Creating a function of hours
I am new to oracle and I need to create a function that will take two datestamp and then tell me how many hours are between these two dates.Opening hours are from 06:00 to 06:00 p.m., Monday to Friday.
For example: if my startdate is 20/07/2010-08:00 and at the end we day 2010-07-02 21:00. Total working hours will be 10 hours no 13.
Another scenario:
start date: 20/07/2010 03:00 and end 20/07/2010 06:01 hour. Total work hours are 1 min.
I have serious difficulty with that.
Thank you
Amir
Hi, Amir,
user10356209 wrote:
Frank,
THiiS is almost perfect. I see that the function is only the dates not accpeting datestamp.
I call the function with these parameters
Select Business_Hours double ((21 juillet 10 07.58.22 AM ', 21 juillet 10 07.58.22 AM'))and I get the following error
SQL error: ORA-01830: date format picture ends before converting all of the input string
01830 00000 - "date format picture ends before converting all of the input string.Any thoughts?
If the function expecects DATEs for the arguments, it does not pass strings.
One thing you can do is TO_DATE allows to convert the strings to DATEs:
Select Business_Hours ( TO_DATE ( '21-JUL-10 07.58.22 AM'
, 'DD-MON-RR HH.MI.SS AM'
)
, TO_DATE ( '21-JUL-10 07.58.22 AM'
, 'DD-MON-RR HH.MI.SS AM'
)
from dual;
If you are still calling the function with strings as arguments, no DATEs, and if the strings are always in the same format, then you could call TO_DATE function, or write a separate function which takes the strings as arguments:
CREATE OR REPLACE FUNCTION business_hours_s
( in_start_datestamp IN VARCHAR2
, in_end_datestamp IN VARCHAR2
)
RETURN NUMBER
DETERMINISTIC
IS
BEGIN
RETURN business_hours ( TO_DATE ( in_start_datestamp
, 'DD-MON-RR HH.MI.SS AM'
)
, TO_DATE ( in_end_datestamp
, 'DD-MON-RR HH.MI.SS AM'
)
);
END business_hours_s
;
It's literally the entire function; just a RETURN statement.
Leave the original function exactly as it is, with the arguments to DATE.
Tags: Database
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