bypassing the shift registers

Similar Questions

• How can I clear the shift registers of sub for loop for each iteration of a larger loop?

  Hello

  I write a program to concatenate multiple text files.  However, I need to treat each column individually before they are concatenated.  I use one for a loop at normalze 6 columns choice the largest loop of concatenation.  However, the shift registers store data from previous iterations of the larger loop.  How can I clear the shift registers of the void loop based on the iteration of the larger loop?

  Thanks in advance!

  OK, that's fine. are there headers?

  In all cases, all you need to do is to place all of the 2D array in the shift register of the inner loop, iterate over the columns relevant to be normaized (use 'index array' to get the column it normalize, put it to help to "replace the subset of table".) You probably want to initialize the outer loop shift register. Use then "building the table" added to the beginning or the data of each file sets.

• Simplify the VI that rate but currently uses too many shift registers

  I have a VI that was made by the Director of scary movie, so beware, this VI is a nightmare!... or at least for me, it is.

  Background:

  I have 20 pans and I have a water level sensor that generates a voltage of 0 to 5 Volts Output. By knowing the volume of the Pan, I calibrated the output to be in gallons. Real output I need is a volumetric flow, i.e. gallons per minute per square foot. We currently is key this by using a VI that a filed summer internship (see table). It works well, but it's so dirty and difficult to clean up and expand. The plan is to have 100 total pans and I don't want to copy paste this code 5 times more!

  Issues related to the:

  -How can I earn a rate differently? If you notice on the attachment Subvi calibration, the rate is calculated manually knowing how fast the loop going in the main VI. I don't know if this is the best way

  -Can I get rid of the shift registers some how?

  Is there a way for me to combine the subVIs in calibration so that I don't have a Subvi for each channel?

  Thanks in advance!

  
  

• Shift registers loop when the chain is connected to the registers

  Hello everyone! I just need to know how these shifts of registers. For example a photo added, I have a stacked sequence structure. Some time ago in a loop with inside case structures. As you can see, there is registry to offset looping with initial string and on the right side of passage registry there is string "entry". So my question is when we run the VI, to check the error case it is going to start from initial case and then transmit the information to the case of entry into the structure of the case. So basically, I need to know how the shift registers can be used with the structures of the case and while loop.

  

  http://www.NI.com/Tutorial/9330/en/

  With this you can post a photo that is executable code.  For us looking at your code is not better than watching a photo with text in Notepad.

  That being said here is some information on shift registers.

  http://www.NI.com/getting-started/LabVIEW-Basics/shift-registers

  https://zone.NI.com/reference/en-XX/help/371361H-01/lvconcepts/shift_registers_concepts/

  To simplify your code, I highly recommend getting rid of the outer sequence structure.  Stacked sequence structures serve generally to cause new problems to users, and sequence variables compound which.  If you want the code to run before the main States are called, you can have a status of initializing in your state machine and do be more manageable.

• Using shift registers global verses

  I'm new to 2009.  Our last update was 7.1.  I'm upgrading our laboratory SW and using events.  EVENT 1: is used to display the data in a text file in a table "data set".  EVENT 2: using to option button and the table "Data set", the user selects the data column to use for the test that is displayed in a table «Points de Test»  EVENT 3: If the user changes the data in the table "set of data', 'Points of Test' test point table is the update.  I use local variables for 'Set data', 'Points of Test' and I was going to use other settings as well (radio button, etc.).  I also think about using a shift register to realize that the same information.  I used shift registers in the past and they can be annoying, but I also understand that you should stay away from variables.  Please pass along an Advisor on the use of local variables shift verse records.  THANKS in advance!

  I don't know what you defined as 'EVENT 1' to '3', but they seem to be quite the case.

  The use of shift registers sounds messy, but they are much better than local Variables If you parallel threads past in your code.

  Clean the threads between the shift registers is to use clusters.

  People of the country appear more clean, until they 'byte' you in the... code...

  EDIT: "they are much better than local Variables If you parallel threads going on in your code" I have to explain... If you have parallel code that uses Variables to local variables as this may lead to a race or conditions...

• Need help with while loop and shift registers

  I have a broad set of data and required to read data at maybe 200 samples at a time to process these samples through my VI and have add and concatenate a file separate lvm.  The part where I am confused is the shift registers. How can I limit the number of samples read in an iteration? How do the while loop to stop when all data are read in?

  I have attached my diagram, there may be something wrong with my technique?

  This will give you an idea.  There are a lot of other (probably more effective) methods.  It is a basic solution, quick and dirty to help you grasp the overall concept.

• Change the shift register

  I hope someone can direct me on that. I'm stuck.

  The NTC, I want that it start at zero, enter the nested loop

  and when the case statement is equal to one, add 3000,

  so I have a lag on "undesirable" elements in the 1 d

  table I'm parsing...

  TIA!

  the nested loop shift register is not initialized, it is best to initialize it with a constant 0

  Then, the index entry Array subset function is connected after or before the function incriment? I can't decide...

  in any case, if it is connected before the incremint function then the nested loop iteration 1 will send a 0 at the entrance to the function of the subset of the Array index.

  EWW! , a lot of entries, words of functions in the above paragraph lol , can u get me here?

  now I can just understand the problem what exactly you're talking about. the sequence of events for your code will be like this:

  After the nested loop is complete, the output will be available (1 d the function add array element table) to the structure of the case where you want to add 3000 to the value of the shift register and start the loop nested with initialized again records with value = 3000? Am I wrong?

  If I'm right, you must reset the shift by using a control register, create a local variable to him and place it in the business structure then her manipulate it as shown below:

  

  Since the default data of "N" type digital command value is 0, then initially the shift registers will be initialized with 0 as the guy above

  Thank you

• StateMachine in Subvi, restart shift registers

  Hello

  I'm having a problem with a reentrant Subvi, which implements a State Machine. The Subvi is called only once in the code, so problems with re-entrant execution concave/no is not the problem.

  The Subvi implements a State Machine whose output is a reference position for a drive motor. The state machine is implemented with while loop with shift registers. The Subvi is called once each control cycle (cycle being about milliseconds time), so that the State Machine while loop is executed once each cycle control (stop Terminal is connected to 'true'). And the shift registers are used to save data between executions.

  When I opened the main VI, it works perfectly. When I stop the VI and restart, the Subvi begins to use the last values of the previous main run of VI. I want that my position reference to start from 0. I guess my problem is that I should start the SubVIs shift registers.

  Is there a way to do this without adding any extra code? (Perhaps an invoke node functionality for the Subvi or something like that?)

  Thanks in advance for your help

  Best regards

  Pestana of Jesus

  Hi jespestana,

  I recommend adding a case of initialization.

  Mike

• Sort of the length of the sample segment longer that the iterations of the loop w/o shift registers?

  Hi all

  My loop runs about every s 0.06 and now I was prompted to add to program a function that will enjoy the latest 3 data and return the max/min value for two of the signals.  I can imagine a clumsy way by program to do this with SHIFT registers - take the max/min for each iteration, save-repeat-compare until you have enough iterations to fill 3 s of time.  But I can't help thinking there must be a cleaner way (better?) to do.

  Any help?

  Thank you

  Hello

  Try looking in a circular buffer.

  http://zone.NI.com/DevZone/CDA/tut/p/ID/7188

  Once you have determined how many times you put entries in the buffer, you will know exactly what is the size of a table to enter and do the Min/Max on.

  Another option is to use a circular table.

  http://decibel.NI.com/content/docs/doc-3414

  I would be created to operate somewhat like a Global functional or motor of the Action.   The Subvi would then be used in your loop DAQ for new data "stack."   Then called in another loop or part of your code to read every three seconds.

• How to bypass the automatic connection in Vista. The SHIFT key after that logging does not work.

  I'll put up a laboratory of small kiosk for my students with a minimum account privs.  Sometimes I need to login with the administrator account to perform regular maintenance or solve a problem.  in xp, all I had to do was hold down the SHIFT key before the blue startup screen and all accounts (including my admin account) were visible.  This doesn't seem to work with vista.  is there a secret combo of keyboard shortcuts?  What should I do to ensure that both accounts visible?

  Hi Scentfromabove,

  Follow this step in order to bypass the automatic connection in vista.

  1. Click Start and type netplwiz in the start search box and press ENTER.
  2. check the users must enter a user name and password to use this computer
  3. click on apply and OK.

  I hope this helps.

  Bindu S - Microsoft Support
  [If this post can help solve your problem, please click the 'Mark as answer' or 'Useful' at the top of this message.] [Marking a post as answer, or relatively useful, you help others find the answer more quickly.]

• problem with the shift register

  for purposes of simplicity, I remove code without problems

  Description:
  1. my state machines, for some reason, a lot of cases.
  2. the order of each case may not change.
  3. the main prupose is to get the difference as on the front panel
  4. prior to entry difference, I first is measured in the case where 2 and TRY using shift register to pass data, ideally at least 5
  5. However, the "previous" value is updated too soon, unlike 'get' is always ZERO.

  for example
  You can see the shift register on the left side has two components, ideally, the 'get' difference should display 2-0 = 2.
  However, given that the second element of the registry team updates too early, my objective cannot reach and meet up with ALWAYS 0

  I think it's my misuse of the shift register for the computer to several cases.

  I pasted this problem for 4 hours... kind of stupid, but could not understand

  in a mulit-case state machine, how to properly passes data to the case (5 in this example) INSTRUCTION to ensure that I get the correct calculation

  GOLD: because I am only looking to the current value and the previous value, are there other ways to get this problem is?

  Thank you

  It is a case where execution highlighting can be helpful. Turn on execution highlighting by clicking the light bulb on the block diagram toolbar. Then, run the VI.  You will see the left side of the team to register the change as the state machine goes through States 3 and 4.  At the time where what happens to 5, all data in the change record is identical.

  One of them might be to use two registers to offset, one for the current value and the other for the previous value.

  Lynn

• shift registers obvious between tracks

  Hello

  The day noob question! I'm building a table and want to erase registers with shift between runs. I have attached a VI. It works a while loop every second, then adds an array of the number of the iteration. I then display the length of the array. I would like it so that whenever I have press run, the program starts with a "blank slate." No standard way to erase everything. I'd like to do something like:

  %

  CLC

  Claire

  whether MATLAB...

  Right click on the shift on the right left register and select "create constant.

  (also use a real stop button, or at least make your Boolean lock action (right-click... mechanical action... lock release))

  () * EDIT: corrected right left)

• Increment of the counter without using the shift register

  Is there a way to count = count + 1, with using a node registry or feedback shift?  I have a structure of the event within a while loop (see table).  When the button is touched (kickoff event), a test is carried out.  Based on the test in the case of a string is passed outside of the event to a case statement of success/failure.  The user can run one of these 'events' as many times as he or she wishes.  And in an order any... Test1 (fails)... test 1 (fails)... again... test1 (go) again... test 2 (pass) then test 1 (pass).  When the stop button is reached, I would like to know how many times each pass/fail is produced for each test.  Try to stay away from shift registers, as I have 18 w key so a possible failure for each, so I would need 36 shift registers.

  In my example, the printed final statement would be:

  TEST PASS/fail # x test was performed

  test1 failure 1

  2 in case of failure test1

  Test1 pass 3

  Test2 pass 1

  4 passes test1

  etc.

  Do not see an attachment.

  You can use a shift register to store a table.

  Each button would be mapped to an array index. For each button pushed you the value of the index table, + 1, replace the array element and pass out back for the shift register.

• Cluster vs multiple Shift Registers

  I had a question about good coding practices.

  Say you have several elements (numeric values, strings,... whatever) you need to iterate between the loops.

  Is it better to make a registry change for each item?
  Or cluster, and then move the cluster to a single shift register?

  It is faster than the other? Or better/worse for another reason?

  Cory,

  Yes.  and no.

  I usually create a large cluster of typedef I call indicators and flags (InF).  I put most of the things that need to be passed around with that.  The cluster of error, the State enum and large data tables are usually in separate shift registers.  Table L: shift registers and data are at the top of the loop and error and SRs of the State are at the bottom.  Most of the code goes between them.  Given the help of bundle/Unbundle documents name to which the data is used in a case.  The InF cluster is usually not displayed on the Panel before and may exist only in a Subvi to save space of block diagram.  The data are unbundled indicators as needed for display to the user.

  If you have a situation where speed is concerned, separate data that must be processed everything quickly and optimize for that.  Strings and arrays within the cluster probably cause some memory interesting distribution issues since they change size, that can be an argument in favour of that separates them.

  Lynn

• How to program the shift register to play only when a new user is detected user?

  Hello

  I'm currently developing a program of position control in labview. The program is quite simple, in which case the user will enter the distance on which he wants the table in the labview program and labview will send the signal to move a motor that will turn a ball screw to move a table horizontally to the targeted position. The criterion is that the profile of the engine depends on the distance to move, if a biphase (acceleration and deceleration) or three phase (acceleration, steady speed, deceleration) to reach the position of the target.

  The problem occurs when the user wants to enter a new entry second position) for the table, as the input by the user is the position that the table should be, but the necessary input to determine what profile the engine follows depends on the distance that the table moves to the target position. Therefore, I need a function to save the entry by the user temporarily and reminds that when a new user input is detected. Hereby, I would be able to use the difference of the input (input [n + 1] [n] input) and animal feed to determine what profile the engine follows and the entry by the user can be kept in the position he wants to the table to get (to compare with encoder).

  I thought to use for shift registers do, but I am not able to perform the deduction ([n + 1] - [n]) only when it detects a new entry. When I try to use registry to offset, it moves to the target location, and we only reached it will go to the original position. For example, when a user entry 90, this means that the table must be moved to the point 90. The shift register is initialized to 0, it will move to the point 90 (90-0 = 90), but arriving at 90, the shift register sends a signal of 90 (90-90 = 0) and the table back to its original position.

  Is it possible that I can delay the reading of the shift register only when a new entry is detected or there at - it another way for me to achieve what I want?

  I tried searching the forum site and neither discussion but could not find similar problems. Thank you for your help in advance.

  As I understand it, the use of shift registers with a structure of the event (to detect a user event when the user enters a new value) should solve the problem. Do not forget to post your request (or a version of it that isolates the issue) when you arrive at the lab, if we can get a clear visual of the issue you are facing.