Customer router how EasyVPN join two easy VPN servers?
I have a router in the branch with dynamic ip address, configured as a client of EasyVPN (network extension mode) needs to connect to both servers (two other branches with static Ip) Easyvpn,... is this possible? and how to do io?
On the HUB router, you can try without the isakmp profile:
Crypto-map dynamic dynmap 10
no set isakmp profile L2L
and also keep the following:
ISAKMP crypto cisco123 key address 0.0.0.0 0.0.0.0
Post edited by: Jennifer Halim
Tags: Cisco Security
Similar Questions
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How to join two fields with slightly different data
I have two columns, I need joined, both keep the columns of numeric data, but are of type varchar2 (6). The problem is that one of the columns keeps leading zeros to ensure that all 6 characters are used, but not the other. And columns preserve leading zeros may vary how many zeros are in the number-based computing.
For example, the column with zeros can contain the number 4200, which would mean that he would remain with 2 zeros as 004200. Or it could contain 320, which means that he would remain with 3 zeros as 000320.
The other column that does not have leading zeros not only keeps the number, so, in the example above, it would keep 4200 and 320 respectively.
Can someone help on how to join these columns so that they match? I guess I have to delete the zeros in one or add zeros in the other? I tried to use the trunc with zeros on the ground, but it did not work...
The following sql code:
M06.mbr06_prv_id has no zeros, prv647.provider_id zeros. See bold below...
SELECT
M06.mbr06_prv_id,
prv647.Site_ID
Of
Odw.mbr06_mbr_elig m06
JOIN THE
Odw.prv647_prov_exp prv647
WE
M06.mbr06_prv_id = prv647.provider_id
WHERE
M06.mbr06_subs_id = "999999999 '
BTW, I have no control on how this data is represented in a table... !Hello
user12296489 wrote:
... I guess I have to delete the zeros in one or add zeros in the other?Yes, this is how I see.
LTRIM removes given characters from the beginning of a string. LPAD adds characters at the beginning of a string. I would use LTRIM in this case, because if you use LTRIM, you probably need to handle a single column. If you use LPAD, you have to play with the two columns, as one of them still has the extra 0, and it sometimes needs them.I tried to use the trunc with zeros on the ground, but it did not work...
TRUNC is working on the kinds or DATEs; you have VARCHAR2s. You can convert them to numbers, but then you risk of errors to cause bad data (and it linked to the wrong data).
>The following sql code:
M06.mbr06_prv_id has no zeros, prv647.provider_id zeros. See bold below...
SELECT
M06.mbr06_prv_id,
prv647.Site_ID
Of
Odw.mbr06_mbr_elig m06
JOIN THE
Odw.prv647_prov_exp prv647
WE
M06.mbr06_prv_id = prv647.provider_id
WHERE
M06.mbr06_subs_id = "999999999 'If you are certain that m06.mbr06_prv_id never has extra characters, whereas the join condition can be
ON m06.mbr06_prv_id = LTRIM ( prv647.provider_id , '0' )
If this isn't the case, CUT then the two columns.
BTW, I have no control on how this data is represented in a table... !
Report a bad design is for people who don't have not this control. Numbers are the number of columns, not VARCHAR2. If the ID really needs to be strings, they should be validated and standardized once, when they are placed in the table, no more, and more, in all queries that use these columns.
I hope that answers your question.
If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all tables and also post the results desired from these data.
Explain, using specific examples, how you get these results from these data.
Always tell what version of Oracle you are using. -
How to join two tables of different schemas of Oracle by using a subquery
I'm trying to join two different schemas of Oracle tables using a subquery. I can extract data from each of the tables without problem. However, when I combine select statements it by using a subquery I get Oracle error *'ORA-00936: lack of expression ' *. Given that each SELECT statement runs on its own without error I don't understand what's missing. I'm trying to get the result set is matching the LINE_ID of PDTABLE_12_1 in the schema with the table PDTABLE_201 MAT_DESCRIPTION DD_12809 in the RA_12809 schema.
The query is as follows:
SQL = "SELECT [DD_12809]. [PDTABLE_12_1]. LINE_ID OF [DD_12809]. [PDTABLE_12_1] JOIN "_".
+ "(SELECT [RA_12809]. [PDTABLE_201]. MAT_DESCRIPTION "_".
"FROM [RA_12809]. [PDTABLE_201]) AS FAB "_".
+ 'ON [DD_12809]. [PDTABLE_12_1]. PIPING_MATER_CLASS = FAB. PIPING_MATER_CLASS ".
The format of the request is copied from a manual of programming SQL.
I also tried running the query uses a right JOIN on the two tables, but got the same results. Any ideas would be useful. Thank you!
Published by: user11338343 on October 19, 2009 06:55The format for the join of two tables in Oracle feels like any other database:
SELECT a.col1, a.col2, ..., b.col1, b.col2, ... FROM schema1.table1 a, JOIN schema2.table2 b ON a.col = b.col and ... WHERE a.other_col = 'FRED' AND ....;
Do not place bracketed identifiers in Oracle. The account that connects to the database must have select privileges on the two tables.
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How to join two tables if you transpose the rows, columns and rows in one of the table
Hi guys,.
can someone help me please in the write request
I have two tables
Agents and Agent phones but in the agent phones table for the id of an agent it displays 4 rows because one of the column there types of different phones (office, mobile, home, fax)
So instead of display 4 rows, I used max(case...) to convert rows to columns
now how to reach it with another table
Requirement:
Database: 11.2.0.2.0
create the table AGENT_PHONE
(
agent_id NUMBER (20) not null,
agent_type_code VARCHAR2 (10) not null,
agent_type_prefix VARCHAR2 (10) not null,
Phone_Number VARCHAR2 (16) not null,
phone_type_code VARCHAR2 (10) not null
)
CREATE TABLEAGENTS
(
agent_id NUMBER (20) not null,
agent_type_code VARCHAR2 (10) not null,
agent_type_prefix VARCHAR2 (10) not null,
NAME VARCHAR2 (40) NOT NULL
)
INSERT INTO AGENT_PHONE(AGENT_ID,AGENT_TYPE_CODE,AGENT_TYPE_PREFIX,PHONE_NUMBER,PHONE_TYPE_CODE)
VALUES (29709, ARE ', 'OFFICE', '4805551436', 'CELL');
INSERT INTO AGENT_PHONE(AGENT_ID,AGENT_TYPE_CODE,AGENT_TYPE_PREFIX,PHONE_NUMBER,PHONE_TYPE_CODE)
VALUES (29709, ARE ', 'OFFICE', '1111111111', 'PHONE');
INSERT INTO AGENT_PHONE(AGENT_ID,AGENT_TYPE_CODE,AGENT_TYPE_PREFIX,PHONE_NUMBER,PHONE_TYPE_CODE)
VALUES (29709, ARE ', 'OFFICE', '2223334444',' OFF');
INSERT INTO AGENT_PHONE(AGENT_ID,AGENT_TYPE_CODE,AGENT_TYPE_PREFIX,PHONE_NUMBER,PHONE_TYPE_CODE)
VALUES (29709, ARE ', 'OFFICE', '5556667788', 'FAX');
INSERT INTO VALUES AGENTS
(29709, ARE ', 'OFFICE', 'FLY');
INSERT INTO VALUES AGENTS
(1234, ARE ', 'OFFICE', 'MIKE');
SELECT * FROM AGENT_PHONES
AGENT_ID AGENT_TYPE_CODE AGENT_TYPE_PREFIX PHONE_NUMBER PHONE_TYPE_CODE ---------------------------------------------------------------------------------------------
29709 RE OFFICE 4805551436 CELL 29709 RE OFFICE 1111111111 PHONE 29709 RE OFFICE 2223334444 OFF 29709 RE OFFICE 5556667788 FAX
SELECT * AGENTS
AGENT_ID AGENT_TYPE_CODE AGENT_TYPE_PREFIX NAME
29709 RE OFFICE ROB 1234 RE OFFICE MIKE
This is so the data we have in both table
Now, I transposed rows to columns in the table of agent phones so I used the following query
SELECT AP. AGENT_ID,. AGENT_TYPE_CODE,. AGENT_TYPE_PREFIX.
MAX (CASE WHEN AP. PHONE_TYPE_CODE = 'CELL' THEN AP. PHONE_NUMBER END) AS CELL.
MAX (CASE WHEN AP. PHONE_TYPE_CODE = 'OFF' THEN AP PHONE_NUMBER END) AS TURNED OFF.
MAX (CASE WHEN AP. PHONE_TYPE_CODE = 'FAX' THEN AP. PHONE_NUMBER END) LIKE FAX,.
MAX (CASE WHEN PHONE_TYPE_CODE = 'PHONE'. THEN AP PHONE_NUMBER END) AS PHONE
AGENT_PHONE AP
WHERE AP. AGENT_ID = 29709
GROUP OF AP. AGENT_ID, AP. AGENT_TYPE_CODE, AP. AGENT_TYPE_PREFIX.
AGENT_ID AGENT_TYPE_CODE AGENT_TYPE_PREFIX CELL OFF FAX PHONE 1 29709 RE OFFICE 4805551436 2223334444 5556667788 1111111111 My question is how this to join the agents table so that my output should be like this...
I want to display all the results in the table of the Agent, even if they are not in the table of agent phones. As you can see there are other agent id 1234 is also populated
AGENT_ID AGENT_TYPE_CODE AGENT_TYPE_PREFIX NAME AGENT_ID AGENT_TYPE_CODE AGENT_TYPE_PREFIX CELL PHONE OFF FAX --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
29709 RE OFFICE ROB 29709 RE OFFICE 4805551436 1111111111 2223334444 5556667788 1234 RE OFFICE MIKE Currently, I run this query and I get the output as below
SELECT *.
AGENTS HAS
LEFT OUTER JOIN AGENT_PHONE AP
ON A.AGENT_ID = AP. AGENT_ID
AND A.AGENT_TYPE_CODE = AGENT_TYPE_CODE.
AND A.AGENT_TYPE_PREFIX = AGENT_TYPE_PREFIX.
AGENT_ID AGENT_TYPE_CODE AGENT_TYPE_PREFIX NAME AGENT_ID AGENT_TYPE_CODE AGENT_TYPE_PREFIX PHONE_NUMBER PHONE_TYPE_CODE 1 29709 RE OFFICE ROB 29709 RE OFFICE 4805551436 CELL 2 29709 RE OFFICE ROB 29709 RE OFFICE 1111111111 PHONE 3 29709 RE OFFICE ROB 29709 RE OFFICE 2223334444 OFF 4 29709 RE OFFICE ROB 29709 RE OFFICE 5556667788 FAX 5 1234 RE OFFICE MIKE I want id 29709 agent in a line with 1234 agent also id to display
You can rotate your phone number of agent in columns
Select *.
of AGENT_PHONE
pivot)
min (PHONE_NUMBER)
for PHONE_TYPE_CODE in ('CELL' as a 'CELL', 'PHONE' like 'PHONE', 'OFF' in the 'OFF', 'FAX' as 'FAX')
)
AGENT_ID AGENT_TYPE_CODE AGENT_TYPE_PREFIX CELL PHONE OFF FAX 29709 RE OFFICE 4805551436 1111111111 2223334444 5556667788 Then you can join to view inline or CTE
with AGENT_PHONE_PIVOT like)
Select *.
of AGENT_PHONE
pivot)
min (PHONE_NUMBER)
for PHONE_TYPE_CODE in ('CELL' as a 'CELL', 'PHONE' like 'PHONE', 'OFF' in the 'OFF', 'FAX' as 'FAX')
)
)
SELECT *.
AGENTS HAS
LEFT OUTER JOIN AGENT_PHONE_PIVOT AP
ON A.AGENT_ID = AP. AGENT_ID
AND A.AGENT_TYPE_CODE = AGENT_TYPE_CODE.
AND A.AGENT_TYPE_PREFIX = AGENT_TYPE_PREFIX.
AGENT_ID AGENT_TYPE_CODE AGENT_TYPE_PREFIX NAME AGENT_ID AGENT_TYPE_CODE AGENT_TYPE_PREFIX CELL PHONE OFF FAX 29709 RE OFFICE ROB 29709 RE OFFICE 4805551436 1111111111 2223334444 5556667788 1234 RE OFFICE MIKE - - - - - - - Is that what you're looking for?
-
Hello
I want to join the two tables to retrieve the data from the columns of the two table passing parameters to the join query. Tables have primary and foreign key relationships
Details of the table
Alert-1 - AlertCode (FK), AlerID (PK)
2 AlertCode-AlertDefinition-(PK)
Help, please
----------
Hi Vincent,.
I think that you have not worked on adf 12.1.3. In adf 12.1.3 you don't have to explicitly create the association. When you create the EO to your table, Association xxxxFkAssoc, will be created by ADF12.1.3 for you automatically. Please try this and do not answer anything... You can also follow the links below. I solved the problem by using the following link
---
-
How to join two parallel identification relationships?
I have four entities A, B, C and D with the following identification relationships:
A <-b
A <--C
B <-d
C <-d
A has a unique primary key HELP. B and C have their own primary keys SUBMISSION and CID and the primary foreign keys for the primary key of the a. So the primary keys of B and C are (SUBMISSION, HELP) and (CID, HELP). D has its own primary key DID and primary and foreign to B and C keys. So the primary key of D is (, (SUBMISSION, HELP), (CID, AID)). As you can see the primary key of A appears twice in the primary key of D, because of two relationships Parallels identification.
Now I want two aides in the primary key of D are identical. The primary key of D should be a four tuple (SUBMISSION, CID, DID, HELP).
How can I Express that in the logic model of the Data Modeler?
What I've tried so far: I designed the logic model in a physical model and changed there a parallel relations. I changed the child column associated with the redundant reference to HELP the other. After that data Modeler asked me to remove the column created automatically, which is not a reference more. This seems to be a solution for the physical model.
But: there seems to be not possible for this model in the logic model directly nor is engineer possible changes to the physical return to the logical model.
So, what can I do?
I asked this question with some names of more concrete variables to stackoverflow:
http://StackOverflow.com/q/13027950/402322
And this is the physical model after the change explained above:
https://picasaweb.Google.com/LH/photo/TCeW1Si0UOybltn34oIWj9MTjNZETYmyPJy0liipFm0Hello
You must play with attributes that overlap / folding. Open the properties of the D entity dialog box, go to 'Overlap attributes' page - you should see help-ecosystems1 pair listed. Check the "fold" checkbox. Ecosystems1 attribute will remain in the entity, but there will be no column associated with the relational model after engineering before him. You can change your decision during the direct engineering - data Modeler detects existence of keys that overlap and dialogue engineering position on related tab.
Philippe
-
How to join two tables without constraints?
I want to get back the tables to join without constraints!
Table 1:
get 100
101 wet
series 102
and
Table 2:
10 xxx movies
11 yyy
12 zzz
QUERY 1:
SELECT * FROM TO LEAVE P, CUSTES C
WHERE (P.ID, P.NAME, C.ID, C.NAME) IN (SELECT P1.ID, P1.NAME, C1.ID, C1.NAME
OF P1, C1 CUSTES TO GO)
I got the result like this,
ID ID NAME
101 wet 10 xxx
zzz 101 wet 12
YYY 101 wet 11
Get 100 10 xxx
102 the yyy 11 value
series 102 10 xxx
100 get 11 yyy
100 get 12 zzz
102 the value 12 zzz
All ranks was sent three times! but I need to write once.
QUERY 2:
Select id as pid, name as the name of go
Union
Select id as pid, name as the name of custes;
QUERY2 OUTPUT IS.
NAME OF PID
10 xxx movies
11 yyy
12 zzz
get 100
101 wet
series 102
In the 2nd query get the attached files of the two tables. But my need is two tables record to display like this
ID NAME NAME_1 ID_1
Get 10 xxx 100
wet 11 101 yyy
set of 12 zzz 102
I'm looking for is, I want to join in parallel columns in my trips!
Is there a source... ? or the same code is happy...!Something like that?
WITH t1 AS (SELECT '100' id, 'get' name FROM DUAL UNION SELECT '101', 'wet' FROM DUAL UNION SELECT '102', 'set' FROM DUAL), t2 AS (SELECT '10' id, 'xxx' name FROM DUAL UNION SELECT '11', 'yyy' FROM DUAL UNION SELECT '12', 'zzz' FROM DUAL) SELECT id, name, (SELECT id FROM (SELECT ID, name, ROWNUM rw FROM t2) t_in WHERE t_in.rw = t_out.rw) id_1, (SELECT name FROM (SELECT ID, name, ROWNUM rw FROM t2) t_in WHERE t_in.rw = t_out.rw) name_1 FROM (SELECT ID, name, ROWNUM rw FROM t1) t_out
SQL> WITH t1 AS (SELECT '100' id, 'get' name FROM DUAL 2 UNION 3 SELECT '101', 'wet' FROM DUAL 4 UNION 5 SELECT '102', 'set' FROM DUAL), 6 t2 AS (SELECT '10' id, 'xxx' name FROM DUAL 7 UNION 8 SELECT '11', 'yyy' FROM DUAL 9 UNION 10 SELECT '12', 'zzz' FROM DUAL) 11 SELECT id, 12 name, 13 (SELECT id 14 FROM (SELECT ID, name, ROWNUM rw FROM t2) t_in 15 WHERE t_in.rw = t_out.rw) 16 id_1, 17 (SELECT name 18 FROM (SELECT ID, name, ROWNUM rw FROM t2) t_in 19 WHERE t_in.rw = t_out.rw) 20 name_1 21 FROM (SELECT ID, name, ROWNUM rw FROM t1) t_out; ID NAME ID_1 NAME_1 --- --- -- --- 100 get 10 xxx 101 wet 11 yyy 102 set 12 zzz SQL>
The number of rows in the tables are the same?
-
How to join two sources of data tables
Initially, I had these tables in a data source, and so had the tables attached as follows:
< name cfquery = "getComments" datasource = "#application.dsn #" >
SELECT a.id, a.rideComment, b.firstName, b.middleName, b.lastName, b.nickName, b.showName
OF rideComments an a.riderId = b.id ON LEFT JOIN tUser b
WHERE rideId = #rideInfo.rideId #.
ORDER BY a.id
< / cfquery >
But I recently needed to divide my datasource and both tables got divided into differenct datasources. So, how 'join' them now?
< cfquery name = "getComments" datasource = 'revolution' >
SELECT id, rideId, rideComment
OF rideComments
ORDER BY id
< / cfquery >
< cfquery name = "getComments' datasource 'members' = >
SELECT firstName, middleName, lastName, nickname showName
OF tUser
< / cfquery >This approach is to a query of queries. Run your queries and then use a t/t to join them:
SELECT * from [user]
SELECT * [ROLE]
SELECT *.
OF qryUsers, qryRoles
WHERE qryUsers.roleId = qryRoles.id
-
How to join two pictures together in a Photo on macbook
I can't move pictures from one album to another on the Photos on my Macbook help!
I asked that your message be passage to:
-
How to attach two photos with window live photoshop
How to join two or more pictures with window live photoshop... Please tell me...
Hi puneetdeol,
Thanks for posting your question in the Microsoft answers Forum. For any questions about Windows Live Photo Gallery, please visit the following link:
http://windowslivehelp.com/forums.aspx?ForumID=cafb0556-8959-49b9-AFEB-635314aa02f3
-
Hello.
Could someone show me how to join two lines created with the tool online CC animate so that there is a sharp at the join point. I'm not sure to do that.
For example if I two0 lines like this:
I don't know how to join them so that they look like this:
Thanks for the tips on how to achieve this.
Just make sure that they are joined first, take the point and move it to make sure that the two lines move, if they are well hung. If this is not the case, turn on wink, view-> serpentine--> object snap. And then drag one of the points to each other, you will feel it pull the other point.
Then, all you have to do is choose how they are joined from the line Options Panel.
Replace your line ends Sqaure and the type of join to Mitre and then adjust the Guide tab to get the desired, desired point.
-
How to put all through traffic the easy vpn client VPN server
Hi people
I want to ask you, how to put all of the server the easy vpn client VPN traffic through.
I mean, I have a server vpn at home, and if I connect to the vpn from outside server, to be with an IP address of my home.
There is the configuration up to now. Where is the problem?
ROUTER1 #sh running-config
Building configuration...
Current configuration: 5744 bytes
!
! Last configuration change at 19:51:18 UTC Wed Sep 4 2013 by cska
!
version 15.1
horodateurs service debug datetime msec
Log service timestamps datetime msec
no password encryption service
!
ROUTER1 hostname
!
boot-start-marker
usbflash0:CVO boot-BOOT Setup. CFG
boot-end-marker
!
!
!
AAA new-model
!
!
AAA authentication login ciscocp_vpn_xauth_ml_1 local
AAA authorization ciscocp_vpn_group_ml_1 LAN
!
!
!
!
!
AAA - the id of the joint session
!
Service-module wlan-ap 0 autonomous bootimage
Crypto pki token removal timeout default 0
!
Crypto pki trustpoint TP-self-signed-1604488384
enrollment selfsigned
name of the object cn = IOS - Self - signed - certificate - 1604488384
revocation checking no
!
!
TP-self-signed-1604488384 crypto pki certificate chain
certificate self-signed 01
3082022B 30820194 02020101 300 D 0609 2A 864886 F70D0101 04050030 A0030201
2 060355 04031326 494F532D 53656 C 66 2 AND 536967 6E65642D 43657274 31312F30
69666963 31363034 34383833 6174652D 3834301E 170 3133 30383239 31313539
32395A 17 0D 323030 31303130 30303030 305A 3031 06035504 03132649 312F302D
4F532D53 5369676E 656C662D 43 65727469 66696361 74652 31 36303434 65642D
38383338 3430819F 300 D 0609 2A 864886 01050003, 818, 0030, 81890281 F70D0101
8100CD 57 F1436ED2 8D9E8B99 B6A76D45 FE56716D D99765A9 1722937C F5603F9F
528E27AF 87A24C3D 276FBA1C A5E7C580 CE99748E 39458C 74 862C 2870 16E29F75
7A7930E1 15FA5644 D7ECF257 BF46C470 A3A17AEB 7AB56194 68BFB803 144B7B10
D3722BDD D1FD5E99 8068B77D A1703059 9F0578C7 F7473811 0421490D 627F25C5
4 HAS 250203 010001A 3 53305130 1 130101 FF040530 030101FF 301F0603 0F060355
551 2304 18301680 141B 1326 C111DF7F 9F4ED888 EFE2999A 4C50CDD8 06 12301
03551D0E 04160414 1B1326C1 11DF7F9F 4ED888EF E2999A4C 50CDD812 300 D 0609
2A 864886 04050003 81810096 BD0C2B16 799DB6EE E2C9B7C4 72FEAAAE F70D0101
FF87465C FB7C5248 CFA08E68 522EA08A 4B18BF15 488D D53D9A43 CB400B54 8006
CB21BDFB AA27DA9C C79310B6 BC594A7E D6EDF81D 0DB7D2C1 9EF7251B 19A 75403
211B1E6B 840FE226 48656E9F 67DB4A93 CE75045B A986F0AD 691EE188 7FB86D3F
E43934FA 3D62EC90 8F37590B 618B0C
quit smoking
IP source-route
!
!
!
!
CISCO dhcp IP pool
import all
network 192.168.1.0 255.255.255.0
DNS-server 195.34.133.21 212.186.211.21
default router 192.168.1.1
!
!
IP cef
No ipv6 cef
!
Authenticated MultiLink bundle-name Panel
license udi pid CISCO892W-AGN-E-K9 sn FCZ1530C209
!
!
username privilege 15 secret 5 cska $1$ $8j6G 2sMHqIxJX8MQU6vpr75gp1
!
!
!
!
!
!
crypto ISAKMP policy 1
BA 3des
preshared authentication
Group 2
!
Configuration group customer isakmp crypto VPNGR
vpngroup key
DNS 212.186.211.21 195.34.133.21
WINS 8.8.8.8
domain chello.at
pool SDM_POOL_1
ACL 120
netmask 255.255.255.0
ISAKMP crypto ciscocp-ike-profile-1 profile
match of group identity VPNGR
client authentication list ciscocp_vpn_xauth_ml_1
ISAKMP authorization list ciscocp_vpn_group_ml_1
client configuration address respond
virtual-model 1
!
!
Crypto ipsec transform-set esp-SHA-ESP-3DES-3des esp-sha-hmac
!
Profile of crypto ipsec CiscoCP_Profile1
security association idle time 86400 value
game of transformation-ESP-3DES-SHA
set of isakmp - profile ciscocp-ike-profile-1
!
!
Bridge IRB
!
!
!
!
interface Loopback0
192.168.4.1 IP address 255.255.255.0
IP nat inside
IP virtual-reassembly in
!
interface BRI0
no ip address
encapsulation hdlc
Shutdown
Multidrop ISDN endpoint
!
interface FastEthernet0
!
interface FastEthernet1
!
interface FastEthernet2
!
interface FastEthernet3
!
interface FastEthernet4
!
interface FastEthernet5
!
FastEthernet6 interface
!
interface FastEthernet7
!
interface FastEthernet8
no ip address
Shutdown
automatic duplex
automatic speed
!
type of interface virtual-Template1 tunnel
IP unnumbered Loopback0
ipv4 ipsec tunnel mode
Tunnel CiscoCP_Profile1 ipsec protection profile
!
interface GigabitEthernet0
Description Internet
0023.5a03.b6a5 Mac address
customer_id GigabitEthernet0 dhcp IP address
NAT outside IP
IP virtual-reassembly in
automatic duplex
automatic speed
!
wlan-ap0 interface
description of the Service interface module to manage the embedded AP
192.168.9.2 IP address 255.255.255.0
ARP timeout 0
!
interface GigabitEthernet0 Wlan
Description interface connecting to the AP the switch embedded internal
!
interface Vlan1
no ip address
Bridge-Group 1
Bridge-Group 1 covering-disabled people
!
interface BVI1
IP 192.168.1.1 255.255.255.0
IP nat inside
IP virtual-reassembly in
!
local IP SDM_POOL_1 192.168.4.3 pool 192.168.4.245
IP forward-Protocol ND
!
!
IP http server
local IP http authentication
IP http secure server
overload of IP nat inside source list 110 interface GigabitEthernet0
IP nat inside source static tcp 192.168.1.5 3389 interface GigabitEthernet0 3389
IP nat inside source static udp 192.168.1.5 3389 interface GigabitEthernet0 3389
IP nat inside source static tcp 192.168.1.5 21 interface GigabitEthernet0 21
IP nat inside source static udp 192.168.1.5 21 interface GigabitEthernet0 21
IP nat inside source static tcp 192.168.1.4 3389 interface GigabitEthernet0 3390
IP nat inside source static udp 192.168.1.4 3389 interface GigabitEthernet0 3390
overload of IP nat inside source list 120 interface GigabitEthernet0
IP route 0.0.0.0 0.0.0.0 dhcp
!
exploitation forest esm config
access list 101 ip allow a whole
access-list 110 permit ip 192.168.1.0 0.0.0.255 any
access list 111 permit tcp any any eq 3389
access-list 120 allow ip 192.168.4.0 0.0.0.255 any
!
!
!
!
!
!
!
control plan
!
Bridge Protocol ieee 1
1 channel ip bridge
!
Line con 0
line 2
no activation-character
No exec
preferred no transport
transport of entry all
transport output pad rlogin udptn ssh telnet
line to 0
line vty 0 4
privilege level 15
preferred transport ssh
entry ssh transport
transportation out all
!
Thanks in advance
To do this you must make the following changes:
(1) disable split Tunneling by deleting the ACL of your configuration of the client group.
(2) enable NAT for VPN traffic by adding 'ip nat inside' to your virtual model of the client network to the ACL that controls your PAT.Edit: Theses are the changes to your config (also with a little cleaning):
Configuration group customer isakmp crypto VPNGR
No 120 LCD
!
type of interface virtual-Template1 tunnel
IP nat inside
!
no nat ip inside the source list 120 interface GigabitEthernet0 overload
!
access-list 110 permit ip 192.168.4.0 0.0.0.255 any
no access-list 120 allow ip 192.168.4.0 0.0.0.255 any
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Easy VPN between two ASA 9.5 - Split tunnel does not
Hi guys,.
We have set up a site to site vpn using easy configuration vpn between ver 9.5 race (1) two ASA. The tunnels are up and ping is reached between sites. I also configured split tunnel for internet traffic under the overall strategy of the ASA easy vpn server. But for some unknown reason all the customer same internet traffic is sent to the primary site. I have configured NAT to relieve on the side of server and client-side. Please advise if no limitation so that the installation program.
Thank you and best regards,
Arjun T P
I have the same question and open a support case.
It's a bug in the software 9.5.1. See the bug: CSCuw22886
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Routing between the easy VPN clients
I have easy installation of multiple ASA5505 as VPN clients connecting to a single ASA5510 and can route packets between client subnets easy 5505. Anyone has the clues, how?
Thank you!
You must add the below to the 5510: -.
permit same-security-traffic intra-interface
HTH >
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