript number of days between two dates. I think you will find the explanation to this observation:

  This method does not work correctly if there is an advanced economies jump between the two dates.

  There are examples available to calculate the difference between two dates.

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

• Calculate the number of days between two dates

  Hello

  Can someone help please change my formcalc script to calculate the number of working days between two date fields.  My script currently calculates the total number of days between two dates, including the weekends which must be excluded from the total.

  If

  (HasValue (Start_Date1) & HasValue (End_Date1)) then

  $

  = Date2Num (End_Date1, "YYYY-MM-DD" "en_IE") - Date2Num (Start_Date1, "YYYY-MM-DD" "en_IE") + 1

  on the other

  ""

  endif

  Any help will be most appreciated.

  Thank you.

  Check...

  (1) you said that you put the script on the event «days1» calculate My sample imitates the variable names used in the original message, "Start_Date1" and "End_Date1". If the names of variables for the start and end dates are different, you will need to modify the script to account for these names.

  (2) the Date2Num functions in the calculation of the "totalDays" use the date format "YYYY-MM-DD". If your date habits differ from "YYYY-MM-DD" FormCalc will complain.

  Steve

• MaxL Script to clear the data between two dates

  Hi all

  I need advice to clear the data between two dates, I have three dimensions in my sketch, 'eno', 'hiredate' and the 'actualamount '.

  Now I need to erase the data between the date range, up to now, I have this script,

  Fix ("HireDate", "Eno")

  Difficulty (@relative ("00:00:00",0),@relative("eno",0)) 2015-07-15 "))

  CLEARDATA "sal."

  endfix

  ENDFIX

  These scripts only clears on a specific day, but I tried to write the script to clear between two dates, I surfed on a few sites, but no clear answers, finaanly came here, kindly help in this regard.

  Thanks in advance.

  Have you not tried the format of "startdate":"enddate" for example "August":"September."

  See you soon

  John

• Dynamic calculation of the number of days between two dates in a table

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  Hi BO123,

  BO123 wrote:

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  one of the way to do this by calling ajax on change of end_date.

  See the sample code given below to fetch the resulting duration and making the field read only after calculation

  Step 1: Change your page

  under CSS-> Inline, put the code below

  .row_item_disabled {
    cursor: default;
    opacity: 0.5;
    filter: alpha(opacity=50);
    pointer-events: none;
  }
  

  Step 2: Create on demand Ajax process I say CALC_DURATION

  Please check Procces Ajax, see line 6.7 How to assign a value to the variable sent by ajax call

  Declare
    p_start_date  date;
    p_end_date    date;
    p_duration number;
  Begin
    p_start_date  := to_date(apex_application.g_x01);
    p_end_date    := to_date(apex_application.g_x02);
  
     --do your calculation and assign the output to the variable p_duration
    select p_end_date - p_start_date into p_duration
      from dual;
  
    -- return calculated duration
    sys.htp.p(p_duration);
  End;
  

  Step 3: Create the javascript function

  Change your page-> the function and the declaration of the Global Variable-> put the javascript function

  You must extract the rowid in the first place, for which you want to set the time, see line 2

  assuming f06, f07 and f08 is the id of the start date, and end date columns respectively, and duration

  See no line no 8 how set the value returned by the process of ajax at the duration column

  Replace your column to the respective column identifiers in the code below

  function f_calulate_duration(pThis) {
    var row_id  = pThis.id.substr(4);
    var start_date = $('#f06_'+row_id).val();
    apex.server.process ( "CALC_DURATION", {
    x01: start_date,x02: $(pThis).val()
  }, { success: function( pData ) {
  // set duration to duration column
  $('#f08_'+row_id).val(pData);
  // disable duration column
  $("#f08_" + row_id).attr("readonly", true).addClass('row_item_disabled'); }
  });
  }
  

  Step 4: choose the end date call the javascript function

  Go to report attributes-> edit your Date column end-> column-> Attrbiutes element attributes-> put the code below

  onchange="javascript:f_calulate_duration(this);"
  

  
  

  hope this helps you,

  Kind regards

  Jitendra
  

• Calculate the hours between two dates

  Hello
  
  I have a requirement to count the hours with 2 given timestamps, something like:

  SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;
  
           B
  ----------
          48

  However, I wish it would be that simple. I just need to count the hours between two timestamps for the hours of work for example, 08:00 - 17:00, MONDAY to Friday (excluding weekends).
  So lets say I have to count the hours between two dates above the result should be 18 hours not 48 (4 hours on 20/oct, 9 hours on 21/oct to 5 hours 22/oct).
  How can I achieve this? Any idea will be useful.
  
  Thank you

  My query generates a list of all the hours between the start and end time, filters on the hours that are outside of the hours of work and then account for the remaining lines. Change that to partial hours must just be a case of replace the two occurrences of 1/24 with 24/01/60, then - as say you - Division COUNT (*) by 60.

  There may be performance issues using techniques of generation of line like this, if you put this in a query involving the joining of several lines of other tables (for example where the dates of beginning and end are derived from several employees?) or in several days. If you don't find it then count the number of whole days (taking weekends into account) between dates and work on the partial days after that it could be better. This would probably involve a lot of statements of case (which I don't have time to test it now).

  Ben