DATE OF RETURN TO RQTABLEEVAL COLUMNS

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  Version 11.1.1.7

  I have a dashboard command prompt which invites for a date.

  My analysis is filtered on this prompt.

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  I changed the sql statement

  Of

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  TO

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• Date of maturity in AP column

  Hello friends,
  
  In my report in the date field, I printed payment date, but my client wants the date of maturity in this area
  
  could you please tell me difference between the due date and the payment date
  
  and in which table, we can find the date of maturity in AP column
  
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  Thank you
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  Published by: 805567 on December 10, 2010 05:40

  Due date is also called the future dated payment.

  Try AP_CHECKS_ALL. FUTURE_PAY_DUE_DATE or APFV_PAYMENT_SCHEDULES. FUTURE_PAY_DUE_DATE or the FUTURE_PAY_DUE_DATE column in the tables below
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  AP_PAYMENT_SCHEDULES_ALL
  AP_SELECTED_INVOICE_CHECKS_ALL

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  Alex,

  You can try the following example here:

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• Giving date based return number interval

  Here is an example of what I am trying to accomplish. The setting I will use is which days are available for work in the format of (0,1,1,1,1,1,0).
  
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  Here's the SQL I use as a concept I need help on how to incorporate it.
  
  ~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*~*
  CREATE or REPLACE function custom_add_days
  (start_date_in date, number of days_in)
  date of return
  IS
  number of v_counter;
  date of v_new_date;
  number of v_day_number;
  BEGIN
  
  / * This routine adds a specified number of days (ie: days_in) at a date (ie: start_date). */
  / * It will ignore all weekend days - Saturday and Sunday * /.
  v_counter: = 1;
  v_new_date: = start_date_in;
  
  / * Loop to determine how many days to add * /.
  all in v_counter < = days_in
  loop
  / * Add a day * /.
  v_new_date: = v_new_date + 1;
  v_day_number: = to_char (v_new_date, 'd');
  
  / * Increment counter if day falls between Monday to Friday * /.
  If v_day_number > = 2 and v_day_number < = 6 then
  v_counter: = v_counter + 1;
  end if;
  
  end loop;
  
  RETURN v_new_date;

  Sorry did not see your last post.

  Maybe something like that (changed your function a bit):

  SQL> CREATE OR REPLACE FUNCTION custom_add_days (
    2     start_date_in   DATE,
    3     work_days       VARCHAR2,
    4     days_in         NUMBER
    5  )
    6     RETURN DATE
    7  IS
    8     v_counter          NUMBER;
    9     v_new_date         DATE;
   10     v_day_number       NUMBER;
   11     v_loop_counter     NUMBER := 0;
   12     work_days_status   NUMBER;
   13  BEGIN
   14  /* This routine will add a specified number of days (ie: days_in) to a date (ie: start_date). *
  /
   15  /* It will skip all weekend days - Saturdays and Sundays */
   16     v_counter := 1;
   17     v_new_date := start_date_in;
   18
   19  /* Loop to determine how many days to add */
   20     WHILE v_counter <= days_in
   21     LOOP
   22  /* Add a day */
   23        v_new_date := v_new_date + 1;
   24        v_day_number := TO_NUMBER(TO_CHAR (v_new_date, 'd'));
   25        v_loop_counter := v_loop_counter + 1;
   26        work_days_status :=
   27           TO_NUMBER (SUBSTR (REPLACE (work_days, ','),
   28                              CASE
   29                                 WHEN MOD (v_loop_counter, 7) = 0
   30                                    THEN 7
   31                                 ELSE MOD (v_loop_counter, 7)
   32                              END,
   33                              1
   34                             )
   35                     );
   36
   37  /* Increment counter if day falls between Monday to Friday */
   38        IF  work_days_status = 1
   39        THEN
   40           v_counter := v_counter + 1;
   41        END IF;
   42     END LOOP;
   43
   44     RETURN v_new_date;
   45  END;
   46  /
  
  Function created.
  
  SQL> show errors
  No errors.
  SQL> SELECT sysdate FROM Dual
    2  /
  
  SYSDATE
  ---------
  01-JUL-09
  
  1 row selected.
  
  SQL> SELECT CUSTOM_ADD_DAYS(sysdate, '1,0,1,1,1,0,1', 3) FROM Dual
    2  /
  
  CUSTOM_AD
  ---------
  05-JUL-09
  
  1 row selected.
  
  SQL> 
  

  Kind regards
  JO

  Published by: Joice John July 1, 2009 06:08

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  Hello

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  I want to return a single line of data below

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  1 T345 01/01/2001 1

  1 B455 01/01/1999 2

  1 T555 01/01/1998 3

  1 R433 01/01/1997 4

  1 "T543" 01/01/1996 5

  Thank you

  
  

  SQL> with t
    2  as
    3  (
    4  select 1 client_no, 'T345' tran_code, to_date('01/01/2001', 'dd/mm/yyyy') trandate, 1 rno
    5    from dual union all
    6  select 1 client_no, 'B455' tran_code, to_date('01/01/1999', 'dd/mm/yyyy') trandate, 2 rno
    7    from dual union all
    8  select 1 client_no, 'T555' tran_code, to_date('01/01/1998', 'dd/mm/yyyy') trandate, 3 rno
    9    from dual union all
   10  select 1 client_no, 'R433' tran_code, to_date('01/01/1997', 'dd/mm/yyyy') trandate, 4 rno
   11    from dual union all
   12  select 1 client_no, 'T543' tran_code, to_date('01/01/1996', 'dd/mm/yyyy') trandate, 5 rno
   13    from dual
   14  )
   15  select client_no
   16       , tran_code
   17       , trandate
   18       , rno
   19       , case when t555_cnt > 0 then 'YES' else 'NO' end t555
   20    from (
   21            select t.*
   22                 , count(decode(tran_code, 'T555', 1)) over() t555_cnt
   23              from t
   24             where client_no = 1
   25         )
   26   where rno = 1;
  
   CLIENT_NO TRAN TRANDATE         RNO T55
  ---------- ---- --------- ---------- ---
           1 T345 01-JAN-01          1 YES
  
  SQL>
  

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  Hello world

  My version of DB is

  BANNER

  --------------------------------------------------------------------------------

  Oracle Database 11 g Enterprise Edition Release 11.2.0.1.0 - 64 bit Production

  PL/SQL Release 11.2.0.1.0 - Production

  CORE 11.2.0.1.0 Production

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  Kind regards

  BS2012.

  Hi Frank,.

  I have it. Please check on the following query. Hoooooaaaaaa

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  THEN (SELECT COUNT (*) AS NO_OF_JOINERS FROM EMP WHERE TO_CHAR(HIREDATE,'MON/YY') = ' JUN/81 ' ") END) AS"JUN/81",

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  THEN (SELECT COUNT (*) AS NO_OF_JOINERS FROM EMP WHERE TO_CHAR(HIREDATE,'MON/YY') = ' JUL/81 ' ") END) AS"JUL/81",

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  THEN (SELECT COUNT (*) AS NO_OF_JOINERS FROM EMP WHERE TO_CHAR(HIREDATE,'MON/YY') = ' AUG/81 ' ") END) AS"AUG/81",

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  THEN (SELECT COUNT (*) AS NO_OF_JOINERS FROM EMP WHERE TO_CHAR(HIREDATE,'MON/YY') = ' MS/81 ' ") END) AS THE"SEP/81",

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  THEN (SELECT COUNT (*) AS NO_OF_JOINERS FROM EMP WHERE TO_CHAR(HIREDATE,'MON/YY') = ' OCT/81 ' ") END) AS"OCT/81",

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  THEN (SELECT COUNT (*) AS NO_OF_JOINERS FROM EMP WHERE TO_CHAR(HIREDATE,'MON/YY') = ' NOV/81 ' ") END) AS"NOV/81",

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  WHEN TO_CHAR(HIREDATE,'MON/YY') = "DEC/81 '.

  THEN (SELECT COUNT (*) AS NO_OF_JOINERS FROM EMP WHERE TO_CHAR(HIREDATE,'MON/YY') = ' DEC/81 ' ") END) AS"DEC/81 ".

  FROM EMP;

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  I ignore the xmlns somehow?

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  CONTENT_VAL
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