Converts a string to timestamp

Similar Questions

• [Oracle 8i] How to convert a string (timestamp) in a date?

  I find it difficult to know how to convert a string to a date time stamp (or possibly several).
  
  The timestamp is 20 positions, character (NOT NULL, CHAR (20))
  in the format: YYYYMMDDHHMMSSUUUUUU
  where Y = year, M = month, D = day, M = Minutes, S = seconds and U = microseconds
  
  The reason why I want to convert it is so that I can compare a timestamp to each other (that is, I want to be able to find the MIN (timestamp), MAX (timestamp) and make comparisons of inequality).
  
  Is this possible?
  
  Thanks in advance for the help on this!

  Hello

  As Damorgan said, if all you want to do is find which is the earlier or later, then you can just compare the strings: they are in a format where it works.

  If you need to do other things, such as compare to today date or see the difference between two of your lines of days, you will need to convert it to date. (He has no reason to convert them to numbers).

  A new TIMESTAMP data type, which manages the fractions of a second, was introduced in Oracle 9.
  Since you use Oracle 8 (depending on your subject line), or it must be
  (1) ignores the microseconds, or
  (2) use a separate column for microseconds.

  Whatever it is, use TO_DATE to convert the first 14 characters in DATE:

  TO_DATE ( SUBSTR (txt, 1, 14)
          , 'YYYYMMDDHH24MISS'
          )
  

  where txt is your column of type CHAR.
  To convert microseconds to a number (between 0 and 999999):

  TO_NUMBER (SUBSTR (txt, 15))
  

• String to timestamp

  Hello

  I searched for a while now and still have no answer.

  I'm trying to convert a string to a timestamp.

  I can't find the correct expression to retrieve the seconds and milliseconds.

  I tried %S, %u or even % 3u. It still does not work.

  Any idea.

  

  Hello

  Try the format (without the quotation marks) string "% < %a-%m-%j="" %="" h.%m.%s.%3u=""> T.

  In your example, you had a '%' too behind the "M", also I replaced the comma with another period.

  Greetings!

• Convert Formated date to TimeStamp?

  Hello

  How can I convert a string like '20090424 21:28:12 ' timestamp?

  I can't find the standard java SimpleDateFormat class and the blackberry version is not as even.

  How can I do this conversion?

  Thank you very much.

  If you mean by "Timestamp" milliseconds since the time (midnight 1970-01-01), I do it manually.

  First of all, I break the chain in the year of substrings, month, day, hour, minute, second. Then:

  Calendar c = Calendar.getInstance("UTC");
  c.set(Calendar.YEAR, Integer.parseInt(year));
  c.set(Calendar.MONTH, Integer.parseInt(month) - 1);
  c.set(Calendar.DAY_OF_MONTH, Integer.parseInt(day));
  c.set(Calendar.HOUR, Integer.parseInt(hour));
  c.set(Calendar.MINUTE, Integer.parseInt(minute));
  c.set(Calendar.SECOND, Integer.parseInt(second));
  long millisSinceEpoch = c.getTime().getTime();
  

  Note the - 1 in the month, JAVA months are 0-based.

  Note the "UTC" in Calendar.GetInstance (), without it, you would get a calendar for the local time zone (and midnight 1970-01-01 is not zero, may not matter to you).

  And of course, there could be a better way.

  Cheers, Barak.

• How to convert the string to a full decimal point and left shift

  Hey guys I tried to convert gps string to an integer, like this

  A string that is 2467.8976 and I need to convert it to a similar integer as point of this 2467.8979 so that I can shift the decimal point to the left (24.678979) which i coudnt do it with the chain. It's just been my 2 weeks with the labview so be gentle. Thank you

  Hi Awais07,

  Once you have created an indicator that signals the output of parsing the string, right-click on this indicator > display... Format > increase the value of the digit 9

  Kind regards

  Lennard.C

• Converts a string fragment file values

  Function wich use to convert the string fragment values?

  I have this string in the file:

  Instrument: NOR-DAQ; Date: 01-10-2008;
  Quantity: voltage [V];
  Results: 1.23,3.45,5.65,6.89,...;

  And I need to values - 1.23,3.45,5.65,6.89

  Hi crisdragon,

  You must use the native LabVIEW file and the string API.

  I gave you an example.

  Hope this helps.

• Convert the string with number of floats a number

  How to convert the string as "- 8.9E - 03" to a number of TestStand?

  Thanks in advance

  Hello

  Try to use the Val() function

  In the expression, it looks like this

  People of the country

  .nValue = val (Locals.strValue)

  Locals.nValue = Val("-8.9E-03")

  Hope this helps

  Jürgen

• convert a string to a path

  I want to assign a value to a global variable of the station (type: number) to the local variable (type: number).

  The problem is, that knowledge straight from the global variable of the station at the time of execution.

  I have a string like "StationGlobals.PARAMETER.SWITCH.xx.nRESISTOR_VALUE" - the characters 'xx' variable will be replaced when running...

  Now I want to convert this string to a path variable to assign to the local variable (type: number) the value of the global variable of the station (type: number)

  Do you know how I can do?

  Greetz

  Jonathan K.

  Try

  Locals.nCurrentResistorValue = Evaluate (Locals.sFunctionPath)

• How to convert the string with numbers in U8 with ascii

  Hello

  I have a string with only numbers 0. 9 paper.

  Now, I want to convert to table-U8.

  He works here, but now the problem: How can I change each character to its ascii value?

  Example:

  entry: 123 (string)

  output: x 31, x 32, x 33 (U8-array)

  Thanks for the help

  It's very easy

  String to Byte Array Function
  Have the Palette: string/array/path Conversion functions

  Converts a string to an array of unsigned bytes. Each byte in the array has the ASCII value of the character corresponding to the string.

• How do to convert the string (with the Hex data) in number?

  Hello

  I use TestStand 3.5 to automate a few test cases associated with boot loader.

  The requirement is that I need to read the value in some places for specific address. The values of these addresses are stored in a hexadecimal format.

  We have a step customized in TestStand through which we can read these values by address, but she returns as the type "String".

  For example, the value to 0 x 0000008 is 000001 B 2, and he returned in Locals.Value_Read as "000001 B 2" in the string.

  Is it possible, I can convert the string "000001 B 2" to a number?

  I tried to use the function-> val (locals. Value_Read), but it is return 0 as TestStand figures that the input string is not representing the valid number.

  Please help me with this.

  Thank you and best regards,

  Niraj.

  Try: Val ("0 x" + Locals.Value_Read)

• How to convert a string to byte array

  Hello

  I want to convert a string with a hexadecimal number in the array of bytes, this string includes a cutting-edge information, but I don't want to add this tip to arry bytes.

  detailed information please see the photo. I hope someone can give me some instructions, thank you very much.

  

  The accepted solution of Giedrius.S is not correct, based on the image shown in the first post. That the solution will not eliminate the spaces before the tip, and the string to byte array to convert individual characters '0', '8', 'space', '9', etc. for them to byte values. The right solution, based on the image below:

  

• Converts a string to a 32 long

  Hello, how to convert a string in the form of a figure with its real numerical value to format long32.

  Please see the attachment.

  Nevica

  There is a function "decimal string.

  

• Converts a string (float single precision) in decimal

  Hello

  I use reading series base and write vi to communicate with a device.  The answer I receive (shown in hexadecimal format) is 4606 8D3B, which from what I understand (this discussion: http://forums.ni.com/t5/LabVIEW/string-to-number-conversion-a-very-interesting-observation/m-p/32170... ) the data is not actually hexadecimal but rather binary and appears just hex for the user.

  My camera manual says that this information is "Float - 4-byte ANSII standard simple precision, low to high" and I'm trying to convert this string to a decimal value.  (it should be 0.004 or e-3 xx 4)  So far I've written a program that separates the bytes in a table of 4 bytes, each binary converts and then separate all binary bits and try to group return the binary bits in the exponent and the mantissa to calculate the value, but it seems rather convoluted and I hope that there is a more simple function in that all this is done automatically.  Also, since the answer is low to high, I understand that I must first return the number of 3B8D 0646 make high to low, but I think I did that already, it's just the conversion that I do not know how.

  Any help would be appreciated, thanks

  Alex

  Try this:

  

• 2 value sliders and convert to string

  Hi, I'm still new to labview.

  Can someone give me a snapshot or an image on how to extract 2 value of sliders & convert to string. And then I need to put the 2 values collected in the body of an email.

  Any help please?

  The Format based on the string grows downwards to take more than one entry.

  

• converting a string to some general engineering

  Hello world

  All know how to convert a string of engineering in a normal formatted string?

  Thank you

  Hi nem.

  in your vi there is no 'CH2-01. Do you mean "DAQ21"?

  See the attachment for a few minor changes (deleted sequence, its inhabitants, to build a better way). Why divide you your berries into 4 parts when you need to rebuild all the berries again?

  Are you sure this isn't a problem of formatting Excel? You set all the numbers in the excel worksheet to display in the form of "numbers"?

  When I try your vi I do not get any number in scientific format in Excel. (And I would say to transpose Excel import data...)