Print data with Format separated by commas.

Similar Questions

• problem with column separated by commas

  I'm running into a problem with the following table structure

  CREATE TABLE «DETAILS»

  (

  'ID' NUMBER (22.0) NOT NULL,

  VARCHAR2 (150 CHAR) 'NAME' NOT NULL,

  "COVER" VARCHAR2 (150 CHAR) NOT NULL

  );

  Insert into EXPORT_TABLE (ID, NAME, COVER) values (252613546, 'VCONBU', ', 252612938,');

  Insert into EXPORT_TABLE (ID, NAME, COVER) values (252613549, 'SPMABU', ', 252612932,');

  INSERT INTO EXPORT_TABLE (ID, NAME, COVER) VALUES (252612938, 'HOSTEDTG', NULL);

  Insert into EXPORT_TABLE (ID, NAME, COVER) values (252612932, 'INSTG', null);

  Insert into EXPORT_TABLE (ID, NAME, COVER) values (367708813, 'ICF_1', ', 252613546,');

  Insert into EXPORT_TABLE (ID, NAME, COVER) values (364413059, 'CSWSPT', ', 252613549,');

  commit;

  Output

  ID	NAME	COVER
  252613546	VCONBU	HOSTEDTG
  252613549	SPMABU	INSTG
  252612938	HOSTEDTG
  252612932	INSTG
  367708813	ICF_1	VCONBU
  364413059	CSWSPT	SPMABU

  Hello

  You may want a self-join, like this:

  SELECT c.id

  c.name

  p.name AS cover

  Of export_table c

  LEFT JOIN export_table p WE «,» | p.ID

  || ',' = c.lid

  ;

• AS %s with entry separated by commas

  I'm trying to get a recordeset WHERE the nameArtist of the column 'contains' the 'artist' URL parameter For example, if 'Picasso' is in the parameter and then he must find all projects whose Picasso worked on. The problem is that often the nameArtist column contains an artist for example "Mondrian, Picasso, Chagall. He should always filter this project.

  I tried with LIKE, but that does not give the projects when there are more artists.

  I hope someone can give me a tip I did wrong here... Thankx.

  $colname_rsAllprojects = "-1";
  if (isset($_GET['artist'])) {
    $colname_rsAllprojects = $_GET['artist'];
  }
  mysql_select_db($database_connCasco, $connCasco);
  $query_rsAllprojects = sprintf("SELECT * FROM `2008_content` WHERE nameArtist LIKE %s ORDER BY projectyear DESC", GetSQLValueString($colname_rsAllprojects, "text"));
  $rsAllprojects = mysql_query($query_rsAllprojects, $connCasco) or die(mysql_error());
  $row_rsAllprojects = mysql_fetch_assoc($rsAllprojects);
  $totalRows_rsAllprojects = mysql_num_rows($rsAllprojects);
  

  Brégent is correct. You must put % before and after the value you're looking for. However, put just like it in the SQL query won't work, because Dreamweaver use sprintf() to pass the value to a custom named GetSQLValueString() function to prevent the injection of SQL code. The % must be added to the value passed to GetSQLValueString().

  Dreamweaver doesn't automatically when you add them % to the variable in the SQL of the advanced Recordset dialog box. However, I seem to remember that the way you did in the dialog box has changed in CS3 or CS4. No matter which version you use, it should work in all versions if you edit the PHP code like this:

  $query_rsAllprojects = sprintf("SELECT * FROM `2008_content`WHERE nameArtist LIKE %s ORDER BY projectyear DESC", GetSQLValueString("%" . $colname_rsAllprojects . "%", "text"));
  

• Extract values separated by commas in xquery string

  Hello
  
  We get a string with values separated by comma Ex: a, b, c.
  
  Our requirement is to mark the string and transform values to an XML using xquery.
  
  I'm new to xquery. Can someone help me on this please.
  
  Thank you
  Chauvin

  Hi Jacky,.

  You can use the function "mark".
  For example:

  let $str := "a,b,c"
  return 
  {
   for $i in tokenize($str,",")
   return     { $i }
  }
  
  

  will return:

  
     a
     b
     c
  
  

• Splitting data separated by commas

  Hi friends,

  I have a few million records that must be formatted as data and need your help with this.

  Actual data in the csv file:

  «30375516451 ',' June 3, 2013 23:31:33 ","June 4, 13"," Tag #: 2490544Sharjah - White 33708 ", 'Al Garhoud bridge nine', 'Abu Dhabi', '4.00»»'

  Value using request, separated by commas:

  Select

  Replace (replace (replace (replace (test_value,'"', null"), chr (13), null), chr (160), null), chr (10), null) "test_value"

  of the test

  where to_number (length (test_value) - length (replace(test_value,',',''))) in (3.6);

  Output:

  30375516451, 03-Jun-2013 23:31:33, 4 June 13, Tag #: 2490565Sharjah - white 33708, new Al Garhoud bridge Abu Dhabi, 4.00

  Need to change a part with highest result of the query to make it entirely comma separated:

  Tag #: 2490565Sharjah - White 33708,.

  Output:

  2490565, Sharjah, 33708 white,-remove the space before the comma: white 33708,.

  Power required:

  30375516451, 03-Jun-2013 23:31:33, June 4, 13, 2490544, Sharjah, white 33708, Al Garhoud new bridge, Abu Dhabi, 4.00

  Sample data:

  CREATE TABLE TEST (TEST_VALUE VARCHAR2 (4000));

  INSERT INTO TEST VALUES (' "30375516451","June 3, 2013 23:31:33", "June 4, 13","Tag #: 2490565Sharjah - White 33708", "Al Garhoud bridge nine", "Abu Dhabi", "4.00" ' ");

  Thank you

  with the trial as)
  Select "" 30375516451 ',' June 3, 2013 23:31:33 ","June 4, 13"," Tag #: 2490544Sharjah - 33708 white ', 'Al Garhoud New Bridge', 'Abu Dhabi', '4.00' ' test_value»
  of the double
  )
  Select regexp_replace)
  regexp_replace)
  test_value,
  '( *")| [' || Chr (13) | Chr (160) | Chr (10) | ']',
  NULL,
  1,
  0,
  « n »
  ),
  'Tag #:(\d+)(.+) - ([^,]+)',
  '\1,\2,\3 '.
  ) test_value
  of the test
  /

  TEST_VALUE
  --------------------------------------------------------------------------------------------------------------
  30375516451, 03-Jun-2013 23:31:33, 04-Jun-13, 2490544, Sharjah, White 33708, new Al Garhoud bridge Abu Dhabi, 4.00

  SQL >

  SY.

• Display data in the form of values separated by commas - need help

  Hi all
  
  I have some data formatted in the way below. The ID of the drug are the primary keys of the table and the first 9 digits in the drug ID are the same. They can be separated based on the last two digits.
  
  Type of drug drug ID
  00603107554 respiratory
  00603107556 cough and cold
  Antitussive-00603107558
  
  
  I want that data to be formatted as
  Type of drug drug ID
  006031075 respiratory, cough and colds, Antitussive
  
  I want to cut the last two characters, and format data. And the types must be displayed in the form of values separated by commas. Can someone help me?
  
  Thanks in advance
  
  Rambeau

  WITH t AS (SELECT '00603107554' Drug_ID, 'Respiratory' Drug_Type FROM DUAL
             UNION
             SELECT '00603107556', 'Cough and Cold' FROM DUAL
             UNION
             SELECT '00603107558', 'Antitussive' FROM DUAL)
      SELECT Drug_id, SUBSTR (SYS_CONNECT_BY_PATH (Drug_Type, ','), 2) Drug_Types
        FROM (SELECT SUBSTR (drug_id, 1, LENGTH (drug_id) - 2) drug_id,
                     Drug_Type,
                     ROW_NUMBER ()
                     OVER (PARTITION BY SUBSTR (drug_id, 1, LENGTH (drug_id) - 2)
                           ORDER BY Drug_Type)
                        rn
                FROM t)
       WHERE CONNECT_BY_ISLEAF = 1
  START WITH rn = 1
  CONNECT BY PRIOR rn = rn - 1 AND PRIOR drug_id = drug_id
  

  DRUG_ID     DRUG_TYPES
  006031075     Antitussive,Cough and Cold,Respiratory
  

  just a note, I wonder if blushadow could consider adding techniques agg string to its very useful faq section because it seems a good
  request.

  Published by: pollywog on April 14, 2011 06:42

  Published by: pollywog on April 14, 2011 06:43

• How to print an entry separated by commas

  I would like to print an entry separated by commas to separate entries:

  Like when I put like <? PHP echo $row_rsContent ['artists'];? > I get: 'Picasso, Chagall, Matisse,' but I want like "Picasso < br > < br > Matisse to Chagall.

  And I also want to 'Picasso' a link to another Web site.

  Thanks for any help of furthre.

  Pass your variable to explode() to make a table. Then do what you want with each item.

  $artists = explode(',', $row_rsContent['artists']);
  echo '' . $artists[0] . 
  ';
  echo $artists[1]. '
  ' . $artists[2] . '
  ';
  

• When I view my Photos, they have a place and a date. How can I print them with that on them?

  When I view my Photos, they have a place and a date. How can I print them with that on them?

  You want to print the information on the image itself?  To do this, you will need to export the picture on the desk and edit it with a 3rd party image editor that supports the text and layers:

  Some Image editors that support layers and text:

  
  

  Photoshop Elements for Mac 11 - $79

  GraphicConverter - $40
  The Rainbow painter - $30

  Photos of affinity- $50

  FX Photo Studio - $30

  Inpaint - $20
  Imaging - $38
  Acorn - $50

  Pixelmator - $60

  Seashore - free

  GIMP for Mac - free (Yosemite & Mavericks only)

  

• LaserJet 4000 printing error with USB/parallel interface and DATA light on at all TIMES

  Laptop Dell Vostro 3700, Windows 7/32, Laserjet 4000, connected via the USB interface cable / parallel on USB001. Interface drivers and printer installed automatically after starting the update of Windows PC.

  Single document print OK.

  Document of several pages: printer data LED flashes then REMAINS ON permanently. Printed front page sometimes, sometimes not.

  After some time, box status Control Panel/print poster printer fault and a yellow exclamation point appears on the printer icon.

  No possible mistake OK with MS print Fixit. No other printing possible before initialization of the PC and then to new as shown above.

  Same printer connected via a parallel cable that is normal for old PC Windows 2000 print OK.

  Help, please!

  SOLUTION FOUND!

  A SOLUTION THAT WORKS: add only DC powered USB hub and connect the printer to one of the ports of the hub-s. Let Windows install the drivers for the USB cable and printer and printing is perfect!

  It is that the laptop USB ports do not have enough current or voltage, especially if some other USB devices are connected to the laptop...

• Problem with display Inlines for comma separated output (horizontally)

  Hi all
  
  It's my XML data,
  
  -< EMP_IDS >
  -< > 10001 EMP_ID < / EMP_ID >
  -< > 10002 EMP_ID < / EMP_ID >
  -< > 10003 EMP_ID < / EMP_ID >
  -< > 10004 EMP_ID < / EMP_ID >
  -< > 10005 EMP_ID < / EMP_ID >
  -< / EMP_IDS >
  
  I show all emp_ids in a single horizontal line, separated by commas, using this code
  
  10001,10002,10003,10004,10005.
  
  
  <? xdoxslt:set_variable($_XDOCTX,'C',count(.//EMP_ID))? > <? for-each@inlines:EMP_ID? > <? ? >
  <? If@inlines:position ()! = xdoxslt:get_variable($_XDOCTX,'C')? >, <? end if? >
  <? If@inlines:position () = xdoxslt:get_variable($_XDOCTX,'C')? >. <? end if? >
  <? end foreach? >
  
  Question: What I want is that when my EMP_ID = ' 10002 "should NOT be displayed, so I want the output to be
  
  10001,10003,10004,10005.
  
  I am unable to code this, is there any way by which I can take the value 10002 in a variable and use an if statement to not show this value?
  
  Help, please.
  
  Thank you
  Ronny

  can u try this

• Problem using the list separated by commas with nested table element

  Hello
  
  I have a list separated by commas like this:

  H23004,H24005,T7231,T8231,T9231

  And want to create a function that creates a where clause clause for each element with an output like this:

  UPPER('H23004') IN (UPPER(charge))
  OR UPPER('H23005') IN (UPPER(charge))
  OR UPPER('T7231') IN (UPPER(charge))
  OR UPPER('T8231') IN (UPPER(charge))
  OR UPPER('T9231') IN (UPPER(charge))

  Here's my test function that is not working properly:

  create or replace function FNC_LIST_TO_WHERE_CLAUSE(v_list in VARCHAR2) return varchar2 is
   -- declaration of list type
   TYPE batch_type IS TABLE OF pr_stamm.charge%TYPE;
   -- variable for Batches
   v_batch batch_type := batch_type('''' || replace(v_list,',',''',''') || '''');
   return_script varchar2(1000);
  
   BEGIN
   -- loop as long as there are objects left
   FOR i IN v_batch.FIRST .. v_batch.LAST
   LOOP
     --DBMS_OUTPUT.PUT_LINE(offices(i));
     -- create where clause
     IF i = 1 THEN
       return_script := 'UPPER(' || v_batch(i) || ') IN (UPPER(charge))';
     ELSE
       return_script := return_script || ' OR UPPER(' || v_batch(i) || ') IN (UPPER(charge))';
     END IF;
   END LOOP;
  
   return (return_script);
   end;

  The out put looks like this:

  UPPER('H23004','H24005','T7231','T8231','T9231') IN (UPPER(charge))

  I don't know what I did wrong? It calculates the amount of the incorrect array element! (v_batch. Must be 5)
  v_batch. FIRST = 1
  v_batch. LAST = 1
  
  Kind regards
  
  Tobias

  Try this...

  declare
  text varchar2 (1000): = "H23004, H24005, T7231, T8231, T9231;
  v_where varchar2 (1000);
  Start
  Text: = text | «, » ;
  While instr (text, ',') <> 0
  loop
  v_where: = v_where | ' UPPER ("': substr (Text, 1, InStr(Text,',',1)-1) |") ' IN (UPPER (load)) OR ';
  text: = substr (text, instr(text,',',1) + 1);
  end loop;
  v_where: = substr (v_where, 1, length (v_where)-3);
  dbms_output.put_line (v_where);
  end;

  convert it to function...

• Separation of data with multiple headers

  Hello

  I have a data set that has 6 columns with headers containing information for a cycle of some (data file is attached). About 200 lines later, so that I have a different set of data with 6 columns cycle 2 with a space and a new header and any other 400 lines later I data for cycle 5 with a space and a new header. This pattern is repeated throughout the data set.

  I need a way to separate this data so that I can trace different cycles. When I import this data set in Diadem with the Wizzard use it does not recognize the spaces and the new headers. He label spaces and headers "NO value", there are discontinuities in the data. Is there a way to separate the cycles in this dataset in tiara?

  For example, I would have 215 lines thru 220 630 thru 6 lines, lines 635 thru 1046, lines 1051 to 1462, etc.. This way I can trace different cycles against the execution time.

  Hi wils01,

  Here's a use I created that loads your file data in each cycle in a separate group of the data portal.

  Brad Turpin

  Tiara Product Support Engineer

  National Instruments

• Order by date with a format mask column

  10g - 10.2.0
  
  Hello
  
  This is my request
  

  select to_char(exp_Date,'Mon-YYYY') dt, count(*) from exp_main
  where exp_type like 'Income%Photo%'
  group by to_char(exp_Date,'Mon-YYYY')
  order by exp_date
  
   

  When I run this I get: not a GROUP BY expression
  
  If I remove the order by, it works fine.
  
  Is it possible to order by since the output of the query is sorted character.
  
  I search online most suggested to use the order of column_name. But does not work for me.
  
  Thank you!
  Ryan

  Hello

  Keep the date information as a DATE, with the exception (if required) for display. That means that GROUP BY and ORDER BY DATE, not a string:

  SELECT    TO_CHAR ( TRUNC (exp_Date, 'MONTH')
                , 'Mon-YYYY'
              )          AS dt
  ,       COUNT (*)           AS cnt
  FROM        exp_main
  WHERE        exp_type     LIKE 'Income%Photo%'
  GROUP BY  TRUNC (exp_Date, 'MONTH')
  ORDER BY  TRUNC (exp_date, 'MONTH')
  ;
  

• With the help of a string of separated by commas as lines

  HT a column in which I store the name separated by commas, I have to show them that the lines in a report...
  Help, please

  Check out this link...

  http://nimishgarg.blogspot.com/2009/12/Oracle-SQL-use-comma-seprated-string-to.html

• Build the string separated by commas in query with Expression box sub

  Oracle 10g on Windows XP
  
  Consider the following query:
  
  Select batch_id, tr state_tag_seq where request_type in (select case WHEN PX = 'RETURN' AND 'TRANSFER' |) «, » || "PUBLIC TRANSIT"
  WHEN PX = "RFT" THEN "TRANSIT".
  ELSE 'Invalid '.
  END
  OF THE DOUBLE
  ) ;
  
  
  In this case, PX is accepted to execution of the user interface.
  
  I'm having no rows returned (all valid lines matching in DB) for the following case assessment
  
  WHEN PX = 'RETURN' THEN 'TRANSFER '. «, » ||' Transit "(PX when is evaluated to 'RETURN')
  
  The application works well when it px IS estimated to be "PCR" (as the evaluated expression is just a string ('TRANSIT') single, not separated by commas, as in the other case)
  
  Hiow do rewrite this query, if it gives a correct result? In other words, I actually build the query string slot, which is assessed by the external when query clause.
  
  I think it might be a specific way to use quotes in my case expression, but I'm reaching an impasse. Any help is appreciated.
  
  Thank you
  SR

  You can try

  select batch_id, state_tag_seq
    from tr
   where request_type member of case
                           when px = 'RETURN'
                           then
                            sys.dbms_debug_vc2coll (
                             'TRANSFER',
                             'TRANSIT'
                            )
                           when px = 'RFT'
                           then
                            sys.dbms_debug_vc2coll ('TRANSIT')
                           else
                            sys.dbms_debug_vc2coll ('Invalid')
                           end