by comparing the records with another table

Similar Questions

• can I use: separation by a comma to compare the values with another table

  Hi ALL, I am using oracle 10g, can someone help me with this query
  

  WITH t AS
       (SELECT 20 ID, 'ABC,DEF,GHI' VALUE
          FROM DUAL),
       x AS
       (SELECT 20 ID, 'ABC' VALUE
          FROM DUAL
        UNION ALL
        SELECT 20, 'DEF'
          FROM DUAL
        UNION ALL
        SELECT 20, 'GHI'
          FROM DUAL)
  SELECT x.ID, x.VALUE
    FROM x, t
   WHERE x.VALUE IN (t.value);
  
  o/p required
  -------------------
  20  ABC
  20  DEF
  20 GHI

  I know I can't use t.valeur in TO would adopt. so I tried to use it in the paragraph, but it did not work.
  ''''|| Replace (T.valeur, ",", "", "') |" '
  
  Published by: DeepakDevarapalli on December 15, 2009 19:27

  Hello

  Here's a way to do it:

  SELECT      x.ID
  ,      x.VALUE
  FROM      x
  JOIN     t     ON      ',' || t.value || ','
            LIKE     '%,' || x.value || ',%'
  ;
  

  Extra commas are necessary to avoid the problem of 'mother is in chemotherapy,' when a single value can be one substring of another. If this is impossible (as in your case, where all values are exactly 3 characters) then you don't have them.

• When I subtract two numbers DBL and try to compare the result with another DBL, it fails

  I found a curious problem with subtraction and compare numbers DBL in LabVIEW (8.6). Here's how it works:

  1. subtract two numbers DBL such that the result is not incorporated. (Say, 3.2 - 3.1)

  2. compare the result with a constant/control that is on the result of the subtraction (in the example, 0.1)

  3 see the output of the comparison.

  If the result of the subtraction is an integer, the Boolean result is (as expected). If the result is not complete, the comparison fails.

  (Now, if I simply compare two floating point numbers, it works, so the issue is not with the node comparison itself, but with the data that is entered to the node). Can someone understand why this happens? It's unexpected, it's a pretty serious bug.

  It is provided with all programming languages. Numbers do not have an exact binary floating-point representation. This has been discussed endlessly. Never use the equal function with floats. You can use the function in the range and force.

• Update trigger that inserts the record in another table

  I searched the forum and the web for an example like this and I can not find a:
  
  A field is updated in the TABLE_A and it triggers a single record TABLE_B insert that has the old and the new value of the field.
  
  I write a lot of complex data warehouse SQL-based reports, but very rarely do much PL/SQL, any help would be appreciated.
  Thanks in advance.

  Hello

  You can specify that the trigger should fire only when certain columns are referenced, like this:

  create or replace trigger test_fund_trig
  before update OF FUNDING
  on table_a
  ...
  

  If you do this, the trigger will not draw on statements such as:

  UPDATE  table_a
  SET     mod_date = SYSDATE;
  

  You should always use an IF statement, as I mentioned earlier, if you do not want to follow the updates where the value of this column has not really changed.

• Compare the Collection with the help of the Table less

  Hey there!

  my plan is to transfer an excel file and record in an apex_collection, compare the results with those that already exist in a specific table and write it in another temporary table.

  Import excel, in the collection works perfectly, but I fight with the comparation. I select the form of entries collection and using UNMIS to compare lines with those of another SELECTION that gets the lines of the existing table.

  DECLARE

  BEGIN

  INSERT INTO UPLOADED_DID_LIST_COMP (BAC_CODE, UPSC)

  (

  SELECT BAC_CODE c001

  c002 published

  From apex_collections ca

  WHERE collection_name = "UPLOADED_EXCEL."

  LESS

  SELECT

  BAC_CODE

  EDITED

  OF UPLOADED_DID_LIST upld, apex_collections c WHERE

  collection_name = "UPLOADED_EXCEL."

  AND the upld. BAC_CODE = c.C001

  AND the upld. LʼUPSC = c.C002

  );

  End;

  This does not work because of this error:

  ORA-00933: SQL command not properly ended ORA-06550

  PLS-00103: encountered the symbol "end-of-file" when awaits one of the following numbers: (begin case declare exit end exception for goto rise back loop mod null pragma select update while < ID > < a quot double)

  If it's a copy/paste of your exact code then you just need to fix it, spaces here and there. And remove the superfluous where clause. Maybe:

  BEGIN

  INSERT

  IN UPLOADED_DID_LIST_COMP

  (

  BAC_CODE, SCHOOLING

  )

  (

  C001 SELECT BAC_CODE, EDITED C002

  FROM APEX_COLLECTIONS CA

  WHERE COLLECTION_NAME = "UPLOADED_EXCEL."

  LESS

  SELECT BAC_CODE, SCHOOLING

  OF UPLOADED_DID_LIST UPLD

  );

  END;

  Good luck.

• Compare the records from the same table

  Hi all

  I have this sample, the data were rendered are group by my_id, the same number of records exist for the two my_ids (2 and 62) as:

  create table myTest as
  (
  my_id number, 
  fieldA varchar2, 
  fieldB number, 
  fieldC number, 
  cost_A number, 
  cost_B number
  )
  
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (2, 'MAINT', 60, 5, 10.3, 15.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (2, 'MAINT', 70, 6, 20.3, 25.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (2, 'MAINT', 80, 7, 30.3, 35.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (62, 'MAINT', 60, 5, 10.3, 5.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (62, 'MAINT', 70, 6, 20.3, 25.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (62, 'MAINT', 80, 7, 10.3, 15.00);
  

  How can display the records with numbers of different costs for the same unique key (fieldA, fieldB and FieldC)?

  With the help of Oracle Database 11 g Enterprise Edition Release 11.2.0.4.0.

  I hope that my message is clear.

  Thank you!

  Hello

  user9542267 wrote:

  ... I need all the exits...

  Me too.  Always show the complete, accurate, results you want from the data provided.  If you want 2 rows at the exit point, don't tell you want 1.

  Here are the results you want?

  MY_ID FIELDA, FIELDB, FIELDC OLD_COST_A COST_A OLD_COST_B COST_B

  ------ ---------- ------ ------ ---------- ------ ---------- ------

  MAINT 62 60 5 10.3 10.3 15 5

  MAINT 62 80 7 30.3 10.3 35 15

  If so, here's a way to get them:

  WITH got_old_costs AS

  (

  SELECT fielda, fieldb, fieldc, cost_a, my_id, cost_b

  , LAG (cost_a) OVER (PARTITION BY fielda, fieldb, fieldc)

  ORDER BY my_id

  ) AS old_cost_a

  , LAG (cost_b) OVER (PARTITION BY fielda, fieldb, fieldc)

  ORDER BY my_id

  ) AS old_cost_b

  OF mytest

  WHERE my_id IN (2, 62)

  )

  SELECT my_id, fielda, fieldb, fieldc

  old_cost_a, cost_a

  old_cost_b, cost_b

  OF got_old_costs

  WHERE my_id = 62

  AND (cost_a <> old_cost_a)

  OR cost_b <> old_cost_b

  )

  ORDER BY fielda, fieldb, fieldc

  ;

• How can I do a summation of a table summarizing several points once, leaving me with another table?

  Hello, I tried to find a way to do the summation of a table, the sum of 19 points at a time, leaving me with another table.  I feel like this has a simple solution, but I'm not sure how.

  Thank you.

  A time loop that contains the subset of the table can do.

  Lynn

  

• By comparing the Date with timestamp without time portion

  Hello

  I have table lets say rates, it has a field called expire_date. Now, I need to display the records in this table which expires date is greater than today. Can someone tell me how to do?

  Currently, I do like this:

  Select * rate where expire_date > = (select SYSDATE from DOUBLE);

  This request is now selection of records whose timestamp is greater than the current date and time and other drops while the expire_Date is today with less time stamp.

  I need to show the records that are valid today and coming dates regardless of today

  Kind regards

  Ashish

  Select * rate where expire_date > = trunc (sysdate);

  Avoid the misuse of the double

  Kind regards

• Throw the records with null values columns

  Hi all.
  
  Anyone know how to dispose of records containing null column values?
  
  In the target table, I have the set Null option? with "N"... then the process sqlldr load some records. I need to load all of this without the records with null column values. by result, if the field X is null then load the file.
  
  Kind regards.
  
  Published by: ASzo on 05/06/2013 12:37
  
  Published by: ASzo on 05/06/2013 12:38
  
  Published by: ASzo on 05/06/2013 12:42

  load data
  INFILE...
  in the table...
  When x! = ''
  fields completed by...
  (x ...)

• Update of table column in this table corresponds with another table

  UPDATE of table column where this table corresponds to a column with another table of columns,
  Example:
  
  I need to update column in the table SIEBEL_ASSETS MATACH_FLAG = 'Yes' when less than the conditions of the
  Select a.*, SIEBEL_ASSETS a, gis_cad, c
  where upper (a.Province) = upper (c.province)
  and upper (a.TOWNSHIP_NAME_EXT) = upper (c.suburb)
  and a.Stand_ # = c.ERF_NO

  update siebel_assets a
  set    match_flag = 'yes'
  where  exists (select 1
                 from   gis_cad c
                 where  upper(a.Province) = upper(c.province)
                 and    upper(a.TOWNSHIP_NAME_EXT) = upper(c.suburb)
                 and    a.Stand_# = c.ERF_NO
                )
  ;
  

• You need to reset and or change my old icloud account of moms on the phone with another. When I try to reset it with the information that we know that it says "blocked account"

  You need to reset and or change my old iCloud account of moms on the phone with another. When I try to reset it with the information that we know that it says "blocked account"

  ACCOUNT SAFETY CONTACT NUMBERS

• When I use my brush tool, it works very well unless I overlap the brush with another brush stroke.

  When I use my brush tool, it works very well unless I overlap the brush with another brush stroke. When this happens, it turns bright red. How can I fix this and put it on the default setting?

  Your brush is set to Hard Mix in the options bar.  Change this to normal and everything will be fine.

• How to make a value in a temporary table, the match against another table...

  Hi all.
  
  Please is - can someone provide some guidance on how to...
  
  1. take a value from a temporary table, the match against another table that contains the first values 'equivalent' value.
  2. take this exchange value, call something (using the slider or the variable?) so I can add to my API to load it into ORACLE...
  
  Apology of this sounds confusing, I hope you know everything what I want to do...
  
  Manythanks...
  
  Steven

  and call the API

  declare
     v number;
  begin
     SELECT oracle_loc_code
        into v
     FROM SU_IEXP_LOCATIONS
        , SU_TEMPLOYEE_DETAILS
     WHERE chris_loc_code =location_id
     ;
     Hr_Assignment_Api.update_emp_asg_criteria (v);
  end;
  

• delete all the records in a table, the speed of insertion is not change.

  I have an empty table, and I insert a record need 100ms.
  During this table a 40,0000 trace, I insert a record need 1 s, it's ok, because I need to make a comparison according to an index before inserting a record need, so more record, more time.
  The problem is when I delete all the record in this table, the insertion time is always 1s, not reduce to 100ms. Why?

  Hello

  Read this part of the oracle documentation

  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14220/logical.htm#CNCPT004

  The reason is always 1s, because when you inserted 400ko record as HWM (high tide is the border between old and new space in a segment.) moved to the top. And when you remove all records of your HWM still in the same coordinate system and that you have not reset to 0. So when you insert 1 it save free space and after finding faces (usually a regular insertions got 6 steps it inserts data). If you truncate your table you and try it again it will be faster that your HWM is reset to 0.

  Concerning

• Insert the record of one table to another with the help of the cursor

  Help, please!
  
  the tables are - 1. countries (country_id pk, country_name, region_id)
  2A (country_id, country_name, region_id)
  table data are
  1 to 1
  2 b 2
  3 C 3
  NULL d 4
  5 e 5
  6 f 6
  7 g 7
  -----------------------
  Insert the record in the table a country table with the help of the cursor, insert all the non-null records.
  This procedure does not correct result
  -----------------------
  
  create or replace
  Amit procedure as
  cursor c1 is select * from a;
  RW a % rowtype;
  Start
  Open c1;
  Fetch c1 into rw.
  While (C1% found)
  loop
  insert into countries values (rw.country_id, rw.country_name, rw.region_id);
  commit;
  Fetch c1 into rw.
  If rw.country_id is null then
  Fetch c1 into rw.
  end if;
  end loop;
  Close c1;
  exception
  while others then
  dbms_output.put_line ('exception = name ' |) RW.country_name);
  end;

  You don't need cursor at all;

  create or replace procedure amit as
  
  begin
    insert into countries (Country_ID, Country_Name, Region_ID)
    (select a.Country_ID
           ,a.Country_Name
           ,a.Region_ID
     from a
    );
  
    dbms_output.put_line('Rows inserted : ' || sql%rowcount);
  
    commit;
  
  end;
  /