Configure SQL * more question

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• SQL * more question: unprinted despite SET ECHO ON command

  RDBMS Version: 11.2.0.4

  OS: Oracle Linux 6.4 (bash shell)

  I'm kinda a newbie to SQL * more.

  Here's a SQL * Plus script embedded in bash script that scales multiple data files. This script has been run on the DB server side.

  #! / bin/bash

  export ORACLE_SID = ORCL1

  echo "resize Datafile began to" 'date '.

  sqlplus "/ as sysdba" < < EOF

  set echo on

  Set of feedback on

  ALTER DATABASE DATAFILE '+ DATA/brfcsprd/datafile/manh_audit_lob.338.834340223' resize 25g;

  ALTER DATABASE DATAFILE '+ DATA/brfcsprd/datafile/manh_audit_lob.337.834340223' resize 25g;

  ALTER DATABASE DATAFILE '+ DATA/brfcsprd/datafile/manh_audit_lob.336.834340225' resize 25g;

  ALTER DATABASE DATAFILE '+ DATA/brfcsprd/datafile/manh_audit_lob.335.834340225' resize 25g;

  ALTER DATABASE DATAFILE '+ DATA/brfcsprd/datafile/manh_audit_lob.334.834340225' resize 25g;

  ALTER DATABASE DATAFILE '+ DATA/brfcsprd/datafile/manh_audit_lob.333.834340225' resize 25g;

  ALTER DATABASE DATAFILE '+ DATA/brfcsprd/datafile/manh_audit_lob.332.834340227' resize 25g;

  quit smoking

  EXPRESSIONS OF FOLKLORE

  echo "resize Datafile ended in" 'date '.

  As you can see, the SQL * more script contains ON SET ECHO ON and PUT your COMMENTS.

  But in the logfile (see below), I don't see every ALTER DATABASE DATAFILE... command printing. I see that ' altered database.'  printing messages.

  I executed the script to nohup as

  nohup resize.sh > MyResize2.log &

  $ cat MyResize2.log

  DataFile resize started at Sun Dec 29 00:09:45 MYT 2013

  SQL * more: Production of the 11.2.0.4.0 on Sun Dec 29 00:09:45 version 2013

  Copyright (c) 1982, 2013, Oracle.  All rights reserved.

  Connected to:

  Oracle Database 11 g Enterprise Edition Release 11.2.0.4.0 - 64 bit Production

  With partitioning, Real Application Clusters, Automatic Storage Management, OLAP,.

  Options of Data Mining and Real Application Testing

  SQL > SQL > SQL > SQL > SQL >

  Database altered.

  SQL >

  Database altered.

  SQL >

  Database altered.

  SQL >

  Database altered.

  SQL >

  Database altered.

  SQL >

  Database altered.

  SQL >

  Database altered.

  Hello

  ECHO applies only to the SQL commands * Plus reads through the @ or the STARTUP command, no statements you type directly in the SQL > prompt or read the bash script statements.

  Try to create a separate file, containing only the command ALTER DATABASE in a separate file (let's call it alter_database.sql for now) and call it from your script bash, like this:

  #! / bin/bash

  export ORACLE_SID = ORCL1

  echo "resize Datafile began to" 'date '.

  sqlplus "/ as sysdba".<>

  set echo on

  Set of feedback on

  @whatever/alter_database

  quit smoking

  EXPRESSIONS OF FOLKLORE

  echo "resize Datafile ended in" 'date '.

• SQL MORE QUESTIONS

  According to the tables and the attributes below, I need solve 25 questions. I answered some of them and some of them I couldn't solve. I need your help please.
  
  School (sch_name, sch_phone, sch_code, sch_dean)
  Advisor (adv_code, adv_fname, adv_lname, adv_phone, sch_code)
  Major (maj_code, maj_desc, sch_code)
  maj_adv (maj_code, adv_code)
  student (std_code, std_lname, std_fname, std_gend, maj_code, std_dob)
  rank (std_code, gr_lname, gr_fname, gr_t1, gr_t2, gr_hw, gr_pr)
  
  
  create table school
  (sch_code varchar2 (8) school_sch_code_pk primary key constraint,)
  sch_name varchar2 (50).
  sch_phone varchar2 (12),
  sch_dean varchar2 (20));
  
  insert into the values of the school ('BUS', "School of Business", 281-283-3100', 'Ted Cummings');
  insert into the values of the school ("EDU", «School of Education», 281-283-3600', "Dennis Spuck");
  insert into the values of the school ("MSM", "School letters" and Human Sciences, ' 281-283-3333', "Bruce Palmer");
  insert into the values of the school ('DRY', 'school of Science and engineering', ' 281-283-3700', "Sadegh Davari");
  
  create table Advisor
  (adv_code varchar2 (08) advisor_adv_code_pk primary key constraint,)
  adv_lname varchar2 (15).
  adv_fname varchar2 (15).
  adv_phone varchar2 (12),
  sch_code varchar2 (8) constraint advisor_sch_code_fk references school (sch_code));
  
  insert into portfolioadvisor ('A1', 'Porter', 'Mattie', ' 281-283-3163', 'BUS');
  insert into portfolioadvisor ("A2", "Grady", "Lost", 281-283-3400', 'BUS');
  insert into portfolioadvisor ("A3", "Tran", "Van", 281-283-3203', 'BUS');
  insert into portfolioadvisor ('A4', 'Sale', 'Nili', 281-283-3202', 'BUS');
  insert into portfolioadvisor ("A5", "Kwok-good', 'Yue', 281-283-3864', 'SEC');
  insert into portfolioadvisor ("A6", "Jones", "Lisa", ' 281-283-3551', "EDU");
  insert into portfolioadvisor ("A7", "Palmer", "Bruce", 281-283-3445', "MSM");
  
  
  create major table
  (maj_code varchar2 (10) major_maj_code_pk primary key constraint,)
  maj_desc varchar2 (30),
  sch_code varchar2 (8) constraint major_sch_code_fk references school (sch_code));
  
  insert into large values ('ACCT', 'Accounting', 'BUS');
  insert into the great values ('Ministers', 'Finance', 'BUS');
  insert into large values ("ISAM", 'Management Information systems', 'BUS');
  insert into large values ('SMK', 'Computer Science', 'DRY');
  insert into large values ('HIST', 'History', "MSM");
  insert into large values ("INST", "Instructional Technology", "EDU");
  
  create the table maj_adv
  (maj_code varchar2 (10) constraint maj_adv_maj_code_fk main references (maj_code),)
  adv_code varchar2 (08) constraint maj_adv_adv_code_fk references Advisor (adv_code).
  constraint maj_adv_maj_code_adv_code_cpk primary key (maj_code, adv_code));
  
  insert into maj_adv values ('ACCT', 'A1');
  insert into maj_adv values ("ACCT", "A2");
  insert into maj_adv values ("Ministers", "A2");
  insert into maj_adv values ("ISAM", "A3");
  insert into maj_adv values ("ISAM", "A4");
  insert into maj_adv values ("CSCI", "A5");
  insert into maj_adv values ("INST", "A6");
  insert into maj_adv values ("HIST", "A7");
  
  
  create table students
  (std_code, varchar2 (9))
  std_lname varchar2 (15) constraint student_std_lname_nn not null,
  std_fname varchar2 (15) constraint student_std_fname_nn not null,
  std_gend varchar2 (8).
  maj_code varchar2 (10) constraint student_maj_code1_fk main references (maj_code).
  date of std_dob,
  constraint student_std_code_pk primary key (std_code));
  
  insert into student values ('S1', 'Jordan', 'Michael', 'F' 'Ministers', to_date (10 March 1962 ',' Mon-DD-YYYY ""));
  insert into student values ('S2', 'Barkley', 'Charles, m', null, to_date ('12-Sept-1964, ' Mon-DD-YYYY ""));
  insert into student values ('S3 ', 'Johnson', 'Magic', am ', 'ACCT', to_date ('13-Sep-1960, ' Mon-DD-YYYY ""));
  insert into values student ("S4", "Williams', 'Serena', 'F', 'ISAM', to_date (October 23, 1980 ',' Mon-DD-YYYY" "));
  insert into student values ('S5', 'Duncan', 'Tim', am', 'ISAM', to_date (August 7, 1972 ',' Mon-DD-YYYY'));
  insert into values student ("S6", "Graff", 'Steffi', 'F', 'SMK', to_date (30 April 1962 ',' Mon-DD-YYYY ""));
  insert into values student ("S7", "Navratilova", "Martina", 'F', 'ACCT', to_date (18 December 1972 ',' Mon-DD-YYYY ""));
  
  NOTE Insert student (std_lname, std_fname, std_code, std_dob)
  NOTE values ('S2', 'Barkley', 'Charles', to_date('12-Sep-1964','DD-Mon-YYYY'));
  
  create the table class
  (std_code varchar2 (9) grade_std_code_pk primary key constraint)
  constraint grade_std_code_fk references student (std_code).
  gr_lname varchar2 (15) constraint grade_gr_lname_nn not null,
  gr_fname varchar2 (15) constraint grade_gr_fname_nn not null,
  gr_t1 number (5), constraint grade_gr_t1_cc check (gr_t1 between 0 and 100).
  gr_t2 number (5),
  gr_hw number (5),
  gr_pr number (5));
  
  insert into rank values ('S1', 'Jordan', 'Michael', 90, 80, 98, 90);
  insert into rank values ('S2', 'Barkley', 'Charles', 60, 100, 100, 60);
  insert into rank values ('S3', 'Johnson', 'Magic', 88, 98, 96, 98);
  insert into rank values ("S4", "Williams", "Serena", 92, 92, 92, 92);
  insert into rank values ('S5', 'Duncan', 'Tim', 90, 94, 94, 96);
  insert into rank values ("S6", "Graffiti", "Steffi", 80, 83, 84, 72);
  insert into category values ("S7", "Navratilova", "Martina", 91, 88, 94, 95);
  
  the questions are:
  
  Give the following commands:
  
  1 the names of students who do not have a large.
  2 display the names of the students whose name has two "o" inside.
  3 the names of the students whose first name has an "e" in it.
  4 the names of the students whose name has exactly five characters in there.
  5 the names of students with higher test grade 2 test 1 grade.
  6 the names of pupils with grade of the project between trials 1 and 2 test classes.
  7. give the name of the student whose name begins with the character 'B' or who have never transformed into working from home.
  8. give the command that will appear two columns and one record. The first column will have the title "Major" and "ACCT" as value. The second column will have the title of 'MIS_Count' and will display the number of advisors of accounting.
  9 display the name of the student whose test 1 score is higher than the average on test 1.
  10. give the names and surname of the students who scored above average on test 1, as well as above average on the test # 2.
  11 show the date variable system using the double table.
  12. show the date variable system using the table of quality ensuring that the date is displayed only once.
  13. give the name of the student who is the oldest student and scored highest on the first try.
  14 list different majors and number of advisors for these majors.
  15 show the names of students who do not quality for any element.
  16 show the names of students who do not have at least one element.
  17 the names of students who have the same major as 'Michael Jordan'.
  18. give the names of the students whose average on test 1 and test 2 is higher than the average on the homework and project.
  19 display name and the average of the test 1 and 2 test for each student.
  20 display the number of students in the student table using three different methods.
  21. view student numbers in the table of student accountants.
  22 display the number of students of accounting and finance in the student table.
  23 show the average on the test 1 and 2 test for female students.
  24 show the number of students of accounting and finance including test 1 grades are above average on test 1.
  25 display the name of the major that has more than two students.
  
  I'm stuck with the following questions (1,12,13, 15,16,17,24) and the rest, I finished them but I'm not sure.
  Thank you and looking forward to hear your suggestions.

  Hi and welcome to the forum!

  This looks like a duty for me to be perfectly honest. When it's people are usually not willing to spoon feed answers because is not helping improve learning.

  I'll try to help if you can show me what you have tried for the issues that you are having problems with.

  Thank you!

• SQL * more question

  Hello
  Could you help me with writing SQL script, please.
  I had 4 tables.
  1: offers: attributes: Hotel, car, id of the offer, day, place.
  2: clients: attributes: customer id, name, address, no.phone.
  3. travel: attributes: id of the offer, date of the excursion, the price.
  4: reservations; attributes: offer code, the date of the offer, customer id, date of reservation, no.people, prepayment.
  
  I do the script:
  Please provide the name of the customer, address, no.phone. who has chosen to offer for the Special Place. Should be dinamic script.
  
  Help, please.

  SQL> ACCEPT Place PROMPT "Please enter place: "
  Please enter place: Zakopane
  SQL> SELECT  K.NAZWA,
    2          K.ADRES,
    3          K.NR_TELEFONU
    4    FROM  KLIENCI K,
    5          REZERWACJE  R,
    6          OFERTY O
    7    WHERE O.MIEJSCE     = '&Place'
    8      AND R.KOD_OFERTY  = O.KOD_OFERTY
    9      AND K.KOD_KLIENTA = R.KOD_KLIENTA
   10  /
  old   7:   WHERE O.MIEJSCE     = '&Place'
  new   7:   WHERE O.MIEJSCE     = 'Zakopane'
  
  NAZWA           ADRES                NR_TELEFONU
  --------------- -------------------- -----------
  Andrzej Krzak   Ul.Wiosenna Lublin    7814562508
  
  SQL> ACCEPT Place PROMPT "Please enter place: "
  Please enter place: berlin
  SQL> SELECT  K.NAZWA,
    2          K.ADRES,
    3          K.NR_TELEFONU
    4    FROM  KLIENCI K,
    5          REZERWACJE  R,
    6          OFERTY O
    7    WHERE O.MIEJSCE     = '&Place'
    8      AND R.KOD_OFERTY  = O.KOD_OFERTY
    9      AND K.KOD_KLIENTA = R.KOD_KLIENTA
   10  /
  old   7:   WHERE O.MIEJSCE     = '&Place'
  new   7:   WHERE O.MIEJSCE     = 'berlin'
  
  NAZWA           ADRES                NR_TELEFONU
  --------------- -------------------- -----------
  Robert Dole     Ul.Lubelska Ciechan   7522885699
  
  SQL> 
  

  SY.

• SQL * more substitution vs bind variable question

  Hi all, I am trying to automate some SQL within SQL codes * more script that is triggered by a script .bat, the only parts that change are Dates...

  example:

  create table blah as

  Select * from table

  WHERE DATE between start_date and END_DAY;

  the DATE is a numeric field, YYYYMMDD

  The script runs always at the beginning of a new week, so a Monday, unless a public holiday, then a Tuesday.

  The END_DAY is * always * last Friday and I realized that:

  variable L_FRIDAY char (15);

  Start

  Select to_char (next_day(sysdate-7,'FRIDAY'), 'YYYYMMDD') as Last_Friday in: double L_FRIDAY;

  end;

  /

  The thing is that I get an error when I try to use the binding variable?

  create table blah as

  Select * from table

  WHERE DATE between start_date and: L_FRIDAY;

  Then once I found the end date, I was going to use add_months(L_FRIDAY,-12) for previous 12 months for the start_date...

  When I tried to use a variable Substitution I could just hard code the date, but I can not or do not know how to set the value of this exec to the variable?

  Help!

  :-)

  Basically my research reveals that - Bind variables are not allowed for operations of data definition, use substutions instead of bind variables

  I need an automated way to find the END_DAY which is last Friday and START_DATE that is 12 months before Friday and refer to those in the SQL without errors.

  Hello

  Kodiak_Seattle wrote:

  Hi all, I am trying to automate some SQL within SQL codes * more script that is triggered by a script .bat, the only parts that change are Dates...

  example:

  create table blah as

  Select * from table

  WHERE DATE between start_date and END_DAY;

  the DATE is a numeric field, YYYYMMDD

  The script runs always at the beginning of a new week, so a Monday, unless a public holiday, then a Tuesday.

  The END_DAY is * always * last Friday and I realized that:

  variable L_FRIDAY char (15);

  Start

  Select to_char (next_day(sysdate-7,'FRIDAY'), 'YYYYMMDD') as Last_Friday in: double L_FRIDAY;

  end;

  /

  The thing is that I get an error when I try to use the binding variable?

  create table blah as

  Select * from table

  WHERE DATE between start_date and: L_FRIDAY;

  Then once I found the end date, I was going to use add_months(L_FRIDAY,-12) for previous 12 months for the start_date...

  When I tried to use a variable Substitution I could just hard code the date, but I can not or do not know how to set the value of this exec to the variable?

  Help!

  :-)

  Basically my research reveals that - Bind variables are not allowed for operations of data definition, use substutions instead of bind variables

  I need an automated way to find the END_DAY which is last Friday and START_DATE that is 12 months before Friday and refer to those in the SQL without errors.

  Or SQL * more bind variable or variable substitution can be DATEs.  The best you can do is set a different type, as a string, representing a date.  A string as June 19, 2015"represents a date, but so strings like 'SYSDATE' and ' SYSDATE - 7', so you can do something like this:

  SET l_friday = ' NEXT_DAY ((SYSDATE-7), 'FRIDAY').

  DEFINE start_date = "ADD_MONTHS (& l_friday, - 12)"

  SELECT & start_date AS t_n

  , & l_friday AS l_f

  OF the double

  ;

  Output (when executed on 25 June 2015):

  L_F T_N

  ----------- -----------

  June 19, 2014 19 June 2015

• Question on the definition of the width of column in SQL * more with information recovered w SQL

  Hello
  
  Is there a way to tell SQL * more to set the width of a column with the largest width of the items in the column? (as opposed to the default which is declared in the DDL width)
  
  In other words, I would like to do something functionally equivalent to this:
  
  COL < columname > format [select max (length (< columnname >)) < thetablethatcontainscolumname >]
  
  I do above manually in two steps
  
  1. select max (length (columnname)) of...
  
  2 col columnname format a [resultofstep1]
  
  Is it possible to do in one step?
  
  Thank you for your help,
  
  John.

  Hi John

  I don't think that there is a way to do this, because this information is not known at run time (as you proved it, you must run a separate SQL query first to calculate that information - also, what happens if there are predicates, this could affect the defined result so the request will actually be performed twice). You may decide an arbitrary width for each column and set it as being wrapped/word_wrapped/truncated.

  Other that that, you should consider whther you are using the right tool for the job, SQLplus is not exactly ideal for the presentation layer stuff. Something like APEX would give you much more control over the layout and formatting.

  See you soon

  Ben

• SQL * more the 'timing' in SQL Developer command

  I installed SQL Developer version 4.1.1.19. In the sql worksheet, how can I use SQL * more order 'timing' in a script to see a time elapsed SQL? The "Timing" on 'set' did not return any info after running SQL, and 'calendar beginning mon_timer' back 'command Timing is obsolete. Help, please.

  Thank you

  • As you can see, there is no calendar information in the script output log.
  • Then I tried on the discussion forum, found it can be enabled in "tool > preference > Database > startup script" and set as startup script:

  Set serveroutput on

  set timing on

  • However, 2 questions are:
  1. the calendar that he returned is NOT the elapsed time of my stored procedure to run. He simply choose the 2 time points its time, before and not after MS point run. Set timing on is therefore not a solution for me.
  2. He did not follow the instructions in the startup script. After that I put the calendar in the startup script, stop & restart SQL Developer, same laptop charging, timing still on. The only way to turn off now is to configure it to NOT use

  any startup script.

  • Then I developed my own coding as a solution:

  3. control of the COIL

  VAR bv_start_ts VARCHAR2 (30)

  VAR bv_end_ts VARCHAR2 (30)

  VAR bv_elps_ts VARCHAR2 (30)

  DECLARE

  v_start_ts VARCHAR2 (30);

  BEGIN

  SELECT TO_CHAR (SYSTIMESTAMP, 'yyyymmddfxDyhh24miss.ff6') INTO v_start_ts FROM DUAL;

  : bv_start_ts: = v_start_ts;

  END;

  /

  IMPRESSION bv_start_ts

  EXEC pmsmmi.rpt.rpt_ethncty_race_smry (15);

  DECLARE

  v_end_ts VARCHAR2 (30);

  BEGIN

  SELECT TO_CHAR (SYSTIMESTAMP, 'yyyymmddfxDyhh24miss.ff6') INTO v_end_ts FROM DUAL;

  : bv_end_ts: = v_end_ts;

  END;

  /

  IMPRESSION bv_end_ts

  EXEC: bv_elps_ts: = TO_CHAR (TO_TIMESTAMP (: bv_end_ts, 'yyyymmddfxDyhh24miss.ff6')-TO_TIMESTAMP (: bv_start_ts, 'yyyymmddfxDyhh24miss.ff6'), 'hh:mi:ss.ff6');

  IMPRESSION bv_elps_ts

  SPOOL OFF

  • Then I got what I want, the answer is in the 'PRINT ': bv_elps_ts

  SQL > VAR bv_start_ts VARCHAR2 (30)

  SQL > VAR bv_end_ts VARCHAR2 (30)

  SQL > VAR bv_elps_ts VARCHAR2 (30)

  SQL > DECLARE

  v_start_ts VARCHAR2 (30);

  BEGIN

  SELECT TO_CHAR (SYSTIMESTAMP, 'yyyymmddfxDyhh24miss.ff6') INTO v_start_ts FROM DUAL;

  : bv_start_ts: = v_start_ts;

  END;

  /

  PL/SQL procedure successfully completed.

  Elapsed time: 00:00:00.031

  SQL > PRINT bv_start_ts

  BV_START_TS

  -----------

  20150702Thu112617.775545

  SQL > EXEC pmsmmi.rpt.rpt_ethncty_race_smry (15)

  PL/SQL procedure successfully completed.

  SQL > DECLARE

  v_end_ts VARCHAR2 (30);

  BEGIN

  SELECT TO_CHAR (SYSTIMESTAMP, 'yyyymmddfxDyhh24miss.ff6') INTO v_end_ts FROM DUAL;

  : bv_end_ts: = v_end_ts;

  END;

  /

  PL/SQL procedure successfully completed.

  Elapsed time: 00:00:00.062

  SQL > PRINT bv_end_ts

  BV_END_TS

  ---------

  20150702Thu112630.805786

  SQL > EXEC: bv_elps_ts: = TO_CHAR (TO_TIMESTAMP (: bv_end_ts, 'yyyymmddfxDyhh24miss.ff6')-TO_TIMESTAMP (: bv_start_ts, 'yyyymmddfxDyhh24miss.ff6'), 'hh:mi:ss.ff6')

  PL/SQL procedure successfully completed.

  SQL > PRINT bv_elps_ts

  BV_ELPS_TS

  ----------

  + 00:00:13.030241000 000000

  SQL > SPOOL OFF

• Unable to connect to an instance by using EM but properly connect with SQL * more

  Hello
  
  I followed the following steps (from the document s/n 2 days):
  
  1. I created a model (including the database) to an instance named "orcl" using DBCA, before we proceed to create the model, DBCA informed me that the Forum might be stopped, I told him to go ahead.
  
  2. the model has been successfully created.
  
  3. I am now unable to connect to the instance orcl using EM, but I can connect to this instance without any problem using SQL * more.
  
  Question: Why am I not able to connect to the instance by using EM? and what should I do to fix this?
  
  Thank you very much for your help,
  
  John.
  
  PS: in case it may be useful, the listener tnsnames and Sqlnet files follow:
  

  # listener.ora Network Configuration File: E:\Oracle\product\11.2.0\dbhome_1\network\admin\listener.ora
  # Generated by Oracle configuration tools.
  
  SID_LIST_LISTENER =
    (SID_LIST =
      (SID_DESC =
        (SID_NAME = CLRExtProc)
        (ORACLE_HOME = E:\Oracle\product\11.2.0\dbhome_1)
        (PROGRAM = extproc)
        (ENVS = "EXTPROC_DLLS=ONLY:E:\Oracle\product\11.2.0\dbhome_1\bin\oraclr11.dll")
      )
    )
  
  LISTENER =
    (DESCRIPTION_LIST =
      (DESCRIPTION =
        (ADDRESS = (PROTOCOL = IPC)(KEY = EXTPROC1521))
        (ADDRESS = (PROTOCOL = TCP)(HOST = ORACLE2DAY1)(PORT = 1521))
      )
    )
  
  ADR_BASE_LISTENER = E:\Oracle

  # tnsnames.ora Network Configuration File: E:\Oracle\product\11.2.0\dbhome_1\network\admin\tnsnames.ora
  # Generated by Oracle configuration tools.
  
  DBCA =
    (DESCRIPTION =
      (ADDRESS = (PROTOCOL = TCP)(HOST = ORACLE2DAY1)(PORT = 1521))
      (CONNECT_DATA =
        (SERVER = DEDICATED)
        (SERVICE_NAME = dbca.localsite.com)
      )
    )
  
  ORACLR_CONNECTION_DATA =
    (DESCRIPTION =
      (ADDRESS_LIST =
        (ADDRESS = (PROTOCOL = IPC)(KEY = EXTPROC1521))
      )
      (CONNECT_DATA =
        (SID = CLRExtProc)
        (PRESENTATION = RO)
      )
    )
  
  LISTENER_ORCL =
    (ADDRESS = (PROTOCOL = TCP)(HOST = ORACLE2DAY1)(PORT = 1521))
  
  
  ORCL =
    (DESCRIPTION =
      (ADDRESS = (PROTOCOL = TCP)(HOST = ORACLE2DAY1)(PORT = 1521))
      (CONNECT_DATA =
        (SERVER = DEDICATED)
        (SERVICE_NAME = orcl.localsite.com)
      )
    )

  # sqlnet.ora Network Configuration File: E:\Oracle\product\11.2.0\dbhome_1\network\admin\sqlnet.ora
  # Generated by Oracle configuration tools.
  
  # This file is actually generated by netca. But if customers choose to 
  # install "Software Only", this file wont exist and without the native 
  # authentication, they will not be able to connect to the database on NT.
  
  SQLNET.AUTHENTICATION_SERVICES= (NTS)
  
  NAMES.DIRECTORY_PATH= (TNSNAMES, EZCONNECT)

  I think you change some configuration of your system as domain/IP address/host name.
  You need

  set ORACLE_SID=orcl
  emca -deconfig dbcontrol db -repos drop
  emca -config dbcontrol db -repos create
  

  then after result

• Special characters could not load DB via SQL * MORE

  Hi, I have a pl as .accidentally sets sql script which will insert data in database. The question is there are some records are missing and these missing records contains a special character: Sansao and Strasse. The strange was if I run the script via F5 (Toad), all data can be inserted successfully but run through SQL * MORE (Toad), all records that contain special characters are not inserted.

  Anyone here know why it didn't load these special characters via SQL * MORE?

  Probably because you have given unicode (multi byte charsets) you read with a customer of standard single-byte character set.

  It's SILLY to loading data using SQL * more. It's the wrong tool used for loading the data. It does not support the bind variable. It doesn't support liaison in bulk. It does not support direct path inserts. It is not SQL * Loader.

• Choose one in SQL Developer fails - SQL * more work

  Hi all

  I have the HS to MySLQ connection works correctly and most of the requirements I have in regards to the data works.

  
  However, I "only able to test my procedures and functions in SQL * more." IN SQL Developer 4.0.0.12 there is always a problem and questioning of the results are never displayed.

  Thanks in advance for any advice.

  Sincerely

  JS

  Hello Mike,.

  I use Oracle XE 11.2.0.2 x 64 on Linux. Using the MySQL ODBC 5.3.4 connection.

  I've just upgraded the SQL Developer to version 4.0.3 (released September 2014) and the problem seems to be resolved because I'm able to query the MySQL database and get the results.

  However, there is something I don't like all the whitespace added, whether in SQL Developer 4.0.3 in SQL * more.

  Here's the query I tested:

  Select "host", "User", "Password" in "user"@MYODBC5;

• SP2-0642: SQL * more internal error of State 2165

  Hello

  I was faced with the question with sqlplus suddenly in 11.2.0.3 throw version on solaris 10 OS, it was working fine until today. No changes made on this (11.2.0.3.Q3) oracle home, but new ORACLE HOME installed by Server DBA (shared server) with the Q4 patch.

  -bash-3, $2 sqlplus / as sysdba

  SP2-0642: SQL * more internal error state 2165, context 4294967295:0:0

  Impossible to continue

  As explained in metalink note: 396154.1, I set NLS_DATE_FORMAT, but it doesn't seem to work

  also, I've checked the timezone as explained in the blog file, but the file timezone.dat does not exist in 11.2.0.3 version and all the files in $ORACLE_HOME/oracore/zoneinfo/have permissions of reading to the dba group

  http://arjudba.blogspot.com/2010/07/non-Oracle-user-hits-SP2-0642-or-SP2.html

  -bash - $3.2 ls - ltr

  30942 total

  -rw - r - r - 1 oracle dba readme.txt 6068 7 June 2010

  -rw - r - r - 1 oracle dba 31525 June 7, 2010 timezdif.csv

  -rw - r - r - 1 oracle dba 351525 Aug 21, 2011 timezone_9.dat

  -rw - r - r - 1 oracle dba 302100 August 21, 2011 timezone_8.dat

  -rw - r - r - 1 oracle dba 286815 Aug 21, 2011 timezone_7.dat

  -rw - r - r - 1 oracle dba 286217 Aug 21, 2011 timezone_6.dat

  -rw - r - r - 1 oracle dba 286310 Aug 21, 2011 timezone_5.dat

  -rw - r - r - 1 oracle dba 286264 Aug 21, 2011 timezone_4.dat

  -rw - r - r - 1 oracle dba 286651 Aug 21, 2011 timezone_3.dat

  -rw - r - r - 1 oracle dba 274900 August 21, 2011 timezone_2.dat

  -rw - r - r - 1 oracle dba 344448 Aug 21, 2011 timezone_14.dat

  -rw - r - r - 1 oracle dba 344425 Aug 21, 2011 timezone_13.dat

  -rw - r - r - 1 oracle dba 345024 Aug 21, 2011 timezone_12.dat

  -rw - r - r - 1 oracle dba 345356 Aug 21, 2011 timezone_11.dat

  -rw - r - r - 1 oracle dba 345637 Aug 21, 2011 timezone_10.dat

  -rw - r - r - 1 oracle dba 274427 Aug 21, 2011 timezone_1.dat

  -rw - r - r - 1 oracle dba 801410 Aug 21, 2011 timezlrg_9.dat

  -rw - r - r - 1 oracle dba 616723 Aug 21, 2011 timezlrg_8.dat

  -rw - r - r - 1 oracle dba 601242 Aug 21, 2011 timezlrg_7.dat

  -rw - r - r - 1 oracle dba 586750 Aug 21, 2011 timezlrg_6.dat

  -rw - r - r - 1 oracle dba 587487 Aug 21, 2011 timezlrg_5.dat

  -rw - r - r - 1 oracle dba 531137 Aug 21, 2011 timezlrg_4.dat

  -rw - r - r - 1 oracle dba 527717 Aug 21, 2011 timezlrg_3.dat

  -rw - r - r - 1 oracle dba 507957 Aug 21, 2011 timezlrg_2.dat

  -rw - r - r - 1 oracle dba 791430 Aug 21, 2011 timezlrg_14.dat

  -rw - r - r - 1 oracle dba 782475 Aug 21, 2011 timezlrg_13.dat

  -rw - r - r - 1 oracle dba 785621 Aug 21, 2011 timezlrg_12.dat

  -rw - r - r - 1 oracle dba 787272 Aug 21, 2011 timezlrg_11.dat

  -rw - r - r - 1 oracle dba 792894 Aug 21, 2011 timezlrg_10.dat

  -rw - r - r - 1 oracle dba 493675 Aug 21, 2011 timezlrg_1.dat

  drwxr-xr-x 2 oracle dba 30 Sep 8 05:03 big

  drwxr-xr-x 2 oracle dba 30 Sep 8 05:03 little

  Please suggest alternatives to troubleshoot

  Thank you

  Sol.beach thanks for the reply, I'm able to correct the problem. In fact the PATH variable has put in .profile of export PATH = $PATH: $ORACLE_HOME/bin and the value is lower.

  -bash-3, $ 2 echo $PATH

  /Apps/Oracle/product/9.2.0.8.2009Q4/bin:/usr/ccs/bin:/usr/sbin:/usr/bin:/bin:.:/ bin:/opt/bin:usr/CSS/bin:/usr/ucb:/usr/local/bin:/apps/Oracle/product/11.2.0.3.2014Q3/bin

  I changed as export PATH = $ORACLE_HOME/bin: $PATH and now it works fine. It seems to be a problem with the old Oracle Home, also present in the PATH variable before the bin to the current address of Oracle Home Directory.

  -bash-3, $ 2 echo $PATH

  /Apps/Oracle/product/11.2.0.3.2014Q3/bin:/apps/Oracle/product/9.2.0.8.2009Q4/bin:/usr/ccs/bin:/usr/sbin:/usr/bin:/bin:.:/ bin: / opt/bin: css/usr/bin: / usr/ucb: / usr/local/bin

  Concerning

• Database demo of vision: how to access the database through SQL * more?

  I'm totally new in this space, so forgive my beginner questions.

  What I want to do, is to integrate EBS with APEX. To get there I downloaded (of delivery) and installed the Vision database unique node in a VirtualBox. To do this, I followed this video on YouTube: https://www.youtube.com/watch?v=8JgxMDPsd6s

  Now I want to install APEX and for this I need to access my database as SYS. Now for my questions:

  1. How can I use SQL * more in the VirtualBox?

  2. What is the default password for SYS with this demo database?

  Thanks, Alex

  File under $ORACLE_HOME and the owner is the user 'oracle '.

  You will need to source the file VISION_ebs.env , and then deliver "env | fate"and you should see the set env variables. You can connect as sysdba.

  Thank you

  Hussein

• Cannot access SQL more from other than the Oracle users

  Hello

  I installed Oracle 11 g R2 on Red Hat 6. My problem is that I can't access sqlplus from other than the oracle users.

  I put the PATH, the ORACLE_HOME and ORACLE_SID to the correct values.

  Session1

  Connect as: oracle

  [email protected] password:

  Last login: Sun Aug 24 01:24:46 192.168.202.1 2014

  [oracle@localhost ~] $ echo $PATH

  /usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin:/Home/Oracle/bin:/Home/Oracle/app/Oracle/product/11.2.0/dbhome_1/bin

  [oracle@localhost ~] $ echo $ORACLE_HOME

  /Home/Oracle/app/Oracle/product/11.2.0/dbhome_1

  [oracle@localhost ~] $ echo $ORACLE_SID

  ORCL

  [oracle@localhost ~] $ sqlplus

  SQL * more: Production release 11.2.0.1.0 Sun Aug 24 03:17:32 2014

  Copyright (c) 1982, 2009, Oracle.  All rights reserved.

  Enter the user name:

  Session2

  Connect as: nada

  [email protected] password:

  Last login: Sun Aug 24 02:31:49 192.168.202.1 2014

  [prithwish@localhost ~] $ export PATH=$PATH:/home/oracle/app/oracle/product/11.2.0/dbhome_1/bin

  [prithwish@localhost ~] $ export ORACLE_HOME=/home/oracle/app/oracle/product/11.2.0/dbhome_1

  [prithwish@localhost ~] $ export ORACLE_SID = orcl

  [prithwish@localhost ~] $ echo $ORACLE_HOME

  /Home/Oracle/app/Oracle/product/11.2.0/dbhome_1

  [prithwish@localhost ~] $ echo $ORACLE_SID

  ORCL

  [prithwish@localhost ~] $ echo $PATH

  /usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin:/Home/Prithwish/bin:/Home/Oracle/app/Oracle/product/11.2.0/dbhome_1/bin

  [prithwish@localhost ~] $ sqlplus

  -bash: sqlplus: command not found

  I guess that I could not access sqlplus as the Nada the user has no access to X11R6

  [prithwish@localhost ~] $ cd...

  [Host prithwish@localhost] $ ls - ltr

  Total 8

  drwx-. 30 oracle oinstall 4096 23 August 23:51 oracle

  drwx-. Nada Nada 4096 24 August to 02:33 27 Mathieu

  [Host prithwish@localhost] $

  My question is, although quite stupid, that double

  (1) I have to change the permissions of the directory oracle of 755 for any other user to access the sqlplus?

  (2) why is the user directory under the folder created with permissions of 700, even when the umask is set to 002? Change the permissions of the directory under/Home oracle will cause security problems?

  My apologies for being naïve. It's the first time I installed Oracle under UNIX

  Kind regards

  Prithwsh

  Actually, the default procedure is NOT to install oracle to X11R6, but in/opt/oracle. or maybe/usr/local/oracle.

  This is what you're going to be recommended in the installation documentation, and in doing so, don't forget to run rootpre.sh and root.sh, I never had security problems and could run Oracle from any account.

  Sybrand Bakker

  Senior Oracle DBA

• SQL * Net questions - which forum?

  Does anyone know what forum manages SQL * Net questions?

  THX

  For general issues, it's probably as good a place to ask as any.

  If you have SQL * Net questions that are specific to a particular technology (i.e. how various options of TNS interact with different configurations of CARS), you probably want to ask in the forums dedicated to these products.

  Justin

• Can I connect to SQL * more as SYS after connecting as a user and then run a GRANT?

  Oracle 11 g 2

  Linux RHEL 6.3

  SQL * Plus 11.2.0.2 on Windows 7

  ------------------------------------------------

  I am running a script SQL through SQL * more connected as "DOE, JOHN".

  In the SQL script, I need to connect as SYS to make a GRANT EXECUTE on a SYS package (e.g. GRANT EXECUTE ON DBMS_CRYPTO to JOHN;).

  But it fails with the following error:

  
  GRANT EXECUTE ON TO JOHN DBMS_CRYPTO
  *
  ERROR on line 1:
  ORA-01917: user or role 'JOHN' does not exist

  But of course, 'JOHN' are.  The rest of the SQL script is running "DOE, JOHN" without any problem.

  The code segment of SQL script in question is:

  connect sys/password as sysdba
  GRANT EXECUTE ON DBMS_CRYPTO TO ROYSECITYDATA;  <-fails here
  to connect/DOE

  Please advise on what my being the issue.

  tx103108 wrote:

  I connect to a remote database.  All dbs distance have the same instance name as they are all images.  I see where you're going (I think).  Should I try

  I'll try to connect sys/password@MYDB

  Sounds like a plan... (the instance_name returned with what you expected? or something else?)