calculate the field of vision or the focal length of harvest

Is there a way to do this or a plugin that someone knows?

(If you have a shot at a 14mm but you crop to the center of it, it would be good to know what is equal to the equivalent focal length of culture)

Set the Info Overlay to show the new cropped dimensions. In the case the simplest where the aspect ratio of the culture is the same original image, divide one side original by the culture to get the crop factor. If the original is from a full camera frame, the equivalent of 35 mm. long focal length times the crop factor. If the camera has a sensor that is less than 24 x 36 mm, the total of crop factor is crop factor of the camera times the factor of culture "in LR. So, if you have a Canon 7 d, which has a sensor 5184 x 3456 pixels and a factor of 1.6 harvest and crop you the image to 2592 x 1728, the crop factor resulting is 3.2 and your 14 mm lens. will take the field of VISION of a 44.8 mm lens. on a 35 mm camera.. If the harvest of LR has an aspect ratio different that the original, the equivalence is, of course, different for the height and width.

Tags: Photoshop Lightroom

Similar Questions

  • astrophotography. I want to know that the focal length is to determine the field of vision?

    I'm interested in astrophotography.  I want to buy a camera for my telescope.  You can find the field of vision, if you know the focal length of the telescope.  But what is the focal length of a camera with a fixed lens?  If I have a 50 mm lens, is the focal distance 50 mm? or do you need to know the distance from the camera of body image sensor and add it to the lens focal length?  Thanks in advance...

    If you have a 50mm... lens focal length.  The focal length is the distance between the end of the lens and the image plane.  If you look at a digital SLR, there is a symbol on the body (usually the top of the body and often near the viewfinder) that looks like a small circle with a line through IT... which line marks the position of the focal plane inside the camera.

    There is a friction more... If you have a 'simple' goal, it would be the focal length.  Many modern lenses are technically able to be physically shorter than the focal length they provide... because of the types of 'glass' and the configuration of optics.  So the focal length is based on how long a simple goal should be to provide that same value (even if you were to physically measure it and not get this value.)

    All telescopes list their focal lengths, but also among the specs of the telescope focal reports.  I have a refractor of 540mm with an opening of 101mm... so it is 'roughly' f/5.4 scope.  I have also a larger 14 "SCT with a focal length of 3556mm and it is a stretch of f/10.

    The distance "flange to focal plane" on a camera Canon is 44 mm... in the grand scheme of things with a telescope, it will not substantially change the focal length of the image.

    Depending on the scope, you can use either a "focal reducer" or a "barlow" to decrease or increase the focal length.

    One last thing... many designs of 'Newtonian' type telescope is problematic for astrophotography.  This is because most of the glasses and catadioptric telescopes are designed with the intention that a person would use a diagonal of 90º with their eyepiece.  "The diagonal has a tendency to add"roughly"2" to the overal of the focal path length.  If you are using a camera you take this "diagonal" and simply attach the camera for a shot "straight through".  So even if you have lost the focal length 2 ", created by the diagonal... the camera adds"roughly"the same amount of back in.

    BUT... When you use a Newtonian telescope of reflector design, the eyepiece is near the front and there is no "diagonal" in use.  This means that when you add a camera, focal length gets longer, it would be with an eyepiece.    Pull door-eyepiece tube has some development trips... but because the camera is the longest focal length, you end up having to run the focuser completely 'in' to shorten the length of the focal length to put the image in focus.  And that's where you are having problems... very often on a Newtonian telescope, you exceed the limit of traction of focuser (you can't shorten the development any more that you have) and the image was just starting to focus... but it's still pretty fuzzy.

    This problem not to poison all the reflectors of knighting... some can accommodate cameras and still come to focus.  You really check the specific scope.

  • The lateset, 2015.5 edition, does not transfer data from the metadata, only the focal length objective. Disappointment when you want to know what that lens you used. (It allows to rename the files but after you create a second copy. "It's an improvement.)

    The last edition, 2015.5, does not transfer data from the metadata, only the focal length objective. Disappointment when you want to know what that lens you used. (It allows to rename the files but after you create a second copy. "It's an improvement.)

    Yes, copied files from Nikon NEF, DNG.

  • Is this possible with LR5 to export the EXIF of every photo album (or albums) to an Excel file? My goal is to analyse the focal length I use most

    Is this possible with LR5 to export the EXIF of every photo album (or albums) to an Excel file? My goal is to analyse the focal length I use most. It could be used for various other analysis also

    Therefore change one of your columns in the filter bar to display the focus distance.

  • Is there a way to manually opening of entry and/or the focal length of the lens corrections profile?

    This feature would be very useful for those moments when we shoot with manual glass or use adapters manual or really all cases where metadata is missing or damaged. It is to the correct lens distortions at a specific focal length in the case of the zooms. And manually impute the aperture value would determine how much vignetting correction and chromatic aberration correction is required.


    Thank you!

    This facility is not as much as I know sorry.

  • Lightroom is bad ID'ing the focal length of the lens

    I use Lightroom 6.3 and the pictures I've taken with a 50 mm macro lens are incorrectly identified.  I checked with an external EXIF viewer and the correct information is there, but Lightroom is constituting a 20mm (28-80 mm).

    Can I fix?  Adobe can fix this in a future release?

    Hi Cordy,

    I suggest you to please update Lightroom first to the latest version of Lightroom 6.4: keeping up-to-date for Lightroom

    Kind regards

    Tanuj

  • Interpretation of focal lengths specified

    Are specified for the real EFS lenses focal focal lengths or have they been adjusted to be equivalent 35mm?  For example, if an EF lens with a range of specified the 18-55mm lens is mounted on an EOS 70 d which has a 22.5 x 15mm sensor, angle of somewhat wide to telephoto, or makes the angle range very wide barely more standard.

    I had assumed that the listed focal lengths are true, but then I noticed Cannon describing a marked 50mm as a 'standard' lens, which would be the case for 35mm film, but not for a 22mm sensor.

    (Sorry to ask such a basic question.  I'm new to DSLR).

    -Ehz

    The focal length of the lens are real focal lengths.  They are the same regardless of the EF or EF - S.  Put on a crop sensor will reduce the field of VISION.  The 18-55 on a 70 d will include so something like would make him a 24-70 on a 35mm camera (technically, it would be like 28-88).

  • Script to focal length metadata function

    Hello everyone,

    I'm looking to apply a script on my pictures, which is able to recognize the focal length in the metadata.

    I did a specific series of photo with 3 focal length: 50mm, 70mm and 105 mm and I want to apply a specific script on my photos based on the focal length...

    I hope you can help me

    Best regards

    Change the ActionName and ActionSet in function.

    #target photoshop
    if(documents.length){
    if (ExternalObject.AdobeXMPScript == undefined)  ExternalObject.AdobeXMPScript = new ExternalObject("lib:AdobeXMPScript");
    xmp = new XMPMeta( app.activeDocument.xmpMetadata.rawData );
    if( xmp.doesPropertyExist("http://ns.adobe.com/exif/1.0/", "FocalLength" ) ){
    var fl= xmp.getProperty(XMPConst.NS_EXIF, "FocalLength").toString().match(/^\d+/);
    switch(Number(fl)){
        case  50 : doAction("ActionName","ActionSet"); break;
        case 70 : doAction("ActionName","ActionSet"); break;
        case 105 : doAction("ActionName","ActionSet"); break;
        default : doAction("ActionName","ActionSet"); //any other focal length
        }
    }else{
        //No Focal Length
        doAction("ActionName","ActionSet");
        }
    };
    
  • [Beginner] How you view focal length of 35mm EQ. ?

    How yo view focal length in 35mm equivalent?

    I found a plugin which sorts the photos in eq. 35mm, but I'm looking for a medium/plug-in that displays focal length in eq. 35 mm in the info of the loop.

    Any other editor of PP I have used in the past were less than LR, but always had the ability to view the focal length in 35mm. I wonder why LR, a far superior tool, is lacking in this Department. Since I still have to learn photography and use the 2 systems of interchangeable lens camera with factors of different cultures and although two compact cameras, through my pictures with the focal length in mind really allows me to get a better understanding of the perspective.

    This plugin can do what you want, but read on:

    http://regex.info/blog/Lightroom-goodies/focal-length-sort

    More than 35 years ago, I bought my first 35 mm SLR film camera and a bunch of privileged (i.e. objectives to single focal length) lenses. I walked with three 3 boxes, each fitted with one (1) 'main' focal lens and a camera with three or more lens bag. Fortunately, the equipment of series Olympus OM I used was extremely, compact and light weight, even by today's standards.

    With ranges of today zoom lens you can cover most tire using only two lenses.

    To "learn the purpose" why not create a spreadsheet containing a list of focal lengths of 35mm (14mm, 16mm, 17mm, 24mm, 28mm, 35mm, etc.) and add a column for each camera with its equivalent focal length model.

    You can then create a group of collections of LR based on the length focus groups for purposes of comparison:

    1.x Crop camera 1 1.x Crop camera 35mm 2

    super wide 14-20mm

    width 21mm - 35 mm

    normal 36mm - 69 mm

    70-299mm telephoto

    Super Telephoto 300mm and more

    Add images from one camera at a time by using the sort column filter bar "Lens" and your impression dandy new handy focal distance calculator spreadsheet.

    It will give you a much better appreciation of what your current hardware can and cannot do. And despite what says Web Weaver, you will never be able to take a picture like that with a 50mm lens:

  • Missing EXIF focal length

    I'm having this problem in versions 3 and 4. I have a Canon 40 d and all my photos that I edit in LR (uncropped) lack the focal length in the EXIF data.

    This does not happen with Canon DPP. LR will be the focal length in library view, but when he converted to JPG format and then displayed in ZoomBrowser or whatever this piece of program data is missing.

    Windows 7 SP1 x 64, x 64 LR, "reduced data embded" is unchecked as well.

    I'm doing something wrong?

    Photog1982 wrote:

    I'm having this problem in versions 3 and 4. I have a Canon 40 d and all my photos that I edit in LR (uncropped) lack the focal length in the EXIF data.

    This does not happen with Canon DPP. LR will be the focal length in library view, but when he converted to JPG format and then displayed in ZoomBrowser or whatever this piece of program data is missing.

    I can see what you have noticed for a JPG exported from a CR2 from a 5 d Mk II. BUT:

    The focal length is present in the Exif tag, but Canon ZoomBrowser or DPP will not show it. Try using the Windows Photo Viewer and check the properties, you will see the focal length there (as in other programs like IrfanView, ExifTool, etc.). Same distance from the subject (what is no longer displayed in LR3.6 or 4.0) is included in the format of JPEG Exif.

    Beat

  • Crop Factor, the size of the sensor, field of vision

    I find all of it. a but confusing when many call of cameras themselves as full frame, but when you put the same lens on different cameras, the frame is different.. crop factor. field of vision... different .but
    So what crop factor... is the f55 sony please? I've seen a number of different things on various forums not suggesting no harvest to 1.3 but you see the Abel cine graphic field and the f55 is cropped than a c300, which is 1.6. .some how I thought that we were heading toward a world where 50mm meant 50 mm...

    This becomes particularly relevant by using the lens wide angle. When you use the tokina 11-16 (I think only accepted the wider for those who have no characteristic budget) on one of these cameras, the crop or field of view factor restricted means that you have nowhere near frame... a 1.6 crop what goal can give you the grand scale?

    So what is the truth about the f55... Please thank you...

    So, from what I can tell with the F55...

    Sensor is 24 x 12.7 mm with a diagonal of 27.1 mm

    By comparison, when you work with a negative S35 (1.85, 2.40, 1.78) will all use the same horizontal dimensions for the extraction of the negative. What is happening at 24mm (through the book of ARRI frosted glass dimensions). So what this tells us, it's that your lenses will have the same field of view HORIZONTAL on the F55 as they would a film camera. So a 50mm should have the same field of view HORIZONTAL as a film S35mm camera.

    Even a 3perf S35 cameras extraction rates from the exposed negative will be 23,11 mm, slightly more small, but with regard to the horizontal field of vision, people aren't saying that their 50 isn't a 50 because we turn 3perf vs 4perf.

    Now, using the diagonal, show us the lens cover. Yes, the sensor has the same height as a negative film, so if a lens covers the sensor or will not play with the diagonal. And to also know the lens image circle. I can't find what the image circle is for this device, kind of coverage I can't tell you.

    What I see, is that it was designed for the size of APS - C sensor cameras that, on average, would be a 25.1 x 16.7 mm (all manufactured products have different dimensions some small some bigger ones, that it is supposed to use on average). So a device to sensor APS - C on AVERAGE, a bit of a wider horizontal field of view you. The diagonal of 30.1 mm makes me believe that you should have a cover and that he should not thumbnail, although the difference in horizontal makes me think that it might be a very slight decline offshore on the corners.

    Something to remember... well that this objective was intended for 35mm film, in the world of images is fixed. S35mm film in the film world is different. So when a film camera say it's Full Frame, it is in relation to a negative S35, not a camera negative. So with a film lens, a 50mm would mean a 50mm, but when you start to move the lenses of disciplines, that's when things start to become difficult.

    And please keep in mind, that's how I know. I'm not saying this is 100% the perfect answer, it's just what I saw, what I heard and what tells me the calculation.

  • How to calculate the sum of the fields to fill?

    Hello!

    My question is how can I calculate the sum of filled areas?

    For example, in a PDF document, I have a few fields that must be filled out with name and surname and the end of the document, another field that is the sum of the fields "FullName" which shows how many people is in this document. The operation should not take into account white/empty areas.

    Now, I know that I could do with the simple calculation "(+) sum" but I have to put a '1' for each of this area and I would like to avoid this.

    Yes, it's the first option I described. In this case, you can use this code:

    var total = 0;
    for (var i=1; i<=79; i++) {
        if (this.getField("Nume si prenume "+i).valueAsString!="") total++;
    }
    event.value = total;
    
  • I have 3 domains. A field is a constant date mm/dd/yy. The second field is a digital number (1-120) and can be changed. The third field calculates two fields 1 and 2 in the summation and shown in mm/dd/yy. How do I calculate that in the script?

    How do I calculate that in the script? I have 3 domains. A field is a constant date mm/dd/yy. The second field is a digital number (1-120) and can be changed. The third field calculates two fields 1 and 2 in the summation and shown in mm/dd/yy.

    You searched for ' add days?

    You must write a custom for this JavaScript calculation because you cannot add a number any date. Also the date strings are not just a number, even if we can convert a given date in a number for that date that represents the time form a date date (Epoch). Witn this value, we can achieve them all kinds of date calculations and collect a little information about the date. JavaScirpt uses midnight on January 1, 1970 UTC for starting point or the date of the time. Its value is zero, and every millisecond increases the value of 1. When a date string is converted to the date object JavaScirpt we have access to many properties of the date and can use several methods to extract information or adjust the date object.

    Field 1 is in the format "Date" with a format of "mm/dd/yy".

    Field 2 is in «Number» format with 0 decimal.

    Zone 3 is in the format 'None '. The custom calculation script applies to the formatting.

    The custom for JavaScript calculation area 3:

    var cField1 = this.getField("Field_1").valueAsString;

    var cField2 = this.getField("Field_2").valueAsString;

    Event.Value = "";

    If (cField1! = "" & cField2!) = "") {}

    Console.println (cField1 + "" + cField2);

    calculate that if we as no null data;

    var cDateFormat = "mm/dd/yy";

    convert start date date object.

    Kai var = util.scand (cDateFormat, cField1);

    get the date of the month;

    David var = oDate.getDate ();

    Add field 2 number of days;

    David = Number (nDate) + Number (cField2);

    of being updated for the new date.

    oDate.setDate (nDate);

    Set the field to update formatting;

    Event.Value = util.printd (cDateFormat, letter);

    } / / end of data not null;

  • Calculate the price based on the field

    Hello

    My apologies, I know it's a very basic question, but I can't understand the correct syntax for the custom calculation Script necessary to produce the total cost in my form (I just received Acrobat Pro today).

    I have the user fill in the quantity field and then I try to set the TOTAL field to calculate the cost by multiplying the quantity by the price of $29. I thought it was simple, like writing a formula in Excel, but it doesn't seem to work that way and I can not find all resources on Adobe.com or online who point me in the right direction. Any help anyone can offer would be greatly appreciated.

    It might be easier to use the option of simplified field notation, in which case you must enter:

    29 * QTY

    If you want to use a custom calculation script, it could be something like:

    Custom calculation for a field text script

    (function () {}

    Get the value of the quantity, as number

    var qty = + getField("QTY").value;

    Calculate the value of this field if the quantity is greater than 0

    If (Qty > 0) {}

    Event.Value = util.printf ("%.2f", 29 * qty);  round to the nearest hundred

    } else {}

    Event.Value = "";   This field blank

    }

    })();

    If this option gives you more flexibility. you to round off and empty the field. You can also perform additional checks to ensure that the amount of sense (for example, a positive integer within a certain range) you can find more information in the Acrobat JavaScript reference, and here is a link to a tutorial introduction on how to set up calculations in PDF forms: https://acrobatusers.com/tutorials/how-to-do-not-so-simple-form-calculations

    Be sure to set the computed fields read-only so that the user does not try to interact with them.

  • How to calculate the sum of two digital form fields based on the selection of the checkbox.

    I have a form in Acrobat Pro who needs a custom calculation. How to calculate the sum of two digital form fields based on a selection of the checkbox. I have three number fields. Field-A and B are simple one or two digits. Field-C is the sum, or the total field. I want to field-C have a control box which, when turned on and off, just gives a. gives the sum of A + B

    _ Field - 2

    _ Field - A 4

    [check] _ _ field - 6 C

    [disabled] _ _ field - 2 C

    Thank you

    The custom field C calculation script could be:

    (function () {
    
        // Get the values of the text fields, as numbers
        var v1 = +getField("A").value;
        var v2 = +getField("B").value;
    
        // Set this field's value based on the state of the check box named "CB"
        if (getField("CB").value !== "Off") {
            event.value = v1 + v2;
        } else {
            event.value = v1;
        }
    
    })();
    

    Replace 'A', 'B', and 'CB' with the real names of the fields.

Maybe you are looking for