By selecting only normal characters of the column data

Hello

We have a table column that stores the names of party and this could be in non-English characters. If anyone knows how just to select the regular lines of English character of the table using a select query and does not include rows that have non-English characters?

Thank you

ryansun wrote:
Thank you Frank and Chris,

Group names can have numbers, parentheses, commas (mostly address is attached). I wanted to so all English characters. Whatever in another language can be eliminated. I think in your examples, it considers that the alphabets.

So spaces, punctuation, numbers and symbols like '%' is all right; is this fair?

In this case:

SELECT     *
FROM     table_x
WHERE     CONVERT ( party_name
          , 'US7ASCII'
          )     = party_name
OR      party_name     IS NULL          -- If wanted
;

Tags: Database

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How to cut the column data

Gurus in the morning

I have two tables with the data in the corresponding column, BUT I need to cut the columns in a table
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05/06/2011 00:00:00     0609pro     0609IN002C_06
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07/06/2011 00:00:00     0609pro     0609IN002C_06
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10/06/2011 00:00:00     0609pro     0609IN002C_06
12/06/2011 00:00:00     0609pro     0609IN002C_06
01/06/2012 00:00:00     0609pro     0609IN002C_06
02/06/2012 00:00:00     0609pro     0609IN002C_06
03/06/2012 00:00:00     0609pro     0609IN002C_06
06/06/2012 00:00:00     0609pro     0609IN002C_06
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user11978142 wrote:
Yes the code always starts with an alphabetic character and always ends before the underscore character and the prefix is always digital.

And Yes to the second comment WRT 1 to many relationship.

WRT the duplicates I want the info displayed even if there is no matching printpdf

You talk a LEFT OUTER JOIN, then:

See the example below (the statement are just to reproduce the paintings, just use the last query):

WITH xpq_log AS
(
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   SELECT '0609IN002C_06' log_hdr FROM DUAL UNION ALL
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(
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Output:
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-------------- -------------- -----------------------------------
0499SYS003A_06 SYS003A        STOCK FILE PURGE - PRINT WH CONTROL
0612PV410W1_06 PV410W1        Description 2
2201PA100D1_30 PA100D1
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All,

Run the query against my timesheet tables below, I get the following results:

SQL - CODE

SELECT
TS.ts_date Date,
TS.user_name name,
SCI Account account,
TS.no_of_hrs hours,
Sum (TS.no_of_hrs) OVER (PARTITION BY ts.ts_date) Daily_Total
Of
eba_time_timesheet ts,
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1 December 09 JOHND 489310 1.5 8
1 December 09 JOHND 486830 1.5 8
1 December 09 JOHND 481710 3 8
1 December 09 JOHND 481210 8 0.5
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1 December 09 JOHND 485710 8 0.5
1 December 09 JOHND 481010 8 0.5
December 2 09 JOHND 481710 1 8
December 2 09 JOHND 485710 7 8
December 3 09 JOHND 481710 6 8
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4 December 09 JOHND 489710 8 8
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7 December 09 JOHND 489710 7 8
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1 December 09 JOHND 486840 0.5
1 December 09 JOHND 485710 0.5
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This is my 1st post, so if I missed something or you need more information please let me know.

I use Oracle 10 g
Hello

Welcome to the forum!

Whenever you have a question, it helps if you post the CREATE TABLE and INSERT statements for some examples of data.
For example:
```
CREATE TABLE     eba_time
(     ts_date          DATE
,     name          VARCHAR2 (10)
,     account          NUMBER (6)
,     no_of_hrs           NUMBER
);

INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('1-Dec-09', 'DD-Mon-RR'),  'JOHND',  489310,  1.5);
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INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('1-Dec-09', 'DD-Mon-RR'),  'JOHND',  481710,  3);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('1-Dec-09', 'DD-Mon-RR'),  'JOHND',  481210,  0.5);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('1-Dec-09', 'DD-Mon-RR'),  'JOHND',  486840,  0.5);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('1-Dec-09', 'DD-Mon-RR'),  'JOHND',  485710,  0.5);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('1-Dec-09', 'DD-Mon-RR'),  'JOHND',  481010,  0.5);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('2-Dec-09', 'DD-Mon-RR'),  'JOHND',  481710,  1);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('2-Dec-09', 'DD-Mon-RR'),  'JOHND',  485710,  7);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('3-Dec-09', 'DD-Mon-RR'),  'JOHND',  481710,  6);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('3-Dec-09', 'DD-Mon-RR'),  'JOHND',  488810,  1.5);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('3-Dec-09', 'DD-Mon-RR'),  'JOHND',  481310,  0.5);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('4-Dec-09', 'DD-Mon-RR'),  'JOHND',  489710,  8);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('7-Dec-09', 'DD-Mon-RR'),  'JOHND',  481110,  0.5);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('7-Dec-09', 'DD-Mon-RR'),  'JOHND',  489710,  7);
INSERT INTO eba_time (ts_date, name, account, no_of_hrs) VALUES (TO_DATE ('7-Dec-09', 'DD-Mon-RR'),  'JOHND',  481210,  0.5);
```
I know that you have in fact two different tables, but if you already know how to join them, you could simplify a bit the issue by claiming there is only a single table. Could you tell what you're doing, like this: "what I posted as eba_time really is a join of two tables separate."

GROUP BY... CUMULATIVE (or GROUPING SETS) is a convenient way to get totals for the same set of results with the raw data. It helps if you have a primary key or a sime column that uniquely identifies each row.

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By selecting only normal characters of the column data

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