Conditional formatting based on another column

Similar Questions

• How do column filter based on another column

  In my report, I have column a thru d. I would like to create a filter based on another column where column is column B. I can enter a value that the column cannot be equal to, but I would use a column instead of a value.
  
  Thank you.
  Jonathan

  Try this: icon on the filter columns->-> convert this advanced filter for SQL
  You can reference any other column

  BTW: Have you had a chance to look at my suggestion for your post
  Tables from a Table

• Delete based on another column dublicate records

  How can I remove duplicate records, based on another column.
  
  the table structure
  CREATE TABLE IA_EXPORT_LEVEL
  (
  A_NO VARCHAR2 (22 BYTE),
  IM VARCHAR2 (18 BYTE),
  ctn_level NUMBER (2)
  )
  
  reviews
  A_NO IM ctn_level
  
  S1 S1 1
  S1 M1 2
  S1 h1 3
  H2 S2 1
  S2 h2 2
  S3 h1 2
  S3 h1 3
  S4 h6 4
  S4 h6 5
  
  I want to delete all records other than the minimum value of the ctn_level
  
  output should like below
  S1 S1 1
  H2 S2 1
  S3 h1 2
  S4 h6 4
  
  Published by: OraFighter on December 16, 2011 13:44

  DELETE FROM IA_EXPORT_LEVEL where rowid IN
  (select rid from
  (select rowid rid, row_number() over (partition by A_NO,IM order by ctn_level) rn from IA_EXPORT_LEVEL )
  where rn > 1 )
  /
  

  Hope your question.

• Get the cumulative values in a single column based on another column in reports

  Hi all
  
  I have a requirement to get cumulative values based on another column.

  I 'Sales rep name' in the first column.
  Correspondent "Values of the invoice line" in the second column.
  Want to have cumulative of all the values for each sales invoice line.
  Then apply rank and display the top 10 sales reps based on invoice lines.

  Since there is no rank option in the PivotTable, I do this in the report table.
  
  Looking for the best entries...
  
  Thanks in advance...

  Try below
  2nd column: "name of Sales rep.
  column 2: SUM ("invoice line values ' BY 'Name of Sales rep'") and sort this field desc.
  3rd column: fx RANK (SUM ("invoice line values" BY "Sales rep name")), to hide this column, so that you don't confuse your users.

  and put the filter on the 3rd column below 5

  I hope this works for you

• Link conditional branching to two different pages, based on another column

  Hello
  
  I have a sql report in which 1 column is a link. I want to link to two different pages depending on the value of another column.
  
  Example of
  
  the sql is
  
  Select a, b, c
  x;
  
  The link on column b must create a branch to the 500 page if c = 1 and on page 501 if c = 2.
  Is it possible to do? Thank you.
  
  Suni

  Can assign you points then accordingly...

  Thank you

  Tony Miller
  Webster, TX

• Conditional formatting based on the other content of the cell

  Hello

  I watched tutorials and read other messages of conditional formatting. What I'm trying to do doesn't seem like it should be too difficult, but I can't it to work.

  I created a spreadsheet of travel and I would that my cells spend every day to highlight when I went on the budget (budget in another table on another sheet)

  My conditional formatting looks like this

  

  Who works for the first cell that I put it to the top for the table. If I try to drag the rules to the bottom of the table, or highlight the entire table and and my rule number 1 shows what

  

  and of course, it will not highlight.

  This is an excerpt from the table, on that I try to apply highlighting

  

  And that is the picture that source information.

  

  I use a macbook pro under OS X El Capitan 10.11.1 and numbers 3.6.1 (2566)

  Thanks in advance for any help!

  Hello

  It's looks you're new to spreadsheets... you must add a dollar sign in front of "The rest of the budget per day" (your 1st image), or check the 2 boxes like this:

  

  To understand: http://www.notjustnumbers.co.uk/2011/05/excel-tip-dollar-sign-in-formula-fixing. html

  See you soon

  James

• Filter column based on another column - OBIEE 11 g

  Hi, I have a strange requirement. I am trying to build a dashboard that allows a user to view the data for the current day, last week, last month or last year. I'll create a presentation called "date_range" variable where the user can choose one of these 4 options.
  
  On this basis, I defined a column in answers with the following formula:
  
  Cast
  (
  case
  When 1 = 0 then 'time of the query. "" Date ".
  When @{date_range} {"day"} = 'Day' then Current_Date
  When @{date_range} {'week'} = 'Week' then TIMESTAMPADD (SQL_TSI_DAY,-7, CURRENT_DATE)
  When @{date_range} {"day"} = 'Month' then TIMESTAMPADD (SQL_TSI_DAY-30, CURRENT_DATE)
  When @{date_range} {"day"} = 'Year' then TIMESTAMPADD (SQL_TSI_DAY,-365, CURRENT_DATE)
  of another TIMESTAMPADD (SQL_TSI_DAY,-10000, CURRENT_DATE)
  finish DATE
  )
  
  Based on the variable 4 presentation, this should give the good 'start date' when to extract data.
  
  Now, I've added the effective date of the date dimension column. But I need to put a filter on the date dimension date column that says that it is greater than or equal to the above computed column. How do I do that?
  
  Thank you
  Scott

  I always expect that you are pregnant, but you cannot filter a column on another column. The solution is just to write a formula that returns a literal, so it will be

  When case (your date column) > = (your long form), then put end to 'Y' else ' n

  Then filter this column on 'Y '.

  Kind regards

  Robert

• AF:Switcher, handfuls of line column values based on another column in the table

  Hello
  
  I have a question if you can help me on this. It's on af:switcher.
  
  What I'm trying to do this - is in a table of the adf, based on the value of a column, I want another column to display as a link or not.
  For example, if the status column is 1, then the id column display as a link (I just put a h:outputLink around outputText to do), if it is then show him without bond.
  
  For this I put two different facets and opportunities switcher to decide what facet of show which line.
  
  BUT what is happening is that only on opportunities is made. Either / or scenario. It is not made each line according to the value of the status column.
  
  What is planned.

  I just tried with the dept table.

  The lines for which the deptno > 20, I wanted to display the pass as link and for the deptno<=20, log="" will="" be="" an="" input="" text.="" it="" works="" fine="" for="" me.="" probably,="" you="" may="" need="" to="" get="" rid="" of="" h:outputlink="" and="" use="" commandlink="" golink="">

  Arun-

• Conditionally display the values in the column based on another column

  Hello
  
  I'm sure this has been covered before, but I can't find anything appropriate based on the research I've done.
  
  I have 2 attributes in VO.
  
  I have a table that displays this VO.
  
  I still want to display header for both attributes, but I only want to show the value of attribute 1 in a row, if value of Attibute2 = 'I '.
  
  If Attibute2! = 'I', so I want just the column for Attribute1 to be empty space.
  
  I've not yet done anything with conditional expressions, and I wonder if someone could provide a link or a thread which is similar to this issue.
  
  Thank you
  
  Joel

  You can do according to the post above, but if you are not interested in changing the original Version and I want to just change the user interface page only, you can do as in the example below:

  
  lines = ' #{bindings. " Employee.rangeSize}.
  emptyText = "#{bindings." Employee.Viewable? "{'No data to display.': 'Access Denied.'}".
  fetchSize = "#{bindings." Employee.rangeSize}.
  rowBandingInterval = '0 '.
  selectedRowKeys = ' #{bindings. " Employee.collectionModel.selectedRow}.
  selectionListener = "#{bindings." Employee.collectionModel.makeCurrent}.
  rowSelection = "single" id = "t1" >
  
  headerText = "#{bindings." Employee.hints.Employeeid.label}.
  ID = "c2" >
  
  
  model = ' #{bindings. " Employee.hints.Employeeid.format}"/ >
  
  
  
  headerText = "#{bindings." Employee.hints.Employeename.label}.
  ID = 'c3' >
  
  
  
  headerText = "#{bindings." Employee.hints.Salary.label}.
  ID = "c1" >
  *
  ID = "ot2" >
  
  model = ' #{bindings. " Employee.hints.Salary.format}"/ >
  
  
  

  OutputText for the Attibute1, you can write the EL expression as:
  *<>
  * value = "#{rank." Attibute2 == "I"? "line. "{Attibute1:"}. "
  * id = "ot2" > *.

  I hope this helps.

  Thank you
  Nini

• Display the value of the column automatically based on another column in a table

  Hello

  I use APEX 5.0, I have a requirement to display the field automatically based on the tabular presentation of other numbers.

  

  in the screen shot attached above when I press Add button line a new line is created and enter the value in 'place no.', 'dept and identification of height place' when I press tab or get out of the column "height", "GID" should appear automatically.

  To display the GID my query will be like that. "Select GID from x where no = '1011' place and dept = 88 and height = 88'.

  How to get the value of from GID of the another value entered in Place no, dept and height in tabular form.

  Thanks in advance

  Ravi.

  Hi Ravi

  No need to point of Application or process. I just completed the task with the following steps

  (1) create 4 hidden items

  P2_SELWID

  P2_SELDEPTH

  P2_SELHEIGHT

  P2_CALCWNAME

  (2) gives 3 CSS classes in three columns of tables.

  . WID

  . DEPTH

  . HEIGHT

  (3) create the function jQuery for re - get three items from the page on a line if one of them has been changed.

  Add the following code to the function and the declaration of global variables

  function setRowItemValues(p_rownum){
      wid_col_id = 'f02_' + rownum ;
      wid_col_val = $('#'+wid_col_id).val();
      depth_col_id = 'f03_' + rownum ;
      depth_col_val = $('#'+depth_col_id).val();
      height_col_id = 'f04_' + rownum;
      height_col_val = $('#'+height_col_id).val();
      wname_col_id = 'f05_' + rownum;
      // set P2_SELWID,P2_SELDEPTH,P2_SELHEIGHT
      $s("P2_SELWID", wid_col_val );
      $s("P2_SELDEPTH", depth_col_val );
      $s("P2_SELHEIGHT", height_col_val );
      $s("P2_SELWNAMEID", wname_col_id );
      // Call the Dynamic Action to get WNAME if all values are not null
      if( wid_col_val != ''  && depth_col_val != '' && height_col_val != '' ){
          //Call DA to Get WNAME from WINT
          $.event.trigger("CalcWNAME");
          // set the Tabular form
          $('#'+wname_col_id).val($x("P2_CALCWNAME").value);
      }
  }
  

  and run when the Page loads

  $(document).on("change", ".WID,.DEPTH,.HEIGHT", function(){
      rownum = $(this).attr('id').substr(4);
      setRowItemValues(rownum);
  });
  

  (4) create a dynamic Action to get WNAME based on a PL/SQL function. Note the submitted page elements.

  CalcWNAME

  (5) set of the corresponding element in the line of the function jQuery, after completing the DA.

  Please check and I hope your problem is now solved.

  Concerning

  Mahmoud

• Display a column based on another column

  Hello

  I work in the Apex 4.2.

  I have a tabular presentation based on a query.

  In this form, I have a column of link change with an icon. When I click it, I open a new page with the details of my record.

  I want that this column appears only when the user is entitled.

  So, I got in my request a new column based on a Pl/sql function that returns 1 when the logged-on user has the privilege package update the record.

  I call this new column "can_update."

  After that, I changed the "conditional display" property of my edit_link column.

  In type of condition, I put: "value for the element / the expression 1 column = Expression 2.

  I put in the expression 1: can_update

  I put in the expression 2: 1

  But it does not work as I want. colonm "edit_link" never appears.

  and the can_update column return the good value 1 or 0 on depend on the recording.

  Anyone has an idea on what I didi wrong?

  Thank you.

  Laurent.

  I found a solution to my problem.

  I have a column in my query that return 'none' or 'inline' when I have the privilege to update my file and thus, the column "edit_link."

  Thos query column name is link_disp

  And in the "link attribute" property, the "link in the column" Section of my edit_link, I add: "style =" display: #LINK_DISP #»»

  and it works well

  Laurent.

• update of column based on another column

  Hi all
  
  I want to update the column 2 of the table based on the value of update in column 1 and the existing value in column 1
  
  Assume that table1 has columns ID, col1 and col2
  
  I update col2 based on the update to col1 value and comparing the existing value of col1 in the table.
  
  trying to decode, I think it should work.
  
  Thank you.

  Not like that.

  You change a column of type CHAR, VARCHAR2 column, right? Thus, the data will be same. (Completed with space). For the new data inserted into a column VARCHAR2 TRIM is not necessary.

• Filter the rows based on another column

  Hello

  I have a table like this:

  user_id	team	sla_team	rownum
  11	one	0	1
  22	one	0	2
  33	b	1	3
  44	b	1	4
  55	c	3	5

  I want a list of the first order of 3 users of sla_team.

  If 2 or more users have the same sla_team, must list both of them.

  In this case, I want to return user_id: 11, 22, 33, 44

  A way to do it is like this:

  Select *.

  table

  where sla_team < = (select max (sla_team) in the table where rownum < = 3)

  But my table is bigger and more complex query.

  Any other sugestion?

  Thank you and sorry for my bad English.

  Hello

  Whenever you have a problem, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) of all the tables involved, so that people who want to help you can recreate the problem and test their ideas.

  Also post the exact results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: Re: 2. How can I ask a question on the forums?

  This sounds like a job for a Query of Top - N, like this:

  WITH got_r_num AS

  (

  SELECT table_x. *- or whatever the columns that you want to

  , EVALUATE () DURING (ORDER BY sla_team) AS r_num

  FROM table_x

  -WHERE... - If you need any filtering, put it here

  )

  SELECT *- or the list of all columns except r_num

  OF got_r_num

  WHERE r_num<=>

  ORDER BY r_num

  ;

• Best way to select distinct values, based on another column?

  I have a table with three columns: id (NUMBER), data_dt (DATE) and data_value (NUMBER).
  There is a primary key id and data_dt.
  
  I want to choose the folder with the last data_dt for each unique identification number.
  
  What is the best way to do it?
  I have three different methods, but there may be something that I am missing.
  
  First of all:

  SELECT *
  FROM
  (
    SELECT id, data_dt, data_value,
           FIRST_VALUE(data_dt)
           OVER (PARTITION BY id ORDER BY data_dt DESC) AS last_data_dt
    FROM the_table
  )
  WHERE data_dt = last_data_dt;

  (I use ORDER BY... DESC, instead of just ORDER BY I don't need the clause BETWEEN the LINES)
  
  
  Second:

  SELECT t1.*
  FROM the_table t1
  JOIN
  (
    SELECT id, MAX(data_dt) AS last_data_dt
    FROM the_table
    GROUP BY id
  ) t2 ON (t2.id = t1.id AND t2.data_dt = t1.data_dt);

  Third:

  SELECT t1.*
  FROM the_table t1
  WHERE t1.data_dt =
  (
    SELECT MAX(t2.data_dt)
    FROM the_table t2
    WHERE t2.id = t1.id
  );

  -Don

  As mentioned in hoek, you will need to test all scenarios.

  However, in my opinion the more faster will be those who accesses the table that only ONCE instead of TWICE as some scenarios require.

  HTH!

• command update, based on another column column

  Col A, Col B, Col C
  1, a, null
  1, B, null
  2, a, null
  2, B, null
  3, bis, null
  3, B, null
  3, C, null
  
  How can I query this table to update Col C, with a command...
  
  Final outcome:
  Col A, Col B, Col C
  1, 1 A
  1 B, 2
  2, 1
  2, B, 2
  3, 1
  B, 2, 3
  3, C, 3
  
  Is it possible to update, only using SQL in oracle 10 g?

  You can use a correlated update statement if you are looking to update the data. It was not clear from your post.

  SQL> CREATE TABLE table_x
    2  ( col_a NUMBER
    3  , col_b VARCHAR2(1)
    4  , col_c NUMBER
    5  );
  
  Table created.
  
  SQL> INSERT INTO table_x VALUES(1,'A',NULL);
  
  1 row created.
  
  SQL> INSERT INTO table_x VALUES(1,'B',NULL);
  
  1 row created.
  
  SQL> INSERT INTO table_x VALUES(2,'A',NULL);
  
  1 row created.
  
  SQL> INSERT INTO table_x VALUES(2,'B',NULL);
  
  1 row created.
  
  SQL> INSERT INTO table_x VALUES(3,'A',NULL);
  
  1 row created.
  
  SQL> INSERT INTO table_x VALUES(3,'B',NULL);
  
  1 row created.
  
  SQL> INSERT INTO table_x VALUES(3,'C',NULL);
  
  1 row created.
  
  SQL> SELECT * FROM table_x ORDER BY 1,2;
  
                 COL_A C                COL_C
  -------------------- - --------------------
                     1 A
                     1 B
                     2 A
                     2 B
                     3 A
                     3 B
                     3 C
  
  7 rows selected.
  
  SQL> UPDATE table_x x1
    2  SET    col_c = (
    3                     SELECT rn
    4                     FROM
    5                     (
    6                        SELECT col_a
    7                             , col_b
    8                             , ROW_NUMBER() OVER (PARTITION BY col_a ORDER BY col_b) rn
    9                        FROM   table_x
   10                     )  x2
   11                     WHERE  x2.col_a = x1.col_a
   12                     AND    x2.col_b = x1.col_b
   13                 )
   14  ;
  
  7 rows updated.
  
  SQL> SELECT * FROM table_x ORDER BY 1,2;
  
                 COL_A C                COL_C
  -------------------- - --------------------
                     1 A                    1
                     1 B                    2
                     2 A                    1
                     2 B                    2
                     3 A                    1
                     3 B                    2
                     3 C                    3
  
  7 rows selected.
  
  SQL>