Buckets of the interaction between the physical i/o and buffer cache hach

I read the book Expert Oracle practices on issues of lock contention. While I was reading this chapter. I'm little bit confused the bahavior of the buffer cache when physical i/o occurs. According to Tom Kyte, when data blocks are read on disk (if missed cache) the following steps occurred. Ask Tom & amp; quot; How to work the Database Buffer Cache? & amp; quot;

(a) access to the buffer cache and search for block

(b) if the block isn't here, perform physical i/o and put it in the cache

(c) return the block of memory cache

However, I wonder what stage b has occurred which means put the data block in the buffer cache. For this, the data block is added to the associated buffer cache hash buckets?

As far as I know, in order to cache data hit intended address of applicable block in buffer cache hash bucket. The hash function is generated during this data block address. (if acquired the lock of the child) And then find the address of the data block in the cache buffer chain to locate the block of buffer in the buffer cache.

My second question is what stage an occur (go to the buffer cache and search block) how to block oracle look? I mean where did he look like? My third question relates to my second question, Oracle if discovered that the block in the buffer cache, does know where to find them? I guess that Oracle does not know where to locate it in the buffer cache. Therefore, it uses cache buffer hash buckets. I'm wrong?

Last question is, I'm just trying to understand how buffer cache buffers are linked, buffer cache buffer hash, how it works?

Thanks in advance.

> What happens if planned lines resident for other blocks of data in the table? How can you join the other data block addresses? And, how do you know that lines which are located in what block of data?

See this demo:

Microsoft Windows XP [Version 5.1.2600]

Copyright (C) 1985-2001 Microsoft Corp.

C:\Documents and Settings\Administrateur > sqlplus scott/tiger

SQL * more: Production release 11.2.0.1.0 Wed Dec 18 09:01:50 2013

Copyright (c) 1982, 2010, Oracle.  All rights reserved.

Connected to:

Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production

With partitioning, OLAP, Data Mining and Real Application Testing options

SQL > drop table test is serving;

Deleted table.

SQL > create table test in select * from object;

Table created.

SQL > set line 200.

SQL > column nom_segment for a20;

SQL > select nom_segment, segment_type, header_file, header_block dba_segments where nom_segment like 'TEST '.

NOM_SEGMENT SEGMENT_TYPE HEADER_FILE, HEADER_BLOCK

-------------------- ------------------ ----------- ------------

4 1218 TEST TABLE

Average for test table header block are 1218 that resides in file number 4.

SQL > SELECT

2 dbms_rowid.rowid_relative_fno (rowid) REL_FNO,

3 dbms_rowid.rowid_block_number (rowid) BLOCKNO

4 test where object_name = 'EMP ';

REL_FNO BLOCKNO

---------- ----------

4 2443

SQL > variable s/n varchar2 (30)

SQL > exec: s/n: = dbms_utility.make_data_block_address (4, 2443);

PL/SQL procedure successfully completed.

SQL > print s/n

S/N

--------------------------------

16779659

SQL > SELECT

2 dbms_rowid.rowid_relative_fno (rowid) REL_FNO,

3 dbms_rowid.rowid_block_number (rowid) BLOCKNO

4 test where object_name = 'I_AUDIT ';

REL_FNO BLOCKNO

---------- ----------

4 1223

SQL > exec: s/n: = dbms_utility.make_data_block_address (4, 1223);

PL/SQL procedure successfully completed.

SQL > print s/n

S/N

--------------------------------

16778439

SQL >

Then, I got two dBA for different lines that are in the block No. 2443 and 1223.

Concerning

Girish Sharma

Tags: Database

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