Calculate elapsed hours between two time fields

Similar Questions

• Calculate business hours between two dates in a cursor

  Hello, its me again (?).
  
  Yesterday, I got a solution to a problem here where I need to calculate the hours between two dates, excluding Sat/Sun and from 09:00 to 18:00. I'm now putting this login in a PL/SQL block, so I can calculate it for each record in a slider, all by looping.

  with t (start_date
         ,end_date
         )
  as (select  to_date('22-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') start_dt,
                         to_date('23-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') end_dt
      from dual
     )
  , hrs (dt) as
    (select start_date
     from   t
     union all
     select dt +1/24/60
     from   hrs
     where  hrs.dt < (select end_date-1/24/60 from t)
    )
  select count(*)/60
  from hrs
  where to_char(dt,'dy') not in ('sat','sun')
  and  to_number(to_char(dt,'hh24')) not between 18 and 23
  and  to_number(to_char(dt,'hh24')) not between 0 and 8
  /

  The logic above, I'm up here:

  FOR c_record IN c_1 LOOP
  //For each record, check if the two dates meet the criteria and then raise the counters accordingly
  select  to_date(c_record.REPORTADA,'dd-mon-yyyy hh24:mi:ss') INTO vFch1 FROM DUAL;
  SELECT  to_date(c_record.INICIOREAL,'dd-mon-yyyy hh24:mi:ss') INTO vFch2 FROM DUAL;
  
  IF ((vHoras > 2) AND c_record.PRIORIDAD=3) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE 
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END
      IF;
  
  IF ((vHoras > 4) AND c_record.PRIORIDAD=2) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  IF ((vHoras > 16) AND c_record.PRIORIDAD=1) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  END LOOP;

  I really don't like if the performance is horrible because it will run once a month and should spend only 40-100 records.
  However, I can't find a way to use this connection even in this case
  
  Could you help me?
  Thank you!
  
  Greetings,
  NACEUR

  N wrote:
  I need to calculate the number of minutes between two dates, only count the hours from 9 to 18hs.

  CREATE OR REPLACE
    FUNCTION get_bus_minutes_between(
                                     p_start_date DATE,
                                     p_end_date DATE
                                    )
      RETURN NUMBER
      IS
          v_return NUMBER;
      BEGIN
          with t as (
                     select  case level
                               when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                               else trunc(p_start_date) + level - 15 / 24
                             end start_dt,
                             case connect_by_isleaf
                               when 1 then least(p_end_date,trunc(p_end_date) + 18 / 24)
                               else trunc(p_start_date) + level - 8 / 24
                             end end_dt
                       from  dual
                       connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                    )
          select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
            into  v_return
            from  t
            where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
          RETURN v_return;
  END;
  /
  

  For example:

  SQL> select get_bus_minutes_between(
    2                                 to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'),
    3                                 to_date('22-oct-2012 13:21:00','dd-mon-yyyy hh24:mi:ss')
    4                                ) work_minutes
    5    from dual
    6  /
  
  WORK_MINUTES
  ------------
           261
  
  SQL> 
  

  SY.

• Calculate the hours between two dates

  Hello
  
  I have a requirement to count the hours with 2 given timestamps, something like:

  SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;
  
           B
  ----------
          48

  However, I wish it would be that simple. I just need to count the hours between two timestamps for the hours of work for example, 08:00 - 17:00, MONDAY to Friday (excluding weekends).
  So lets say I have to count the hours between two dates above the result should be 18 hours not 48 (4 hours on 20/oct, 9 hours on 21/oct to 5 hours 22/oct).
  How can I achieve this? Any idea will be useful.
  
  Thank you

  My query generates a list of all the hours between the start and end time, filters on the hours that are outside of the hours of work and then account for the remaining lines. Change that to partial hours must just be a case of replace the two occurrences of 1/24 with 24/01/60, then - as say you - Division COUNT (*) by 60.

  There may be performance issues using techniques of generation of line like this, if you put this in a query involving the joining of several lines of other tables (for example where the dates of beginning and end are derived from several employees?) or in several days. If you don't find it then count the number of whole days (taking weekends into account) between dates and work on the partial days after that it could be better. This would probably involve a lot of statements of case (which I don't have time to test it now).

  Ben

• How to find the hours between two times

  Hai All
  
  I had a problem I need to calculate work time
  
  For example
  
  Respondent outtime
  
  0815 1715
  
  So I need to calculate a time between these two times
  
  How can I do using function for 100 our
  
  Concerning
  
  Srikkanth.M

  Hello

  use the below the update statement.

  update dail_att set wtime =  extract(hour from (to_date(outtime,'HH24:MI')-to_date(intime,'HH24MI')) day to second);
  

  Solution of the sample...

  PRAZY@11gR1> desc dte;
   Name            Null?    Type
   ------------------- -------- --------
   INTIME           VARCHAR2(4)
   OUTTIME        VARCHAR2(4)
   HRS                NUMBER
  
  PRAZY@11gR1> select * from dte;
  
  INTIME     OUTTIME           HRS
  ---------- ---------- ----------
  0815       1715
  0900       1800
  0830       1630
  
  Elapsed: 00:00:00.00
  PRAZY@11gR1> update dte set hrs = extract(hour from(to_date(outtime,'HH24MI')-to_date(intime,'HH24MI')) day to second);
  
  3 rows updated.
  
  Elapsed: 00:00:00.01
  PRAZY@11gR1> select * from dte;
  
  INTIME     OUTTIME           HRS
  ---------- ---------- ----------
  0815       1715                9
  0900       1800                9
  0830       1630                8
  
  Elapsed: 00:00:00.00
  

  Kind regards
  Prazy

  Published by: Prazy on March 24, 2010 12:43

• How to calculate the hours between two dates by the numbers

  If I update 09:00 start time 17:00 end time of shift in C3 and B3, how to use a D3 formula to calculate the number of hours between the two?  Then I can just copy down the lines for nth years...

  It is a spreadsheet of the part-time staff payroll.

  I'm sure that a lot of people out there have done that.

  Help, please.

  Thank you.

  Eddie

  What program of worksheet that you are using? Since you have a newer iMac running El Capitan, I can safely assume that you use NOT AppleWorks, which is a Power PC application that can run on any OS newer than the snow leopard, OS X 10.6.8.

  If you use numbers, try to repost your question in numbers for Mac forum. If you use Microsoft Excel, try posting in the Microsoft forums. LibreOffice also has community support.

• difference in hours between two time zones of differnet

  I have a sysdate (EAST) and a function util_pkg.local_tz returns a different datetime value.
  I need to get the difference in hours between sysdate and another date.
  
  Select sysdate, util_pkg.local_tz (sysdate, ' Asia/Seoul') of double;
  
  18/05/2011 11:15:00.000000000 FROM 18/05/2011 10:15 PM + 09:00
  
  Quest:-find the difference in hours between these two date and then add the difference of hours + sysdate
  
  

  FUNCTION local_tz (p_datetime IN TIMESTAMP,
                        p_timezone IN VARCHAR2)
        RETURN TIMESTAMP WITH TIME ZONE
     AS
     BEGIN
        RETURN FROM_TZ(p_datetime, TZ_OFFSET(con_database_timezone))
                       AT TIME ZONE TZ_OFFSET(p_timezone);
     END local_tz;

  When you calculate the diff between TIMESTAMP WITH TZ they both are converted to time UTC (in fact they are stored as UTC). So diff between SYSTIMESTAMP in EST and SYSTIMESTAMP in Seoul will always be 0, as bioth are "now". You need to cast TIMESTAMP WITH TZ 'losing' time zone timestamp:

  SQL> select cast(systimestamp at time zone 'Asia/Seoul' as timestamp) - systimestamp from dual;
  
  CAST(SYSTIMESTAMPATTIMEZONE'ASIA/SEOUL'ASTIMESTAMP)-SYSTIMESTAMP
  ---------------------------------------------------------------------------
  +000000000 13:00:00.000000
  
  SQL>  
  

  SY.

• Calculations between two time fields

  Hello

  I have a form with a time for the start time field and a text field for the user to enter a duration (for example, 00:30:00).

  There is another field for the end of time (which has a calculation script using the date and starting time fields).

  The script that was placed in the end time field works except the script gives a negative result.

  For example the start time field is 16:03:33 and 00:30:00 duration field calculation end is showing time field-

  Please can someone advise how I can change the script of the time field end to show the correct result of 16:33 (without the negative)?

  
  create string for the current date
  var oToday = new Date();
  sToday var = util.printd ("yyyy/mm/dd", oToday);

  get the value of the start time field

  var sStart = this.getField("Action_Start_Time").value;

  create the JavaScript date object time for start time
  var start = util.scand ("yyyy/mm/dd hh: mm:", sToday + sStart);

  
  get the duration value

  Send var = this.getField("Action_Time").value;

  create a JavaScript date object time to end time
  oEnd var = util.scand ("yyyy/mm/dd hh: mm", sToday + shipment);

  calculate the difference in hours, the difference in hours
  var DiffHours = (oEnd.valueOf () - oStart.valueOf (()) / 1000 / 60 / 60;
  Event.Value = Math.floor (DiffHours) + ': ' + util.printf ("%,302.0f", (((DiffHours % 1) * 60) .toFixed (()));

  Any help will be greatly appreciated.

  You cannot change the '-' operator operator '+' being Modulo calculation date and time calculations. You must calculate the different parts of the date and time of the start time and elapsed time and then convert these values into a date object time and format of this new date time object.

  Clear the field
  Event.Value = "";
  getting the activity start time
  var sEventStart = this.getField("Activity_Start_Time").value;
  calculate only if there is a start time
  If (sEventStart! = "") {}
  operations of the console are for debugging and illustration
  /*
  Console.Show ();
  Console.clear();
  */
  convert a date object change if necessary format
  var oEventStart = util.scand ("YYYY, mm, DD, HH", nNowYear + "," + (nNowMonth + 1) + ',' + nNowDate + ', ' + sEventStart);
  Console.println ("oEventStart:" + oEventStart);

  get the date current time
  var oNow = new Date();
  Console.println ("oNow:" + oNow);
  get the date parts
  var nNowYear = oNow.getFullYear ();
  var nNowMonth = oNow.getMonth ();
  var nNowDate = oNow.getDate ();
  /*
  Console.println ("nNowYear:" + nNowYear);
  Console.println ("nNowMonth:" + nNowMonth);
  Console.println ("nNowDate:" + nNowDate);
  */
  get the duration of activity
  var sEventDuration = this.getField('Event_Duration').value;
  If no entry in force at time zero
  if(sEventDuration == '') sEventDuration = "00:00:00 ';
  convert the time in hours and minutes
  var aEventDuration = sEventDuration.split(":");
  /*
  Console.println (' hours - aEventDuration [0]: "+ aEventDuration [0]");
  Console.println ('Minutes - aEventDuration [1]: "+ aEventDuration [1]");
  Console.println (' hours start: "+ oEventStart.getHours ());
  Console.println ("minutes:" + oEventStart.getMinutes ());
  Console.println ("second Start:" + oEventStart.getSeconds ());
  */
  calculate the minutes and the end times
  var nEndHour = Number (oEventStart.getHours ()) + Number(aEventDuration[0]);
  var nEndMinute = Number (oEventStart.getMinutes ()) + Number(aEventDuration[1]);
  if(aEventDuration.Length == 3)
  var nEndSecond = Number (oEventStart.getSeconds ()) + Number(aEventDuration[2]);
  on the other
  var nEndSecond = Number (oEventStart.getSeconds () + 0;
  /*
  Console.println ("nEndHour:" + nEndHour);
  Console.println ("nEndMinute:" + nEndMinute);
  Console.println ("nEndSecond:" + nEndSecond);
  Console.println ("nNowYear:" + nNowYear);
  Console.println ("nNowMonth:" + nNowMonth);
  Console.println ("nNowDate:" + nNowDate);
  */
  do the date for the end of the event object - calculate the hours and minutes
  oEnd var = new Date (nNowYear, nNowMonth, nNowDate, nEndHour, nEndMinute, nEndSecond);
  Console.println ('oEnd: ' + oEnd);
  change the format if necessary
  Event.Value = util.printd ("HH", oEnd);
  } / / end of event time

• Formula of FormCalc to make the difference between two time fields if they are populated - help please

  
  Hello

  I have a laptop (TotalTime1) which refers to two other cells in the updated hour-shaped (Start1 and 1 to finish).

  The formula below is intended to make the difference between the time of departure and of arrival if they are populated.

  I had to work unconditionally HasValue, but the formula was calculated when there is no value in the Start1 and Finish1 (due to the time format).

  This is the code I have, it is said that there is an error of almost the last line; I'm sorry if I'm posting this in the wrong way, I haven't posted on this forum before but this is:

  If (HasValue (Finish1) and HasValue (Start1)) then if (Time2Num (Start1.formattedValue, "HH: mm") < Time2Num (Finish1.formattedValue, "Hh: mm")) then Abs (Time2Num (Start1.formattedValue, "HH: mm")-Time2Num (Finish1.formattedValue, "HH: mm")) / (60 * 60 * 1000) another 24 - ABS (Time2Num (Finish1.formattedValue, "HH: mm")-Time2Num (Start1.formattedValue, "HH: mm")) / (60 * 60 * 1000) endif

  Any help would be appreciated.

  Cordially Fetachini

  you need an another endif at the end (you have nested statement and only 1 endif)

• How to calculate the difference between two times by the NUMBERS

  I'm so bothered by the fact that I can't understand that.

  Cell B2 - 08:00

  Cell C2 - 10:50

  (How can cell D2 - I get this cell to calculate the difference and say 02:50?)

  I know it's probably one of the most basic operations, but for the life of me I can't understand it. The cells B2 and C2 are formatted for a 24-hour clock. But if I tell the system to just subtract the two, I get "0,118. Everything I find on the forum search goes beyond what I need. Can someone help me?

  Thank you

  Hi sapirs,

  Departure and arrival of the cells are in Date and time with Date format: no and time: 24-hour clock.

  

  Formula in D2 (fill down)

  = C2−B2

  

  The results become a duration format, but under automatic (numbers automatically worth this format)

  

  If you wish, you can change the cells of lasting results.

  What Data Format have your result cells?

  Kind regards

  Ian.

• Calculate business hours between 2 dates with negative numbers

  Hi all

  I use a function to calculate the difference between 2 dates schedules. The function was taken and adapted from this thread:

  Calculate business hours between two dates in a cursor

  CREATE OR REPLACE
  FUNCTION get_bus_minutes_between(
                                   p_start_date DATE,
                                   p_end_date DATE
                                  )
    RETURN NUMBER
    IS
        v_return NUMBER;
    BEGIN
        with t as (
                   select  case level
                             when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                             else trunc(p_start_date) + level - 15 / 24
                           end start_dt,
                           case connect_by_isleaf
                             when 1 then least(p_end_date,trunc(p_end_date) + 20 / 24)
                             else trunc(p_start_date) + level - 4 / 24
                           end end_dt
                     from  dual
                     connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                  )
        select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
          into  v_return
          from  t
          where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
        RETURN v_return;
    END;
    /

  I am running into an issue that when the p_end_date is before the p_start_date value the function returns the full time between the dates without regard for business hours. if the end_date is before the start date I get the expected result i.e. difference between the dates in business hours.

  Using example dates of start 19th October 2012 13:00:00 and end 22nd october 2012 13:21:00 the business minutes are 681. However if i reverse the dates I get -4341.

  


  Correct labour code is the following, I've annotated so that he could help someone else looking for a solution like this:

  CREATE OR REPLACE
  FUNCTION get_bus_minutes_between(
                                   p_start_date DATE,  --these are the 2 dates passed into the function
                                   p_end_date DATE     --these are the 2 dates passed into the function
)
RETURN NUMBER
IS
v_return NUMBER;

          l_start  DATE;

          l_end    DATE;

          l_factor NUMBER;
    BEGIN

          IF p_start_date <= p_end_date THEN            --this IF section checks which of the 2 dates is the greatest


             l_start  := p_start_date;                  -- and then assigns the earliest date to p_start_date


             l_end    := p_end_date;

             l_factor := 1;

          ELSE   -- swap the dates around, and multiply the result by -1

             l_start  := p_end_date;

             l_end    := p_start_date;

             l_factor := -1;

          END IF;


          with t as (
                   select  case level
                             when 1 then greatest(l_start,trunc(l_start) + 9 / 24)  -- this sets the start of working hours
                             else trunc(l_start) + level - 15 / 24  --if the start time is adjusted this value must also be adjusted
                           end start_dt,
                           case connect_by_isleaf
                             when 1 then least(l_end,trunc(l_end) + 20 / 24)  -- this sets the end of working hours
                             else trunc(l_start) + level - 4 / 24  -- if the end time is adjusted this value must also be adjusted
                           end end_dt
                     from  dual
                     connect by level <= trunc(l_end) - trunc(l_start) + 1
                  )
        select  sum(end_dt - start_dt) * 24 * 60 work_minutes  -- this subtracts the 2 dates and then multiplies by hours and minutes
          into  v_return
          from  t
          where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- this exclude weekends
        RETURN v_return * l_factor;  -- this gives the negative or positive results so you can see if it was completed before or after the required date.
    END;
    /

• Difference between two times

  I am building a working method in LiveCycle, and I want to track how long the procedure takes. To do this, I have two time fields, and then a third time field to find the difference between two time fields. Looking at other posts to discussion, I could find a Javascript code that was part of what I wanted, but I can't get the third time field to display in the format I want. I tried to change the habits of the fields and that did not work. Could someone offer some advice on how to change the format or help me with the code?  I couldn't figure to attach the actual file, but I have attached a picture of the PDF file and the Javascript code I used.  If you look at the TimeIn (hh: mm) and time (hh: mm) areas (on the photo, I have attached), you will notice that the TotalTime comes out like HMM, and I want that it out as hh: mm.

  

  

  Any help would be greatly appreciated!

  Thank you

  this.rawValue = (totalHrs > 9? String (totalHrs): '0' + String (totalHrs)) + ':' + (totalMins > 9? String (totalMins): '0' + String (totalMins));

• Help!  Calculate a percentage between two fields that the sum of columns

  Members of the forum good day!
  
  I'm hoping to get help with and model RTF I use to sum up the output of a query in PeopleSoft.
  
  I have a line with two fields of the query and a third field calculates a percentage using the query fields:
  Row1, Field1: EXPR14_14
  Row1, Field2: EXPR1_1
  Row1, Field3: <? xdofx: If EXPR1_1 <>0 and EXPR14_14 0 then (EXPR1_1 DIV EXPR14_14) <>* 100 or 0 end if? >
  
  I have a second row who has these fields:
  Row2, Field1: <? sum (EXPR14_14)? >
  Row2, Field2: <? sum (EXPR1_1)? >
  Row3, Field3: I need the third field to calculate the percentage of sum of two fields.
  
  I tried different ways to insert this calculation with no luck. It's my first time to create a rtf report and any help would be gratly appreciated.
  
  In advanced thank you for your help.
  
  Kind regards
  Raquel

  For the calculation of percentage you can use something similar to this (adjust the formula you need)

  For Row1, Field3:

  Hope that helps. If you need more help, send me the xml file and the [email protected] model

  Thank you
  Bipuser

• Count the hours between the times of the day

  Hello

  It is a timesheet, calculation of payment:

  I'm trying to find a way to calculate how many hours is between two specific times of the day.

  I enter a start time and an end time (in 2 different items), I calculate the number of hours that is. What I can understand.

  Then I need to know how many hours is between 16:00 and 22:00.

  The reason is that there is an additional extra payment for those hours.

  So: "payment on time' X ' total hours work in a day ' + 'bonus' X ' hours between 16 and 22" = "total wages for a day" "»

  Thank you

  

  Enter the full date and time in columns A and B (for example ' 12 Sep 2016 8:00 AM "or you like the what ever valid date time value):

  C2 = B2−A2

  D2 = C2−DURATION (0, 0, 24 × MAX (TIMEVALUE "(04:00 PM)") −TIMEVALUE (A2), 0)) −DURATION (0, 0, 24 × MAX (TIMEVALUE (B2) −TIMEVALUE (' 22:00 "" "), 0))

  Select cells C2 and D2, copy

  Select cells C2 at the end of column D, dough

  If you prefer the values in column D as decimal hours use the formula:

  dur2hours (D2)

  or replace the formula earlier as follows:

  D2 = dur2hours (C2−DURATION (0, 0, 24 × MAX (TEMPSVAL ("04:00 PM") −TIMEVALUE (A2), 0)) −DURATION (0, 0, 24 × MAX (TIMEVALUE (B2) −TIMEVALUE (' 22:00 "" "), 0)))

• calculation of time between two time as timestamp

  How can calculate two hour, START as the timestamp TIME in the data type, END TIME as of time also.

  select END_TIME-START_TIME from PROG_DLY_WORK
  

  Result

  + 01:50:00.000000 000000000

  How can get exactly the time spent as 01:50 ? and these calculated time must sum (elapsed_time) in another column.

  oracle as PaaS cloud environment

  Product	VERSION	STATUS
  NLSRTL	11.2.0.3.0	Production
  Oracle Database 11g Enterprise Edition	11.2.0.3.0	64 bit Production
  PL/SQL	11.2.0.3.0	Production
  AMT for Linux:	11.2.0.3.0	Production

  Time difference between two columns in hours

  Start

  FOR REC IN (SELECT START_TIME, END_TIME, CALC_TIME CAL_ID)

  LOOP

  UPDATE CALc_TIME

  SET ELAPSED_TIME = round (())

  TO_DATE (to_char (REC. End_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")-

  TO_DATE (to_char (REC. Start_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")

  () * 24).

  WHERE CAL_ID = REC. CAL_ID;

  END LOOP;

  end;

  Lag in minutes

  Start

  FOR REC IN (SELECT START_TIME, END_TIME, CALC_TIME CAL_ID)

  LOOP

  UPDATE CALc_TIME

  SET ELAPSED_TIME = round (())

  TO_DATE (to_char (REC. End_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")-

  TO_DATE (to_char (REC. Start_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")

  () * 24 * 60)

  WHERE CAL_ID = REC. CAL_ID;

  END LOOP;

  end;

• Calculate the hours between 2 business days

  Hi all

  Do a complex calculation on the days I do not know how to achieve this.

  Here is my case:

  I have a week of work with hours of work.

  

  Then there's this delivery time sheet for how long should be set an order ready to be delivered:

  Order1: max 5 hours of work

  Order2: max 8 working hours

  Order3: max 16 hours of work

  When an order is placed, the time of the order is recorded, and when an order has been set in ready to be delivered, this time is also registered.

  How to calculate the time difference between the time where an order has been placed and the time where the order has been on loan. Thereby also taking into account the working days and hours of work.

  Example: type order1 order was placed Tuesday at 15:00.

  Order has been fixed loan Wednesday at 14:00

  This means that to fix this ready order lasts 7 hours, which means that it is 2 hours time.

  CREATE TABLE REF_WORKDAYS
    (
      
      "WERKDAG"       VARCHAR2(15 ) NOT NULL ENABLE,
      "SOORT_WERKDAG" VARCHAR2(15 ) NOT NULL ENABLE,
      "BEGIN_TIJD"    VARCHAR2(10 ) NOT NULL ENABLE,
      "EIND_TIJD"     VARCHAR2(10 B) NOT NULL ENABLE,
      
    )
  

  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Monday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Tuesday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Wednesday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Thursday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Friday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Satrurday','WORKINGDAY','08:00','14:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Sunday','NOT-WORKINGDAY','08:00','16:00');
  
  COMMIT;
  

  create table glas_order
  
  (order_id number
  , order_desc varchar2(100) not null
  , order_type varchar2(10) not null
  , order_date date not null
  , order_ready date
  
  );
  

  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (1,'order bla','Order1',to_date('07-APR-15 09:00','DD-MON-RR HH24:MI'),to_date('08-APR-15 12:00','DD-MON-RR HH24:MI'));
  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (2,'order nice','Order1',to_date('14-APR-15 10:00','DD-MON-RR HH24:MI'),to_date('16-APR-15 16:00','DD-MON-RR HH24:MI'));
  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (3,'order ugly','Order2',to_date('18-APR-15 13:00','DD-MON-RR HH24:MI'),to_date('21-APR-15 09:00','DD-MON-RR HH24:MI'));
  
  COMMIT;
  

  Thank you

  Diana

  Select

  I like order_id

  such as length d

  order_type

  d decode(order_type,'Order1',5,'Order2',8)

  overtime

  of glas_order o

  model

  Reference r on

  (select

  WERKDAG w

  begin_tijd b

  e eind_tijd

  , (to_date (eind_tijd, 'HH24') - to_date (begin_tijd, 'HH24')) * 24 hard

  of ref_workdays

  where soort_werkdag = "WORKINGDAY")

  dimension (w)

  measures (b, e, hard)

  main m

  partition of (order_id I)

  size of (0 n)

  measures (0d, order_date, order_ready, cast (null as varchar2 (10)) as wday, order_type)

  iterate (1e6) rules until (iteration_number > = trunc(order_ready[0]) - trunc(order_date[0])))

  WDAY [0] = to_char (order_date [0] + iteration_number, 'FMDay', 'NLS_DATE_LANGUAGE = ENGLISH')

  , d [0] = d [0] +.

  case

  When trunc(order_date[0]) = trunc(order_ready[0]) - beginning and ready same day

  then presentv (r.b [wday [0]],)

  less (largest (order_ready [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')), to_date (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))

  -bigger (to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI'), least (order_date [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))))

  0) * 24

  When order_date [0] + iteration_number = order_date [0] - first day

  then presentv (r.b [wday [0]],)

  TO_DATE (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]], 'YYYYMMDDHH24:MI')

  -bigger (order_date [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]],'YYYYMMDDHH24:mi'))))

  0) * 24

  When trunc(order_date[0]) + iteration_number = trunc(order_ready[0]) - last day

  then presentv (r.b [wday [0]],)

  less (order_ready [0], to_date (to_char (order_ready [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))

  -to_date (to_char (order_ready [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')

  0) * 24

  of another nvl (r.dur [wday [0]], 0)

  end

  )

  ORDER_ID	DURATION	ORDER_TYPE	OVERTIME
  1	11	Order1	6
  2	22	Order1	17
  3	10	Order2	2

  Rewrittten party rules for readability purposes (more resources)

  measures (0d, order_date, order_ready, cast (null as varchar2 (10)) as to_date (null), (null) to_date, bd, order_type, wday ed)

  iterate (1e6) rules until (iteration_number > = trunc(order_ready[0]) - trunc(order_date[0])))

  WDAY [0] = to_char (order_date [0] + iteration_number, 'FMDay', 'NLS_DATE_LANGUAGE = ENGLISH')

  , comics [0] = to_date (to_char (order_date [0] + iteration_number, 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')

  , ed [0] = to_date (to_char (order_date [0] + iteration_number, 'YYYYMMDD') | r.e [WDAY [0]], 'YYYYMMDDHH24:MI')

  , d [0] = d [0] +.

  case

  When trunc(order_date[0]) = trunc(order_ready[0]) - beginning and ready same day

  then presentv (r.b [wday [0]],)

  less (largest (order_ready [0], [0] bd), ed [0])

  -Greatest (BD [0], least(ORDER_DATE[0],ED[0]))

  0) * 24

  When order_date [0] + iteration_number = order_date [0] - first day

  then presentv (r.b [wday [0]],)

  ED [0]

  -Greatest(ORDER_DATE[0],BD[0])

  0) * 24

  When trunc(order_date[0]) + iteration_number = trunc(order_ready[0]) - last day

  then presentv (r.b [wday [0]],)

  least(order_ready[0],ED[0])

  -bd [0]

  0) * 24

  of another nvl (r.dur [wday [0]], 0)

  end

  )

  Jubilee should be Saturday I guessed.