Count the items in the drop-down list by repeating the subform if the user selects "S/o".

Similar Questions

• How to pre-select an item in a drop-down list

  Hello

  I need to pre-select an item in a drop-down list, but I don't see how to achieve this using the current or existing methods.  I know that if I set the rawValue then it works, but later when I try to retrieve the data in the selected drop-down list the order of the day list, I get an 'empty' which does not help.  What he needs, is the value, the pair of label to work properly. When I manually select an item in the drop-down list, it works perfectly. But not when I try programtically set. So now I wonder if it is possible to set the index for the drop-down menu, so that he believes have a selected item, when I survey I get the correct value.

  Hope you can help.

  Kind regards

  Ian

  Hello

  You can use the selectedIndex property to set the desired value.

  And to retrieve a value, I recommend you to use *.getDisplayItem (*.selectedIndex);

  I hope this will help you!

• How to change the items in a drop-down list box that is part of an array of clusters

  Hello

  In the attached vi, I have an array of clusters and each cluster contains two drop-down list boxes. How can I edit the items in the drop-down list box 1 for all elements in the array? (All elements of list box 1 has the same elements.)

  By way of illustration, I have also included the case of trivila, for example, edit the items in a separate drop-down list box that is is not part of an array of clusters (combo box 3). Please notify. Thank you.

  Peter

  Right click on the drop-down list box and select Create-> Node-> String() property. Place it on the block diagram. Change to write (right click) and then feed him an array of strings.

• How to fill out a drop-down list on the selection of items in another drop-down list using adf 12.1.3

  Hello

  I have a page that has the load drop-down lists and a "submit" button. The first drop down menu got filled using query based VO (IE read only VO) for LOV. The requirement is as below

  -on the selection of an element any in the first drop-down list, the user must fill the second dropdown.

  -Once the second dropdown is completed, the user can select element in the second drop-down list.

  -capture the second drop down menu items value selected in the method of action of the click on the submit button.

  Any help in this scenario will be useful.

  ---

  Rabindranath

  Sameh salvation,

  Thanks for the reply. Your code

  1. DCIteratorBinding iter is BindingContext.getCurrent () .getCurrentBindingsEntry () .get ("iteratorNameInPageDef") (DCIteratorBinding);.
  2. Object secondDropdownValue = iter.getCurrentRow () .getAttribute ("AttributeName");  has been really helpful to get the selected value.

  Thank you very much.

  ---

  Rabindranath

• get the index of a selected item in a drop-down list box

  Hello

  If I have a list of strings in a drop-down list box and the user selects one in the drop-down menu, how can I get the index?  I was able to explore the table for the selected channel, but it seems like duplication of effort to create a list and then go back and research it.

  Thank you

  Brendon

  It's easier to change control of the ring or Enum which gives the index as a default value, a drop-down list box gives a string that must be converted. But if you like really graphic and you want to use the drop-down list you can uncheck the "use strings as values" option and enter the index as numbers and then make a string to Decimal conversion.

  /Y

• If statement to change the items in a drop-down list

  Is there a way to change the options in a drop-down list in a script (without data binding)? So I have a drop down list and depending on what the user selects the second drop-down list will have different options. These elements can be specified by an if statement in the preOpen the second dropdown list event? The form will be filled out offline, so I don't want to put a link of data binding.

  Thank you!

  Hello

  There are at least two ways, as shown in http://forums.adobe.com/message/4321707#4321707.  Basically clearItems/addItem if pre Reader 9.0 or setItems supported if you use Reader 9.0 or later.

  Bruce

• You can choose several items in a drop-down list?

  I was asked if it is possible to make a drop-down list in which two elements could be selected?  (as you want to choose colors gray and blue) Or it is limited to one per drop of water down)

  If so, how to set the drop-down for this button?

  I'm a newbie, be gentle.  Thank you.

  No, it is not possible with a drop-down list. You can do this by using a list box

  field, however.

  Tuesday, December 1, 2015 to 23:01, carlas70158474, [email protected]>

• Using a drop-down list to make a subform becomes visible/invisible

  I'm trying to do something simple... I can't work. I have a menu named 'property' (which is part, BECAUSE the BORROWER HAVE a PROPERTY INTEREST IN ANY OTHER GOOD? and I have choices 'Y' and 'n'.) When the user selects 'Y' I want the subform (which is currently invisible) named "sometimesHidden" to appear. Then, if the user selects "N" after that they have already selected 'Y' I want it to disappear. It's a Virgin with no O/N by default, just empty form. It turns out to be just... There is no need to pass anything... just appear and disappear.

  

  I tried to run on the 'Output' in JavaScript for menu drop-down mode. I tried to use other examples and nothing. Any help?

  Thank you!

  I got it to work by changing the save options from a static to a dynamic PDF PDF. I'm not a coder very decent, just, I went in the designer of the Action and created a show and hide Action on this article and it has worked very well. If I left it as a static PDF code show/hide and the Action never worked. Once I saved it as a PDF dynamic, it worked very well.

• What is the initial value of a drop-down list empty?

  I wrote a script to populate the items in a drop-down list but only if there is no existing entry.

  The problem I have is to acknowledge that the list is empty. I tried to test the value null (if dropdown.isNull = true) and test the

  rawValue = "" and a bunch of other things without good result.

  I don't know that it's easy, but apparently not for me.

  Thanks for the help!

  These commands to test the value selected by the user. As they have not chosen anything and yet they will not have a value.

  The command:

  DropDownList1.items.nodes.length

  This will give you the number of items in the DDlist. It is 1 based. Note that it will count all the elements that have been added to the drop-down list by the user.

  Paul

• Width of drop-down list and the number of drop-down list values

  How to increase / decrease the width of a drop-down list on the screen of your interview? In addition, how you increase the number of menu options drop-down user, some of my options in drop-down list don't show up. This shows only 3 points:...

  For OPM 10.4:

  Increase the number of visible items in a drop-down list

  There are two options:

  1. make a regular drop-down list instead of a list of drop-down list box. Regular drop-down lists always display all items, regardless of the length of the list. To do this, set "enable-search-comboboxes = false" in the appearance.properties file. "

  2. increase in the search results max for the combo box in the file appearance.properties, for example 'search max-results = 20' (or another number as appropriate)

  See article OPM the User Guide for more details: http://docs.oracle.com/html/E54499_01/toc.htm#Interviews%20and%20flows/Customize_Web_Determinations.htm#Change4

  I have a vague memory that the increase in the width of the drop-down lists is a bit more tedious. I'll take a look and post here...

  See you soon,.

  Jasmine

• Deletion of a single list in the drop-down list of choices

  Maybe I just don't see the simple solution, but how do I give a user the ability to simply remove his choice in a drop-down selection list. I have added a clear form button to clear all form data, but how do I allow the user once he or she has selected an item in a drop-down list to just go back and remove any choice of an element of the single drop-down list? Actually I think that this should be possible with all the elements of shape, right?

  With the "resetForm" javascript command, you can specify a single field or multiple fields to zero. Add this event to the button action and replace "Combo Box1" with the names of the fields that you want to reset:

  this.resetForm ("Combo Box1") / / resets only Combo Box1

  Alternatively, you can use one of the following conditions:

  this.resetForm (["Box1 Combo", "Box2 Combo"]) / / resets only Combo Box1 and Box2 Combo

  this.resetForm () / / resets the entire form

• Problem with the drop-down list related calculations

  Hi all

  I worked on a leave form using Adobe LiveCycle ES2 Design for more than three weeks. I am new to my work computer applications programming, and I've not had many world real experience with Javascript. My problem is that I have two drop-down lists in two separate subforms. I have a separate box for users to insert the number of hours of leave, they want to take next to each drop-down list. At the bottom of the form, I have a subform that I want to track the total number of hours for the type of leave, the users selected in the drop-down list.

  I tried several methods of JavaScript to FormCalc, but I succumbed to find a way to indicate each of my category of leave amounts to fields to reflect the value in field hours (this is... if the leave type list specifies the type of leave). I'm tired of scouring the Internet and books to see if I can find a viable solution to this subject. I have another issue to discuss with this same form regarding my case to add calculations, but he will have to wait until I am able to get this rectified issue. Can someone help me?

  

  The script necessary to each calculation of total field.

  The only thing different between them, it's the '6' is changed for each category (i.e. personal leave is '0'). FormCalc select in the script editor. It really works in your form - guaranteed!

  Older var = _IndvSubForm.count

  var totHrs = 0

  for i = 1 to older don't

  If (IndvSubForm [i-1]. DataDropDownList2 == "6") then

  totHrs is totHrs + IndvSubForm [i-1]. TotalHours2

  continue

  on the other

  continue

  endif

  ENDFOR

  $ = totHrs

  Good luck

  Stephen

• Change the background color of a table cell, depending on the selection in a drop-down list

  I have a drop-down list wrapped in a subform in a table cell. Users can choose green, yellow or red, and I want the background color to change according to their choice.

  Can you tell me why this script does not work? I'm sure that some of you, dear friends can see in a second.

  
  

  If (this. ListItem == "green") {}

  Subform1.DropDownList1.fillColor = "000,128,000"; BackgroundFill = "solid";

  }

  If (this. ListItem == 'yellow') {}

  Subform1.DropDownList1.fillColor = "255,128,000";

  }

  If (this. ListItem == 'red') {}

  Subform1.DropDownList1.fillColor = "255,000,000;

  }

  
  

  Thank you

  Hello

  I think you should be able to use the following code in the event change of the dropdownlist control.

  Form1. #subform [0]. Table1.row2.DropDownList1::change - (JavaScript, client)

  If {(xfa.event.change=="green)"}

  this.fillColor = "000,128,000";

  }

  If {(xfa.event.change=="yellow)"}

  this.fillColor = "255,128,000";

  }

  If {(xfa.event.change=="red)"}

  this.fillColor = "255,000,000;

  }

  Concerning

  Bruce

• Text of default list - see the HTML drop-down list as an indicator, no show in the list

  I would like to have the text of the 'selected option', 'COLOR' to be visible as a hint, but did not appear as a choice in the drop-down list.

  Existing code as follows:

  < select name = "color" id = "color" >

  < option selected = "selected" > COLOR < / option >

  < Option > BLACK < / option >

  < Option > COAL < / option >

  < / select >

  Thank you...

  Something like that...

  Choose a color

  Black

  Red

  Green

• Returns all the duplicate values in object lookup (PHP, drop-down list)

  Hi, I have a PHP page I designed as a search page. I have a number of drop-down lists that get their dynamic values from the fields in a MySQL database.

  At present, if there are any entries that have duplicate values in a certain area, they are all listed, in the order of the index database. For example:

  City:

  Derby

  Stoke

  Stafford

  Stoke

  Derby

  Derby

  Stoke

  etc...

  Now, I want to do is be able to show all results for a given city. In the find what drop-down list box, I would than each of the cities to appear only once rather than every time it is registered. included in this, I would like the page of results to then display ALL results that match this search criteria.

  Thus, in the example above, "Derby" appears only once, but when the user has selected 'Derby', it would return all three results in the results page.

  My results page is built on a dynamic form, so I am confident that the results page would make it according to the needs. However, how can I get the drop-down list box to ask him?

  > 'SELECT DISTINCT table1.champ1, table1.champ2, table1.champ3 FROM Table1 ";

  Duplicate rows to remove the DISTINCT keyword strength SQL. In other words, that it will only return the unique combinations of fields in your selection list. If you examine your results set, you will see that each line is separate, although there may be duplicates in a particular area. Because you want to populate a drop-down list, you must include a field in your select list only, otherwise you get of the dupes.