Create a new application of the place out to start other applications of APEX (APEX 4.2 or 5 APEX)
Hello
, I built 3 separate applications. Now I have to build another application with a list where to go out, I'll start other applications such as http://localhost: 8080/apex/f? p_104:1
When I do, I have to connect to the new application. How can I call this whithout application passing the username and password?
Thank you for your help.
Kind regards
Siegwin
Hi siegwin.port,
siegwin.port wrote:
In my child application I get this statement for post logout URL f? p = PORTAL: 1: & SESSION.
1 page is the home page of the main portal of the application where the application child out called
That won't happen. Reason: We maintain session state between applications using a Session Cookie. When you click the logout link in master/child applications, he is serving at the session of the APEX and the session cookie. As page 1 in the PORTAL application requires the user to be authenticated with valid session, where he re - directs you to the login page of the main application.
I want to go to this page without a new connection.
To do this rather than provide this URL to logout, create a new Navigation bar entry 'Application Switch' that redirects to the homepage of the main application.
If you go at the end of the blog entry, you will find the last section about the creation of "Home" and "Switch Application" navigation links.
Reference: maintain authentication between the APEX applications
I hope this helps!
Kind regards
Kiran
Tags: Database
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