Compare the Collection with the help of the Table less

Similar Questions

• Compare the table structures in different schemas. help please

  Hi all
  
  I have a question...
  
  
  I have pictures on different schemas something like
  
  
  Diagram A
  -------------
  Table 1
  Table 2
  Table 3
  
  
  Diagram B
  ------------
  Table 1
  Table 2
  Table 3
  
  
  Now situation is table 1 and table 2 will have a similar structure or table 1 in Figure B will have additional columns.
  
  like so... on... for all other tables...
  
  example!
  

  Schema A:
  
  Desc Table 1;
  
  Name                                  Type            Null
  -------------                             -------             -------
  No                                Number            Notnull
  Name                           Varchar2(10)     Not null
  Fee                              Number (10,2)   Not null
  
  
  
  Scheam B;
  
  Desc Table1;
  
  Name                                  Type               Null
  -------------                             -------             -------
  DX_No                                Number            Notnull
  DX_Name                           Varchar2(10)      Not null
  DX_Fee                              Number (10,2)   Not null
  comments                          Varchar(2)        

  Now I need to write some sort of procedure for the thing to compare these tables which are in different in the column names in the schema and get it had exported to an Excel sheet.
  and here it's first three columns SHOULD BE CONSIDERED AS SAME even if the DX_ prefix are from the REST OF the PART OF THE COLUMN NAME IS SAME.
  
  and the same way commit coloumn new schema B only... So it should be noted that excel sheets...
  
  I don't know how the ADO or SQL Developer handle this... Is there any plsql block that I can write to do it...
  
  Thanks in advance...

  Comparison of columns on all the tables in the two schema

  select tc1.owner,tc1.TABLE_NAME,tc1.COLUMN_NAME,
         tc2.owner,tc2.TABLE_NAME,tc2.COLUMN_NAME
  from
    all_tab_columns tc1
    full outer
    join all_tab_columns tc2 on &user1=tc2.owner
                             and tc1.TABLE_NAME=tc2.TABLE_NAME
                             and tc1.COLUMN_NAME like '%'||tc2.COLUMN_NAME
  where
  tc1.owner=&user2
  and tc1.TABLE_NAME in (
                        select t1.table_name
                        from all_tables t1
                        join all_tables t2 on t2.owner=&user2 and t1.table_name=t2.table_name
                        where t1.owner=&user1)
  

  Published by: xtender on 06.11.2010 12:43

• Compare the table and out of the common elements

  Hello

  Can you help me to compare the two tables in the attached file in VI and out the elements common to the two tables?

  Thank you

  hiNi

  There is no wire table through the False State in the structure of your business.  Use the default value if unwired is selected for this tunnel. the default value for this tunnel is an array of empty strings.  Run the wire straight through, and Bob's your father's brother.

  

• Remove the entries in the table less resolution to

  For example, I have the following table:

  [1 k, 2 k, 3 k, 23 k, 24 k, 25 k, 26 k, 51 k, 52 k, 54 k, 56 k, k 76, 78 k]

  For example, the resolution is 10 k

  I want to process the table in a way so that it returns a table with the frequencies-more-than-resolution deleted while at the more-than-resolution-frequencies only maintain the highest and delete the rest.

  In the table above, I've separated the elements to indicate the Group of frequencies forming 'more-than-resolution-frequencies' example 1 k, 2 k, 3 k are more-than-resolution-frequencies

  The resulting table should look like.

  [3 k, 26 k, 78 k]

  In the example above, there are 3 groups of frequencies ilustration purposes, but it could be any number.

  Round table and removing duplicates close brings the result but this adds an error equal to the resolution.

  I hope this helps.

  

• convert the table less smaples per second

  Have great picture with 9 channels of data by time stamp.

  Timestamp shows that there are about 100 samples per second.

  I need to generate the table that displays only an average value per channel, per second.

  Faced with the 'picture of generation' and 'index' to get the picture right.

  Suggestions?

  markfranklin wrote:

  Faced with the 'picture of generation' and 'index' to get the picture right.

  Suggestions?

  I bag the building and indexing and discover the screw decimate in the range of Signal Processing.  Unless you're stuck with the basic version.

• Cannot compare a line with other lines in a table... (comparison of many to many)

  Hi all..
  I am very new to PL/SQL...
  I need through through a table to compare its lines with the table with the other lines. For that I'm trying to use Pl/sql below.
  -----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
  create or replace compare()
  Declare
  VAR_HIT CHAR (1);
  SEARCH_RECORD_DATA UDB.table1%ROWTYPE;
  CANDIDATE_RECORD_DATA UDB.table1%ROWTYPE;
  CURSOR SEARCH_RECORDS_CURSOR IS SELECT * FROM UDB.table1 by registration_id;
  CURSOR CANDIDATE_RECORDS_CURSOR IS SELECT * FROM UDB.table1 by registration_id;
  BEGIN
  FOR SEARCH_RECORD_DATA IN SEARCH_RECORDS_CURSOR LOOP
  FOR CANDIDATE_RECORD_DATA IN CANDIDATE_RECORDS_CURSOR LOOP
  IF (CANDIDATE_RECORD_DATA. THE DECISION = 'P') THEN
  VAR_HIT: = 'y ';
  IF (CANDIDATE_RECORD_DATA. First_name! = 'unknown') AND (CANDIDATE_RECORD_DATA. FIRST_NAME! = SEARCH_RECORD_DATA. FIRST_NAME) THEN
  VAR_HIT: = 'n';
  ELSIF (CANDIDATE_RECORD_DATA. Last_name! = 'unknown') AND (CANDIDATE_RECORD_DATA. LAST_NAME! = SEARCH_RECORD_DATA. LAST_NAME) THEN
  VAR_HIT: = 'n';
  ELSIF (CANDIDATE_RECORD_DATA. BIRTH_DATE! = 'unknown') AND (CANDIDATE_RECORD_DATA. BIRTH_DATE! = SEARCH_RECORD_DATA. BIRTH_DATE) THEN
  VAR_HIT: = 'n';
  ELSIF (CANDIDATE_RECORD_DATA. GENDER EQUALITY! = 'U') AND (CANDIDATE_RECORD_DATA. SEX! = SEARCH_RECORD_DATA. SEX) THEN
  VAR_HIT: = 'n';
  ELSIF (CANDIDATE_RECORD_DATA. FATHER_NAME! = 'unknown') AND (CANDIDATE_RECORD_DATA. FATHER_NAME! = SEARCH_RECORD_DATA. FATHER_NAME) THEN
  VAR_HIT: = 'n';
  ELSIF (CANDIDATE_RECORD_DATA. MOTHER_NAME! = 'unknown') AND (CANDIDATE_RECORD_DATA. MOTHER_NAME! = SEARCH_RECORD_DATA. MOTHER_NAME) THEN
  VAR_HIT: = 'n';
  END IF;
  IF(VAR_HIT='y') THEN
  INSERT IN THE UDB. VALUES OF (REGISTRATION_ID, SEARCH_ID, HIT_CANDIDATE_ID, SEARCH_DETAILS, CANDIDATE_DETAILS) BIO_DI_HIT_RESULT (SEARCH_RECORD_DATA. REGISTRATION_ID, SEARCH_RECORD_DATA. EGM_NO, CANDIDATE_RECORD_DATA. EGM_NO, VAR_SEARCH_DETAILS, VAR_CANDIDATE_DETAILS);
  UPDATE UDB. SET BIO_RECORDS_DEMOGRAPHICS = A DECISION ';
  END IF;
  END IF;
  END LOOP;
  commit;
  END LOOP;
  END;
  
  --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
  Outer loop works well (it is raversing throughout the table) is (say by 8000 saves 8,000 times)
  But Enner loop does not work fine e.i. it runs just for 8000 times for 8000 records. While it must run more time then 8000...
  Can someone help me...
  Is the way to use two cursor on a table to compare each line of the report is correct? :(

  >

  But even once come with a problem more in the part of sql, I shared. It does not cover part of my State... :(
  --> If the secondary search field are 'unknown' this field (please AVI single field not as search folder) will not be considered as search criteria.
  But in my current sql, all the side of any field research as "unknown" is not even taken to search for any candidate for other fields match.

  Try to change all the terms in this way (I show here only how to change a condition):

  Instead of:

  AND (SEARCH.BIRTH_DATE!='unknown' AND CANDIDATE.BIRTH_DATE IN (SEARCH.BIRTH_DATE,'unknown'))
  

  Use this one:

  AND (SEARCH.BIRTH_DATE = 'unknown' OR CANDIDATE.BIRTH_DATE IN (SEARCH.BIRTH_DATE,'unknown'))
  

  In the case of the search.birthdate condition will be 'unknown', it will be ignored, otherwise this condition will be used.

• Compare the table

  Hello:

  I need to compare two index table, to see the file please, and if there is no specific line or column changes then indicate any number of line and colunm

  How can I do in labview

  Thank you

  Brice

  I have created 2 examples in the attached VI.

  The loop at the top of the page search for any line that indicates the index of the first inconsistency and incompatibility.

  The loop at the bottom search all mismatched line/column, regardless of having previously found it an inconsistency in the same row.  It gives you a complete list.

  The example (s) should give you an idea of how to do to implement your solution.

• by comparing certain objects... helps with the formatting and variables

  I want to delete computer accounts in an ORGANIZATIONAL unit that do not exist in a folder of vmware...

  Step 1. Compare.

  $ad = Get-QADComputer -SearchRoot 'domain.lan/Test-NoGPO'
  $vmware= Get-VM -Location VDI_RemoteAccess
   
  Write-Host "AD" $ad
  Write-Host "VMWARE" $vmware
   
  Compare-Object  $ad $vmware
  
  

  Gives me this result:

  AD DOMAIN\DSTASA1$ DOMAIN\SXCH100$ DOMAIN\SKFB111$ DOMAIN\FAKEPC$
  VMWARE vstaq16 vstaq18
  
  InputObject                                                               SideIndicator                                                           
  -----------                                                               -------------                                                           
  vstaq16                                                                   =>                                                                      
  vstaq18                                                                   =>                                                                      
  DOMAIN\DSTASA1$                                                          <=                                                                      
  DOMAIN\SXCH100$                                                          <=                                                                      
  DOMAIN\SKFB111$                                                          <=                                                                      
  DOMAIN\FAKEPC$                                                           <=    
  
  

  I need the output of 2 first orders are the same... preferably just the 'name' of the pc. On the subject line - compare I tried to use $ad. Name and $vmware. Name but that the errors and says that it is null when the script runs...

  How to disinfect these lists and end up with a list of computers that are not in both places? (to later be deleted with other commands, not relevant here)

  You were there at halfway when you tried with the Name property.

  But you must keep all the computernames in 1 table and all VMnames in another table.

  Then, you can compare the 2 tables.

  Something like that

  $ad = Get-QADComputer -SearchRoot 'domain.lan/Test-NoGPO' | %{$_.Name}$vmware= Get-VM -Location VDI_RemoteAccess | %{$_.Name}
  
  Compare-Object $ad $vmware
  

• Help compare the negative and positive values

  Well guys, I do this example to show you what I mean

  

  With this example, I can get positive and negative numbers in digital

  But for me, the 'negative' mean nothing

  Example:

  If I have "100-200" for me the biggest value is - 200

  But if I compare the values of bouth got 100 as greater value

  I do the same calc for 3 different variables such as A, B, C

  and after that I need to calc whose value is 'more '.

  But my problem is that if I have the values "-350 300-400.

  the largest will be "300", but for me the 'negative' mean nothing

  so I need to the largest value is "-400".

  For all positive values, its works very well!

  I compare A and B, after the highest is on C and have a result!

  but when I have negative and positive values... I had this problem...

  and when I have negative values only I have a problem too.

  '-300-400-500' for me the largest value must be "-500" but labview-watch "300".

  as - 300 is greater than-500 in algebriac.

  And if I use absolute values, I will always have a positive value... but I need to know if the value is positive or negative

  No matter which, can help me with this?

  Thank you

  

  Ben

• I can't install cs6 master collection with serial number, the message is: Impossible to condone this number, but in our account page retrieve number series, everything is correct. Thank you

  I can't install cs6 master collection with serial number, the message is: Impossible to condone this number, but in our account page retrieve numbers series, everything is OK. Thank you

  Since this is an open forum, not Adobe support... you must contact Adobe personnel to help

  Chat/phone: Mon - Fri 05:00-19:00 (US Pacific Time)<=== note="" days="" and="">

  Don't forget to stay signed with your Adobe ID before accessing the link below

  Serial number and activation support (non - CC)

  http://helpx.Adobe.com/x-productkb/global/Service1.html

• How to compare a Date with the current year data and member of period on FIX

  Hi experts,
  
  I have a Sun project that each Member is a project (P01, P02,...)
  and account IMGs who stores the information of each project (name, Start date, finished...)
  Finished Date member is of data type Date
  
  So how can write an IF condition below in order to be able to compare the end Date of the project with the members of the current year and period on FIX
  DIFFICULTY (@Descendants (Projects), Descendants (year-round), Descendants ("year Total")...)
  IF (@CURRMBR (Period)-> @CURRMBR (Year) < Project > - FinishedDate)
  Do something...
  On the other
  Do something
  
  
  Please help me on this. Sorry for my bad grammar. Please ask if there is something not clear
  
  Thank you very much
  Van Huy.
  
  Published by: Van Huy on 29 January 2013 01:14
  
  Published by: Van Huy on 29 January 2013 02:24
  
  Published by: Van Huy on 29 January 2013 02:25
  
  Published by: Van Huy on 29 January 2013 18:04

  Here's what I did. Post for which may later cover

  VAR FM; / * End of month of the project.
  VAR EXERCISE; / * Year of the project terminated * /.
  VAR CM; / * Capture the current month on FIX declarations * /.
  VAR CY; / * Capture current year on FIX declarations * /.

  DIFFICULTY (@RELATIVE ('year', 0), @RELATIVE ('period', 0), @IDescendants ("core projects")...)

  FY = @ROUND ('TGHT'-> ' NA contract "-> 'FY06'-> ' NA period" / 10000, 0);
  FM = @MOD (@ROUND ('TGHT'-> ' NA contract "-> 'FY06'-> ' NA period" / 100, 0), 100);
  / * For FY13 back 13... */
  CY = @JgetDoubleFromString (@CONCATENATE ('20', @SUBSTRING (@NAME (@CURRMBRRANGE (year, Lev, 0, 0, 0)), 2)));
  / * Value CM set based on perceived period on the DIFFICULTY of statement * /.
  IF (@ISMBR ("Jan"))
  CM = 1;
  ELSE IF (@ISMBR ("February"))
  CM = 2;
  .....
  ELSE IF (@ISMBR ("Dec"))
  CM = 12;
  ENDIF

  IF (CY< fy="" or="" (="" cy="=" fy="" and="" cm=""><>
  Do something...
  ON THE OTHER
  Do something...
  ENDIF
  ENDFIX

  Published by: Van Huy on 19 February 2013 23:10

  Published by: Van Huy on February 20, 2013 19:46

• No need to advise - compare the date in *.sql with sysdate.

  Hi guys,.
  
  Need some help here.
  
  Someone has a script that will compare the date specified with the current sysdate. If previously, he will order that SQL * PLUS to leave immediately.
  The audit will be essentially in a script *.Sql. Whenever we run the script, @c:\script.sql, it will be first of all to compare the dates and decide whether to proceed with the rest of the codes (dml) below the date checker in the same script.sql
  
  Thank you

  I would like to combine the solutions of bencol and alberto:

  whenever sqlerror exit
  
  DECLARE
     v_date   DATE := TO_DATE('', 'YYYYMMDD');
  BEGIN
     IF v_date >= TRUNC(SYSDATE) -- or perhaps:  v_date>= sysdate
     THEN
       null;
     ELSE
       raise_application_error(-20000,'Date is before SYSDATE!');
     END IF;
  END;
  /
  
  whenever sqlerror continue
  
  -- rest of your script
  ...
  

  (not tested)

  Published by: hm on 08.05.2012 02:51

• by comparing the records with another table

  Hello
  I have the following 2 tables (test_prs & test_dep) and registers
  My goal is to compare test_prs with test_dep records and return the records that are not in test_dep
  
  Here is the table scripts

  create table test_prs (id ,p_id ,r_id)
  as
  select 1,200566,200566 from dual
   union all
  select 2,200567,200567
  from dual
  
  create table test_dep (id,de_typ,de_id,de_u_typ,de_u_id)
  as
  select 10,'AS',200566,'PG',200566
  FROM DUAL
  UNION ALL
  select 11,'AS',200567,'PG',200567
  FROM DUAL
  
  
  insert into test_dep 
  select 12,'AS',400189,'PG',400273 FROM dual union all
  select 13,'AS',400273,'PG',400250 FROM dual union all
  select 14,'AS',400273,'PG',400192 FROM dual union all
  select 15,'AS',400273,'PG',400191 FROM dual
  
  insert into test_prs
  select 3,400273,400273 from dual

  I tried the following query to meet my criteria. My output should be null, but all records

  select * from 
  test_prs  prs
  where  exists (select 1 from test_dep de where de.de_id !=prs.p_id and de.de_u_id !=prs.p_id )

  Could you please help me the same
  
  Published by: smile on 7 March 2012 15:00

  Smile says:
  Thanks for the request

  The query does not work with the following documents

  insert into test_dep
  select 16,'AS',750664,'PG',750758 FROM dual 
  
  insert into test_prs
  select 4,750758,750668 from dual
  

  the r_id should not be put in correspondence with the columns in the test_dep table. P_id must only be put in correspondence

  OK, you want to match against the de_id and the de_u_id p_id? Or a line where either p_id concordances r_id de_u_id or de_id must not be returned?

  To match p_id against de_id and de_u_id, you can write the query like this:

  select id, p_id, r_id from test_prs where
  p_id in
  (select p_id from test_prs
  minus
  select de_id from test_dep
  minus
  select de_u_id from test_dep);
  

  Brgds
  Johan

• Compare the result of a query with a number and return a message

  Hello
  I have the following query in oracle 9i:
  
  SELECT COUNT (*)
  OF hourly_files
  WHERE date_received = TO_DATE ((SELECT TO_CHAR (SYSDATE - INTERVAL '1' DAY, 'DDMMYYYY')
  (THE DOUBLE), 'DDMMYYYY');
  
  This will produce a number of lines required
  
  I need to compare the number of output with another number hardcoded (threshold) and print an appropriate example message
  
  If the result of the query above is 18000 and the number of threshold is fixed at 20000, then output a meesage:
  
  Number of files received less than 2000
  
  Any help will be very appreciated!
  
  Thank you.

  SQL> ed
  Wrote file afiedt.buf
  
    1  SELECT CASE WHEN COUNT(*) >5 THEN 'Number is > than 5'
    2              WHEN COUNT(*) <1 THEN 'Its less than 1'
    3  ELSE 'Its in between'
    4  END
    5  FROM emp
    6* WHERE deptno=20
  SQL> /
  
  CASEWHENCOUNT(*)>5
  ------------------
  Its in between
  
  SQL> SELECT COUNT(*) FROM emp
    2  WHERE deptno=10;
  
    COUNT(*)
  ----------
           3
  

• CVI suggested help update on 'programming with the Table controls.

  Hello

  May I suggest adding a sentence to the chapter 'Programming with the Table controls', 'Creation and deletion of cells' section help of CVI.

  After the sentence "use the following functions to control the number of rows in a table control...". "I would like to add a suspicion that the number of lines is also affected by (programmatically) adjustment of the height of the table.

  Now that I've discovered, it's obvious ;-)

  Hi Wolfgang,.

  I think you might be misunderstanding this sentence in aid. It does not refer to the size of the table, in regard to the number of lines go in the table. It is in fact the number of real lines exist in the table. And the total number of rows in the table is absolutely not affected by the height of the table.

  Luis