Calendar function returns strange values

Can someone please help

Calendar rightNow = Calendar.GetInstance ();
int aa = Calendar.DATE;
int bb = Calendar.MONTH;

in aa value is 5, it is and in the bb, it is 2.

I checked my date system as well as the date of Simulator. I don't know why it's happening.

These values Calendar.DATE and Calendar.MONTH are the contacts to be used in conjueciton with the Calendar.getField () method.

Like this:

int = rightNow.getField (Calendar.MONTH) MB

Tags: BlackBerry Developers

Similar Questions

Function return undefined values

My function returns undefined values. It seems that the return of the function statement is executed before the database is queried and values are assigned to variables. If I do an alert within the loop for () I get the correct values from the database, but these values are not affected before excecuting the return statement function. How can I do this differently?

function getColumnNames(table){
    var rs1, rs2, rs3, rs4, rs5;
    db.transaction(function (tx) {
        tx.executeSql("SELECT * FROM schema WHERE table_name=?",[table], function(ax, results){
            var size = results.rows.length, i;
            var item;
            for (i = 0; i < size; i++){
                item = results.rows.item(i);
                rs1 = item.col1;
                rs2 = item.col2;
                rs3 = item.col3;
                rs4 = item.col4;
                rs5 = item.col5;
                                alert(rs1); //correct value is returned here
            }
        });
    });
    return [rs1, rs2, rs3, rs4, rs5];
}

Hey Fabian,.

You are quite correct that the return statement is executed before the database returns the results. There are ongoing asynchronous calls. You can set breakpoints in JavaScript code to see what is happening. You can correct the problem by using function callbacks. I edited your code below to use the callback functions - there might be a few typos, but the general approach should be wooded.

function getColumnNames(table, callback){
    var rs1, rs2, rs3, rs4, rs5;
    db.transaction(function (tx) {
        tx.executeSql("SELECT * FROM schema WHERE table_name=?",[table], function(ax, results){
            var size = results.rows.length, i;
            var item;
            for (i = 0; i < size; i++){
                item = results.rows.item(i);
                rs1 = item.col1;
                rs2 = item.col2;
                rs3 = item.col3;
                rs4 = item.col4;
                rs5 = item.col5;
                    alert(rs5); //correct values are being returned
                callback([rs1, rs2, rs3, rs4, rs5]);
            }
        });
    });
}

// example of how to call getColumnNames with callback
getColumnNames('importantTable', function (result)
{
    console.log(result);
});

// alternative version
function onCallback(result)
{
    console.log(result);
}

getColumnNames('importantTable', onCallback);

I hope this helps.

See you soon,.

James

ORA-06503: PL/SQL: function returned no value ORA-06512:

Hi all
SQL > set serveroutput on
SQL > CREATE OR replace FUNCTION qty_value (p_item_id number)
2 RETURN NUMBER
3 EAST
4 v_qty_arrival NUMBER;
5 BEGIN
6. SELECT THE CASE SENSITIVE OPTION
7. WHAT (SUM (b.quantity) - SUM (b.quantity_received)) < = 0 THEN 0
8 ELSE (SUM (b.quantity) - SUM (b.quantity_received))
9 END Qty_Arrival
10 INTO v_qty_arrival
Po_lines_all 11 a,
po_line_locations_all 12 b
13 WHERE a.po_line_id = b.po_line_id
14 AND a.item_id = p_item_id;
15 EXCEPTION
16 THEN THAN OTHERS THEN
17 v_qty_arrival: = NULL;
18 RETURN v_qty_arrival;
19 END qty_value;
20.
The function is created.
SQL >
SQL > select xxc_qty_arrivale (214960) double
2.
Select xxc_qty_arrivale (214960) double
*
ERROR on line 1:
ORA-06503: PL/SQL: function returned no value
ORA-06512: at the 'APPS '. XXC_QTY_ARRIVALE', line 19

Back AFTER using the exception block is fine as long as your code actually REACHED the exception block.

When there are no errors, then your code will not enter the exception block, but you still NEED to return a value, since it is what functions a function wants to return a value, that's what the functions are made for.

Spot the differences between the following 3 functions. Understand how they work.

The first function has only a return in the exception block but runs correctly. Result: error, because the back is missing in the code block.

The second function has a return in the exception block and one in the block of code and runs correctly. Result: no error, because the return is not missing in the code block.

The third function has a return in the exception block and one in the block of code and is forced into an error. Result: no error, because the return of the exception handler is used (instead of retriggering of the error, which you would normally do).

SQL > create or replace function myfunc

2 return number

3 as

4 start

5 dbms_output.put_line ('in the section of code');

6 null;

7 exception

8 then than others

9. can

10 dbms_output.put_line (' in the exception handler ' |) SQLERRM);

11      --

12 return 0;

13      --

14 end;

15.

The function is created.

SQL > select double myfunc;

Select double myfunc

*

ERROR on line 1:

ORA-06503: PL/SQL: function returned no value

ORA-06512: at "GHPLUS. MYFUNC", line 14

In the section of code

SQL > create or replace function myfunc

2 return number

3 as

4 start

5 dbms_output.put_line ('in the section of code');

6 null;

7    --

8 return 1;

9    --

10 exceptional

11 so that others

12. can

13 dbms_output.put_line (' in the exception handler ' |) SQLERRM);

14      --

15 return 0;

16      --

end 17;

18.

The function is created.

SQL > select double myfunc;

MYFUNC

----------

1

1 selected line.

In the section of code

SQL > create or replace function myfunc

2 return number

3 as

n number 4;

5. start

6 dbms_output.put_line ('in the section of code');

7 n: = 1/0; -force an error (zero divisor) to join the exception handler

8    --

9 return 1;

10-

exception 11

12 so that others

13. can

14 dbms_output.put_line (' in the exception handler ' |) SQLERRM);

15      --

16 return 0;

17      --

18 end;

19.

The function is created.

SQL > select double myfunc;

MYFUNC

----------

0

1 selected line.

In the section of code

In the handler for exception ORA-01476: divisor is equal to zero

SQL >

ORA-06503: PL/SQL: function returned no value
Hi guys,.
I wrote a function that returns the number of quarter for a given date.
Here's the function

FUNCTION to CREATE or REPLACE fn_get_quarter
(p_date DATE)
RETURN NUMBER
AS
v_qtr NUMBER;
BEGIN
Select TO_CHAR (p_date, 'Q')
IN v_qtr
DOUBLE;
dbms_output.put_line (' it's quarter ' | v_qtr);
END;

It compiled without error.

Here is the test case that I wrote

DECLARE
p_date DATE: = TO_DATE('12/22/2009','MM/DD/YYYY');
v_qtr NUMBER;
BEGIN
v_qtr: = fn_get_quarter (p_date);
END;

When I run the present, I get the following error.

ORA-06503: PL/SQL: function returned no value
ORA-06512: at "GPS_FVO. FN_GET_QUARTER', line 13
ORA-06512: at line 7

But surprisingly, I get the result.

Please suggest and let me know how to get rid of this error and why I get this error.

Thanks in advance.
Sam
RETURN v_qtr;
should be added after DBMS_OUTPUT

Function - return multiple values in a concatenated string
Hello

Is it possible for a function return a concatenated string (combining more than one number). I'm trying to return the purchase by the introduction and invoice_id number and code order number, but an invoice_id can have several PO with the same code number. I want to concatenate the PO numbers with commas, for example

10124, 10090, 10987

At the present time, the function returns NULL for those cases that have more than one purchase order number.

Thank you
```
func_get_po(i.invoice_id, cc.code_combination_id) "PO No",
func_get_po_requester(i.invoice_id, cc.code_combination_id, func_get_po(i.invoice_id, cc.code_combination_id)) "PO Requester",
```
Of course, this can be done without any problem.
If it returns NULL, then you must debug function and check the operating logic. I know that it will take a little of your time, but not problems with the logic of syntax and concatenation.

APEX 4.0.1: $v () function returns multiple values for the box?
Hello

I have a report that uses apex_item.checkbox (...) to generate the check box. This report correctly displays a check box for each line. The source code that is generated in the html page is:
< input type = "checkbox" name = "f01" value = "202" id = "P1_CHECKBOX" / >
...
...
< input type = "checkbox" name = "f01" value = "220" id = "P1_CHECKBOX" / >
...
...
< input type = "checkbox" name = "f01" value = "210" id = "P1_CHECKBOX" / >
...
...

I want to use the javascript function $v () to get the values of the enabled check box. I thought that the return of this function all the checked values separated by ':' but I noticed that my code alert ($v ('P1_CHECKBOX')); return whenever the value of the first checkbox if it is checked.
It returns '202' if the first box is checked, but nothing, if only the second checkbox is checked and '202' if the box of the first and the second is checked.
Hello

first of all, $v, $x and $s are supposed to not work for items on the page, not the columns in a table or manually generated HTML elements.

Secondly, I think that your HTML code is not correct, because each of your boxes has the same ID. But the ID must be unique in the DOM of the browser tree. Thus the different box should actually named P1_CHECKBOX_1... P1_CHECKBOX_3. Just look at what is actually generated for a page element real checkbox. BTW, I think that you should not name the checkbox as part of page elements, because they are not actually page elements. I think that this could be confusing for other developers.

Hope that helps
Patrick
-----------
My Blog: http://www.inside-oracle-apex.com
APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
Twitter: http://www.twitter.com/patrickwolf

Function returned no value error

create or replace function dssppv.hra_find_short_path (
   p_new_rgmn_grp_gid    in   number
  ,p_tail_rgmn_grp_gid   in   number
  ,p_mkt_cnfgr_gid       in   number
)
   return string

is
   v_rgmn_grp_path varchar2 ( 2000 );
   check_step varchar2 ( 2000 );
begin
   dbms_output.put_line
      ( 'Begin of function  hra_find_short_path to Check Circular Loop : '
        || to_char ( sysdate, 'YYYY-MM-DD HH24:MI:SS' )
      );
   check_step                 := ' Step 1 - Circular loop Check up.';

   --Checking for the circular loop
   select rgmn_path || '/' || gt.rgmn_grp_nam
   into   v_rgmn_grp_path
   from   ( select  min_rgmn_node
                   ,rgmn_path
                   ,rgmn_grp_gid
           from     ( select    level as min_rgmn_node
                               ,dt.rgmn_grp_gid
                               ,dt.tail_rgmn_grp_gid
                               ,gp.rgmn_grp_nam
                               ,rtrim
                                   ( reverse
                                        ( sys_connect_by_path
                                                  ( reverse ( gp.rgmn_grp_nam )
                                                   ,'/ '
                                                  )
                                        )
                                    ,'/ '
                                   ) as rgmn_path
                     from       dssppv.t_market_cnfgr_rgmn_grp_dtl dt join dssppv.t_market_cnfgr_rgmn_grp gp
                                on (     dt.rgmn_grp_gid = gp.rgmn_grp_gid
                                     and gp.mkt_cnfgr_gid = p_mkt_cnfgr_gid
                                   )
                     start with dt.tail_rgmn_grp_gid = p_new_rgmn_grp_gid
                     connect by nocycle prior dt.rgmn_grp_gid =
                                                          dt.tail_rgmn_grp_gid )
           where    rgmn_grp_gid = p_tail_rgmn_grp_gid
           order by min_rgmn_node )
         ,dssppv.t_market_cnfgr_rgmn_grp gt
   where  gt.rgmn_grp_gid = p_new_rgmn_grp_gid and rownum = 1;

   dbms_output.put_line ( ' Circular Loop is formed as shown :'
                          || v_rgmn_grp_path
                        );

   if ( v_rgmn_grp_path is not null )
   then
      dbms_output.put_line ( ' Circular Loop is formed as shown :'
                             || v_rgmn_grp_path
                           );
   else
      dbms_output.put_line ( ' No Loop is formed.' );
   end if;

   dbms_output.put_line
         ( 'End of function  hra_find_short_path to Check Circular Loop : '
           || to_char ( sysdate, 'YYYY-MM-DD HH24:MI:SS' )
         );
   return v_rgmn_grp_path;
exception
 --  when no_data_found
  -- then
   --   dbms_output.put_line
    --     ( 'End  of function  hra_find_short_path to Check Circular Loop : '
     --      || to_char ( sysdate, 'YYYY-MM-DD HH24:MI:SS' )
      --   );
      --return null;
   when others
   then
      dbms_output.put_line
                     ( 'Error in function DSSPPV.hra_find_short_path at: '
                       || check_step
                     );
      dbms_output.put_line ( sqlerrm );
      dbms_output.put_line
         ( 'End of function  hra_find_rgmn_grp_loops to Check Circular Loop : '
           || to_char ( sysdate, 'YYYY-MM-DD HH24:MI:SS' )
         );
end hra_find_short_path;
/

I have fully commented goal no. Data Exception not found top check if she is to return null when no record is found.

But he was wrong in not found exception when there is no data record.

But when run sql separately he showed zero records without don't raise the no found error of data.

He would not even through the loop fi... Please correct me if I did something wrong

 if ( v_rgmn_grp_path is not null )
   then
      dbms_output.put_line ( ' Circular Loop is formed as shown :'
                             || v_rgmn_grp_path
                           );
   else
      dbms_output.put_line ( ' No Loop is formed.' );
   end if;

You may not assume that v_rgmn_grp_path will retain the NULL value if the query returns no rows. In this case AS the value of the variable is not defined. I suggest yo change:

Select rgmn_path. '/' || gt.rgmn_grp_nam

Select count (*) case when 1 then max(rgmn_path ||) '/' || end of gt.rgmn_grp_nam)

This way NO_DATA_FOUND will not be raised and the v_rgmn_grp_path will be NULL if there is no corresponding line.

SY.

MONTHS_BETWEEN function returns negative values 'bad '?

Hello
I can't understand why these values are results.
SQL > select months_between (to_date (February 2, 13 ',' DD-MON-RR'), to_date ('February 28, 13 ', ' DD-MON-RR')) twice;
MONTHS_BETWEEN(TO_DATE('02-FEB-13','DD-MON-RR'),TO_DATE('28-FEB-13','DD-MON-RR')
--------------------------------------------------------------------------------
-.83870968
SQL > select months_between (to_date (February 2, 13 ',' DD-MON-RR'), to_date ('April 1, 13 ', ' DD-MON-RR')) twice;
MONTHS_BETWEEN(TO_DATE('02-FEB-13','DD-MON-RR'),TO_DATE('01-APR-13','DD-MON-RR')
--------------------------------------------------------------------------------
-1.9677419
SQL > select months_between (to_date (February 2, 13 ',' DD-MON-RR'), to_date ('April 2, 13 ', ' DD-MON-RR')) twice;
MONTHS_BETWEEN(TO_DATE('02-FEB-13','DD-MON-RR'),TO_DATE('02-APR-13','DD-MON-RR')
--------------------------------------------------------------------------------
-2

user13393428 wrote:

But,

Select months_between (to_date (February 2, 13 ',' DD-MON-RR'), to_date ('April 2, 13 ', ' DD-MON-RR')) twice;

How it is-2? Should not be-1?

Do you really think there's only 1 month between February and April? you have a very convenient calendar you can watch...

Analytical function - return 2 values

I don't know I need to use an analytical function to do this, I can't do things. I appreciate the help.
Statements of table and insert:

create table TST_CK
(
DOC_ID NUMBER(6)      not null,
ROW_SEQ_NBR NUMBER(6) not null,
IND_VALUE VARCHAR2(2) null
)
INSERT INTO TST_CK VALUES ('1','6',NULL);
INSERT INTO TST_CK VALUES ('1','5',NULL);
INSERT INTO TST_CK VALUES ('1','4','T');
INSERT INTO TST_CK VALUES ('1','3','R');
INSERT INTO TST_CK VALUES ('1','9',NULL);
INSERT INTO TST_CK VALUES ('1','10',NULL);
INSERT INTO TST_CK VALUES ('1','7','T');
INSERT INTO TST_CK VALUES ('1','8','R');
INSERT INTO TST_CK VALUES ('2','1',NULL);
INSERT INTO TST_CK VALUES ('2','2',NULL);
INSERT INTO TST_CK VALUES ('2','3','T');
INSERT INTO TST_CK VALUES ('2','4','R');
INSERT INTO TST_CK VALUES ('2','5',NULL);
INSERT INTO TST_CK VALUES ('2','6',NULL);
INSERT INTO TST_CK VALUES ('2','7','T');
INSERT INTO TST_CK VALUES ('2','8','R');
INSERT INTO TST_CK VALUES ('4','1',NULL);
INSERT INTO TST_CK VALUES ('4','2',NULL);
INSERT INTO TST_CK VALUES ('4','3','X1');
INSERT INTO TST_CK VALUES ('4','4',NULL);
INSERT INTO TST_CK VALUES ('4','5',NULL);
INSERT INTO TST_CK VALUES ('4','6',NULL);
INSERT INTO TST_CK VALUES ('4','7','T');
INSERT INTO TST_CK VALUES ('4','8','R');
INSERT INTO TST_CK VALUES ('4','9',NULL);
INSERT INTO TST_CK VALUES ('4','10',NULL);
INSERT INTO TST_CK VALUES ('4','11',NULL);
INSERT INTO TST_CK VALUES ('4','12',NULL);
INSERT INTO TST_CK VALUES ('4','13','T');
INSERT INTO TST_CK VALUES ('4','14','R');
INSERT INTO TST_CK VALUES ('4','15',NULL);
INSERT INTO TST_CK VALUES ('4','16',NULL);
COMMIT;

Here is what I tried that gets me close:

SELECT MAX (TST_CK.DOC_ID), MAX (TST_CK.ROW_SEQ_NBR), TST_CK.IND_VALUE
  FROM ASAP.TST_CK TST_CK
 WHERE (TST_CK.IND_VALUE IS NOT NULL)
GROUP BY TST_CK.IND_VALUE
ORDER BY 2 ASC

Here is my desired outcome:

CV_1      CV_2

 T           R

Or even better result would be:

concat(CV_1,CV_2)

Result:

T,R

Thanks for looking

G

GMoney says:
Basically, I just need to make sure what I captures the last T and R entered in the column

Still not clear. You want to find the last two lines (function ROW_SEQ_NBR) where IND_VALUE is 't' & 'R', right? If so:

with t as (
           select  doc_id,
                   row_seq_nbr,
                   ind_value,
                   row_number() over(partition by ind_value order by row_seq_nbr desc) rn
             from  tst_ck a
             where ind_value in ('T','R')
          )
select  doc_id,
        row_seq_nbr,
        ind_value
  from  t
  where rn = 1
/ 

    DOC_ID ROW_SEQ_NBR IN
---------- ----------- --
         4          14 R
         4          13 T

SQL>

SY.

I need to return multiple values in function

create or replace function f (p) in varchar2) return varchar2
is
a number (10);
Start

for loop 1 in 1.10
Select instr('yyyyyyyyynnnnnyynny','y',1,i) in the doubles.
end loop;
return a;
end;

my function return a value, but I need to return multiple values
Thanks in advance

I don't know if that's what you want (you should give expected results also)

SQL> create or replace type mytabletype as table of number;
  2  /

Type created.

SQL> create or replace function f (p in varchar2) return myTableType pipelined is
  2    a number(10);
  3  begin
  4    for i in 1..10 loop
  5      select instr('yyyyyyyyynnnnnyynny','y',1,i) into a from dual;
  6      pipe row (a);
  7    end loop;
  8  end;
  9  /

Function created.

SQL> select * from table(f('1'));

COLUMN_VALUE
------------
           1
           2
           3
           4
           5
           6
           7
           8
           9
          15

10 rows selected.

SQL>

Published by: Leo Mannhart on March 22, 2011 11:01

could even be compressed into

create or replace function f (p in varchar2) return myTableType pipelined is
begin
  for i in 1..10 loop
    pipe row (instr('yyyyyyyyynnnnnyynny','y',1,i));
  end loop;
end;

How to return two values of a function?
Hi all
I have a function which returns a varchar2 value. This value is used in the SQL of a ref cursor

Now I want this function returns two values. I tried to use varray, but could not accomplish the task.

Can you tell me how can I find the two values from a function? and how this function can be called in a SQL query?

Thank you very much
The query should look like:
```
SELECT v.col.name AS name
     , v.col.flag AS flag
FROM   ( SELECT kk_test_kk(t.somecolumn,t.someothercolumn,42) AS col
         FROM   sometable t ) v;
```
Note that you need to prefix with the name of view inline ('v' in the example) and the expression of the function ('col' in the example).

How the two function return values

Dear all,
Please explain, how the two values of function return?
give a simple example.

OK, a few examples...

First example, using a type of structured on the database object:

SQL > create or replace type tMyValues as an object (yr number, number, number of dy mn)
2.

Type of creation.

SQL > create or replace function getMyValues return tMyValues is
2 number of y: = extraction (year sysdate);
number of 3 m: = extraction (sysdate months);
number of 4 d: = extract (day of sysdate);
5. start
6 return new tMyValues(y,m,d);
7 end;
8.

The function is created.

SQL > set serverout on

SQL > declare
2 myValues tMyValues;
3. start
4 myValues: = getMyValues();
5 dbms_output.put_line (' year: ' | myValues.yr);
6 dbms_output.put_line (' month: ' | myValues.mn);
7 dbms_output.put_line (' date: ' | myValues.dy);
8 end;
9.
Year: 2015
Month: 4
Day: 1

PL/SQL procedure successfully completed.

Second example, using an associative array within PL/SQL:

SQL > set serverout on
SQL > declare
2 type tMyValues is table of the index number to varchar2 (10);
3 myValues tMyValues;
4
5 function getMyValues return tMyValues is
6 retValues tMyValues;
7. start
8 retValues ('Year'): = extraction (year sysdate);
9 retValues ('Month'): = extraction (sysdate months);
10 retValues ('Day'): = extract (day of sysdate);
11 return retValues;
12 end;
13. begin
14 myValues: = getMyValues();
15 dbms_output.put_line (' year: ' | myValues ('Year'));
16 dbms_output.put_line (' month: ' | myValues ('Month'));
17 dbms_output.put_line (' date: ' | myValues ('Day'));
18 end;
19.
Year: 2015
Month: 4
Day: 1

PL/SQL procedure successfully completed.

For the pipeline functions, see the example I wrote on the link provided by ReemaPuri (answer No. 3) that I don't need to re - write what I did before.

Mathmatical function to return the value in injectors
Hello
I have obliged. If value for ex Lake 4400000, he should return as 4.4millions even for billions.
is there an oracle function to return the value in this format. ???
Hello

When I want to have a "readable" released in large numbers, I use to do the following:
```
Scott@my11g SQL>with t as (
  2  select 3456123456 n from dual
  3  union all select 4567123 from dual
  4  union all select 123465 from dual
  5  )
  6  select n, case when n>1000000000 then trunc(n/1000000000,1)||' Billions'
  7  when n>1000000 then trunc(n/1000000,1)||' Millions'
  8  else to_char(n) end fmtn
  9  from t ;

         N FMTN
---------- -------------------------------------------------
3456123456 3.4 Billions
   4567123 4.5 Millions
    123465 123465
```
------
* + [change] + *.
Moreover, lakh [url http://en.wikipedia.org/wiki/Lakh] has no meaning outside of South Asia.
Especially for a French man like me, grown with [url http://en.wikipedia.org/wiki/International_System_of_Units] International system of units that is fighting against what I call "funky" measures empirical such miles, yards, feet, inches, just not multiple of 10³
Same billion mean differ depending on the country (see [url http://en.wikipedia.org/wiki/Long_and_short_scales] long and short scales)

Just for "fun": [url http://articles.cnn.com/1999-09-30/tech/9909_30_mars.metric.02_1_climate-orbiter-spacecraft-team-metric-system?_s=PM:TECH] this is what can happen when we do not use the same system of units.

Return multiple values from a function in a SELECT statement
I hope I've provided enough information here. If not, let me know what I'm missing.

I create a view that will combine the information from several tables. Most are pretty simple, but there are a couple of columns in the view that I need to get by running a function within a package. Even if this is quite simple (I have a function named action_date in a package called rp, for example, that I can use to return the date that I need through SOME rp.action_date (sequence_number).

Here is the question: I really need to return several bits of information of the same record (not only action_date, but also action_office, action_value, etc.)-a join of the tables will work not here, as I will explain below. I can, of course, perform a function separate for each statement, but this is obviously inefficient. Within the select statement of the view, however, I don't know how each of the values that I need to get back.

For example, right now, I have:

Table 1:
sequence_number NUMBER (10),
name varchar (30),
...

Table2:
Table1_seq NUMBER (10),
action_seq NUMBER (10),
action_date DATE,
action_office VARCHAR (3),
action_value VARCHAR (60),
...

I can't just simply join Table1 and Table2 because I have to perform processing in order to determine the rows returned matching, I really need to select. If the package opens a cursor and treats each line until it finds the one I need.

The following works but is ineffective since all calls to the package returns the columns of the same record. I don't know how to put all the values that I need in the SELECT statement.
CREATE VIEW all_this_stuff AS
SELECT sequence_number, name,
RP.action_date (sequence_number) action_date,
RP.action_office (sequence_number) action_office,
RP.action_value (sequence_number) action_value
FROM table1

Is there a way to return multiple values in my SELECT statement or I'm going about this all wrong?

Any suggestions?

Thank you very much!
Hello

What you want is a Query of Top - N , what you can do using the ROW_NUMBER analytic function in a subquery, like this:
```
WITH     got_rnum     AS
(
     SELECT     action_seq, action_dt, action_office, action_type, action_value
     ,     ROW_NUMBER () OVER ( ORDER BY  action_date
                               ,            action_seq
                         ,            action_serial
                       ) AS rnum
     FROM     table2
     WHERE     action_code     = 'AB'
     AND     action_office     LIKE 'E'     -- Is this right?
)
SELECT     action_seq, action_dt, action_office, action_type, action_value
FROM     got_rnum
WHERE     rnum     = 1
;
```
As written, this returns a single line (at most).
I suspect you'll actually get a rank for each group , where a group is defined by a value in a table in which you join.
In this case, add a PARTITION BY clause to the ROW_NUMBER function.
If post you a small example of data (CREATE TABLE and INSERT statements), I could show you exactly how.
As I don't have your tables, I'll show you the use of the tables in the scott schema.
This is a view containing data in the scott.dept table and also to scott.emp, but only for the highest employee in each Department (in other words, the employee whose oldest hire date). If there be a tie for the first hire date, while the candidate with the lowest empno is selected.
```
CREATE OR REPLACE VIEW     senior_emp
AS
WITH     got_rnum     AS
(
     SELECT     d.deptno
     ,     d.dname
     ,     e.empno
     ,     e.ename
     ,     e.hiredate
     ,     ROW_NUMBER () OVER ( PARTITION BY  d.deptno
                               ORDER BY          e.hiredate
                         ,                e.empno
                       ) AS rnum
     FROM     scott.dept     d
     JOIN     scott.emp     e     ON     d.deptno     = e.deptno
)
SELECT     deptno
,     dname
,     empno
,     ename
,     hiredate
FROM     got_rnum
WHERE     rnum     = 1
;

SELECT     *
FROM     senior_emp
;
```
Output:
```
.    DEPTNO DNAME               EMPNO ENAME      HIREDATE
---------- -------------- ---------- ---------- ---------
        10 ACCOUNTING           7782 CLARK      09-JUN-81
        20 RESEARCH             7369 SMITH      17-DEC-80
        30 SALES                7499 ALLEN      20-FEB-81
```
Moreover, one of the conditions to the query you posted has been
```
action_office     LIKE 'E'
```
which equals
```
action_office     = 'E'
```
(AS is always equivalent to = if the string that follows AS does not contain the winning cards.)
Did you mean say that or did you mean something like this:
```
action_office     LIKE 'E%'
```
Instead?

Return a value of date using a function
I have a function in which I'm passing a date, but given the entry as a varchar data type.

I'm the date inside the print function value and then return the value date.

When I'm passing through January 20, 2009 as the date, I make out like 20 January 09 only.
The year is get truncated in the output.

How can I get January 20, 2009 as the value of output.

Thanks in advance

Kind regards
Rambeau
Try this:
```
DECLARE
  MANIFEST_DT VARCHAR2(25) := '20-Jan-2009';
  V_SAMP_DT DATE;
BEGIN
  SELECT TO_DATE(MANIFEST_DT,'DD-MON-YYYY') + 4
  INTO   V_SAMP_DT
  from   dual;
  DBMS_OUTPUT.PUT_LINE('SAMPLE DATE IS: ' ||to_char(V_SAMP_DT, 'dd-Mon-yyyy'));
END;
/
```
When you store/work with dates in the database, it is best to convert the dates as a string in the format of date (with to_date) as soon as possible.

When you need a date in the format of a specific way when it came to the end/screen/report on the forehead, then use to_char to return a date into a string format.

Published by: Boneist on January 20, 2009 11:41

Calendar function returns strange values

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