const compilation error

Hello

If I declare a const, which is based on a value previously declared const I get a compilation error:

const int MY_INT_CONST1 = 10;  no error.
const int MY_INT_CONST2 = MY_INT_CONST1 + 10; compile error: initializer must be constant

I tried to search the Internet to see if this goes against ANSI-C, but did not find the relevant answer.

Anyone who knows and who have a source of information?

Thank you!

dml72

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Hello

As I remember, in ansi C, global variables must be initialized by constants.
So, we can write:
# define MYVAR 5
int a = MYVAR;
because the preprocessor replace MYVAR by 5 before compiling the sources.

But if we write
const int a = 1;
const int b = a;

We want to initialize b with the value of a, which is a global variable and the compiler should detect an error (declare a constant variable will generate a compiler error if the variable is reassigned to the program, but is still a variableand not a constant).

The same compilation error should appear if write us in the global section

int a = 1;

int b = a;

int c = myFunc ();

However in the locals, initialiseur initializer is not necessary to be consistent, so we can write

void myFunc (void) {}
const a = 1;
const b = a;
c const = myfunction2 ();
...
}

In summary, the keyword "const" is not the reason for this error, you can add or remove this keyword, the error will always be the same.

It is simply impossible to initialize a global variable with another variable as global variables are initialized before executing any statement.

Concerning

Etienne

Tags: NI Software

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