Help!  Calculate a percentage between two fields that the sum of columns

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• line set between two icons on the toolbar.

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  11.1 and especially you have virtual column

  SQL> create table t
    2  (
    3     a number
    4   , b number
    5   , c generated always as (a+b) virtual
    6  );
  
  Table created.
  
  SQL> insert into t (a, b) values (1, 2);
  
  1 row created.
  
  SQL> select * from t;
  
           A          B          C
  ---------- ---------- ----------
           1          2          3
  

  Before that, a front insert - trigger

  SQL> create table t
    2  (
    3     a number
    4   , b number
    5   , c number
    6  );
  
  Table created.
  
  SQL> create or replace trigger t_default before insert on t for each row
    2  begin
    3    :new.c := :new.a+:new.b;
    4  end;
    5  /
  
  Trigger created.
  
  SQL> insert into t (a, b) values (1, 2);
  
  1 row created.
  
  SQL> select * from t;
  
           A          B          C
  ---------- ---------- ----------
           1          2          3
  

• I subscribe to the student package and I also received a confirmation SMS saying that the sum was deducted. But when I connect through creative cloud, it shows that I'm still working on a trial version. Why is this?

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• Help! Static route between two router WRT160NL

  Hi all

  I have my internet connection to connect to my main router from Linksys WRT160NL (192.168.1.1) with 192.168.1.x.

  My 2nd Linksys router to connect to the first gateway as well.
  The 2nd router has the ip 192.168.1.100 WAN and it's a local subnet as 192.168.2.x.

  My 192.168.2.x machines can access the internet and connect to all the machines in the network 192.168.1.x.

  However, the 1.x network cannot access the machines on the network of the 2. And because of that, I can't share or print between two networks.

  I try to add static routes on my main router (192.168.1.1) with the road: 192.168.2.0 mask 255.255.255.0 and default gateway 192.168.1.100

  However, the road does not work yet.

  in any case to ensure that the 1.x network able to access the network 2.x and 2.x access 1.x file and print sharing.

  Thanks for your help!

  Gateway of the router does NAT who made the side inaccessible side LAN WAN, unless you configure port forwarding automatic or similar. If she would not make your LAN 192.168.1 would be accessible from the internet. Static routing will not change that.

  You will need to disable NAT (aka switch to router mode) on the second router. You must configure a static route on the main router then. However, most likely your network 192.168.2 * will not have Internet more because the main router will NAT for 192.168.1. * and no 192.168.2. *.

  If possible set up the second router as access point only and run a LAN.

• How to stop the connectivity between two computers that use the same IP address... ?

  Today, I managed to connect two computers with the same IP address. But now it is to be feared. for example, a person can access my computers using my IP and MAC address. So now, how can I stop the connectivity between these two computers. should what setting I use to stop.

  Tahnks.

  Hello

  1 have. what measures you taken to connect 2 computers with the same IP address?

  2. How are the 2 computers connected?

  3. how exactly you want to stop the connectivity between 2 computers?

  I want to tell you that 2 computers on the same network cannot have the same address. Each machine must have a unique address to identify it. A private network, as a home network connected to the internet, can be connected to a router to connect to the network, will have only 1 address, public IP address.

  In addition, if we know the IP address of a computer along the user ID and password, we can access the computer/shared files.

   
  If you are referring to the change of the IP address of the two computers, you can follow these steps and check.
   
  a. network connections open. Click the Start button, and then click Control Panel. In the search box, type 'adapter' and then, under center network and sharing, click view network connections.
  b. right click on the connection you want to change. Click on properties. If you are prompted for an administrator password or a confirmation, type the password or provide confirmation.
  c. click on the network tab. Under this connection uses the following items, click Internet Protocol Version 4 (TCP/IPv4) or Internet Protocol Version 6 (TCP/IPv6), and then click the properties button. To specify your IP for IPv4, click on use the following IP address, and then, at the address IP, subnet mask, and gateway boxes by default, type IP address settings.
   
  A typical IPv4 address looks like 192.168.0.2; a typical subnet mask is 255.255.255.0. The default gateway is usually the address of your router.
  For example, IP address: 192.168.0.2 by 192.168.0.12 (for computers)
  Subnet mask: 255.255.255.0
  DNS: 192.168.0.1
   

  I hope this helps. If you have any other queries/issues related to Windows, write us and we will be happy to help you further.

• Select all dates between two fields txt. How?

  In a slider form 6i, I need to select all dates between two dates provided. I have two fields text Fld1 and Chp2 with the data type date. There is no table behind the two fields.
  For example
  ': FLD1: = MARCH 1, 2013;
  ': CHP2: = MARCH 10, 2013;
  
  Now I have to choose all dates between 01-mar-2013 and 2013-mar-10 '. How to do?

  Gul says:
  In a slider form 6i, I need to select all dates between two dates provided. I have two fields text Fld1 and Chp2 with the data type date. There is no table behind the two fields.
  For example
  ': FLD1: = MARCH 1, 2013;
  ': CHP2: = MARCH 10, 2013;

  Now I have to choose all dates between 01-mar-2013 and 2013-mar-10 '. How to do?

  As'salamualikum Gul

  Try this

  SELECT TO_DATE('01-MAR-2013', 'DD-MON-RRRR') - 1 + rownum AS d
  FROM ALL_OBJECTS
  WHERE TO_DATE('01-MAR-2013', 'DD-MON-RRRR') - 1 + rownum BETWEEN TO_DATE('01-MAR-2013', 'DD-MON-RRRR') AND TO_DATE('10-MAR-2013', 'DD-MON-RRRR')
  

  Hope this helps

• Calculate business hours between two dates in a cursor

  Hello, its me again (?).
  
  Yesterday, I got a solution to a problem here where I need to calculate the hours between two dates, excluding Sat/Sun and from 09:00 to 18:00. I'm now putting this login in a PL/SQL block, so I can calculate it for each record in a slider, all by looping.

  with t (start_date
         ,end_date
         )
  as (select  to_date('22-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') start_dt,
                         to_date('23-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') end_dt
      from dual
     )
  , hrs (dt) as
    (select start_date
     from   t
     union all
     select dt +1/24/60
     from   hrs
     where  hrs.dt < (select end_date-1/24/60 from t)
    )
  select count(*)/60
  from hrs
  where to_char(dt,'dy') not in ('sat','sun')
  and  to_number(to_char(dt,'hh24')) not between 18 and 23
  and  to_number(to_char(dt,'hh24')) not between 0 and 8
  /

  The logic above, I'm up here:

  FOR c_record IN c_1 LOOP
  //For each record, check if the two dates meet the criteria and then raise the counters accordingly
  select  to_date(c_record.REPORTADA,'dd-mon-yyyy hh24:mi:ss') INTO vFch1 FROM DUAL;
  SELECT  to_date(c_record.INICIOREAL,'dd-mon-yyyy hh24:mi:ss') INTO vFch2 FROM DUAL;
  
  IF ((vHoras > 2) AND c_record.PRIORIDAD=3) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE 
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END
      IF;
  
  IF ((vHoras > 4) AND c_record.PRIORIDAD=2) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  IF ((vHoras > 16) AND c_record.PRIORIDAD=1) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  END LOOP;

  I really don't like if the performance is horrible because it will run once a month and should spend only 40-100 records.
  However, I can't find a way to use this connection even in this case
  
  Could you help me?
  Thank you!
  
  Greetings,
  NACEUR

  N wrote:
  I need to calculate the number of minutes between two dates, only count the hours from 9 to 18hs.

  CREATE OR REPLACE
    FUNCTION get_bus_minutes_between(
                                     p_start_date DATE,
                                     p_end_date DATE
                                    )
      RETURN NUMBER
      IS
          v_return NUMBER;
      BEGIN
          with t as (
                     select  case level
                               when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                               else trunc(p_start_date) + level - 15 / 24
                             end start_dt,
                             case connect_by_isleaf
                               when 1 then least(p_end_date,trunc(p_end_date) + 18 / 24)
                               else trunc(p_start_date) + level - 8 / 24
                             end end_dt
                       from  dual
                       connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                    )
          select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
            into  v_return
            from  t
            where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
          RETURN v_return;
  END;
  /
  

  For example:

  SQL> select get_bus_minutes_between(
    2                                 to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'),
    3                                 to_date('22-oct-2012 13:21:00','dd-mon-yyyy hh24:mi:ss')
    4                                ) work_minutes
    5    from dual
    6  /
  
  WORK_MINUTES
  ------------
           261
  
  SQL> 
  

  SY.

• Calculation of connection between two fields

  In my PDF, I have two fields - allows you to call the A and B.

  When you enter the number 26 in the to field, B field should automatically generate the value 14 (less than the value in A 12). I managed to get this working.

  However, I wish this works in reverse, so that if you field a number (for example, 3) in the B field, will automatically generate the number 15 (greater than the value of B 12).

  Unfortunately, I can't get either to work, but not both. If I set the to field with the formula, all what I enter in the B field cannot substitute the calculation generated from the value defined in A.

  Any ideas on how I can get this working? Thank you.

  You can use JavaScript in the Calculate of the two fields event.

  For example, in the first field, do something like:

  (function () {
  
      if (event.source && event.source !== event.target) {
          event.value = +getField("text2").value + 12;
      }
  
  })();
  

  and in the other field, use:

  (function () {
  
      if (event.source && event.source !== event.target) {
          event.value = +getField("text1").value - 12;
      }
  
  })();
  

  Change "text2" and "text1" to match the domain names that you use.