difference in hours between two time zones of differnet

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• How to find the hours between two times

  Hai All
  
  I had a problem I need to calculate work time
  
  For example
  
  Respondent outtime
  
  0815 1715
  
  So I need to calculate a time between these two times
  
  How can I do using function for 100 our
  
  Concerning
  
  Srikkanth.M

  Hello

  use the below the update statement.

  update dail_att set wtime =  extract(hour from (to_date(outtime,'HH24:MI')-to_date(intime,'HH24MI')) day to second);
  

  Solution of the sample...

  PRAZY@11gR1> desc dte;
   Name            Null?    Type
   ------------------- -------- --------
   INTIME           VARCHAR2(4)
   OUTTIME        VARCHAR2(4)
   HRS                NUMBER
  
  PRAZY@11gR1> select * from dte;
  
  INTIME     OUTTIME           HRS
  ---------- ---------- ----------
  0815       1715
  0900       1800
  0830       1630
  
  Elapsed: 00:00:00.00
  PRAZY@11gR1> update dte set hrs = extract(hour from(to_date(outtime,'HH24MI')-to_date(intime,'HH24MI')) day to second);
  
  3 rows updated.
  
  Elapsed: 00:00:00.01
  PRAZY@11gR1> select * from dte;
  
  INTIME     OUTTIME           HRS
  ---------- ---------- ----------
  0815       1715                9
  0900       1800                9
  0830       1630                8
  
  Elapsed: 00:00:00.00
  

  Kind regards
  Prazy

  Published by: Prazy on March 24, 2010 12:43

• Calculate elapsed hours between two time fields

  I have a form with fields TimeStart and TimeEnd. Both are formatted as field time in the format hh: mm tt. I also have a field called hours with the number format. Here is the Javascript code that I have in the section calculation Script custom field hours. Could someone tell me why it doesn't work? This script started as a date calculation script (work), and I changed to the calculation of hours instead of days.

  var strStart = this.getField("TimeStart").value;

  var strEnd = this.getField("TimeEnd").value;

  If (strStart.length & & strEnd.length)

  {

  var timeStart = util.scand ("h: mm tt", strStart);

  var timeEnd = util.scand ("h: mm tt", strEnd);

  diff var = timeEnd.getTime () - timeStart.getTime ();

  var hour = 60 * 60 * 1000;

  var h = Math.floor (diff/oneHour);

  Event.Value = hours;

  }

  of another event.value = 0;

  The order for the calculation of the fields is wrong, you need to update.

• Difference between two times

  I am building a working method in LiveCycle, and I want to track how long the procedure takes. To do this, I have two time fields, and then a third time field to find the difference between two time fields. Looking at other posts to discussion, I could find a Javascript code that was part of what I wanted, but I can't get the third time field to display in the format I want. I tried to change the habits of the fields and that did not work. Could someone offer some advice on how to change the format or help me with the code?  I couldn't figure to attach the actual file, but I have attached a picture of the PDF file and the Javascript code I used.  If you look at the TimeIn (hh: mm) and time (hh: mm) areas (on the photo, I have attached), you will notice that the TotalTime comes out like HMM, and I want that it out as hh: mm.

  

  

  Any help would be greatly appreciated!

  Thank you

  this.rawValue = (totalHrs > 9? String (totalHrs): '0' + String (totalHrs)) + ':' + (totalMins > 9? String (totalMins): '0' + String (totalMins));

• Calculate the hours between two dates

  Hello
  
  I have a requirement to count the hours with 2 given timestamps, something like:

  SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;
  
           B
  ----------
          48

  However, I wish it would be that simple. I just need to count the hours between two timestamps for the hours of work for example, 08:00 - 17:00, MONDAY to Friday (excluding weekends).
  So lets say I have to count the hours between two dates above the result should be 18 hours not 48 (4 hours on 20/oct, 9 hours on 21/oct to 5 hours 22/oct).
  How can I achieve this? Any idea will be useful.
  
  Thank you

  My query generates a list of all the hours between the start and end time, filters on the hours that are outside of the hours of work and then account for the remaining lines. Change that to partial hours must just be a case of replace the two occurrences of 1/24 with 24/01/60, then - as say you - Division COUNT (*) by 60.

  There may be performance issues using techniques of generation of line like this, if you put this in a query involving the joining of several lines of other tables (for example where the dates of beginning and end are derived from several employees?) or in several days. If you don't find it then count the number of whole days (taking weekends into account) between dates and work on the partial days after that it could be better. This would probably involve a lot of statements of case (which I don't have time to test it now).

  Ben

• Calculate the difference in days between two Dates

  Hello

  I'm trying to understand how to calculate the difference in days between two dates using JavaScript in LiveCycle. (Minimum = JavaScript knowledge)

  Where 'Start_Date' and 'Current_Date' are the names of the two dates in the palette of the hierarchy. (the two Date/time field)

  * Current date is using the object > value > execution property > current Date/time

  I need a text or number field showing the difference in days. (Difference_in_Days)

  I noticed the following code is pretty standard among other responses:

  var

  Start_date = new Date (Start_Date);

  var

  Current_Date = new Date (Current_Date);

  var

  nAgeMilliseconds = Current_Date.getTime) - Start_date.getTime ();

  var

  nMilliSecondsPerYear = 365 * 24 * 60 * 60 * 1000 ;

  I know there is lack of code and code above are may not be not correct.

  Please notify.

  OK, that's because of the way that javascript and works of the calculate event.  The field will be filled with whatever the script resolves at the end of execution. Technically, your script does not have a value because the last thing you do is an assignment to a variable.  Change the last line as follows:

  Math.ABS ((firstDate.getTime)

  ((- secondDate.getTime (()) / (oneDay));

  (eliminate the variable assignment) and get rid of the app.alert.  Your script will "return" (have) regardless of the value of calculation from the East and which will be stored in the field.

• How to make the difference in percentage between two matrices?

  Hello everyone, I just want to ask how to make the difference in percentage between two binary matrices. This is to compare two images converted to matrices in LabView. Thank you.

  Well, in the current image interesting pixels are zero in the reference image. Here is a small example that would take all the zero 100% pixel, then look at the pixels of same in the other image to see how are always 0.

  Modify if needed.

  

• Calculate business hours between two dates in a cursor

  Hello, its me again (?).
  
  Yesterday, I got a solution to a problem here where I need to calculate the hours between two dates, excluding Sat/Sun and from 09:00 to 18:00. I'm now putting this login in a PL/SQL block, so I can calculate it for each record in a slider, all by looping.

  with t (start_date
         ,end_date
         )
  as (select  to_date('22-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') start_dt,
                         to_date('23-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') end_dt
      from dual
     )
  , hrs (dt) as
    (select start_date
     from   t
     union all
     select dt +1/24/60
     from   hrs
     where  hrs.dt < (select end_date-1/24/60 from t)
    )
  select count(*)/60
  from hrs
  where to_char(dt,'dy') not in ('sat','sun')
  and  to_number(to_char(dt,'hh24')) not between 18 and 23
  and  to_number(to_char(dt,'hh24')) not between 0 and 8
  /

  The logic above, I'm up here:

  FOR c_record IN c_1 LOOP
  //For each record, check if the two dates meet the criteria and then raise the counters accordingly
  select  to_date(c_record.REPORTADA,'dd-mon-yyyy hh24:mi:ss') INTO vFch1 FROM DUAL;
  SELECT  to_date(c_record.INICIOREAL,'dd-mon-yyyy hh24:mi:ss') INTO vFch2 FROM DUAL;
  
  IF ((vHoras > 2) AND c_record.PRIORIDAD=3) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE 
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END
      IF;
  
  IF ((vHoras > 4) AND c_record.PRIORIDAD=2) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  IF ((vHoras > 16) AND c_record.PRIORIDAD=1) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  END LOOP;

  I really don't like if the performance is horrible because it will run once a month and should spend only 40-100 records.
  However, I can't find a way to use this connection even in this case
  
  Could you help me?
  Thank you!
  
  Greetings,
  NACEUR

  N wrote:
  I need to calculate the number of minutes between two dates, only count the hours from 9 to 18hs.

  CREATE OR REPLACE
    FUNCTION get_bus_minutes_between(
                                     p_start_date DATE,
                                     p_end_date DATE
                                    )
      RETURN NUMBER
      IS
          v_return NUMBER;
      BEGIN
          with t as (
                     select  case level
                               when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                               else trunc(p_start_date) + level - 15 / 24
                             end start_dt,
                             case connect_by_isleaf
                               when 1 then least(p_end_date,trunc(p_end_date) + 18 / 24)
                               else trunc(p_start_date) + level - 8 / 24
                             end end_dt
                       from  dual
                       connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                    )
          select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
            into  v_return
            from  t
            where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
          RETURN v_return;
  END;
  /
  

  For example:

  SQL> select get_bus_minutes_between(
    2                                 to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'),
    3                                 to_date('22-oct-2012 13:21:00','dd-mon-yyyy hh24:mi:ss')
    4                                ) work_minutes
    5    from dual
    6  /
  
  WORK_MINUTES
  ------------
           261
  
  SQL> 
  

  SY.

• find the difference in days between two dates

  Hello world
  
  I'm trying to find out the difference in days between two dates and the execution of the query that I'm passing
  
  SELECT TO_char(sysdate, 'dd/mm/yyyy') - TO_char('15/11/2011', 'dd/mm/yyyy') DAYS FROM DUAL
  
  the error I get is
  
  ORA-01722: invalid number
  01722 00000 - "invalid number."
  * Cause:
  * Action:
  
  Could someone please help.
  
  Thanks in advance

  user10636796 wrote:
  Hello world

  Thanks a lot for all the replies. I am trying to apply it in a statement to my table like this

  SELECT trunc (sysdate) - TO_char (date_last_recommended, ' dd/mm/yyyy') DAYS OF recommendation;

  SELECT trunc (sysdate) - TRUNC (date_last_recommended) DAYS OF recommendation;

• Formula of FormCalc to make the difference between two time fields if they are populated - help please

  
  Hello

  I have a laptop (TotalTime1) which refers to two other cells in the updated hour-shaped (Start1 and 1 to finish).

  The formula below is intended to make the difference between the time of departure and of arrival if they are populated.

  I had to work unconditionally HasValue, but the formula was calculated when there is no value in the Start1 and Finish1 (due to the time format).

  This is the code I have, it is said that there is an error of almost the last line; I'm sorry if I'm posting this in the wrong way, I haven't posted on this forum before but this is:

  If (HasValue (Finish1) and HasValue (Start1)) then if (Time2Num (Start1.formattedValue, "HH: mm") < Time2Num (Finish1.formattedValue, "Hh: mm")) then Abs (Time2Num (Start1.formattedValue, "HH: mm")-Time2Num (Finish1.formattedValue, "HH: mm")) / (60 * 60 * 1000) another 24 - ABS (Time2Num (Finish1.formattedValue, "HH: mm")-Time2Num (Start1.formattedValue, "HH: mm")) / (60 * 60 * 1000) endif

  Any help would be appreciated.

  Cordially Fetachini

  you need an another endif at the end (you have nested statement and only 1 endif)

• calculation of time between two time as timestamp

  How can calculate two hour, START as the timestamp TIME in the data type, END TIME as of time also.

  select END_TIME-START_TIME from PROG_DLY_WORK
  

  Result

  + 01:50:00.000000 000000000

  How can get exactly the time spent as 01:50 ? and these calculated time must sum (elapsed_time) in another column.

  oracle as PaaS cloud environment

  Product	VERSION	STATUS
  NLSRTL	11.2.0.3.0	Production
  Oracle Database 11g Enterprise Edition	11.2.0.3.0	64 bit Production
  PL/SQL	11.2.0.3.0	Production
  AMT for Linux:	11.2.0.3.0	Production

  Time difference between two columns in hours

  Start

  FOR REC IN (SELECT START_TIME, END_TIME, CALC_TIME CAL_ID)

  LOOP

  UPDATE CALc_TIME

  SET ELAPSED_TIME = round (())

  TO_DATE (to_char (REC. End_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")-

  TO_DATE (to_char (REC. Start_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")

  () * 24).

  WHERE CAL_ID = REC. CAL_ID;

  END LOOP;

  end;

  Lag in minutes

  Start

  FOR REC IN (SELECT START_TIME, END_TIME, CALC_TIME CAL_ID)

  LOOP

  UPDATE CALc_TIME

  SET ELAPSED_TIME = round (())

  TO_DATE (to_char (REC. End_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")-

  TO_DATE (to_char (REC. Start_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")

  () * 24 * 60)

  WHERE CAL_ID = REC. CAL_ID;

  END LOOP;

  end;

• Count the hours between the times of the day

  Hello

  It is a timesheet, calculation of payment:

  I'm trying to find a way to calculate how many hours is between two specific times of the day.

  I enter a start time and an end time (in 2 different items), I calculate the number of hours that is. What I can understand.

  Then I need to know how many hours is between 16:00 and 22:00.

  The reason is that there is an additional extra payment for those hours.

  So: "payment on time' X ' total hours work in a day ' + 'bonus' X ' hours between 16 and 22" = "total wages for a day" "»

  Thank you

  

  Enter the full date and time in columns A and B (for example ' 12 Sep 2016 8:00 AM "or you like the what ever valid date time value):

  C2 = B2−A2

  D2 = C2−DURATION (0, 0, 24 × MAX (TIMEVALUE "(04:00 PM)") −TIMEVALUE (A2), 0)) −DURATION (0, 0, 24 × MAX (TIMEVALUE (B2) −TIMEVALUE (' 22:00 "" "), 0))

  Select cells C2 and D2, copy

  Select cells C2 at the end of column D, dough

  If you prefer the values in column D as decimal hours use the formula:

  dur2hours (D2)

  or replace the formula earlier as follows:

  D2 = dur2hours (C2−DURATION (0, 0, 24 × MAX (TEMPSVAL ("04:00 PM") −TIMEVALUE (A2), 0)) −DURATION (0, 0, 24 × MAX (TIMEVALUE (B2) −TIMEVALUE (' 22:00 "" "), 0)))

• How to calculate the hours between two dates by the numbers

  If I update 09:00 start time 17:00 end time of shift in C3 and B3, how to use a D3 formula to calculate the number of hours between the two?  Then I can just copy down the lines for nth years...

  It is a spreadsheet of the part-time staff payroll.

  I'm sure that a lot of people out there have done that.

  Help, please.

  Thank you.

  Eddie

  What program of worksheet that you are using? Since you have a newer iMac running El Capitan, I can safely assume that you use NOT AppleWorks, which is a Power PC application that can run on any OS newer than the snow leopard, OS X 10.6.8.

  If you use numbers, try to repost your question in numbers for Mac forum. If you use Microsoft Excel, try posting in the Microsoft forums. LibreOffice also has community support.

• How to find the difference "within weeks" between two date values?

  Hi all

  Jdev version 11.1.1.7.1

  I used two < af:inputDate > & a < af:inputText > < af:panelFormLayout > components. My requirement is, I want to display the difference of weeks between these two day values in the inputText component when the user clicks the shape.

  Any suggestion would be appreciated.

  Kind regards

  
  

  Novel

  You can use this method to get the number of days between the day and date, and then divided by 7 to get the number of weeks

  public static long getDifferenceDaysBetweenTwoDates (d1, d2 oracle.jbo.domain.Date oracle.jbo.domain.Date)

  {

  If (d1! = null & d2! = null)

  {

  return (d1.getValue () .getTime () - d2.getValue () .getTime ()) / (24 * 60 * 60 * 1000);

  }

  return 0;

  }

  Check - http://sameh-nassar.blogspot.in/2014/10/dealing-with-dates-in-java.html

  Ashish

• Calculations between two time fields

  Hello

  I have a form with a time for the start time field and a text field for the user to enter a duration (for example, 00:30:00).

  There is another field for the end of time (which has a calculation script using the date and starting time fields).

  The script that was placed in the end time field works except the script gives a negative result.

  For example the start time field is 16:03:33 and 00:30:00 duration field calculation end is showing time field-

  Please can someone advise how I can change the script of the time field end to show the correct result of 16:33 (without the negative)?

  
  create string for the current date
  var oToday = new Date();
  sToday var = util.printd ("yyyy/mm/dd", oToday);

  get the value of the start time field

  var sStart = this.getField("Action_Start_Time").value;

  create the JavaScript date object time for start time
  var start = util.scand ("yyyy/mm/dd hh: mm:", sToday + sStart);

  
  get the duration value

  Send var = this.getField("Action_Time").value;

  create a JavaScript date object time to end time
  oEnd var = util.scand ("yyyy/mm/dd hh: mm", sToday + shipment);

  calculate the difference in hours, the difference in hours
  var DiffHours = (oEnd.valueOf () - oStart.valueOf (()) / 1000 / 60 / 60;
  Event.Value = Math.floor (DiffHours) + ': ' + util.printf ("%,302.0f", (((DiffHours % 1) * 60) .toFixed (()));

  Any help will be greatly appreciated.

  You cannot change the '-' operator operator '+' being Modulo calculation date and time calculations. You must calculate the different parts of the date and time of the start time and elapsed time and then convert these values into a date object time and format of this new date time object.

  Clear the field
  Event.Value = "";
  getting the activity start time
  var sEventStart = this.getField("Activity_Start_Time").value;
  calculate only if there is a start time
  If (sEventStart! = "") {}
  operations of the console are for debugging and illustration
  /*
  Console.Show ();
  Console.clear();
  */
  convert a date object change if necessary format
  var oEventStart = util.scand ("YYYY, mm, DD, HH", nNowYear + "," + (nNowMonth + 1) + ',' + nNowDate + ', ' + sEventStart);
  Console.println ("oEventStart:" + oEventStart);

  get the date current time
  var oNow = new Date();
  Console.println ("oNow:" + oNow);
  get the date parts
  var nNowYear = oNow.getFullYear ();
  var nNowMonth = oNow.getMonth ();
  var nNowDate = oNow.getDate ();
  /*
  Console.println ("nNowYear:" + nNowYear);
  Console.println ("nNowMonth:" + nNowMonth);
  Console.println ("nNowDate:" + nNowDate);
  */
  get the duration of activity
  var sEventDuration = this.getField('Event_Duration').value;
  If no entry in force at time zero
  if(sEventDuration == '') sEventDuration = "00:00:00 ';
  convert the time in hours and minutes
  var aEventDuration = sEventDuration.split(":");
  /*
  Console.println (' hours - aEventDuration [0]: "+ aEventDuration [0]");
  Console.println ('Minutes - aEventDuration [1]: "+ aEventDuration [1]");
  Console.println (' hours start: "+ oEventStart.getHours ());
  Console.println ("minutes:" + oEventStart.getMinutes ());
  Console.println ("second Start:" + oEventStart.getSeconds ());
  */
  calculate the minutes and the end times
  var nEndHour = Number (oEventStart.getHours ()) + Number(aEventDuration[0]);
  var nEndMinute = Number (oEventStart.getMinutes ()) + Number(aEventDuration[1]);
  if(aEventDuration.Length == 3)
  var nEndSecond = Number (oEventStart.getSeconds ()) + Number(aEventDuration[2]);
  on the other
  var nEndSecond = Number (oEventStart.getSeconds () + 0;
  /*
  Console.println ("nEndHour:" + nEndHour);
  Console.println ("nEndMinute:" + nEndMinute);
  Console.println ("nEndSecond:" + nEndSecond);
  Console.println ("nNowYear:" + nNowYear);
  Console.println ("nNowMonth:" + nNowMonth);
  Console.println ("nNowDate:" + nNowDate);
  */
  do the date for the end of the event object - calculate the hours and minutes
  oEnd var = new Date (nNowYear, nNowMonth, nNowDate, nEndHour, nEndMinute, nEndSecond);
  Console.println ('oEnd: ' + oEnd);
  change the format if necessary
  Event.Value = util.printd ("HH", oEnd);
  } / / end of event time