Columns separated by commas

Oracle 10.2.0.1
Windows XP

I have a table that stores the data of our customers. When I said:

Select city, city_code as CS, count (*) as the early group of customers by city, city_code:
It returns:
CITY                                     CS        TOT
---------------------------------------- -- ----------
Delhi                                    01         23
Bangalore                                02         36
Mumbai                                   03         33
Hyderabad                                04          8
Jaipur                                   00          2
Patna                                    00          1
Chennai                                  05        114
Power required:
CITY                                     CS        TOT                        IDS
---------------------------------------- -- ----------     ----------------------
Jaipur                                   01          2                    393,405
Patna                                    02          1                        200
Means that if Tot for a city is between 1,5; I want to get these IDS to customer (from the customer table itself)
separated by commas as above, so that I can know who are the customers, because all the
cities whose number is < = 5, there are errors in the name of the city.

Thank you.

NOT TESTED! not having do not have database access

select city,city_code,tot,substr(sys_connect_by_path(to_char(customer_id),','),2) ids
  from (select c.customer_id,c.city,c.city_code,e.tot,
               row_number() over (partition by c.city,c.city_code order by customer_id) the_row
          from customers c,
               (select city,city_code,count(*) tot
                  from customers
                 group by city,city_code
                 having count(*) <= 5
               ) e
         where e.city = c.city
           and e.city_code = c.city_code
       )
 where connect_by_isleaf = 1
 start with the_row = 1
 connect by prior the_row + 1 = the_row
        and prior city = city
        and prior city_code = city_code
        and prior tot = tot

Concerning

Etbin

Tags: Database

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TABLE_NAME                     COLUMN_NAMES
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Elapsed: 00:00:00.01

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    and PC_FLAG = 'C';



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    Thanks in advance.


    Kind regards

    SB2011



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    PC_FLAG,

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    PLATFORM,

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    PC_FLAG,

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  • have a column that has values separated by commas... and I'm s

    Have a column that has values separated by commas... and I'm trying to separate.
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    cursor cx is with testa as
    (select name of the advertiser pagenumber)
    Select regexp_substr (pagenumber, ' [^,] +', 1, rownum) result
    the advertiser
    connect by level < = length (regexp_replace (pagenumber, ' [^,] + "")) + 1
    where advt_no = madvtno;


    Start
    for xxx CX
    loop
    insert into adv_invoice (magazine_no, advtno, adissue, section, opinion, salesman_code)
    values (mmagazine_no, madvtno, missueno, msection, xxx.result, msalesman_code);

    end loop;

    end;


    But when I run the present... it creates no procedure. . I receive he following error...
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    -------- ----------------------------------------------------
    5/14 PL/SQL: statement ignored
    9/69 PL/SQL: ORA-00933: SQL not correctly completed command
    SQL >
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    Change the query to swap the last two lines:

    ...
cursor cx is with testa as
(select pagenumber name from advertiser)
select regexp_substr(pagenumber, '[^,]+', 1, rownum) result
from advertiser
where advt_no = madvtno
connect by level <= length(regexp_replace(pagenumber, '[^,]+')) + 1;
...

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    Dear members

    Please give me the solution for the below question

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    Ename product
    A 1,2,3
    B 1,2,3


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    Output should be like this.

    Ename, product
    A 1
    A 2
    A 3
    B 1
    B 2
    B 3

    Can we get the output above using just Oracle SQL select statement?
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    Welcome to the forum.

    Here is another interesting site, with lots of useful examples:
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    Also, be sure to read the SQL and PL/SQL FAQ:
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  • Select the column of values such as 1 row of values (separated by commas)

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union all 
select '2063' as bacc from dual
union all 
select '2072' as bacc from dual
union all 
select '2073' as bacc from dual

    http://rogertroller.blogspot.com/2009/10/5-ways-to-aggregate-columns-into-comma.html

    There is an option is missing... the new oracle 11g listagg function

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  • SQL - Multiple Fetch in a single column with a comma separator

    Hello Experts,
    Good day to all...

    I need your help on the following scenarios. The following query returns all channels titleID. Rather than print them one under the other as a result of the query, I want the output to be in the batch of 25 values.i.e than each line must have 25 values separated by commas. IE if there are 100 titles satisfying the output, then there should be only four lines with and each line with 25 titles in comma separated way.
    SELECT DISTINCT title_id
           FROM pack_relation
          WHERE package_id IN (      SELECT DISTINCT fa.package_id
                                                FROM annotation fa
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DECLARE
   v_str   VARCHAR2 (32767)  := NULL;

   CURSOR c1
   IS
     SELECT DISTINCT title_id
           FROM pack_relation
          WHERE package_id IN (      SELECT DISTINCT fa.package_id
                                                FROM annotation fa
                                            GROUP BY fa.package_id
                                              HAVING COUNT
                                                        (fa.package_id) <100);
BEGIN
   FOR i IN c1
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      v_str := v_str || ',' || i.title_id;
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   v_str := SUBSTR (v_str, 2);
   DBMS_OUTPUT.put_line (v_str);
EXCEPTION
   WHEN OTHERS
   THEN
      DBMS_OUTPUT.put_line ('Error-->' || SQLERRM);
END;
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    You can use CEIL

    Code example

    SELECT
    nt,
    LTRIM(MAX(SYS_CONNECT_BY_PATH(val,',')) KEEP (DENSE_RANK LAST ORDER BY curr),',') AS concat_val
FROM
    (
        SELECT
            val,
            nt,
            ROW_NUMBER() OVER (PARTITION BY nt ORDER BY val)    AS curr,
            ROW_NUMBER() OVER (PARTITION BY nt ORDER BY val) -1 AS prev
        FROM
            (
                SELECT
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                    ceil(rownum/3)  as nt /* Grouped in batches of 3 */
                FROM
                    dual
                    CONNECT BY level <= 10
            )
    )
GROUP BY
    nt
    CONNECT BY prev = PRIOR curr
AND nt              = PRIOR nt
    START WITH curr = 1;

        NT CONCAT_VAL
---------- --------------------------------------------------------------------------------
         1 1,2,3
         2 4,5,6
         3 7,8,9
         4 10

    Your code

    SELECT
    nt,
    LTRIM(MAX(SYS_CONNECT_BY_PATH(title_id,',')) KEEP (DENSE_RANK LAST ORDER BY curr),',') AS concat_val
FROM
    (
        SELECT
            title_id,
            nt,
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            ROW_NUMBER() OVER (PARTITION BY nt ORDER BY title_id) -1 AS prev
        FROM
            (
                SELECT
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                FROM
                    pack_relation tdpr
                JOIN annotation fa
                ON
                    tdpr.package_id = fa.package_id
                GROUP BY
                    title_id,
                    fa.package_id
                HAVING
                    COUNT (fa.package_id) < 500
            )
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GROUP BY
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    CONNECT BY prev = PRIOR curr
AND nt              = PRIOR nt
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    rsMakeFromString: creates a column of a result set of a string.

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    Jonathan
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  • How to store the values separated by commas

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   l_input   VARCHAR2 (4000) := '123,27890,3543';
   l_count   BINARY_INTEGER;
   l_array   DBMS_UTILITY.lname_array;
BEGIN
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      list     => REGEXP_REPLACE (l_input, '(^|,)', '\1x'),
      tablen   => l_count,
      tab      => l_array);
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   FOR i IN 1 .. l_count
   LOOP
      DBMS_OUTPUT.put_line (
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         || TO_CHAR (i)
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END;

Result:
3
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Element 2 of array contains: 27890
Element 3 of array contains: 3543
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                     UNION all
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    Hello

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    Sudhir

    Try this...

    / * code deleted after suggested by BluShadow * /.

    I'll post other methods of String-aggregation...
    Try this...

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from xx
group by emp_name
order by cnt desc;

    For versions > 11g Release 2

    select
    emp_name,
    count(*) cnt,
    LISTAGG(client_name,',') WITHIN GROUP(ORDER BY NULL)
from xx
group by emp_name;

    Published by: Vanessa B on 7 December 2012 18:50
    -adding code

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