Concatenation of data with the GROUP BY clause

Hi again!

Following my previous thread...
Re: Need help with RANK() on data ZERO

I tried to apply the GROUP BY clause instead of preforming my query with RANK() to manage records NULL... I have a scenario where I also need to concatenate data from several lines.

CREATE TABLE T_EMP (NUMBER OF EMP_NO, NAME VARCHAR2 (20));
INSERT INTO T_EMP VALUES (1001, 'MARK');
INSERT INTO T_EMP VALUES (1002, 'DAVID');
INSERT INTO T_EMP VALUES (1003, "SHAUN");
INSERT INTO T_EMP VALUES (1004, "JILL");

CREATE TABLE T_EMP_DEPT (NUMBER OF EMP_NO, DEPT_NO NUMBER);
INSERT INTO T_EMP_DEPT VALUES (1001, 10);
INSERT INTO T_EMP_DEPT VALUES (1001, 20);
INSERT INTO T_EMP_DEPT VALUES (1002, 10);
INSERT INTO T_EMP_DEPT VALUES (1002, 20);
INSERT INTO T_EMP_DEPT VALUES (1002, 30);
INSERT INTO T_EMP_DEPT VALUES (1003, 20);
INSERT INTO T_EMP_DEPT VALUES (1003, 30);
INSERT INTO T_EMP_DEPT VALUES (1004, 10);

CREATE TABLE T_EMP_VISITS (NUMBER OF EMP_NO, DEPT_NO NUMBER, VISITED DATE);
INSERT INTO T_EMP_VISITS VALUES (1001, 10, 1 JAN 2009');
INSERT INTO T_EMP_VISITS VALUES (1002, 10, 1 JAN 2009');
INSERT INTO T_EMP_VISITS VALUES (1002, 30, 11 APR 2009');
INSERT INTO T_EMP_VISITS VALUES (1003, 20, 3 MAY 2009');
INSERT INTO T_EMP_VISITS VALUES (1003, 30: 14 FEB 2009');
COMMIT;

I have a T_EMP master table that stores the name and number of the emp. Each emp is required to visit some departments. This mapping is stored in the T_EMP_DEPT table. An employee can visit one or more departments. T_EMP_VISITS table stores the dates where the employee visited the services required. I need to view the report which should show when an employee all completed visits, which is the maximum date when it finished to visit all departments. If he did not visit any of the report should display date max, otherwise NULL. I was able to do using GROUP BY such proposed by Salim, but how do I show a list separated by commas of the services required for an employee in the same query.

SELECT
EMP_NO,
NAME,
MAX (DEPT_NO) KEEP (DENSE_RANK LAST ORDER BY VISITED) MAX_DEPT_NO,.
MAX (VISITED) KEEP (DENSE_RANK LAST ORDER PER VISIT) VISITS_COMP
DE)
SELECT
T_EMP. EMP_NO,
NAME,
T_EMP_DEPT. DEPT_NO,
VISITED
OF T_EMP
LEFT OUTER JOIN T_EMP_DEPT
ON T_EMP. EMP_NO = T_EMP_DEPT. EMP_NO
LEFT OUTER JOIN T_EMP_VISITS
ON T_EMP_DEPT. EMP_NO = T_EMP_VISITS. EMP_NO
AND T_EMP_DEPT. DEPT_NO = T_EMP_VISITS. DEPT_NO)
GROUP EMP_NO, NAME;

Output
EMP_NO NAME MAX_DEPT_NO VISITS_COMP
1001 MARK 20
1002 DAVID 20
1003 SHAUN 20 3 MAY 09
JILL 1004

Power required
EMP_NO NAME REQ_DEPTS MAX_DEPT_NO VISITS_COMP
1001 MARC 20 10.20
1002 DAVID 10,20,30 20
1003 SHAUN 20,30 20 3 MAY 09
JILL 10 1004

Can we do this in a single query?

Hello

user512647 wrote:
... Sanjay
The query you provided that stragg() use seems to work but my requirement is not in the result set. I don't know how to use stragg with
MAX (DEPT_NO) KEEP (DENSE_RANK LAST ORDER BY VISITED) MAX_DEPT_NO,.
MAX (VISITED) KEEP (DENSE_RANK LAST ORDER PER VISIT) VISITS_COMP
I need more, these two columns these gives me the date when they have completed all visits. If they missed any Department then the result must be NULL in the VISITS_COMP field.

Just add them to the SELECT clause:

SELECT    t_emp.emp_no,
       name,
       STRAGG (t_emp_dept.dept_no)     AS deptno,
       MAX (t_emp_dept.dept_no) KEEP (DENSE_RANK LAST ORDER BY visited)
                                  AS max_dept_no,
       MAX (visited)                      AS visits_comp
FROM             t_emp
LEFT OUTER JOIN      t_emp_dept     ON   t_emp.emp_no     = t_emp_dept.emp_no
LEFT OUTER JOIN      t_emp_visits     ON   t_emp_dept.emp_no     = t_emp_visits.emp_no
                             AND  t_emp_dept.dept_no = t_emp_visits.dept_no
GROUP BY  t_emp.emp_no
,            name
;

The column called visit_comp is simply the last visited, regardless of how the employee visited departments.
If you want to have the NULL value if the employee has not yet visited all 3 departments:

...       CASE
          WHEN  COUNT (DISTINCT t_emp_dept.dept_no) = 3
          THEN  MAX (visited)
       END                    AS visits_comp

The 'magic number' 3 is the total number of departments.
If you want to understand the correct value of that at the time of the execution of the query, replace the code literal 3 hard with a scalar subquery.

Note that 'KEEP MAX (x) (DENSE_RANK OVER LAST SERVICE BY x)' (where the exact same column is used as an argument and that the ORDER BY column) is just "MAX (x)".

Tags: Database

Similar Questions

A question about the analytical function used with the GROUP BY clause in SHORT

Hi all

I created the following table named myenterprise

CITY       STOREID    MONTH_NAME TOTAL_SALES            
---------- ---------- ---------- ---------------------- 
paris      id1        January    1000                   
paris      id1        March      7000                   
paris      id1        April      2000                   
paris      id2        November   2000                   
paris      id3        January    5000                   
london     id4        Janaury    3000                   
london     id4        August     6000                   
london     id5        September  500                    
london     id5        November   1000

If I want to find which is the total sales by city? I'll run the following query

SELECT city, SUM(total_sales) AS TOTAL_SALES_PER_CITY
FROM myenterprise
GROUP BY city
ORDER BY city, TOTAL_SALES_PER_CITY;

that works very well and produces the expected result, i.e.

CITY       TOTAL_SALES_PER_CITY   
---------- ---------------------- 
london     10500                  
paris      17000

Now in one of my books SQL (Mastering Oracle SQL) I found another method by using the SUM, but this time as an analytic function. Here's what the method of the book suggests as an alternative to the problem:

SELECT city, 
       SUM(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
FROM myenterprise
GROUP BY city
ORDER BY city, TOTAL_SALES_PER_CITY;

I know that the analytic functions are executed after the GROUP BY clause has been transformed completely and Unlike regular aggregate functions, they return their result for each line belonging to the partitions specified in the partition clause (if there is a defined partition clause).

Now my problem is that I do not understand what we have to use two functions SUM? If we only use one only, i.e.

SELECT city, 
       SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
FROM myenterprise
GROUP BY city
ORDER BY city, TOTAL_SALES_PER_CITY;

This generates the following error:

Error starting at line 2 in command:
SELECT city, 
       SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
FROM myenterprise
GROUP BY city
ORDER BY city, TOTAL_SALES_PER_CITY
Error at Command Line:2 Column:11
Error report:
SQL Error: ORA-00979: not a GROUP BY expression
00979. 00000 -  "not a GROUP BY expression"
*Cause:    
*Action:

The error is generated for the line 2 column 11 which is, for the expression SUM (total_sales), well it's true that total_sales does not appear in the GROUP BY clause, but this should not be a problem, it has been used in an analytical function, so it is evaluated after the GROUP BY clause.

So here's my question:

Why use SUM (SUM (total_sales)) instead of SUM (total_sales)?

Thanks in advance!
:)

In case you are interested, that's my definition of the table:

DROP TABLE myenterprise;
CREATE TABLE myenterprise(
city VARCHAR2(10), 
storeid VARCHAR2(10),
month_name VARCHAR2(10),
total_sales NUMBER);

INSERT INTO myenterprise(city, storeid, month_name, total_sales)
  VALUES ('paris', 'id1', 'January', 1000);
INSERT INTO myenterprise(city, storeid, month_name, total_sales)
  VALUES ('paris', 'id1', 'March', 7000);
INSERT INTO myenterprise(city, storeid, month_name, total_sales)
  VALUES ('paris', 'id1', 'April', 2000);
INSERT INTO myenterprise(city, storeid, month_name, total_sales)
  VALUES ('paris', 'id2', 'November', 2000);
INSERT INTO myenterprise(city, storeid, month_name, total_sales)
  VALUES ('paris', 'id3', 'January', 5000);
INSERT INTO myenterprise(city, storeid, month_name, total_sales)
  VALUES ('london', 'id4', 'Janaury', 3000);
INSERT INTO myenterprise(city, storeid, month_name, total_sales)
  VALUES ('london', 'id4', 'August', 6000);
INSERT INTO myenterprise(city, storeid, month_name, total_sales)
  VALUES ('london', 'id5', 'September', 500);
INSERT INTO myenterprise(city, storeid, month_name, total_sales)
  VALUES ('london', 'id5', 'November', 1000);

Edited by: dariyoosh on April 9, 2009 04:51

It is clear that thet Analytics is reduntant here...
You can even use AVG or any analytic function...

SQL> SELECT city,
  2         avg(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  3  FROM myenterprise
  4  GROUP BY city
  5  ORDER BY city, TOTAL_SALES_PER_CITY;

CITY       TOTAL_SALES_PER_CITY
---------- --------------------
london                    10500
paris                     17000

CFQUERYPARAM tag does not work in the GROUP BY clause
I get an error whenever I put a CFQUERYPARAM tag in a GROUP BY clause. I saw on another forum, someone had a similar problem with the ORDER BY clause

Here's a sample of what might look like my code
Select x, y, z of ABC
Group of < cfqueryparam value = 'x' cfsqltype = "cf_sql_float" >

Here is the error I get.

Run database query error.
[Macromedia] [Oracle JDBC Driver] [Oracle] ORA-00979: not a GROUP BY expression

Any idea?
Cachedwithin and cachedafter functions store the query results in the RAM of the server. This means that, even if it is cached, when you run it, you get the cached result instead of going to the database to run again. This increases the speed of course, but if the data is changed during the period of cover, you have accuracy problems.

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Hi Jasonbichard,

1. what type of drive is D? Is - this another partition on the same disk?

2 Windows operating system you are using?

You can change the location of the disk to save the data in the d: instead of C: and check if it helps.

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d. click on apply and Ok.

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Hi Robert,.

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Philippe

Dynamic action for validation of date with the notification message plugin

Hi all
Someone help me please with dynamic action for validation of date with the message notification plugin. I have a form with two elements of the date picker control and message notification plugin.
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} else {}

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}

}

The logic based on setting (I have two years from years of 365 days preceding)

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For a group shape, use the boundsInParent property.
```
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```

Select the columns not in the group by clause

Hello

My version of DB is 10.0.2

I have query, where in I need to select two columns more but that should not be part of the group by Clause.

Does perform a work around?

SELECT  F.custnum, 
  V.Import_date,
 -- F.ErledigtMM,F.ErledigtGrundMM, (Columns to be selected additionally)
  nvl(sum(nvl(round(V.VerAuf16/1000,2), 0)  +nvl(round(V.VerAuf17/1000,2), 0)  + nvl(round(V.VerAuf18/1000,2), 0)  + nvl(round(V.VerAuf19/1000,2), 0)  + nvl(round(V.VerAuf20/1000,2), 0)  + nvl(round(V.VerAufKAPUn/1000,2), 0)  + nvl(round(V.VerAufKAPVz/1000,2), 0) ), 0)  Mandantenforderung,
  nvl(sum(nvl(round(V.VerAuf4/1000,2), 0) ), 0) Inkassokosten,
  nvl(sum(nvl(round(V.VerAuf5/1000,2), 0) ), 0) KontoFuehrungsgebuehren,
  nvl(sum(nvl(round(V.VerAuf1/1000,2), 0)  + nvl(round(V.VerAuf2/1000,2), 0) ), 0)  Verwertungskosten,
  nvl(sum(nvl(round(V.VerAuf10/1000,2), 0)  + nvl(round(V.VerAuf8/1000,2), 0) + nvl(round(V.VerAuf9/1000,2), 0) ), 0)  Barauslagen,
  nvl(sum(nvl(round(V.VerAuf13/1000,2), 0)  + nvl(round(V.VerAuf14/1000,2), 0) + nvl(round(V.VerAuf15/1000,2), 0)  + nvl(round(V.VerAuf6/1000,2), 0) ),0)  Gerichtskosten,
  nvl(sum(nvl(round(V.VerAuf11/1000,2), 0)  + nvl(round(V.VerAuf12/1000,2), 0)  + nvl(round(V.VerAuf7/1000,2), 0) ), 0) RAKosten,
  TO_CHAR(F.Created_Date,'MM.YYYY') Created_Date_MM ,
  TO_CHAR(F.Created_Date,'YYYY') Created_Date_MMRRRR
FROM FACM F, VA V 
   WHERE  F.custnum =  DECODE(0,0,F.custnum,0) AND
  F.accnum = V.accnum 
  GROUP BY F.custnum, V.Import_date,TO_CHAR(F.Created_Date,'MM.YYYY') ,TO_CHAR(F.Created_Date,'YYYY'))

Hello

Here's what I suggest:

select
a.custnum,
a.import_date,
b.ErledigtMM,
b.ErledigtGrundMM,
a.Mandantenforderung,
a.Inkassokosten,
a.KontoFuehrungsgebuehren,
a.Verwertungskosten,
a.Barauslagen,
a.Gerichtskosten,
a.RAKosten,
a.Created_Date_MM ,
a.Created_Date_MMRRRR
from (
SELECT  F.custnum,
  V.Import_date,
  nvl(sum(nvl(round(V.VerAuf16/1000,2), 0)  +nvl(round(V.VerAuf17/1000,2), 0)  + nvl(round(V.VerAuf18/1000,2), 0)  + nvl(round(V.VerAuf19/1000,2), 0)  + nvl(round(V.VerAuf20/1000,2), 0)  + nvl(round(V.VerAufKAPUn/1000,2), 0)  + nvl(round(V.VerAufKAPVz/1000,2), 0) ), 0)  Mandantenforderung,
  nvl(sum(nvl(round(V.VerAuf4/1000,2), 0) ), 0) Inkassokosten,
  nvl(sum(nvl(round(V.VerAuf5/1000,2), 0) ), 0) KontoFuehrungsgebuehren,
  nvl(sum(nvl(round(V.VerAuf1/1000,2), 0)  + nvl(round(V.VerAuf2/1000,2), 0) ), 0)  Verwertungskosten,
  nvl(sum(nvl(round(V.VerAuf10/1000,2), 0)  + nvl(round(V.VerAuf8/1000,2), 0) + nvl(round(V.VerAuf9/1000,2), 0) ), 0)  Barauslagen,
  nvl(sum(nvl(round(V.VerAuf13/1000,2), 0)  + nvl(round(V.VerAuf14/1000,2), 0) + nvl(round(V.VerAuf15/1000,2), 0)  + nvl(round(V.VerAuf6/1000,2), 0) ),0)  Gerichtskosten,
  nvl(sum(nvl(round(V.VerAuf11/1000,2), 0)  + nvl(round(V.VerAuf12/1000,2), 0)  + nvl(round(V.VerAuf7/1000,2), 0) ), 0) RAKosten,
  TO_CHAR(F.Created_Date,'MM.YYYY') Created_Date_MM ,
  TO_CHAR(F.Created_Date,'YYYY') Created_Date_MMRRRR
FROM FACM F, VA V
   WHERE  F.custnum =  DECODE(0,0,F.custnum,0) AND
  F.accnum = V.accnum
  GROUP BY F.custnum, V.Import_date,TO_CHAR(F.Created_Date,'MM.YYYY') ,TO_CHAR(F.Created_Date,'YYYY'))
) a,
FACM b
where b.custnum = a.custnum

By the way

WHERE  F.custnum =  DECODE(0,0,F.custnum,0) AND F.accnum = V.accnum

can be translated into

WHERE F.accnum = V.accnum

because

F.custnum =  DECODE(0,0,F.custnum,0)

is always true
because

DECODE(0,0,F.custnum,0)

means

if 0=0 then F.custnum else 0

request with the date of the Group's values
Hi all

I have an adate of table with 13 columns with a column named trandate
with the value as "2008-11-07 18:00:19.

Now I want to retrieve the values from the table as

SELECT count (*) from trandate which where ttype = '081' and T_FILE like 'mountain % ';

I want to count the records for all the months as

Jan-2009 - 120 (120 is the number of records satifying the above condition and belong to the period January 2009 (derived from trandate column)
Feb-2009 - 150 (150 is the number of records satifying the above condition and belong to the period February 2009 (derived from trandate column)

How can I rewrite the query

Thank you
Kai

Published by: KaiS on February 1st, 2011 04:23
```
select to_char(trandate,'mmm - yyyy') trandate,
          count(1)
from trandate
where where ttype = '081' and T_FILE like 'monT%'
group by to_char(trandate,'mmm - yyyy');
```

Need help in the optimization of the query with the Group and joins by clause

I'm having the problem by running the following query... It takes a lot of time. To simplify, I added the two tables FILE_STATUS = stores the file load details and COMM table Board table job showing records treated successfully and which was communicated to the other system real. Records with status = T is trasnmitted to another system and traansactions with P is waiting.

CREATE TABLE FILE_STATUS
(FILE_ID VARCHAR2(14),
FILE_NAME VARCHAR2(20),
CARR_CD VARCHAR2(5),
TOT_REC NUMBER,
TOT_SUCC NUMBER);

CREATE TABLE COMM
(SRC_FILE_ID VARCHAR2(14),
REC_ID NUMBER,
STATUS CHAR(1));

INSERT INTO FILE_STATUS VALUES ('12345678', 'CM_LIBM.TXT', 'LIBM', 5, 4);
INSERT INTO FILE_STATUS VALUES ('12345679', 'CM_HIPNT.TXT', 'HIPNT', 4, 0);

INSERT INTO COMM VALUES ('12345678', 1, 'T');
INSERT INTO COMM VALUES ('12345678', 3, 'T');
INSERT INTO COMM VALUES ('12345678', 4, 'P');
INSERT INTO COMM VALUES ('12345678', 5, 'P');
COMMIT;

Here's the query I wrote to give me the details of the file that has been loaded into the system. He reads the table of State and the commission files to display the name of the file, total records loaded, total at the table of the commission and the number of records which has finally been passed successfully loaded (Status = T) with other systems.

SELECT 
    FS.CARR_CD 
    ,FS.FILE_NAME 
    ,FS.FILE_ID
    ,FS.TOT_REC
    ,FS.TOT_SUCC
    ,NVL(C.TOT_TRANS, 0) TOT_TRANS
FROM FILE_STATUS FS
LEFT JOIN
(
    SELECT SRC_FILE_ID, COUNT(*) TOT_TRANS
    FROM COMM
    WHERE STATUS = 'T'
    GROUP BY SRC_FILE_ID
) C ON C.SRC_FILE_ID = FS.FILE_ID
WHERE FILE_ID = '12345678';

In production, this request has several joins and takes a long time to deal with... the main culprit for me is the join on the COMM table to count the number of number of transactions sent. Please can you give me tips to optimize this query to get results faster? What I need to delete the Group and use the partition or something else. Help, please!

Don't know if it will be faster based on the information provided, but analytical functions offer an alternative approach;

select carr_cd, file_name, file_id, tot_rec, tot_succ, tot_trans
  from (select fs.carr_cd,
               fs.file_name,
               fs.file_id,
               fs.tot_rec,
               fs.tot_succ,
               count(case
                        when c.status = 'T' then
                         1
                        else
                         null
                      end) over(partition by c.src_file_id) tot_trans,
               row_number() over(partition by c.src_file_id order by null) rn
          from file_status fs
          left join comm c
            on c.src_file_id = fs.file_id
         where file_id = '12345678')
 where rn = 1;

CARR_CD FILE_NAME            FILE_ID           TOT_REC   TOT_SUCC  TOT_TRANS
------- -------------------- -------------- ---------- ---------- ----------
LIBM    CM_LIBM.TXT          12345678                5          4          2

How to INSERT a SELECT statement with a GROUP BY clause on a table with an IDENTITY column?

n an application, I intend to truncate and insertion on a 12 c Oracle database, but have found this problem with a IDENTITY column. Even if the INSERT... SELECT statement works on most SELECT uses I tried, if this statement was also a GROUP BY clause, it does not work, delivering a "ORA-00979: not a GROUP BY expression ' complaint. Some examples of code:
```
create table aux ( owner_name varchar2(20), pet varchar2(20) );  
insert into aux values ('Scott', 'dog'); 
insert into aux values ('Mike', 'dog'); 
insert into aux values ('Mike', 'cat'); 
insert into aux values ('John', 'turtle');  


create table T1 (
  id number generated always as identity,
  owner_name varchar2(20),
  pet_count number ); 
select owner_name, count(*) as pet_count from aux group by owner_name; -- works just fine
insert into T1 (owner_name, pet_count) select owner_name, count(*) as pet_count from aux group by owner_name; -- doesn't work
```
The select statement works by itself, but it fails as an INSERT... SELECT statement.
Appreciate the help!

Looks like a bug. You must open the SR with Oracle. Meanwhile, you could materialize select:

SQL > insert into T1 (owner_name, pet_count)
2 with t as (select / * + materialize * / owner_name, count (*) as pet_count to the owner_name group)
3. Select owner_name, pet_count t
4.

3 lines were created.

SQL > select * from t1;

ID OWNER_NAME PET_COUNT
---------- -------------------- ----------
1 John 1
Scott 2 1
3 Mike 2

SQL >

Keep in mind index THAT MATERIALIZE is undocumented.

SY.

Is this a bug with the grouping sets?

Version is the database of Oracle 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production

SQL> with data as
  2  (select rownum r, 'X' x, 1 n from dual connect by rownum <= 10)
  3  select x
  4       , sum(n) s
  5       , (select sum(1) from dual where dummy = x) t
  6  from data
  7  group by grouping sets (x, ())
  8  /

X          S          T
- ---------- ----------
X         10          1
          10
SQL>

Shouldn't the superaggregate row have a 1 in the T column?

Here's your QUERY with the addition of the GROUPING() function:

SQL> WITH data AS
  2  (
  3     SELECT rownum r
  4          , 'X'    x
  5          , 1      n
  6     FROM   dual
  7     CONNECT BY rownum <= 10
  8  )
  9  SELECT GROUPING(x)
 10       , x
 11       , sum(n) s
 12       , (SELECT sum(1) FROM dual WHERE dummy = x) t
 13  FROM   data
 14  GROUP BY GROUPING SETS (x, ())
 15  ;

GROUPING(X) X          S          T
----------- - ---------- ----------
          0 X         10          1
          1           10

In this case, the value of X is zero because it is a subtotal line. If you look at this statement execution plan:

PLAN_TABLE_OUTPUT
------------------------------------------------------------------------------------------------------------------------------
SQL_ID  gumphwvgumqc4, child number 0
-------------------------------------
WITH data AS (  SELECT rownum r       , 'X'    x       , 1      n  FROM
  dual  CONNECT BY rownum <= 10 ) SELECT /*+gather_plan_statistics*/ x
    , sum(n) s      , (SELECT sum(1) FROM dual WHERE dummy = x) t FROM
 data GROUP BY GROUPING SETS (x, ())

Plan hash value: 1718326399

-----------------------------------------------------------------------------------------------------------------------------
| Id  | Operation                       | Name | Starts | E-Rows | A-Rows |   A-Time   | Buffers |  OMem |  1Mem | Used-Mem |
-----------------------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT                |      |      1 |        |      2 |00:00:00.01 |       0 |    |  |          |
|   1 |  SORT AGGREGATE                 |      |      2 |      1 |      2 |00:00:00.01 |       4 |    |  |          |
|*  2 |   TABLE ACCESS FULL             | DUAL |      2 |      1 |      1 |00:00:00.01 |       4 |    |  |          |
|   3 |  SORT GROUP BY ROLLUP           |      |      1 |      1 |      2 |00:00:00.01 |       0 |  2048 |  2048 | 2048  (0)|
|   4 |   VIEW                          |      |      1 |      1 |     10 |00:00:00.01 |       0 |    |  |          |
|   5 |    COUNT                        |      |      1 |        |     10 |00:00:00.01 |       0 |    |  |          |
|   6 |     CONNECT BY WITHOUT FILTERING|      |      1 |        |     10 |00:00:00.01 |       0 |    |  |          |
|   7 |      FAST DUAL                  |      |      1 |      1 |      1 |00:00:00.01 |       0 |    |  |          |
-----------------------------------------------------------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   2 - filter("DUMMY"=:B1)

The value of X is related to the subquery. If X is zero this returns no rows (I'm sure you already knew that :)). I would say it should although confusing behavior. You get the same results if you use CUBE or ROLLUP as well.

Store data with the VM disks?

I read a few whitepapers that suggest a maximum number of VM are run by LUN. That being said, the recommendation would be to "drive with the virtual machine shop", or on a separate data store? In what senario would you do one of the two?

If you have group single disc less than 2 TB total in most cases there is no need to make separate data warehouses.

---

MCSA, MCTS, VCP, VMware vExpert 2009

http://blog.vadmin.ru

Need help get data with the most recent date of entry into
Hey guys;

I need help with fine tuning a query to get the one with the most recent implementation.

Here's my current query:

/**********************************************
Select sge.seal_group_id,
SGE.equipment_id,
SGE.effective_date
of seal_group_equipment EMS.
seal_group sg
where equipment_id = 48801
AND EMS. SEAL_GROUP_ID = SG. SEAL_GROUP_ID
and sge.end_date is null
Group of sge.equipment_id, sge.seal_group_id, sge.effective_date
After having sge.effective_date = max (sge.effective_date)

******************************************************/

Which produces the following results:
SEAL_GROUP_ID - EQUIPMENT_ID - EFFECTIVE_DATE
25-48801 - 01/01/1993-00: 00:00
11730-48801 - 22/08/2003 08:42:11

What I really need, is to show only the line with the most recent date of entry into
I hope someone can help
Thank you
MAX will not work because the SEAL_GROUP_ID could depart. I would say analytical:
```
select seal_group_id,
equipment_id,
effective_date
from (
select sge.seal_group_id,
sge.equipment_id,
sge.effective_date,
RANK() over (partition by equipment_id order by effective_date desc) r
from seal_group_equipment sge,
seal_group sg
where equipment_id = 48801
AND SGE.SEAL_GROUP_ID = SG.SEAL_GROUP_ID
and sge.end_date is null)
where r = 1;
```
Keep in mind if two records have the same effective_date, they would both appear.

Note: query above has not been tested, since there is no script provided.

Concatenation of data with the GROUP BY clause

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