Combination of several lines into one

Similar Questions

• Representing data of several lines into one line

  Hi all
  
  Please check the query below:
  

  select manager_id mg_id, employee_id emp_id, last_name name from employees 
  where manager_id = '100'
  and DEPARTMENT_ID = '80'

  If I run the following query, o/p then comes wise line; as below:
  

         mg_id           emp_id            name
         100             145                     Russell
         100             146                     Partners
         100             147                     Errazuriz
         100             148                     Cambrault
         100             149                     Zlotkey

  But if I want the o/p as below; That is to say; under Manager # 100, all employees emp_id and name should come in ONE row NOT in several lines:
  

  mg_id                   emp_id     name          emp_id       name       emp_id     name         emp_id     name                emp_id         name
  100                             145             Russell     146       Partners        147     Errazuriz       148              Cambrault        149        Zlotkey

  pls help me sort the above desired o/p.
  
  kindly tell me if there are guidelines of accounting (except 'Plain Text help' on the right side) in this forum. I tried a lot of post above 2 o/p in easy to read format, but could not do so.
  
  Published by: Francis Sep 20, 2009 04:28
  
  Published by: Francis Sep 20, 2009 04:29
  

• grouping of several lines into one line

  Totally, I need help with this easy... Basically, I have several lines for a unique userid that I need to be grouped into a single line.
  
  Here's what I have before:
  
  USER ID MONTH1_SEVERITY MONTH2_SEVERITY MONTH3_SEVERITY
  
  MODERATE 1900055
  1900055 <... it'sa just space... > MODERATE
  1900055 <... it'sa just space... > MODERATE
  
  
  What I wish to see:
  USER_ID MONTH1_SEVERITY MONTH2_SEVERITY MONTH3_SEVERITY
  
  MODERATE MODERATE MODERATE 1900055
  
  
  Thanks in advance.

  Rotate the data

  Select user_id,
  Max (month_1_severity),
  Max (month_2_severity),
  Max (month_3_severity)
  from table_name
  Group of user_id

• Report to concatenate several lines into one line

  I have three tables:
  1 project Pk = proj_id
  2 Resources_on_Project Pk = Resources_on_proj_id Foreign_key = proj_id
  3 cost Pk = cost_id Foreign_key = proj_id
  
  columns in the table:
  
  Project: proj_id, proj_name, proj_description
  Resources_on_Project: Resources_on_proj_id, proj_id, id_ressource
  cost: cost_id, proj_id, cost_type, cost_incurred
  
  the table relationships:
  
  Project: Resources_on_project 1:m (project has several resources in Appendix)
  Cost of the project: 1:m (project has many costs in annex)
  
  Data:
  
  Project:
  PROJ_ID, proj_name, proj_description
  1, CDM, Advisory Services
  
  2, efficient lighting, efficient ESCO
  
  Resources_on_project
  Resources_on_proj_id, proj_id, id_ressource
  1, 1, 1
  2, 1, 2
  3, 2, 3
  4, 2, 4
  
  Cost:
  cost_id proj_id cost_type cost_incurred
  1.1, food, 1200
  2.1, travel, 2000
  3.1, trip, 3500
  4.1 food, 1200
  5.1, trip, 1400
  6.1, travel, 1200
  7,2 trip, 2000
  8.2 food, 1200
  9.2, trip, 1300
  10.2, food, 2000
  11.2, travel, 800
  12.2, travel, 1150
  13.2, food, 3000
  14.2, food, 1000
  15.2, food, 2400
  
  
  First project has 2 resources attached to it and 6 different costs.
  Second project includes 2 resources and 9 heads of different costs.
  
  I want a report that gives me:
  
  Proj_name, Proj_description, id_ressource, cost_incurred
  Advisory services CDM 10500 1/2
  
  ESCO effective effective lighting 14850 3/4
  
  
  I wrote a query:
  «Select «PROJECT»» PROJ_NAME' as 'PROJ_NAME. "
  ««PROJECT»» PROJ_DESCRIPTION' as 'PROJ_DESCRIPTION. "
  sum (COST. COST_INCURRED) as "COST_INCURRED."
  'RESOURCES_ON_PROJECTS '. "" RESOURCE_ID ' as 'RESOURCE_ID.
  'COST', 'cost ',.
  "RESOURCES_ON_PROJECTS" "RESOURCES_ON_PROJECTS"
  'PROJECT' 'PROJECT '.
  where "PROJECT. "" PROJ_ID "=" RESOURCES_ON_PROJECTS. " "" PROJ_ID.
  and 'PROJECT '. "" "PROJ_ID '=' COST. PROJ_ID.
  PROJECT group. PROJ_NAME, PROJECT. PROJ_DESCRIPTION, RESOURCES_ON_PROJECTS. ACCOUNTABLE_RESOURCE_ID
  
  the result is:
  
  Advisory services CDM 1 10500
  Advisory services CDM 2 10500
  ESCO effective effective lighting 3 14850
  ESCO effective effective lighting 4 14850
  
  It gives a new line for each different resource.
  
  
  I want to:
  Advisory services CDM 10500 1/2
  ESCO effective effective lighting 14850 3/4
  
  any help will be appreciated.
  
  Published by: Rahul Gupta on September 7, 2009 16:07

  Rahul Gupta says:
  Shadow of Blu,

  It's exactly what I wanted. But the measures specified by you are not clear for me.

  can you let me know how I can implement?

  Okay... Let's take the internal selection...

  SQL> select proj_name
    2        ,proj_desc
    3        ,resource_id
    4        ,cost
    5        ,row_number() over (partition by proj_name order by resource_id) as rn
    6  from output
    7  /
  
  PROJ_NAME PROJ_DESC               RESOURCE_ID       COST         RN
  --------- ----------------------- ----------- ---------- ----------
  CDM       Advisory Services                 1      10500          1
  CDM       Advisory Services                 2      10500          2
  Efficient ESCO Efficient lighting           3      14850          1
  Efficient ESCO Efficient lighting           4      14850          2
  
  SQL>
  

  This affects a line number for each line, each group proj_name (partition). Line numbers are allocated in the order of the id_ressource.

  Now, using a (hierarchical) query connection we create a hierarchy of folders as well as RN = 2 is considered to be a child of RN = 1, etc..

  SQL> ed
  Wrote file afiedt.buf
  
    1  select level
    2        ,lpad(' ',(level-1)*2,' ')||x.proj_name as proj_name -- indent for hierarchical illustration only
    3        ,x.proj_desc
    4        ,x.resource_id
    5        ,x.cost
    6        ,x.rn
    7  from (
    8        select proj_name
    9              ,proj_desc
   10              ,resource_id
   11              ,cost
   12              ,row_number() over (partition by proj_name order by resource_id) as rn
   13        from output
   14       ) x
   15  connect by proj_name = prior proj_name and rn = prior rn + 1
   16* start with rn = 1
  SQL> /
  
       LEVEL PROJ_NAME       PROJ_DESC               RESOURCE_ID       COST         RN
  ---------- --------------- ----------------------- ----------- ---------- ----------
           1 CDM             Advisory Services                 1      10500          1
           2   CDM           Advisory Services                 2      10500          2
           1 Efficient       ESCO Efficient lighting           3      14850          1
           2   Efficient     ESCO Efficient lighting           4      14850          2
  
  SQL>
  

  Now, using the sys_connect_by_path function we can get it to collect the data, because it passes through to the bottom of the hierarchy...

  SQL> ed
  Wrote file afiedt.buf
  
    1  select level
    2        ,lpad(' ',(level-1)*2,' ')||x.proj_name as proj_name
    3        ,x.proj_desc
    4        ,x.resource_id
    5        ,sys_connect_by_path(resource_id,'/') as resources
    6        ,x.cost
    7        ,x.rn
    8  from (
    9        select proj_name
   10              ,proj_desc
   11              ,resource_id
   12              ,cost
   13              ,row_number() over (partition by proj_name order by resource_id) as rn
   14        from output
   15       ) x
   16  connect by proj_name = prior proj_name and rn = prior rn + 1
   17* start with rn = 1
  SQL> /
  
       LEVEL PROJ_NAME       PROJ_DESC               RESOURCE_ID RESOURCES        COST         RN
  ---------- --------------- ----------------------- ----------- ---------- ---------- ----------
           1 CDM             Advisory Services                 1 /1              10500          1
           2   CDM           Advisory Services                 2 /1/2            10500          2
           1 Efficient       ESCO Efficient lighting           3 /3              14850          1
           2   Efficient     ESCO Efficient lighting           4 /3/4            14850          2
  
  SQL>
  

  Now, we can store up to the sys_connect_by_path to eliminate the left "/" simply by using the TRIM function.
  We also need to do however is to choose only the lines that have reached the bottom of the hierarchy (the nodes). We have a pseudo-device column we can refer to called CONNECT_BY_ISLEAF...

  SQL> ed
  Wrote file afiedt.buf
  
    1  select level
    2        ,lpad(' ',(level-1)*2,' ')||x.proj_name as proj_name
    3        ,x.proj_desc
    4        ,x.resource_id
    5        ,ltrim(sys_connect_by_path(resource_id,'/'),'/') as resources
    6        ,x.cost
    7        ,x.rn
    8        ,connect_by_isleaf
    9  from (
   10        select proj_name
   11              ,proj_desc
   12              ,resource_id
   13              ,cost
   14              ,row_number() over (partition by proj_name order by resource_id) as rn
   15        from output
   16       ) x
   17  connect by proj_name = prior proj_name and rn = prior rn + 1
   18* start with rn = 1
  SQL> /
  
       LEVEL PROJ_NAME       PROJ_DESC               RESOURCE_ID RESOURCES        COST         RN CONNECT_BY_ISLEAF
  ---------- --------------- ----------------------- ----------- ---------- ---------- ---------- -----------------
           1 CDM             Advisory Services                 1 1               10500          1             0
           2   CDM           Advisory Services                 2 1/2             10500          2             1
           1 Efficient       ESCO Efficient lighting           3 3               14850          1             0
           2   Efficient     ESCO Efficient lighting           4 3/4             14850          2             1
  
  SQL>
  

  So now we can filter only the lines where CONNECT_BY_ISLEAF = 1, also remove the output columns and calculates values etc, we don't need to see.

  SQL> ed
  Wrote file afiedt.buf
  
    1  select x.proj_name
    2        ,x.proj_desc
    3        ,ltrim(sys_connect_by_path(resource_id,'/'),'/') as resources
    4        ,x.cost
    5  from (
    6        select proj_name
    7              ,proj_desc
    8              ,resource_id
    9              ,cost
   10              ,row_number() over (partition by proj_name order by resource_id) as rn
   11        from output
   12       ) x
   13  where connect_by_isleaf = 1
   14  connect by proj_name = prior proj_name and rn = prior rn + 1
   15* start with rn = 1
  SQL> /
  
  PROJ_NAME       PROJ_DESC               RESOURCES        COST
  --------------- ----------------------- ---------- ----------
  CDM             Advisory Services       1/2             10500
  Efficient       ESCO Efficient lighting 3/4             14850
  

• How to display/concatenate several lines into one line

  I have a report that retrieves a project name and its corresponding attached resources.
  If tha project has 4 resources attached will appear 4 different columns.
  is there a way to display a single line with the corresponding resources names concatenated into a single cell?

  There is a related issue of PL/SQL and is not a matter of apex. However, see this as an example:

  http://Apex.Oracle.com/pls/OTN/f?p=31517:84

  There are also a bunch of other code related to this issue.

  Denes Kubicek
  ------------------------------------------------------------------------------
  http://deneskubicek.blogspot.com/
  http://www.Opal-consulting.de/training
  http://Apex.Oracle.com/pls/OTN/f?p=31517:1
  ------------------------------------------------------------------------------

• Concatenate the strings of several lines into one line.

  Hello
  
  What is the name of this analytical function (or log in) which
  would return more line as a concatenated line strings. that is to say:
  (I know that it is possible using the regular functions of pipeline).
  

  ROW1:   STR1
  ROW2:   STR2
  ROW3:   STR3
  
  select tadah().... from ...
  
  result:
  
  ROW1: STR1 STR2 STR3

  Thank you.

  Hello

  DanielD wrote:
  Hello

  What is the name of this analytical function (or log in) which
  would return more line as a concatenated line strings. that is to say:
  (I know that it is possible using the regular functions of pipeline).

  ROW1:   STR1
  ROW2:   STR2
  ROW3:   STR3
  
  select tadah().... from ...
  
  result:
  
  ROW1: STR1 STR2 STR3
  

  The function is SYS_CONNECT_BY_PATH

• Combining the NACHA several files into one

  Gurus, we will implement the new file format NACHA for our payroll service. Payroll running a DOS command to concatenate several files into one .mf. Is there a way to Oracle to achieve the same?
  
  Database server
  ----------------------------------------
  RDBMS: 11.2.0.3.0
  Oracle Applications: 11.5.10.2
  
  
  Thanks, Naveen Gagadam.
  
  Published by: mascot of Oracle on May 30, 2013 10:26

  Vignesh Hi, I just went through our Installer and there are Consolidation defined for each payroll that we use. I think it is better the purpose of having a consolidation set. Could you tell me how to consolidate several salary mass as a whole or alternatively can add several wage masses on the fly (as parameters) for each race NACHA?

  Thanks, Naveen.

• Combine the two projects into one

  I know it is a very popular question and I read many answers excellent previous answers.  The two most popular procedures seem to be simple copy - paste and use clips of compounds with copy / paste.  CPF has improved this process over the years and I ask the question again to get the benefit of current thinking.   I have an iMac (mid-2011) OS X 10.11.4 and FCP worm 10.2.2.  I have two separate events within the same library.  There is a completed project, with all the transitions, effects and music, located within each discipline.    Current ideas on how to combine these two projects into one would be greatly appreciated.

  Thank you.

  Copy and paste is the only method I know.

  Open the project in the timeline first.

  Open the second project in the timeline panel. Only one project appears at the same time.

  Select an item in the timeline and press command + A to select all, then control + C to copy.

  Use the project navigation arrows to return the first project:

  

  Move the playhead to where copied clips must be glued and press command + V.

  Al

• Y at - it a safe application for concatenating several files into one .rtf?

  Y at - it a safe application for concatenating several files into one .rtf?

  Why do you do this?

  Is it arril (3D image files) or .rtf (Rich Text Format) files?

• I currently have a creative cloud with an e-mail account, however I have a behance with an e-mail account that I have had for many years (even Adobe and Behance made before part of the same group). Can I combine these two accounts into one?

  I currently have a creative cloud with an e-mail account, however I have a behance with an e-mail account that I have had for many years (even Adobe and Behance made before part of the same group). Can I combine these two accounts into one? I want to use the account that I pay cloud Creative if I can use the new portfolio feature.

  Thank you.

  This is an open forum, not Adobe support... below to connect with Adobe personnel to help

  While the forums are open 24/7 you can't contact Adobe support at any time

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• How to scan several documents into one PDF

  How to scan several documents into single PDF - have no ADF

  Thanks - great app

• Combine multiple lines into one line (from two tables / result sets)

  Hello experts,

  I would like to know how to combine multiple lines/records in a single record. Here are the DDL and DML to tables:

  create table test_table)

  client_name varchar2 (50 char),

  login_time timestamp (6).

  logout_time timestamp (6).

  auto_type varchar2 (10 char)

  )

  create table root_table)

  navigation_time timestamp (6).

  client_name varchar2 (50 char),

  VARCHAR2 (50 char) nom_du_groupe

  )

  Insert into test_table

  values ("John", TO_TIMESTAMP ('2013-12-05 17:04:01.512 ',' YYYY-MM-DD HH24:MI:SS.)) FF'), TO_TIMESTAMP ('2013-12-05 17:27:31.308 ',' YYYY-MM-DD HH24:MI:SS.) FF'), 'SIMPLE');

  Insert into test_table

  values ('David', TO_TIMESTAMP ('2013-12-05 06:33:01.308 ',' YYYY-MM-DD HH24:MI:SS.)) FF'), TO_TIMESTAMP ('2013-12-05 06:45:01.112 ',' YYYY-MM-DD HH24:MI:SS.) FF'), 'SIMPLE');

  insert into root_table

  values (TO_TIMESTAMP ('2013-12-05 17:04:01.512 ',' YYYY-MM-DD HH24:MI:SS.)) FF'), 'John', "invalid");

  insert into root_table

  values (TO_TIMESTAMP ('2013-12-05 17:14:22.333 ',' YYYY-MM-DD HH24:MI:SS.)) FF'), 'John', "GROUP_1");

  insert into root_table

  values (TO_TIMESTAMP ('2013-12-05 17:27:31.308 ',' YYYY-MM-DD HH24:MI:SS.)) FF'), 'John', "GROUP_1");

  insert into root_table

  values (TO_TIMESTAMP ('2013-12-05 06:33:01.308 ',' YYYY-MM-DD HH24:MI:SS.)) FF'), "David", "invalid");

  insert into root_table

  values (TO_TIMESTAMP ('2013-12-05 06:45:01.112 ',' YYYY-MM-DD HH24:MI:SS.)) FF'), 'David', 'GROUP_5');

  game results test_table

  client_name

  
  login_time logout_time auto_typeJohn05/12/2013 5:04:01.512000 PM05/12/2013 5:27:31.308000 PMSIMPLEDavid05/12/2013 6:33:01.308000 AM05/12/2013 6:45:01.112000 AMSIMPLE

  root_table result set

  navigation_time	client_name	GroupName
  05/12/2013 5:04:01.512000 PM	John	Not valid
  05/12/2013 5:14:22.333000 PM	John	GROUP_1
  05/12/2013 5:27:31.308000 PM	John	GROUP_1
  05/12/2013 6:33:01.308000 AM	David	Not valid
  05/12/2013 6:45:01.112000 AM	David	GROUP_5

  And here is the SQL code I'm writing:

  Select a.customer_name, a.login_time, a.logout_time, a.auto_type, Max (b.group_name)

  from test_table a, b root_table

  where a.customer_name = b.customer_name

  Group of a.customer_name, a.login_time, a.logout_time, a.auto_type

  As the 'invalid' value is greater than the value "GROUP_1" (based on the number of letter in English), the GroupName is returned as 'invalid '. I want to bring the GroupName based on the navigation_time column in the root_table so that it always returns a valid GroupName. Please help me.

  Output current:

  Client_name.      Login_Time.     Logout_Time |     Auto_Type |     GroupName

  --------------------------------------------------------------------------------------------------------------------------------------------

  John |     05/12/2013 5:04:01.512000 PM |     05/12/2013 5:27:31.308000 PM |     SIMPLE |     Not valid

  David |     05/12/2013 6:33:01.308000 AM |     05/12/2013 6:45:01.112000 AM |     SIMPLE |     Not valid

  Expected results:

  Client_name.      Login_Time.     Logout_Time |     Auto_Type |     GroupName

  --------------------------------------------------------------------------------------------------------------------------------------------

  John |     05/12/2013 5:04:01.512000 PM |     05/12/2013 5:27:31.308000 PM |     SIMPLE |     GROUP_1

  David |     05/12/2013 6:33:01.308000 AM |     05/12/2013 6:45:01.112000 AM |     SIMPLE |     GROUP_5

  Thank you!

  Adding INSERT statements, current and planned outputs.

  This...

  SELECT client_name

  login_time,

  logout_time,

  auto_type,

  GroupName

  Of

  (select a.customer_name,

  a.login_time,

  a.logout_time,

  a.auto_type,

  b.group_name,

  ROW_NUMBER() over (PARTITION BY a.customer_name, a.login_time, a.logout_time, a.auto_type ORDER BY b.group_name) rn

  from test_table a, b root_table

  where a.customer_name = b.customer_name)

  WHERE rn = 1;

  OUTPUT:-

  =========

  David	DECEMBER 5, 13 06.33.01.308000000 AM	DECEMBER 5, 13 06.45.01.112000000 AM	SIMPLE	GROUP_5
  John	DECEMBER 5, 13 05.04.01.512000000 PM	DECEMBER 5, 13 05.27.31.308000000 PM	SIMPLE	GROUP_1

  Thank you

  Ann

• The combination of several lines to line of monkey through SQL Stmt

  Hello
  
  I try to combine the values returned by several rows in a row,
  through indoor/outdoor sql or any optimally.
  In the example, I would like to have name, surname, email and phone to be
  returned in a single line.

  create table TEMP_AAAAA
  (
    FIRST_NAME VARCHAR2(25),
    LAST_NAME  VARCHAR2(25),
    CON_METHOD VARCHAR2(25),
    CON_VALUE  VARCHAR2(25)
  
  )
  
  INSERT INTO TEMP_AAAAA VALUES('TOM','MAC','EMAIL','[email protected]');
  INSERT INTO TEMP_AAAAA VALUES('TOM','MAC','PHONE','12345');

  Any suggestion to do this through sql stmt.
  I did it through pl/sql, I wondered if it could be realized only thru SQL Stmt

  DECLARE
  v_FIRST_NAME  VARCHAR2(25);
  v_SECOND_NAME VARCHAR2(25);
  v_EMAIL       VARCHAR2(25);
  v_PHONE       VARCHAR2(25);
  BEGIN
  v_FIRST_NAME := NULL;
  v_SECOND_NAME := NULL;
  v_EMAIL := NULL;
  v_PHONE := NULL;
  
  FOR IMPL_CUR IN(SELECT * FROM TEMP_AAAAA ORDER BY CON_METHOD DESC)
  LOOP
  
          IF v_FIRST_NAME IS NULL
          THEN
             v_FIRST_NAME := IMPL_CUR.FIRST_NAME;
          END IF;
          IF v_SECOND_NAME IS NULL
          THEN
             v_SECOND_NAME := IMPL_CUR.LAST_NAME;
          END IF;   
          IF v_PHONE IS NULL AND IMPL_CUR.CON_METHOD = 'PHONE'
          THEN
             v_PHONE := IMPL_CUR.CON_VALUE;
          END IF;
         
          IF v_FIRST_NAME = IMPL_CUR.FIRST_NAME AND 
             v_SECOND_NAME = IMPL_CUR.LAST_NAME AND 
             length(v_PHONE) > 0 
          THEN
            IF v_EMAIL IS NULL AND IMPL_CUR.CON_METHOD = 'EMAIL'
            THEN
               v_EMAIL := IMPL_CUR.CON_VALUE;
               EXIT;
            END IF;        
          END IF;
          
          
          
  END LOOP;
  
                     
           DBMS_OUTPUT.put_line('firstName...:' || v_FIRST_NAME);     
           DBMS_OUTPUT.put_line('lastName....:' || v_SECOND_NAME);     
           DBMS_OUTPUT.put_line('PHONE.......:' || v_PHONE);
           DBMS_OUTPUT.put_line('EMAIL.......:' || v_EMAIL); 
  
  END;

  SELECT FIRST_NAME, LAST_NAME,
  MAX (SUBSTR (SYS_CONNECT_BY_PATH (CON_VALUE,' '), 2)) EMP_LIST
  (SELECT FIRST_NAME, LAST_NAME, CON_VALUE,
  ROW_NUMBER() OVER (PARTITION FIRST_NAME, LAST_NAME ORDER BY CON_METHOD) RN
  OF TEMP_AAAAA)
  CONNECT BY PRIOR (FIRST_NAME |) LAST_NAME. =(FIRST_NAME||) RN) LAST_NAME. (RN-1))
  START BY RN = 1
  GROUP FIRST_NAME, LAST_NAME;

  FIRST_NAME LAST_NAME EMP_LIST
  ------------------------- ------------------------- ------------------------------------------------
  TOM MAC [email protected] 12345

• Fusion of the 2 lines into one

  Greedings,
  
  I have the following output
  

          
  1       A       null     null
  
  2      null      B         C

  How is it possible to merge in one line?
  

  CREATE TABLE test_g 
  (
  a VARCHAR2(1),
  b VARCHAR2(1),
  c VARCHAR2(1)
  )

  INSERT INTO test_g 
  VALUES (null,'B','C');
  
  INSERT INTO test_g 
  VALUES ('A',null,null);

  You could do this:

  SELECT MAX(a),
         MAX(b),
         MAX(c)
  FROM   test_g
  

• How to combine two different accounts into one?

  We have an account at work that has a subscription of cloud on that and I also have a separate for work as I can access only. How am I supposed to combine the two is multi-user account? My account has expired so I need re-new anyway with the other one.

  Help, please!

  Since this is an open forum, not Adobe support... you must contact Adobe personnel to help

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  -https://helpx.adobe.com/contact/creative-cloud-teams.html using the team

  -manage your account http://forums.adobe.com/thread/1460939?tstart=0 team