Check the string

Similar Questions

• How let labview to check the string is in Scientific Notation.

  Hey all,.

  I want to labview to convert a worksheet string in a table. It's easy using the tool 'chain of worksheet to the table '. The only problem I have is that I get the string from a RS232 device and the critical moment arrives.

  Example:

  If I read the data from the buffer it gives me:

  1.50337800E + 00 + 1.70316300E + 00 for both channels, it is converted and accepted

  If there is a slight delay, I get:

  + 1.50337800E + 00 + 1.70316

  It is also accepted because + 1.70316 is also recognized as a number.

  How can program labview to check each number he reads is according to Scientific Notation?

  Thank you

  This regex seems to work for me, for all cases, I've tried:

  [+/-]\d+\.\d+[Ee][+/-]\d+

  Note that it is very restrictive and only follows the shape of ±n.nnnE±mm

• check the string number

  Hello

  In my application, TestStand receives a response from a DLL I give the floor. This DLL can return either a numeric value (casting in a string), as "120" or some sunk in a text string, as a "MISTAKE." I would like to make the test step fails, if the return string is NOT a number.

  Someone at - it a clues on how to do it? I tried something like an IsNumeric function, but couldn't find one.

  Jeroen

  Hello

  You can use the Val (string, ) function in an expression to convert your value chain. Check using this function.

• Check the string only Alpha characters

  Is there a function in ColdFusion that will check that a string of alpha only characters (not digital or for example &, $, etc.)? I try to avoid creating a string of alpha characters or all all nonalphanumeric characters to loop on and the text is authoritative.

  Which could easily be done with a regular expression using REFIND() function search.

  Something like that on the top of my head and untested example.  REFIND("[^A-Za-z]",yourStringVar).  If that returns true then we characters other characters then alpha in the chain.

• Check the string value when using xdoxslt

  Hello

  I'm new to the BEEP and will have questions in writing this simple code for a model RTF. In plain language, that's what I want to do:

  If (instr(FirstName,'concern',0) > 0 and instr(LastName,'concern',0) > 0 and instr(MiddleName,'concern',0) > 0) then the VNAME variable value "

  on the other

  If (instr(LastName,'1-',0) > 0), then set VNAME variable FirstName

  on the other

  the value of VNAME variable FirstName + "" + name

  Finally... show the VNAME variable

  ===========

  I wrote it, but it doesn't work:

  declared variable... Initialize it to x.

  <? xdoxslt:set_variable($_XDOCTX,_'v_RTPMName',_'x')? >

  String value of control-> - error.

  <? If: (xdoxslt:Instr (lower(coFirstName|| coMiddleName || coLastName), "abuses", 0) > 0)? >

  <? xdoxslt:set_variable($_XDOCTX,_'v_RTPMName',_'')? >

  <? end if? >

  write the variable

  <? xdoxslt:get_variable($_XDOCTX,_'v_RTPMName')? >

  Thanks for the help!

  For a quick overview,.

  InStr is belong to the xdofx family, must be used in this way instead of xdoxslt:Instr()

  For example: If condition 1 0 otherwise true back

  0 then 1 or 0 end if? >

• JavaScript to check the value of the Textbox

  Hi all
  
  I have a few simple javascript in the header of my page to check the value of an element... There is no errors in Firebug, but the alert window is also never coming.
  

  if ($v('P2_ITEM') == 'VALUE1')
  {
  alert('VALUE1');
  }
  if ($v('P2_ITEM') == 'VALUE2')
  {
  alert('VALUE2');
  }
  if ($v('P2_ITEM') == 'VALUE2')
  {
  alert('VALUE2');
  }

  Thanks for any help.

  Use double quotes in JS to check the string values:

  function test_choice()
  {
  if ($x('P2_ITEM') == "Test1")
  {
  alert("Test1");
  }
  if ($x('P2_ITEM') == "Test2")
  {
  alert("Test2");
  }
  if ($x('P2_ITEM') == "Test3")
  {
  alert("Test3");
  }
  }
  

• function to check the alphanumeric string of pan card

  for example a pan card number ' * AAFCQ4563U *'
  
  I wan to create a function that checks the first 5 digits as capital alphabets and total length of the string is 10.
  
  Published by: arnaud August 2, 2011 22:45

  Hi Arnaud,.

  As already mentioned by Barend, you should always put the version number that you are using. You can use the REGEXP_LIKE expression to get the desired result. The TANK contains also the first 5 digits as the alphabets, nest 4 numbers and the last one like alphabet still once, then you should check the chain rest as well.

  You can try. It works fine on Oracle 10 g and Oracle 11 g version 10.2.0.4 and 11.2.0.1.

  CREATE OR REPLACE FUNCTION validate_pan_num (pan IN VARCHAR2)
     RETURN VARCHAR2
  AS
  BEGIN
     IF (REGEXP_LIKE (pan, '[A-Z]{5}[0-9]{4}[A-Z]{1}') AND LENGTH (pan) = 10)
     THEN
        RETURN 'true';
     ELSE
        RETURN 'false';
     END IF;
  END;
  

  Kind regards
  Ankit

• Check if the string is a number

  I need to check if a string is entered in a textinput control is not a number and do something. I tried
  
  If ((object.text is Number) == false) {}
  error = true;
  }
  
  But this does not work, I tried google, but didn't find anything useful.

  I think I'll go with the regex solution, even if it still does not work: s

  It always returns true even if it has an 'a' or so in it. It seems to only do that when the 'a' is NOT in front of the string.

  EDIT: found on google: var expression: RegExp = / ^ [0-9] + $/;

  Thank you for you answer and help me :)

• How to check the value of a string is numeric, alphanumeric or characters?

  Hi all
  I have a task to validate an employee ID, assume that the employee Id is E121212. Now according to the validation rule, I need to check "the first letter of the employee Id is a character and rest are numbers." How can I do this? Please answer.
  
  
  
  Thanks and greetings
  Marie Laurence

  Hello

  You can opt for regexp_like in this case. See the code below

  with data as (
    select 'E121212' s from dual union all
    select '121212' from dual union all
    select 'EE121212' from dual union all
    select 'EE1212EE' from dual union all
    select 'É121212' s from dual
  )
  
  select
  *
  from data
  where
  regexp_like (s, '^[A-Z]\d+$')
  
  S
  E121212 
  

  ^ [A-Z] means that, at the beginnign (^), should be only between A - Z characters, uppercase. If you want to add lowercase letters, you can easily replace it [A-Za-z]. \d is a symbol for the numbers and + means it must complete at least one or more of her. $ means the end, so he stayed there until the end but nothig figures.

  If yoou want characters as allowed, you can change the character class to [: alpha:]

  select
  *
  from data
  where
  regexp_like (s, '^[[:alpha:]]\d+$')
  
  S
  E121212
  É121212 
  

  concerning

  Published by: chris227 on 26.07.2012 00:53
  fix

• How to check the length of the string (from viewobject) attribute on jspx?

  Hello
  
  JDEV: 11.1.1.4
  
  I use the component of the carousel, inside, I use the Description attribute to display the content about to carousel,
  Now, I want to display a link as well, whenever the length of the description is longer than 150 characters.
  
  Currently backing bean that I am setting the property chklength to true or false, but the problem, the length is that I need a partial target
  and that's my Carousel component I get updated every time... is possible to check the length in page jspx itself inside the vissible property
  
  This is my code
  

  <af:outputText value="#{item.bindings.Descrip.inputValue}"
                                                           id="ot49"/>
                                             <af:commandImageLink text="more.." id="moreid" shortDesc="click to see more.." 
                                                                   visible="#{pageFlowScope.chklength}">
                                              <af:showPopupBehavior popupId="::p1"/>
                                              </af:commandImageLink>              

  Thank you
  Guillet

  You can try with # instead of $?

  visible = "#{FN: length (Item.Bindings.descrip.inputValue) > 150} '"

  Thank you
  Nini

• Bug: Find/replace does not work if the statement contains the string is too long

  Hello

  in my sequence, I press Ctrl + F to open the Find dialog box and enter a string. All the checkboxes are checked 'Elements for search' and ' limit the search to "is not enabled.

  Now comes the finding it is only announcing the discovery in the main sequence.

  Other places in a sous-suite that are part of a labview vi action setting is not in the list. Also if I open the sequence and I'm looking at this place.

  If I create a comment in the subsequence containing the searchstring, then it is.

  When I open the properties of the action of labview and open the parameter that contains the string and click on check for errors, and then close all and supplementary search then the value lies.

  Is it possible that the variable is too long setting? It's about 200 characters and one thing very nested SationGlobals and the table and the TestSockets. Search string Dees is finally an arrayindex in this grand statement.

  It seems that this is the problem.

  Is this a known bug?

  Solved.

  There was an empty character at the end of the search string...

• define the string as "empty" or "nothing".

  Hello

  I know that one can define a number such as "NaN" - that's great, because it's a great way to check the weather, the variable is still filled. But is possible to do something similar with string? Something as string = "empty" or "nothing"...

  Thanks for your help

  Jonathan K.

  There is a Len() function for strings. What about assigning "" the strings and given a string with Len() = 0 as empty?

• With the help of the function of worksheet to convert the string in table 1 d

  Hello to all 2!

  I have the following problem: I have a string (which I have read in a txt file), and using the chain of worksheet to the array function, I want to turn this string in a table 1 d of double. MY PROBLEM is that the resulting string is only the first element. How I see the other items too?

  4 thank you for your time!

  P.S. I use LabView 8.5.1. Windows XP SP 2

  Check the code below:

  

  or only one solution: (do not know why Path2 showed up to... ignore her...)

  

• How can I get the installer for my application check the operating system type and then install the correct driver type?

  I have a request that I wrote and have been use and distribute for awhile. The installer I created for this application is an additional installer to install a driver for the USB connection. The USB connection is actually a virtual COM Port. The problem is that the people who drafted modified driver setup the installation program itself. They used to have an installer that would check for 32-bit or 64-bit OS and then install the appropriate driver.

  Now, they have two distinct installation programs: one for the other for 32-bit and 64-bit. They let the user know their OS and install the appropriate driver. I'd rather not have to rely on my users to do. From what I've seen the creater Installer provides that an executable to be run after the application installs.

  Is it possible to have the installer of the application, check the type of OS and then run the correct executable file after installing my application? I think that I could write an Installer 'wrapper' that checks the type of operating system then executes the correct Installer. But I expect a better solution.

  Thank you
  Joe

  So, I make it work!

  The trick is to find a way to determine what type of OS you are using. The method I used was, indeed, read the environment variable. A buddy of mine sent me this link:

  http://StackOverflow.com/questions/2401756/how-to-find-if-the-machine-is-32bit-or-64bit One of the phrases he bibliography the Processor_Architecture environment variable.

  It seemed like a reasonable idea. So I started to research how read LV it environment variables turns out, you do it by reading a registry key. There is an example of LV on how to read a registry key. But I did not know where they are in the registry. So, I searched the Processor_Architecture registry. I found it in HKEY_LOCAL_MACHINE\SYSTEM\ControlSet001\Control\Session Manager\Environment.

  According to the article in the link, this value will already be x 86 for a 32 bit OS, or something with 64 inside. I just check the response for x 86 string. If it is, I just run the x 86 version of the driver Installer. Otherwise, I run the x 64 version.

  It turned out to be as simple as that.

  I hope this helps someone.

  Joe

• Looking for a pattern in the string

  Hi all

  I have a string input that consists of a number. 5 numbers separated by semmicolon represents a set. The numbers may be of the numbers 2, 3, or 4 digits.

  And there could be 1, 2, 3 or 4 sets. How can I check if one of all of the entry contains a 0; 0; 0; 0; 0.000;?

  I tried to use first Match string and string /False true Match. But string true or false game looks at only the beginning of the string.

  Can anyone suggest some ideas hw to go forward?

  Hi Nightcrwlr,

  Why don't you use SpreadsheetStringToArray and just check the number of items in the table to separate your 'sets '?

  

  After splitting sets (ArraySubset), you can just compare each set to zero...