By default, all nodes expanded in table tree jsff page in adf

Similar Questions

• expand all the nodes in an af:tree component

  Hello
  
  We use the ADF 11 g. In a one of our pages, we use an af:tree control and we want to show all nodes developed by default. How to get there? "Expand all" in the menu contextual works only for the current node.
  
  Thank you.
  
  Published by: Deniz Gulmez on 16.Ara.2009 06:27

  Hi Deniz,

  Have you tried setting the property initiallyExpanded to true for the tree?

  Something like

  Arun-

  Edit: Also, take a look at Frank blog

• Table tree ADF elements at all levels in nodeStamp facet

  Fusion Middleware Version: 11.1.1.5

  WebLogic: 10.3.5.0

  JDeveloper Build: Build JDEVADF_11.1.1.5.0_GENERIC_110409.0025.6013

  Project: Custom Portal Application WebCenter integrated with ADF custom workflows.

  Hello

  
  I have a problem with ADF Tree Table (af:treeTable) that if I add an item to a group under the facet "nodeStamp" he repeats for all levels in the tree even those outside the group.

  Overview:

  -3-master level / retail structure created using ADF business components (display objects 3 connected by 2 show links)

  -ADF Tree Table based on the master-detail

  -Requirement to indicate 3 levels of data in the first column tree

  -Table tree renders correctly showing the values for "node. FullName ',' node. DisplayValue' and ' node. HoursType' respectively in a tree of level 3.

  -When another element is added to the top node in the tree ("node. FullName') for example, some output text ('node. TimeBuildingBlockId'), it is displayed along components side ' node. DisplayValue' and ' node. HoursType' as well.

  Code snippet:

  < af:treeTable value = "#{bindings." Var PerPeopleFVO1.treeModel}' = 'node '.

  selectionListener = "#{bindings." PerPeopleFVO1.treeModel.makeCurrent}.

  rowSelection = "single" id = "tt1" styleClass = "AFStretchWidth."

  horizontalGridVisible = "true" verticalGridVisible = "true".

  disableColumnReordering = 'true' summary =' entered in the time sheet.

  displayRow = "selected" expandAllEnabled = "false".

  contentDelivery = 'immediate' autoHeightRows = '24 '.

  columnStretching = "column: column1 '.

  Binding = "#{pageFlowScope.TimecardMB.tree_binding}" >

  < f: facet name = "nodeStamp" >

  < af:column id = "c1" headerText = "Partner details" width = "500" >

  < af:group id = "g4" >

  < af:outputText value = "#{node." FullName}"id ="ot3"/ >

  < af:outputText value = "#{node." TimeBuildingBlockId}"id ="ot1"/ >

  < / af:group >

  < af:outputText value = "#{node." DisplayValue}"id ="ot4 ".

  inlineStyle = "color: Green;" make-weight: bolder; "/ >

  < af:outputText value = "#{node." HoursType}"id ="ot5"/ >

  < f: facet = 'filter' name / >

  < / af:column >

  < / f: facet >

  < f: facet name = "pathStamp" >

  < af:outputText value = "#{node}" id = "ot2" / >

  < / f: facet >

  < af:column FROM HERE... >

  Any ideas greatly appreciated.

  Hello

  Try to use a blender to distinguish three levels of the tree. You can have three different facets, three different af:group's.

  When you add at one level, it will not repeat in the other classes.

  Please see the excerpt below.

  selectionListener = "#{bindings." RefBusinessUnitView1.treeModel.makeCurrent}.

  rowSelection = "single" id = "t1" >

  facetName ="#{node.hierTypeBinding.viewDefName}">

  Alisson

• Expand the whole tree of the af:tree component nodes programmatically

  Hello dear,
  Could you please help me by posting a tree with all nodes to disclose. Forum ADFCodeCorner (http://www.oracle.com/technetwork/developer-tools/adf/learnmore/21-expand-tree-on-initial-render-169158.pdf) shared a code that does not disclose the first level nodes. I made a few changes to disclose all nodes, but it was decided to disclose only the first-level nodes.
  
  public class treeNodeExpander
  {
  
  RKS RowKeySet;
  public treeNodeExpander()
  {
  }
  The listener to phase itself is referenced in a bean managed property of method 'beforePhase' of the f: view component.
  < f: view beforePhase = "#{treeSampleBacking.beforeRenderOnViewLoad}" >... < / f: view >
  
  public void beforeRenderOnViewLoad (PhaseEvent phaseEvent)
  {
  Try
  {
  
  If (phaseEvent.getPhaseId () is PhaseId.RENDER_RESPONSE)
  {
  
  FacesContext fctx = FacesContext.getCurrentInstance ();
  AdfFacesContext adfFacesContext = AdfFacesContext.getCurrentInstance ();
  Make sure that this code is run on the original page only request
  Boolean isInitialRequest =! adfFacesContext.isPartialRequest (fctx);
  If (isInitialRequest)
  {
  
  UIViewRoot viewRoot = fctx.getViewRoot ();
  Tree of UIComponent = viewRoot.findComponent ("t2");
  If (tree! = null)
  {
  Model CollectionModel (CollectionModel) = ((RichTree) tree) .getValue ();
  JUCtrlHierBinding treeBinding = (JUCtrlHierBinding) model.getWrappedData ();
  JUCtrlHierNodeBinding RootNode = treeBinding.getRootNodeBinding ();
  RKS = (((RichTree) tree) .getDisclosedRowKeys ());
  getAllTreeNodes (rootNode);
  Collections.sort ();
  ((RichTree) tree) .setDisclosedRowKeys (rks);
  
  }
  }
  }
  }
  catch (Exception ex)
  {
  System.out.println ("Exception" + ex.getMessage ());
  }
  Add the code in the event here...
  }
  
  
  Recursive function that get all the child node of the node root
  
  public void getAllTreeNodes (JUCtrlHierNodeBinding rootNode)
  {
  
  If (rootNode.getChildren () is nothing)
  {
  System.out.println ("root node has no Childs");
  }
  on the other
  {
  NodeList list < JUCtrlHierNodeBinding > = rootNode.getChildren ();
  If (rks is nothing)
  {
  RKS = new RowKeySetImpl();
  }
  for (node JUCtrlHierNodeBinding: nodeList)
  {
  node.getChildren ();
  L ArrayList = new ArrayList();
  l.Add (node.getRowKey ());
  System.out.println ("Roe key is" + node.getRowKey () m:System.NET.SocketAddress.ToString ());
  RKS. Add (l);
  getAllTreeNodes (node);
  }
  System.out.println ("this is the Else Condition");
  }
  
  }
  
  }

  Zeeshan please follow this link http://biemond.blogspot.com/2009/11/find-and-expand-all-nodes-of-adf-tree.html

• Table tree icons has not erased even after the application of CSS

  Hello
  
  I need to change the table tree developed and reduced and the head node icon.
  
  Leaf node icon happens correctly, but the other two are misapplied.
  
  In the background the old default image becomes redered and in addition to this the newly given image is displayed.
  
  Here are the .css declarations used to change icons.
  
  AF|treeTable::expanded-icon{content:URL(/org/CalWIN/UI/superweb/image/yellowBlueMarker-minus_trans.gif);
  background: no ;}
  AF|treeTable::collapsed-icon{content:URL(/org/CalWIN/UI/superweb/image/yellowBlueMarker_trans_plus.gif);
  {Background: none}
  AF|treeTable::leaf-icon{content:URL(/org/CalWIN/UI/superweb/image/blueCircleMarker_trans.gif);
  {Background: none}
  
  Can anyone suggest a solution for this.
  
  Thank you
  Praveen.

  Hello

  If you extend an existing skin, try - tr - inhibit: all;

  AF | treeTable: {expanded icon

  -tr - inhibit: all;
  Content:URL(/org/CalWIN/UI/superweb/image/yellowBlueMarker-minus_trans.gif);
  Background: none;
  }

  in case there is a problem with the legacy

  Frank

• How to get to a particular node in a hierarchical tree?

  I want to do this simple thing with a hierarchical tree of forms.
  
  Given that the tree has many levels and branches I want to give a search box.
  
  The user types the label and press a button. The form must then ask the tree node and expand ONLY the path where is the node (if found) and highlight. If a node with a label is NOT found, I give an error message to the user.
  
  I put hands on a code segment to explode a tree and changed it, but it does not work. The entire tree is expanded and you don't know where you are.
  
  Any help will be greatly appreciated?
  
  PROCEDURE Expand_All_Nodes_in_Tree IS
  node ftree.node;
  htree;
  VARCHAR2 (30) of the State;
  
  BEGIN
  -Search the ID of the tree-
  htree: = Find_Item ('menu.tree');
  
  -Search the root-
  node: = Ftree.Find_Tree_Node(htree, '');
  
  -Expand all nodes-
  While WHAT NOT of LOOP of Ftree.ID_NULL (node)
  
  State: = Ftree.Get_Tree_Node_Property (htree, node, Ftree.NODE_STATE);
  State of IF = Ftree.COLLAPSED_NODE THEN
  Ftree.Set_Tree_Node_Property (htree, node, Ftree.NODE_STATE, Ftree.EXPANDED_NODE);
  END IF;
  
  node: = Ftree.Find_Tree_Node (htree, ", ftree.find_NEXT, Ftree.NODE_LABEL, cm, node);
  
  IF Ftree.Get_Tree_Node_Property (htree, node, Ftree.NODE_LABEL) =: ctrl.node_lable_to_search THEN
  EXIT;
  END IF;
  END LOOP;
  
  
  END;

  Try this line

  DECLARE
  htree;
  BEGIN
  htree: = Find_Item ('menu.tree');
  Ftree.Set_Tree_selection (htree, 1, Ftree.SELECT_ON);
  END;

  -Clément

• Extract all nodes and filter them based on the WHERE clause

  <?xml version="1.0" encoding="UTF-8"?>
  <report_repository_summary>
     <sql sql_id="gyn915ynqjspa" sql_exec_start="08/19/2015 22:23:02" sql_exec_id="16777217">
        <status>DONE</status>
        <sql_text>BEGIN DBMS_STATS.GATHER_FIXED_OBJECTS_STATS; END;</sql_text>
        <first_refresh_time>08/19/2015 22:23:10</first_refresh_time>
        <last_refresh_time>08/19/2015 22:24:52</last_refresh_time>
        <refresh_count>54</refresh_count>
        <inst_id>1</inst_id>
        <session_id>26</session_id>
        <session_serial>20363</session_serial>
        <user_id>0</user_id>
        <user>SYS</user>
        <con_id>3</con_id>
        <con_name>PDB01_1</con_name>
        <module>sqlplus@lab (TNS V1-V3)</module>
        <service>1_1.up.com</service>
        <program>sqlplus@lab (TNS V1-V3)</program>
        <plan_hash>0</plan_hash>
        <is_cross_instance>N</is_cross_instance>
        <stats type="monitor">
           <stat name="duration">110</stat>
           <stat name="elapsed_time">109822091</stat>
           <stat name="cpu_time">78295097</stat>
           <stat name="user_io_wait_time">1388002</stat>
           <stat name="application_wait_time">1228</stat>
           <stat name="concurrency_wait_time">9175702</stat>
           <stat name="cluster_wait_time">41691</stat>
           <stat name="plsql_exec_time">39369731</stat>
           <stat name="other_wait_time">20920371</stat>
           <stat name="buffer_gets">616087</stat>
           <stat name="read_reqs">837</stat>
           <stat name="read_bytes">22998016</stat>
        </stats>
     </sql>
  </report_repository_summary>
  
  
  

  With above document XML stored as varchar2 (4000) in 12.1.0.2.0, how can I retrieve and display the relevant information(sql_id,session_id,plan_hash,duration,read_bytes) based on the place where condition to filter on any node. For example.

  select * from (
  SELECT EXTRACT (xmltype.createxml (a.report_summary), '//stats/stat[2]/text()').getstringval () AS elap_time from dba_hist_reports a WHERE component_name = 'sqlmonitor'
  )
  where elap_time > 100000000
  /
  
  
  

  Here, I try to get sql_id, sql_exec_id, duration and other information stored in the xml document by applying the where on elapsed_time condition. But to do this, I must write the part EXTRACT for all nodes in the inline view which seems like very bad way of writing of XML query. Is there an easy way to get all the information of nodes so that I can freely apply node whatever, I want in the WHERE condition to filter the records? No better way to write the code then the code below?

  select     REPORT_ID,
             EXTRACT (xmltype(a.report_summary), '//sql/@sql_id')                                    "sql_id",
             EXTRACT (xmltype(a.report_summary), '//sql/@sql_exec_id')                               "sql_exec_id",
             EXTRACT (xmltype(a.report_summary), '//sql/@sql_id')                                    "sql_exec_start",
             EXTRACT (xmltype(a.report_summary), '//status/text()')                                  "status",
             EXTRACT (xmltype(a.report_summary), '//sql_text/text()')                                "sql_text",
             EXTRACT (xmltype(a.report_summary), '//first_refresh_time/text()')              "first_refresh_time",
             EXTRACT (xmltype(a.report_summary), '//last_refresh_time/text()')               "last_refresh_time",
             EXTRACT (xmltype(a.report_summary), '//refresh_count/text()')                   "refresh_count",
             EXTRACT (xmltype(a.report_summary), '//inst_id/text()')                                         "inst_id",
             EXTRACT (xmltype(a.report_summary), '//session_id/text()')                              "session_id",
             EXTRACT (xmltype(a.report_summary), '//session_serial/text()')                  "session_serial",
             EXTRACT (xmltype(a.report_summary), '//user_id/text()')                                         "user_id",
             EXTRACT (xmltype(a.report_summary), '//user/text()')                                    "user",
             EXTRACT (xmltype(a.report_summary), '//con_id/text()')                                  "con_id",
             EXTRACT (xmltype(a.report_summary), '//con_name/text()')                                "con_name",
             EXTRACT (xmltype(a.report_summary), '//module/text()')                                  "module",
             EXTRACT (xmltype(a.report_summary), '//service/text()')                                         "service",
             EXTRACT (xmltype(a.report_summary), '//program/text()')                                         "program",
             EXTRACT (xmltype(a.report_summary), '//plan_hash/text()')                               "plan_hash",
             EXTRACT (xmltype(a.report_summary), '//is_cross_instance/text()')               "is_cross_instance",
             EXTRACT (xmltype(a.report_summary), '//stat[1]/text()')                                 "duration",
             EXTRACT (xmltype(a.report_summary), '//stat[2]/text()')                                 "elapsed_time",
             EXTRACT (xmltype(a.report_summary), '//stat[3]/text()')                                 "cpu_time",
             EXTRACT (xmltype(a.report_summary), '//stat[4]/text()')                                 "user_io_wait_time",
             EXTRACT (xmltype(a.report_summary), '//stat[5]/text()')                                 "application_wait_time",
             EXTRACT (xmltype(a.report_summary), '//stat[6]/text()')                                 "concurrency_wait_time",
             EXTRACT (xmltype(a.report_summary), '//stat[7]/text()')                                 "cluster_wait_time",
             EXTRACT (xmltype(a.report_summary), '//stat[8]/text()')                                 "plsql_exec_time",
             EXTRACT (xmltype(a.report_summary), '//stat[9]/text()')                                 "other_wait_time",
             EXTRACT (xmltype(a.report_summary), '//stat[10]/text()')                                        "buffer_gets",
             EXTRACT (xmltype(a.report_summary), '//stat[11]/text()')                                        "read_reqs",
             EXTRACT (xmltype(a.report_summary), '//stat[12]/text()')                                        "read_bytes"
  from       DBA_HIST_REPORTS a
  

  Don't know why, but it pays just 1 or 0. Even in your case his statement just 0 or 1 for all X 2 columns table.

  I guess I do something wrong in declaring XPATH for X 2 table but not able to find what it is.

  It makes account 0 or 1 because path expressions are bad.

  "For example: ' @name ="duration"

  This is a Boolean expression, not a step of XPath and so gets evaluated as such, which gives 0/1 for false/true values.

  What you need, it is something like this:

  SELECT x1.*
  FROM dba_hist_reports t
     , xmltable('/report_repository_summary/sql'
         PASSING xmlparse(document t.report_summary)
         COLUMNS
           sql_id              varchar2(15) path '@sql_id'
         , sql_exec_start      varchar2(30) path '@sql_exec_start'
         , sql_exec_id         number       path '@sql_exec_id'
         , status              varchar2(10) path 'status'
         , stats_duration      number       path 'stats/stat[@name="duration"]'
         , stats_elapsed_time  number       path 'stats/stat[@name="elapsed_time"]'
         , stats_cpu_time      number       path 'stats/stat[@name="cpu_time"]'
       ) x1
  where sql_id = 'c1tb2666n5rfx'
  and sql_exec_id = 16777668
  

• Table tree select questions

  Hi all

  I use Jdeveloper 12.1.2.0.0.

  My requirement is to select the checkbox all rows in a table from the tree root level when the user clicks a checkbox control named selectAll (this box resides outside the TreeTable). If the user disables the selectAll checkbox all rootLevel in tree lines must be unchecked.

  The tree has two levels. I used a transitional mode attribute in the t and when the user clicks the selectall checkbox, ValueChange Listener fires and I'm looping through the lines of the iterator, setting the transient value to be true.

  It works fine all the time but not the first time. When I click on the for the first time selectAll checkbox, the ValueChange listener fires but the treeTable lines are not get verified. The second time, it works perfectly.

  I have a partial trigger to the TreeTable.

  If I use a button instead of a check, it works fine all the time.

  Could someone help me.

  Do not know what causes this. Have you tried in jdev 12.1.3?

  To work around the problem, you can but a button hidden on the page and the queue an event to actin the listener to change value of the check box for the button. So easy the key dies at work, and it should work.

  Timo

• How to set programmatically the current node in a tree view of the ADF.

  Hello
  

  I'm trying to understand how to set programmatically the current node in a tree view of the ADF.

  My use case example is quite simple; If we take the sample application ADF Summit where under Management Summit, we have a tree view on the left with a list of high level of the country which in turn contain a subset of customers; then, in the right pane, we the customer detail information.

  What I'm trying to achieve is a solution by which I can add a new customer, commit and then to the tree show the client newly created as the currently selected entry.

  I use a pop-up dialog box to create my new entry of the customer and everything works well in this area, and my newly created folder is saved in the database.

  I know how to force the tree to cool off, but what I can't understand is how to do so, it highlights the newly created folder.

  Any help would be much appreciated.

  Refer

  https://blogs.Oracle.com/jdevotnharvest/entry/how_to_programmatically_disclose_a

  http://www.Oracle.com/technetwork/developer-tools/ADF/learnmore/78-man-expanding-trees-treetables-354775.PDF

• By default the command of a table / inserted record seems to be at the forefront

  I'm ready to be confused with the result of the insert function and order 'default' a table while I practice with the employee, EMP table

  After inserting a new row in the EMP table, I tried to show the result with SELECT * FROM EMP and found that the last record inserted appeared on the first line of the table.

  SQL > INSERT INTO EMP (EMPNO, ENAME, JOB) VALUES ('& EMPNO ',' & ENAME', ' & JOB ");

  Enter the value for empno: 1234

  Enter the value of ename: JIMMY

  Enter the value of job: MANAGER

  old 1: INSERT INTO EMP (EMPNO, ENAME, JOB) VALUES ('& EMPNO ',' & ENAME', ' & JOB ")

  new 1: INSERT INTO EMP (EMPNO, ENAME, JOB) VALUES ("1234", "JIMMY", "MANAGER")

  SQL > SELECT * FROM EMP;

  EMPNO, ENAME, JOB HIREDATE DEPTNO COMM SAL MGR

  ---------- -------------------- ------------------ ---------- ---------- ---------- ---------- ----------

  1234 JIMMY MANAGER

  7369 SMITH CLERK 7902 17/12/1980 800 20

  7499 ALLEN SALESMAN 7698 20/02/1981 1600 300 30

  7521 WARD SALESMAN 7698 22/02/1981 1250 500 30

  7566 JONES MANAGER 02/04/1981 7839, 2975 20

  7654 MARTIN SALESMAN 7698 28/09/1981 1250 1400 30

  7698 BLAKE MANAGER 01/05/1981 7839, 2850 30

  7782 CLARK MANAGER 7839 09/06/1981 2450 10

  7788, SCOTT, ANALYST, 7566 04/19/1987 3000 20

  PRESIDENT OF KING 7839 17/11/1981 5000 10

  7844 TURNER SALESMAN 7698 08/09/1981 1500 0 30

  7876 ADAMS CLERK 7788 OF 23/05/1987, 1100 20

  7900 JAMES CLERK 7698 03/12/1981 950 30

  7902 FORD ANALYST 7566 03/12/1981 3000 20

  7934 MILLER CLERK 1300 7782 10 23/01/1982

  15 selected lines.

  Should not go to the bottom of the table since it was introduced last?

  I noticed that it was posted in the first place, because I gave the employee number is the smallest; also the empno. is the first column of the table, that it has something to do with the order?

  I does not have an ORDER BY clause when I typed in the statements.

  Is the table always controlled by the first column, by "default"?

  Also: command - line by default, you place your order for a query select in oracle - Stack Overflow

  What I found from this link: «...» "For obvious reasons, if you create a new table, inserting some rows and do a" select * "without the"where"clause, it returns the rows in the order they have been inserted." "

  This is my first post here, the result is displayed in the console can be a bit messy... as if the question is too easy or something, my apologies, I started to learn.

  Thank you!

  Hello

  As Solomon said, there is no default order for the rows of a table.

  If

  -the lines have been inserted in order by empno, and

  -the table is very small, and

  -lines don't have never updated or deleted, and

  -you select all rows in the table, and

  -you do not use the analytical functions, and

  -you do not use CONNECT BY, GROUP BY, or certain other clauses

  then exit may still be in order by empno, depending on your version and platform, but you can't count on it.  Oracle emphatically does not order for the lines as they are stored in a table, or the way in which they appear in the output when you do not use an ORDER BY clause.

• Problem with table tree ADF

  Hello

  I have following scenario.

  I have two read only vo (expert mode, not based on the entity) with a link between them. I want to display the data in a tree with checkboxes to parent nodes and child table. When the user selects a check box to the corresponding parent node with child nodes checkboxes should be auto selected.for achieve this I created transient Boolean attributes on two VO on the user interface layer, I use the Valuechangelistner to get the records of the child and the update of the transitional attribute.but, the problem is that the selection does not occur on the UI for the child node check boxes.

  Here is the code for updating the transient attributes.

  	{} public void deptSelected (ValueChangeEvent valueChangeEvent)
  	Add the code in the event here...
  	DCBindingContainer bc = (DCBindingContainer) BindingContext.getCurrent () .getCurrentBindingsEntry ();
  	Iterator DCIteratorBinding = bc.findIteratorBinding ("DepartmentVOIterator");
  	Region of DepartmentVORowImpl (DepartmentVORowImpl) = iterator.getCurrentRow ();
  	RowIterator ri = region.getEmployeesVO ();
  	String ID = null;
  	{if (valueChangeEvent.getOldValue ()! = null)}
  	Check Boolean = (Boolean) valueChangeEvent.getNewValue ();
  	if(Check==true) {}
  	region.setisDeptSelected (true);
  	}
  	Else if (check == false) {}
  	region.setisDeptSelected (false);
  	}
  	{while (RI.hasNext ())}
  	EmployeesVORowImpl empRow = ri.next ((EmployeesVORowImpl));
  	if(Check ==true) {}
  	empRow.setAttribute ("isEmployeeSelected", true);
  	}
  	Else if (check == false) {}
  	empRow.setAttribute ("isEmployeeSelected", false);
  	}			}

  }
  	}

  whenever the parent is checked valueChangeListner to fires and but the changes don't get triggered on the user interface. I suspect that some how the viewlinkaccesor is getting executed and transitional attribute values are lost.

  Guidance on the question?

  Thank you

  Sam.

  Sam, your question a bit sounds like something that I did in my last project.  I have a treeTable with two columns with components selectBooleanCheckbox.  Mine has the boxes with render = "false" for the parent nodes, but I see no reason why you couldn't do what you want with the parent nodes.

  The key is in the bean support - the value attribute of the boxes should be a map, so you can have individual values for each node.  So, I have:

  Map reqServices = new HashMap();
      public void setReqServices(Map reqServices) {
           this.reqServices = reqServices;
       }
       public Map getReqServices() {
           return reqServices;
       }
  

  And on the page, the elements are similar:

  Note this node. ConduitePlan is the index of the card, so when you process the card value is true if the checkbox for that conduitePlan has been verified or does not exist in the map or is set to false if the box is unchecked.  It is added to the card when the user first checks the box, it changes to false if the previously checked box is unchecked.  You will probably use a ValueChangeListener to check the child nodes when a parent node is activated.

• all rows in the table are not eligible for the specified partition

  SQL > Alter Table ABC
  Exchange 2 Partition P1 with Table XYZ;
  
  Modified table.
  
  SQL > Alter Table ABC
  Exchange 2 Partition P2 with Table XYZ;
  
  
  P2 Partition Exchange with XYZ Table
  *
  ERROR on line 2:
  ORA-14099: all rows in the table are not eligible for the specified partition
  
  The exchange partition works fine for the first time. However, if we try to swap the 2nd partition it gives the error.
  How to solve this error?
  How can I find the lines which are not qualified for a specific part. is there a query to find out the same thing?

  >
  Well, exchange of syntax and logic is not clearly as it should (IMHO). There is no element of syntax that tells Oracle we want to Exchange partition data in a table that is not partitioned or not partitioned into partition table data.
  >
  What? Not sure where you got that but maybe it was before you had first cup of coffee? ;)

  An "Exchange", it's just that; an Exchange. Partition data end up in the non-partitioned table and vice versa. It is meaningless and totally obsolete if "we want Exchange partition data in a table that is not partitioned or not partitioned into partition table data".
  >
  It was decided by Oracle not partitioned table control. If the non-partitioned table is empty, it means you want to Exchange data partition in a non-partitioned table. And if not partitioned table is not empty, it means you want to Exchange data in the table that is not partitioned into partition.
  >
  There is no decision to make. The segments are swapped. Oracle doesn't check, know or even care if one or the other or both segments are empty. 'Control' which is carried out (by default except if NO CONTROL is used) only consists of ensuring all the data in the segment intended for the partition belongs to this partition.

  It is what gives the example of John. This can NEVER work if table1 is empty unless p1 is empty at the beginning:
  1 Exchange p1 with table1
  2 Exchange p2 with table1

  As John explains, assuming that no other operations are trying to put the data from p1 P2 which is not possible if p1 actually contains data.

  You can save it for next April 1!

• How to make a node of a hierarchical tree in BOLD

  When we click on the node of a hierarchical tree, we want to make the "BOLD" node. We tried to use the item set property but it does not work.

  It is not really a built-ins that will allow you to change the font of the tree node label. You might be able to do this with Java, but you must write your own Java Bean to implement. It might be easier to simply add an asterisk (*) to the label programmatically by using the Set-Tree-Node - Property () built-in, but there are problems with the removal of the asterisk when you exit the selected node or select a new node. It can be solved, but you'll have to save all of the information you will need to reset the node - just namly the Node_ID.

  Hope this helps,
  Craig B-)

  If someone useful or appropriate, please mark accordingly.

  Published by: Silvere on February 24, 2012 07:52

• deselect all rows in af: table in the adf.

  Dear all,
  
  I have af:table with activated single selection. When the page is initially loaded I want all rows of the table deselection... so, how can I achieve this?
  
  
  Thank you.
  Kind regards.
  
  jdev version 11.1.1.4.0

  Remove the attribute according to the definition of af: table when a display object is instance fell into the page in a table:

  selectedRowKeys = ' #{bindings. " Employees.collectionModel.selectedRow}.

  The example of table definition should look like:

  
  lines = ' #{bindings. " Employees.rangeSize}.
  emptyText = "#{bindings." Employees.Viewable? "{'No data to display.': 'Access Denied.'}".
  fetchSize = "#{bindings." Employees.rangeSize}.
  rowBandingInterval = '0 '.
  selectionListener = "#{EmpTableBean.onTableNodeSelection} '"
  rowSelection = "single" id = "t1" >

  The following code can be used to get the selected node - after the user selects a node:

  {} public void onTableNodeSelection (SelectionEvent selectionEvent)
  resolveMethodExpression ("links. Employees.collectionModel.makeCurrent} «»
  NULL, new class [] {SelectionEvent.class},
  (New Object() {selectionEvent});
  Object richeTableau = (RichTable) selectionEvent.getSource ();
  Line line = null;
  {for (object facesRowKey: {object.getSelectedRowKeys ())}
  object.setRowKey (facesRowKey);
  Object o = object.getRowData ();
  JUCtrlHierNodeBinding rowData = o (JUCtrlHierNodeBinding);
  line = rowData.getRow ();
  }
  System.out.println (Row.GetAttribute("FirstName"). ToString());
  }

  public Object resolveMethodExpression (String expression, class returnType,
  Class [] argTypes,
  Object [] argValues) {}
  FacesContext facesContext = FacesContext.getCurrentInstance ();
  Application app = facesContext.getApplication ();
  ExpressionFactory elFactory = app.getExpressionFactory ();
  ELContext elContext = facesContext.getELContext ();
  MethodExpression methodExpression =
  elFactory.createMethodExpression (elContext, expression, returnType,
  argTypes);
  Return methodExpression.invoke (elContext, argValues);
  }

  Thank you
  Nini

• 1.5.4 - slow to expand the tables for oracle 9 connection

  Hello
  
  I have tried version 1.5.4 and have found that in developing the node tables in the Connections tab is extremely slow (about 3 min) for my oracle 9.2.0.6 connections.
  
  As with this [this bug: http://forums.oracle.com/forums/thread.jspa?threadID=867600 & tstart = 0] it's ok on a 10.2.0.3 connection.
  
  Expand the tables for the same connection in 1.5.3 is good too. I'm concerned that this latest version of the sql dev was not particularly well tested with oracle 9 abit.
  
  Oracle 9 is still a supported with sql developer version?
  
  Thank you
  Paul

  This issue is dealt with the last patch, ' check for update ' should take care of everything.