Compare several records in the same table

Similar Questions

• Compare two rows in the same table

  Hi all
  
  I need to compare two rows in the same table, I don't know hoe to do it in pl/sql. Please help me on this.
  
  example:
  
  price of ro TR
  xya0001 AMA.7 12
  xya0003 ama6 14
  xya0004 AMA.7 16
  
  in table b is a unique value for each line, I need to compare the price column and see if the first value is less than or greater than the following value and, if there is more to put the corresponding value of br to a variable, and if it is less, put the corresponding value of the br to another variable. I don't know a method to do this, as I'm new to pl/sql. Please help me in this

  for data in(select tr,br,price, lag(price) over ( order by tr) newcol
  from yourtable)
  loop
  if nvl(data.newcol,0) > data.price then
  variable1:=data.br;
  else
  varable2:=data.br;
  end if;
  end loop;
  

• Update of several rows of the same table using trigger

  Hello

  I have the following table

  ---------------------------------------------------------------------------------------------------------

  CREATE TABLE ATT_PERMISSIONS
  (
  DATE OF PRMONTHYR,
  EMPID	NUMBER (10)	DEFAULT VALUE 0	,
  FROMDATETIME	DATE		,
  TODMTFDATETIME	DATE		,
  NUMBER OF PERMMINS (3),

  SSLINASTRETCH NUMBER (3).

  PERMATTINELIGIBLE	NUMBER (1)	DEFAULT VALUE 0
  );

  ------------------------------------------------------------------------------------------------------

  I want to update the column PERMATTINELIGIBLE in the same table when each line is inserted.

  I created following trigger for that

  CREATE OR REPLACE TRIGGER SSL_AFTER_UPDATE AFTER UPDATE ON ATT_PERMISSIONS

  FOR EACH LINE

  BEGIN

  Update ATT_PERMISSIONS set PERMATTINELIGIBLE =

  (

  SELECT THE CHECK BOX

  WHEN PERMMINS < = 60

  or

  (

  PERMMINS < = SSLINASTRETCH

  AND

  COUNT (CASE WHEN PERMMINS = 0 THEN NULL OTHERWISE 1 END)

  COURSES (PARTITION BY empid, prmonthyr) < = 1

  )

  THEN 1

  0 OTHERWISE

  END

  FROM ATT_PERMISSIONS where prmonthyr =:new.prmonthyr, empid =:new.empid

  ) where prmonthyr =:new.prmonthyr, empid =:new.empid;

  END;

  ---------------------------------------------------------------------------------------------------

  That is to say.

  When a row is inserted the PERMATTINELIGIBLE of all records for this employee for the month is recalculated.

  There would be only two or three records for an employee for a month.

  PERMMINS is the number of minutes to use as short leave.

  If it is less than 60 is eligible for the bonus to attendance for this employee.

  If this isn't normally the date is not eligible for the attendance for this employee premium.

  but an exception is that if a short leaves of DISP employee allowed a month (IE. ( SSLINASTRETCH ) in a straight line, IE. one day, that day is eligible for the bonus of presence.

  That is to say. Why the number of short leaves in a month is taken. If it's one and done minutes use is lower to SSLINASTRETCH, then the day is eligible for the attendance bonus.

  But when I try to create the trigger I get error, PL/SQL: ORA-00907: missing a right parenthesis.

  Help, please

  I use oracle 10g

  I want to update the column PERMATTINELIGIBLE in the same table, when each row is inserted.

  No - you do NOT want to do in a trigger.

  You cannot query the same table that the trigger is activated on. -C' is a MUTANT and you will get an exception.

  When a row is inserted is recalculated to the PERMATTINELIGIBLE of all the records for that employee for that month.

  There would be only two or three records for an employee for a month.

  PERMMINS is the number of minutes to use as short leave.

  If it is less than 60 is eligible for the bonus to attendance for this employee.

  If is not normally the day is not eligible for the premium of attendance for this employee.

  but an exception is that if a short leaves of DISP employee allowed a month (IE. SSLINASTRETCH) in a straight line, IE. one day, that day is eligible for the bonus of presence.

  That is to say. Why the number of short leaves in a month is taken. If it's one and done minutes use is less than SSLINASTRETCH, then the day is eligible for the bonus of presence.

  But when I try to create the trigger I get error, PL/SQL: ORA-00907: missing a right parenthesis.

  You can not do in a trigger. Even if correct you this error of syntax, you will get the exception that I mentioned above.

  Oracle is a multi-user system. Other users can modify the same table that you use.

  So even if you could try to interview "all the records for this employee" some of them may be locked if other users access them. Also, an insert statement could try to insert two rows for an employee and the trigger could not have seen the other lines still.

  If you want to work with data SETS (all records for an employee), you must write the PL/SQL code that LOCKS all lines updated to prevent others to interfere.

  Then you make your operations but NOT in a trigger. Perform inserts and then use an UPDATE query to set this value.

  Then VALIDATE to unlock the lines.

• comparing string values in the same table

  I have a table with ID (14 digit string values) starting with "A". Ex: A21849B1020792. There may be a different ID with the same substring 'B1020792' in the same table, example: A12349B1020792. If this happens, the ID of the last creation date of must be returned in the result. In other words, comparison is done on the same table. "In the example provided, say A12349B1020792 has the date of 1 January 2015 'and A21849B1020792 has date February 1, 2015", since A21849B1020792 has the most recent date, the result must contain only A21849B1020792.

  ID create_date

  ---                              ------------------

  A21849B1020792 02/01/2015

  A12349 B1020792 01/01/2015

  A12345B1234567 01/03/2015      

  A43567B1234567 01/04/2015      

  
  Here's the query I used:

  substr (a.id, 7) select sc, max (a.create_date) cd1

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A12349B1020792', 'A21849B1020792','A12345B1234567 ','A43567B1234567')

  Group of substr (a.id, 7);

  Result:

  ---------

  sc                    cd1

  ---                    ------

  B1020792 02/01/2015

  B1234567 04/01/2015

  There is one thing that I'm not able to do with my request, that is, be able to get real IDs list and not list of substrings. If I added a.id column in the select clause and the group by clause, the query includes both by substr (a.id, 7) and a.id and as a result, the query returns four lines as below:

  substr (a.id, 7) select sc, max (a.create_date) cd1, a.id ID

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A12349B1020792', 'A21849B1020792','A12345B1234567 ','A43567B1234567')

  Group by substr (a.id, 7), a.id.

  Result:

  ---------

  sc                    cd1                      ID

  ---                    ------                   ---------

  01/01/2015 A12349B1020792 B1020792

  B1020792 01/02/2015 A21849B1020792

  B1234567 01/03/2015 A12345B1234567

  B1234567 01/04/2015 A43567B1234567

  
  

  My goal is to retrieve a list of all the unique identifiers that have the later dates.

  
  

  ID:

  ---

  A21849B1020792

  A43567B1234567

  
  

  Thanks for your time in advance!
  

  Hello

  user11951344 wrote:

  I have a table with ID (14 digit string values) starting with "A". Ex: A21849B1020792. There may be a different ID with the same substring "B1020792" in the same table, example: A12349B1020792. If this is the case, the ID of the last creation date must be returned in the result. In other words, comparison is done on the same table. "In the example provided, say A12349B1020792 updated 1 January 2015 ' and A21849B1020792 a date February 1, 2015", as A21849B1020792 has the most recent date, the result should contain only the A21849B1020792.

  ID create_date

  ---                              ------------------

  A21849B1020792 02/01/2015

  A12349B1020792 01/01/2015

  A12345B1234567 03/01/2015

  A43567B1234567 01/04/2015

  Here's the query I used:

  substr (a.id, 7) select sc, max (a.create_date) cd1

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A21849B1020792', 'A12345B1234567', 'A12349B1020792', 'A43567B1234567')

  Group of substr (a.id, 7);

  Result:

  ---------

  sc                    cd1

  ---                    ------

  B1020792 02/01/2015

  B1234567 01/04/2015

  There is one thing that I am not able to do with my request, that is, the ability to retrieve the list of IDs real and not a list of substrings. If I added a.id column in the select clause and the group by clause, the query groups according to the two substr (a.id, 7) and a.id and as a result, the query returns four lines as below:

  substr (a.id, 7) select sc, max (a.create_date) cd1, a.id ID

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A21849B1020792', 'A12345B1234567', 'A12349B1020792', 'A43567B1234567')

  Group by substr (a.id, 7), a.id.

  Result:

  ---------

  sc                    cd1                      ID

  ---                    ------                   ---------

  B1020792 01/01/2015 A12349B1020792

  B1020792 02/01/2015 A21849B1020792

  B1234567 03/01/2015 A12345B1234567

  B1234567 01/04/2015 A43567B1234567

  My goal is to retrieve a list of all the unique identifiers that have the later dates.

  ID:

  ---

  A21849B1020792

  A43567B1234567

  Thanks for your time in advance!

  If it makes sense to treat the first 6 characters of the ID separately from the rest of the id in this problem, maybe it makes sense to store those two parts of the id in two different columns.  Relational databases work best when each column of each row contains 1 single piece of data (at most).  It is so fundamental to the design of table that he called the first normal form.

  Given that the two parts are stored in column 1, so you can something like this Request Top - N:

  WITH got_r_num AS

  (

  SELECT r.id

  r.create_date AS cd1

  , RANK () OVER (PARTITION OF SUBSTR (r.id, 7))

  ORDER BY r.create_date DESC

  ) AS r_num

  FROM table_x g - g for data values

  JOIN table_x r - r for related values

  ON SUBSTR (r.id, 7) = SUBSTR (g.id, 7)

  WHERE g.id IN ('A12349B1020792'

  , "A21849B1020792".

  , "A12345B1234567".

  , "A43567B1234567".

  )

  - AND g.id LIKE 'A %' - if necessary.   The above condition ensures already g.id start with "A".

  AND r.id LIKE 'a % '.

  )

  SELECT id, create_date

  OF got_r_num

  WHERE r_num = 1

  ;

  If you would care to post CREATE TABLE and INSERT instructions for the sample data, and then I could test this.

• Several updates on the same Table

  Hello
  
  I need to update the same Table (T1) but to filter for different conditions as below.
  and I have a set of filter conditions 50 and update the same table.
  
  Is it possible to get in the single update statement?
  
  BEGIN
  UPDATE T1
  SET PTA_CLM_CNT = v_PTA_CLM_CNT__77,
  PTB_CLM_CNT = v_PTB_CLM_CNT__77
  WHERE run_dt = v_in_parm_dt
  AND state_code = '77';
  EXCEPTION
  WHEN NO_DATA_FOUND THEN
  null;
  WHILE OTHERS THEN
  v_error_cd: = SQLCODE;
  v_error_msg: = SUBSTR (SQLERRM, 1, 200);
  v_curr_record: = 'sum_bene_state_updt_77 ' | v_in_parm_dt;
  create_error_log ('_sum_cnts', v_error_cd, v_error_msg, v_curr_record);
  END;
  
  BEGIN
  UPDATE T1
  SET PTA_CLM_CNT_ = v_PTA_CLM_CNT__78,
  PTB_CLM_CNT_ = v_PTB_CLM_CNT__78
  WHERE run_dt = v_in_parm_dt
  AND state_code = '78';
  EXCEPTION
  WHEN NO_DATA_FOUND THEN
  null;
  WHILE OTHERS THEN
  v_error_cd: = SQLCODE;
  v_error_msg: = SUBSTR (SQLERRM, 1, 200);
  v_curr_record: = 'sum_bene_state_updt_78 ' | v_in_parm_dt;
  create_error_log ('sum_cnts', v_error_cd, v_error_msg, v_curr_record);
  END;
  
  Thanks in advance

  May be trying to use DECODE

  UPDATE T1
     SET PTA_CLM_CNT = DECODE(state_code,77,v_PTA_CLM_CNT_77,78,v_PTA_CLM_CNT_78)
         PTB_CLM_CNT = DECODE(state_code,77,v_PTB_CLM_CNT_77,78,v_PTB_CLM_CNT_78)
   WHERE run_dt = v_in_parm_dt;
  

• Compare the records from the same table

  Hi all

  I have this sample, the data were rendered are group by my_id, the same number of records exist for the two my_ids (2 and 62) as:

  create table myTest as
  (
  my_id number, 
  fieldA varchar2, 
  fieldB number, 
  fieldC number, 
  cost_A number, 
  cost_B number
  )
  
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (2, 'MAINT', 60, 5, 10.3, 15.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (2, 'MAINT', 70, 6, 20.3, 25.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (2, 'MAINT', 80, 7, 30.3, 35.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (62, 'MAINT', 60, 5, 10.3, 5.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (62, 'MAINT', 70, 6, 20.3, 25.00);
  insert into myTest (my_id, fieldA, fieldB, fieldC, cost_A, cost_B)
  values (62, 'MAINT', 80, 7, 10.3, 15.00);
  

  How can display the records with numbers of different costs for the same unique key (fieldA, fieldB and FieldC)?

  With the help of Oracle Database 11 g Enterprise Edition Release 11.2.0.4.0.

  I hope that my message is clear.

  Thank you!

  Hello

  user9542267 wrote:

  ... I need all the exits...

  Me too.  Always show the complete, accurate, results you want from the data provided.  If you want 2 rows at the exit point, don't tell you want 1.

  Here are the results you want?

  MY_ID FIELDA, FIELDB, FIELDC OLD_COST_A COST_A OLD_COST_B COST_B

  ------ ---------- ------ ------ ---------- ------ ---------- ------

  MAINT 62 60 5 10.3 10.3 15 5

  MAINT 62 80 7 30.3 10.3 35 15

  If so, here's a way to get them:

  WITH got_old_costs AS

  (

  SELECT fielda, fieldb, fieldc, cost_a, my_id, cost_b

  , LAG (cost_a) OVER (PARTITION BY fielda, fieldb, fieldc)

  ORDER BY my_id

  ) AS old_cost_a

  , LAG (cost_b) OVER (PARTITION BY fielda, fieldb, fieldc)

  ORDER BY my_id

  ) AS old_cost_b

  OF mytest

  WHERE my_id IN (2, 62)

  )

  SELECT my_id, fielda, fieldb, fieldc

  old_cost_a, cost_a

  old_cost_b, cost_b

  OF got_old_costs

  WHERE my_id = 62

  AND (cost_a <> old_cost_a)

  OR cost_b <> old_cost_b

  )

  ORDER BY fielda, fieldb, fieldc

  ;

• Selection of records in the same table problem

  Hi all
  
  I have the following table
  

  with emp as (
             select '11' A,'aaa' B, '40' C from dual union all
             select '11','bbb', '40' from dual union all
             select '33','ccc', '30' from dual union all
             select '44','ddd', '20' from dual union all
             select '11','eee', '10' from dual
            )

  My results should be
  

  A           B        C
   
  11        aaa      40
  11        bbb     40      
  11        eee     10

  Basically the requirement is select different combination of values in the column 'B' need to know what is the value of 'A' (it must be the same for all records of three)
  
  
  Hope in this sense.
  
  
  See you soon
  
  Sexy

  an attempt to rephrase:

  you want all the files "aaa", "bbb" and "EEA" where, for each set of column A, where they exist.

  that is, if games to have only "aaa" and "bbb" but not "eee" in column B, then you don't want to retrieve this record?

  Try this:

  SQL> with emp as (
    2  select '11' A,'aaa' B, '40' C from dual union all
    3  select '11','bbb', '40' from dual union all
    4  select '33','ccc', '30' from dual union all
    5  select '44','ddd', '20' from dual union all
    6  select '11','kkk', '20' from dual union all
    7  select '10','eee', '20' from dual union all
    8  select '11','eee', '10' from dual
    9  )
   10  select a, b, c
   11   from (select emp.*, count(*) over (partition by a) cnt
   12    from emp
   13   where b in ('aaa','bbb','eee'))
   14   where cnt = 3
   15  /
  
  A                                B                                C
  -------------------------------- -------------------------------- --------------------------------
  11                               eee                              10
  11                               aaa                              40
  11                               bbb                              40
  
  3 rows selected.
  

  Published by: WhiteHat June 30, 2011 11:04

• problem of query by comparing records from the same table against each other

  Hi, i'ms truggling to see where I am going wrong here. I have data from cards of following music: -.

  with charts_table as (select 1 id,'oasis' product_name,0801 week, 20 week_chart_position, 20 highest_chart_position from dual
  union select 2,'oasis',0802,14,14 from dual
  union select 3,'oasis',0803,17,14 from dual
  union select 4,'oasis',0804,29,14 from dual
  union select 5,'kings of leon',0801,55,55 from dual
  union select 6,'kings of leon',0802,22,22 from dual
  union select 7,'kings of leon',0803,35,22 from dual
  union select 8,'kings of leon',0804 , 11 , 11  from dual
  union select 9,'bob dylan',0801, 88 , 88  from dual
  union select 10,'bob dylan',0802,79 , 79  from dual
  union select 11,'bob dylan',0803,54,54 from dual
  union select 12,'bob dylan',0804,22,22 from dual
  union select 13,'kid rock',0801,19,19 from dual
  union select 14,'kid rock',0802,24,19 from dual
  union select 15,'kid rock',0803,55,0 from dual
  union select 16,'kid rock',0804,44,0 from dual)

  italic , I need to identify the rogue data where the highest_position is incorrectly registered lower or 0 as there
  position of the highest week was at an earlier date. (stick with me) for example in this kid of rock data initially charted at position 19. What follows
  week (0802) his week_chart_position slipped to 24 and the position the highest card is correctly saved at 19 (ie the week 1). The problem
  is available in week 0803 and 0804 when somehow the data was corrupted and the higest_chart_position is trying to read 0 (instead of 19). How can I write a query to identify this error?
  
  is the best I have at the moment:-

  select * from charts_table ct1 where 
  nvl2(highest_chart_position,0,99999)>
  (select min(week_chart_position) from charts_table ct2
  where ct2.week<ct1.week
  and ct1.product_name=ct2.product_name)

  but it's not working. can someone help and tell where I'm wrong. Thanks a lot for the research/resolve.

  Ahh, I was suggesting using the lag function to ensure that highest chart position is not fall lower than highest prior chart positions. Your concern is he reports a higher chart position that she never had. In this case I use the MIN function as an analytic function rather than as an aggregate function:

  with t1 as (
    select ct.*
         , min(week_chart_position) over( PARTITION by product_name order by week) highest
      from charts_table ct
     order by product_name, week
  )
  select * from t1 where highest != highest_chart_position;
  

  Conversely, you place your order of cards, which is the highest rank is 1, thew me. I saw the high word and the expected value in the highest chartposition column to be on the rise, but has seen examples of it decreases. It was an oversight on my part.

  Published by: Sentinel on October 9, 2008 08:31

• COMPARING TWO ROWS IN THE SAME TABLE AND DELETE THEM USING DELETION BLOCK

  Hi all
  I have a problem. I have an Employee table
  
  employee
  
  Emp_name Emp_id Emp_status Emp_date
  
  John 1 P 11-27-2010
  
  Mike 2 26/11/2010 S
  
  Simon P 3 22 / 11 / 2010
  
  Dennis C 4 25/11/2010...
  
  
  I compare the rows in the table and their employee_status if 'P', should I remove the... Here, I should delete lines 1 and 3 as their Emp_status is 'P '. I only use BULK DELETE... I tried to use the join query internal and deletion, but it does not work... Can someone help me...

  Ooops, it should be:

  and e2.emp_status in ('P', 'C')

  not

  and e2.emp_status in ('P', 'A')

  Here it goes:

  SQL> select  *
    2    from  employees
    3  /
  
  E EMP_NAME      EMP_KEY          X
  - ---------- ---------- ----------
  C John              123          1
  P Mike              123          2
  P Paul              123          6
  C Harry             124          5
  A Gass              125          7
  C Gass              125          7
  
  6 rows selected.
  
  delete  employees e1
    where 2 = (
               select  count(distinct e2.emp_status)
                    from  employees e2
                    where e2.emp_key = e1.emp_key
                      and e2.emp_status in ('P','C')
                 )
  /
  
  3 rows deleted.
  
  SQL>
  

  SY.

• parents and children of the same table records

  I want to create a query that is a union such that 2nd resultset is based on the game of results 1. I have a table that has parent and child records in the same table.
  
  Table: EVENTS
  EVENT_ID
  PARENT_EVENT_ID
  CREATED_DATE
  (other columns)
  
  If PARENT_EVENT_ID is null, then this is a parent record, otherwise it is a book of the child. I want to select all parent records then union them with all the related child records... something like this:
  
  Select * from EVENTS where CREATED_DATE < sysdate - 90 and PARENT_EVENT_ID is null - all parents
  Union
  Select * event where PARENT_EVENT_ID in (select EVENT_ID of EVENTS where CREATED_DATE < sysdate - 90 and PARENT_EVENT_ID is null)-include all children selected from the top parent
  
  It works but it of kind of ugly, I want to avoid using the subselect in the 2nd because it is a repeat of the 1st statement, is there a way to alias the first statement and only refer to him in the 2nd query?

  Hello

  CONNECTION is very similar to a UNION on the same table. How is this:

  SELECT     *
  FROM     events
  WHERE     created_date     < SYSDATE - 90
  START WITH     parent_event_id     IS NULL
  CONNECT BY     parent_event_id     = PRIOR event_id
       AND     LEVEL          <= 2    -- Maybe
  ;
  

  ?

  To answer your question: Yes, you can still keep the result set of a query and the Treaty as if it were a table or vew, like this:

  WITH     roots     AS
  (
       SELECT     *
       FROM     events
       WHERE     created_date     < SYSDATE - 90
       AND     parent_event_id     IS NULL
  )
  SELECT     *
  FROM     roots
       --
  UNION ALL
          --
  SELECT     *
  FROM     events
  WHERE     created_date     < SYSDATE - 90
  AND     parent_event_id     IN (
                        SELECT  event_id
                        FROM    roots
                    )
  ;
  

  It's always a bit ugly, however. I would use CONNECT BY or from Oracle 11.2, a recursive WITH clause (which is explicitly a UNION), or, in any version, a self-join, like this:

  SELECT     c.*
  FROM          events  c
  LEFT OUTER JOIN     events     p  ON   p.event_id  = c.parent_event_id
  WHERE   p.parent_event_id  IS NULL
  ;
  

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
  Report where the queriy above (the one you decide to use) is producingthe bad results and explain, using specific examples, how you get the right results from these data in these places.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

• Copy a few lines in the same table, but with different IDS

  Hi all
  I had this problem... I have a table with its pk (which is a sequence). With a statement select, I extract a few lines, and then I would record in the same table, but with IDS different (obviously eheheh).
  
  I don't know how to do...
  
  Thks for all help ;)
  
  
  p.s. I want to change some fields in lines before saving as well... don't know how do it more...
  
  example:
  
  ID NAME TYPE
  1 ferrari car
  2 cars lamborghini
  
  
  I'm trying to copy the second and changing its type in "BMW".
  
  I could result:
  
  1 ferrari car
  2 cars lamborghini
  3 bmw cars
  
  
  
  Thank you

  Assuming that your table is named cars_tb and the cars_seq of the sequence.

   insert into cars_tb
    select cars_seq.nextval, name, type
    from cars_tb
  

  This would overlap with any existing lines, but with a new id.

  If you want to duplicate a specific line and change a value, you could do something like:

   insert into cars_tb
    select cars_seq.nextval, name, 'BMW'
    from cars_tb
    where type = 'lamborghini'
  

  or better, use the PK

   insert into cars_tb
    select cars_seq.nextval, name, 'BMW'
    from cars_tb
    where id = 2
  

• Updated with the values in the same table, for other records corresponding to conditions

  Hi Experts,

  Sorry do not provide the structure of the table (it is a simple structure)

  I have a requirement where I need to update the columns of a table based on the same table with some match empid and date values. If the date and empid match so I have these values to any other folder and update of one who is not having details of Office . I need the Update query

  Before the update my array of values is as below

  Sort_num Emp_id Bureau start_date

  1 101 AUS 01/01/2013
  2 101 01/01/2013
  3 101 15/01/2013
  4 103 USA 01/05/2013
  5 103 01/01/2013
  6 103 05/01/2013
  7 104 FRA 01/10/2013
  8 104 10/01/2013
  9 104 01/01/2013

  After update my table should be as below

  Sort_num Emp_id Bureau start_date

  1 101 AUS 01/01/2013
  2 101 AUS 01/01/2013
  3 101 15/01/2013
  4 103 USA 01/05/2013
  5 103 01/01/2013
  6 103 USA 01/05/2013
  7 104 FRA 01/10/2013
  8 104 FRA 01/10/2013
  9 104 01/01/2013

  Thanks in advance

  I don't have the time to create the table with the data, but basically, you should be able to code the following text

  update one table

  Office set = (select desktop in table b where b.emp_id = a.emp_id)

  and b.start_date = a.start_date

  and b.office is not null

  )

  where is ([as well as overall query])

  and a.office is null

  In my opinion, who will do the trick.

  HTH - Mark D Powell.

• Comparing the same tables of two schemas

  I had already posted a similair on this thread. So, I thought I would start a new thread on this to avoid confusion
  
  I want to generate a report that shows the difference in the data type of the columns in the same table in two different patterns.
  
  The query using LESS shows the difference below.
  
  

  create table SCOTT.mytab1 (empid number);
  create table HR.mytab1 (empid varchar2(34));
  
  
  SELECT   table_name, column_name, OWNER schema, data_type
  FROM     dba_tab_cols where owner = 'SCOTT'
  AND TABLE_NAME = 'MYTAB1'
  MINUS
  SELECT   table_name, column_name, OWNER schema, data_type
  FROM     dba_tab_cols where owner = 'HR'
  AND TABLE_NAME = 'MYTAB1'
  
  Result:
  TABLE_NAME      COLUMN_NAME     SCHEMA     DATA_TYPE
  --------------- --------------- ---------- ------------
  MYTAB1          EMPID           SCOTT      NUMBER

  But, since it is a report, I want to see the form of results the two schemas that has column of different data types with the same names of table
  
  Expected results:

  TABLE_NAME      COLUMN_NAME     SCHEMA     DATA_TYPE
  --------------- --------------- ---------- ------------
  MYTAB1          EMPID           SCOTT      NUMBER
  MYTAB1          EMPID           HR         VARCHAR2

  Anyway I could do this?

  Why not get a single line with two types of data:

  select a.table_name, a.column_name, a.data_type schema1_type, b.data_type schema2_type
  from all_tab_columns a, all_tab_columns b
  where a.owner = 'SCOTT'
  and b.owner = 'HR'
  and a.table_name=b.table_name
  and a.column_name=b.column_name
  and a.data_type!=b.data_type;
  

  This extracted single query columns present on the two schemas but with different data types. These columns only on one of the two schemas are not extracted.

  Max

• update to column values (false) in a copy of the same table with the correct values

  Database is 10gr 2 - had a situation last night where someone changed inadvertently values of column on a couple of hundred thousand records with an incorrect value first thing in the morning and never let me know later in the day. My undo retention was not large enough to create a copy of the table as it was 7 hours comes back with a "insert in table_2 select * from table_1 to timestamp...» "query, so I restored the backup previous nights to another machine and it picked up at 07:00 (just before the hour, he made the change), created a dblink since the production database and created a copy of the table of the restored database.
  
  My first thought was to simply update the table of production with the correct values of the correct copy, using something like this:
  
  
  Update mnt.workorders
  Set approvalstat = (select b.approvalstat
  mnt.workorders a, mnt.workorders_copy b
  where a.workordersoi = b.workordersoi)
  where exists (select *)
  mnt.workorders a, mnt.workorders_copy b
  where a.workordersoi = b.workordersoi)
  
  It wasn't the exact syntax, but you get the idea, I wanted to put the incorrect values in x columns in the tables of production with the correct values of the copy of the table of the restored backup. Anyway, it was (or seem to) works, but I look at the process through OEM it was estimated 100 + hours with full table scans, so I killed him. I found myself just inserting (copy) the lines added to the production since the table copy by doing a select statement of the production table where < col_with_datestamp > is > = 07:00, truncate the table of production, then re insert the rows from now to correct the copy.
  
  Do a post-mortem today, I replay the scenario on the copy that I restored, trying to figure out a cleaner, a quicker way to do it, if the need arise again. I went and randomly changed some values in a column number (called "comappstat") in a copy of the table of production, and then thought that I would try the following resets the values of the correct table:
  
  Update (select a.comappstat, b.comappstat
  mnt.workorders a, mnt.workorders_copy b
  where a.workordersoi = b.workordersoi - this is a PK column
  and a.comappstat! = b.comappstat)
  Set b.comappstat = a.comappstat
  
  Although I thought that the syntax is correct, I get an "ORA-00904: 'A'. '. ' COMAPPSTAT': invalid identifier ' to run this, I was trying to guess where the syntax was wrong here, then thought that perhaps having the subquery returns a single line would be cleaner and faster anyway, so I gave up on that and instead tried this:
  
  Update mnt.workorders_copy
  Set comappstat = (select distinct)
  a.comappstat
  mnt.workorders a, mnt.workorders_copy b
  where a.workordersoi = b.workordersoi
  and a.comappstat! = b.comappstat)
  where a.comappstat! = b.comappstat
  and a.workordersoi = b.workordersoi
  
  The subquery executed on its own returns a single value 9, which is the correct value of the column in the table of the prod, and I want to replace the incorrect a '12' (I've updated the copy to change the value of the column comappstat to 12 everywhere where it was 9) However when I run the query again I get this error :
  
  ERROR on line 8:
  ORA-00904: "B". "" WORKORDERSOI ": invalid identifier
  
  First of all, I don't see why the update statement does not work (it's probably obvious, but I'm not)
  
  Secondly, it is the best approach for updating a column (or columns) that are incorrect, with the columns in the same table which are correct, or is there a better way?
  
  I would sooner update the table rather than delete or truncate then re insert, as it was a trigger for insert/update I had to disable it on the notice re and truncate the table unusable a demand so I was re insert.
  
  Thank you

  Hello

  First of all, after post 79, you need to know how to format your code.

  Your last request reads as follows:

  UPDATE
    mnt.workorders_copy
  SET
    comappstat =
    (
      SELECT DISTINCT
        a.comappstat
      FROM
        mnt.workorders a
      , mnt.workorders_copy b
      WHERE
        a.workordersoi    = b.workordersoi
        AND a.comappstat != b.comappstat
    )
  WHERE
    a.comappstat      != b.comappstat
    AND a.workordersoi = b.workordersoi
  

  This will not work for several reasons:
  The sub query allows you to define a and b and outside the breakets you can't refer to a or b.
  There is no link between the mnt.workorders_copy and the the update and the request of void.

  If you do this you should have something like this:

  UPDATE
    mnt.workorders     A      -- THIS IS THE TABLE YOU WANT TO UPDATE
  SET
    A.comappstat =
    (
      SELECT
        B.comappstat
      FROM
        mnt.workorders_copy B   -- THIS IS THE TABLE WITH THE CORRECT (OLD) VALUES
      WHERE
        a.workordersoi    = b.workordersoi      -- THIS MUST BE THE KEY
        AND a.comappstat != b.comappstat
    )
  WHERE
    EXISTS
    (
      SELECT
        B.comappstat
      FROM
        mnt.workorders_copy B
      WHERE
        a.workordersoi    = b.workordersoi      -- THIS MUST BE THE KEY
        AND a.comappstat != b.comappstat
    )
  

  Speed is not so good that you run the query to sub for each row in mnt.workorders
  Note it is condition in where. You need other wise, you will update the unchanged to null values.

  I wouold do it like this:

  UPDATE
    (
      SELECT
        A.workordersoi
        ,A.comappstat
        ,B.comappstat           comappstat_OLD
  
      FROM
        mnt.workorders        A      -- THIS IS THE TABLE YOU WANT TO UPDATE
        ,mnt.workorders_copy  B      -- THIS IS THE TABLE WITH THE CORRECT (OLD) VALUES
  
      WHERE
        a.workordersoi    = b.workordersoi      -- THIS MUST BE THE KEY
        AND a.comappstat != b.comappstat
    ) C
  
  SET
    C.comappstat = comappstat_OLD
  ;
  

  This way you can test the subquery first and know exectly what will be updated.
  This was not a sub query that is executed for each line preformance should be better.

  Kind regards

  Peter

• Insert select on the same table: possible without side effects?

  I have a very large table T1 containing millions of records. I need to treat its lines and create a few new lines based on selection.

  Table T1 contains events and one of them, with the code 100, is created by the further development of other events inside the table.

  My code is as follows:

  insert /*+append */ into T1 (code,...) values (100, c1,c2,...)
  select c1,c2... from T1 where (code=20 or code=10) and <other conditions>...
  
  

  as you can see I'm extract T1 lines to insert again in T1 with a different code and I use the direct path in order to get good performance.

  My fear is: choose is made from the same table I risk data loss? In general it is a good practice? Or is it better to create another table?

  Hello

  No I don't think that there may be loss of data. But that may depend on the behavior of the application and your where clause.

  I will explain how it is treated, so you can see if it's ok:

  1. the table is locked because of the insert add, (as)

  2 lines are read by select and make compatible from the State that was at the beginning of the query - 1.

  3 rows are inserted at the end, after the high-water line

  4 columns for new lines are sorted to be merged in the index

  5. high watermark is adjusted - visible new lines and lock is released

  Note that 2. and 3. occur at the same time: rows are inserted all read.

  Note that anyone can choose in the table during the operation - they see the changes committed only - if the State 1.

  all other DML are waiting for the lock being released, and will see new ranks and then

  If you have things that prevent the direct-path insert, append the hint will be ignored. So, if you must rely on close to 1. then the best lock explicitly with table lock. But I don't think that you need.

  Kind regards

  Franck.