Convert the string with number of floats a number

Similar Questions

• How do to convert the string (with the Hex data) in number?

  Hello

  I use TestStand 3.5 to automate a few test cases associated with boot loader.

  The requirement is that I need to read the value in some places for specific address. The values of these addresses are stored in a hexadecimal format.

  We have a step customized in TestStand through which we can read these values by address, but she returns as the type "String".

  For example, the value to 0 x 0000008 is 000001 B 2, and he returned in Locals.Value_Read as "000001 B 2" in the string.

  Is it possible, I can convert the string "000001 B 2" to a number?

  I tried to use the function-> val (locals. Value_Read), but it is return 0 as TestStand figures that the input string is not representing the valid number.

  Please help me with this.

  Thank you and best regards,

  Niraj.

  Try: Val ("0 x" + Locals.Value_Read)

• How to convert the string with numbers in the table of Boolean 2D

  Hello

  I have input a string with comma separated numbers 1,192 (starting at 1).

  This string must be converted to a table 2D-boolean. Each number that appears should be true, not true rest.

  The 2D table consists of 4 times of 0.47 Boolean values.

  1.48--> [0.47] numbers [0]
  49.96--> [0.47] numbers [1]
  Numbers 97.144--> [0.47] [2]
  145.192--> [0.47] numbers [3]

  If a '1, 49, 97 145' input string put all [0] [0.3] true.

  How can it be easy/fast resolved?

  Thanks for help

  Break the string of numbers in a table of numbers.  (Spreasheet String to Array).

  In a loop For, index with each issue of this table.  Use in the range and Coerce to see if it is in the range of numbers.  (You can put this in a loop For as auto good indexing through the ranges).  If it's in the range, then use subset replace table to activate the corresponding item in a real.  If this is not the case, do nothing.  Maintain the table of Boolean in a shift register.

  Repeat this step for each number in your table.

  (What is a class assignment?)

• How to convert the string with numbers in U8 with ascii

  Hello

  I have a string with only numbers 0. 9 paper.

  Now, I want to convert to table-U8.

  He works here, but now the problem: How can I change each character to its ascii value?

  Example:

  entry: 123 (string)

  output: x 31, x 32, x 33 (U8-array)

  Thanks for the help

  It's very easy

  String to Byte Array Function
  Have the Palette: string/array/path Conversion functions

  Converts a string to an array of unsigned bytes. Each byte in the array has the ASCII value of the character corresponding to the string.

• Converts a string with period in full

  Hello, I am easily able to convert the string "24233" in full, but I am unable to convert '2313.213123' in full why? How can I make the parser recognize the period as a decimal?

  Thank you

  Noah NAKED

  Hey noahnu,

  I tried to do what you said and it worked fine on my end. Here is the code that I tested with:

  var txt:String = "2313.213123";
  
  var num:int = parseInt(txt);
  
  trace(num); // traces 2313
  

  are you trying to keep the decimal value as well? If so, try rather using the number object:

  var txt:String = "2313.213123";
  
  var num:Number = Number(txt);
  
  trace(num); // traces 2313.213123
  

  hope that helps. Good luck!

• Convert the string separated by commas in the rows

  Dear gurus,
  
  I want to convert the string separated by commas in the rows to insert in the collection.
  
  for example, the string 1234,2323,23232,2343,34234
  Higher up in the chain must be converted to ranks in order to insert into the table or the collection
  
  Thanks in advance
  Sanjeev

  String in rows separated to convert the comma.

  with t
  as
  (
  select '1234,2323,23232,2343,34234' as txt from dual
  )
  select REGEXP_SUBSTR (txt, '[^,]+', 1, level)
    from t
   connect by level <= length(regexp_replace(txt,'[^,]*'))+1
  

• How to concatenate the string with a digital command?

  Hello

  How to concatenate the string with a digital command?

  Thank you.

  

  I think I forgot to add the semicolon, what you can do is, drag the CONCATENATE function and add semicolon.

• How to convert numbers to the string with an optimal number of numbers?

  Hello.

  I'm doing something that seems just, and I wonder how much trouble I have with this.  I'm sure there is a way to get LabVIEW for this.

  I have a table of numbers (double), and I use the 'Worksheet picture String' function to generate a string that I can write to a file.

  The problem I have is I want to make the chain to omit useless zeros after the decimal point, but I don't want to limit the accuracy of the numbers that requires it.

  For example, if my data is as follows:

  0.02

  0.4476

  -0.0244570001

  I would like for the string I can be exactly like what I wrote above.  However, depeding on the format string that I use, that's what I get:

  format string: %.10f

  0.0200000000

  0.4476000000

  -0.0244570001

  format string: %f (it seems that by default 6 figures)

  0.020000

  0.447600

  -0.024457

  format string: %.4f

  0,0200

  0.4476

  -0.0244<= all="" trailing="" digits="" for="" this="" number="" have="" been="">

  Anyone know what the format string should be to get the string I want to (what is this

  0.02

  0.4476

  -0.0244570001

  Thanks in advance,

  Alejandro

  Hello Alejandro:

  Try %#f

• Problem with convert the string to date using DateTimeStringConverter

  Hello

  I would like convert string date (JJ/MM/AAAA) - it is useful to compare dates in TableColumns.

  so I use DateTimeStringConverter (the string "01/11/2014" is a value of date picker)

  DateTimeStringConverter format = new DateTimeStringConverter (Locale.FRANCE,

  "dd/MM/YYYY");

  Date d1 = format.fromString("01/11/2014");

  D1. ToString()

  "I do not get the right date, but that date =" Mon Dec 30 00:00:00 THIS 2013!

  I don't understand what the problem is (which in fact should not be a problem)?

  Any ideas?

  Thanks in advance

  Fabrice

  You have an error in the spec use format ' dd/MM/YYYY' instead of 'dd/MM/YYYY '.

  DateTimeStringConverter f = new DateTimeStringConverter(Locale.FRANCE, "dd/MM/yyyy");
  Date d1 = f.fromString("01/11/2014");
  System.out.println(d1.toString()); // --> Sat Nov 01 00:00:00 CET 2014
  

  If you do not need long, I would use DateStringConverter

• How to convert the string to a full decimal point and left shift

  Hey guys I tried to convert gps string to an integer, like this

  A string that is 2467.8976 and I need to convert it to a similar integer as point of this 2467.8979 so that I can shift the decimal point to the left (24.678979) which i coudnt do it with the chain. It's just been my 2 weeks with the labview so be gentle. Thank you

  Hi Awais07,

  Once you have created an indicator that signals the output of parsing the string, right-click on this indicator > display... Format > increase the value of the digit 9

  Kind regards

  Lennard.C

• convert the string ASCI spell

  The attached VI allows me to convert a single ASCII character to the spell.

  If I have a string of ASCII characters, I can convert them to break the string into individual characters and converting each individually then forming a chain again. Is there an easy way to convert a hexadecimal ASCII without analysis string?

  For example: CN1003001A (string ASCII) must be equal to 434E3130303330303141 (string hex).

  Thank you

  String to byte array, number in hexadecimal string Concantanate String.

  

• Replace the string with quouts

  Hi all

  I use the oracle version below:

  12 c Oracle database Release 12.1.0.1.0 - 64 bit Production

  PL/SQL Release 12.1.0.1.0 - Production

  CORE Production 12.1.0.1.0

  AMT for Linux: Version 12.1.0.1.0 - Production

  NLSRTL Version 12.1.0.1.0 - Production

  I have a string like:

  0,1,5,9,10,58... so now

  I need to convert the above string in form below:

  '0 ', '1', '2',' 3'... well now

  Here, I want to add quotes to open and closing of all the numbers that are separated by a comma.

  Select '0,1,2,3' double;

  but I pulled out as:

  '0 ', '1', '2',' 3'

  Here, there are a lot of numbers in a string, but all are separated by commas.

  Thank you

  something like:

  WITH the DATA (str) AS (SELECT ' 0,1,5,9,10,58' FROM dual)

  Select regexp_replace (str, '(\d+)', q '{' \1'}')

  from the data

  /

  ?

  HTH

• convert the string to type vCAC:vCACHost

  Hi all

  
  I have a client that wants to start a flood of vCO from an external source using the REST API of vCO. One of the arguments sent to the vCO workflow that will trigger, is the vCAC hostname.

  My question is - since the arguments acts as a channel of appeal REST, how to convert into a vCAC:vCACHost object in order to be used in a script in my stream.

  
  Thank you.

  Your customer can either pass a string representing the object to the REST API as described in this tutorial.

  Otherwise they can pass a string containing the host id and get the object vCACHost in the workflow like this:

  var vCACHosts = Server.findAllForType("vCACHost");
  
  for each (var vCACHost in vCACHosts) {
    if (vCACHosts.id==histId) {
     var matchingHost = vCACHosts;
    break;
    }
  }
  

  If there were many guests then I recommend using the entityManager to filter by ID and then by converting the entities back to object with the getInventoryObject() method as described in this article.

  1 problem, 3 solutions

• Problem with regexp_substr if the string with null values between commas.

  Hi all
  
  My version of DB is 10.1.0.5.0
  I want to extract the string values using query below, but I am unable to provide the correct result.
  

  WITH t  AS ( select '123,1,3,22' col FROM DUAL
          UNION ALL
          SELECT '123,,2,1' FROM DUAL
          UNION ALL
          SELECT '5,1,2,,' FROM DUAL
          ) 
  SELECT regexp_substr(t.col,'[^,]*',1,1)
        ,regexp_substr(t.col,'[^,]*',1,2)
        ,regexp_substr(t.col,'[^,]*',1,3)
        ,regexp_substr(t.col,'[^,]*',1,4) FROM DUAL,t   ;

  My required result as below.

  123     1      3      22
  123            2       1
  5       1      2        

  Please help me to get the required result by using regular expressions.
  Thanks, Ram

  Hello

  In Oracle 10, you can do so by combining REGEXP_SUBSTR with something else like RTRIM:

  SELECT     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 1), ',')     AS part_1
  ,     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 2), ',')     AS part_2
  ,     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 3), ',')     AS part_3
  ,     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 4), ',')     AS part_4
  FROM     t
  ;
  

  Starting Oracle 11 REGEXP_SUBSTR alone can do.

  But look at the first response; regular expressions will be probably less effective than less powerful features, especially when all channels have the same number of separators.

  Published by: Frank Kulash on 29 December 2012 08:36

• Basic question on the string-to-number conversion

  Hello
  
  I have a string, for example '23,2445,45'
  I want to extract the numbers of this string and put it in an array of numbers.
  
  Any keyword SQL is available. What is the best way to do it.
  
  Thank you
  MD

  Try this

  declare
  
  type vnum is varray(20)  of number;
  
  vnum1 vnum :=vnum();
  
  j number;
  
  begin
  
  j:= 1;
     for i in (
     with t as (
     select '23,2445,45' product_string from dual
     )
     SELECT   *
         FROM (SELECT
                      RTRIM(LTRIM(SUBSTR(product_string,
                                         INSTR(',' || product_string||',', ',', 1, n),
                                           INSTR(',' || product_string||',', ',', 1, n + 1)
                                         - INSTR(',' || product_string||',', ',', 1, n))),
                            ' ,') AS prod
                 FROM t,
                      (SELECT     ROWNUM n
                             FROM DUAL
                       CONNECT BY LEVEL < 10))
       WHERE prod IS NOT NULL)
       loop
  
       vnum1.extend;
       vnum1(j):= to_number(i.prod);
  
       dbms_output.put_line(vnum1(j));
  
       j:=j+1;
  
       end loop;
  
       end;
    
  

  vnum1 vnum: = vnum (0,0,0,0,0,0,0,0,0);

  I did it because I don't know how to initialize the array. Need to read more about it.

  This will put the values in the vnum1 table.

  If you need to do something with the numbers in the string

  so you can do the following without using a table.

  declare
  begin
     for i in (
     with t as (
     select '23,2445,45' product_string from dual
     )
     SELECT   *
         FROM (SELECT
                      RTRIM(LTRIM(SUBSTR(product_string,
                                         INSTR(',' || product_string||',', ',', 1, n),
                                           INSTR(',' || product_string||',', ',', 1, n + 1)
                                         - INSTR(',' || product_string||',', ',', 1, n))),
                            ' ,') AS prod
                 FROM t,
                      (SELECT     ROWNUM n
                             FROM DUAL
                       CONNECT BY LEVEL < 10))
       WHERE prod IS NOT NULL)
       loop
  
  -----Do what ever you want with the number.
  
       dbms_output.put_line(i.prod);
  
       end loop;
       end;
    
  

  Published by: alvinder on March 11, 2009 15:18

  Discovered how to initialize the array.