Calculations between two time fields

Similar Questions

• Formula of FormCalc to make the difference between two time fields if they are populated - help please

  
  Hello

  I have a laptop (TotalTime1) which refers to two other cells in the updated hour-shaped (Start1 and 1 to finish).

  The formula below is intended to make the difference between the time of departure and of arrival if they are populated.

  I had to work unconditionally HasValue, but the formula was calculated when there is no value in the Start1 and Finish1 (due to the time format).

  This is the code I have, it is said that there is an error of almost the last line; I'm sorry if I'm posting this in the wrong way, I haven't posted on this forum before but this is:

  If (HasValue (Finish1) and HasValue (Start1)) then if (Time2Num (Start1.formattedValue, "HH: mm") < Time2Num (Finish1.formattedValue, "Hh: mm")) then Abs (Time2Num (Start1.formattedValue, "HH: mm")-Time2Num (Finish1.formattedValue, "HH: mm")) / (60 * 60 * 1000) another 24 - ABS (Time2Num (Finish1.formattedValue, "HH: mm")-Time2Num (Start1.formattedValue, "HH: mm")) / (60 * 60 * 1000) endif

  Any help would be appreciated.

  Cordially Fetachini

  you need an another endif at the end (you have nested statement and only 1 endif)

• Calculate elapsed hours between two time fields

  I have a form with fields TimeStart and TimeEnd. Both are formatted as field time in the format hh: mm tt. I also have a field called hours with the number format. Here is the Javascript code that I have in the section calculation Script custom field hours. Could someone tell me why it doesn't work? This script started as a date calculation script (work), and I changed to the calculation of hours instead of days.

  var strStart = this.getField("TimeStart").value;

  var strEnd = this.getField("TimeEnd").value;

  If (strStart.length & & strEnd.length)

  {

  var timeStart = util.scand ("h: mm tt", strStart);

  var timeEnd = util.scand ("h: mm tt", strEnd);

  diff var = timeEnd.getTime () - timeStart.getTime ();

  var hour = 60 * 60 * 1000;

  var h = Math.floor (diff/oneHour);

  Event.Value = hours;

  }

  of another event.value = 0;

  The order for the calculation of the fields is wrong, you need to update.

• Difference between two times

  I am building a working method in LiveCycle, and I want to track how long the procedure takes. To do this, I have two time fields, and then a third time field to find the difference between two time fields. Looking at other posts to discussion, I could find a Javascript code that was part of what I wanted, but I can't get the third time field to display in the format I want. I tried to change the habits of the fields and that did not work. Could someone offer some advice on how to change the format or help me with the code?  I couldn't figure to attach the actual file, but I have attached a picture of the PDF file and the Javascript code I used.  If you look at the TimeIn (hh: mm) and time (hh: mm) areas (on the photo, I have attached), you will notice that the TotalTime comes out like HMM, and I want that it out as hh: mm.

  

  

  Any help would be greatly appreciated!

  Thank you

  this.rawValue = (totalHrs > 9? String (totalHrs): '0' + String (totalHrs)) + ':' + (totalMins > 9? String (totalMins): '0' + String (totalMins));

• calculation of time between two time as timestamp

  How can calculate two hour, START as the timestamp TIME in the data type, END TIME as of time also.

  select END_TIME-START_TIME from PROG_DLY_WORK
  

  Result

  + 01:50:00.000000 000000000

  How can get exactly the time spent as 01:50 ? and these calculated time must sum (elapsed_time) in another column.

  oracle as PaaS cloud environment

  Product	VERSION	STATUS
  NLSRTL	11.2.0.3.0	Production
  Oracle Database 11g Enterprise Edition	11.2.0.3.0	64 bit Production
  PL/SQL	11.2.0.3.0	Production
  AMT for Linux:	11.2.0.3.0	Production

  Time difference between two columns in hours

  Start

  FOR REC IN (SELECT START_TIME, END_TIME, CALC_TIME CAL_ID)

  LOOP

  UPDATE CALc_TIME

  SET ELAPSED_TIME = round (())

  TO_DATE (to_char (REC. End_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")-

  TO_DATE (to_char (REC. Start_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")

  () * 24).

  WHERE CAL_ID = REC. CAL_ID;

  END LOOP;

  end;

  Lag in minutes

  Start

  FOR REC IN (SELECT START_TIME, END_TIME, CALC_TIME CAL_ID)

  LOOP

  UPDATE CALc_TIME

  SET ELAPSED_TIME = round (())

  TO_DATE (to_char (REC. End_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")-

  TO_DATE (to_char (REC. Start_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")

  () * 24 * 60)

  WHERE CAL_ID = REC. CAL_ID;

  END LOOP;

  end;

• How to find the hours between two times

  Hai All
  
  I had a problem I need to calculate work time
  
  For example
  
  Respondent outtime
  
  0815 1715
  
  So I need to calculate a time between these two times
  
  How can I do using function for 100 our
  
  Concerning
  
  Srikkanth.M

  Hello

  use the below the update statement.

  update dail_att set wtime =  extract(hour from (to_date(outtime,'HH24:MI')-to_date(intime,'HH24MI')) day to second);
  

  Solution of the sample...

  PRAZY@11gR1> desc dte;
   Name            Null?    Type
   ------------------- -------- --------
   INTIME           VARCHAR2(4)
   OUTTIME        VARCHAR2(4)
   HRS                NUMBER
  
  PRAZY@11gR1> select * from dte;
  
  INTIME     OUTTIME           HRS
  ---------- ---------- ----------
  0815       1715
  0900       1800
  0830       1630
  
  Elapsed: 00:00:00.00
  PRAZY@11gR1> update dte set hrs = extract(hour from(to_date(outtime,'HH24MI')-to_date(intime,'HH24MI')) day to second);
  
  3 rows updated.
  
  Elapsed: 00:00:00.01
  PRAZY@11gR1> select * from dte;
  
  INTIME     OUTTIME           HRS
  ---------- ---------- ----------
  0815       1715                9
  0900       1800                9
  0830       1630                8
  
  Elapsed: 00:00:00.00
  

  Kind regards
  Prazy

  Published by: Prazy on March 24, 2010 12:43

• Week, month, quarter and year calculation between two days with a quantity?

  I have a problem that I can't solve.
  
  Users enter a forecast (quantity) and a validity period between two dates.
  Expected quantity is always a monthly forecast.
  
  The problem is that the user wants to see the forecast by week, month, quarter and year.
  
  
  Material |     Quantity |     Date_from | Date_to
  Label45 |     1500 |     2009-09-01 | 2009-12-31
  
  
  How can I easily calculate the amount so that the user can enter e.g. week 2009.41 and see the forecast this week?

  You should test for your specific environment, but I would be very surprised if a function has surpassed SQL directly.

• difference in hours between two time zones of differnet

  I have a sysdate (EAST) and a function util_pkg.local_tz returns a different datetime value.
  I need to get the difference in hours between sysdate and another date.
  
  Select sysdate, util_pkg.local_tz (sysdate, ' Asia/Seoul') of double;
  
  18/05/2011 11:15:00.000000000 FROM 18/05/2011 10:15 PM + 09:00
  
  Quest:-find the difference in hours between these two date and then add the difference of hours + sysdate
  
  

  FUNCTION local_tz (p_datetime IN TIMESTAMP,
                        p_timezone IN VARCHAR2)
        RETURN TIMESTAMP WITH TIME ZONE
     AS
     BEGIN
        RETURN FROM_TZ(p_datetime, TZ_OFFSET(con_database_timezone))
                       AT TIME ZONE TZ_OFFSET(p_timezone);
     END local_tz;

  When you calculate the diff between TIMESTAMP WITH TZ they both are converted to time UTC (in fact they are stored as UTC). So diff between SYSTIMESTAMP in EST and SYSTIMESTAMP in Seoul will always be 0, as bioth are "now". You need to cast TIMESTAMP WITH TZ 'losing' time zone timestamp:

  SQL> select cast(systimestamp at time zone 'Asia/Seoul' as timestamp) - systimestamp from dual;
  
  CAST(SYSTIMESTAMPATTIMEZONE'ASIA/SEOUL'ASTIMESTAMP)-SYSTIMESTAMP
  ---------------------------------------------------------------------------
  +000000000 13:00:00.000000
  
  SQL>  
  

  SY.

• How to calculate the difference between two times by the NUMBERS

  I'm so bothered by the fact that I can't understand that.

  Cell B2 - 08:00

  Cell C2 - 10:50

  (How can cell D2 - I get this cell to calculate the difference and say 02:50?)

  I know it's probably one of the most basic operations, but for the life of me I can't understand it. The cells B2 and C2 are formatted for a 24-hour clock. But if I tell the system to just subtract the two, I get "0,118. Everything I find on the forum search goes beyond what I need. Can someone help me?

  Thank you

  Hi sapirs,

  Departure and arrival of the cells are in Date and time with Date format: no and time: 24-hour clock.

  

  Formula in D2 (fill down)

  = C2−B2

  

  The results become a duration format, but under automatic (numbers automatically worth this format)

  

  If you wish, you can change the cells of lasting results.

  What Data Format have your result cells?

  Kind regards

  Ian.

• calculations between two values of the sequential loop iterations

  Hi all

  I have a code that came out our power (DSP) of a FFT spectral density. An input frequency and then intervened at a value of input from the user. I would like to know the difference of the PSD between each stage of the frequency. Attached, that's what I would get. To avoid confusion, I don't want to produce a file that looks like this. I want just the column 'delta' as an indicator on the front panel, so I can control my change in PSD. I don't need the entire table, just the delta between the current iteration and the previous iteration. I tried to use a loop with shift registers, but I'm not sure where to go to from there. I thought that, since the shift registers sends the data of loop to loop, that I could output the value before it went into the next iteration, but I don't have a chance. Any help is appreciated. Unfortunately, I am unable to put the code due to the policy of the company. I know it makes things much more difficult.

  Thank you.

  Suggestions do not seem quite right, but I found a way to do it. Attached, is the way that I did.

• calculation between two columns that depends on the minimum value

  I have the table with the following values, how can auto calculation based to a minimum value to assign each line then?

  Seq 1	reference ID	price	price of the difference	% of difference
  1	3	1500
  2	3	3500
  3	3	4000

  
  

  calculation logic

  
  

  
  

  the result should be...

  Seq 1	reference ID	price	price of the difference	% of difference
  1	3	1500	0	0
  2	3	3500	2000	1.333
  3	3	4000	2500	1,666

  Dev environment

  service of Cloud Computing by oracle

  PRODUCT	VERSION	STATUS
  NLSRTL	11.2.0.3.0	Production
  Oracle Database 11g Enterprise Edition	11.2.0.3.0	64 bit Production
  PL/SQL	11.2.0.3.0	Production
  AMT for Linux:	11.2.0.3.0	Production

  with

  a_table as

  (select 1 seq_1, 3 ref_id, 1500 Union double all the)

  Select 2,3,3500 from all the double union

  Select double 3,3,4000

  )

  Select seq_1, ref_id, price,

  price - min (price) on differece_price (partition by ref_id by seq_1 order),

  price / min (price) over (partition by seq_1 order ref_id) - 1 difference_percent

  of a_table

  SEQ_1	REF_ID	PRICE	DIFFERECE_PRICE	DIFFERENCE_PERCENT
  1	3	1500	0	0
  2	3	3500	2000	1.33333333333333333333333333333333333333
  3	3	4000	2500	1.66666666666666666666666666666666666667

  Concerning

  Etbin

• HOW TO USE BETWEEN TWO TIMES

  CREATE TABLE HH (HELLO NUMBER (10));
  
  DATA TABLE 1,2,3,4,5,6 HH... 30
  
  NOTE: NOT USED UNIOUN FUNCTION
  
  NEED TO OUTPUT
  -------------
  DISPLAYED 10 > = HELLO AND HELLO < = 15 AND
  20 > = HELLO AND HELLO < = 25
  
  
  PLEASE GIVE ME THE QUREY
  
  
  
  
  
  I AM USNIG THIS QUERY-> NO RESULTS COME
  -----------------------
  SELECT * HELLO WHERE BETWEEN 10 AND 15 HH
  AND HELLO BETWEEN 20 AND 25

  Please do not write in all caps: this is considered a bad practice in a forum.

  You use OR instead of AND:

  select * from hh
  where hello between 10 and 15 or hello between 20 and 25;
  

• Problem with difference of calculation between two dates from Monday to Saturday

  Hello

  I need help to change a function return number you dates, including Saturday hours (09:00 - 14:00), Monday to Friday (09:00 - 21:00);

  This is my code;

  CREATE OR REPLACE
  FUNCTION TEST2 (FECHA_INICIO DATE, DATE FECHA_FIN)

  RETURN NUMBER IS THE NUMBER OF HORASTOTALES;
  date the date;
  
  BEGIN
  If)
  SELECT date, to_char (date, 'DY', 'NLS_DATE_LANGUAGE = ENGLISH') dia.
  (SELECT to_date('FECHA_INICIO') + LEVEL - 1 date
  OF THE DOUBLE
  CONNECT BY LEVEL < = (FECHA_FIN - FECHA_INICIO))
  WHERE TO_CHAR (DATE, 'DY', 'NLS_DATE_LANGUAGE = ENGLISH') not IN ("SAT") THEN
  
  with t as)
  
  SELECT CASE LEVEL
  When 1 then greatest (fecha_inicio, trunc (fecha_inicio) + 9 / 24)
  to another level - 15 + trunc (fecha_inicio) / 24
  end fecha_inicio
  case connect_by_isleaf
  When 1 then least (fecha_fin, trunc (fecha_fin) + 21 / 24)
  Another trunc (fecha_inicio) + level - 3 / 24
  end fecha_fin
  of the double
  
  connect by level < = trunc (fecha_fin) - trunc (fecha_inicio) + 1).
  
  Select sum (more large (fecha_fin - fecha_inicio, 0)) * 24 horas
  in horastotales
  T
  
  WHEN TRUNC (FECHA_INICIO) - TRUNC (FECHA_INICIO, 'iw') < 5;
  
  RETURN HORASTOTALES;
  
  ) ELSE IF
  Return HORASTOTALES + 5;
  END;

  concerning

  Hello again,

  Using this function, which makes me ask properly, what hours, my problem is that I can not include Saturday hours;

  create or replace FUNCTION TEST (FECHA_INICIO DATE, FECHA_FIN DATE

  )

  RETURNS the NUMBER IS horastotales NUMBER;

  BEGIN

  with t as)

  SELECT CASE LEVEL

  When 1 then greatest (fecha_inicio, trunc (fecha_inicio) + 9 / 24)

  to another level - 15 + trunc (fecha_inicio) / 24

  end fecha_inicio

  case connect_by_isleaf

  When 1 then least (fecha_fin, trunc (fecha_fin) + 21 / 24)

  Another trunc (fecha_inicio) + level - 3 / 24

  end fecha_fin

  of the double

  connect by level<= trunc(fecha_fin)="" -="" trunc(fecha_inicio)="" +="">

  )

  Select sum (more large (fecha_fin - fecha_inicio, 0)) * 24 horas

  in horastotales

  T

  When TRUNC (FECHA_INICIO) - TRUNC (FECHA_INICIO, 'iw')<>

  RETURN horastotales;

  END;

  Example:

  SELECT TEST (TO_DATE (January 7, 2013 09:10 ',' DD-MM-YYYY HH24 '), TO_DATE (February 7, 2013 09:00 "," DD-MM-YYYY HH24 ')) horas

  OF THE DOUBLE

  output: 11, 8 hours

  Then try to add parts of your function, to get what I want, but it gives me compilation errors

• Time sheet calculation of time fields (TimeIN + TimeOUT) - (BreakIN + BreakOUT)

  Hello

  
  

  I'm really a novice in the field of pdf script, I would like to ask if someone could help me make a calculation script of a time field with a TOTAL production WORKED HOURS in a day to a calculation of

  (TimeIN + TimeOUT) - (TimeBreakIN + TimeBreakOUT)

  still other topics that the TimeIN, timeout, the TimeBreakIN or the TimeBreakOUT can also run through midnight

  I'm looking for other forums, but not found anything that could match my needs.

  Time at: 17:00

  TimeBreakIN: 20:00

  TimeBreakOUT: 21:00

  OUT time: 02:30

  the script that I expected to be in the

  TOTAL HOURS WORKED is: 8.50 (or 08:30)

  I will be also repopulate this script to each row/day until I add in 1 pay as a TOTAL period

  Thanks in advance to those who can help me.

  Hi JunPapay,

  You may want to take a look at this: calculations between two time fields

  Thank you

  Abhishek

• Date/time field calculation

  Hi Experts,
  
  Our requirement is in the Service request object when one of the values from the drop-down list is changed into announcements, then the column date deadline must fill in with the value of the 4 hours added to the current date/time date/time.
  
  How to get there. Therefore, I see no function to perform calculations on date/time fields.
  
  Immediate response is appreciated.
  
  Thank you and best regards,
  Lemu

  Hello
  You will need to create a WF for this.
  Name of WF: Change status
  Raises the event: before save modified record
  Record Service of Type request:

  In Action of WF
  Name: Update Date
  Type: field update
  Field name: Your domain name
  value: Timestamp() + Duration ('P0Y0DT4H')

  It's your problem.