DataPump - expdp.open creates tables in the schema

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• Creating table in the schema has with the user B and granting permissions to the user C

  Hello, I have a problem fun - we have a large table which requires a batch to make millions of updates, and he needs to finish more quickly. It takes several hours as an update, but a select create table did the same thing in about a minute. Yay! Then we just delete the old table and rename the new table to the former, rebuild all the index and grant select/insert/update/delete permissions to another user who needs access... and there is the problem, Oracle said insufficient privs.
  
  We have A figure, which is the owner of the table, userid B who done all the stuff of application batch and userid C which performs inserts for a process of middleware. None of them are actual users, of course. We want that user B to do the ETG, rename, rebuild and re-grant of the authorisation of the index. But user B apparently cannot grant permissions on objects in the schema A to user C, even if B has created the table and has the role DBA (not ideal, I know)!
  
  What's really crazy is that there is no sense unique user b can grant permissions to user C, which is to:
  
  grant select any table USER c;
  grant insert any table USER c;
  grant update any table USER c;
  Grant delete any table USER c;
  
  It seems really perverse can create tables in diagram A and even grant C privs "whole table" that user B, but may not grant privs specifically on this object in the schema A, even with DBA privs. I must be missing something... right?

  Yes. By default, the stored procedures are stored procedures from DEFINER rights. If A is the owner of a stored procedure, this stored procedure can do whatever A enjoys the privileges to directly. If A grants B privileges RUN this stored procedure, when B calls the stored procedure, the procedure runs with the privileges.

  I agree point stew, however, re-creating objects in Oracle is generally a bad idea and a TRUNCATE with one insert direct-path, possibly combined with the deactivation and the rebuilding of the index would be more appropriate than a DEC. If you're going to stick with this Assignment, however, that really do in a stored procedure owned by A while B has no need to CREATE ANY TABLE.

  Justin

• avoid triggers on all tables in the schema

  I need to put a CREATION TIMESTAMP to the timestamp of the database server (not the timestamp of session) in all tables in a schema to create and update. Is to create a trigger on all the tables in the schema a less time consuming way to do?
  
  Similarly, I need to set up columns such as CREATE_USER, LAST_UPDATE_USER.
  
  Thank you in advance.

  You can easily generate the DDL for adding new columns.

  The extent of the filling of the columns, your choice is either to use insertion befire table and triggers to update to fill the columns or the application to provide the necessary information.

  Basic trigger logic would be pretty much the same for all tables, then write a little SQL or PL/SQL to generate the code of the trigger should be simple enough.

  Depending on your application, such as web based with only one Oracle user, you may need to get the real user through dbms_application_info by the logic of the server-based application.

  HTH - Mark D Powell.

  Edited by: Mark D Powell 5 May 2010 07:48

• create table in the remote database

  Hi friends,
  
  Is it possible to create a table in a remote with the syntax as database
  
  create table - on the remote database
  in select * from tbl - table with user defined data types.
  
  Thank you
  Akila Mathon.

  Remote DDL operations are not allowed.

  Create a procedure on the remote database, which will create the table using

  execute immediate 'Create table table_1 as select * from table@remote_link '
  
  Example
   create procedure ddl_remote(str varchar2)
   as
   begin
     execute immediate str ;
   end ;
   /
  

  Where remote_link is the database when you call the procedure.

  Directly GRANT EXECUTE CREATE TABLE to the user in which the procedure is created.

  Call the procedure of your current database.

  begin
     ddl_remote@DB_remote('create table emp as select * from emp@remote_link ') ;
  end ;
  /
  

  HTH
  SS

• How to delete all TABLEs in the schema SYS that are created from 09:15?

  Unfortunately a script created a lot of tables in the diagram (= SYS) and bad Tablespace (= SYSTEM).
  
  How can I delete all TABLES that are created inTablespace = SYSTEM and SCHEMA = SYS (in a DDL command)
  respectively for the past 3 hours from 09:15 to 25 Sep 2011?
  
  Alternative: How can I move these tables in another schema (for example ATEST) and Tablespace (USERS)?
  Is this possible with Oracle XE or Oracle Enterprise?
  
  Peter

  You can use ALTER TABLE... MOVE. It offers a TABLESPACE clause, which allows you to choose a different tablespace as target. Refer to the documentation for your version of the database.

• How exp/tables in the schema hosted Apex 4.2

  Hi all

  I created a test and schema + tables hosted apex application:

  Oracle APEX 4.2 instance hosted by Oracle, https://apex.oracle.com/pls/apex/f?p=4550:1:0

  How I can exp or expdp schema or tables that I created here in it?

  Thank you very much

  MK

  MariaKarpa (MK) wrote:

  Do the images of data type and BLOB like (photos, jpeg, pdf), the recorded data can be extracted as well?  text or xml?

  It would be much faster to try this for yourself, rather than post it here.

  Values of BLOB columns can be unloaded as XML, but not in the form of text.

• querying table inside the schema of the IOM

  Hello
  
  I created a table looks in the scheme of the IOM. I want to insert data into this table custom through my scheduled task. As I try to insert data into a table that is located in the schema of the IOM itself, I hope I don't have to make a JDBC connection. Could you get it someone please let me know how can I go about it?
  
  Thank you
  PETREA

  You can use the statement prepared for her and use tcDataProvider (IOM) to make connections.

• Creating table in the desired tablespace

  Hello

  I created the CUZK_BACKUP tablespace:

  
  
  CREATE the TABLESPACE CUZK_BACKUP DATAFILE ' / oradata/RUIAN/cuzk_backup01.dbf' SIZE 3 G AUTOEXTEND ON NEXT 100 M MAXSIZE 15 G;
  
  
  Now I'm trying to create table in this space of table like this:
  
  

  BEGIN

  -zjisti, if jiz existuji tabulky ve schematu centrumadmin (0 - no, 1 - year)

  SELECT COUNT (*) in the nCount_aud FROM dba_tables owner WHERE to = 'CENTRUMADMIN' and table_name = "$ _BACKUP2";

  SELECT COUNT (*) in the nCount_fga FROM dba_tables owner WHERE = 'CENTRUMADMIN' and table_name = "FGA_LOG$ _BACKUP2";

  IF (nCount_aud < = 0)-pokud tabulka neexistuje, vytvor ji partisnovanou po mesici

  THEN

  v_sql_aud: =' CREATE TABLE CENTRUMADMIN. AUD$ _BACKUP2

  TABLESPACE CUZK_BACKUP

  storage (initial 500 m next 50 m maxextents unlimited)

  PARTITION BY RANGE (NTIMESTAMP #)

  INTERVAL (NUMTOYMINTERVAL (1, "MONTHS"))

  (

  P_2013 PARTITION VALUES LOWER THAN (TO_DATE ("01/01/2014", "DD-MM-YYYY"));

  P_2014_01 PARTITION VALUES LOWER THAN (TO_DATE ("02/01/2014", "DD-MM-YYYY"));

  P_2014_02 PARTITION VALUES LOWER THAN (TO_DATE ("03/01/2014", "DD-MM-YYYY"));

  P_2014_03 PARTITION VALUES LOWER THAN (TO_DATE ("04/01/2014", "DD-MM-YYYY"));

  P_2014_04 PARTITION VALUES LOWER THAN (TO_DATE ("05/01/2014", "DD-MM-YYYY"));

  P_2014_05 PARTITION VALUES LESS THAN (TO_DATE ("06/01/2014", "DD-MM-YYYY")))

  AS select * from SYS. AUD$ where 1 = 2';

  EXECUTE IMMEDIATE v_sql_aud;

  DBMS_OUTPUT. Put_line ('Vytvorena tabulka CENTRUMADMIN.) AUD$ _BACKUP2.') ;

  ON THE OTHER

  DBMS_OUTPUT. Put_line (' CENTRUMADMIN Tabulka.) AUD$ _BACKUP2 jiz existuje.') ;

  END IF;

  Table is created, but not in the CUZK_BACKUP tablespace:

  Select table_name, tablespace_name from dba_tables where owner = "CENTRUMADMIN";

  TABLE_NAME, TABLESPACE_NAME

  ------------------------------ ------------------------------

  CUZK_SLUZBY OKO_USR_SCD

  CUZK_LOG_BEHU OKO_USR_SCD

  CUZK_LOG_FAZE OKO_USR_SCD

  CUZK_LOG_CHYBY OKO_USR_SCD

  AUD$ _BACKUP

  AUD$ _BACKUP2

  FGA_LOG$ _BACKUP

  FGA_LOG$ _BACKUP2

  Why there is no tablespace and how to make it work?

  Thank you

  Honza

  
  
  
  

  For a partitioned table, the actual segments are at the Partition level.  If a query DBA_TAB_PARTITIONS and DBA_SEGMENTS.

  Hemant K Collette

• Select all the tables in the schema

  Hi, I'm looking for x, y of the tables in a schema, get the error "missing expression," working with oracle 11g.
  
  
  declare
  
  v_sql varchar2 (4000);
  number of v_x;
  number of v_y;
  number of V_n;
  
  Start
  
  for rec in loop (select table_name as table_name from all_tables where table_name like '% oumou %' ORDER BY 1)
  
  
  v_sql: = ' select a.idnumber, t.x, t.y, table (sdo_util.getvertices (a.geometry)) t OF ' | Rec.table_name | « a » ;
  V_sql EXECUTE IMMEDIATE v_n, v_x, v_y;
  dbms_output.put_line(V_n|| v_x || v_y);
  
  
  end loop;
  
  
  end;

  ...
    --only for fetching implizit CURSOR cur1
    CURSOR t2 IS SELECT CAST('' AS VARCHAR2(20))idnumber, CAST(0 AS NUMBER) x, CAST(0 AS NUMBER) y FROM dual;
    rec2   t2%ROWTYPE;
  ...
  

  To the implicit CURSOR cur1, you can set a variable-FETCH with CUR1% ROWTYPE.
  So, I defined an explicit CURSOR t2, bringing me the types for the columns of results:
  IDNUMBER (VARCHAR2 (20)), X (NUMBER) and Y (NUMBER)
  This T2 of cursor, I can set a % ROWTYPE VARIABLE t2 to fetch the results.

  Please give points for the solution.

• get information from inside a trigger of the other tables in the schema even

  Addendum:
  
  ... Sorry I forgot: Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64 bit
  
  *******************
  
  Hello
  
  I'm trying for a few hours to get information from inside a trigger to another table in the same pattern.
  
  My trigger is PSE_BKB. NUM_PHANTOM_BP
  
  I first tried a simple solution...
  
  
  CREATE OR REPLACE TRIGGER PSE_BKB. NUM_TR_PHANTOM_BP
  BEFORE DELETING, INSERTION OR UPDATE
  ON PSE_BKB. NUM_PHANTOM_BP
  REFERRING AGAIN AS NINE OLD AND OLD
  FOR EACH LINE
  DECLARE
  
  v_recht NUMBER (1): = 0;
  v_recht2 NUMBER (1): = 0;
  v_change_mitarbeiter NUMBER (1): = 0;
  v_recht_mitarbeiter NUMBER (1): = 0;
  v_typ varchar2 (20);
  v_obj_key varchar2 (11): = "gugus";
  v_ph_key varchar2 (11);
  -ph_key varchar2 (11);
  v_obj_keys varchar2 (4000): = ', ';
  
  anz_num NUMBER: = 0;
  anz_num_tmp NUMBER: = 0;
  anz_st_si NUMBER: = 0;
  
  
  BEGIN
  
  ...
  Select count (*)
  in anz_num
  of pse_bkb.num_objekt o
  where o.obj_key in
  (select distinct (ov.obj_key)
  of pse_bkb.num_objekt_verb ov
  where ov.phantom_key =: old.phantom_key
  )
  and o.typ = "NUM";
  
  ...
  
  Explanation: my trigger table is PSE_BKB. NUM_PHANTOM_BP.
  
  On the pse_bkb.num_objekt_verb of the table, I have a relationship 1: n to one or several object-key (field named obj_key!) on my referenced key: old.phantom_key. With this obj_key, I want to watch the weather, I have one or more lines in the table type num_objekt "NUM". So the internal selection gives me all the num_objekt_verb obj_key with my: old.phantom_key and with whom I count the number of lines I have on num_objekt with type "NUM".
  
  The problem is that the trigger does not see the table.
  
  I tried many variations.
  
  The latest version I tried was with a cursor inside the trigger definition as in the block of code below.
  
  For debugging purposes, I inserted a RAISE_APPLICATION_ERROR in the inner loop - see below. The v_obj_key variable is never defined, as in all the other variations, I tried-, I still see the predefined "gugus" in the declare section.
  
  It seems that oracle can not read other tables at this point. La: old.phantom_key is defined (in this simple example there would come a return obj_key).
  
  Thanks in advance for your help - and excuse my English.
  
  Trigger code:
  
  CREATE OR REPLACE TRIGGER PSE_BKB. NUM_TR_PHANTOM_BP
  BEFORE DELETING, INSERTION OR UPDATE
  ON PSE_BKB. NUM_PHANTOM_BP
  REFERRING AGAIN AS NINE OLD AND OLD
  FOR EACH LINE
  DECLARE
  
  v_recht NUMBER (1): = 0;
  v_recht2 NUMBER (1): = 0;
  v_change_mitarbeiter NUMBER (1): = 0;
  v_recht_mitarbeiter NUMBER (1): = 0;
  v_typ varchar2 (20);
  v_obj_key varchar2 (11): = "gugus";
  v_ph_key varchar2 (11);
  -ph_key varchar2 (11);
  v_obj_keys varchar2 (4000): = ', ';
  
  anz_num NUMBER: = 0;
  anz_num_tmp NUMBER: = 0;
  anz_st_si NUMBER: = 0;
  
  
  BEGIN
  
  
  Start
  declare
  
  cursor nums is
  
  Select obj_key
  of PSE_BKB.num_objekt_verb
  where phantom_key =: old.phantom_key;
  
  Start
  
  for the RC looping nums
  v_obj_key: = cr.obj_key;
  
  RAISE_APPLICATION_ERROR (-20099,' AGAIN 9 v_obj_key: ' | v_obj_key |) ': old.phantom_key ' | (: old.phantom_key);
  
  When the exit nums % NOTFOUND;
  
  Select count (*) in the pse_bkb.num_objekt anz_num_tmp where obj_key = v_obj_key and type = "NUM";
  anz_num: = anz_num + anz_num_tmp;
  end loop;
  
  end;
  end;
  
  Published by: user832075 on 14.01.2013 06:18

  The reason why you get count_n = 0 in tr_c is that there is no line in B with key_c = 17, to the moment you arrive at tr_c. The removal of B has already occurred, and since you're in a single transaction, the application for tr_c:

  select count(*)
    into   counter_n
    from   a aa
    where  aa.key_a in (select distinct(bb.key_a)
                        from   b bb
                        where  bb.key_c = v_ph_key
                       )
    and    aa.typ = 'n';
  

  'knows' that the row has been deleted then gets a number of 0.

  I added a set of instructions dbms_output to show the order in which triggers run, and that's what I get:

  SQL> delete from b_vw where key_a = 1 and key_c = 17 ;
  in trigger b_tr_vw
  In tr_b
  in tr_c
  delete from b_vw where key_a = 1 and key_c = 17
              *
  ERROR at line 1:
  ORA-20077: Remark: counter_n: 0 counter_s: 0 v_ph_key: 17 old.key_c: 17
  new.key_c:
  ORA-06512: at "OPS$ORACLE.TR_C", line 38
  ORA-04088: error during execution of trigger 'OPS$ORACLE.TR_C'
  ORA-06512: at "OPS$ORACLE.B_TR_VW", line 17
  ORA-04088: error during execution of trigger 'OPS$ORACLE.B_TR_VW'
  

  Thus b_tr_vw trigger is triggered first and deletes a B. trigger fires tr_b as part of this statement to remove and check against A, happening apparently so no error is triggered and succeeds the removal of B. Now tr_b_vw takes back control and deletes C. Since the B line which has key_c = 17 already deleted a control for counter_n > 0 and counter_s = 0 fails and raise you the-20002 error. Note that I'm assuming that the error of-20077 you lift is just to see the values and is not intended to be part of your actual code.

  Because I have really no idea what you're trying to accomplish here I can't offer a lot of advice that you might want to try entering two tr_c of the tr_b_vw trigger validation queries before deliver you the removal of b and put the counter_n > 0 and counter_s = 0 control under tr_b_vw to decide whether or not you want to remove.

  John

• create table on the production database

  Hi expert I want some knowledge in real time
  If a user has requested to create a table on the production database where DBA one should contact 1.
  form where dba approval for create table.
  
  
  Thanks and greetings
  Sanat

  It depends on your hierarchy of society. Generally, your immediate boss.

• Creating tables with the same Structure and with the remote control FOR the parts database

  Hello
  
  I have a remote DB connection and a local DB connection in my system
  I want to create the same Table and data from my DB remote to Local Connection DB connection.
  
  Please tell me how to do this?

  CREATE TABLE LOCAL_TABLE AS SELECT * FROM REMOTE_TABLE@TNS_ALIAS;

• Create table replaces the existing table in mssql

  In a program that allows us to update our sites, we use the function 'create an array' of MS SQL to create missing tables in databases.
  
  Thousands of time we used it, if a table already exists with the same name of the table in the create table MS SQL survey command an error.
  
  In fact, MS SQL documentation indicates that only if you include the optional 'replace' command, will be a replaced existing table.
  
  But today, we used this program on a new host, that we are trying, and the create table command actually did replace an existing table with a new table, delete all the records from the old table.
  
  I'm trying to understand what this would allow the settings at the server level.
  
  This is the code we use:
  
  < CFQUERY NAME = "recipe" DATASOURCE = "recipe" dbtype = "ODBC" username = "" #ruser # "password =" #rPASS #">"
  Create table recipecats)
  RecipecatID int IDENTITY(1, 1) NOT NULL PRIMARY KEY,
  recipecatdescription NVARCHAR (50) NULL)
  < / cfquery >

  Are you sure that this is not just to create another table with the same name, but one
  different owner?

  I saw the strangeness (it's probably just weird for me because I am ignorant)
  of what is happening), I can READ a table owned by another user without
  calling the name of the table with its owner, and when I go to CREATE a table
  of the same name, it is actually created as my current user and subsequently when
  you ask the name of the full table, I get the results of one, is not new
  the former. If I'm right in the name of the table, I can ask both/either. Kind
  way similar CF hunting around different scopes when you aren't eligible one
  reference to a variable.

  Also, your code should probably be testing to see if the table exists
  before you try to create it anyway. "Just try and catch.
  "If it errors" is not considered as 'test' if there is

  --
  Adam

• How to create table of the method

  Hello-
  
  Could someone please tell me how can I create an af:table with more than one column of an AppsModule method.
  
  When I have a 1 d table return for example:
  
  public String [] createTable()}
  String [] str = new String [1];
  return str;
  }
  
  I can get as a table and a column is created. But how do I get mutiple columns in a table. I want to write a method that when inserted on jsp page create table with multiple columns.
  
  I use ADF 11 g.
  
  Please suggest.
  
  Greetings-
  Rohit

  Hello

  to do this, you use a matrix, or a list of arrays of objects. The object represents the contents of the line, e.g., person. The Person class then have setter/getter for each property you want to display in a column

  Frank

• Create table in the select statement.

  Hello Oracle gurus,
  
  I am creating a table using select * in the other table.
  
  The procedure I am following is as follows: -.
  
  I have a temporary table whose signature is on delete rows commit.
  
  I insert records into this table.
  
  When I select * from temporary_table, perm_table, I get a few lines.
  
  so I try to create a result_table the use of this
  
  CREATE TABLE result_table
  AS SELECT * FROM temporary_table, perm_table;
  
  I see the created array, but the number of records in 0. Please can someone explain where the validation is performed while the sequence in this query occurs.
  
  Thank you
  
  Published by: user10696492 on November 10, 2009 08:47

  Hello

  When you perform DDL like CREATE TABLE implicit validation takes place just before and just after the statement.

  Concerning
  Peter