corresponding same string twice

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  Syn66,

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  Hello
  
  I had posted a question earlier before in the forum in lieu of the chain
  
  > >Delete Sting
  
  My requirement is user will pass the string that is mentioned below
  
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  logic for this query is it should return the string anything between [] another user that never enter it should return.
  
  Please suggest me
  
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  SELECT col1 FROM
  (
  with the data as
  (
  Select trim ('FID_28eff73b_125a3e651e2__7c26') double NECK
  )
  SELECT TRIM ('] ' OF REGEXP_SUBSTR (COL, ' [^ \] +', 1, 2])) COL1
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  Thank you
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  Published by: Sudhir_Meru on June 29, 2012 21:14

  This will work with the sample you provided...

  SQL> with t as
    2  (select 'SUCCESS[FID_28eff73b_125a3e651e2__7d76]' str from dual union all
    3   select '[FID_28eff73b_125a3e651e2__7d76]' str from dual union all
    4   select 'FID_28eff73b_125a3e651e2__7d76' str from dual )
    5  select str,case when str like '%[%]%'
    6                  then regexp_replace(str,'([^\[]?+\[)([^]]+)(].*?)','\2')
    7              else str
    8         end output
    9  from t;
  
  STR                                      OUTPUT
  ---------------------------------------- ----------------------------------------
  SUCCESS[FID_28eff73b_125a3e651e2__7d76]  FID_28eff73b_125a3e651e2__7d76
  [FID_28eff73b_125a3e651e2__7d76]         FID_28eff73b_125a3e651e2__7d76
  FID_28eff73b_125a3e651e2__7d76           FID_28eff73b_125a3e651e2__7d76
  

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  ....
  20                           15
  21                           15

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• Contains do not correspond to the same word twice

  I'm guessing that it won't work, but I'm the throw it out there anyway.
  
  I have a table of addresses where the indexed column consists of the city, a domain name optional, the street name and street number. For example "Stockholm Drottninggatan 2".
  
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  create index addressIndex on addressSearch(address)
  indextype is ctxsys.context
  /
  
  select * from addressSearch where contains (address, 'Stockholm AND (Stock% MINUS Stockholm)') > 0;
  

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