Report to concatenate several lines into one line

I have three tables:
1 project Pk = proj_id
2 Resources_on_Project Pk = Resources_on_proj_id Foreign_key = proj_id
3 cost Pk = cost_id Foreign_key = proj_id

columns in the table:

Project: proj_id, proj_name, proj_description
Resources_on_Project: Resources_on_proj_id, proj_id, id_ressource
cost: cost_id, proj_id, cost_type, cost_incurred

the table relationships:

Project: Resources_on_project 1:m (project has several resources in Appendix)
Cost of the project: 1:m (project has many costs in annex)

Data:

Project:
PROJ_ID, proj_name, proj_description
1, CDM, Advisory Services

2, efficient lighting, efficient ESCO

Resources_on_project
Resources_on_proj_id, proj_id, id_ressource
1, 1, 1
2, 1, 2
3, 2, 3
4, 2, 4

Cost:
cost_id proj_id cost_type cost_incurred
1.1, food, 1200
2.1, travel, 2000
3.1, trip, 3500
4.1 food, 1200
5.1, trip, 1400
6.1, travel, 1200
7,2 trip, 2000
8.2 food, 1200
9.2, trip, 1300
10.2, food, 2000
11.2, travel, 800
12.2, travel, 1150
13.2, food, 3000
14.2, food, 1000
15.2, food, 2400

First project has 2 resources attached to it and 6 different costs.
Second project includes 2 resources and 9 heads of different costs.

I want a report that gives me:

Proj_name, Proj_description, id_ressource, cost_incurred
Advisory services CDM 10500 1/2

ESCO effective effective lighting 14850 3/4

I wrote a query:
«Select «PROJECT»» PROJ_NAME' as 'PROJ_NAME. "
««PROJECT»» PROJ_DESCRIPTION' as 'PROJ_DESCRIPTION. "
sum (COST. COST_INCURRED) as "COST_INCURRED."
'RESOURCES_ON_PROJECTS '. "" RESOURCE_ID ' as 'RESOURCE_ID.
'COST', 'cost ',.
"RESOURCES_ON_PROJECTS" "RESOURCES_ON_PROJECTS"
'PROJECT' 'PROJECT '.
where "PROJECT. "" PROJ_ID "=" RESOURCES_ON_PROJECTS. " "" PROJ_ID.
and 'PROJECT '. "" "PROJ_ID '=' COST. PROJ_ID.
PROJECT group. PROJ_NAME, PROJECT. PROJ_DESCRIPTION, RESOURCES_ON_PROJECTS. ACCOUNTABLE_RESOURCE_ID

the result is:

Advisory services CDM 1 10500
Advisory services CDM 2 10500
ESCO effective effective lighting 3 14850
ESCO effective effective lighting 4 14850

It gives a new line for each different resource.

I want to:
Advisory services CDM 10500 1/2
ESCO effective effective lighting 14850 3/4

any help will be appreciated.

Published by: Rahul Gupta on September 7, 2009 16:07

Rahul Gupta says:
Shadow of Blu,

It's exactly what I wanted. But the measures specified by you are not clear for me.

can you let me know how I can implement?

Okay... Let's take the internal selection...

SQL> select proj_name
  2        ,proj_desc
  3        ,resource_id
  4        ,cost
  5        ,row_number() over (partition by proj_name order by resource_id) as rn
  6  from output
  7  /

PROJ_NAME PROJ_DESC               RESOURCE_ID       COST         RN
--------- ----------------------- ----------- ---------- ----------
CDM       Advisory Services                 1      10500          1
CDM       Advisory Services                 2      10500          2
Efficient ESCO Efficient lighting           3      14850          1
Efficient ESCO Efficient lighting           4      14850          2

SQL>

This affects a line number for each line, each group proj_name (partition). Line numbers are allocated in the order of the id_ressource.

Now, using a (hierarchical) query connection we create a hierarchy of folders as well as RN = 2 is considered to be a child of RN = 1, etc..

SQL> ed
Wrote file afiedt.buf

  1  select level
  2        ,lpad(' ',(level-1)*2,' ')||x.proj_name as proj_name -- indent for hierarchical illustration only
  3        ,x.proj_desc
  4        ,x.resource_id
  5        ,x.cost
  6        ,x.rn
  7  from (
  8        select proj_name
  9              ,proj_desc
 10              ,resource_id
 11              ,cost
 12              ,row_number() over (partition by proj_name order by resource_id) as rn
 13        from output
 14       ) x
 15  connect by proj_name = prior proj_name and rn = prior rn + 1
 16* start with rn = 1
SQL> /

     LEVEL PROJ_NAME       PROJ_DESC               RESOURCE_ID       COST         RN
---------- --------------- ----------------------- ----------- ---------- ----------
         1 CDM             Advisory Services                 1      10500          1
         2   CDM           Advisory Services                 2      10500          2
         1 Efficient       ESCO Efficient lighting           3      14850          1
         2   Efficient     ESCO Efficient lighting           4      14850          2

SQL>

Now, using the sys_connect_by_path function we can get it to collect the data, because it passes through to the bottom of the hierarchy...

SQL> ed
Wrote file afiedt.buf

  1  select level
  2        ,lpad(' ',(level-1)*2,' ')||x.proj_name as proj_name
  3        ,x.proj_desc
  4        ,x.resource_id
  5        ,sys_connect_by_path(resource_id,'/') as resources
  6        ,x.cost
  7        ,x.rn
  8  from (
  9        select proj_name
 10              ,proj_desc
 11              ,resource_id
 12              ,cost
 13              ,row_number() over (partition by proj_name order by resource_id) as rn
 14        from output
 15       ) x
 16  connect by proj_name = prior proj_name and rn = prior rn + 1
 17* start with rn = 1
SQL> /

     LEVEL PROJ_NAME       PROJ_DESC               RESOURCE_ID RESOURCES        COST         RN
---------- --------------- ----------------------- ----------- ---------- ---------- ----------
         1 CDM             Advisory Services                 1 /1              10500          1
         2   CDM           Advisory Services                 2 /1/2            10500          2
         1 Efficient       ESCO Efficient lighting           3 /3              14850          1
         2   Efficient     ESCO Efficient lighting           4 /3/4            14850          2

SQL>

Now, we can store up to the sys_connect_by_path to eliminate the left "/" simply by using the TRIM function.
We also need to do however is to choose only the lines that have reached the bottom of the hierarchy (the nodes). We have a pseudo-device column we can refer to called CONNECT_BY_ISLEAF...

SQL> ed
Wrote file afiedt.buf

  1  select level
  2        ,lpad(' ',(level-1)*2,' ')||x.proj_name as proj_name
  3        ,x.proj_desc
  4        ,x.resource_id
  5        ,ltrim(sys_connect_by_path(resource_id,'/'),'/') as resources
  6        ,x.cost
  7        ,x.rn
  8        ,connect_by_isleaf
  9  from (
 10        select proj_name
 11              ,proj_desc
 12              ,resource_id
 13              ,cost
 14              ,row_number() over (partition by proj_name order by resource_id) as rn
 15        from output
 16       ) x
 17  connect by proj_name = prior proj_name and rn = prior rn + 1
 18* start with rn = 1
SQL> /

     LEVEL PROJ_NAME       PROJ_DESC               RESOURCE_ID RESOURCES        COST         RN CONNECT_BY_ISLEAF
---------- --------------- ----------------------- ----------- ---------- ---------- ---------- -----------------
         1 CDM             Advisory Services                 1 1               10500          1             0
         2   CDM           Advisory Services                 2 1/2             10500          2             1
         1 Efficient       ESCO Efficient lighting           3 3               14850          1             0
         2   Efficient     ESCO Efficient lighting           4 3/4             14850          2             1

SQL>

So now we can filter only the lines where CONNECT_BY_ISLEAF = 1, also remove the output columns and calculates values etc, we don't need to see.

SQL> ed
Wrote file afiedt.buf

  1  select x.proj_name
  2        ,x.proj_desc
  3        ,ltrim(sys_connect_by_path(resource_id,'/'),'/') as resources
  4        ,x.cost
  5  from (
  6        select proj_name
  7              ,proj_desc
  8              ,resource_id
  9              ,cost
 10              ,row_number() over (partition by proj_name order by resource_id) as rn
 11        from output
 12       ) x
 13  where connect_by_isleaf = 1
 14  connect by proj_name = prior proj_name and rn = prior rn + 1
 15* start with rn = 1
SQL> /

PROJ_NAME       PROJ_DESC               RESOURCES        COST
--------------- ----------------------- ---------- ----------
CDM             Advisory Services       1/2             10500
Efficient       ESCO Efficient lighting 3/4             14850

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