Comparing the same tables of two schemas

Similar Questions

• How can I align two different text lines in the same table in two different directions (centered on one and one on the left)?

  Hello

  I want to focus the two different text lines that are in the same table, but one on the Center and the other on the left. I put a < span > tag in the hope that he was overwhelmed the family of police .bottomsel table class properties and the. Police-family Cig84 and color but the text-align only: they are both on the left.

  Here is my source and CSS codes:

  Source:

  < table width = "600" border = "0" >

  < b >

  < class td = "bottomref" > < p > < span class = "bottomsel" > | < a href = "index.html" target = "_self" > Main < /a > | " < a href = "about.html" target = "_self" > on < /a > | " < a href = "clients.html" target = "_self" > customers < /a > | " < a href = "contact.html" target = "_self" > Contact < /a > | " </span > < br / >

  < span class = 'credits' > credits: < span class = "Cig84" > Cig84 </span > < / span > < /p > < table >

  < /tr >

  < /table >

  CSS:

  {.bottomsel}

  text-align: center;

  do-family: Georgia, "Times New Roman", Times, serif;

  }

  {.credits}

  text-align: left;

  }

  . {Cig84}

  Color: #F00;

  do-family: "Comic Sans MS", cursive;

  }

  Use tags to paragraph with CSS classes.

  CSS:

  . Center {text-align: center}

  .the {text-align: left}

  HTML:

  This text is centered This text is left-aligned

  Nancy O.

• Compare two rows in the same table

  Hi all
  
  I need to compare two rows in the same table, I don't know hoe to do it in pl/sql. Please help me on this.
  
  example:
  
  price of ro TR
  xya0001 AMA.7 12
  xya0003 ama6 14
  xya0004 AMA.7 16
  
  in table b is a unique value for each line, I need to compare the price column and see if the first value is less than or greater than the following value and, if there is more to put the corresponding value of br to a variable, and if it is less, put the corresponding value of the br to another variable. I don't know a method to do this, as I'm new to pl/sql. Please help me in this

  for data in(select tr,br,price, lag(price) over ( order by tr) newcol
  from yourtable)
  loop
  if nvl(data.newcol,0) > data.price then
  variable1:=data.br;
  else
  varable2:=data.br;
  end if;
  end loop;
  

• comparing string values in the same table

  I have a table with ID (14 digit string values) starting with "A". Ex: A21849B1020792. There may be a different ID with the same substring 'B1020792' in the same table, example: A12349B1020792. If this happens, the ID of the last creation date of must be returned in the result. In other words, comparison is done on the same table. "In the example provided, say A12349B1020792 has the date of 1 January 2015 'and A21849B1020792 has date February 1, 2015", since A21849B1020792 has the most recent date, the result must contain only A21849B1020792.

  ID create_date

  ---                              ------------------

  A21849B1020792 02/01/2015

  A12349 B1020792 01/01/2015

  A12345B1234567 01/03/2015      

  A43567B1234567 01/04/2015      

  
  Here's the query I used:

  substr (a.id, 7) select sc, max (a.create_date) cd1

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A12349B1020792', 'A21849B1020792','A12345B1234567 ','A43567B1234567')

  Group of substr (a.id, 7);

  Result:

  ---------

  sc                    cd1

  ---                    ------

  B1020792 02/01/2015

  B1234567 04/01/2015

  There is one thing that I'm not able to do with my request, that is, be able to get real IDs list and not list of substrings. If I added a.id column in the select clause and the group by clause, the query includes both by substr (a.id, 7) and a.id and as a result, the query returns four lines as below:

  substr (a.id, 7) select sc, max (a.create_date) cd1, a.id ID

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A12349B1020792', 'A21849B1020792','A12345B1234567 ','A43567B1234567')

  Group by substr (a.id, 7), a.id.

  Result:

  ---------

  sc                    cd1                      ID

  ---                    ------                   ---------

  01/01/2015 A12349B1020792 B1020792

  B1020792 01/02/2015 A21849B1020792

  B1234567 01/03/2015 A12345B1234567

  B1234567 01/04/2015 A43567B1234567

  
  

  My goal is to retrieve a list of all the unique identifiers that have the later dates.

  
  

  ID:

  ---

  A21849B1020792

  A43567B1234567

  
  

  Thanks for your time in advance!
  

  Hello

  user11951344 wrote:

  I have a table with ID (14 digit string values) starting with "A". Ex: A21849B1020792. There may be a different ID with the same substring "B1020792" in the same table, example: A12349B1020792. If this is the case, the ID of the last creation date must be returned in the result. In other words, comparison is done on the same table. "In the example provided, say A12349B1020792 updated 1 January 2015 ' and A21849B1020792 a date February 1, 2015", as A21849B1020792 has the most recent date, the result should contain only the A21849B1020792.

  ID create_date

  ---                              ------------------

  A21849B1020792 02/01/2015

  A12349B1020792 01/01/2015

  A12345B1234567 03/01/2015

  A43567B1234567 01/04/2015

  Here's the query I used:

  substr (a.id, 7) select sc, max (a.create_date) cd1

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A21849B1020792', 'A12345B1234567', 'A12349B1020792', 'A43567B1234567')

  Group of substr (a.id, 7);

  Result:

  ---------

  sc                    cd1

  ---                    ------

  B1020792 02/01/2015

  B1234567 01/04/2015

  There is one thing that I am not able to do with my request, that is, the ability to retrieve the list of IDs real and not a list of substrings. If I added a.id column in the select clause and the group by clause, the query groups according to the two substr (a.id, 7) and a.id and as a result, the query returns four lines as below:

  substr (a.id, 7) select sc, max (a.create_date) cd1, a.id ID

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A21849B1020792', 'A12345B1234567', 'A12349B1020792', 'A43567B1234567')

  Group by substr (a.id, 7), a.id.

  Result:

  ---------

  sc                    cd1                      ID

  ---                    ------                   ---------

  B1020792 01/01/2015 A12349B1020792

  B1020792 02/01/2015 A21849B1020792

  B1234567 03/01/2015 A12345B1234567

  B1234567 01/04/2015 A43567B1234567

  My goal is to retrieve a list of all the unique identifiers that have the later dates.

  ID:

  ---

  A21849B1020792

  A43567B1234567

  Thanks for your time in advance!

  If it makes sense to treat the first 6 characters of the ID separately from the rest of the id in this problem, maybe it makes sense to store those two parts of the id in two different columns.  Relational databases work best when each column of each row contains 1 single piece of data (at most).  It is so fundamental to the design of table that he called the first normal form.

  Given that the two parts are stored in column 1, so you can something like this Request Top - N:

  WITH got_r_num AS

  (

  SELECT r.id

  r.create_date AS cd1

  , RANK () OVER (PARTITION OF SUBSTR (r.id, 7))

  ORDER BY r.create_date DESC

  ) AS r_num

  FROM table_x g - g for data values

  JOIN table_x r - r for related values

  ON SUBSTR (r.id, 7) = SUBSTR (g.id, 7)

  WHERE g.id IN ('A12349B1020792'

  , "A21849B1020792".

  , "A12345B1234567".

  , "A43567B1234567".

  )

  - AND g.id LIKE 'A %' - if necessary.   The above condition ensures already g.id start with "A".

  AND r.id LIKE 'a % '.

  )

  SELECT id, create_date

  OF got_r_num

  WHERE r_num = 1

  ;

  If you would care to post CREATE TABLE and INSERT instructions for the sample data, and then I could test this.

• If I have the two LOV in the same table then how to connect when I select first and second LOV value also change?

  Mr President

  If I have the two LOV in the same table then how to connect when I select first and second LOV value also change?

  My two fields are FLOW AND DR_NAME

  FLOW = ACCT_ID

  DR_NAME = ACCT_NAME

  I created with success of LOV for these fields.

  First LOV gives acct_id in the debit field and second LOV gives the value of acct_name to dr_name.

  How can I report these lov, it's that when I change my acct_id then acct_name also change

  I have these two tables

  CREATE TABLE "NOM"  (
    "ACCT_ID" VARCHAR2(7) NOT NULL ENABLE, 
    "ACCT_NAME" VARCHAR2(50) NOT NULL ENABLE, 
    "O_BAL" NUMBER(13,2),
    CONSTRAINT NOM_PK PRIMARY KEY ("ACCT_ID")ENABLE
     
     );
  CREATE TABLE "VOUCHERDET" (
    "V_ID" VARCHAR2(9) NOT NULL ENABLE,
    "LINEITEM" NUMBER ,
    "DEBIT" VARCHAR2(7) , 
    "DR_NAME" VARCHAR2(50), 
    "CREDIT" VARCHAR2(7) , 
    "CR_NAME" VARCHAR2(50), 
    "PARTICULARS" VARCHAR2(100), 
    "AMOUNT" NUMBER(21,2),
  CONSTRAINT VOUCHERDET_PK PRIMARY KEY ("V_ID","LINEITEM")ENABLE, 
  CONSTRAINT PUR_SAL_LINE_POD_FK FOREIGN KEY(PROD_ID)
    REFERENCES PRODUCTS (PROD_ID)ENABLE,  
  CONSTRAINT VOUCHERDET_DEBIT_FK FOREIGN KEY ("DEBIT")
     REFERENCES "NOM" ("ACCT_ID") ENABLE, 
  CONSTRAINT VOUCHERDET_CREDIT_FK FOREIGN KEY ("CREDIT")
     REFERENCES "NOM" ("ACCT_ID") ENABLE,  
  CONSTRAINT VOUCHERDET_V_FK FOREIGN KEY ("V_ID")
     REFERENCES "VOUCHER" ("V_ID") ON DELETE CASCADE ENABLE
    );
  
  

  Concerning

  so, instead of this second ActId, choose ACCT_NAME:

  

• FRM - 40202:Field must be entered on two blocks with the same table

  I have two blocks, blockA and blockB, both from the same table that is tableX.
  
  When I ask of blockA and it worked, then I go to blockB and modify data, and save, there is no problem. But when I do not run the query of blockA or if the query did not return any results, I go to blockB and change some data then save, I got this error. The cursor then go to first blockA point. So now, I have to delete this empty line before the Save.
  
  
  Any suggestion?

  you set a few initial values programmatically for a block?
  in this case, the status changes to INSERT and you will get this message.
  You can check the staus with GET_RECORD_PROPERTY (1, "A BLOCK", STATUS), e.g. with the trigger KEY-COMMIT.

• Comparison of columns in the same Table, with the exception

  Hi all
  
  
  I need compare two values of column in the same table. But should ignore a few characters like space, comma, point
  
  Following should be consistent
  

  'ABcd f' = 'AbCDf'
  'xyz ..' = 'xy z'

  How is it possible
  
  
  See you soon
  
  Sexy

  with t as
  (
  select 'ABcd f' col1,'AbCDf' col2 from dual union all
  select 'xyz ..','xy z' from dual union all
  select 'xyz ..x','xy z' from dual
  )
  select *
  from t
  where upper(translate(col1,'a ,.','a')) =
             upper(translate(col2,'a ,.','a'));
  
  COL1    COL2
  ------- -----
  ABcd f  AbCDf
  xyz ..  xy z  
  

  Published by: JAC on 4 February 2013 17:22

• Sinlge select query in the diff for the same table (same Structure) diagrams

  Scenario:
  
  Table XYZ is created in detail a.
  After a year, the old data of the previous year could be moved to another schema. However in the other schema of the same table name would be used.
  
  For example
  
  A schema contains XYZ table with data from the year 2012
  Schema B contains XYZ table with data for the year 2011
  Table XYZ in the two schemas have an identical structure.
  
  So we can draw a single select query to read the data from the tables in an effective way.
  For example select * from XYZ so including date between October 15, 2011 to March 15, 2012.
  However, the data resides in 2 different schema altogether.
  
  
  Creating a view is an option.
  But my problem, there are ORM (Hibernate or Eclipse Top Link) layer between the application and the database.
  If the queries would be constituted by the ORM layer and are not generated by hand.
  So I can't use the view.
  So is there any option that would allow me to use only query on different scheme?

  970773 wrote:
  Scenario:

  Table XYZ is created in detail a.
  After a year, the old data of the previous year could be moved to another schema. However in the other schema of the same table name would be used.

  For example

  A schema contains XYZ table with data from the year 2012
  Schema B contains XYZ table with data for the year 2011
  Table XYZ in the two schemas have an identical structure.

  So we can draw a single select query to read the data from the tables in an effective way.
  For example select * from XYZ so including date between October 15, 2011 to March 15, 2012.
  However, the data resides in 2 different schema altogether.

  Creating a view is an option.
  But my problem, there are ORM (Hibernate or Eclipse Top Link) layer between the application and the database.
  If the queries would be constituted by the ORM layer and are not generated by hand.
  So I can't use the view.

  Why not make the ORM as below?

  SELECT * FROM VIEW_BOTH;
  -VIEW_BOTH is a real VIEW of Oracle

• Three blocks in the same way, belong to the same table

  Hi people,

  I am trying to find a way to make this work. I have currently 3 blocks on the form even where the first block is on the main canvas in blocks 2 and 3 will be on separate bunk canvases. According to a column value (Radio button group), I'll show stacked canvas 1 (block 2) or stacked canvas 2 (block 3). Unfortunately, all these elements must remain in the same table. I also keep them in separate blocks because some of the columns must be in two blocks.

  Landing up, which happens is that before INSERT trigger pulls the two blocks (since BLOCK_STATUS of the second block's NEW as well) and I'm landing by creating two records which is obviously a no-no situation.

  I tried the trigger for INSERTION WE with null, but then what's going on, it's that nothing is saved.

  For any idea or suggestion would be greatly appreciated.

  I use Forms 9i.

  Have a great weekend.

  Thank you!

  Perhaps this - make sure that a single database block, which has the "mirror elements' (use to synchronize it with the Item property).

  Kind regards

  Zlatko

• Update of several rows of the same table using trigger

  Hello

  I have the following table

  ---------------------------------------------------------------------------------------------------------

  CREATE TABLE ATT_PERMISSIONS
  (
  DATE OF PRMONTHYR,
  EMPID	NUMBER (10)	DEFAULT VALUE 0	,
  FROMDATETIME	DATE		,
  TODMTFDATETIME	DATE		,
  NUMBER OF PERMMINS (3),

  SSLINASTRETCH NUMBER (3).

  PERMATTINELIGIBLE	NUMBER (1)	DEFAULT VALUE 0
  );

  ------------------------------------------------------------------------------------------------------

  I want to update the column PERMATTINELIGIBLE in the same table when each line is inserted.

  I created following trigger for that

  CREATE OR REPLACE TRIGGER SSL_AFTER_UPDATE AFTER UPDATE ON ATT_PERMISSIONS

  FOR EACH LINE

  BEGIN

  Update ATT_PERMISSIONS set PERMATTINELIGIBLE =

  (

  SELECT THE CHECK BOX

  WHEN PERMMINS < = 60

  or

  (

  PERMMINS < = SSLINASTRETCH

  AND

  COUNT (CASE WHEN PERMMINS = 0 THEN NULL OTHERWISE 1 END)

  COURSES (PARTITION BY empid, prmonthyr) < = 1

  )

  THEN 1

  0 OTHERWISE

  END

  FROM ATT_PERMISSIONS where prmonthyr =:new.prmonthyr, empid =:new.empid

  ) where prmonthyr =:new.prmonthyr, empid =:new.empid;

  END;

  ---------------------------------------------------------------------------------------------------

  That is to say.

  When a row is inserted the PERMATTINELIGIBLE of all records for this employee for the month is recalculated.

  There would be only two or three records for an employee for a month.

  PERMMINS is the number of minutes to use as short leave.

  If it is less than 60 is eligible for the bonus to attendance for this employee.

  If this isn't normally the date is not eligible for the attendance for this employee premium.

  but an exception is that if a short leaves of DISP employee allowed a month (IE. ( SSLINASTRETCH ) in a straight line, IE. one day, that day is eligible for the bonus of presence.

  That is to say. Why the number of short leaves in a month is taken. If it's one and done minutes use is lower to SSLINASTRETCH, then the day is eligible for the attendance bonus.

  But when I try to create the trigger I get error, PL/SQL: ORA-00907: missing a right parenthesis.

  Help, please

  I use oracle 10g

  I want to update the column PERMATTINELIGIBLE in the same table, when each row is inserted.

  No - you do NOT want to do in a trigger.

  You cannot query the same table that the trigger is activated on. -C' is a MUTANT and you will get an exception.

  When a row is inserted is recalculated to the PERMATTINELIGIBLE of all the records for that employee for that month.

  There would be only two or three records for an employee for a month.

  PERMMINS is the number of minutes to use as short leave.

  If it is less than 60 is eligible for the bonus to attendance for this employee.

  If is not normally the day is not eligible for the premium of attendance for this employee.

  but an exception is that if a short leaves of DISP employee allowed a month (IE. SSLINASTRETCH) in a straight line, IE. one day, that day is eligible for the bonus of presence.

  That is to say. Why the number of short leaves in a month is taken. If it's one and done minutes use is less than SSLINASTRETCH, then the day is eligible for the bonus of presence.

  But when I try to create the trigger I get error, PL/SQL: ORA-00907: missing a right parenthesis.

  You can not do in a trigger. Even if correct you this error of syntax, you will get the exception that I mentioned above.

  Oracle is a multi-user system. Other users can modify the same table that you use.

  So even if you could try to interview "all the records for this employee" some of them may be locked if other users access them. Also, an insert statement could try to insert two rows for an employee and the trigger could not have seen the other lines still.

  If you want to work with data SETS (all records for an employee), you must write the PL/SQL code that LOCKS all lines updated to prevent others to interfere.

  Then you make your operations but NOT in a trigger. Perform inserts and then use an UPDATE query to set this value.

  Then VALIDATE to unlock the lines.

• Question: Is foreign key references to a different column in the same table

  Hello

  I'm not grasp this concept. Would you be able to provide the logic how and why you need to create a foreign key that references a column of the same table?

  For example, referencing the schema, SupervisorNo @ here is a FOREIGN KEY to the "EmpNo" column in the same table.

  EMPLOYEE (EmpNo, title, Fname, Lname, phone, Email, date of birth, sex, salary, HireDate, OutNo, SupervisorNo @)

  
  

  Why would you want to do this and how can it be used? If you are filling out the data in the table, and this constraint is enabled, you will not be able to load whatever it is because the "EmpNo" column will be empty.

  
  

  Any input you can provide me with this would be greatly appreciated. Thank you!

  
  

  
  

  His name

  Self-referential integrity constraints

  Lets say that we have the table emp with emp_no and mgr_no columns.

  Now all managers should also be an employee too. How can I check this when inserting data into this table? I applied auto integrity constraint. It would help me to make sure no handler (doesn't mean no mgr_no) must be registered if this Manager is not an employee of this organization. Which means, I won't be able to enter any mgr_no in the column until and unless that the same employee also is an employee (emp_no from the same table).

  Check the link as well below.

  Data integrity

  Thank you

  Ishan

• Code and the database tables in different schemas

  Hello
  My version of db: database Oracle 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production
  
  I would like to understand the advantages and disadvantages of the following situation:
  We have only one request.
  The design of the db for this application has 44 paintings, of which 28 are base tables related by PK and FK relations. The other 16 are look upward and refer to tables that are not related to one.
  The team has decided to place the tables in a diagram 28 A and the other 16 in another schema B within the same database. (The reason for this is... because it's done in other projects to do it here too).
  Coming now to the code (stored procedures, functions, packages, etc.). Teams want to ask most of the code in the diagram B with the Ref 16 tables. (the reason being again the same).
  What are the advantages and disadvantages this?
  Please advice.
  
  PS:
  I have googled and find something on these lines:

  cons:  
  o harder to manage
  o harder to upgrade
  o harder to patch
  o harder to maintain
  o causes your shared pool size to increase 1,000 times (shared sql goes down the tubes)
  o takes more space
  o queries against the dictionary will be impacted
  o latching on the shared pool goes WAY up (latching = locks = serialization device = 
  slows you down)
  
  pros:
  o none that I can think of.

  From my experience, if you see natural divisions that give you smaller patterns, well contained, you should take advantage of them and start with separate schemas. If done correctly, it can greatly improve the maintainability of your application.

  Assume that your initial project will have 60 paintings and they might fall into three groups of 15, 20 and 25 tables respectively. There are also objects of code such as PL/SQL packages. Your choice is:
  -Use a single scheme of 60 paintings, suppose that with 100 objects in code.
  -Use 3 diagrams divided as described. The total code objects will probably be a little more that unique schema design, because they need to provide interfaces with others. So let's assume that schemas will have 30, 40 and 50 code objects each.

  Now, wait 3 years.

  The history of single-schema:
  -The single-schema is passed to 120 tables. There has been a corresponding increase in code, now more than 200 objects. But they are very complex. Over time, each piece of code will interact with the tables more and more and many other objects in code.
  -You (the architect or Manager) can not really apply any internal for this structure since no subsidy is required to add dependencies. Therefore, if you change a table there is a vast impact.
  -You can easily divide the responsibilities because everything affects everything else. You can't manage simultaneous development efforts because the impact widespread changes cause the same tables/components to be affected by multiple projects. If you have the project execution dependencies / as you have interdependencies technique/code.
  -You have a "big ball of mud" and it is very difficult to get out of this situation.

  Multi-schema history:
  -Each of the 3 original patterns has grown, but some more than others. A fourth was added a year ago, when there was a major expansion in a new district, as a result of "natural divisions.
  -On the inside of each of these schemas, it is always a challenge to impose internal structure. But those patterns more smaller and therefore more small problems.
  -Through schemes, subsidies are necessary to allow interaction, this is not a "wild west" where everyone can access everything (and introduce dependencies on everything). Teams to define interfaces (packages or the views that are specifically intended to be interface points) where the interactions with other scehmas are necessary.
  -If changes to a table are needed, the impact can be limited to the schema that contains naturally. You know that no one else has created dependencies at this table, because you were never issued grants on this.
  -The responsibility for these schemas was divided between 2 teams, each team having full responsibility for its 2 diagrams.
  -Teams can complete projects much more easily, even with a parallel development, because there is less than a "domino effect" with each change.

  Now, these benefits depend on "natural divisions that give you the diagrams smaller, well contained." If you make the wrong choice here, you will always have a mess. You design with the end in mind scenario.

• UPDATE on the same table in the sub query

  DB version: 11.2
  
  We have a table called SHP_GC_TRACK, which has about 8 million records with partitions. In the below UPDATE, it updates a column based on the SELECT on the same table in a subquery.
  

  UPDATE shp_gc_track a
     SET f_tran_proc  = 'Y'
   WHERE last_update_date <
            (SELECT MAX (last_update_date)
               FROM shp_gc_track b
              WHERE a.shp_trx_rowid = b.shp_trx_rowid
                AND a.c_shp_inst = b.c_shp_inst
                AND a.f_tran_proc  = b.f_tran_proc 
                AND b.f_ltr_received = 'D'
                AND f_rec_code IN ('G', 'W')
                AND b.f_rec_status = 'B'
                AND b.c_shp_inst = :b1
                )
     AND a.c_shp_inst = :b1
     AND a.f_ltr_received = 'D'             -----------------> part of composite index
     AND a.f_tran_proc  = 'N'              -----------------> part of composite index
     AND a.f_rec_code IN ('G', 'W')      --------------> part of composite index  
     AND a.f_rec_status = 'B';              -----------------> part of composite index  

  This UPDATE takes a long time to run and sometimes get hung up.
  
  We have a composite index on four columns f_ltr_received, f_rec_code, f_rec_status and f_tran_proc. Explain the plan shows that this composite index is used.
  
  
  
  Any way to rewrite this query or suggestion?

  Steve_74 wrote:
  DB version: 11.2

  We have a table called SHP_GC_TRACK, which has about 8 million records with partitions. In the below UPDATE, it updates a column based on the SELECT on the same table in a subquery.

  UPDATE shp_gc_track a
  SET f_tran_proc  = 'Y'
  WHERE last_update_date <
  (SELECT MAX (last_update_date)
  FROM shp_gc_track b
  WHERE a.shp_trx_rowid = b.shp_trx_rowid
  AND a.c_shp_inst = b.c_shp_inst
  AND a.f_tran_proc  = b.f_tran_proc
  AND b.f_ltr_received = 'D'
  AND f_rec_code IN ('G', 'W')
  AND b.f_rec_status = 'B'
  AND b.c_shp_inst = :b1
  )
  AND a.c_shp_inst = :b1
  AND a.f_ltr_received = 'D'             -----------------> part of composite index
  AND a.f_tran_proc  = 'N'              -----------------> part of composite index
  AND a.f_rec_code IN ('G', 'W')      --------------> part of composite index
  AND a.f_rec_status = 'B';              -----------------> part of composite index  
  

  This UPDATE takes a long time to run and sometimes get hung up.

  We have a composite index on four columns f_ltr_received, f_rec_code, f_rec_status and f_tran_proc. Explain the plan shows that this composite index is used.

  Any way to rewrite this query or suggestion?

  Setting updates with subqueries may be difficult: (.) Unfortunately my suggestions below are of the try-it-and-see-what-happens variety - nothing of certain

  First of all, check the index. Is it bitmap or tree? If the tree to see if the more restrictive columns are listed first - this can help with effectiveness of b-tree indexes. Also if the tree a composite bitmap for columns with lots of repeat values instead could help

  Its a correlated subquery so that you cannot run just the subquery first put the result in a scalar varaiable and using the variable in the SQL instead. You can try putting the keys w/join subuqery results in a TWG first to use TWG in SQL to see if I/O is reduced together during these two operations.

  You have the license for the parallel query option? Using parallel DML (this must be activated manually) can help. Check the documentation of the ALTER SESSION command to do so. In addition, the PARALLEL_INDEX() indicator could help

  Display the SQL execution plan

• Developer SQL is no longer let me look at the same table on 2 servers name

  I used to be able to look at the same table (such as; "ATS_Reminders") on my development box and my box of production at the same time. Now when I connect the two databases, if I try to open the table even on the second square, the first table closed so I can't watch side by side. Is there a way to fix this annoying problem?
  
  I am on Windows 7 running:
  
  Java (TM) Platform 1.6.0_11
  Oracle IDE 3.1.07.42
  Support versioning 3.1.07.42

  Hi bucketofsquid.

  You need to pin the 1st Editor. This can be done manually by clicking on the view button to freeze on the toolbar of the object viewer or automatically by setting auto freeze on in the preferences. Tools-> preferences-> database-> ObjectViewer-> automatically freeze object viewer Windows

  Brian Jeffries
  SQL development team

• 2 forms to modify the same table at the same time

  I have a block record multi and now we add more fields to the table. I thought I had
  users press a button for a specific record in the block and then he would open another form (or something like that)
  to set up a regular shape where they may enter these details).
  But then I think two forms at the same time, changing the same table is going to be a problem.
  right?
  Is there a way to do what I want? I want the user to choose and to be able to change some things of 'a grid.
  aka multi-record block and then be able to go to a non tabular entry in the details form. Is it possible to do?

  then he would open another form (or something like that)

  Could be another form, or just another block in a different window/canvas or even field in the same block using 'Reflect the elements' ('synchronize with' - property)

  But then I think two forms at the same time, changing the same table is going to be a problem.

  Not necessarily. If you use CALL_FORM or OPEN_FORM without having to open a new session it is no problem to do so. You just check that the modifications of the form "first" are recorded or posted at least before opening detailed form.