SQL MORE QUESTIONS

According to the tables and the attributes below, I need solve 25 questions. I answered some of them and some of them I couldn't solve. I need your help please.

School (sch_name, sch_phone, sch_code, sch_dean)
Advisor (adv_code, adv_fname, adv_lname, adv_phone, sch_code)
Major (maj_code, maj_desc, sch_code)
maj_adv (maj_code, adv_code)
student (std_code, std_lname, std_fname, std_gend, maj_code, std_dob)
rank (std_code, gr_lname, gr_fname, gr_t1, gr_t2, gr_hw, gr_pr)


create table school
(sch_code varchar2 (8) school_sch_code_pk primary key constraint,)
sch_name varchar2 (50).
sch_phone varchar2 (12),
sch_dean varchar2 (20));

insert into the values of the school ('BUS', "School of Business", 281-283-3100', 'Ted Cummings');
insert into the values of the school ("EDU", «School of Education», 281-283-3600', "Dennis Spuck");
insert into the values of the school ("MSM", "School letters" and Human Sciences, ' 281-283-3333', "Bruce Palmer");
insert into the values of the school ('DRY', 'school of Science and engineering', ' 281-283-3700', "Sadegh Davari");

create table Advisor
(adv_code varchar2 (08) advisor_adv_code_pk primary key constraint,)
adv_lname varchar2 (15).
adv_fname varchar2 (15).
adv_phone varchar2 (12),
sch_code varchar2 (8) constraint advisor_sch_code_fk references school (sch_code));

insert into portfolioadvisor ('A1', 'Porter', 'Mattie', ' 281-283-3163', 'BUS');
insert into portfolioadvisor ("A2", "Grady", "Lost", 281-283-3400', 'BUS');
insert into portfolioadvisor ("A3", "Tran", "Van", 281-283-3203', 'BUS');
insert into portfolioadvisor ('A4', 'Sale', 'Nili', 281-283-3202', 'BUS');
insert into portfolioadvisor ("A5", "Kwok-good', 'Yue', 281-283-3864', 'SEC');
insert into portfolioadvisor ("A6", "Jones", "Lisa", ' 281-283-3551', "EDU");
insert into portfolioadvisor ("A7", "Palmer", "Bruce", 281-283-3445', "MSM");


create major table
(maj_code varchar2 (10) major_maj_code_pk primary key constraint,)
maj_desc varchar2 (30),
sch_code varchar2 (8) constraint major_sch_code_fk references school (sch_code));

insert into large values ('ACCT', 'Accounting', 'BUS');
insert into the great values ('Ministers', 'Finance', 'BUS');
insert into large values ("ISAM", 'Management Information systems', 'BUS');
insert into large values ('SMK', 'Computer Science', 'DRY');
insert into large values ('HIST', 'History', "MSM");
insert into large values ("INST", "Instructional Technology", "EDU");

create the table maj_adv
(maj_code varchar2 (10) constraint maj_adv_maj_code_fk main references (maj_code),)
adv_code varchar2 (08) constraint maj_adv_adv_code_fk references Advisor (adv_code).
constraint maj_adv_maj_code_adv_code_cpk primary key (maj_code, adv_code));

insert into maj_adv values ('ACCT', 'A1');
insert into maj_adv values ("ACCT", "A2");
insert into maj_adv values ("Ministers", "A2");
insert into maj_adv values ("ISAM", "A3");
insert into maj_adv values ("ISAM", "A4");
insert into maj_adv values ("CSCI", "A5");
insert into maj_adv values ("INST", "A6");
insert into maj_adv values ("HIST", "A7");


create table students
(std_code, varchar2 (9))
std_lname varchar2 (15) constraint student_std_lname_nn not null,
std_fname varchar2 (15) constraint student_std_fname_nn not null,
std_gend varchar2 (8).
maj_code varchar2 (10) constraint student_maj_code1_fk main references (maj_code).
date of std_dob,
constraint student_std_code_pk primary key (std_code));

insert into student values ('S1', 'Jordan', 'Michael', 'F' 'Ministers', to_date (10 March 1962 ',' Mon-DD-YYYY ""));
insert into student values ('S2', 'Barkley', 'Charles, m', null, to_date ('12-Sept-1964, ' Mon-DD-YYYY ""));
insert into student values ('S3 ', 'Johnson', 'Magic', am ', 'ACCT', to_date ('13-Sep-1960, ' Mon-DD-YYYY ""));
insert into values student ("S4", "Williams', 'Serena', 'F', 'ISAM', to_date (October 23, 1980 ',' Mon-DD-YYYY" "));
insert into student values ('S5', 'Duncan', 'Tim', am', 'ISAM', to_date (August 7, 1972 ',' Mon-DD-YYYY'));
insert into values student ("S6", "Graff", 'Steffi', 'F', 'SMK', to_date (30 April 1962 ',' Mon-DD-YYYY ""));
insert into values student ("S7", "Navratilova", "Martina", 'F', 'ACCT', to_date (18 December 1972 ',' Mon-DD-YYYY ""));

NOTE Insert student (std_lname, std_fname, std_code, std_dob)
NOTE values ('S2', 'Barkley', 'Charles', to_date('12-Sep-1964','DD-Mon-YYYY'));

create the table class
(std_code varchar2 (9) grade_std_code_pk primary key constraint)
constraint grade_std_code_fk references student (std_code).
gr_lname varchar2 (15) constraint grade_gr_lname_nn not null,
gr_fname varchar2 (15) constraint grade_gr_fname_nn not null,
gr_t1 number (5), constraint grade_gr_t1_cc check (gr_t1 between 0 and 100).
gr_t2 number (5),
gr_hw number (5),
gr_pr number (5));

insert into rank values ('S1', 'Jordan', 'Michael', 90, 80, 98, 90);
insert into rank values ('S2', 'Barkley', 'Charles', 60, 100, 100, 60);
insert into rank values ('S3', 'Johnson', 'Magic', 88, 98, 96, 98);
insert into rank values ("S4", "Williams", "Serena", 92, 92, 92, 92);
insert into rank values ('S5', 'Duncan', 'Tim', 90, 94, 94, 96);
insert into rank values ("S6", "Graffiti", "Steffi", 80, 83, 84, 72);
insert into category values ("S7", "Navratilova", "Martina", 91, 88, 94, 95);

the questions are:

Give the following commands:

1 the names of students who do not have a large.
2 display the names of the students whose name has two "o" inside.
3 the names of the students whose first name has an "e" in it.
4 the names of the students whose name has exactly five characters in there.
5 the names of students with higher test grade 2 test 1 grade.
6 the names of pupils with grade of the project between trials 1 and 2 test classes.
7. give the name of the student whose name begins with the character 'B' or who have never transformed into working from home.
8. give the command that will appear two columns and one record. The first column will have the title "Major" and "ACCT" as value. The second column will have the title of 'MIS_Count' and will display the number of advisors of accounting.
9 display the name of the student whose test 1 score is higher than the average on test 1.
10. give the names and surname of the students who scored above average on test 1, as well as above average on the test # 2.
11 show the date variable system using the double table.
12. show the date variable system using the table of quality ensuring that the date is displayed only once.
13. give the name of the student who is the oldest student and scored highest on the first try.
14 list different majors and number of advisors for these majors.
15 show the names of students who do not quality for any element.
16 show the names of students who do not have at least one element.
17 the names of students who have the same major as 'Michael Jordan'.
18. give the names of the students whose average on test 1 and test 2 is higher than the average on the homework and project.
19 display name and the average of the test 1 and 2 test for each student.
20 display the number of students in the student table using three different methods.
21. view student numbers in the table of student accountants.
22 display the number of students of accounting and finance in the student table.
23 show the average on the test 1 and 2 test for female students.
24 show the number of students of accounting and finance including test 1 grades are above average on test 1.
25 display the name of the major that has more than two students.

I'm stuck with the following questions (1,12,13, 15,16,17,24) and the rest, I finished them but I'm not sure.
Thank you and looking forward to hear your suggestions.

Hi and welcome to the forum!

This looks like a duty for me to be perfectly honest. When it's people are usually not willing to spoon feed answers because is not helping improve learning.

I'll try to help if you can show me what you have tried for the issues that you are having problems with.

Thank you!

Tags: Database

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    drwxr-xr-x 2 oracle dba 30 Sep 8 05:03 big

    drwxr-xr-x 2 oracle dba 30 Sep 8 05:03 little

    Please suggest alternatives to troubleshoot

    Thank you

    Sol.beach thanks for the reply, I'm able to correct the problem. In fact the PATH variable has put in .profile of export PATH = $PATH: $ORACLE_HOME/bin and the value is lower.

    -bash-3, $ 2 echo $PATH

    /Apps/Oracle/product/9.2.0.8.2009Q4/bin:/usr/ccs/bin:/usr/sbin:/usr/bin:/bin:.:/ bin:/opt/bin:usr/CSS/bin:/usr/ucb:/usr/local/bin:/apps/Oracle/product/11.2.0.3.2014Q3/bin

    I changed as export PATH = $ORACLE_HOME/bin: $PATH and now it works fine. It seems to be a problem with the old Oracle Home, also present in the PATH variable before the bin to the current address of Oracle Home Directory.

    -bash-3, $ 2 echo $PATH

    /Apps/Oracle/product/11.2.0.3.2014Q3/bin:/apps/Oracle/product/9.2.0.8.2009Q4/bin:/usr/ccs/bin:/usr/sbin:/usr/bin:/bin:.:/ bin: / opt/bin: css/usr/bin: / usr/ucb: / usr/local/bin

    Concerning

  • Database demo of vision: how to access the database through SQL * more?

    I'm totally new in this space, so forgive my beginner questions.

    What I want to do, is to integrate EBS with APEX. To get there I downloaded (of delivery) and installed the Vision database unique node in a VirtualBox. To do this, I followed this video on YouTube: https://www.youtube.com/watch?v=8JgxMDPsd6s

    Now I want to install APEX and for this I need to access my database as SYS. Now for my questions:

    1. How can I use SQL * more in the VirtualBox?

    2. What is the default password for SYS with this demo database?

    Thanks, Alex

    File under $ORACLE_HOME and the owner is the user 'oracle '.

    You will need to source the file VISION_ebs.env , and then deliver "env | fate"and you should see the set env variables. You can connect as sysdba.

    Thank you

    Hussein

  • Cannot access SQL more from other than the Oracle users

    Hello

    I installed Oracle 11 g R2 on Red Hat 6. My problem is that I can't access sqlplus from other than the oracle users.

    I put the PATH, the ORACLE_HOME and ORACLE_SID to the correct values.

    Session1

    Connect as: oracle

    [email protected] password:

    Last login: Sun Aug 24 01:24:46 192.168.202.1 2014

    [oracle@localhost ~] $ echo $PATH

    /usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin:/Home/Oracle/bin:/Home/Oracle/app/Oracle/product/11.2.0/dbhome_1/bin

    [oracle@localhost ~] $ echo $ORACLE_HOME

    /Home/Oracle/app/Oracle/product/11.2.0/dbhome_1

    [oracle@localhost ~] $ echo $ORACLE_SID

    ORCL

    [oracle@localhost ~] $ sqlplus

    SQL * more: Production release 11.2.0.1.0 Sun Aug 24 03:17:32 2014

    Copyright (c) 1982, 2009, Oracle.  All rights reserved.

    Enter the user name:

    Session2

    Connect as: nada

    [email protected] password:

    Last login: Sun Aug 24 02:31:49 192.168.202.1 2014

    [prithwish@localhost ~] $ export PATH=$PATH:/home/oracle/app/oracle/product/11.2.0/dbhome_1/bin

    [prithwish@localhost ~] $ export ORACLE_HOME=/home/oracle/app/oracle/product/11.2.0/dbhome_1

    [prithwish@localhost ~] $ export ORACLE_SID = orcl

    [prithwish@localhost ~] $ echo $ORACLE_HOME

    /Home/Oracle/app/Oracle/product/11.2.0/dbhome_1

    [prithwish@localhost ~] $ echo $ORACLE_SID

    ORCL

    [prithwish@localhost ~] $ echo $PATH

    /usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin:/Home/Prithwish/bin:/Home/Oracle/app/Oracle/product/11.2.0/dbhome_1/bin

    [prithwish@localhost ~] $ sqlplus

    -bash: sqlplus: command not found

    I guess that I could not access sqlplus as the Nada the user has no access to X11R6

    [prithwish@localhost ~] $ cd...

    [Host prithwish@localhost] $ ls - ltr

    Total 8

    drwx-. 30 oracle oinstall 4096 23 August 23:51 oracle

    drwx-. Nada Nada 4096 24 August to 02:33 27 Mathieu

    [Host prithwish@localhost] $

    My question is, although quite stupid, that double

    (1) I have to change the permissions of the directory oracle of 755 for any other user to access the sqlplus?

    (2) why is the user directory under the folder created with permissions of 700, even when the umask is set to 002? Change the permissions of the directory under/Home oracle will cause security problems?

    My apologies for being naïve. It's the first time I installed Oracle under UNIX

    Kind regards

    Prithwsh

    Actually, the default procedure is NOT to install oracle to X11R6, but in/opt/oracle. or maybe/usr/local/oracle.

    This is what you're going to be recommended in the installation documentation, and in doing so, don't forget to run rootpre.sh and root.sh, I never had security problems and could run Oracle from any account.

    Sybrand Bakker

    Senior Oracle DBA

  • Can I connect to SQL * more as SYS after connecting as a user and then run a GRANT?

    Oracle 11 g 2

    Linux RHEL 6.3

    SQL * Plus 11.2.0.2 on Windows 7

    ------------------------------------------------

    I am running a script SQL through SQL * more connected as "DOE, JOHN".

    In the SQL script, I need to connect as SYS to make a GRANT EXECUTE on a SYS package (e.g. GRANT EXECUTE ON DBMS_CRYPTO to JOHN;).

    But it fails with the following error:


    GRANT EXECUTE ON TO JOHN DBMS_CRYPTO
    *
    ERROR on line 1:
    ORA-01917: user or role 'JOHN' does not exist

    But of course, 'JOHN' are.  The rest of the SQL script is running "DOE, JOHN" without any problem.

    The code segment of SQL script in question is:

    connect sys/password as sysdba
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    to connect/DOE

    Please advise on what my being the issue.

    tx103108 wrote:

    I connect to a remote database.  All dbs distance have the same instance name as they are all images.  I see where you're going (I think).  Should I try

    I'll try to connect sys/password@MYDB

    Sounds like a plan... (the instance_name returned with what you expected? or something else?)

  • BECAUSE a node: when to stop through SQL * more...


    Hello

    I installed a CCR node for the first time and playing with it to get better knowledge. The underlying cluster has two nodes, call them the Node_A and node_b.

    The cluster database itself is called upon to DEVELOP, DEVELOP_1 instance is running on the node Node_A, instance DEVELOP_2 is supposed to work on node_b. The preferred node is

    NŒUD_A.

    When testing database online relcation everything works as expected: DEVELOP_1 instance Gets the stop on Node_A node - instance DEVELOP_2 is started on node_b.

    But what closing instance DEVELOP_1 on Node_A with SQL * more I was surprised of the result:

    -C' is not instance DEVELOP_2 which began on node_b - it was DEVELOP_1 for instance!  (Because of this my control sews has changed - but is not the issue of this discussion).

    Now my questions are:

    -is the clusterware responsible for the DEVELOP_1 instance on node_b startup behavior when I stop instance DEVELOP_1 down on Node_A via SQL * more?

    - and if this behavior is documented? I went through the RAC documentation node, but could not find something useful

    Any help will be appreciated.

    Rgds

    Jan

    Hi Jan,

    Yes, its expected behavior in a node of the FCAC, please consult the document below.

    "Oracle Real Application Clusters one node Overview" (Page 1) (relocation of the database online)

    http://www.Oracle.com/technetwork/products/Clustering/overview/TWP-rac1nodev1-1-130698.PDF

  • Privileges differ between SQL * more and stored procedure

    A user with the dba role can access dba_role_privs. But this is not possible in a stored procedure created by the same user.
    Normally, the example should work fine
    But with Oracle XE 11.02 - cost free database with some limitations - I get error 942

    I show a simple example in SQL * more:

    SQL > r
    1 * select distinct dba_role_privs recipient where the recipient as "SY %.

    DEALER
    ------------------------------
    SYSTEM
    SYS

    SQL > create or replace procedure x as
    2 start
    3 for rec in (select distinct dba_role_privs dealer where the beneficiary as 'SY %')
    4 loop
    5 zero;
    6 end of loop;
    7 end;
    8.

    Warnung: Prozedur wurde mit Kompilierungsfehlern standing.
    English translation: procedure created with compilation errors

    SQL > show error

    LINE/COL ERROR
    -------- -----------------------------------------------------------------
    3/14 PL/SQL: statement ignored
    3/43 PL/SQL: ORA-00942: table or view does not exist
    SQL >

    How can I fix?

    Why do you think the example should work properly?

    Normally, regardless of the version, the privileges granted through roles (such as DBA) not available for stored procedures. Stored procedure of a DEFINER rights can only take advantage of the privileges granted directly to the owner of the procedure. Stored procedure of the invoker rights can enjoy privileges granted by a role, but that requires that the appellant has independent privileges to query the table in question (and, in this case, would require dynamic SQL usage).

    Generally, the simplest approach would be to grant the privilege to CHOOSE ANY DICTIONARY to the owner of the procedure.

    Justin

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