Change data type for the column in a table - Oracle 8i

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• change the data type of the columns

  Oracle 10g version.
  I have a table with 150 columns.
  I would like to change the data type of the columns in my table to varchar.
  Do we have a query for this task?
  
  Thank you.

  Not knowing yet what you meet John:

  If your table is empty, you can use the datadictionary to generate a statement and run the query to a file that makes the DDL using dynamic SQL or spool and run that...

  Example:

  MHO%xe> create table bla (col1 number, col2 number);
  
  Tabel is aangemaakt.
  
  MHO%xe> select column_name, data_type from user_tab_columns where table_name = 'BLA';
  
  COLUMN_NAME                    DATA_TYPE
  ------------------------------ ---------------------------------------------------------------------
  COL1                           NUMBER
  COL2                           NUMBER
  
  MHO%xe> declare
    2    l_sql varchar2(4000);
    3    l_sep varchar2(1);
    4  begin
    5    l_sql := 'alter table BLA modify ('||chr(10);
    6    for rec in ( select column_name from user_tab_columns where table_name = 'BLA')
    7    loop
    8      l_sql := l_sql||l_sep||' '||rec.column_name||' varchar2(50)'||chr(10);
    9      l_sep := ',';
   10    end loop;
   11    --
   12    dbms_output.put_line(l_sql||' )');
   13    --
   14    execute immediate l_sql||' )';
   15    --
   16  end;
   17  /
  alter table BLA modify (
   COL1 varchar2(50)
  , COL2 varchar2(50)
   )
  
  PL/SQL-procedure is geslaagd.
  
  MHO%xe> select column_name, data_type from user_tab_columns where table_name = 'BLA';
  
  COLUMN_NAME                    DATA_TYPE
  ------------------------------ ---------------------------------------------------------------------
  COL1                           VARCHAR2
  COL2                           VARCHAR2
  

• How to recover the data type of a column in a table?

  Hello
  
  I want to retrieve the data type of a column in a table. At the moment I'm querying attribute 'OCI_ATTR_DATA_TYPE', but it is SQLT_CHR varchar2 and nvarchar2 data type columns. I need to make a distinction between these columns of two separate data types. Y at - it all API through which I could get the exact data type of a column, i.e. "nvarchar2?
  
  Thanks in advance.
  
  Hashim

  Hello

  It is not a very direct way to do it. What you can do is to call OCIDescribeAny on the table that you want to get information. You can then get the OCI_ATTR_CHARSET_FORM attribute for the column. If the value of the attribute that you get is SQLCS_IMPLICIT, that would mean its a varchar/char/varchar2 column regular. If you get SQLCS_NCHAR, this means that the column is NCHAR. You can get the example of it here:

  http://download.Oracle.com/docs/CD/B14117_01/AppDev.101/b10779/oci06des.htm#446491

  Just look for the section "Recovering for a Table column Datatypes".

  Thank you
  Sumit

• y at - it Systemtable of the data types of the column?

  Is QUESTION 1 Systemtable of the data types of the column?
  
  _________________________________________________________________
  QUESTION2
  
  IF REGEXP_SUBSTR (p_datatype, "[''!" [¤ % & / =? *; >: <]') IS NOT NULL
  
  We say: you can not write that! » ¤ % & / = ? ' ^ * ; >: <-each of each example ">".
  
  How can I say... you can NOT write PENIS, NIPPLES, hole word "NIPPLES".
  __________________________________________________________________
  
  Published by: user619226 on 19-sep-2008 01:15

  Do you mean something like this...

  SQL> ed
  Wrote file afiedt.buf
  
    1  declare
    2    v_txt VARCHAR2(200) := 'FRED,JOE';
    3  begin
    4    IF regexp_like(v_txt, '^[[:alnum:]]*$') THEN
    5      dbms_output.put_line('Text is OK as it contains just a word');
    6    ELSE
    7      dbms_output.put_line('Text is not OK.  Must only contain a single word');
    8    END IF;
    9* end;
  SQL> /
  Text is not OK.  Must only contain a single word
  
  PL/SQL procedure successfully completed.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  declare
    2    v_txt VARCHAR2(200) := 'FRED';
    3  begin
    4    IF regexp_like(v_txt, '^[[:alnum:]]*$') THEN
    5      dbms_output.put_line('Text is OK as it contains just a word');
    6    ELSE
    7      dbms_output.put_line('Text is not OK.  Must only contain a single word');
    8    END IF;
    9* end;
  SQL> /
  Text is OK as it contains just a word
  
  PL/SQL procedure successfully completed.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  declare
    2    v_txt VARCHAR2(200) := 'FRED JOE';
    3  begin
    4    IF regexp_like(v_txt, '^[[:alnum:]]*$') THEN
    5      dbms_output.put_line('Text is OK as it contains just a word');
    6    ELSE
    7      dbms_output.put_line('Text is not OK.  Must only contain a single word');
    8    END IF;
    9* end;
  SQL> /
  Text is not OK.  Must only contain a single word
  
  PL/SQL procedure successfully completed.
  
  SQL>
  

• table col name get the details of the table column and inserting of values depending on the data type of the column

  Hello

  I am train to write a procedure where I would spend the table as a parameter name and then the code would determine it is column names, and then he would insert records in each column depending on the data type. could someone help me with this.

  Thank you

  SM

  Hello

  Perhaps you need to dummy data just for the table.

  Here is my exercise

  create or replace
  procedure generate_rows(p_table_name varchar2, p_count number)
  is
    --
    function insert_statement(p_table_name varchar2) return clob
    is
      l_columns clob;
      l_expressions clob;
      l_sql clob default
        'insert into p_table_name (l_columns) select l_expressions from dual connect by level <= :p_count';
    begin
      select
        -- l_columns
        listagg(lower(column_name), ',') within group (order by column_id),
        -- l_expressions
        listagg(
          case
          when data_type = 'DATE'
            then  'sysdate'
          when data_type like 'TIMESTAMP%'
            then  'systimestamp'
          when data_type = 'NUMBER'
            then  replace('dbms_random.value(1,max)',
                    'max', nvl(data_precision - data_scale, data_length)
                  )
          when data_type = 'VARCHAR2'
            then  replace(q'|dbms_random.string('a',data_length)|',
                    'data_length', data_length
                  )
          else
                  'NULL'
          end, ',') within group (order by column_id)
      into
        l_columns,
        l_expressions
      from user_tab_columns
      where table_name = upper(p_table_name);
      --
      l_sql := replace(replace(replace(l_sql,
        'p_table_name', p_table_name),
        'l_columns', l_columns),
        'l_expressions', l_expressions);
      -- debug
      dbms_output.put_line(l_sql);
      --
      return l_sql;
    end;
  begin
    execute immediate insert_statement(p_table_name) using p_count;
  end;
  /
  
  -- test
  create table mytable(
    id number(4,0),
    txt varchar2(10),
    tstz timestamp with time zone,
    dt date,
    xml clob
  )
  ;
  set serveroutput on
  exec generate_rows('mytable', 10);
  select id, txt from mytable
  ;
  drop procedure generate_rows
  ;
  drop table mytable purge
  ;
  
  Procedure GENERATE_ROWS compiled
  Table MYTABLE created.
  PL/SQL procedure successfully completed.
  
  insert into mytable (id,txt,tstz,dt,xml) select dbms_random.value(1,4),dbms_random.string('a',10),systimestamp,sysdate,NULL from dual connect by level <= :p_count
          ID TXT
  ---------- ----------
           3 WnSbyiZRkC
           2 UddzkhktLf
           1 zwfWigHxUp
           2 VlUMPHHotN
           3 adGCKDeokj
           3 CKAHGfuHAY
           2 pqsHrVeHwF
           3 FypZMVshxs
           3 WtbsJPHMDC
           3 TlxYoKbuWp
  
  10 rows selected
  
  Procedure GENERATE_ROWS dropped.
  Table MYTABLE dropped.
  

  and here is the vision of Tom Kyte for the same https://asktom.oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:2151576678914

  Edit: to improve my code, it must use p_count as bind as Tom.

• The date type of the column in the view

  Hello
  
  I would like to keep the start_date column type as a "date" type. But when create the view like below the type of the column is automatically set to varchar2 (11)
  
  {code}
  create table emp
  (digital emp_no
  , varchar2 (10) name
  start_date date);
  
  insert into the emp
  values
  (10, "Alan", January 1, 2010 "")
  insert into the emp
  values
  (20, 'Smith', may 12, 2000 ')
  
  create or replace view emp_v
  (emp_no
  first name
  start_date
  )
  as
  Select
  e.emp_no
  e.first_name
  , to_char (e.start_date, ' Mon-dd-yyyy "")
  from emp e
  {code}
  
  Thanks in advance
  Concerning
  Anna

  insert into the emp
  values
  (10, "Alan", January 1, 2010 "")
  insert into the emp
  values
  (20, 'Smith', may 12, 2000 ')

  you forcing oracle to convert string to date here - the best practice is to say explicitly what you mean with a to_date()

  the reason for which the view is created with a varchar column is that you explicitly convert a character with to_char() value, something you don't need as demonstrated above the column date.

• How do I edit/change data type on the report which has been selected by mistake

  
  Hello

  I've created a report in the APEX and a column is in error because the data type of a supposed to be a varchar2 column, but somehow the report was created with a data type Date. I want to change the data type without re-creating the whole report. Can anyone help? I tried to edit the report but could not be able to understand.

  Help...

  I found a solution for this, I thank you.

• How can I find what is the data type of a column of a Table in oracle or SQL?

  (a) what happens if I want to know the type of data in a specific column in the Table.

  (b) how to find the column data types?

  Can someone help me please. I am new to oracle and try to learn a few tricks

  Hello

  How to do

  SQL > desc

  SQL> desc emp
   Name                                      Null?    Type
   ----------------------------------------- -------- ----------------------------
   EMPNO                                     NOT NULL NUMBER(4)
   ENAME                                              VARCHAR2(10)
   JOB                                                VARCHAR2(9)
   MGR                                                NUMBER(4)
   HIREDATE                                           DATE
   SAL                                                NUMBER(7,2)
   COMM                                               NUMBER(7,2)
   DEPTNO                                             NUMBER(2)
  

• Disable the previous dating date picker in the column in a table

  can someone please help.

  on the date column in a table, need to disable previous dates.

  Current functionality. But when the validation page gets updated and the user is able to select earlier dates.

  
  

  
  

  To restrict the datePicker for new lines changed the URL of the button 'Add Row '.

  javascript:myAddRow();

  In the page edit, I added this to "Javascript > function and Variable global statement.

  function myAddRow()
  { apex.widget.tabular.addRow(); 
  $("td[headers='DETAIL_DATE'] input:last") 
  .datepicker("option","changeMonth",false) 
  .datepicker("option","minDate",$v("P2_MASTER_MONTH_MINDATE")) 
  
  .datepicker("option","maxDate",$v("P2_MASTER_MONTH_MAXDATE")); };
  
  https://Apex.Oracle.com
  w/u/p: nani5048/test/test
  App 92603 5 page
  Thank you
  Nani
  			 
  I created a dynamic action
  the loading of the page
  $("td [en-têtes = 'STATUS_DATE'] entrée")
  . DatePicker ("option", "minDate", $v ("P5_MASTER_MONTH_MINDATE"));
  as well as the global javascript function
  function myAddRow() {}
  apex.widget.tabular.addRow ();
  $("td [en-têtes = 'STATUS_DATE'] entrée")
  . DatePicker ("option", "minDate", $v ("P5_MASTER_MONTH_MINDATE"));
  }
  		   

• Disable previous Dates for date picker in the column in a table

  Hi all

  I'm in the form of the building where it contains details of the Transaction and I want to provide validations for start date and end date by disabling dates previous calendar datepicker.

  I wrote Javascript code in page load >service and global variables declaration:

  function f_disable_date(pThis){
      var row_id  = pThis.id.substr(4);  
      var start_date = $('#f02_'+row_id).val(); 
      
      //$(function() {
      $( "#f02_" ).datepicker({ minDate: -4});
  //});
  }
  

  But it is not disable dates. Please provide suggestion to make it work.

  APEX VERSION: 5.0

  Kind regards.

  See page 3

  I created a dynamic action

  real action on page load

  $("td [en-têtes = 'START_DATE'] entrée")

  . DatePicker ("option", "minDate", $v ("P3_X"));

  in P3_X

  matches the element hidden with select (sysdate-4) double value;

  its working fine

  But at the time of the Add_row()

  Just call it by making it as a javascript function so that it is also applicable to the new line

  I hope you got the point

• How 2 call a procedure with the data type for the parameter Ftree.NODE

  Hello
  
  in this link
  http://Andreas.Weiden.ORCL.over-blog.de/article-29307730.html
  
  
  Down in the page after you run the package, I created the procedure and it compiled successfully but when call PR_WTNS in trigger WHEN-TREE-NŒUD-SELECTED
  
  PROCEDURE PR_WTNE (i_ndNode IN Ftree.NODE);
  
  as
  
  PR_WTNE (i_ndNode Ftree.NODE);
  
  
  I got the error message; A wrong number or types of argument in the call
  
  pls I'm stuck can help any one?
  
  
  Kind regards
  
  Abdetu...
  
  Published by: Abdetu on October 24, 2010 02:36
  
  Published by: Abdetu on October 24, 2010 02:36

  YKou have to give a variable of type Ftree.NODE when calling this function. If called fromm a WHEN-TREE-NODE-SELECTED-trigger, use: SYSTEM. TRIGGER_NODE

• change data type...

  Hello...
  
  Change the data type of a column... replacement... it generates the error...
  

  ERROR at line 1:
  ORA-01439: column to be modified must be empty to change datatype 

  How can I change the data type of the column, without trucating and re - insert the records...
  
  Thank you
  Baskar.l

  Baskar.l wrote:
  Hello..

  is there a way to take the table offline? and do... rather than shoot the PB... Suppose that even if it is the activity less period... is the new records inserted when you change the column will be inserted in the new column?

  Thank you
  Baskar.l

  There is no need to bring the entire base down. Choose a time of low activity and go for it!

  If you are on 10g there is a chance that it will fail with an ORA-00054 as an exclusive table lock is necessary. If not you will have to try again.

  If you are in 11g, add a column does not require an exclusive lock, but drop the column will be even if the risk is always there.

  HTH!

• How to change the data type of a column after the creation of the table

  It comes to my table desc

  SQL > desc job1

  Name                                      Null?    Type

  ----------------------------------------- -------- ----------------------------

  JOB_CODE NOT NULL VARCHAR2 (3)

  JOB_CLASS VARCHAR2 (30)

  CHG_HOUR NUMBER (5.2)

  OVERTIMECHARGE NOT NULL NUMBER

  I want to change column CHG_HOUR to store numbers up to 12 digits in length (including the decimal points).

  I tried the following and it did not help

  SQL > alter table job1 change column chg_hour number (6.6);

  ALTER table job1 change column chg_hour number (6.6)

  *

  ERROR on line 1:

  ORA-01735: invalid option of ALTER TABLE

  SQL > alter table job1 change chg_hour number (6.6);

  ALTER table job1 change chg_hour number (6.6)

  *

  ERROR on line 1:

  ORA-01438: value larger than the precision specified for the column

  where I'm going wrong?

  Hello

  I want to change the CHG_HOUR column to store numbers up to 12 digits in length (including the decimal points).

  I tried the following and it did not help

  ALTER table job1 change chg_hour number (12.6);

• A question about the conservation of fields (hour, min, sec) time DATE type in the table on the changes of NLS_DATE_FORMAT

  Hello

  Oracle version: 12.1.0.1.0 - 64 bit

                    OS:   Fedora Core 17 X86_64

  My question is about the conservation of fields (hour, minute, second) time DATE type in the array on NLS_DATE_FORMAT changes.

  Take the following test case:

  SQL> create table tmptab(dateval date);
  
  Table created.
  
  SQL> alter session set nls_date_format = 'yyyy-mm-dd hh24:mi:ss';
  
  Session altered.
  
  SQL> insert into tmptab(dateval) values('2014-01-01 00:00:00');
  
  1 row created.
  
  SQL> insert into tmptab(dateval) values('2014-01-01 10:00:00');
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> select * from tmptab;
  
  DATEVAL
  -------------------
  2014-01-01 00:00:00
  2014-01-01 10:00:00
  
  SQL> alter session set nls_date_format = 'yyyy';
  
  Session altered.
  
  SQL> select * from tmptab where dateval > '2014';
  
  no rows selected
  
  SQL>
  

  I don't understand why it returns nothing. The second test case above insert statement inserted a line with 10 as the value for the time of the DATE field column dateval.

  Accordingly, while comparing this with the literal '2014' (which based on the new value of NLS_DATE_FORMAT = "yyyy" is implicitly converted to DATE), shouldn't the above query returns the line 2014-01-01 10:00 ?

  I mean, I changed the NLS_DATE_FORMAT but data from time in the table fields are preserved and that's why they should normally be taken into account in the comparison of date.

  What I'm trying to say is that for me (Please correct me if I'm wrong), no matter what NLS_DATE_FORMAT configuration is the following test

  SQL> select * from tmptab where dateval > '2014';
  

  is the same thing that

  SQL> select * from tmptab where dateval > to_date('2014-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss');
  

  And because the line 2014-01-01 10: 00:00 in the tmptab table. The following test

  2014-01-01 10:00:00 > to_date('2014-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')
  

  evolves normally true (beucase of TIME = 10 on the left side of the test) and therefore this line must be returned which is not the case in the test above.

  You kindly could you tell me what I misunderstood?

  Thanks in advance,

  This is the price for the use of implicit conversions. Implicit DATE conversion rules are not as direct as it can be assumed. In your case, all you provide is year as date format. In this case date implicit conversion rules assumes that month in the current month, day 1 and time as 00:00:00.

  SQL > alter session set nls_date_format = "yyyy";

  Modified session.

  SQL > select to_char (to_date ('2014 "), ' mm/dd/yyyy hh24:mi:ss') twice;

  TO_CHAR (TO_DATE('20)
  -------------------
  01/08/2014-00:00:00

  SQL >

  So, when you start:

  Select * from tmptab where dateval > '2014 '.

  Oracle implicitly converts date using "YYYY", which translates as August 1, 2014 '2014'. That's why your quesry returns no rows.

  SY.

• Display the data type of a column in the status bar

  Hi all

  n pl/sql developer, when I select a column in a table.

  If I clicked with the mouse on the column in the query results box, it shows me the type of data and the size of the column in the status bar

  Developer SQL does not by default,

  is there an option I can change to do the same task?

  Thank you

  No, you will need to open a popup DESC of the query to see the data types of the data returned.