compare the 4 fields in a table
Hi, today my brain pains, can someone please tell me how to compare 4 fields in a table to see if they are all equal?create table dm_test (n_1 number,
n_2 number,
n_3 number,
n_4 number);
INSERT INTO dm_test
(n_1,
n_2,
n_3,
n_4)
VALUES
(1,
1,
1,
1);
INSERT INTO dm_test
(n_1,
n_2,
n_3,
n_4)
VALUES
(3,
2,
2,
2);
INSERT INTO dm_test
(n_1,
n_2,
n_3,
n_4)
VALUES
(0,
0,
0,
3);
The result of my query must return onlyfirst row
1 1 1 1
Thanks people...
Maybe something like that?
SQL> SELECT *
2 FROM dm_test
3 WHERE n_1 = n_2
4 AND n_2 = n_3
5 AND n_3 = n_4
6 /
N_1 N_2 N_3 N_4
-------------------- -------------------- -------------------- --------------------
1 1 1 1
It won't however if you're concerned about NULL values. Do you want a row to return if they are NULL?
EDIT:
The version that supports the NULL:
SQL> INSERT INTO dm_test VALUES(NULL,NULL,NULL,NULL);
1 row created.
SQL> SET NULL '(null)'
SQL> SELECT *
2 FROM dm_test
3 WHERE NVL(n_1,-1) = NVL(n_2,-1)
4 AND NVL(n_2,-1) = NVL(n_3,-1)
5 AND NVL(n_3,-1) = NVL(n_4,-1)
6 /
N_1 N_2 N_3 N_4
-------------------- -------------------- -------------------- --------------------
1 1 1 1
(null) (null) (null) (null)
Edited by: Centinul May 14, 2010 07:07
Tags: Database
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